Answer:
a) [tex] t_{\alpha/2}=\pm 2.447[/tex]
b) [tex] t_{\alpha/2}=\pm 2.718[/tex]
c) [tex] t_{\alpha/2}=\pm 2.779[/tex]
d) [tex] t_{\alpha/2}=\pm 2.650[/tex]
Step-by-step explanation:
Part a
The degrees of freedom are given by:
[tex] df=n-1= 7-1=6[/tex]
The confidence is 95% or 0.95 the significance would be [tex]\alpha=0.05[/tex] and the critical values would be:
[tex] t_{\alpha/2}=\pm 2.447[/tex]
Part b
The degrees of freedom are given by:
[tex] df=n-1=12-1=11[/tex]
The confidence is 98% or 0.98 the significance would be [tex]\alpha=0.02[/tex] and the critical values would be:
[tex] t_{\alpha/2}=\pm 2.718[/tex]
Part c
The degrees of freedom are given by:
[tex] df=n-1=27-1=26[/tex]
The confidence is 99% or 0.99 the significance would be [tex]\alpha=0.01[/tex] and the critical values would be:
[tex] t_{\alpha/2}=\pm 2.779[/tex]
Part d
The degrees of freedom are given by:
[tex] df=n-1=14-1=13[/tex]
The confidence is 98% or 0.98 the significance would be [tex]\alpha=0.02[/tex] and the critical values would be:
[tex] t_{\alpha/2}=\pm 2.650[/tex]
A value of a test statistic defines the upper bounds of a confidence interval, statistical significance in a test statistic is known as the crucial value.
critical value:For part a )
n = 7
Calculating the degrees of freedom [tex]= df = n - 1 = 7 - 1 = 6[/tex]
At [tex]95\%[/tex] the confidence level, the t:
[tex]\alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\frac{\alpha}{ 2} = \frac{0.05}{ 2} = 0.025\\\\t_{\frac{\alpha}{ 2}}\\\\df = t_{0.025,6} = 2.447\\\\[/tex]
The critical value = 2.447
For part b )
n =12
Calculating the degrees of freedom[tex]= df = n - 1 = 12 - 1 = 11[/tex]
At [tex]98\%[/tex] the confidence level , the t:
[tex]\alpha = 1 - 98\% = 1 - 0.98 = 0.02\\\\\frac{\alpha}{ 2}= \frac{0.02}{ 2} = 0.01\\\\t_{\frac{\alpha}{ 2}}\\\\df = t_{0.01,11} =2.718\\\\[/tex]
The critical value =2.718
For part c )
n = 27
Calculating the degrees of freedom [tex]= df = n - 1 = 27 - 1 = 26[/tex]
At [tex]99\%[/tex] the confidence level, the t:
[tex]\alpha = 1 - 99\% = 1 - 0.99 = 0.01\\\\\frac{\alpha}{ 2} = \frac{0.01}{ 2} = 0.005\\\\t_{\frac{\alpha}{ 2}}\\\\df = t_{0.005,26}=2.779\\\\[/tex]
The critical value =2.779
For part d )
n = 14
Calculating the degrees of freedom [tex]= df = n - 1 = 14 - 1 = 13[/tex]
At [tex]98\%[/tex] the confidence level, the t:
[tex]\alpha = 1 - 98\% = 1 - 0.98 = 0.02\\\\\frac{\alpha}{ 2} = \frac{0.02}{ 2} = 0.01\\\\t_{\frac{\alpha}{ 2}} \\\\df = t_{0.01,13} =2.650[/tex]
The critical value =2.650
Find out more about the critical value here:
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Which is the solution to the linear equation? 2/3 x-1/2=1/3+5/6x
Answer: X = -5
Step-by-step explanation:
1) Multiply both sides by 6, which is 4x - 3 = 2 + 5x
2) Move the terms, 4x - 5x = 2 + 3
3) Combine like terms, -x = 5
4) Multiply both sides by -1, x = -5
Determine whether the given limit leads to a determinate or indeterminate form. HINT [See Example 2.]
lim
x→−[infinity] 2/−x + 3
determinate form
indeterminate form
Evaluate the limit if it exists. (If you need to use or –, enter INFINITY or –INFINITY, respectively. If an answer does not exist, enter DNE.)
