Answer:
the price of each lemon bought by Encik Halim is RM1.45.
Step-by-step explanation:
Encik Halim bought 108 lemons and packed them into packets of 3 lemons each. So he made a total of 108/3 = 36 packets.
Let's assume that the cost of each lemon bought by Encik Halim is x RM.
The total cost of 108 lemons would then be 108x RM.
Encik Halim sold each packet at a price of RM6.80, so the total revenue he earned from selling 36 packets would be 36 x RM6.80 = RM244.80.
We are told that Encik Halim made a profit of RM88.20 from the sale of these packets, so his total cost would be:
Total cost = Total revenue - Profit
Total cost = RM244.80 - RM88.20
Total cost = RM156.60
We know that Encik Halim bought 108 lemons, so we can write:
Total cost = Number of lemons bought x Cost per lemon
RM156.60 = 108x
Therefore, the cost per lemon bought by Encik Halim is:
x = RM156.60/108
x = RM1.45
So the price of each lemon bought by Encik Halim is RM1.45.
A map shows the vertices of a campsite are (25,10), (25,-5), (-5,-5), and (-5,10). The vertices of your tent are (0,-3), (0,6), (10,6), and (10,-3). The coordinates are measured in feet. What percent of the campsite is not covered by your tent?
The percent of the area that is not covered is 80 percent
How to calculate the area that is not coveredIn mathematics area is defined as the absolute or total space that an object or shape occupies. It is usually measured using centimeters, cm ² square or the use of meter square m ².
area of tent
= (10 - 0) * (6 - (-3))
= 90
The area of the campsite would be:
(25 - (-5) x (10 - (-5))
= 450
Then the area would be 450 - 90
= 360
the percentage that is not covered by tent = 360 / 450 x 100
= 80 percent
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I need help please can somebody help me please
The values of the matrices operations are [tex]4G + 2F = \left[\begin{array}{ccccc}34&-4&-42&-18&48\\-42&-8&16&30&8\\24&32&4&34&34&-12&-32&-12&-42&-20\end{array}\right][/tex] and [tex]4D - 3B= \left[\begin{array}{ccccc}31&6&34&-14&-57\\-19&-27&-18&18&27\\47&14&-1&-40&9&10&12&-19&-15&-58&-14&-23&10&-8&10\end{array}\right][/tex]
Evaluating the matrices operationsFrom the question, we have the following parameters that can be used in our computation:
[tex]G = \left[\begin{array}{ccccc}8&-5&-7&-1&10\\-6&-7&1&9&2\\4&6&3&7&5&-4&-3&0&-10&-9\end{array}\right][/tex]
Also, we have
[tex]F = \left[\begin{array}{ccccc}1&8&-2&-5&9\\-9&10&6&-3&0\\4&5&-4&3&7&2&-10&-6&-1&-8\end{array}\right][/tex]
Using the above as a guide, we have
[tex]4G + 2F = 4\left[\begin{array}{ccccc}8&-5&-7&-1&10\\-6&-7&1&9&2\\4&6&3&7&5&-4&-3&0&-10&-9\end{array}\right] + 2 \left[\begin{array}{ccccc}1&8&-2&-5&9\\-9&10&6&-3&0\\4&5&-4&3&7&2&-10&-6&-1&-8\end{array}\right][/tex]
Evaluate the sum
[tex]4G + 2F = \left[\begin{array}{ccccc}34&-4&-42&-18&48\\-42&-8&16&30&8\\24&32&4&34&34&-12&-32&-12&-42&-20\end{array}\right][/tex]
Next, we have
[tex]D = \left[\begin{array}{ccccc}7&-6&3&-8&-9\\2&-9&-6&6&9\\8&2&5&-10&-3&10&-3&-4&3&-7&1&-2&4&-5&-2\end{array}\right][/tex]
Also, we have
[tex]B = \left[\begin{array}{ccccc}-1&-10&-8&-6&7\\9&-3&-2&2&3\\-5&-2&7&0&-7&10&-8&1&9&10&6&5&2&-4&-9\end{array}\right][/tex]
The matrix expression is then represented as
[tex]4D - 3B= 4\left[\begin{array}{ccccc}7&-6&3&-8&-9\\2&-9&-6&6&9\\8&2&5&-10&-3&10&-3&-4&3&-7&1&-2&4&-5&-2\end{array}\right] - 3\left[\begin{array}{ccccc}-1&-10&-8&-6&7\\9&-3&-2&2&3\\-5&-2&7&0&-7&10&-8&1&9&10&6&5&2&-4&-9\end{array}\right][/tex]
Evaluate
[tex]4D - 3B= \left[\begin{array}{ccccc}31&6&34&-14&-57\\-19&-27&-18&18&27\\47&14&-1&-40&9&10&12&-19&-15&-58&-14&-23&10&-8&10\end{array}\right][/tex]
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Models that represent z+9=14 ASAP
To represent z+9=14, we can start by subtracting 9 from both sides of the equation:
z + 9 - 9 = 14 - 9
Simplifying the left side of the equation gives:
z = 5
Therefore, the solution to the equation z+9=14 is z=5.
