for the hypothetical salaries in the following
dataset, what is the average salary per year?
Data set of hypothetical salaries: $46,000 per year,
$20,000 per year, $33,000 per year, $27,000 per year,
$91,000 per year.

For The Hypothetical Salaries In The Followingdataset, What Is The Average Salary Per Year?Data Set Of

Answers

Answer 1

Answer: $43400 per year

Explanation:

The Data set of hypothetical salaries is given as:

$46,000 per year,

$20,000 per year,

$33,000 per year,

$27,000 per year,

$91,000 per year.

The average salary per year will be the addition of the salaries per year above which will then be divided by 5. This will be:

= ($46,000 + $20,000 + $33,000 + $27,000 + $91,000) / 5

= $217000/5

= $43400 per year

The average salary per year will be $43400


Related Questions

Knowledge and skills learned through socialization are an example of

Multiple Choice

1. human resources.
2. social resources.
3. political resource.
4. cultural resources.​

Answers

Answer:

I think no.2 the answer

Because socialization and social resources are both for me

The correct answer is 4. cultural resources. Knowledge and skills learned through socialization.

What are Knowledge and skills learned through socialization?

Knowledge and skills learned through socialization refer to the cultural, social, and behavioral norms and values that individuals learn through interaction with others in their environment. This process of learning begins in childhood and continues throughout an individual's life, through various social institutions such as family, education, religion, media, and peer groups.

Here,
The correct answer is 4. cultural resources. Knowledge and skills learned through socialization are an example of cultural resources because they are shaped by the cultural norms, values, and beliefs of the society in which an individual grows up.

Learn more about knowledge and skill learned here:

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how many protons would the element with the atomic number 10 contain?

Answers

Answer:

the atomic number is the same as the proton numbers so your answer is D.10

Answer:

It contains 10 protons and 10 electrons.

The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.80 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.

Answers

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

Which on the map
represents Asia?

Answers

Answer:

B because it's on Asia but that pfp tho

The answer is B that represents Asia

Water is kept in a vessel at a temperature of 100°C. What would happen if a metal ball having a temperature of 30°C is dropped in it? Mention the direction of the heat flow.

Answers

Answer:

there will be a heat flow from water to the metal ball...

The charge on the sphere is monitored as a beam of monochromatic light shines on the sphere. Initially nothing happens. The wavelength of the light is slowly decreased. When the wavelength reaches a certain value, a positive charge is suddenly measured on the sphere. The wavelength is then held constant, and the charge continues to increase at a constant rate. The intensity of the beam is then increased without the wavelength being changed, and the rate of increase of the charge becomes greater.
In a coherent paragraph-length response, describe the cause of the charge on the sphere and the changes in the observations about the charge, in terms of physics principles.

Answers

Answer:

explanation of this effect  is  the photoelectric effect

Explanation:

Let's describe the process, when light of large wavelength falls, this implies a small energy, according to Planck's equation

           E = h f = [tex]\frac{h \ c}{ \lambda}[/tex]

the energy of the photons is not enough to carry out an electronic transition between two states of the material, when we decrease the wavelength (the energy of the photons increases), the point is reached where the energy of the beam is equal to some energy of a transition, by which the electrons are promoted and since we can see a certain charge, as the atoms are neutral, some electrons must be removed from the material, this is represented in the macroscopic case as the work function of the material, consequently a unbalanced load that is what we can measure.

When we increase the lightning intensity, what we do is that we increase the number of photons and if each photon can remove an electron, by removing the electrons the difference between it and the positive charge (fixed in the nuclei) increases.

We can analyze the interaction of the photon and the electron as a particular collision.

The explanation of this effect was made by Einstein in his explained of the photoelectric effect

Which type of reaction is this formula an example of?

CH3OH + O2→CO2 + 2H2O + heat

Answers

Explanation:

This is an exothermic reaction. An exothermic reaction is one which releases heat to the surroundings. When CH3OH reacts with O2, heat is released on the product side of the reaction.

Two coils of wire are placed close together. Initially, a current of 3.03 A exists in one of the coils, but there is no current in the other. The current is then switched off in a time of 3.03 x 10-2 s. During this time, the average emf induced in the other coil is 4.13 V. What is the mutual inductance of the two-coil system

Answers

Answer:

4.13 ×10^-2 H

Explanation:

mutual inductance of the two-coil system can be calculated using below expression

mutual inductance = (- E Δt)/ ΔIp

Where E= average emf induced

Δt= time

ΔIp= change in current

ΔIp=( 0s - 3.03 A)

Δt=3.03 x 10-2 s.

