Elijah invested $530 in an account paying an interest rate of 8 % compounded
continuously, Cafter invested $530 in an account paying an interest rate of 8%
compounded annually. After 11 years, how much more money would Elijah have in
his account than Carter, to the nearest dollar?

Answers

Answer 1

Answer: the answer is $18

Step-by-step explanation:


Related Questions

120 meals to 52 meals what is the percentage change?
hurry!!

Answers

Answer:

56.67

Step-by-step explanation:

I think it is 56.67%

Answer:

The percentage change is 56.67%.

9. A juice glass holds 180mL. If a client drinks 7/2 glasses , how many milliliters did
the client consume? (5 points)

Answers

Answer:

630 ml

Step-by-step explanation:

1 glass contains 180 ml juice

7/2 glasses contains = 180 × 7/2 = 630 ml

Help ASAP!!!!!! Plzzzzzz

Answers

Answer:

2nd option

Step-by-step explanation:

I’ll give brainliest answer to whoever answers first !!!

Answers

Answer:

bottom right

Step-by-step explanation:

the bottom right shows the data

Four people recorded the number of minutes they exercised today. Mackenzie exercised for 3 as many minutes as Brinley. Brinley exercised for 17 fewer minutes than Ariana. Ariana exercised for 3 times as many minutes as Seth Together, Ariana and Mackenzie exercised for 20 more minutes than Brinley and Seth. Let z represent the number of minutes Seth exercised.​

Answers

Answer:

False

True

True

False

Yw hope this helped yall

Step-by-step explanation:

The equation represents this situation is

3x + 1/2 x (3x + - 17) = x + (3x - 17 ) + 20 — False

x = 40 — True

Brinley and Seth exercised for a combined 95 minutes —-True

Mackenzie exercised for 26 minutes. — False

If f(x)=3x^2+2x=1 find f(x+2)​

Answers

Answer:

f(x+2) = 3(x+2)^2 + 2(x+2) + 1

Step-by-step explanation:

Replace x with x+2 and you get the solution above. Hope this helps!

1. The diner sells 4 different sandwiches, 6 different drinks, and 3
different deserts. How many different orders could you place if you
decided to buy a sandwich and a desert?

2. The Downtown Theater has 1 ticket window. In how many ways can 2 people line up to buy tickets?

3. The Downtown Theater has 1 ticket window. In how many ways can 3 people line up to buy tickets?

4. The Downtown Theater has 1 ticket window. In how many ways can 4 people line up to buy tickets?

5. The Downtown Theater has 1 ticket window. In how many ways can 6 people line up to buy tickets?

Answers

Answer:

72

Step-by-step explanation:

because you got to multiply to see what you gone get.

Help answer this question please

Answers

Answer:

no and no

Step-by-step explanation:

1. 9+6 = 15 not 17

2. 9 - 3 = 6 not 5

please leave a like if this answers your question

Please answer the question in the picture

Answers

Answer:

Step-by-step explanation:

use the distance formula

dist = sqrt[ (x2-x1)^2 + (y2-y1)^2 ]

where point one ,P1,  is A and point 2, P2,  is C, so

P1 = (x1,y1) = (-7,3)

P2 =(x2,y2) = (0,6)

then

dist = sqrt[ (0 - (-7))^2 + (6-3)^2 ]

dist = sqrt [ 7^2 + 3^2 ]

dist = sqrt [49 +9 ]

dist = sqrt [58]

dist = 7.6157....

AC = 7.6 ( rounded to nearest tenth)

Help please thank you

Answers

Answer:

In the explanation :)

Step-by-step explanation:

So if we have 1 cup of raisins, then we have 2 1/2 cups of pretzels. Since we doubled the raisins, we double the pretzels as well.

I believe this is right but I'm not sure anymore with today's math

Mathematical logic for this game to make the best

Answers

Answer:

Ok tell me which mathematic game

Quadrilateral PQRS is parallelogram.What is the length of the diagonal SQ?
ST=x^2-8
TQ=3x+2

Answers

Answer:

3x+x^2-6

Step-by-step explanation:

Have a great rest of your day.

Bye

Again I don’t know this . Plz help me

Answers

Answer:

y-2=0(x-3)

Step-by-step explanation:

Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the population of potential clientele have head breadths that are Normally distributed with a mean of 5.9 inches and a standard deviation of 0.8 inches.