At 9 15 , a van left Blossom Village for River Town at an average speed of 50 Km/h. Half an
hour later, a car passed Blossom Village heading towards River Town along the same route
at an average speed of 60 Km/h.
A) At what time would the car catch up with the van?
B) If the car reached River Town at 15 45, what was the distance between the two towns?
Answer: A) Let's first calculate how far the van would have traveled in the half hour before the car started. The van's speed is 50 km/h, which means in half an hour it would have traveled 50/2 = 25 km.
Now let's consider the time it takes for the car to catch up to the van. We can represent this using the formula:
distance = rate × time
Let's call the time it takes for the car to catch up "t". We know that during this time, the van is also traveling. In fact, it has been traveling for t + 0.5 hours (the half hour before the car started plus the time it takes for the car to catch up). So the distance the van has traveled is:
distance van = 50 × (t + 0.5)
The distance the car has traveled is:
distance car = 60t
When the car catches up to the van, they will have traveled the same distance. So we can set the two distances equal to each other:
50(t + 0.5) = 60t
Simplifying this equation:
50t + 25 = 60t
Subtracting 50t from both sides:
25 = 10t
So t = 2.5 hours.
But we're not done yet! We need to add the 0.5 hours that the van traveled before the car started to get the total time it took for the car to catch up:
t + 0.5 = 2.5 + 0.5 = 3 hours
So the car catches up to the van 3 hours after the van started, or at 12:15 pm.
B) We can use the formula:
distance = rate × time
to find the distance between the two towns. We know the car traveled for 6 hours (from 9:45 am to 3:45 pm) and its speed was 60 km/h. So the distance it traveled is:
distance car = 60 × 6 = 360 km
We also know that the van traveled for 6.5 hours (from 9:15 am to 3:45 pm) and its speed was 50 km/h. So the distance it traveled is:
distance van = 50 × 6.5 = 325 km
The distance between the two towns is the difference between these two distances:
distance = distance car - distance van = 360 - 325 = 35 km
So the distance between the two towns is 35 km.
PLEASE HELP ME QUICK!!!
Answer:
Option D. [tex]g(x)=5(0.8)^{x}+2[/tex]
Step-by-step explanation:
Main concepts
Concept 1: identifying horizontal asymptote
Concept 2: assuring decreasing exponential function
Concept 1. identifying horizontal asymptote
Any exponential function of the form [tex]y=a*b^x[/tex] has a horizontal asymptote on the x-axis. A constant (positive or negative) added to the end of the exponential expression will shift the graph of the exponential function up (if positive) or down (if negative) the number of units equal to the magnitude of the number. Since the original function f(x) has a "+2" at the end, it has been shifted up 2 units. Thus, we can eliminate answers A and C from feasible answers since they each shift the exponential function up 3 units, not 2.
Concept 2. assuring decreasing exponential function
Exponential functions of the form [tex]y=a*b^x[/tex] increase or decrease based on the value of "b".
If "b" is between 0 and 1 (a "small" number), the function will decrease.If "b" is larger than 1 (a "big" number), the function will increase.Observe that the graph of the function f(x) is decreasing, and the value of b=0.5.
To ensure that g(x) also decreases, the b-value must be between 0 and 1, which eliminates option B.
Option D is the correct answer because the value of "b" is between 0 and 1 (making the graph of the function a decreasing exponential), and the number added at the end is "+2", causing the horizontal asymptote to be at a height of positive 2.
