f (x) = 7x Find f^-1 (x)​

Answer:

the first and third one

Step-by-step explanation:

have a great day

Answer:

yes you are correct as 3/5 = 0.6 and 0.6*5.5 = 3.3

Answer:

Option B 540 is the amswer

A number that would lie between -2.15 and -2.16 on the number line are 2.151.

Integers are arranged at equal intervals along horizontal straight lines called number lines. A number line can be used to represent every number in a series. The endpoints of this line go on forever. Some will have a defined beginning and end. It refers to those as closed number lines. Number lines might be alternatively left empty or blank. A number ladder is a vertical number line.

There are some possibilities would include the following:

2.151, 2.152, 2.153, 2.154, 2.155, 2.156, 2.157, 2.158, 2.159

therefore, the numbers that are between 2.15 and 2.16 are 2.151.

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Answer: .209

Step-by-step explanation:

took the test

Answer:

an addition problem

Step-by-step explanation:

Answer:

x=50

Step-by-step explanation:

Answer:

2x°=-205

x=-205/2=-102.5

Probablity of selecting a red marble= 35%

Probablity of not selecting a red marble= 100%-35%

=65%

Hope it helps you. Please mark brainliest.

Answer:

tan(A−B)=tan(A)−tan(B)/1+tan(A)tan(B)

1+tan(A)tan(B) To prove this, we should know that:

1+tan(A)tan(B) To prove this, we should know that:sin(A−B)=sin(A)cos(B)−cos(A)sin(B)

1+tan(A)tan(B) To prove this, we should know that:sin(A−B)=sin(A)cos(B)−cos(A)sin(B)AND

1+tan(A)tan(B) To prove this, we should know that:sin(A−B)=sin(A)cos(B)−cos(A)sin(B)ANDcos(A−B)=cos(A)cos(B)+sin(A)sin(B)

1+tan(A)tan(B) To prove this, we should know that:sin(A−B)=sin(A)cos(B)−cos(A)sin(B)ANDcos(A−B)=cos(A)cos(B)+sin(A)sin(B)We start with:

1+tan(A)tan(B) To prove this, we should know that:sin(A−B)=sin(A)cos(B)−cos(A)sin(B)ANDcos(A−B)=cos(A)cos(B)+sin(A)sin(B)We start with:tan(A−B)=sin(A−B)/cos(A−B)

cos(A−B)tan(A−B)=sin(A)/cos(B)−cos(A)sin(B)cos(A)cos(B)+sin(A)sin(B)(1)

cos(B)−cos(A)sin(B)cos(A)cos(B)+sin(A)sin(B)(1)We would want to divide both numerator and denominator by cos(A)cos(B)

cos(B)−cos(A)sin(B)cos(A)cos(B)+sin(A)sin(B)(1)We would want to divide both numerator and denominator by cos(A)cos(B)but there are 4 cases,

cos(B)−cos(A)sin(B)cos(A)cos(B)+sin(A)sin(B)(1)We would want to divide both numerator and denominator by cos(A)cos(B)but there are 4 cases,cos(A)=0 and cos(B)≠0cos(A)≠0 and cos(B)=0cos(A)=0 and cos(B)=0cos(A)≠0 and cos(B)≠0The question on this page is asking for specific formula, which comes from Case 4, so I will only solve Case 4 here.

cos(B)−cos(A)sin(B)cos(A)cos(B)+sin(A)sin(B)(1)We would want to divide both numerator and denominator by cos(A)cos(B)but there are 4 cases,cos(A)=0 and cos(B)≠0cos(A)≠0 and cos(B)=0cos(A)=0 and cos(B)=0cos(A)≠0 and cos(B)≠0The question on this page is asking for specific formula, which comes from Case 4, so I will only solve Case 4 here.Dividing numerator and denominator in (1) by cos(A)cos(B) we get:

cos(B)−cos(A)sin(B)cos(A)cos(B)+sin(A)sin(B)(1)We would want to divide both numerator and denominator by cos(A)cos(B)but there are 4 cases,cos(A)=0 and cos(B)≠0cos(A)≠0 and cos(B)=0cos(A)=0 and cos(B)=0cos(A)≠0 and cos(B)≠0The question on this page is asking for specific formula, which comes from Case 4, so I will only solve Case 4 here.Dividing numerator and denominator in (1) by cos(A)cos(B) we get:tan(A−B)=sin(A)/cos(B)−cos(A)/sin(B)/;2cosA)cos(B)/cos(A)cos(B)+sin(A)sin(B)/cos(A)cos(B)

cos(A)cos(B)tan(A−B)=sin(A)cos(B)/cos(A)cos(B)−cos(A)sin(B)cos/(A)cos(B)cos/(A)cos(B)co(A)cos(B)+sin(A)sin(B)/cos(A)cos(B)

cos(A)cos(B)tan(A−B)=sin(A)/cos(A)−sin(B)cos(B)1+sin(A)cos(A)sin(B)cos(B)

cos(A)−sin(B)cos(B)1+sin(A)cos(A)sin(B)cos(B) tan(A−B)=tan(A)−tan(B)/1+tan(A)tan(B)

Step-by-step explanation:

Hope it is helpful....