According to the 68-95-99.7 rule, we expect 95% of head breadths to be
between blank and blank inches.

Answers

Answer:

We expect 95% of head breadths to be between 4.3 inches and 7.5 inches.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 5.9 inches, standard deviation = 0.8 inches.

We expect 95% of head breadths to be between

Within 2 standard deviations of the mean, so:

5.9 - 2*0.8 = 5.9 - 1.6 = 4.3 inches

5.9 + 2*0.8 = 5.9 + 1.6 = 7.5 inches

We expect 95% of head breadths to be between 4.3 inches and 7.5 inches.

Which expression is equivalent to
y
2

Answers

Answer:

Hello!

Distributive property: a(b+c)=ab+ac

Minus and plus sign.

Then multiply by the numbers.

Hope this helps!

Thanks!

Have a great day!

Step-by-step explanation:

CAN SOMEONE PLEASE ANSWER THIS QUICKLY I DONT GOT TIME​

Answers

Answer:

5/20 x 4/15 =1/15

6/7 x 7/6 =1

2 x 7/10 =7/5

Hope this helps!

Find the domain of the following functions?

Answers

Answer:

d. D: (-∞ , ∞) , R: (-10 , ∞)

Step-by-step explanation:

You select a marble without looking and then put it back. If you do this 6 times, what is the
best prediction possible for the number of times you will pick a purple marble?

Answers

Answer:

One time

Step-by-step explanation:

The probability of picking a purple marble once is 1/6, so if I pick a marble 6  times, then (1/6)*6=1

Mystery Boxes: Breakout Rooms

The boxes below contain 14 numbers, listed in order, of which 6 have been removed. Your job is

to use the clues given to determine the missing numbers. Write your answers in the boxes.

• The mean is 26

• The median is 22

The interquartile range is 20

The mode is 18

. The range is 60

1

4

15

18

29

30

32

58

Answers

Answer:

[tex]\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}[/tex]

Required

Fill in the box

From the question, the range is:

[tex]Range = 60[/tex]

Range is calculated as:

[tex]Range = Highest - Least[/tex]

From the box, we have:

[tex]Least = 1[/tex]

So:

[tex]60 = Highest - 1[/tex]

[tex]Highest = 60 +1[/tex]

[tex]Highest = 61[/tex]

The box, becomes:

[tex]\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}[/tex]

From the question:

[tex]IQR = 20[/tex] --- interquartile range

This is calculated as:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]Q_3[/tex] is the median of the upper half while [tex]Q_1[/tex] is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

Lower half:

[tex]\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}[/tex]

Upper half

[tex]\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}[/tex]

The quartile is calculated by calculating the median for each of the above halves is calculated as:

[tex]Median = \frac{N + 1}{2}th[/tex]

Where N = 7

So, we have:

[tex]Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th[/tex]

So,

[tex]Q_3[/tex] = 4th item of the upper halves

[tex]Q_1[/tex]= 4th item of the lower halves

From the upper halves

[tex]\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}[/tex]

We have:

[tex]Q_3 = 32[/tex]

[tex]Q_1[/tex] can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

[tex]IQR = Q_3 - Q_1[/tex]

Where [tex]Q_3 = 32[/tex] and [tex]IQR = 20[/tex]

So:

[tex]20 = 32 - Q_1[/tex]

[tex]Q_1 = 32 - 20[/tex]

[tex]Q_1 = 12[/tex]

So, the lower half becomes:

Lower half:

[tex]\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}[/tex]

From this, the updated values of the box is:

[tex]\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}[/tex]

From the question, the median is:

[tex]Median = 22[/tex] and [tex]N = 14[/tex]

To calculate the median, we make use of:

[tex]Median = \frac{N + 1}{2}th[/tex]

[tex]Median = \frac{14 + 1}{2}th[/tex]

[tex]Median = \frac{15}{2}th[/tex]

[tex]Median = 7.5th[/tex]

This means that, the median is the average of the 7th and 8th items.

The 7th and 8th items are blanks.