What is 2 1/4 divided by 1 1/2?
Answer:
2 1/4 divided by 1 1/2 is equal to 9/2 or 4 1/2.
Step-by-step explanation:
To divide 2 1/4 by 1 1/2, we first need to convert both mixed numbers to improper fractions:
2 1/4 = (2 × 4 + 1) / 4 = 9 / 4
1 1/2 = (1 × 2 + 1) / 2 = 3 / 2
Now we can divide by multiplying by the reciprocal of the second fraction:
(9/4) / (3/2) = (9/4) * (2/3)
We can simplify this multiplication by canceling the common factor of 3 in the numerator of the second fraction and the denominator of the first fraction:
(9/4) * (2/3) = (33/4) * (2/13) = 9/2
So 2 1/4 divided by 1 1/2 is equal to 9/2 or 4 1/2.
[tex]\boxed{\sf \dfrac{3}{2}}.[/tex]
Step-by-step explanation:1. Write the expression.[tex]\sf \dfrac{2\dfrac{1}{4} }{1\frac{1}{2} }[/tex]
2. Convert the mixed fractions into improper fractions.[tex]\sf 2\dfrac{1}{4}\Longrightarrow\dfrac{4}{4} +\dfrac{4}{4} +\dfrac{1}{4} =\dfrac{4+4+1}{4} =\dfrac{9}{4}[/tex]
[tex]1\dfrac{1}{2} =\dfrac{2}{2} +\dfrac{1}{2} =\dfrac{2+1}{2} =\dfrac{3}{2}[/tex]
3. Rewrite the division.[tex]\sf \dfrac{\dfrac{9}{4} }{\dfrac{3}{2} }[/tex]
4. Rewrite again using the properties of fractions.• Check the attached image.
[tex]\dfrac{9}{4} *\dfrac{2}{3}[/tex]
5. Calculate and simplify.[tex]\dfrac{9*2}{4*3} =\dfrac{18}{12} \\ \\\dfrac{18/2}{12/2} =\dfrac{9/3}{6/3}=\boxed{\sf \dfrac{3}{2}} .[/tex]
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The mean monthly salary of female employees of a company is 3750 Birr, while the mean monthly salary of male employees is 4500 Birr. It is known that the mean monthly salary of male and female employees combined is 4000 Birr. a) What is the ratio of the number of female employees to male employees? b) What percentage of employees are females?
A population of rabbits is increasing at a rate of 1.5% per month. If there are 60 rabbits today, how many will there be after 10 months? Round to the nearest whole.
If population of rabbits is increasing at a rate of 1.5% per month, after 10 months, there will be approximately 71 rabbits in the population.
To solve this problem, we need to use the formula for exponential growth:
A = P(1 + r)ᵗ
where A is the final amount, P is the initial amount, r is the growth rate as a decimal, and t is the time period. In this case, we have P = 60, r = 0.015 (1.5% expressed as a decimal), and t = 10.
Plugging these values into the formula, we get:
A = 60(1 + 0.015)¹⁰
A ≈ 71
t's important to round to the nearest whole, so we can't be exact, but we know the answer will be somewhere between 70 and 72 rabbits.
Exponential growth is a model that assumes continuous growth over time, which may not be entirely accurate in real-world scenarios.
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Trundle wheels are used to measure distances along the ground.
The radius of the trundle wheel is 30 cm.
Jim wants to work out the distance between two junctions on a road.
He rolls the trundle wheel between the two junctions.
The trundle wheel rotates exactly 48 times.
Work out the distance between the two junctions.
Give your answer in metres correct to the nearest metre.
The distance between the two junctions is, 90 meters, when rounded off to the nearest meter.
:: Radius of trundle wheel = 30 cm = 0.3 meter (as 100 cm = 1 m)
:: No. of rotations = 48
:: Circumference of a circle = ( 2 x π x r )
where, r is radius of the circle
So, as,
Distance between junctions = [ (circumference of trundle wheel) x (no. of rotations) ]
Therefore,
Distance = (2 x π x 0.3) x (48)
Distance = 2 x (3.14) x 0.3 x 48
Distance = 90.432 meters
When rounded off to the nearest meter,
Distance = 90 meters.
