The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be 0.000343311 %
What is the probability?Probability is synonymous with possibility. It is concerned with the occurrence of a random event.
Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.
No of failure,n = 7
No of trials,x≥6
A binomial probability is represented as;
[tex]\rm P(x) = nC_x p^z(1-p)^{n-r}[/tex]
Substitute the given data;
[tex]P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}[/tex]
[tex]\rm P(x \geq 6) = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%[/tex]
Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be 0.000343311 %
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Which number has a repeating decimal form?
O A.
[tex] \sqrt{15} [/tex]
OB.
[tex] \frac{11}{25} [/tex]
O C.
[tex] \frac{3}{20} [/tex]
O D.
[tex] \frac{2}{6} [/tex]
Answer:
D. [tex] \frac{2}{6} [/tex]
Step-by-step explanation:
2÷ 6 = 0.33333
As you can see 3 is repeating.
Therefore [tex] \frac{2}{6} [/tex] as repeating decimal form.
Find the length of diagonal BC of ABCD to the nearest hundredth.
The length of BC as shown in the diagram is 6.32units
Calculating distance between two pointsThe formula for calculating the distance between two points is expressed as:
D = √(x2-x1)²+(y2-y1)²
Given the following coordinate points (3, 6) and (5, 0)
Substitute
BC = √(0-6)²+(5-3)²
BC = √(36+4)
BC = √40
BC = 6.32 units
Hence the length of BC as shown in the diagram is 6.32units
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If g(x) is the inverse of f(x), what is the value of f(g(2))?
0-6
O-3
02
O 5
Answer:
2
Step-by-step explanation:
When a function and its inverse are composed, the output is equal the input.
explain please thanks :)
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Which of the following is an example of a quadratic equation?
A. y = 216+6
B. x²-64 = 0
C. y = 4x+6
D. x+10 = 33
Answer: B
Step-by-step explanation:
A quadratic equation has degree 2.
The graph of the function f(x) = (x-3)(x + 1) is shown.
-10-8-6
q
10-
Which describes all of the values for which the graph is
positive and decreasing?
all real values of x where x < -1
all real values of x where x < 1
all real values of x where 1
O all real values of x where x > 3
Answer:
x < -1
Step-by-step explanation:
Draw a parabola (the graph) passing trough two x-intercepts -1 and 3 and open up.
What is the range of the given data set?
Answer:
6
Step-by-step explanation:
21 - 15 = 6
Which of the following is equivalent to the
complex number ;³¹?
Choose 1 answer:
A
B
C
D
1
i
-1
-i
Step-by-step explanation:
[tex] = {i}^{31} [/tex]
[tex] = {i}^{28} \times {i}^{3} [/tex]
[tex] = {( {i}^{4} )}^{7} \times ( {i}^{2} \times i)[/tex]
[tex] = ( {i}^{2} \times {i}^{2} ) {}^{7} \times {i}^{2} \times i[/tex]
[tex] = ( - 1 \times ( - 1)) {}^{7} \times ( - 1) \times i[/tex]
[tex] = {1}^{7} \times ( - i)[/tex]
[tex] = 1 \times ( - i)[/tex]
[tex] = - i[/tex]
The answer is D.
Which expression is equivalent to 7a³ (8a² + a)²-4a³?
Simplify.
[tex]7a³ (8a² + a)²-4a³ \\ \\ 7 {a}^{3}(8 { {a}^{2} + a)(8 {a}^{2} + a )} - 4 {a}^{3} \\ \\ 7 {a}^{3} ( {8a}^{2} (8 {a}^{2} + a ) + a(8 {a}^{2} + a ) - 4 {a}^{3} \\ \\ 7 {a}^{3} (64 {a}^{4} + 8{a}^{3} + 8 {a}^{3} + {a}^{2} ) - 4 {a}^{3} \\ \\ 7 {a}^{3} (64 {a}^{4} + 16 {a}^{3} + {a}^{2} ) - 4 {a}^{3} \\ \\ 448 {a}^{7} + 112 {a}^{6} + 7 {a}^{5} - 4 {a}^{3} \\ \\ {a}^{3} (448 {a}^{4} + 112 {a}^{3} + 7 {a}^{2} - 4).[/tex]
What is the missing reason in the proof?
