Find the exponential equation that passes through the points 0,6 and 2,3.84 in y=ab^x form

Answers

Answer 1

Answer:

y=ab^x

y=6.0.8^x

Step-by-step explanation:

find exponential function by substituting given values into y=ab^x and the solve


Related Questions

Which values are solutions to the inequality below? Check all that apply.

x^2 > 16

A. 4
B. -6
C. -1
D. 5

Answers

Answer:

B. -6 and D. 5

Step-by-step explanation:

x^2 - 16 > 0

y = (x - 4)(x + 4)  > 0

The critical point are x = -4 and x = 4

When x  < -4,   y > 0

When x > 4, y > 0

When -4 < x < 4, y < 0

When x = -4 and x = 4 , y = 0.

So the values that apply are

B. -6 and D. 5

Pre-calc/Trig
Suppose that θ=arcsin(4/6). What is cos(2θ)? (round to 4 decimals)

Answers

Answer:

0.7453

Step-by-step explanation:

[tex]arcsin( \frac{4}{6} ) = 0.7297 \\ cos(0.7297) = 0.7453[/tex]

If a =3 and ab =6 then a²-b² =

Answers

Answer:

5

Step-by-step explanation:

a = 3

ab = 6

so b must be 2

3 squared is 9 and 2 squared is 4

so 9 - 4 is equal to 5

Answer:

Step-by-step explanation:

If a =3 and ab =6 then a²-b² =

a = 3

ab = 6

find b

b = 6:3 = 2

-------------------

3² - 2² =

9 - 4 =

5

Which triangle is possible?
3 ft, 4ft, and 5ft 4yd, 5ft, and 10yd
3 ft, 3 ft, and 7 ft.
4 in, 4 in, and 8 in

Answers

Answer:

  (a)  3 ft, 4 ft, 5 ft

Step-by-step explanation:

The triangle inequality requires the sum of the two short sides exceed the long side.

__

a) 3 ft + 4 ft = 7 ft > 5 ft . . . . . triangle is possible

b) 4 yd + 1 2/3 yd = 5 2/3 yd < 10 yd . . . . not a possible triangle

c) 3 ft + 3 ft = 6 ft < 7 ft . . . . not a possible triangle

d) 4 in + 4 in = 8 in . . . . not a possible triangle (not greater than 8 in)

__

The first set of side lengths can form a triangle: 3 ft, 4 ft, 5 ft.

Ted says that the triangle below cannot be classified because all sides are different lengths. Is Ted correct? Explain why or why not.

Answers

Answer:

Ted is wrong

The triangle is a right triangle because of the right 90° angle formed at the bottom.

can someone help me I pay you £50

Answers

Answer:

1,-1  1,-3 6,1

Step-by-step explanation:

keep the eruos

Calculate the volume of the right rectangular prism shown.

Edulastic Question

Answers

since we have the area of the front side, to get its volume we can simple get the product of the area and the length, let's firstly change the mixed fractions to improper fractions.

[tex]\stackrel{mixed}{23\frac{2}{3}}\implies \cfrac{23\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{71}{3}} ~\hfill \stackrel{mixed}{4\frac{7}{8}}\implies \cfrac{4\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{39}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{71}{3}\cdot \cfrac{39}{8}\implies \cfrac{71}{8}\cdot \cfrac{39}{3}\implies \cfrac{71}{8}\cdot 13\implies \cfrac{923}{8}\implies 115\frac{3}{8}~in^3[/tex]

if the box is to be made out of wood that costs $4 per square foot, which of your designs would be less expensive to produce? Explain.

Answers

The second box is less expensive to make since it has a smaller surface area and hence requires less wood to construct the sides.

What is a cuboid?

It is defined as the six-faced shape, a type of hexahedron in geometry.

It is a three-dimensional shape.

Here some data is not given, so we are assuming the volume of the box is 24 cubic feet.

If the volume is 24 cubic feet, the box's three dimensions must multiply to equal 24.

We can make two designs:

2 × 2 × 6 and 2 × 3 × 4.