However, from the question; the mode is:

[tex]Mode = 18[/tex]

Since the values of the box are in increasing order and the average of 18 and 18 do not equal 22 (i.e. the median), then the 7th item is:

[tex]7th = 18[/tex]

The 8th item is calculated as thus:

[tex]Median = \frac{1}{2}(7th + 8th)[/tex]

[tex]22= \frac{1}{2}(18 + 8th)[/tex]

Multiply through by 2

[tex]44 = 18 + 8th[/tex]

[tex]8th = 44 - 18[/tex]

[tex]8th = 26[/tex]

The updated values of the box is:

[tex]\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}[/tex]

From the question.

[tex]Mean = 26[/tex]

Mean is calculated as:

[tex]Mean = \frac{\sum x}{n}[/tex]

So, we have:

[tex]26= \frac{1 + 2nd + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 12th + 58 + 61}{14}[/tex]

Collect like terms

[tex]26= \frac{ 2nd + 12th+1 + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 58 + 61}{14}[/tex]

[tex]26= \frac{ 2nd + 12th+304}{14}[/tex]

Multiply through by 14

[tex]14 * 26= 2nd + 12th+304[/tex]

[tex]364= 2nd + 12th+304[/tex]

This gives:

[tex]2nd + 12th = 364 - 304[/tex]

[tex]2nd + 12th = 60[/tex]

From the updated box,

[tex]\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}[/tex]

We know that:

The 2nd value can only be either 2 or 3

The 12th value can take any of the range 33 to 57

Of these values, the only possible values of 2nd and 12th that give a sum of 60 are:

[tex]2nd = 3[/tex]

[tex]12th = 57[/tex]

i.e.

[tex]2nd + 12th = 60[/tex]

[tex]3 + 57 = 60[/tex]

So, the complete box is:

[tex]\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}[/tex]

A tennis ball was thrown from the top of a tall building. The height of the tennis ball above the ground can be found using the function y = -12.5x + 50, where x is the time in seconds the tennis ball has been in the air.
how many seconds did it take the tennis ball to reach the ground?​

Answers

Answer:

t = 4 seconds

Step-by-step explanation:

Given that,

The height of the tennis ball above the ground can be found using the function y = -12.5x + 50

where x is the time in seconds the tennis ball has been in the air.

We need to find how many seconds did it take the tennis ball to reach the ground.

When it reaches the ground, y = 0

So,

-12.5x + 50 = 0

12.5x = 50

x = 4 seconds

So, it will take 4 seconds for the ball to reach the ground.

5
Find the value of x. Show work to prove your answer.
(3x +
18)
93°

Answers

Answer:

x=34.5

Step-by-step explanation:

(3x+18)° and 93° lie along a straight line. The angles in a straight line add up to 180. So:

3x+18+93=`80

2x=180-111

x=69/2

x=34.5

What is the measure of B ?

Answers

Answer: if you add then all up you get 75 so it could be A or D  I don't know if it want the volume and the volume is 75 hope this helped

Step-by-step explanation:

pleas make brainly

Power +, Inc. produces AA batteries used in remote-controlled toy cars. The mean life of these batteries follows the normal probability distribution with a mean of 36 hours. hours and a standard deviation of 5.5 hours. As a part of its quality assurance program, Power +, Inc. tests samples of 9 batteries.
a. What can you say about the shape of the distribution of the sample mean?
b. What is the standard error of the distribution of the sample mean? (Round your answer to 4 decimal places.)
c. What proportion of the samples will have a mean useful life of more than 38 hours? (Round z value to 2 decimal places and final answer to 4 decimal places.)
d. What proportion of the sample will have a mean useful life greater than 34.5 hours? (Round z value to 2 decimal places and final answer to 4 decimal places.)
e. What proportion of the sample will have a mean useful life between 34.5 and 38 hours? (Round z value to 2 decimal places and final answer to 4 decimal places.)

Answers

Answer:

a) By the Central Limit Theorem, it is approximately normal.

b) The standard error of the distribution of the sample mean is 1.8333.

c) 0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d) 0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours

e) 0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 36 hours and a standard deviation of 5.5 hours.

This means that [tex]\mu = 36, \sigma = 5.5[/tex]

a. What can you say about the shape of the distribution of the sample mean?

By the Central Limit Theorem, it is approximately normal.

b. What is the standard error of the distribution of the sample mean? (Round your answer to 4 decimal places.)

