find the empirical formula of a compound containing 32.0g of bromine and 4.9 of magnesium.

but its c because it dealing with power

Explanation:

Answer:

The answer of this question is 3

Answer:

The molecules tend to speed up and move faster throughout the substance once thermal energy increases. This is evident whenever we heat up water as its molecules tend to move faster throughout the water as thermal energy tends to increase

Hope this helps!

Answer:

covalent is the bonding that occurs in H2O  

Explanation:

Answer:

The correct answer is B. From the chemical reaction, the reactants are carbon dioxide and water. Reactants are the substances that take part in the chemical reaction which, as a result, produces new substances called the products

Explanation:

Hope it helps

Answer:

I would tell him to open the tent in order to breathe frsh air.

Explanation:

Even if propane is not ignited, the buildup of the gas can be deadly due to inhalation. Breathing the gas can cause hypoxia, which is a form of oxygen deprivation that can lead to death. Hence you shouldnt use propane indoors.

Answer:

The answer is 0.073

Explanation:

Final step: 0.73 x 10^-1

Answer:

a. The limiting reactant is Ca(OH)₂

b. The theoretical yield of CaCl₂ is approximately 621.488 grams

c. The percentage yield of CaCl₂ is approximately 47.06%

Explanation:

a. The given chemical reaction is presented as follows;

Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

Therefore;

One mole of Ca(OH)₂ reacts with two moles of HCl to produce one mole of CaCl₂ and two moles of water H₂O

The mass of HCl in an experiment, m₁ = 229.70 g

The mass of Ca(OH)₂ in an experiment, m₂ = 207.48 g

The molar mass of HCl, MM₁ = 36.458 g/mol

The molar mass of Ca(OH)₂, MM₂ =74.093 g/mol

The number of moles of HCl, present, n₁ = m₁/MM₁

∴ n₁ = m₁/MM₁ = 229.70 g/(36.458 g/mol) ≈ 6.3 moles

The number of moles of Ca(OH)₂, present, n₂ = m₂/MM₂

∴ n₂ = m₂/MM₂ = 207.48 g/(74.093 g/mol) ≈ 2.8 moles

The number of moles of Ca(OH)₂, present, n₂ = 2.8 moles

According the chemical reaction equation the number of moles of HCl the 2.8 moles of Ca(OH)₂ will react with, = 2.8 × 2 moles = 5.6 moles of HCl

Therefore, there is an excess HCl in the reaction and Ca(OH)₂ is the limiting reactant

b. According the chemical reaction equation the number of moles of CaCl₂ produced in he reaction by the 2.8 moles of Ca(OH)₂ = 2.8 × 2 moles = 5.6 moles of CaCl₂

The molar mass of CaCl₂ = 110.98 g/mol

The mass of the 5.6 moles of CaCl₂ = 5.6 moles × 110.98 g/mol ≈ 621.488 grams

The theoretical yield of CaCl₂ ≈ 621.488 grams

c. Given that the actual mass of CaCl₂ produced = 292.5 grams, we have;

The percentage yield of CaCl₂ = The actual yield/(The theoretical yield) × 100

∴ The percentage yield of CaCl₂ = (292.5 g)/(621.488 g) × 100 ≈ 47.0644646397%

The percentage yield of CaCl₂ ≈ 47.06%.

answer:

explanation:

Answer:

c

Explanation:

Answer:

V = 39.38 L

Explanation:

Given that,

No. of moles of H₂, n = 2

Temperature, T = 300 K

Pressure, P = 1.25 atm

We need to find the volume occupied by the gas. We can use the ideal gas law to find it such that,

[tex]PV=nRT[/tex]

Where

R is gas constant, R = 0.08205 L-atm/mol-K

V is volume of the gas

Rearranging the above formula for V. So,

[tex]V=\dfrac{nRT}{P}\\\\V=\dfrac{2\times 0.08205\times 300}{1.25}\\\\V=39.38\ L[/tex]

So, the volume occupied by the gas is 39.38 L.

The volume occupied by this hydrogen gas is equal to 39.408 Liters.

Given the following data:

To determine the volume occupied by this hydrogen gas, we would use the ideal gas law equation;

[tex]V= \frac{nRT}{P}[/tex]

Where;

Substituting the given parameters into the formula, we have;

[tex]V=\frac{2 \times 0.0821 \times 300 }{1.25} \\\\V=\frac{49.26}{1.25}[/tex]

Volume, V = 39.408 Liters.

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Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

Answer:

a. more than the earth pull on the moon sorry if false

Answer:

Is this a general question or is there supposed to be a picture

Explanation:

Answer:

Dirt

mud

rocks

ect.

Explanation:

Answer:

189.6 mL

Explanation:

As per Boyles law when a gas is kept at a constant temperature and mass in a closed container, the volume and pressure vary inversely.

P1V1= P2V2

Here, P1 = 0.79 atm, V1 = 240 ml, P2= 1 atm

therefore, substituting values in above equation we get

0.79×240 = 1×V2

⇒V2 = 189.6 ml

therefore,  its volume at STP (1 atm and 0 oC) = 189.6 ml

Answer:

30 g

Explanation:

In order to convert from moles of CH₃COOH to grams, we need to use its molar mass:

Now we convert moles into grams:

So 0.5 moles of CH₃COOH have a mass of 30 grams.

