find the range of the given function -

[tex]f(x) = x {}^{2} [/tex]


thankyou ~​

Answer:

Step-by-step explanation:

We Notice that 2 and 5 are two prime numbers

Remark : the least common multiple of two prime numbers is equal to their product .

Then

LCM(2 , 5) = 2 × 5 = 10

2 * 5

= 10 ⟶ least common multiple of the number (since no common factor is there)

Answer:

(x +2y ) ( 2x-3y)

= 2x² + 4xy -3xy -6y²

= 2x² +xy -6y²

Step-by-step explanation:

2x^2 +xy-6y is the answer

THIS ONE I CANT FIGURE OUT SORRY :C

Answer:

See below ~

Step-by-step explanation:

Solving :

(a) Coordinates of P and Q

⇒ Equate the lines' equations

⇒ 2x² - 6x - 8 = 2x - 14

⇒ 2x² - 8x + 6 = 0

⇒ x² - 4x + 3 = 0

⇒ (x - 3)(x - 1) = 0

⇒ x = 3 and x = 1

Substitute each x-value in the any of the 2 equations :

⇒ y = 2(3) - 14

⇒ y = 6 - 14

⇒ y = -8

⇒ P = (3, -8)

⇒ y = 2(1) - 14

⇒ y = 2 - 14

⇒ y = -12

⇒ Q = (1, -12)

(b)

(i) 2x² - 6x - 8 = 0

⇒ x² - 3x - 4 = 0

⇒ (x - 4)(x + 1) = 0

⇒ x = 4 and x = -1

(ii) 2x² - 6x = -4

⇒ 2x² - 6x + 4 = 0

⇒ x² - 3x + 2 = 0

⇒ (x - 1)(x - 2) = 0

⇒ x = 1 and x = 2

(c) Line of symmetry

Finding the vertex :

⇒ Vertex = (h, k)

⇒ h = -b/2a

⇒ h = -(-6)/2(2)

⇒ h = 6/4

⇒ h = 1.5

⇒ The axis of symmetry's equation is : x = 1.5

(d)

⇒ As the mentioned function is a quadratic function, irrational values such as √2, √3, √6, etc. cannot be taken into consideration

The nth term of the Sequence: 40, 33, 26, .... is 47 - 7n.

An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same.

Here, we know nth term of the Arithmetic Sequence is

             Aₙ = A + (n - 1)D

where, A is first term and D is common difference

   A = 40 and D = 33 - 40 = -7

Now,    Aₙ = 40 + (n - 1) (-7)

            Aₙ = 40 - 7n + 7

          Aₙ = 47 - 7n

Thus, the nth term of the Sequence: 40, 33, 26, .... is 47 - 7n.

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The shapes that are under the trapezoid in the quadrilateral hierarchy are parallelogram and isosceles trapezoid.

A quadrilateral is a polygon that has four sides and four angles. Types of quadrilateral are kite, square, parallelogram and so on.

The shapes that are under the trapezoid in the quadrilateral hierarchy are parallelogram and isosceles trapezoid.

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Answer:

5747.37

Step-by-step explanation:

5 000 ( 1 + .01) ^14

 =   5747.37

fixed cost= $8

cost= $4.50

payed= $50

recieved= $10.50

how many days Hannah rented the bike.

let the unknown be ( x )

[tex]x = 50 - (10.50 + 8)[/tex]

[tex]x = 50 - 18.50[/tex]

[tex]x = 13.50[/tex]

[tex]x = \frac{13.50}{4.50} [/tex]

[tex]x = 7[/tex]

hence, Hannah rented the bike for 7 days.

2,400 + 70N = S

hope this helps ya mate

50m ≅164 ft (3s.f.)

50m/s≅164 ft/s

distance after 20s:

d=164 ft/s ⋅20s

=3280ft

Hope This Helps!

Answer:

Step-by-step explanation:

x² - 2x + 5 = 0

x² - 2x = -5

x² - 2x + 1 = -5 + 1

(x - 1)² = -4

(x - 1) = ±2i

[tex]\\ \rm\Rrightarrow (f+g)(x)[/tex]

[tex]\\ \rm\Rrightarrow f(x)+g(x)[/tex]

[tex]\\ \rm\Rrightarrow x^2-4x+6+2x^2+2x-5[/tex]

[tex]\\ \rm\Rrightarrow 3x^2-2x+1[/tex]

Done!