Now, finding the surface area for each design.

First box

SA = 2wl + 2wh + 2hl

SA = 2×2×2 + 2×2×6 + 2×2×6

SA = 56 square feet

Second box

SA = 2×2×3 + 2×2×4 + 2×3×4

SA = 52 square feet

At $4 per square foot

For 56 ft², the price is $224

For 52 ft², the price is $208

Thus, the second box is less expensive to make since it has a smaller surface area and hence requires less wood to construct the sides.

Learn more about the cuboid here:

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PLEAZE HELP WILL MARK BRAINLIEST!

Answers

Answer:

B: π/6

Step-by-step explanation:

A: 0

B: π / 6

C: π / 4

D: π / 3

E: π / 2

F: π

G: 3π / 2

Here is a complete unit circle...

NO LINKS!! Please help me with these graphs. Part 1​

Answers

Problem 9

The instructions aren't stated anywhere, but I'm assuming your teacher wants you to find the equation of each parabola.

The vertex here is (h,k) = (-6,-4) which you have correctly determined.

This means

[tex]y = a(x-h)^2 + k\\\\y = a(x-(-6))^2 +(-4)\\\\y = a(x+6)^2 - 4\\\\[/tex]

Next we plug in one of the other points on the parabola. We cannot pick the vertex again. Let's pick the point (-4,0) which is one of the x intercepts. We'll do this to solve for 'a'

[tex]y = a(x+6)^2 - 4\\\\0 = a(-4+6)^2 - 4\\\\0 = a(2)^2 - 4\\\\0 = a(4) - 4\\\\0 = 4a-4\\\\4a-4 = 0\\\\4a = 4\\\\a = 4/4\\\\a = 1\\\\[/tex]

This means

[tex]y = a(x+6)^2 - 4\\\\y = 1(x+6)^2 - 4\\\\y = (x+6)^2 - 4\\\\[/tex]

represents the equation of the parabola in vertex form.

Answer: [tex]y = (x+6)^2 - 4\\\\[/tex]

========================================================

Problem 10

The vertex is (h,k) = (-2,-6)

So,

[tex]y = a(x-h)^2 + k\\\\y = a(x-(-2))^2 + (-6)\\\\y = a(x+2)^2 - 6\\\\[/tex]

Now plug in another point on the parabola like (-1,-8) and solve for 'a'

[tex]y = a(x+2)^2 - 6\\\\-8 = a(-1+2)^2 - 6\\\\-8 = a(1)^2 - 6\\\\-8 = a(1) - 6\\\\a-6 = -8\\\\a = -8+6\\\\a = -2\\\\[/tex]

Answer:  [tex]y = -2(x+2)^2 - 6\\\\[/tex]

For each equation, you could optionally expand things out to get it into y = ax^2+bx+c form, but I think it's fine to leave it as vertex form.

Answer:

[tex]\textsf{9)} \quad y=(x+6)^2-4[/tex]

[tex]\textsf{10)} \quad y=-2(x+2)^2-6[/tex]

Step-by-step explanation:

Vertex form of a parabola:  

[tex]y=a(x-h)^2+k[/tex]  where (h, k) is the vertex

Question 9

From inspection of the graph, the vertex is (-6, -4)

[tex]\implies y=a(x+6)^2-4[/tex]

To find [tex]a[/tex], substitute the coordinates of a point on the curve into the equation.

Using point (-4, 0):

[tex]\implies a(-4+6)^2-4=0[/tex]

[tex]\implies a(2)^2-4=0[/tex]

[tex]\implies 4a=4[/tex]

[tex]\implies a=1[/tex]

Therefore, the equation of the parabola in vertex form is:

[tex]y=(x+6)^2-4[/tex]

Question 10

From inspection of the graph, the vertex is (-2, -6)

[tex]\implies y=a(x+2)^2-6[/tex]

To find [tex]a[/tex], substitute the coordinates of a point on the curve into the equation.