Answer:

cupro - nickel

if u on its weight its 9.00gms and diameter:23mm

Answer:

Silver

Explanation:

Because when white metal has an illustrious reputation for its use on jewelry and coins, but today, silvers primary use is industrial.

Explanation:

Soap solution is called a mixture because you're combining a ratio of liquid soap and water to make a mixture.

Answer:

d

Explanation:

Answer:

Explanation:.the device controlled the activation as shown by the water holding room temperature for 15 seconds until activation by crushing the pills. The temperature rose 30° over two minutes, showing a measurable exothermic reaction from the Calcium Chloride dissolving in the water. Pour 5mL water in a quart bag Place Thermometer in the bag to make contact Fill two gelatin 000 capsules with 1 gram of Calcium Chloride Place capsules into the bag Wait 15 seconds to crush the capsules while they are submerged in the water Temperatures - 0 Seconds 75° 15 Seconds - Activation 75° 30 Seconds 85° 60 Seconds 95° 90 Seconds 104° 120 Seconds 105° Test #2 For this trial, the variables of the water Calcium Chloride will be increased by the factor of one.

Answer:

CaCl2 + 2AgNO3 = Ca(NO3)2 + 2AgCl

Explanation:

Calcium chloride reacts with silver nitrate to produce calcium nitrate and silver(1) chloride

Answer:

Nuclear decay is also called radioactive decay, and it occurs in a series of sequential reactions until a stable nucleus is reached. Nuclear reactions release much more energy—orders of magnitude more—than exothermic chemical reactions.

Explanation:

Answer:

A monoprotic acid has only one equivalence point in a titration curve while a triprotic acid has three equivalence points.

Explanation:

Monoprotic acids, HA, are acids that are able to donate one proton per molecule during the process of ionization or dissociation as shown below:

HA ----> H⁺ + A⁻

A triprotic acid is a polyproprotic acid, that is acids that can donate more than one proton per molecule during ionization. a triprotic acid can donate three protons per molecule during the process of ionization. The dissociation of a triprotic acid is shown below;

H₃A -----> H₂A⁻ + H⁺

H₂A⁻ ----> HA²⁻ + H⁺

HA²⁻ -----> A³⁻ + H⁺

The value Ka, is known as the acid dissociation constant. It is found by looking at the equilibrium constant for the dissociation of the acid. The higher the Ka, the more the acid dissociates

A titration curve is the plot of the pH of the analyte solution versus the volume of the titrant added as the titration progresses.

In a titration curve in which base is added to acid, the pH rises slowly until the equivalent point at which point the pH remains constant before it begins to rise again on the addition of more base.

In a titration curve of a monoprotic acid, there is only one region in which the equivalence point is obtained corresponding to the point of acid of dissociation of all its protons.

In the titration curve of a triproprotic acid, three equivalent points are obtained corresponding to the point of dissociation of each of three protons of the triprotic acid.

The titration curves are shown below

Answer:

2.1 atm

Explanation:

We are given the following variables to work with:

Initial pressure (P1): 2.5 atm

Initial temperature (T1): 320 K

Final temperature (T2): 273 K

Constant volume: 7.0 L

We are asked to find the final pressure (P2). Since volume is constant, we want to choose a gas law equation that relates initial pressure and temperature to final pressure and temperature. Gay-Lussac's law does this:

[tex]\frac{P_{1}}{T_1} =\frac{P_{2}}{T_2} \\[/tex]

We can rearrange the law algebraically to solve for [tex]P_{2}[/tex].

[tex]{P_{2}} =\frac{(T_2)(P_{1} )}{T_1} \\[/tex]

Substitute your known variables and solve:

[tex]P_2 = \frac{273K(2.5atm)}{320K} = 2.1 atm[/tex]

molecule, cell, tissue, organ, organ system, organism, population, community, ecosystem, biosphere.

Answer:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. ... A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Answer:

1. 1.56 M

2. Water →  0.803

Ethanol → 0.197

3. - 8.07°C

Explanation:

1. To solve this problem, we need benzene's density in order to determine the volume.

We assume the volume of solvent, as the volume of solution

Density for benzene is 0.8786 g/mL.

Density = m/V → V = m/density

Volume = 217 g /0.8786 g/mL = 247 mL

We convert the mass to moles and then, to mmoles

49.3 g . 1mol / 128g . 1000mmol / mol = 385.1 mmol

M = 385.1 mmol / 247mL = 1.56 M

2. We determine moles of each, solute and solvent

94.2 g. 1mol /18g = 5.23 moles of water

58.7 g . 1mol /46g = 1.28 moles of ethanol.

Total moles = 5.23 + 1.28 = 6.51

Mole fraction of water = Moles of water / Total moles

Mole fraction of ethanol = Moles of ethanol / Total moles

Water → 5.23 / 6.51 = 0.803

Ethanol →  1.28 / 6.51 = 0.197

3. Freezing point depression → ΔT = Kf . m . i

i = Van't Hoff factor, ions that are present in the solution.

As the solute is organic, i = 1.

Kf = 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

2.17 mol / 0.5kg = 4.34 m

ΔT = Freezing T° of pure solvent - Freezing T° of solution.

We replace data → 0° - Freezing T° of solution = 4.34m . 1.86°c/m . 1

Freezing T° of solution = - 8.07°C