Find the equivalent resistance of this circuit. ​

Answer: Stars are formed in dust clouds and are found in most galaxies.

Explanation:

Answer: Stars form inside relatively dense concentrations of interstellar gas and dust known as molecular clouds.

Explanation:

Answer:

the above picture might help

Answer:

B

Explanation:

Density ( as shown) = g/ml

   density =  5 g / 2.5 ml =  2 g/ml

The magnitude of the gravitational force exerted on the satellite by the planet  will be F = 11970.1 N

The gravitational force is a force that attracts any two objects with mass.It is directly proportional to the masses and inverse of the distance between the two objects.

It is given that,

Mass of the satellite, m = 2400 kg

Speed of the satellite, v = 6670 m/s

Radius of the circular path,

Let F is the magnitude of the gravitational force exerted on the satellite by the planet. The centripetal force is equal to the gravitational force. It is equal to :

[tex]F=\dfrac{mv^2}{r}[/tex]

[tex]F=\dfrac{2400\times (6670)^2}{8.92\times 10^6}[/tex]

F = 11970.1 N

So, the magnitude of the gravitational force exerted on the satellite by the planet is 11970.1 N. Hence, this is the required solution.

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Answer:

Since the resistors are in series, all of them carry the same current I.

if the potential drop across the 12 Ω is 4 V

I = 4 / 12 = 1/3 = .333 amp

a)  25 Ω * .333 amp = 8.33 V

b)  62 V * .333 amp = 20.7 V

Answer:

The answer is velocity.

Explanation:

Answer:

if it were submerged 1000 m in the ocean it would be crushed because of the differences of the air and water pressure.

If it were taken 10,000 m (higher than Mt Everest) it would explode due to the differences of external and internal air pressures.

Answer:

51°

Explanation:

dark fringe equation = dsinθ = (m + 1/2)λ

sinθ = [(m + 1/2)λ]d

sinθ1 = [(m + 1/2)λ]d

sinθ1/sinθ =  [(m + 1/2)(λ/d)] / [[(m + 1/2)(λ/d)] = [(m + 1/2)] / [(m + 1/2)]

sinθ1 = [(m + 1/2)] / [(m + 1/2)] (sinθ)

sinθ1 = [1+1/2]/[0+1/2] (sin15)

sinθ1 = 3sin15

sinθ1 = 0.77645

θ1 = sin^-1( 0.77645)

θ1 = 50.94° = 51°

The dark fringe for m = 0 in a young's double-slit experiment is located at an angle. The angle that locates the dark fringe for m = 1 is  51°.

When light passes through a slit , it produces a spectrum which can be seen on the screen kept a distance in form of fringes of different intensity. The fringe with intensity zero is called the dark fringe.

Given is the angle θ = 15°

The equation for the dark fringe is

d sinθ = (m + 1/2)λ

For m= 0 and m=1, the ratio of the sines  is

sinθ₁/sinθ₀ = [(m + 1/2)] / [(m + 1/2)]

Rearranging for sinθ₁, we have

sinθ₁ = [(m + 1/2)] / [(m + 1/2)] (sinθ₀)

Substituting the values into the equation and solving for θ₁

sinθ₁ = [1+1/2]/[0+1/2] (sin15)

θ₁ = 51°

Thus, the angle that locates the dark fringe fro m = 1 is 51°.

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If we were to illuminate them only with light from the balmer transition considered above, the solar panels would not produce current.

Solar panels are used to produce energy according to the principle of the photoelectric effect. When the solar panel is hit with light in the balmer series, the light is reflect hence no current is produced.

Therefore, If we were to illuminate them only with light from the balmer transition considered above, the solar panels would not produce current.

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More work is done when one man lifts the weight using a pulley. Option C is correct.

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtained efficiency of  forces in levers and pulley.

It is an effective way of amplify the force in simple machines like lever  The theoretical mechanical advantage is defined as the ratio of the force responsible for the useful work in the system  to the applied force.

More work is done when one man lifts the weight using a pulley. With the pulley, the mechanical advantage is increasing.

Hence, option C is correct.