So, The distance between the two junctions is, 90 meters, when rounded off to the nearest meter.
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.If $10,000 is deposited in an account earning 5 ¾ % interest compounded monthly. How much money will be in the account in 5 years.
The total amount in the acount in 5 years is approximately $13,321.76.
What is the accrued amount in the account in 5 years?The formula accrued amount in a compounded interest is expressed as;
[tex]A = P( 1 + \frac{r}{n} )^{n*t}[/tex]
Where A is accrued amount, P is principal, r is interest rate and t is time.
Given that:
Principal P = $10,000Compounded monthly n = 12Time t = 5 yearsInterest rate r = 5 3/4% = 5.75%Accrued amount A = ?First, convert R as a percent to r as a decimal
r = R/100
r = 5.75/100
r = 0.0575
Plug the given values into the above formula and solve for A.
[tex]A = P( 1 + \frac{r}{n} )^{n*t}\\\\A = 10000( 1 + \frac{0.0575}{12} )^{(12*5)}\\[/tex]
A = $13,321.76
Therefore, the accrued amount is $13,321.76.
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A spinner divided into three equal sections marked A A and Z is spun 570 times approximately how many times will it be expected to land on an A
If a spinner divided into three equal sections marked A A and Z is spun 570 times . The number of times it will be expected to land on an A is 380 times.
How to find the Expected number of time ?Since the spinner has three equal sections in which two of them are marked A. The probability of landing on an A in a single spin will be 2/3 while the probability of landing on Z will be 1/3.
So,
Expected number of time E(A) =Number of spins x Probability of landing on A
Expected number of time E(A) = 570 x (2/3)
Expected number of time E(A) = 380
Therefore the Expected number of time E(A) is 380 times.
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A local radio station is running a contest were 35 people have qualified. From these qualifiers, 3 will be randomly selected to win a trip to the Bahamas. How many different possibilities are there for the outcome of this contest?
Answer:
39270
Step-by-step explanation:
When the first person is picked, there is a 1 in 35 chance that it will be Person 1. If they are selected, that leaves 34 people left in the pool. After Person 2 is selected, there are 33 people left in the pool for Person 3.
35*34*33=39270
The architect stands 6 feet from a climbing frame looking up at the top of the frame at an angle of 63.43
The value of the height of the entire climbing frame is 11.99 feet
How to determine the valueTo determine the value, we need to know the different trigonometric identities.
These identities are;
tangentcotangentcosecantsecantcosinesineFrom the information given, we have that;
In the triangle, the parameters are;
Hypotenuse is the distance between the architect and frame
The angle is 63.43
Adjacent is 6 feet
Using the tangent identity, we have;
tan 63.43 = h/6
cross multiply, we get;
h = tan (63. 43) × 6
Find the tangent value and substitute, we have;
h = 1. 99 × 6
Multiply the values, we have;
h = 11. 99 feet
Then, the height of the entire climbing frame is 11. 99 feet
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Complete question:
'The architect stands 6 feet from climbing frame, looking up at the top of the frame at an angle of 63.43" It is 5 and half feet from ground to the architect's eyes: The vertical distance from eye level to the top of the climbing frame is feet: The height of the entire climbing frame is feet:'
if my circular garden requires 2 cups of water per 10 square feet, how many cups of water do i need when the radius is 3 feet
6 yards 2 feet 5 inches equals
Answer:
245 inches
Step-by-step explanation:
Yards->Inches
1 yard = 36 inches
Therefore, 6 yards = 36 x 6 = 216 inches
Feet->Inches
1 feet = 12 inches
Therefore, 2 feet = 2 x 12 = 24 inches
Adding all inches,
=> 216 + 24 + 5
=> 245 inches
I understand the lower and upper class limits but there are only one number but I don't know what to do
The class mark of the modal class is: 25
How to solveFrom the given histogram, the following Frequency Distribution is obtained:
Class Interval Mid point Frequency
625-675 650 3
676-726 701 5
727 - 777 752 7
778 - 828 803 8
829 - 879 854 6
880 - 930 905 2
931 - 981 956 0
982 - 1032 1007 1
b. To find the lower class limit of the first class:
First class: 625
c. The upper limit of the first class is:
First class: 676
The class mark of the modal class is:
The modal class is: 803
The class mark is upper limit + lower limit/2
Thus, 828-778/2
=> 50/2
The class mark of the modal class is: 25
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Find the volume of the cone shown. Use 3.14 for pi. Round your answer to the nearest hundredth.