Using point (-1, -8):

[tex]\implies a(-1+2)^2-6=-8[/tex]

[tex]\implies a(1)^2-6=-8[/tex]

[tex]\implies a-6=-8[/tex]

[tex]\implies a=-2[/tex]

Therefore, the equation of the parabola in vertex form is:

[tex]\implies y=-2(x+2)^2-6[/tex]

Help! Explain please I need to know I have a test tomorrow!

Answers

hey there!

The given expression is [tex] 25x^{2}-49y^{2}[/tex]

This can be written as [tex](5x)^{2}-(7y)^{2}[/tex]

This is in the form of [tex]a^{2}-b^{2}[/tex]

This can be written in form of (a+b)(a-b)

So now our answer is (5x-7y)(5x+7y)

Hope it helps you dear!
Have a good day <3
given:

[tex]25 {x}^{2} - 49 {y}^{2} [/tex]

solution:

[tex] {a}^{2} - {b}^{2} = (a + b)(a - b)[/tex]

[tex]a = 5x[/tex]

[tex]b = 7y[/tex]

[tex]25 {x}^{2} - 49 {y}^{2} [/tex]

[tex] = (5x - 7y) {}^{2} [/tex]

[tex] = (5x - 7y)(5x + 7y)[/tex]

hence, the correct answer is option B

Which pair of angles are coterminal?

Answers

Answer:

5 pi / 9   &    23 pi / 9

Step-by-step explanation:

adding or subtracting multiples of   2pi are coterminal

   2pi =   18pi/9

5 pi / 9   +  18pi/9 = 23 pi/9


I need help, Asap!’

Answers

Answer:

so on the bottom you will see an x and on the left side you will see an y, for 1,4 the 1 will be on the x and the 4, just go up to the four for 2,8 on the x you will go on two on the bottom, for y you will go up to the 8, for 4,16 the x is four and you will go up to 16, for 5,20 the x will be 5 and then go up to 20. I really hope that this helped

Step-by-step explanation:

HELPPPPPPP SO CONFUSED

Answers

Answer:

x = 80

Step-by-step explanation:

The diagram shows that arc AB is 80 degrees, and the measure of an arc defined as being equal to the central angle(the minor angle of the arc). Because the arc AB is 80, the central angle x is 80 degrees as well. Although if point O wasn't at the center of the circle, x might not be 80.

A town population is 50,000 in 2018. The population has been growing at a rate of 3.7% each year. What is the estimated population of 2025?

Answers

Answer:

The formula for exponential growth is: Total = Starting value(1 + rate)^time

2018 to 2025 is 7 years:

Step-by-step explanation:

Total = 50,000(1+0.037)^7

Total = 50,000(1.037)^7

Total = 64,479 -(Answer)

The estimándose did did did did did did did did JD I’d did di sis 20

If 1ml of water fills 1 cubic centimeter of space, how many ml of water are needed to fill each tank?

Answers

Answer:

Tank Volume/1 cubic centimeter.

Step-by-step explanation:

We dont know how big the tank is.

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Answers

2x+20=58 then your would subtract 20 from 58 which would turn into 38 and your would divide 38/2 it would be 19 so the answer is x=19 if I’m not mistaken this is correct hope this helps

find the surface area of this prism
3cm
7cm
5cm

Answers

Answer:

105cm

Step-by-step explanation:

please click crown below my answer.

Please Answer The Following Maths Question: "Could you change $2 for me for the parking meter?" inquired the young woman.


"Sure," I replied, knowing I had more than $2 change in my pocket.


In actual fact however, although I did have more than $2 in change, I could not give the woman $2.


What is the largest amount of change I could have in my pocket without being able to give $2 exactly?