If the limit does not exist, say why. (If the limit does exist, so state.)
Answer:
The limit leads to a determinate form.
[tex]\lim_{x \to \infty} \frac{2}{-x+3} = 0[/tex]
Step-by-step explanation:
The following are indeterminate forms.
[tex]\frac{0}{0} \ and \ \frac{\infty}{\infty}[/tex]
Given the limit of a function [tex]\lim_{x \to \infty} \frac{2}{-x+3}[/tex], to show if the given limit is determinate or indeterminate form, we will need to substitute the value of -[tex]\infty[/tex] into the function as shown,
[tex]\lim_{x \to \infty} \frac{2}{-x+3}\\= \frac{2}{-(-\infty)+3}\\= \frac{2}{\infty+3}\\= \frac{2}{\infty}\\\\Generally, \ \frac{a}{\infty} =0[/tex]
where a is any constant, therefore [tex]\frac{2}{\infty} = 0[/tex]
Since we are able to get a finite value i.e 0, this shows that the limit does exist and leads to a determinate form
Someone plz help me solved this problem I need help ASAP! Plz help me!!
Answer:
a. $52.20
b. [tex]z=11x+0.09y[/tex]
Step-by-step explanation:
[tex]z=7x+0.11y[/tex]
a.
x = 4
y = 220
[tex]z=(7*4)+(0.11*220)\\z=28+24.2\\z=52.2[/tex]
It costs $52.20 under those conditions.
b.
[tex]z=11x+0.09y[/tex]
If z is still how much it costs in total
If x is how many days rented
If y is how many miles driven
A cylinder has a diameter of 14 centimeters and a volume of 112π cubic centimeters. What is the height in centimeters of the cylinder?
Step-by-step explanation:
we have diameter and volume
and volume function is : v=(3.14)(r^2)h
so : h = 196/112
Consider the following linear programming problem: Max Z = $15x + $20y Subject to: 8x + 5y ≤ 40 0.4x + y ≥ 4 x, y ≥ 0 Determine the values for x and y that will maximize revenue. Given this optimal revenue, what is the amount of slack associated with the first constraint?
Answer:
x=0, y=8
slack is zero
surplus is 4
Step-by-step explanation:
See graph for optimal region
if x=0, y=8
15(0)+20(8)= 160
if x= 0, y=4
15(0) + 20(4)= 80
if x=10/3 , y=8/3
15(10/3) + 20(8/3)= 310/3
Slack
8(0)+ 5(8) ≤ 40
40≤40
slack is zero
0.4(0) + 8 ≥ 4
8 ≥ 4
Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions the population follows a logistic growth model:
P(t) =
d
1 + ke−ct
where c, d, and k are positive constants. For a certain fish population in a small pond d = 1400, k = 13, c = 0.2, and t is measured in years. The fish were introduced into the pond at time t = 0.
(a) How many fish were originally put in the pond?
Correct: Your answer is correct.
fish
(b) Find the population after 10, 20, and 30 years. (Round your answers to the nearest whole number.)
10 years Fish
20 years fish
30 years fish
Answer:
a) 19,600 fishes were originally put in the pond.
b) Population of fishes after 10 years = 3,863
Population of fishes after 20 years = 1,733
Population of fishes after 30 years = 1,403
Step-by-step explanation:
The population follows a logistic model
P(t) = d (1 + ke⁻ᶜᵗ)
For a fish pond,
d = 1400, k = 13, c = 0.2
Inserting the values of these constants
P(t) = 1400 (1 + 13 e⁻⁰•²ᵗ)
a) How many fish were originally put in the pond?
At the start of the whole thing, t = 0
P(t=0) = 1400 (1 + 13 e⁰) = 1400 × 14 = 19,600
Hence, 19,600 fishes were originally put in the pond.
b) Find the population after 10, 20, and 30 years.