Answer: 100.48 cubic feet
Step-by-step explanation:
Consider the line y = -8x + 7.
Find the equation of the line that is perpendicular to this line and passes through the point (-5, 3).
Find the equation of the line that is parallel to this line and passes through the point (-5, 3).
The equation of the line that is parallel to the line that passes through the point (7, 6) is y = 8x - 50.
What is a line?A line is an object in geometry that is indefinitely long and has neither breadth nor depth nor curvature.
Since lines can exist embedded in two, three, or higher dimensions environments, they are one-dimensional objects.
The term "line" can also be used to describe a line segment in daily life that contains two locations that serve as its ends.
So, the lines with the same slope but a different y-intercept are said to be parallel.
Therefore, we must use the same slope to plug in the point (7, 6) and solve for the y-intercept.
We thus have:
y = 8x + b
6 = 8(7) + b
6 = 56 + b
b + 56 = 6
b + 56 - 56 = 6 - 56
b = -50
The equation is: y = 8x - 50
Therefore, the equation of the line that is parallel to the line that passes through the point (7, 6) is y = 8x - 50.
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Correct question:
Consider the line y = 8x - 4. Find the equation of the line that is parallel to this line and passes through the point (7, 6).
What type of distribution is pictured in this histogram?
Responses
Bimodal
Normal
Skewed
The type of distribution pictured in this histogram is skewed.
What is a skewed distribution?
A skewed distribution is a statistical distribution that is not symmetrical around its mean or median.
In a skewed distribution, the tail of the distribution is pulled in one direction or the other, resulting in a longer tail on one side than the other.
There are two types of skewed distributions: positively skewed and negatively skewed.
The distribution in the image is positively skewed as its is pulled towards the left.
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Which number is the greatest? 20 -100 -45 50
Find the degree of the monomial. 3a^8b^7
3.4 The rectangular box has the length of 8x² and the breadth of 6x² - 4x 3.4.1 What is the area of the box? 3.4.2 Factorise the area of the box? 3.4.3 If x = 2 what will be the value of the length and the breadth?
Answer:
3.4.1) (8x^2)(6x^2 - 4x) = 48x^4 - 32x^2
3.4.2) 48x^4 - 32x^2 = (16x^2)(3x^2 - 2)
3.4.3) Length = 16(2^2) = 16(4) = 64
Width = 3(2^2) - 2 = 3(4) - 2
= 12 - 2 = 10
Area = 64(10) = 640
If GI and JL are parellel lines and m
The measure of angle IHE is 23°.
Since DF and GI are parallel, we know that angle HJF is congruent to angle GHJ. Therefore, we have:
mHJF = mGHJ = 134°
We can now use this information to find the measure of angle IHE. To do this, we need to use the fact that the sum of the angles in a straight line is 180°. Since H, J, F, and I lie on a straight line, we have:
mHJF + mFJI + mIHE = 180°
Substituting the values we know, we get:
134° + mFJI + mIHE = 180°
Simplifying the equation, we get:
mFJI + mIHE = 46°
We still need to find the measure of angle FJI. To do this, we can use the fact that the angles in a triangle add up to 180°. Triangle GHJ is a straight line, so its angles add up to 180°. Therefore, we have:
mGHJ + mHJF + mFJI = 180°
Substituting the values we know, we get:
134° + mFJI + mFJI = 180°
Simplifying the equation, we get:
2mFJI = 46°
Dividing both sides by 2, we get:
mFJI = 23°
Finally, we can substitute this value back into our earlier equation to find the measure of angle IHE:
mFJI + mIHE = 46°
23° + mIHE = 46°
Subtracting 23° from both sides, we get:
mIHE = 23°
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Complete Question:
If DF and GI are parallel lines and mGHJ = 134°, what is mIHE?
Find the consumers' surplus at a price level of $1 for the price-demand equation
p= D(x) = 20-0.1x
where p is the price and x is the demand. Do not include a dollar sign or any commas in your answer.
The consumers' surplus at a price level of $1 for the price-demand equation is -1072.5.
Given that price-demand equation p= D(x) = 20-0.1x, we need to find the consumers' surplus at a price level of $1.
So,
From the equation we have,
20-0.1x = 1
0.1x = 19
x = 190
Therefore, the equilibrium point = (190, 1) = (xe, Pe)
Now,
Cs = [tex]\int\limits^{x_e}_0 {D(x)} \ dx\, -Pexe[/tex]
[tex]\int\limits^{190}_0 {20-0.1x} \ dx\, -(190)[/tex]
= 20-0.1{9025}-190
= -1072.5
Hence the consumers' surplus at a price level of $1 for the price-demand equation is -1072.5
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Bob has saved $600 each month for the last 3 years
to make a down payment on a house. The account
earned an interest rate of 0.50 percent per month.
How much money is in Bob's account?
Answer:
300
Step-by-step explanation:
Johnny's cafe serves desserts. One serving of ice cream and two servings of blueberry pie provides 790 calories. Three servings of ice cream and two serving of blueberry pie provides 1290 calories
The caloric content for ice cream C is 250 calories while the caloric content for ice cream B is 270 calories.
How to determine the caloric contentTo determine the caloric content, we will assign algebraic notations to each of the dessert types.
1 Icecream + 2 Blueberry pie = 790 calories
3 icecream + 2 Blueberry pie = 1290 calories
Now the first equation will be subtracted from the second equation as follows:
2 icecream = 500 calories
So, 1 ice cream is 250 calories.
Also, since, 1 icecream serving equals 250 calories, 2 Blueberry pies = 790 - 250 = 540 calories, and 1 Blueberry pie equals 270 calories.
Complete question:
Johnny's cafe serves desserts. One serving of ice cream and two servings of blueberry pie provides 790 calories. Three servings of ice cream and two servings of blueberry pie provides 1290 calories. Find the caloric content of each item.
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The cost of a pen is $15. Find the cost of 162 pens
Answer: 15 x 162 = 2430$
Please solve using the given picture
Answer:
61°
Step-by-step explanation:
You want the angle XCA in the figure, given that angle XBA is 70°, and ABCD is a rectangle with AB=5.6m and BC=6.4m. Angles at A are right angles.
DiagonalThe length of diagonal AC is found using the Pythagorean theorem.
AC² = AB² +BC²
AC = √(5.6² +6.4²) = 0.8√113 ≈ 8.504 . . . . meters
HeightThe length XA is found using the tangent function:
Tan = Opposite/Adjacent
tan(B) = XA/AB
XA = AB·tan(B) = 5.6·tan(70°) . . . . meters
AngleThe angle XCA is found from the tangent relation:
tan(XCA) = XA/AC
tan(XCA) = 5.6·tan(70°)/(0.8√113) = 7·tan(70°)/√113
angle XCA = arctan(7·tan(70°)/√113) ≈ 61.07°
The angle XC makes with the horizontal is about 61°.
I need help i don't know how to do this please
The size of matrix cM is given as follows:
9 x 10.
What happens when a matrix is multiplied by a constant?When a matrix is multiplied by a constant, we have that every element in the matrix is multiplied by the constant. Hence, the dimension of the matrix remains constant.
The parameters for this problem are given as follows:
Constant c.Matrix M of dimensions 9 x 10.Hence the size of matrix cM is given as follows:
9 x 10.
(same size as the original matrix, as we simplify multiply each element in the matrix by the constant, hence the dimensions remain the same).
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A company produces two products, A and B. At
least 30 units of product A and at least 10 units of
product B must be produced. The maximum
number of units that can be produced per day is
80. Product A yields a profit of $15 and product B
yields a profit of $8. Let a = the number of units of
product A and b = the number of units of product
B.
What objective function can be used to maximize
the profit?
P=
DONE✔
a+
b
The objective function that can be used to maximize the profit is Profit = 15a + 8b
Let a is the number of units of product A and b is the number of units of product B.
Profit = 15a + 8b
This function represents the total profit earned by producing a units of product A and b units of product B
Given that the profit per unit of product A is $15 and the profit per unit of product B is $8.
To maximize the profit, we would need to find the values of a and b that satisfy the constraints given in the problem and maximize the value of the objective function
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