Answers

5$ is the highest amount of change you can give without it being 2$ exactly

Answer:

$5

Step-by-step explanation:

Conditions

More than $2Not exactly $2

In the currency bills are printed as : $1, $5, $10, $20, $50, $100

Hence, the largest amount he could give the woman is $5

please answer this question


Answers

Answer:

[tex]\dfrac{dy}{dx}=\cot x+\dfrac{1}{x}[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{6 cm}\underline{Product\:Rule}\\\\$\dfrac{d}{dx}[f(x)g(x)]=f(x)g'(x)+f'(x)g(x)$\\\\\\\underline{Chain\:Rule}\\\\$\dfrac{dy}{dx}=\dfrac{dy}{du} \times \dfrac{du}{dx}$\\\end{minipage}}[/tex]

[tex]\textsf{Given}:y=\log (x \sin x)[/tex]

[tex]\textsf{Let }u=x \sin x \implies y=\log(u)[/tex]

Using the product rule, differentiate y with respect to [tex]u[/tex]:

[tex]\textsf{If }y=\log(u) \implies \dfrac{dy}{du}=\dfrac{1}{u}\implies \dfrac{dy}{du}=\dfrac{1}{x \sin x}[/tex]

----------------------------------------------------------------------------------------

Differentiate [tex]u=x \sin x[/tex] with respect to x using the product rule:

[tex]\implies \textsf{Let }f(x)=x \implies f'(x)=1[/tex]

[tex]\implies \textsf{Let }g(x)=\sin x \implies g'(x)=\cos x[/tex]

[tex]\implies \dfrac{du}{dx}=x \cos x + \sin x[/tex]

----------------------------------------------------------------------------------------

Use the chain rule to differentiate y with respect to x:

[tex]\implies \dfrac{dy}{dx}=\dfrac{dy}{du} \times \dfrac{du}{dx}[/tex]

[tex]\implies \dfrac{dy}{dx}=\dfrac{1}{x \sin x} \times (x \cos x + \sin x)[/tex]

[tex]\implies \dfrac{dy}{dx}=\dfrac{x \cos x + \sin x}{x \sin x}[/tex]

[tex]\implies \dfrac{dy}{dx}=\dfrac{x \cos x}{x \sin x}+\dfrac{\sin x}{x \sin x}[/tex]

[tex]\implies \dfrac{dy}{dx}=\cot x+\dfrac{1}{x}[/tex]

Answer:

[tex]\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{1}{x\ln 10} + \dfrac{\cot x}{\ln 10}}[/tex]

Step-by-step explanation:

Given:

[tex]\displaystyle \large{y=\log (x\sin x)}[/tex]

Recall the (common) logarithmic differentiation & chain rules:

[tex]\displaystyle \large{\dfrac{d}{dx}[\log (u)] = \dfrac{u'}{u\ln 10}}[/tex]

Let [tex]\displaystyle \large{u=x\sin x}[/tex] then:

[tex]\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{(x\sin x)'}{x\sin x \ln 10}}[/tex]

Recall product rules:

[tex]\displaystyle \large{[f(x)g(x)]' = f'(x)g(x)+f(x)g'(x)}[/tex]

Hence:

[tex]\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{(x)'\sin x + x(\sin x)'}{x\sin x \ln 10}}\\\\\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{\sin x + x\cos x}{x\sin x \ln 10}}\\\\\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{\sin x}{x \sin x \ln 10} + \dfrac{x \cos x}{x\sin x \ln 10}}\\\\\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{1}{x\ln 10} + \dfrac{\cot x}{\ln 10}}[/tex]

From above, recall that:

[tex]\displaystyle \large{\dfrac{d}{dx}(\sin x) = \cos x}\\\\\displaystyle \large{\dfrac{A\pm B}{C} = \dfrac{A}{C} \pm \dfrac{B}{C}}\\\\\displaystyle \large{\dfrac{\cos x}{\sin x} =\cot x}[/tex]

Hence, the answer is:

[tex]\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{1}{x\ln 10} + \dfrac{\cot x}{\ln 10}}[/tex]

A scale model of a skateboarding ramp is a right triangular prism as shown in the
figure.

In the actual ramp, the triangular base has a height of 15 in.
What is the VOLUME of the actual ramp?

Please explain in detail:)

Answers

The volume of the actual ramp including the underside is 16 cubic ft.

The height of the actual ramp = 15 feet  

The height of the model = 6 cm

What is the volume of a right triangular prism?

