Answer: summer
Explanation:
In June, when the Earth is tilted towards Sun and the Sun reaches its highest point in the sky, that is called the summer solsticeand is the longest day of the year.
(figure 1)shows the wave function of an electron in a rigid box. The electron energy is 14. 5 ev. You may want to review (page 1151)
The energy of an electron in a rigid box when it is in the next higher state is 19.6 eV
What is electron energy?The energy carried by the electron when jumping from one energy level to another is called as electron energy.
Energy in the nth level for a rigid box of length L and mass of electron m is represented as
[tex]E_{n} = \dfrac{n^2{h^{2} } }{8mL^{2} }[/tex]
As the energy is proportional to n².
[tex]\dfrac{E_{n+1} }{E_{n} } =(\dfrac{n+1}{n} )^{2}[/tex]
Substitute the value 3 for n in the above equation. So, we have the energy of an electron is
E₄ = 19.6 eV
Thus, energy of electron in a rigid box when it is in the next higher state is 19.6 eV.
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How many stars has been observed by Hubble telescope till now ?
Answer:
More Than 1.3 million.
Hope it helps :))
Directions: identify the input work and output work in the different situations.
1. A cyclist is pedaling on his bicycle.
2. You exert force to move a rake.
3. You sweep the dry leaves in your garden using bamboo.
4. Lifting a handless wheelbarrow.
5. Ben lifts the 50 kgs weight of barbel.
Answer:
it would have to be 1 or maybe 2
Consider a pendulum of length 3. 171 m. The acceleration of gravity is 9. 832 m/s2. A) what is its period at the north pole?answer in units of s
The period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
What is time period of pendulum?Pendulum is the body which is pivoted to a point and perform back and forth motion around that point by swinging due to the influence of gravity.
The time period of a pendulum is the time taken by it to complete one cycle of swing left to right and right to left.
It can be given as,
[tex]T=2\pi \sqrt{\dfrac{L}{g}}[/tex]
Here, (g) is the gravitational force of Earth and (L) is the length of the pendulum.
A pendulum of length 3.171 m. The acceleration of gravity is 9.832 m/s2. The period at the north pole is,
[tex]T=2\pi \sqrt{\dfrac{3.171}{9.832}}\\T=3.57\rm\; s[/tex]
Thus, the period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
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5) Select the best answer.
Which object will accelerate faster?
an object that has 500 N of force applied to it
an object that has 50 N of force applied to it
Answer:
I think the object with 500 N of force applied.
Energy from the sun drives the _ of the water from the ocean surface. As the air moves up the west side of the mountain, the water vapor cools and undergoes _ . The force of gravity causes the _ of the water from the cloud. Choices for the _ are condensation, evaporation, precipitation
Answer: The air is full of water, as water vapor, even if you can't see it. Condensation is the process of water vapor turning back into liquid water, with the best example being those big, fluffy clouds floating over your head. And when the water droplets in clouds combine, they become heavy enough to form raindrops to rain down onto your head.
Explanation:
‼️PLEASE ANSWER WILL MARK BRAINLIEST‼️
Answer:
b 1000
if you multiply 2m/s by 500 you get 1000 it should look like this.
500 x 2m/s
Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is
The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.
What is pascal law?Pressure applied to a closed system of fluid will be transfer at each point of the fluid and the boundaries of the system.
Let suppose at the two point of such system the input force apllied is F₁ and output force we get is F₂. The area of this points is A₁ and A₂ respectively. As the pressure at both point is same. Then by the pascal law,
[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\[/tex]
In case of radius,
[tex]\dfrac{F_1}{\pi r_1^2}=\dfrac{F_2}{\pi r_2^2}\\\\\dfrac{F_1}{r_1^2}=\dfrac{F_2}{ r_2^2}[/tex]
Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. Thus,
[tex]r_1=2.67\rm\; cm[/tex]
[tex]r_2=20.0\rm\; cm[/tex]
The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is The force applied on second piston is,
[tex]F_2=mg\\F_2=2000\times9.81\\F_2=19620 \rm\; N[/tex]
Put the values in the above formula,
[tex]\dfrac{F_1}{2.67^2}=\dfrac{19620}{20^2}\\F_1=\dfrac{19620\times2.67^2}{20^2}\\F_1\approx 350\rm\; N[/tex]
Thus, the downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.