P(t) = 1400 (1 + 13 e⁻⁰•²ᵗ)
At t = 10, 0.2t = 0.2 × 10 = 2
P(t=10) = 1400 (1 + 13e⁻²) = 1400 (1 + 1.759) = 3,863.1 = 3,863
At t = 20, 0.2t = 0.2 × 20 = 4
P(t=20) = 1400 (1 + 13e⁻⁴) = 1400 (1 + 0.238) = 1,733.3 = 1,733
At t = 30, 0.2t = 0.2 × 30 = 6
P(t = 30) = 1400 (1 + 13e⁻⁶) = 1400 (1 + 0.00248) = 1,403.47 = 1,403
Hope this Helps!!
In circle Qwith the measure of minor arc PR= 70°, find m/PSR.
Answer: 290 degrees
Step-by-step explanation:
subtract the minor arc's measure from 360 to get the major arc's measure
I keep getting this answer wrong please help!!
Answer:
30 mph50 mphStep-by-step explanation:
They closed the 200 mile distance in 2.5 hours, so the sum of their speeds was ...
(200 mi)/(2.5 h) = 80 mi/h
If s is the speed of the slower one, then ...
s + (s+20) = 80
2s = 60
s = 30
The slower wander's speed was 30 mph; the faster one's was 50 mph.
What is the conjugate
√8-√9
Answer:
[tex]\frac{-1}{(\sqrt{8}+\sqrt{9} )}[/tex]
Answer:
the water here is wet.
Step-by-step explanation:
if sin B=8/17 WHAT IS TAN B?
Answer:
In first quadrant, [tex]\tan B=\frac{8}{15}[/tex]
In second quadrant, [tex]\tan B=\frac{-8}{15}[/tex]
Step-by-step explanation:
Given: [tex]\sin B=\frac{8}{17}[/tex]
To find: [tex]\tan B[/tex]
Solution:
Trigonometry explains the relationship between the sides and the angles of the triangle.
Here,
[tex]\sin B=\frac{8}{17}[/tex]
So, B can be in first or second quadrant as sine is positive both first and second quadrants.
Cosine and tangent are positive in first quadrant but negative in second quadrant.
In first quadrant:
[tex]\cos B=\sqrt{1-\sin ^2B}=\sqrt{1-\left ( \frac{8}{17} \right )^2}=\sqrt{1-\frac{64}{289}}=\sqrt{\frac{225}{289}}=\frac{15}{17}[/tex]
So, [tex]\tan B=\frac{\sin B}{\cos B}=\frac{\frac{8}{17}}{\frac{15}{17}}=\frac{8}{15}[/tex]
In second quadrant:
[tex]\cos B=-\sqrt{1-\sin ^2B}=-\sqrt{1-\left ( \frac{8}{17} \right )^2}=-\sqrt{1-\frac{64}{289}}=-\sqrt{\frac{225}{289}}=\frac{-15}{17}[/tex]
[tex]\tan B=\frac{\sin B}{\cos B}=\frac{\frac{8}{17}}{\frac{-15}{17}}=\frac{-8}{15}[/tex]
wirk out the values of 5x-2y when x=-2 and y = -2
Step-by-step explanation:
5x - 2y
5(-2) - 2(-2)
-10 + 4
= - 6
how much of other chemicals must be evaporated from 400grams of a hand sanitizer that is 24% alcohol to strengthen it to a hand sanitizer that is 30% alcohol? correct your answer to the nearest whole number
Answer:
llolololol
Step-by-step explanation:
Answer:80 grams
Step-by-step explanation:
(4x-4)+(3x-2)+(2x+6)=180
Answer:
x=20
Step-by-step explanation:
Let's solve your equation step-by-step.
4x−4+3x−2+2x+6=180
Step 1: Simplify both sides of the equation.
4x−4+3x−2+2x+6=180
4x+−4+3x+−2+2x+6=180
(4x+3x+2x)+(−4+−2+6)=180(Combine Like Terms)
9x=180
9x=180
Step 2: Divide both sides by 9.
9x
9
=
180
9
x=20
Answer:
x=20
Answer:
x=20
Step-by-step explanation:
im pretty sure this is right. you can't take away 4 from 4 x, so you do it like this: -4+(-2)+6 =0. 4x + 3x + 2x =9x. 180/9 = 20
20 POINTS A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the smaller number. Which equations represent the situation?