Sample of 9 means that [tex]n = 9[/tex]. So

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{5.5}{\sqrt{9}} = 1.8333[/tex]

The standard error of the distribution of the sample mean is 1.8333.

c. What proportion of the samples will have a mean useful life of more than 38 hours?

This is 1 subtracted by the pvalue of Z when X = 38. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{38 - 36}{1.8333}[/tex]

[tex]Z = 1.09[/tex]

[tex]Z = 1.09[/tex] has a pvalue of 0.8621

1 - 0.8621 = 0.1379

0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d. What proportion of the sample will have a mean useful life greater than 34.5 hours?

This is 1 subtracted by the pvalue of Z when X = 34.5. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{34.5 - 36}{1.8333}[/tex]

[tex]Z = -0.82[/tex]

[tex]Z = -0.82[/tex] has a pvalue of 0.2061.

1 - 0.2061 = 0.7939

0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours.

e. What proportion of the sample will have a mean useful life between 34.5 and 38 hours?

pvalue of Z when X = 38 subtracted by the pvalue of Z when X = 34.5. So

0.8621 - 0.2061 = 0.656

0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

The Lazy River has a current of 5 miles per hour. A motorboat can travel 20 miles
down the river in and back in 3 hours. What is the speed of the boat in still water?
Please show your work and use table to relate time, speed, distance.

Answers

Answer:

5 mph

Step-by-step explanation:

Answer:

15 mph = rate of boat in still water

Step-by-step explanation:

D = RT

Let R = rate of boat in still water

Rate down stream = R + 5

Time down stream = 20/(R + 5)

Rate upstream = R - 5

Time upstream = 20/(R - 5)

Total time = 20/(R + 5) + 20/(R - 5) = 3

                    20(R - 5) + 20(R + 5) = 3(R + 5)(R - 5)

                     20R - 100 + 20R + 100 = 3R^2 - 75

                                  3R^2 + 40R - 75 = 0

                                  (3R + 5)(R - 15) = 0

                                      R = -5/3  or  15

Rate cannot be negative, so R = 15 mph = rate of boat in still water  

           

which of the following is written as a rational function

Answers

What??????????????????????

Answer:

f(x)=x-5/3x

Step-by-step explanation:

Need help with this if possible ​

Answers

Answer:

hope it helps...

Step-by-step explanation:

A bag contains hair ribbons for a spirit rally. The bag contains 18 black ribbons and 2 green ribbons. Lila selects
a ribbon at random, then Jessica selects a ribbon at random from the remaining ribbons. What is the probability
that Lila selects a black ribbon and Jessica selects a green ribbon? Express your answer as a fraction in
simplest form

Answers

1/18 1/2 or 2/18 2/2

Answer:

9/95

Step-by-step explanation:

just had an exam on it

hope this helps:)

Photo Attached
Please Help ASAP

Answers

Answer:

C

Step-by-step explanation:

A is just the opposite value of the second integral.

B is just 3 times the first.

D-you can write a sum of integrals over the same intervals as one integral of the sum of the integrands of those integrals over that same interval. The answer would be 3(8)+-2.

For choice C, we would need more information.

Individual gas mileages (in miles per gallon) of Model Extra SS (Extra Super-Sporty) sedans are normally distributed with a population mean of 20 and a population standard deviation of 2. Based on these information, if you bought a Model Extra SS sedan, what is the probability that the gas mileage (in miles per gallon) of your single, individual sedan is between 19.5 and 20.5

Answers

Answer: 0.1974

Step-by-step explanation:

Let X be a random variable that denotes the gas mileage (in miles per gallon) of the individual sedan.

Given: Population mean: [tex]\mu=20[/tex]

Standard deviation: [tex]\sigma=2[/tex]

The probability that the gas mileage (in miles per gallon) of your single, individual sedan is between 19.5 and 20.5:

[tex]P(19.5<x<20.5)=P(\dfrac{19.5-20}{2}<\dfrac{x-\mu}{\sigma}<\dfrac{20.5-20}{2})\\\\=P(-0.25<z<0.25)=2P(0.25)-1 [P(-z<Z<z)=2P(Z<z)-1]\\\\=2(0.5987)-1=0.1974[/tex]

The required probability=0.1974

help plssssssssssssssssss

Answers

1). 2/3

2). 5/7

3). 2/3
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