A right triangular prism is a 3-dimensional triangle with two congruent triangular faces and 3 rectangular faces that connect the triangular.

The volume of a right triangular prism = ( height× Base Area)

Scale factor = 1.2 feet / 6 cm = 0.2 ft/cm

Actual base = 16 cm × 0.2 ft/cm = 3.2 ft

The volume of a right triangular prism = ( height× Base Area)

= [tex]5 \times 3.2\\ 16.0[/tex]

Hence, the volume of the actual ramp including the underside is 16 cubic ft.

Learn more about the volume here:

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PLEASE HELP ME WITH THIS! IM BEHIND

Answers

Answer:40

Step-by-step explanation: i may be wrong but i subtracted 136 from 95 and i got 40 im sorry if it is wrong

The pattern 2, 5, 17, ________, ________ follows the rule multiply by 4, then subtract 3. What are the next two terms?

Group of answer choices

68, 260

68, 257

Answers

Answer:

None of the answer choices.

Step-by-step explanation:

The pattern to this problem is multiply by 4, and subtract 3. However when doing 17 * 4, you get 68. Look how both of the answer chouces start with 68, and we haven't even subtracted 3 yet. This shows that the answer choices are wrong.

Correct Answer: 65, 257

The answer: ———————> 68, 257

3 to the 2nd power plus 2 to the 3rd power

Answers

Answer:

17

Step-by-step explanation:

[tex]3^2=3\cdot3=9\\\\2^3=2\cdot2\cdot2=8\\\\3^2+2^3=9+8=17[/tex]

Answer:

17

Step-by-step explanation:

Solving

3² + 2³(3 × 3) + (2 × 2 × 2)9 + 817

PLS PLS HELP HELP ME ITS EASY ITS FREE PONTS LOL PLS PLS HELP HELP ME ITS EASY ITS FREE PONTS LOL PLS PLS HELP HELP ME ITS EASY ITS FREE PONTS LOL PLS PLS HELP HELP ME ITS EASY ITS FREE PONTS LOL

Answers

Answer:

37

Step-by-step explanation:

90 - 53 = 37

Answer:

x = 37°

Step-by-step explanation:

Given angle AOB = 53°, angle AOC = 90°

To find x°

From above figure, angle AOC = angle AOB + angle BOC

Now angle AOB = 53°, angle AOC = 90°

90° = 53° + angle BOC

=> angle BOC = x° = 90 - 53

=> x° = 37°

HOPE THIS HELPS AND HAVE A NICE DAY <3

Simplify: 5 3/4 divide5 5/9
by substituting a numerical value for a in the expression.

Answers

Answer: 8

Step-by-step explanation: divion

Please show your work and I'll mark brainliest if you do! Thank you :)

Answers

Answer:

what r u supposed to do with that perimeter or area pls state question well

Pls help me!!!!!!!!!!

Answers

Answer:

72 degrees

Step-by-step explanation:

180-108=72

Hope this helps!

Answer:

Step-by-step explanation:

m<2 + 108 = 180

m<2 = 72

What’s the volume for this problem?

Answers

Answer:

2144.66

Step-by-step explanation:

Answer:

2144.93yd^3

Step-by-step explanation:

[tex]volume \: of \: a \: spher = \frac{4}{3} \pi \: r {3}^{} \\ radius \: r = \frac{16}{2} = 8yd \\ volume = \frac{4}{3} \times 3.142 \times 8 {}^{3} \\ volume = \frac{6434.816}{3} = 2144.93yd {}^{3} [/tex]

2 + 10n + 9 + 6n


Explain please

Answers

Answer:

11 + 16n

Step-by-step explanation:

Collect the like terms

2 + 9 = 11
10n + 6n = 16n

11 + 16n is the final answer, and cannot be simplified further

Answer:

16n + 11

Step-by-step explanation:

Simpifying

Combine like terms (n and number terms)

2 + 10n + 9 + 6n10n + 6n + 2 + 916n + 11
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