A.2 x minus y = negative 6 and 3 x minus y = negative 5
B.2 x minus y = negative 3 and 3 x minus y = negative 5
C.2 x minus y = negative 6 and x minus 3 y = 5
D.2 x minus y = negative 3 and x minus 3 y = 5
Answer:
A.2 x minus y = negative 6 and 3 x minus y = negative 5
Step-by-step explanation:
A ) 2x-y=-6, and 3x-y=-5
Consider the provided information.
First convert the statement into mathematical representation.Consider the smaller number is x and the larger number is y.
y, is equal to twice the sum of a smaller number and 3.
This information can be written as: y=2(x+3)
The larger number is also equal to 5 more than 3 times the smaller number.
This information can be written as: y=5+3x
Answer:
A ) 2x-y=-6, and 3x-y=-5
Step-by-step explanation:
A student's course grade is based on one midterm that counts as 5% of his final grade, one class project that counts as 25% of his final grade, a set of homework assignments that counts as 35% of his final grade, and a final exam that counts as 35% of his final grade. His midterm score is 72, his project score is 83, his homework score is 91, and his final exam score is 74. What is his overall final score? What letter grade did he earn (A, B, C, D, or F)? Assume that a mean of 90 or above is an A, a mean of at least 80 but less than 90 is a B, and so on.His overall final score is nothing.
Answer:
His overal final score is 81.2. His letter grade is a B.
Step-by-step explanation:
Weighed average:
The sum of all values multiplied by it's weight. The weight is a proportion(a value between 0 and 1).
So.
Score of 72 on the midterm, which counts 5%.
Score of 83 on the project score, which counts 25%.
Score of 91 on homework assignments, which counts 35%.
Score of 74 on the final exam, which counts 35%.
His grade is:
G = 72*0.05 + 83*0.25 + 91*0.35 + 74*0.35 = 82.1.
His overal final score is 81.2.
At least 80 but less than 90 is a B
So his letter grade is a B.
Amy filled bags with mixed nuts. The weights of the bags are 1/8 lb, 1/4 lb, 1/8 lb, 1/2 lb, 1/8 lb, 1/4 lb, 1/8lb, 1/2 lb, 1/8 lb, 1/4 lb, 1/8 lb, 1/2 lb, 1/8 lb, 1/8 lb, 1/4 lb, and 1/2 lb.
Part A: Organize the information in a line plot. (on your own paper)
Part B: What is the average weight of the bags? ________ lb
Answer:
(a)See attached
(b)[tex]\text{Average Weight =}\dfrac{1}{4}$ lb[/tex]
Step-by-step explanation:
The weights of the bag are given below:
[tex]1/8 lb, 1/4 lb, 1/8 lb, 1/2 lb, 1/8 lb, 1/4 lb, 1/8lb, 1/2 lb \\1/8 lb, 1/4 lb, 1/8 lb, 1/2 lb, 1/8 lb, 1/8 lb, 1/4 lb, 1/2 lb.[/tex]
When sorted, we have:
[tex]1/8 lb, 1/8 lb, 1/8lb, 1/8 lb, 1/8 lb, 1/8 lb, 1/8 lb, 1/8 lb\\ 1/4 lb,1/4 lb, 1/4 lb, 1/4 lb\\ 1/2 lb, 1/2 lb, 1/2 lb,1/2 lb,[/tex]
8 bags weigh [tex]\frac{1}{8}lb[/tex]4 bags weigh [tex]\frac{1}{4}lb[/tex]4 bags weigh [tex]\frac{1}{2}lb[/tex]Part A
See attached for the Line plot
Part B
Average Weight of the bags
[tex]=\dfrac{(8X\dfrac{1}{8})+ (4X\dfrac{1}{4})+(4X\dfrac{1}{2})}{16} \\=\dfrac{1+1+2}{16}\\=\dfrac{4}{16}\\$Average Weight =\dfrac{1}{4}$ lb[/tex]
Given the functions f(x) = 7x + 13 and g(x) = x + 2, which of the following functions represents f[g(x)] correctly?