Given: ∠ABC is a right angle, ∠DBC is a straight angle
Prove: ∠ABC ≅ ∠ABD
Answer: Since they have the some points in common we can just plot them and seeing ang. DBC would just be a straight line and angle ABC would be 90 degrees and half of that angle so they would be equal
Please help asap
What is the domain and range of T
Answer:
Domain = {-3, -2}Range = {-4, -3, 4}Step-by-step explanation:
The domain is the set of x-values, and the range is the set of y-values.
One third of a number less than nine equal to seven
The table gives the average monthly precipitation, in inches, in Seattle, Washington, from January through July, where January is month 1 and July is month 7. How would you describe the relationship between the variables in the data? Select all that apply.
There is a linear association between the month and average monthly precipitation.
There is a nonlinear association between the month and average monthly precipitation.
As the number of months increases, the average monthly precipitation, in inches, increases.
As the number of months increases, the average monthly precipitation, in inches, decreases.
The relationship between the variables in the data will be as the number of months increases, the average monthly precipitation, in inches, decreases. Then the correct option is D.
What is a function?A statement, principle, or policy that creates the link between two variables is known as a function.
The table gives the average monthly precipitation, in inches, in Seattle, Washington, from January through July, where January is month 1 and July is month 7.
Month 1 2 3 4 5 6 7
Average monthly precipitation 5.2 3.9 3.3 2.0 1.6 1.4 0.6
Then the relationship between the variables in the data will be as the number of months increases, the average monthly precipitation, in inches, decreases.
Then the correct option is D.
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please help, performance task: trigonometric identities
The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
How to solve the trigonometric equations?Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)
The equation can be split as follows:
y = 1 - cos(x)
y = 2 - 2sin²(x)
Next, we plot the graph of the above equations (see graph 1)
Under the domain interval (-π, π), the curves of the equations intersect at:
(-π/3, 0.5) and (π/3, 0.5)
Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)
The equation can be split as follows:
y = 4cos⁴(x) - 5cos²(x) + 1
y = o
Next, we plot the graph of the above equations (see graph 2)
Under the domain interval [0, 2π), the curves of the equations intersect at:
(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
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Solve for X
picture below
Describe all of the transformations occurring as the parent function f(x) = x^3 is transformed into g(x) = -0.5(3(x+4))^3 -8
Step-by-step explanation:
The translations of the typical functions are
[tex]y = a(bx + c) + d[/tex]
Where a is the vertical translation,
If a is greater than 1 or less than -1, we have a vertical stretch
If a is between -1 and 1 , we have a vertical compressions or shrink.
If a is negative, we have a negative reflection across the x axis.
If b is greater than 1 or less than -1, we have a horizontal compression or shrink
If b is between -1 and 1, we have a horizontal stretch
If b is negative, we have a reflection about the y axis,
If c is negative, we have a translation to the right c units
If c is positive, we have a translation to the left c units
If d is positive, we have a translation upward d units
If d is negative, we have a translation downward d units.
Here in this problem, our parent function is x^3.
So I would do the following transformations.
Reflect about the x axis Vertical Shrink by a factor of 1/2Horizontal Shrink by a factor of 3Shift to the left 4 unitsShift downward 8 units.In a market survey, 100 traders sell fruits, 40 sell apples, 46 oranges, 50 mangoes. 14 apples and oranges. 15 apples and mangoes, and 10 sell the three fruits. Each of the 100 traders sells at least one of the three fruits. Find the number that sell oranges and mangoes only.
The number of traders that sell oranges and mangoes only are 17.
How to determine the common differenceSince there are three sets, use the formula
n (A∪O∪M) = n(A) + n(O) + n(M) - n(A∩O) -n(O∩M) - n(A∩M) + n(A∩O∩M)
A represents apple traders = 40
O represents orange traders = 46
M represents mangoes traders = 50
A∪O∪M = total traders = 100
A∩O = 14
O∩M = ?