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Answer:

The Fulcrum is the pivot in the middle and the Force is applied with your hand at the end. The item being cut has a “Shear” force applied to it by the blades.

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Compared to the electric field energy density at b, the electric field energy density at a is large by a factor of 16.

The energy of a particle by virtue of its position.

The potential at B = Vb =V

Vb = 1/4π∈₀ x e/r₁ = ke/r₁

V =ke/r₁

and r₁ = ke /V

The potential at A = Va = 2V

2V = ke/r₂

r₂ = ke/2V

The electric field at point B. Eb = ke/r₁²

Substitute the value of r₁, we get

Eb = V²/ke

The electric field at point A , Ea = ke /r₂²

Substitute the value of r₂, we get

Ea = 4V²/ke

The electric field energy density at point A and B,

Ua  = 1/2 ∈Ea²

Ub = 1/2 ∈Eb²

electric field energy density is proportional to the square of electric field at the particular point.

Ua/Ub =(Ea/Eb)²

Substitute the values, we get

Ua/Ub = 16

Thus, compared to the electric field energy density at b, the electric field energy density at a is large by a factor of 16.

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The equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

The equilibrium constant in a chemical reaction is the reaction quotient when the chemical reaction is at equilibrium constant.

The equilibrium constant for the for reaction at 25 °c given in the problem as,

[tex]2A\rightleftharpoons B+C, K_1=1.0 \\2B\rightleftharpoons C+D, K_2=16 \\2C+D\rightleftharpoons 2P, K_3=25 \\[/tex]

Now, the reaction for which the equilibrium constant at 25 °c has to be find out is,

[tex]P\rightleftharpoons A+\dfrac{1}{2}B[/tex]

[tex]K_4=\sqrt{\dfrac{1}{K_1}+\dfrac{1}{K_2}+\dfrac{1}{K_3}}\\K_4=\sqrt{\dfrac{1}{25}+\dfrac{1}{16}+\dfrac{1}{1}}\\K_4=\dfrac{1}{20}[/tex]

Thus, the equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

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The maximum temperature is -320.44 and the minimum temperature is -333.22.

In this case, there was an increase of 50 °C in the temperature of this object. We say that the temperature variation suffered by the body was 50°C, and this can be determined mathematically through the difference between the final value and the initial temperature value (60 – 10 = 50).

In this case, we have:

[tex]x+ 333.22 = 12.78\\x=12.78-333.22\\x=-320.44[/tex]

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-320.44 is the maximum temperature at which nitrogen is a liquid.

-346 is the minimum temperature at which nitrogen is a liquid

Answer:

8 V

Explanation:

Equivalent R

Finding Current

Finding V

Answer:

See below ~

Explanation:

The fact that water is attracted to itself, a property called cohesion, leads to another important property, the liquid form of water is more dense than the solid form. As water solidifies into ice, the molecules must move apart in order to fit in to a crystal lattice structure, causing water to expand as it freezes. Because of this, ice floats and water sinks, which keeps the oceans liquid and prevents them from freezing solid from the bottom up.

Answer:

Option 2

Explanation:

The theory supported by the statement : "Mountain ranges often appear on the edges of continents.", is that :

Answer: b. Mountain ranges were formed when continents collided.

Explanation:

The most effective insulating material is polystyrene.

The material which isolates the body and doesn't allow heat and mass to flow out of the control system.

The insulating material should have the lowest thermal conductivity.

Polystyrene foam has low thermal conductivity which makes it a great insulator to heat.

Aluminum foil can be an effective insulating material because it doesn't flow heat out into the environment.

Cotton wool is effective, but not it is not fire resistant.

Thus, the best effective insulating material is polystyrene.

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A moonbow is occurred due to reflection and refraction of moonlight.

A moonbow also known as a lunar rainbow. It is the phenomenon occurs when the moonlight is refracted through water droplets in the air. The amount of light available from the full moon is very less than that produced by the sun. So, the moonbows are the type of rainbow, produced by the moonlight refraction and reflection through water droplets. Moonbows are fainter than rainbows.

Thus, a moonbow is occurred due to reflection and refraction of moonlight.