If we substitute the values into above expresion, we have,

E= 4.13 V.

mutual inductance = (- E Δt)/ ΔIp

= - (4.13 V × 3.03 x 10^-2 s.)/ ( 0s - 3.03 A)

= 4.13 ×10^-2 H

Hence, the mutual inductance of the two-coil system is 4.13 ×10^-2 H

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower

Answers

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

Answer:

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Explanation:

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

A concert loudspeaker suspended high off the ground emits 33.0 W of sound power. A small microphone with a 0.600 cm2 area is 52.0 m from the speaker. What is the sound intensity at the position of the microphone

Answers

Answer:

The sound intensity at the position of the microphone is [tex]9.71\times10^{-4} W/m^{2}[/tex]

Explanation

Sound intensity is given by the formula

[tex]I=\frac{P}{A}[/tex]

Where [tex]I[/tex] is the sound intensity, [tex]P[/tex] is the power and [tex]A[/tex] is the area.

Since the loudspeaker radiates sound in all directions, we have a spherical sound wave where the radius r is the distance of the microphone from the speaker.

∴ [tex]A[/tex] is given by [tex]4\pi r^{2}[/tex] where [tex]r[/tex] is the radius

From the question, [tex]P[/tex] = 33.0W, [tex]r[/tex] = 52.0m

[tex]I=\frac{P}{A} = \frac{P}{4\pi r^{2} }[/tex]

[tex]I = \frac{33.0}{4\pi \times (52.0)^{2} }[/tex]

∴ [tex]I = 9.71\times10^{-4} W/m^{2}[/tex]

Hence, the sound intensity at the position of the microphone is 9.71 × 10⁻⁴ W/m²

WILL MARK YOU BRAINLIEST
Describe the importance and reliability of systems that use digital signals to store information. (Include the advantages of storing information digitally, as opposed to physical copies.)
Describe three instances of digital transmission and storage in your everyday life. Be sure to explain how you know data transmission or storage is occurring in each instance.
Explain how radio waves and digital signals will store and transmit this assignment to your instructor.
Describe how wave behavior and interactions can affect the quality of a signal received by a mobile device.
A medical office is planning to convert to an electronic database to store patient information. What are the pros and cons to making changes in this form of storage of personal medical information instead of written physical files? Provide evidence based on your knowledge of digital storage to support your reasoning.
As seen in the lesson video, solar photovoltaic technologies help provide clean electrical energy. Using the video animation as a guide, diagram and label the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems. Include a screen shot or picture of your diagram below.

Answers

Digital signals are a more reliable form of transmitting information because an error in the amplitude or frequency value would have to be very large in order to cause a jump to a different value. Signals are composed of infinite possible values. ... Sound signals can vary smoothly in volume and pitchAdvantages to using digital signals, including digital signal processing (DSP) and communication systems, include the following:

Digital signals can convey information with less noise, distortion, and interference.

Digital circuits can be reproduced easily in mass quantities at comparatively low costs.

Answer:

it is easy to change the data if you have the right computer programs

Explanation:

If a rock is sitting at the top of a 400-m cliff
and has a mass of 32 kg, what is the potential
energy of the rock?

Answers

Answer:

0.

Explanation:

rocks dont have energy

An organ pipe closed at one end is 0.76 m long. (A) Determine its fundamental frequency. (B) What are the 3rd and 5th harmonics? Note: Use 344 m/s as the speed of sound.

Answers

Answer:

A) 113.16 Hz

B) 339.47 Hz

565.79 Hz

Explanation:

Only odd harmonics are present in closed pipes that was why they asked for 3rd and 5th harmonics.

i need written answer with solution:-
a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity​

Answers

Answer:

~65.9m/min

Explanation:

Excuse the messy handwriting!

A student is producing a power rating of 100 W. What will be the student's power rating if she performs 3 times the work in twice the amount of time?​

Answers

600W is the correct answerr

on which principle thermometer is based?​

Answers

Answer:

Thermal Expansion

Explanation:

These liquid thermometers are based on the principal of thermal expansion. When a substance gets hotter, it expands to a greater volume. Nearly all substances exhibit this behavior of thermal expansion. It is the basis of the design and operation of thermometers.

Any magnet has two ends, each one called a(n)​

Answers

pole (north pole and south pole)

a box is slides down a slope

Answers

Answer:

120 N

Explanation:

From the question given above, the following data were obtained:

Angle (θ) = 35°

Mass (m) = 15 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (N) =?