A∩M = 15
A∩O∩M = 10
Substitute values into the formula
100 = 40 + 46 + 50 - 14 - 15 - O∩M + 10
100 = 146 - 29 - O∩M
100 = 117 - O∩M
Make O∩M subject of formula
- O∩M = 100 -117
O∩M = 17 traders
Therefore, the number of traders that sell oranges and mangoes only are 17.
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Which expression is equivalent to
(Q^5)^2
The correct value that equates to this expression is q¹⁰
.
To solve this expression, just:
eliminate the parentheses and multiply the exponents among themselves;[tex] \boxed{ \large \sf (a {}^{n} ) {}^{m} \rightarrow a {}^{n \times m} } \\ \\ [/tex]Resolution[tex]{ = \large \sf (q {}^{5} ) {}^{2} } [/tex]
[tex]{ = \large \sf q {}^{5 \times 2} } [/tex]
[tex] \pink{ \boxed{ = \large \sf q {}^{10} } } \\ [/tex]
Therefore, the answer will be q¹⁰
Answer:
Q¹⁰
Step-by-step explanation:
Given that,
(Q⁵)^2Solution:
Well,there is a law of exponents,which states that:
(a^b)^c = a^bcSame case is here as well.
Just multiply both powers given.
(Q⁵)²5*2 = 10
Q¹⁰Hence, the expression equivalent to (Q⁵)² is (Q)¹⁰
if 13n-6 = 98 what is the value of n
Answer:
n = 8
Step-by-step explanation:
13n-6 = 98
Solution:
13n = 98+613n = 104n = 104/13n = 8Hence the value of n is 8.
13n - 6 = 98
13n = 98 + 6
13n = 104
n = 104/13
n = 8
Z varies directly as x and y, z=6 when x=2 and y=6 find the value of z when x=3 and y=8
Answer:
12
Step-by-step explanation:
Direct Variation. I think it's gonna be like this.
SInce Z is not inversely to y , its varies directly to both.
Then it's,
Z=kxy, where k is constant.
subst. Z=6,x=2 and y=6.
6=k×2×6
6=k×12=12k
6=12k=½
the formula connecting them is
Z=½xy
Z=½×3×8
Z= 1×3×8÷2
Z=24÷2
Z=12.
That's my solution.
(5x-1) -(2-8x) for x = 0.75
What number were both the numerator and denominator multiplied by to arrive at the equivalent fraction? What number were both the numerator and denominator multiplied by to arrive at the equivalent fraction ?
Answer:
Both the numerator and denominator should be multiplied by the same number to arrive at the equivalent fraction.
Step-by-step explanation:
Equivalent fractions = two or more than two fractions are said to be equal if both results the same fraction after simplification.
For example, consider the fraction 1/3
Multiplying numerator and denominator with 2, we get 1/3 × 2/2 = 2/6
Multiplying numerator and denominator with 3, we get 1/3 × 3/3 = 3/9
Multiplying numerator and denominator with 4, we get 1/3 × 4/4 = 4/12
Therefore, we can conclude that,
1/3 = 2/6 = 3/9 = 4/12 these are equivalent fractions.
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Answer: 2 and 6/8
Step-by-step explanation:
The probability distribution for a
random variable x is given in the table.
-10
-5
15
20
Probability
.20
15
.05
.15
Find the probability that x ≥ 5
Answer:
Step-by-step explanation:
Comment
There is only 1 number under probability that is greater than or equal to 5. That number is 15
There are 4 possible answers. Only 1 is successful.
Answer: P(y≥5) = 1/4 or 0.25
how many spherical balls of diameter 15cm can be covered by 40 square metres of material
Answer:
It's very simple: divide the 40 m² area by area of 1 one sphere
[tex] \frac{40 \: m {}^{2} }{3.41 \times 15m {}^{2} } = 565[/tex]
f(x) = 3x + 2
g(x) = x^2 + 1
find gf(x) in the form ax^2 + bx + c
please add an explanation because i’ve seen it being solved i just do not understand some steps
like, where does 12x come from
Answer:
g(f(x)) = 9x² + 12x + 5
Step-by-step explanation:
g(f(x))
= g(3x + 2) ← substitute x = 3x + 2 into g(x)
= (3x + 2)² + 1
to expand (3x + 2)² = (3x + 2)(3x + 2)
each term in the second factor is multiplied by each term in the first factor
3x(3x + 2) + 2(3x + 2) ← distribute both parenthesis
= 9x² + 6x + 6x + 4 ← collect like terms
= 9x² + 12x + 4
then
g(f(x)) = (3x + 2)² + 1 = 9x² + 12x + 4 + 1 = 9x² + 12x + 5
PLEASE HELP ME WITH THIS
Answer:
Vertex
Vertex are the end points of parabola where it opens up
locus are the group of points
latus rectum is the line parallel to it .