Answer:

[tex](f+g)(x)=3x^2-2x+1[/tex]

Step-by-step explanation:

[tex]\begin{aligned}\textsf{Given functions}: \quad f(x) &=x^2-4x+6\\g(x) &=2x^2+2x-5\\\end{aligned}[/tex]

[tex]\begin{aligned}(f+g)(x) & =f(x)+g(x)\\& =(x^2-4x+6)+(2x^2+2x-5)\\& =x^2-4x+6+2x^2+2x-5\\& =x^2+2x^2-4x+2x+6-5\\& =3x^2-2x+1\end{aligned}[/tex]

Answer:

B

Step-by-step explanation:

Let's take a look at each statement.

A: ∠1 ≅ ∠8

Angle 1 is congruent to angle 8.

If lines are parallel then angle 1 and angle 8 would be same side (consecutive) exterior angles which are supplementary and not congruent.

Therefore this statement would prove that the lines are not parallel.

B: ∠1 ≅ ∠7

Angle 1 is congruent to angle 7.

If lines are parallel then angle 1 and angle 7 would be alternate exterior angles which are congruent.

This statement proves that the lines are parallel. We have angle 1 that is at line AB and angle 7 which is at line CD. It's important that one angle is at one line and the second angle at the other line, otherwise we cannot prove that the lines are parallel.

C: ∠6 ≅ ∠8

Angle 6 is congruent to angle 8.

Angles 6 and 8 are vertical angles and they are congruent.

This statement is correct but it doesn't tell us anything about the relationship of angles at the other line, therefore it proves nothing.

D: ∠1 and ∠2 are supplementary.

Angles 1 and 2 create a linear pair, therefore they are supplementary.

This statement is also correct but again it tells us nothing about the angles at the other line so it again proves nothing.

Answer:

Your answer is A and B

Step-by-step explanation:

A. Has 8 by 3 by 2 = 48

B. 6 by 4 by 2 = 48

C. 4 by 4 by 4 = 64

D. 11 by 2 by 2 = 44

Answer:

10/10

Step-by-step explanation:

Answer:

I will answer them from top to bottom

1. 2A

2. 2A-B

3. 2A+3A

4. 2(A-B)

Step-by-step explanation:

You don't need an explanation. I am just putting this here so my answer does not get taken down.

Answer:

you first can check online, call your bank, visit an ATM, set up alerts, or ask a teller.

The SECA taxes for the income $57000 will be $7068.

SECA stands for Self Employed Contributions Act. These taxes are computed from the net earnings, which in this case is $57000.

The basic rate for SECA taxes is 6.2% for employeer and 6.2% for employee. In the case of people who are self employed, the taxes are double, because they are employee and employeer at the same time.

So, Doug have to pay 12.4% taxes, which is equivalent to:

[tex]\rm SECA=57000\times 12.4\%= $7067[/tex]

Therefore, the SECA deduction for Doug is $7068.

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Answer:

they are really different

Answer:

{5a-b+c=10}

{a-3b-c=-4

[2a+2b-c=6

Step-by-step explanation: so it's 6 hope this helps. Let me know if it helps and give brainliest.

quaddale dingle said hey, whats up

Answer:

[tex]\frac{4}{13}[/tex]

Step-by-step explanation:

1÷3[tex]\frac{1}{4}[/tex]=3+[tex]\frac{1}{4}[/tex],  3×[tex]\frac{4}{4}[/tex]

1÷[tex]\frac{13}{4}[/tex]

Answers:

Domain:  [tex](-\infty, 5)[/tex]

Range:  [tex][-3, \infty)[/tex]

Both are in interval notation. There's a square bracket next to the -3, and everything else is a curved parenthesis.

===========================================================

Explanation:

The domain is the set of allowed x input values of a function. We have a hole at x = 5, so this value is not allowed in the domain. But we can use anything smaller than this. The domain as an inequality is [tex]x < 5[/tex] which is the same as writing [tex]-\infty < x < 5[/tex] and that directly translates to the interval notation of [tex](-\infty, 5)[/tex]

The curved parenthesis say "exclude this endpoint". The domain is anything between negative infinity to 5, excluding both endpoints.

----------------------

The range is the set of possible y outputs of a function.

The lowest the function goes is at y = -3. The arrow indicates it goes up forever, meaning that the range as an inequality is [tex]y \ge -3[/tex] which is the same as [tex]-3 \le y[/tex] and the same as [tex]-3 \le y < \infty[/tex]

Then that directly turns into the interval notation of [tex][-3, \infty)[/tex]

We have a square bracket at -3 to include this endpoint. We can't ever reach infinity, so we of course can't include this endpoint. Always use parenthesis for either infinity.