Answer:
f[g(x)]= 7x + 27
Step-by-step explanation:
g(x) = x + 2,
f(x) = 7x + 13,
f[g(x)] means you substitute the value of g(x) into the variable of f(x);
Which is 7( x+2) + 13 = 7x +14 +13
= 7x + 27
The total surface area of a right circular cylinder is 84 pie cm square and the altitude is 11 cm .find the radius of the base
Answer:
r = 3cm
Step-by-step explanation:
Use the formula for the surface area of a cylinder and solve to obtain r=3cm
Hence radius of base is 3 cm of right circular cylinder.
What is a right circular cylinder?The cylinder is known as a right circular cylinder when the axis (one of the rectangle's sides) is perpendicular to the radius ((r)). The base and top of the right circular cylinder are both round and parallel to one another. The general formula for the total surface area of a cylinder is T. S. A. =[tex]2\pi rh+2\pi r^{2} .[/tex]
How to solve?Given total surface area of right circular cylinder =84[tex]\pi cm^{2}[/tex]
Using formula for right circular cyinder =.[tex]2\pi rh+2\pi r^{2} .[/tex]=84
and height=11 cm
[tex]2\pi r11+2\pi r^{2} =84.\pi[/tex]
⇒[tex]11r+ r^{2} =84/2[/tex]
⇒[tex]11r+ r^{2} =42[/tex]
⇒[tex]r^{2} +11r-42=0[/tex]
⇒r = [tex]\frac{-11+-\sqrt{11^{2}-4(1)42 } }{2}[/tex]
⇒r=[tex]\frac{-11+-17}{2}[/tex]
⇒r=3,-1
Hence radius of base is 3 cm as value can't be negative .
Learn more about surface area of cylinder https://brainly.com/question/12763699
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Hannah went swimming after she woke up. It took Hannah 15 minutes to get ready to go swimming. She swam for 30 minutes and then sunbathed for 25 minutes. Then she talked on the phone with her friends for 35 minutes. She finished talking to her friends at 9:30 a.m. What time did Hannah wake up?
Find the total minutes:
15 + 30 + 25 + 35 = 105 minutes
This is equal to 1 hour and 45 minutes
Subtract 1 hour and 45 minutes from 9:30
She woke up at 7:45 am
Whats the answer according to the image ?
Defatted blackcurrant seeds (DBS) could be used as a dietary supplement in gluten-free bread but their use may affect texture. A 2011 study measured bread volume (in cm) using independent random samples of bread loaves baked with flours containing different DBS levels. The data showed no skew or outliers. Here are the summary statistics: Flour type z Mean StDev No DBS 00 552 18 5% DBS 00 525 23 15% DBS 00 485 24 We want to know if bread volume is significantly affected by the type of flour used.
Which inference procedure should be used?
1. chi-square for two-way tables
2. one sample or matched-pairs t procedure for a mean
3. z procedure for a proportion
4. two sample t procedure for two means
5. ANOVA for several means
Note: This is the correct table format.
Flour type z Mean StDev
No DBS 00 552 18
5% DBS 00 525 23
15% DBS 00 485 24
Answer:
5. ANOVA for several means
Step-by-step explanation:
In this question, three different means of the data are compared. ANOVA is used for comparing between two or more means to test for differences. It extends the z and t test that are only used for comparing two means.
Since three means are compared, the inference procedure to be used is ANOVA.
At the Northside assembly plant, 30% of the workers were classied as minority, while at the Southside assembly plant, 60% of the workers were classied as minority. When Northside and Southside were closed, all workers transferred to the new Eastside plant to make up its entire work force. If 40% of the 3750 employees at Eastside are minority, then how many employees did Northside and Southside have originally?A. Northside had 2500 employees, and Southside had 1250 employees. B. Northside had 1250 employees, and Southside had 2500 employees. C. Northside had 1000 employees, and Southside had 1100 employees. D. Northside had 1875 employees, and Southside had 1875 employees.