Answer: SMART Goal: I will keep my locker clean and organized as a sign of respect for myself and to save time.

Achievable: Each week, I will clean out my locker by throwing away anything I don’t need and making sure everything is in its correct place.

Time-Based: I will organize my locker before school starts. I will clean it every week. By the end of the first semester, I’ll automatically know where everything in my locker can be found.

Step-by-step explanation:

Answer:

268 hope i helped

Step-by-step explanation:

Answer:

268!

Step-by-step explanation:

You can easily g0ogle this so you don't need to waste points!  

Answer:

(1,-2)

Step-by-step explanation:

you just have to multiply the coordinates by 1/4

4x1/4=1

-8x1/4=-2

so the new coordinates are (1,-2)

The image of the given point is (1,-2).

Important information:

If a point is dilated by a scale factor of [tex]k[/tex] centered at the origin, then the rule of dilation is defined as:

[tex](x,y)\to (kx,ky)[/tex]

Using the above rule, we get

[tex](4,-8)\to \left(\dfrac{1}{4}(4),\dfrac{1}{4}(-8)\right)[/tex]

[tex](4,-8)\to \left(1,-2\right)[/tex]

Therefore, the image of the given point is (1,-2).

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Answer:

-3

Step-by-step explanation:

Answer:

I think it is 0

Step-by-step explanation:

the 9 goes down by 3 so maybe each point goes down 3

Answer:

Number that can be definitely defined, like 3.75, not 3.777....

Hope that helps!

Step-by-step explanation:

Answer: 1/6

Step-by-step explanation:

Answer:

2(19-5z)

Step-by-step explanation:

Factor out 2

Consider 11-5z+8. Multiply and combine like terms.

Rewrite the complete factored expression.

Answer:

3796.65

Step-by-step explanation:

I = $ 3,106.35

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 3.9%/100 = 0.039 per year,

then, solving our equation

I = 17700 × 0.039 × 4.5 = 3106.35

I = $ 3,106.35

The simple interest accumulated

on a principal of $ 17,700.00

at a rate of 3.9% per year

for 4.5 years is $ 3,106.35.

$ 6,903.00 - 3,106.35 = 3796.65

Answer:

V = 785.7ft³

Step-by-step explanation:

V = π r² h

V = 22/7 (5) 10

V = 22/7 × 25 ×10

V = 22/7 × 250

V = 22 × 250 ÷ 7

V = 550 ÷ 7

V = 785.7ft³ answer

Answer: The volume of the cylinder is 785.7ft³

Answer:

x = -2

Step-by-step explanation:

Arrange 6x + y= -5, -6x + 12y=96 vertically:

6x + y= -5

-6x + 12y=96       Now combine like terms:

--------------------

       13y = 91

Solving for y by dividing both sides by 13:  y = 7

Find x by substituting 7 for y in the second equation:  -6x + 12(7) = 96

Then -6x = -84 + 96, or:

-6x = 12, and so x = -2

Answer:

Step-by-step explanation:

1. Not a function. Fails the vertical line test.

2. It is a quadratic function.

3. It is a linear function.

4. Not a function. Two of the points have the same x-coordinate but different y-coordinates.

Answer:

D

Step-by-step explanation:

Answer:

D m-2

Step-by-step explanation:

Because you can see that input is m and the answer is the output

35-2=33

36-2=34

hope this helps!

pls brainliest

[tex]\tt{}5x + 6y + x + 2[/tex]

[tex]\tt{}6x + 6y + 2[/tex]

[tex]\tt{}2(3x + 3y + 1)[/tex]

Answer:

it is 25 percent

Step-by-step explanation:

Answer:

the answer is 1.25 un decimal

u + 4u = ?

According to the question, the value of u is 6.

6 + 4(6) = 6 + 24 = 30

u + 4u = 30 (If the value of u is 6)

In polar form the expression is ( 14 , 30 )

To convert the expression x +iy  to polar form ( r , [tex]\rm \theta[/tex] ) , the standard equations used are

r = [tex]\rm \sqrt {x^2 + y^2}[/tex]

tan [tex]\rm \theta[/tex] = y/x

The given expression is

7 √3 - 7i

x = 7 √3

y = -7

r = [tex]\rm \sqrt {(7\sqrt{3})^2 +(-7)^2}[/tex]

r = √196

r = 14

tan [tex]\rm \theta[/tex] = (-7)/(7√3)

[tex]\rm \theta[/tex] = 30 degree

Therefore in polar form the expression is ( 14 , 30 ).

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Answer:The polar form of 7 StartRoot 3 EndRoot minus 7 i is 14(cos(330o) + i sin(330o))

Step-by-step explanation: