Answers
When h = 0 , [f(x + h) - f(x)]/h = 2x +2 for the given expression.
The missing expression is f(x) = x² + 2x.
What is formula of difference quotient ?f(x+h)-f(x)/h is called the formula of difference quotient.
When h---> 0 ,
the expression f'(x) = (f(x-h) - f(x)) / h is the equation for tangent to the line
Here the the expression is
f(x) = x² + 2x
Determining f(x + h) by substituting x = x + h on both sides of the given f(x).
Then f(x + h) = (x + h)² + 2(x + h)
= x² + 2xh + h² + 2x + 2h
the difference f(x + h) - f(x).
f(x + h) - f(x) = [x² + 2xh + h² + 2x + 2h] - [x² + 2x]
= 2xh + h² + 2h
Divide the difference from h as in the formula of difference coefficient
[f(x + h) - f(x)]/h = (2xh + h² + 2h) / h
= 2x + h + 2
So, when h = 0 , [f(x + h) - f(x)]/h = 2x +2
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Related Questions
Help me with this piecewise function!
Answers
Answer:
According to the given function, the value of h(-1) is -1, h(-0.5) is 0 and h(1) is 1.
Step-by-step explanation:
The given function says that:
If the range of the values of x is x∈(-2,-1], then the value of the function is -1.
If the range of the values of x is x∈(-1,0], then the value of the function is 0.
If the range of the values of x is x∈(0,1], then the value of the function is 1.
If the range of the values of x is x∈(1,2], then the value of the function is 2.
In the first case, we have x = -1. This satisfies the first condition. So accordingly, the value that the function will give is -1.
In the second case, we have x = -0.5. This satisfies the second condition. So accordingly, the value that the function will give is 0.
In the third case, we have x = 1. This satisfies the third condition. So accordingly, the value that the function will give is 1.
So, h(-1) = -1, h(-0.5) = 0 and h(1) = 1.
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Which expression is equivalent to (1−sinβ)(1+sinβ)/cos2β for all values of β for which (1−sinβ)(1+sinβ)/cos2β is defined?
Select the correct answer below:
tan2β
tanβ+secβ
tanβ
sec2β
1
Answers
Using a trigonometric identity, it is found that the equivalent expression is given by 1.
What are the trigonometric identities used to solve this question?Relating sine and cosine, we have that:
[tex]\sin^{2}{\beta} + \cos^{2}{\beta} = 1[/tex]
Then:
[tex]\cos^{2}{\beta} = 1 - \sin^{2}{\beta}[/tex]
For the tangent, we have that:
[tex]\tan{\beta} = \frac{\sin{\beta}}{\cos{\beta}}[/tex].
For the secant, we have that:
[tex]\sec{\beta} = \frac{1}{\cos{\beta}}[/tex].
In this problem, the expression is:
[tex]\frac{(1 - \sin{\beta})(1 + \sin{\beta})}{\cos^{2}{\beta}} = \frac{1 - \sin^2{\beta}}{\cos^2{\beta}} = \frac{\cos^2{\beta}}{\cos^2{\beta}} = 1[/tex]
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Over what interval is the function in this graph increasing? A. –5 ≤ x ≤ 5 B. –3 ≤ x ≤ 2 C. –4 ≤ x ≤ –2 D. –2 ≤ x ≤ 3
Answers
The function in this graph is increasing in the interval –2 ≤ x ≤ 3 , Option D is the right answer.
What is a function ?A function is a mathematical statement used to relate a dependent and an independent variable.
From the graph it can be seen that the graph is increasing in the interval
–2 ≤ x ≤ 3
The graph is said to be increasing when the value of y is getting more and more positive
As –2 ≤ x ≤ 3 , y varies from -3 to +3
Therefore Option D is the right answer.
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Answer:
–2 ≤ x ≤ 3
Step-by-step explanation:
Janelle and Jacob are considering a $130,000 mortgage for 30 years at 4.8%. With this information, their monthly payment
would be $682.06.
If they make only the minimum payment each month, what is the total payback of this loan?
How much of this total payback is interest?
Answers
Total payback = 360 x $682.06 = $245,541.60
Interest = 245,541.60 - 130,000 = $115,541.60
You are given the steps for using a compass and a straightedge to construct a line perpendicular to a given line through a point not lying on the given line. Arrange the steps in the proper sequence.
Place the compass needle on the external
point R. Make the compass width greater
than the distance from R to the given line.
Draw an arc cutting the given line at
two points. Mark and label the points
of intersection P and Q.
Draw a line from the external point R to
the point where the arcs intersect, S.
Line RS is perpendicular to line PQ and
passes through the external point R.
Move the compass needle to P and make an
arc below the line. Keep the compass width,
and move the compass needle to Q. Draw an
arc below the line crossing the other arc.
Mark and label the point of intersection S.
Answers
The proper steps for the construction are given as 1, 2 4, and then 3.
Write the steps for construction?The proper steps for the construction are;
1. Place the compass needle on the external point R. Make the compass width greater than the distance from R to the given line.
2. Draw an arc cutting the given line at two points. Mark and label the points of intersection P and Q.
3. Move the compass needle to P and make an arc below the line. Keep the compass width, and move the compass needle to Q. Draw an arc below the line crossing the other arc. Mark and label the point of intersection S.
4. Draw a line from the external point R to the points where the arcs intersect, S. Line RS is perpendicular to line PQ and passes through the external point R.
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Simplify the following expression. (2x − 1)(3x + 2) Simplify the following expression . ( 2x − 1 ) ( 3x + 2 )
Answers
=6x^2+x-2
Sum to n terms of each of following series. (a) 1 - 7a + 13a ^ 2 - 19a ^ 3+...
Answers
Notice that the difference in the absolute values of consecutive coefficients is constant:
|-7| - 1 = 6
13 - |-7| = 6
|-19| - 13 = 6
and so on. This means the coefficients in the given series
[tex]\displaystyle \sum_{i=1}^\infty c_i a^{i-1} = \sum_{i=1}^\infty |c_i| (-a)^{i-1} = 1 - 7a + 13a^2 - 19a^3 + \cdots[/tex]
occur in arithmetic progression; in particular, we have first value [tex]c_1 = 1[/tex] and for [tex]n>1[/tex], [tex]|c_i|=|c_{i-1}|+6[/tex]. Solving this recurrence, we end up with
[tex]|c_i| = |c_1| + 6(i-1) \implies |c_i| = 6i - 5[/tex]
So, the sum to [tex]n[/tex] terms of this series is
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \underbrace{\sum_{i=1}^n i (-a)^{i-1}}_{S'} - 5 \underbrace{\sum_{i=1}^n (-a)^{i-1}}_S[/tex]
The second sum [tex]S[/tex] is a standard geometric series, which is easy to compute:
[tex]S = 1 - a + a^2 - a^3 + \cdots + (-a)^{n-1}[/tex]
Multiply both sides by [tex]-a[/tex] :
[tex]-aS = -a + a^2 - a^3 + a^4 - \cdots + (-a)^n[/tex]
Subtract this from [tex]S[/tex] to eliminate the intermediate terms to end up with
[tex]S - (-aS) = 1 - (-a)^n \implies (1-(-a)) S = 1 - (-a)^n \implies S = \dfrac{1 - (-a)^n}{1 + a}[/tex]
The first sum [tex]S'[/tex] can be handled with simple algebraic manipulation.
[tex]S' = \displaystyle \sum_{i=1}^n i (-a)^{i-1}[/tex]
[tex]\displaystyle S' = \sum_{i=0}^{n-1} (i+1) (-a)^i[/tex]
[tex]\displaystyle S' = \sum_{i=0}^{n-1} i (-a)^i + \sum_{i=0}^{n-1} (-a)^i[/tex]
[tex]\displaystyle S' = \sum_{i=1}^{n-1} i (-a)^i + \sum_{i=1}^n (-a)^{i-1}[/tex]
[tex]\displaystyle S' = \sum_{i=1}^n i (-a)^i - n (-a)^n + S[/tex]
[tex]\displaystyle S' = -a \sum_{i=1}^n i (-a)^{i-1} - n (-a)^n + S[/tex]
[tex]\displaystyle S' = -a S' - n (-a)^n + \dfrac{1 - (-a)^n}{1 + a}[/tex]
[tex]\displaystyle (1 + a) S' = \dfrac{1 - (-a)^n - n (1 + a) (-a)^n}{1 + a}[/tex]
[tex]\displaystyle S' = \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2}[/tex]
Putting everything together, we have
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 S' - 5 S[/tex]
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2} - 5 \dfrac{1 - (-a)^n}{1 + a}[/tex]
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} =\boxed{\dfrac{1 - 5a - (6n+1) (-a)^n + (6n-5) (-a)^{n+1}}{(1+a)^2}}[/tex]
Unas deportivas cuestan $600 he visto que hay una rebaja del 20% cuánto dinero rebajado las reporteras
Answers
Answer:
600/100*20=6*20=120
600-120=480$
Solve the system of equations : y = x/2 , y = -x - 3 . You can use any method you wish for solving systems of equations. Check your answer.
Answers
Answer:
x=−2 and y=−1
Step-by-step explanation:
Problem:
Solve y=x2;y=−x−3
Steps:
I will solve your system by substitution.
y=1/2x;y=−x−3
Step: Solve y= 1/2x for y:
Step: Substitute 1/2 x for y in y=−x−3:
y=−x−3
1/2x= =−x−3
1/2x+x=−x−3+x(Add x to both sides)
3/2x = -3
3/2x/3/2 = -3/3/2 (Divide both sides by 3/2)
x=−2
Step: Substitute −2 for x in y=1/2x:
y=1/2x
y=1/2(-2)
y=−1(Simplify both sides of the equation)
Answer:
x=−2 and y=−1
(a) 3.1563x106
(b) 5.65x10-4 convert to usual form
Answers
Answer:
[tex](a) \: 3.1563 \times {10}^{6} = 31563 \times {10}^{6} \times {10}^{ - 4} = 31563 \times {10}^{6 - 4} = 31563 \times {10}^{2} = 3156300[/tex]
__o__o__
[tex](b) \: 5.65 \times {10}^{ - 4} = 565 \times {10}^{ - 4} \times {10}^{ - 2} = 565 \times {10}^{ - 4 - 2} = 565 \times {10}^{ - 6} = 0.000565[/tex]
12. A bag contains 12 red, 9 green and 5 black markers. If Cooper randomly selects 7 markers, how many
ways could this be done if EXACTLY 6 are to be the same color?
Answers
Answer:
Step-by-step explanation:
7 marks
6 same colors
from 12 red 6 same exactly the same
12 x 11 x 10 x 9 x7 x6
1 remainig
from 9 green 6 saem exactly the same
9 x 8 x 7 x 6 x5 x4
1 remaining
add the results above to get your final answer
26 markers in total
6 to be chosen of the same color from 7
Is 3.5 greater than 3.39
Answers
Answer:
yes
Step-by-step explanation:
4. In 2010, the amount in Raja's account was 40 Lakhs. He debited 8000 in 2011, and in 2012, he debited 2,07,000. In 2013, he credited 1,16,000, and in 2014 he credited 12,000. How much more he has to credit to be worth what it was at at the start of 2010
Answers
Answer:
don't know is is mathematics or any other subject
Which is not a solution of sin 20 = 1?
A = 90
B = 45
C = 225
D = - 135
Answers
Need answers asap please
Answers
The inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
a(n) = 3n - 30
To find make subject n and solve
a(n) + 30 = 3n
[tex]\rm n = \dfrac{a(n) + 30}{3}[/tex]
Plug n = n(a) and a(n) = a
[tex]\rm n(a) = \dfrac{a + 30}{3}[/tex]
Thus, the inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
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Which of the following best describes the set of complex numbers?
OA. The set of all numbers of the form a+bi, where a and bare any
real numbers and i equals -1
B. The set of all numbers of the form abi, where a and bare any real
numbers and i equals 1
C. The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1
OD. The set of all numbers of the form abi, where a and b are any real
numbers and / equals -1
Answers
Answer:
C
Step-by-step explanation:
The correct statement is option C.
What is complex number?A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively. Additionally, i = √-1 and both a and b are real numbers.
Since we know that
Complex number is of the form a+ib
Where,
a is real number belongs to real axis
And b is also a real number belongs to imaginary axis.
And the value of i = √-1
Thus,
The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1 is the correct statement.
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What is the surface area of the figure? 9 ft 9 ft 15 ft 15 ft 4 ft
Answers
The surface area of the given composite figure is; 528 ft²
How to find the area of a composite figure?To get the surface area of the attached composite shape, we will have to break the object down into smaller shapes to get;
Surface area 1 = 2(15 * 4) = 120 ft²
Surface area 2 = 2(9 * 4) = 72 ft²
Surface area 3 = 2(6 * 4) = 48 ft²
Surface area 4 = 2((15 * 15) - (9 * 9)) = 288 ft²
Thus;
Total surface area = 120 + 72 + 48 + 288
Total surface area = 528 ft²
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A chain weighs 12 pounds per foot. How many ounces will 7 inches weigh?
Answers
Answer:
The chain of the length 7 inches weighs 112 ounces.
Step-by-step explanation:
As we know there are 12 inches in a foot and 16 ounces in a pound
That is 1 foot = 12 inches.
and 1 pound = 16 ounces.
Given that the weight of the chain that is 1 foot long = 12 pounds
So weight of the chain per inch is = 12/12
which is equal to 1 pound
and according to the formula 1 pound = 16 ounces
So weight of the chain per inch is = 16 ounces
therefore weight of the chain that is 7 inch long = 7 × 16
that is 112 ounces.
The chain of the length 7 inches weighs 112 ounces.
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what is the domain and range of this graph
Answers
Answer:
Domain: All real number
Range: y≤-4
. In 1 hour, a car can cover 70 km. How much distance will it cover in 2 hours?
I need it fast
Answers
Answer:
140km
Step-by-step explanation:
Distance = Speed x Time
= 70km/h x 2 hours
= 140km
Simplify (3^1\2x2^1\3)^1\2
Answers
Answer:
1.37
Step-by-step explanation:
3^1=3/2=1.5
2^(1/3)=1.26
1.5×1.26=1.89
1.89^(1/2)=1.37
Choose the equation that satisfies the data in the table.
[xy−100−41−8]
A. y=−4x−4
B. y=−14x+4
C. y=4x−4
D. y=14x+4
Answers
The linear equation that satisfy the data in the table is: A. y = −4x − 4.
How to Find the Linear Equation for a Data in a Table?Given the table attached below, find the slope (m) = change in y / change in x using two pairs of values, say, (-1, 0) and (0, -4):
Slope (m) = (-4 - 0)/(0 - (-1)) = -4/1 = -4
Find the y-intercept (b), which is the value of y when x = 0. From the table, when x = 0, y = -4.
b = -4.
Substitute m = -4 and b = -4 into y = mx + b
y = -4x + (-4)
y = -4x - 4
The equation that satisfy the data is: A. y = −4x − 4.
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what is the sum of the series
Answers
Answer: 925
Step-by-step explanation:
This is an arithmetic series with first term 1 and last term 3(25)-2=73, with a total of 25 terms.
Using the sum of an arithmetic series formula, we get the sum is:
[tex]\frac{25}{2}(1+73)=\boxed{925}[/tex]
If 6^(2x)=4 find 36^(6x-2) could anyone help me please?
Answers
Answer:
3.160
Step-by-step explanation:
You can solve for x using logarithm.
