Find the acceleration of a body of mass 300g being acted upon by a force of 6N.

Please show the working

Answer:

both velocity and acceleration

Explanation:

answer May be 3

Answer:

La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].

Explanation:

Asumamos que tanto el acróbata, el mono y el sistema acróbata-mono son conservativos y que el acróbata comienza su acción a una altura de cero. El estudio se divide en dos etapas: (i) El acróbata se dirige al mono, (ii) El acróbata recoge al mono y alcanzan una altura máxima.

Para resolver esta cuestión, nos valemos del Principio de Conservación de la Energía.

Parte I

La energía cinética traslacional inicial ([tex]K_{1,a}[/tex]) es igual a la suma de la energía cinética traslacional final ([tex]K_{2, a}[/tex]) y la energía potencial gravitacional final ([tex]U_{g,2,a}[/tex]).

[tex]K_{1,a} = K_{2,a} + U_{g,2,a}[/tex] (1)

[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex] (1b)

Donde:

[tex]M[/tex] - Masa del acróbata.

[tex]g[/tex] - Constante gravitacional.

[tex]v_{o}[/tex] - Rapidez inicial del acróbata.

[tex]v_{1}[/tex] - Rapidez del acróbata justo antes de recoger al mono.

[tex]h[/tex] - Altura inicial del mono.

Parte II

La suma de las energías iniciales cinética traslacional ([tex]K_{2, a}[/tex]) y potencial gravitacional de acróbata ([tex]U_{g,2,a}[/tex]) y la energía inicial potencial gravitacional del mono ([tex]U_{g,2,m}[/tex]) es igual a la suma de las energías potenciales gravitacionales iniciales del sistema acróbata-mono ([tex]U_{g,3,a+m}[/tex]), es decir:

[tex]K_{2,a} + U_{g,2,a}+U_{g,2,m} = U_{g,3,a+m}[/tex] (2)

[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex] (2b)

Donde:

[tex]m[/tex] - Masa del mono.

[tex]z[/tex] - Altura máxima del sistema acróbata-mono.

De (1b) tenemos que la rapidez del acróbata justo antes de recoger al mono es:

[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex]

[tex]v_{o}^{2} = v_{1}^{2}+2\cdot g\cdot h[/tex]

[tex]v_{1} = \sqrt{v_{o}^{2}-2\cdot g\cdot h}[/tex]

Finalmente, la altura máxima alcanzada por el sistema acróbata-mono es:

[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex]

[tex]z = \frac{M\cdot v_{1}^{2}}{2\cdot (M+m)\cdot g}+h[/tex]

[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot (v_{o}^{2}-2\cdot g\cdot h)+ h[/tex]

[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex]

La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].

Answer:

How does the weight of the nose on a paper

airplane affect the distance it will travel

when measured in centimeters?

EXPERIMENT CONCLUSION: (Explain whether or

not your data supports, or fails to support your identified

prediction. Explain why, including facts and details!)

The distance did increase when I added 1 paper clip.

However, I was surprised that the distance decreased

when I added a second paper clip. I believe this

happened because the nose of the plane became too

heavy. When the plane was released, the nose of the

plane descended much quicker. I think the plane was

more balanced in weight when only 1 clip was on the

nose.

Answer:

option C

Explanation:

farsightedness

Answer:

C and True :)

Explanation:

Hope you got it right!

Answer:

b. increases, decrease

Explanation:

Answer:

B. Acceleration in the direction of motion speeds you up

Explanation:

Acceleration is defined as when something gains speed. For example, when a car speeds up. Deceleration is when the car slows down, and looses speed. When defining these terms, think of a car going faster, then slowing down at a red light.

Answer:

gravity

Explanation:

its hard to explain its one of the resons we do gravity assists for space probes and such the meteor will catch earths gravity and be pulled in by it if you look at sednas orbit as it gets closer to the sun it speeds up.

The force that causes the meteor's speed to increase as it gets closer to Earth is the gravitational force of earth.

Gravity is defined as the force by which a planet attracts another body towards its center.

Here,

The meteor was moving through space and the speed of the meteor started increasing as it moves closer to the earth.

This is because of the gravitational force of earth that is being exerted on the meteor. Gravitational force of earth is defined as the force of attraction that the earth exerts on another body in its gravitational field and draws them towards the center of the earth.

As the meteor moves towards the earth's , it gets accelerated by the earth's gravitational field such that the speed of the meteor increases and thus it attains more kinetic energy. As a result, the meteor moves faster when it gets closer to earth. This is because of the force of gravity of the earth.

Hence,

The force that causes the meteor's speed to increase as it gets closer to Earth is the gravitational force of earth.

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Answer:

which question

paper, pencil, wood, human beings, moon.

Luminous objects are those objects which emit their own light.

Luminous objects can be natural as well as manmade.

One of the examples of natural luminous objects are- torch bulb, stars, sun, lighted candle.

Artificial luminous objects are those which cannot emit their own light.

Some of the examples of the artificial luminous objects are- paper, pencil, wood, human beings, moon.