The normal force acting on the object can be obtained as:

N = mg × Cosθ

N = 15 × 9.8 × Cos 35

N= 147 × 0.8192

N = 120 N

Therefore, the normal force acting on the object is 120 N

2) A 45-kg person steps on a scale in an elevator. The scale reads 460 N. What is the elevator doing?

Answers

Answer:

The elevator is stationary

ball A is dropped from a hot air balloon rising at a costant velocity of 14,7 m.s'1 at a height of 19,7 m above the ground.the ball took 1.5s to reach its maximum height and hits the ground after some time in air.ignore the effects of air resistanceUse the ground as zero reference.3.1.1calculate the maximum height reached by the ball above the ground​

Answers

Answer:

this slow site thinks the answer is a link

Explanation:

this was a week ago so i dont know if u still need help

The National Institute of Health is testing sensors which measure the energy felt by goalkeepers when blocking soccer balls coming at them and the velocity of soccer balls. One sensor measuring velocity is inside a 16 ounce soccer ball, which is kicked by a player at an initial velocity of 31 m/s. The ball bounces off the goalkeeper at a final velocity of 2.25 m/s. How much energy in Joules should the sensor say the goalkeeper absorbed, not accounting for wind and drag

Answers

Answer:

E = 216.76 J

Explanation:

The amount of energy absorbed by the goalkeeper will be equal to the difference between the initial and the final kinetic energy of the ball.

[tex]Energy\ Absorbed = Initial\ Kinetic\ Energy - Final\ Kinetic\ Energy\\Energy\ Absorbed = E = \frac{1}{2}mv_{i}^2 - \frac{1}{2}mv_{f}^2\\E = \frac{1}{2}m(v_{i}^2 - v_{f}^2)\\[/tex]

where,

m = mass of ball = (16 ounce)(0.0283495 kg/1 ounce) = 0.4535 kg

vf = final velocity = 2.25 m/s

vi = initial velocity = 31 m/s

Therefore,

[tex]E = \frac{1}{2}(0.4535\ kg)[(31\ m/s)^2 - (2.25\ m/s)^2][/tex]

E = 216.76 J

A driver is texting without seeing the traffic ahead and crashes into a stationary vehicle. Explain what happens to the kinetic energy. Answer in 4-6 sentences.

Answers

Answer:

By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.

Explanation:

By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.

Use the drop-down menus to complete the sentences.
A concave lens is
in the middle than at the edges, and causes light rays to
A convex lens is
in the middle than at the edges, and causes light rays to

Answers

Answer:

1) thinner, diverge

2) thicker, converge

Explanation:

i got it right thanks to the other user :)

A concave lens is thinner in the middle than at the edges, and causes light rays to diverge.

A convex lens is thicker in the middle than at the edges, and causes light rays to converge.

What are concave and convex lens?

The lenses used to form images of the object placed a distant apart.

The concave mirror form images by virtual meeting of the light rays and appear to meet. They are thin at the middle portion.

The convex mirror form images by real meeting of the light rays. They converge the rays coming from object. They are thick at the middle portion.

Thus, A concave lens is thinner in the middle than at the edges, and causes light rays to diverge.

A convex lens is thicker in the middle than at the edges, and causes light rays to converge.

Learn more about concave and convex lens.

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You find an unmarked blue laser on your way to physics class. When you get to class you realize you can determine the wavelength of the laser by doing a double slit experiment. Shining the laser through a double slit with a slit separation of 0.342 mm on the wall 2.12 m away the first bright fringe is 2.80 mm from the center of the pattern. What is the wavelength

Answers

Answer:

λ = 451.7 nm

Explanation:

The expression for the constructive interference of the double diffraction experiment is

          d sin θ = m λ

let's use trigonometry

          tan θ = y / L

   

how the experiment occurs at very small angles

          tan θ = sin θ / cos θ = sin θ

          sin θ = y / L

we substitute

         d y / L = m λ  

         λ = [tex]\frac{d \ y}{m \ L}[/tex]

let's calculate

          λ = [tex]\frac{0.342 \ 10^{-3} \ 2.80 \ 10^{-3} }{1 \ 2.12 }[/tex]

          λ = 4.51699 10⁻⁷ m

          λ = 4.517 10⁻⁷ m (109 nm / 1m)

          λ = 451.7 nm

Marcy pulls a backpack on a wheels down the 100m hall. The 60N force is applied at an angle of 30° above the horizontal. How much work is done by Marcy?