HELP! WILL GIVE BRAINLIEST AND 100 POINTS!
A study showed that low-intensity vibration therapy reduces pain levels in patients with fibromyalgia. During each session in the study, vibration pads were placed on the pain site indicated by the patient. Pain reduction was measured through self-reporting after each session.
Another study is being designed to examine whether low-intensity vibration therapy also reduces pain in patients suffering from ruptured disks in the lumbar region of the back. Three hundred male patients are subjects in the new study.
Part A: What is an appropriate design for the new study? Include treatments used, method of treatment assignment, and variables that should be measured. (4 points)
Part B: If the study consisted of 150 male and 150 female patients instead of 300 male patients, would you change the study design? If so, how would you modify your design ? If not, why not? (4 points)
Part C: Could your design be double-blind? Explain. (2 points)
Answer:
Part A: The appropriate design for the study includes;
Treatment used; Chamomile oil treatment
Method of treatment; Application of the chamomile oil to the cervical region of patients experiencing pain due to pinched nerves
Treatment assignment; Treatment should be assigned to patients with pinched nerves
Variables that should be measured; Reduction or relief of pain as reported by the patients
Part B; The study should be administered equally to both male and female as the symptoms can be experienced by both male and female
Part C; The design could be double blind by replacing the chamomile administered by placebo, thereby preventing bias from both researcher and participants in the results of the research.
Step-by-step explanation:
I'm gonna need so help
Answer:
-4 and -6 are the answers
Question 4 (Essay Worth 10 points)
(05.06; 05.07 MC)
A prism and two nets are shown below:
Image of a right triangular prism and 2 nets. The triangle bases have base 4, height 3, and diagonal side 5. The length of the prism from the bases is 8.6. Net A has 3 rectangles in a row. The middle one has sides AC and CD. This middle one has triangle ABC on top and identical triangle below. Net B is the same except that the triangle base ABC is on top of the last rectangle which has sides AC and CD. Units are in inches.
Part A: Which is the correct net for the prism? Explain your answer. (2 points)
Part B: Write the measurements of Sides AB, BC, and CD of the correct net. (4 points)
Part C: What is the surface area of the prism? Show your work. (4 points)
Answer:
115.2 in^2
Step-by-step explanation:
total surface area Stot = 113.2 in2
lateral surface area Slat = 103.2 in2
top surface area Stop = 6 in2
bottom surface area Sbot = 6 in2
A locker combination consists of two nonzero digits, and each combination consists of different digits. Event A is defined as choosing an odd number as the first digit, and event B is defined as choosing an odd number as the second digit.
If a combination is picked at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A. 5/18
B. 4/9
C. 1/2
D. 5/9
The correct answer is option B which is P ( A|B) will be ( 4 / 9 ).
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Given that:-
A locker combination consists of two nonzero digits, and each combination consists of different digits. Event A is defined as choosing an odd number as the first digit, and event B is defined as choosing an odd number as the second digit.The total sample will have 9 numbers
S = { 1,2,3,4,5,6,7,8,9} = 9
Even Number = { 2,4,6,8} = 4
Odd Number = { 1,3,5,7,9} = 5
P ( A ) = ( 4 / 9 )
P ( B ) = ( 5 / 9 )
The probability will be calculated as:-
P( A:B ) = [tex]\dfrac{P(A)\times P(B)}{P(B)}[/tex]
P( A:B ) =[tex]\dfrac{( 5/9 ) ( 4/9 )}{5 / 9 }[/tex]
P( A:B ) = 4 / 9
Therefore the correct answer is option B which is P ( A|B) will be ( 4 / 9 ).
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