Answer:

4) we take a can of cold soda there is a transfer from hand to can.  a current passes through a light bulb, it becomes incandescent and gives ligh

5) the law of energy conservation states that energy is neither created nor destroyed, therefore what happens is that you use energy and transform it into another type of energy,

Explanation:

4) This exercise is asked to give some examples of thermal and electrical energy transfer

the transfer of thermal energy occurs when we grasp a hot or cold body due to the difference in temperature between the body and us there is an exchange of heat, for example when drinking a cup of hot coffee there is a transfer of energy from the cup to the hand .

If we take a can of cold soda there is a transfer from hand to can.

Electrical transfer occurs, for example, when a current passes through a light bulb, it becomes incandescent and gives light.

In all modern electrical appliances there is transformation of electrical energy

5) the law of energy conservation states that energy is neither created nor destroyed, therefore what happens is that you use energy and transform it into another type of energy,

For example, when you lift a box, the potential energy of the box increases with height, but the energy of the person decreases because it does work that is negative.

In amusement park rides, the energy accumulated in one part of the game generally with height is transformed into energy of movement in another part of the game, but the total energy remains constant.

Answer:

50/20 = ans

Explanation:

you tube - superio s

Answer:

True

Explanation:

Answer:

D. Exothermic because energy is a product

Explanation:

ENDOTHERMIC REACTION: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.

EXOTHERMIC REACTION: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.

Hence, the correct answer for this question will be:

D. Exothermic because energy is a product

Answer:

the answer is B

visible light

Answer:

if sams answer is yes that they can have a child who is a non-taster then your answer is yes

Explanation:

if both parents are heterozygotes, 25% of their children can be nontaster.

Answer:

E = 2.7 x 10¹⁶ J

Explanation:

The release of energy associated with the mass can be calculated by Einstein's mass-energy relation, as follows:

[tex]E = mc^2[/tex]

where,

E = Energy Released = ?

m = mass of material reduced = 0.3 kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]E = (0.3\ kg)(3\ x\ 10^8\ m/s)^2[/tex]

E = 2.7 x 10¹⁶ J

The formula for momentum is p = m*v

The conservation of momentum suggests:

m*vi = m*vf (initial mass times initial velocity = final mass times final velocity or initial momentum = final momentum)

(0.0010)(52.2) = (0.0010 + 3.3)vf

vf = (0.0010)(52.2)/(0.0010 + 3.3) = 0.0522/3.301 ≈ 0.01581 m/s

To the nearest thousandth  ≈ .016 m/s

Answer:

thermal decomposition reaction

Explanation:

The reaction 2KCIO₃ → 2KCI + 3O₂ is a decomposition reaction. It dissociates into its constituent elements.

Decomposition reactions involve the breakdown of a compound into two or more simpler substances. In this case, potassium chlorate (KCIO₃) decomposes into potassium chloride (KCI) and oxygen gas (O₂).

The balanced equation for the reaction is:

2KCIO₃ → 2KCI + 3O₂

This reaction is typically initiated by applying heat to KCIO₃, causing it to decompose into its constituent elements.

Therefore, The reaction 2KCIO₃ → 2KCI + 3O₂ is a decomposition reaction. It dissociates into its constituent elements.

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Answer:

Gravity such as magnets

Explanation:

Hope this helped

Answer:

It is higher at the point on the left

Explanation:

Answer:

 W_net = μ 5.58,   μ = 0.1     W_net = 0.558 J

Explanation:

The work is defined by the related

          W = F. d ​​= F d cos θ

where bold indicates vectors.

In the case, the work of the friction force on a circular surface is requested.

The expression for the friction force is

              fr = μ N

the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1

               W = - fr d

the path traveled half the length of the circle

               L = 2 π R

               d = L / 2

               d = π R

we substitute

                 W = - μ N d

Total work is initial to

                W_neto = - μ π R (N_b - N_a)

let's calculate

                W_net = - μ π 0.550 (0.670 - 3.90)

                W_net = μ 5.58

for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1

                W_net = 0.1 5.58

                W_net = 0.558 J

Answer:

so a A lunar phase is an angle of the moon to the earth so it appears differently every day. The moon goes through 8 major phases. A new moon is when the moon cannot be seen because we are looking at the unlit half of the Moon. The new moon phase occurs when the Moon is directly between the Earth and Sun. A solar eclipse can only happen at new moon.

Explanation:

hope this helps

Answer:

The basic unit of matter is atoms

Answer:

B. atom

Explanation:

it's atom........

Answer:

1. 231.25 mL

2. 218.75 kPa

3. 6.21 L

4. 427.5 mL

5. 83.01 mL

6. 307.6 mL

7. 1.15 L

Explanation:

Boyle's law equation is used in this questions as follows;

P1V1 = P2V2

Where;

P1 = initial pressure

P2 = final pressure

V1 = initial volume

V2 = final volume

Please find the solutions to each subquestion as an attachment

Answer:

I would say all of the above

Explanation:

I think this bcuz it says it should be useful and comfortable and so four is correct bcuz they need to know if it feels good and also if it possibly would give a rash or worse. Next, all the other ones would prove how well the suits work in the conditions need for use.

Hope this helps.