Answer:
A. Northside had 2500 employees, and Southside had 1250 employees.Step-by-step explanation:
At the Northside assembly plant, 30% of the workers were classied as minority, while at the Southside assembly plant, 60% of the workers were classied as minority. When Northside and Southside were closed, all workers transferred to the new Eastside plant to make up its entire work force. If 40% of the 3750 employees at Eastside are minority, then how many employees did Northside and Southside have originally?
The distance traveled varies directly with the time spent in motion wh
If d represents the distance traveled and t represents time, which eq
If you travel 150 miles in 4 hours, what is the constant of variation?
If you continue traveling at a constant speed, how long will it take to
an hour.
about
hours
*
Step-by-step explanation:
The distance traveled varies directly with the time spent in motion. If d is distance and t is time taken. Then,
[tex]d\propto t[/tex]
or
[tex]d=kt[/tex]
k is the constant of variation
If d = 150 miles and t = 4 hours
[tex]k=\dfrac{d}{t}\\\\k=\dfrac{150}{4}\\\\k=37.5\ mph[/tex]
Could someone give me the answer to this please?
Answer:
A = 55.15
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adjacent/ hypotenuse
cos A = 4/7
Take the inverse cos of each side
cos^-1 cos A = cos^-1 (4/7)
A = 55.15009542
To the nearest hundredth
A = 55.15
im awful with dis TwT pls help me it makes me understand better and learn
also:
- surface area
- lateral area
- volume
Answer:
Surface Area: 1,200 units²
Lateral Area: 624 units²
Volume: 960 units³
Step-by-step explanation:
Surface Area is the area of all the faces of the object.
Lateral Area is the area of all the faces of the object NOT INCLUDING the base.
Volume is how much the object can hold.
Using the formula [tex]\frac{1}{2} *b*h[/tex] the area of ONE of the lateral faces of the pyramid is
0.5×24×13=
12×13=
156 units²
156 un² × 4 lateral faces =
624 un²
The lateral surface area is 624 units²
Since the lateral surface area + base is the total surface area:
The base is 24² or 576 units²
624 un²+576 un²=
1,200 units² is the total surface area.
Volume formula for a pyramid is [tex]\frac{1}{3} *b*h[/tex]
We know the base is 576 units².
We don't know the height yet.
We can use the Pythagorean Theorem to find the height of our pyramid.
a²+b²=c²
Half of 24 is 12
12²+b²=13²
144+b²=169
Subtract 144 from both sides.
b²=25
Square root both sides.
b=[tex]\sqrt{25}[/tex]
b=5
The height of our pyramid is 5.
[tex]\frac{1}{3} *576*5=\\\\192*5=\\\\960[/tex]
Our volume for the pyramid is 960 units³
Hope you understand more!
A distribution consists of three components with frequencies 200,250 and 300 having means 25,10,and 15 and standard deviations 3,4, and 5 respectively.Calculate the mean and standard deviation.
Answer:
The mean and standard deviation of the combined distribution is 16 and 7.192 respectively.
Step-by-step explanation:
We have given that a distribution consists of three components with frequencies 200, 250, and 300 having means 25, 10, and 15 and standard deviations 3, 4, and 5 respectively.
And we have to find the mean and standard deviation of the combined distribution.
Firstly let us represent some symbols;
[tex]n_1[/tex] = 200 [tex]\bar X_1[/tex] = 25 [tex]\sigma_1[/tex] = 3
[tex]n_2[/tex] = 250 [tex]\bar X_2[/tex] = 10 [tex]\sigma_2[/tex] = 4
[tex]n_3[/tex] = 300 [tex]\bar X_3[/tex] = 15 [tex]\sigma_3[/tex] = 5
Here, [tex]\bar X_1, \bar X_2 , \bar X_3[/tex] represent the means and [tex]\sigma_1,\sigma_2,\sigma_3[/tex] represent the standard deviations.