Rewrite in logarithm form
[tex]log_{6}4=2x\\\\x=\frac{log_64}{2}\\x=\frac{\frac{log4}{log6}}{2}\\x=\frac{log4}{log6} * \frac{1}{2}\\x=\frac{log4}{log6 * 2}\\x\approx0.386852807\\36^{6(0.386852807)-2} \approx3.160[/tex]
The point A(0,3) and point B(4,19) lie on the line L.
Find the equation of line L
Answers
Answer: The equation is y = 4x+3
Slope = 4
y intercept = 3
========================================================
Explanation:
Let's start off by finding the slope.
[tex]A = (x_1,y_1) = (0,3) \text{ and } B = (x_2,y_2) = (4,19)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{19 - 3}{4 - 0}\\\\m = \frac{16}{4}\\\\m = 4\\\\[/tex]
The slope is 4.
The y intercept is 3 because of the point (0,3)
We go from y = mx+b to y = 4x+3
m = slope
b = y intercept
---------------
Check:
Plug in x = 0 and we should get to y = 3
y = 4x+3
y = 4(0)+3
y = 0+3
y = 3
That works out. Now try x = 4. It should lead to y = 19
y = 4x+3
y = 4(4)+3
y = 16+3
y = 19
The answer is confirmed.
Which values of x and y would make the following expression represent a real number?
(4 +51)(x + yı)
O x = 4, y =
O x=-4, y = 0
Ox = 4, y = -5
O x = 0, y = 5
Answers
The values of x and y would make the following expression represent a real number is 4 and -5 respectively
Complex and real numberThe standard form of writing a complex number is given asl
z= x + iy
where
x is the real part
y is the imaginary part
Given the expression below;
(4 +5i)(x + yi)
Expand
4x + 4yi + 5ix + 5y(-1)
4x + 4yi + 5ix - 5y
Hence the values of x and y would make the following expression represent a real number is 4 and -5 respectively
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A chopstick model of a catapult launches a marshmallow in a classroom. The path of the marshmallow can be modeled by the quadratic y=−0.07x2+x+2.2,
where y represents the height of the marshmallow, in feet,
and x represents the horizontal distance from the point it is launched, in feet.
When the marshmallow hits the ground, what is its horizontal distance from the point where it was launched?
Answers
The horizontal distance from the point where it was launched is 7.143.
We have given that,
The path of the marshmallow can be modeled by the quadratic y=−0.07x^2+x+2.2,
x represents the horizontal distance from the point it is launched, in feet.
What is the horizontal distance?Horizontal distance means the distance between two points measured at a zero percent slope.
(1) Put x = 7.143 in given equation
y= -0.07(7.143)^2+7.143+2.2
y= 2.2
y= 5.771
We have to determine the what is its horizontal distance from the point where it was launched.
The value of x is called horizontal distance.
Therefore the horizontal distance from the point where it was launched is 7.143.
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Help me please help help
Answers
[tex]\angle P = \angle S \Rightarrow \angle S = 42 &^\circ\\\angle Q = \angle T \Rightarrow \angle S = 86 &^\circ\\\angle R = \angle U\\[/tex]
Sum of all angles in a triangle equals 180:
[tex]\angle R = 180 - (86 + 42) = 180 - 128 = 52[/tex]
Answer:
[tex]U = 52 &^ \circ[/tex]
Need help with algebra homework
Answers
Answer:
the answer for this problem is A, big
Eric recorded the number of automobiles that a used car dealer in his town sold in different price ranges. From the Histogram given, what is the number of cars sold for the price range of $4000 to $4999? A. 15 B. 20 C. 30 D. 50
Answers
The correct answer is option A which is the number of cars sold for the price range of $4000 to $4999 will be 15.
What is a histogram?
A histogram is a graph for the representation of the data on the plot of the rectangular boxes. It has the data sets on the horizontal and the vertical axes.
As we can see from the histogram data we will conclude that the price range of $4000 to $4999 is shown by the third block and this third block reaches the height of 15.
Therefore the correct answer is option A which is the number of cars sold in the price range of $4000 to $4999 will be 15.
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