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The electric field strength created by a charge decreases with increasing distance from the charge. The relationship between the electric field strength (E) and the distance (r) from the charge is given by the inverse square law:

E ∝ 1/r^2

Let's consider the given scenario:

At a distance of 40 cm (0.4 m) from the charge, the electric field strength is measured as 8 N/C.

We want to determine the electric field strength at a distance of 80 cm (0.8 m) from the charge when the charge is reduced to 1/2 Q.

First, we can set up a proportionality based on the inverse square law:

(E1)/(E2) = (r2^2)/(r1^2)

Substituting the given values:

8/E2 = (0.8^2)/(0.4^2)

Simplifying the equation:

E2 = 8 * (0.4^2)/(0.8^2)

E2 = 8 * 0.16/0.64

E2 = 2 N/C

Therefore, at a distance of 80 cm from the charge, when the charge is reduced to 1/2 Q, the electric field strength would be 2 N/C.

The strength of an electric field depends on the magnitude of the charge creating the field and the distance from the charge. In this case, since the charge is reduced to 1/2 Q, the electric field strength is also halved.

Additionally, as we move twice as far away from the charge (from 40 cm to 80 cm), the electric field strength decreases according to the inverse square law. As a result, the electric field strength is reduced to 2 N/C at a distance of 80 cm.

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Answer:

the answer is equal to visible light , ultraviolet, x-rays, gamma rayst

The sequence of types of electromagnetic radiation is arranged from that with the least to the most energetic photons will be visible light , ultraviolet, x-rays, gamma rays.

Electromagnetic radiation is a type of energy that is transmitted in incident photons as both magnetic and electric waves.

Electromagnetic radiation has a spectrum with varying wavelengths and frequencies, which gives it different properties.

Electromagnetic radiation is a type of energy that travels in packets of energy called photons as both electrical and magnetic waves.

Wave-particle duality is the name given to this phenomenon. This is a notion that defines how a wave behaves whether it behaves like particles, waves, or both particles and waves.

Hence the sequence of types of electromagnetic radiation is arranged from that with the least to the most energetic photons will be  visible light , ultraviolet, x-rays, gamma rays.

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Answer:

a. electrons

Explanation:

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Answer:

0.5V

Explanation:

The formula for the potential difference is V=W/Q where W is the work and Q is the charge.

10/5 = 0.5

Hope this helped!

Answer:

   Find the original location of the decimal.

   Determine if the number will be positive or negative.

   Move the decimal point until it creates a number between one and ten.

   Count how many times you moved the decimal.

Explanation:

The energy of an electron in a rigid box when it is in the next higher  state is 19.6 eV

The energy carried by the electron when jumping from one energy level to another is called as electron energy.

Energy in the nth level for a rigid box of length L and mass of electron m is represented as

[tex]E_{n} = \dfrac{n^2{h^{2} } }{8mL^{2} }[/tex]

As the energy is proportional to n².

[tex]\dfrac{E_{n+1} }{E_{n} } =(\dfrac{n+1}{n} )^{2}[/tex]

Substitute the value 3 for n in the above equation. So, we have the energy of an electron is

E₄ =  19.6 eV

Thus, energy of electron in a rigid box when it is in the next higher state is 19.6 eV.

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Answer:

468.42N

Explanation:

Here,

Work done(W)=1780J

Displacement(s)=3.8m

As we have,

Work=Force×displacement

Now,

[tex]\hookrightarrow 1780J=F\times3.8m\\\\\hookrightarrow \frac{1780J}{3.8m} =F\\\\\hookrightarrow F=468.42N[/tex]

The electric potential at a distance from a nucleus of charge 50e is 144 Volts.

The potential is the work done by the test charge to move it from infinity to a particular point.

The potential is given by the relation

V = kQ / r

The distance of a point from the nucleus is 5.0 × 10⁻¹⁰ m and the charge on the nucleus is 50 e = 50 × 1.9 × 10⁻¹⁹ C.

k = 9 × 10⁹ kg-m²/s²-C²

Here, Q is the charge, r is the distance and k is the constant.

Substituting the value into the equation and solving, we get

V = 144 Volts

Thus, the potential at a distance from a nucleus of charge 50e is 144 Volts.

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