Now, as we know that Mean of the combined distribution is given by;
[tex]\bar X = \frac{n_1 \times \bar X_1+n_2 \times \bar X_2+n_3 \times \bar X_3}{n_1+n_2+n_3}[/tex]
Putting the above values in the formula we get;
[tex]\bar X = \frac{200 \times 25+250 \times 10+300 \times 15}{200+250+300}[/tex]
[tex]\bar X = \frac{5000+2500 +4500}{750}[/tex]
[tex]\bar X = \frac{12000}{750}[/tex] = 16
Similarly, the formula for combined standard deviation is given by;
[tex]\sigma = \sqrt{\frac{n_1\sigma_1^{2} + n_1(\bar X_1-\bar X)^{2}+n_2\sigma_2^{2} + n_2(\bar X_2-\bar X)^{2}+n_3\sigma_3^{2} + n_3(\bar X_3-\bar X)^{2} }{n_1+n_2+n_3} }[/tex]
[tex]\sigma = \sqrt{\frac{(200 \times 3^{2}) + 200 \times (25-16)^{2}+(250 \times 4^{2}) + 250 \times (10-16)^{2}+(300 \times 5^{2}) + 300 \times (15-16)^{2} }{200+250+300} }[/tex]
[tex]\sigma = \sqrt{\frac{1800 + (200 \times 81)+4000 + (250 \times 36)+7500 +( 300 \times 1) }{750} }[/tex]
[tex]\sigma = \sqrt{\frac{1800 + 16200+4000 + 9000+7500 +300 }{750} }[/tex]
[tex]\sigma = \sqrt{\frac{38800 }{750} }[/tex] = 7.192
Hence, the mean and standard deviation of the combined distribution is 16 and 7.192 respectively.
Evaluate Combination (6,6)
Answer:
[tex] nCx = \frac{n!}{x! (n-x)!}[/tex]
On this case n =6 and x =6 we got:
[tex] 6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1[/tex]
Step-by-step explanation:
The utility for the combination formula is in order to find the number of ways to order a set of elements
For this case we want to find the following expression:
[tex] 6C6[/tex]
And the general formula for combination is given by:
[tex] nCx = \frac{n!}{x! (n-x)!}[/tex]
On this case n =6 and x =6 we got:
[tex] 6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1[/tex]
The baseball team ordered 140 T-shirts to sell at the school fair. Of those T-shirts, 50% are white, 20% are blue, 15% are green, 10% are red, and 5% are black. How many black T-shirts did the baseball team order? How many red T-shirts?
Answer:
The team ordered 7 black T-shirts.
The team ordered 14 red T-shirts.
Step-by-step explanation:
The team ordered 140 T-shirts.
How many black T-shirts did the baseball team order?
Of those, 5% are black.
0.05*140 = 7
The team ordered 7 black T-shirts.
How many red T-shirts?
Of those, 10% are red.
0.1*140 = 14
The team ordered 14 red T-shirts.
Can someone help me with these two problems?
Answer:
C. 38°
D. 30°
Step-by-step explanation:
The relevant relation in both cases is the inscribed angle measures half the measure of the arc it intercepts.
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C. Angle TSQ intercepts arc TQ, so the measure of arc TQ is 2(86.5°) = 173°. The measure of arc TR is the difference between the measures of arcs TQ and RQ, so is ...
arc TR = 173° -135° = 38°
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D. Inscribed angle PQR intercepts arc PR, so is half its measure.
angle PQR = 60°/2 = 30°
A particular group of men have heights with a mean of 181 cm and a standard deviation of 6 cm. Earl had a height of 196 cm. a. What is the positive difference between Earl's height and the mean? b. How many standard deviations is that [the difference found in part (a)]? c. Convert Earl's height to a z score. d. If we consider "usual" heights to be those that convert to z scores between minus2 and 2, is Earl's height usual or unusual?
Answer:
a. 15
b. based on the result of part a, 15 standard deviation above the mean.
c. 2.5
d. Earl's height is unusual
Step-by-step explanation:
We have that "x" would be the height of Earl = 196, the mean m = equals 181 and the standard deviation (sd) = 6, now:
a. the positive difference between the mean and Earl's height:
D = x - m
D = 196 - 181 = 15
b. based on the result of part a, 15 standard deviation above the mean.
c. The z value is given by:
z = x - m / sd
replacing:
z = (196 - 181) / 6
z = 2.5
d. the z-score is unusual since the value of z is 2.5 which is a value greater than than 2 standard deviations above the mean, which means that Earl's height is unusual