Answers

Answer:

Work= Fcos∆×S

W=60N×cos 30⁰×100

W=60×0.866×100=5196.1J

PLEASE GIVE BRAINLIEST

What is the magnitude of the resultant vector? Round
your answer to the nearest tenth.
m
R
5 m
13 m
Intro
Done

Answers

Answer: 13.9 m

Explanation:

Answer:

13.9m

Explanation:

Answer on Edge

A car is stopped at a traffic signal. A second car rear-ends the first car. From the crush of the two vehicles, it is estimated that the second car was traveling at 15 mph when it impacted the first car. If the second car laid down 166 feet of skid marks before the crash took place, how fast was the second car traveling when its brakes were locked up

Answers

The question is incomplete. The complete question is :

A car is stopped at a traffic signal. A second car rear-ends the first car. From the crush of the two vehicles, it is estimated that the second car was traveling at 15 mph when it impacted the first car. If the second car laid down 166 feet of skid marks before the crash took place, how fast was the second car traveling when its brakes were locked up? The approach to the intersection where the accident took place is on a 2.5 percent downgrade. Assume the AASHTO recommended deceleration rate of [tex]$11.2 \ ft/s^2.$[/tex]

Solution :

From the equation, the skid distance is given by

[tex]$S=\frac{u_i^2-u_f^2}{2g\left(\frac{a_d}{g}+h\right)}$[/tex]

Here, [tex]$a_d$[/tex] = deceleration rate, [tex]$11.2 \ ft/s^2.$[/tex]

         h = [tex]$-\frac{2.5}{100}$[/tex] = -0.025

         [tex]$u_i$[/tex] = initial speed of the car

         [tex]$u_f$[/tex] = speed when impacted

Therefore,

[tex]$166=\frac{u_i^2-(15 \times 1.467)^2}{2\times 32.2\left(\frac{11.2}{32.2}+0.025\right)}$[/tex]

[tex]$\Rightarrow u_i^2 = 3935.36$[/tex]

[tex]$\Rightarrow u_i = 62.73 \ ft/s$[/tex]

or [tex]$ u_i = \frac{62.73}{1.467} $[/tex]

   [tex]$ u_i = 42.76 \ mph $[/tex]

write each of the following in scientific notation, correct to 2 decimal places.
a. 0.00000123 N
b. 417 000 000 kg
c. 246800 A
d. 0,00088 mm​

Answers

Answer:

The scientific notation for the each number is given below:

Explanation:

The scientific notation for the following numbers are:

a. For 0.00000123 N

1.23 × 10^-6

b. For 417 000 000 kg

4.17 × 10^8

c. For 246800 A

2.47 × 10^5

d. For 0.00088m

8.8 × 10^-4

The above represent scientific notations of each numbers

6/30
What is the total circuit resistance of the following five resistors connected in series?
R1 = 27 ohms
R2 = 33 ohms
R3 = 51 ohms
R4 = 1.2 kohms
R5 = 240 ohms
Rt =
Ohms

Answers

Answer:

Explanation:

in series, resistors just add up

27+33+51+1200+240= 1551 ohms

I’m not sure sorry hope someone helps :)

a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, find the ball's kinetic, potential, and mechanical energies (a) a its initial position, (b) at 5 m above the initial position, and (c) at its maximum height

Answers

Answer:

a) [tex] E_{p} = 0 [/tex]

[tex] E_{k} = 168.7 J [/tex]

[tex] E_{m} = 168.7 J [/tex]

b) [tex] E_{p} = 73.6 J [/tex]

[tex] E_{k} = 95.8 J [/tex]

[tex] E_{m} = 169.4 J [/tex]

c) [tex] E_{p} = 169.2 J [/tex]

[tex] E_{k} = 0 [/tex]

[tex] E_{m} = 169.2 J [/tex]

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

[tex] E_{p} = mgh = 0 [/tex]

The kinetic energy is:

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J [/tex]

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

[tex] E_{p} = mgh = 1.5*9.81*5 = 73.6 J [/tex]

Now, to find the kinetic energy we need to calculate the speed at 5 m:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9 [/tex]

[tex] v_{f} = \sqrt{126.9} = 11.3 m/s [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J [/tex]

c) At its maximum height:

[tex] v_{f}[/tex]: is the final speed = 0

[tex] h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m [/tex]

Now, the potential, kinetic and mechanical energies are:

[tex] E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = 0 [/tex]

[tex] E_{m} = 169.2 J + 0 = 169.2 J [/tex]

I hope it helps you!    

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