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A proton and an antiproton have equal energies of 450gev. The particles collide head-on. Find the available energy ea. The rest energy of the proton is 938mev
The available energy ea when the proton and the antiproton have equal energies of 450gev is 29 GeV.
How to find the available energy after the collision?The available energy can be found out with the following formula.
[tex]E_a=\sqrt{2E_tE_k++(m_1c^2)^2+(m_2c^2)^2}[/tex]
Here C is the speed of light (3×10⁸ m/s), Et is the energy of proton, Ek is the rest energy.
A proton and an antiproton have equal energies of 450gev. The particles collide head-on. The rest energy of the proton is 938mev
Thus, put the given values in the above formula,
[tex]E_a=\sqrt{2(450\times\dfrac{10^9eV}{1MeV})(938\times\dfrac{10^6eV}{1MeV})+(938\times\dfrac{10^6eV}{1MeV})^2+(938\times\dfrac{10^6eV}{1MeV})}\\E_a=29\rm\; Gev[/tex]
Thus, the available energy ea when the proton and the antiproton have equal energies of 450gev is 29 GeV.
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The formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of which function(s)? tangent only cosine only sine and tangent cosine and sine
The formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of tangent, cosine and sine.
What is vertical motion of a projecile?The vertical motion of a projectile is affected by gravity and the velocity of vertical motion given by the following formula;
Vy = Vsinθ
What is horizontal motion of a projecile?The horizontal velocity of a projectile is given by the following formula;
Vx = Vcosθ
Direction of the motionThe direction of the motion is calculated as follows;
tanθ = Vy/Vx
Thus, the formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of tangent, cosine and sine.
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Answer:
d
Explanation:
edg 2022
The Andromeda Galaxy (our nearest spiral neighbor) has spectral lines that show a blue shift. From this we may conclude that:
The universe is the collection of galaxies, The Andromeda Galaxy has spectral lines with blue shift. The conclusion is that the Universe has stopped expanding.
What is Andromeda Galaxy?The Andromeda Galaxy is the nearest spiral neighbor that has spectral lines showing a blue shift.
Therefore, this concludes that, the Universe has stopped expanding. This galaxy is slowly shifting towards us.
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at 20° c, 33 meters of copper wire has a restaurants of 0.6 ohms. what is the resistance of 165 meters?
Resistance for 165 metres is 3 ohms.
The dark fringe for m = 0 in a young's double-slit experiment is located at an angle of θ = 15°. What is the angle that locates the dark fringe for m = 1?
Answer:
51°
Explanation:
dark fringe equation = dsinθ = (m + 1/2)λ
sinθ = [(m + 1/2)λ]d
sinθ1 = [(m + 1/2)λ]d
sinθ1/sinθ = [(m + 1/2)(λ/d)] / [[(m + 1/2)(λ/d)] = [(m + 1/2)] / [(m + 1/2)]
sinθ1 = [(m + 1/2)] / [(m + 1/2)] (sinθ)
sinθ1 = [1+1/2]/[0+1/2] (sin15)
sinθ1 = 3sin15
sinθ1 = 0.77645
θ1 = sin^-1( 0.77645)
θ1 = 50.94° = 51°
The dark fringe for m = 0 in a young's double-slit experiment is located at an angle. The angle that locates the dark fringe for m = 1 is 51°.
What is dark fringe?When light passes through a slit , it produces a spectrum which can be seen on the screen kept a distance in form of fringes of different intensity. The fringe with intensity zero is called the dark fringe.
Given is the angle θ = 15°
The equation for the dark fringe is
d sinθ = (m + 1/2)λ
For m= 0 and m=1, the ratio of the sines is
sinθ₁/sinθ₀ = [(m + 1/2)] / [(m + 1/2)]
Rearranging for sinθ₁, we have
sinθ₁ = [(m + 1/2)] / [(m + 1/2)] (sinθ₀)
Substituting the values into the equation and solving for θ₁
sinθ₁ = [1+1/2]/[0+1/2] (sin15)
θ₁ = 51°
Thus, the angle that locates the dark fringe fro m = 1 is 51°.
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A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Another green arrow starts where the first arrow touched the wall and goes up and left at the same shallow angle. As the wave interacts with a wall, which kind of wave interaction is shown? absorption diffraction refraction reflection
Answer:
reflection
Explanation:
Answer: Reflection
Explanation: I have my ways :>
1. As a person stands on earth they put a force on the ground and the ground puts a force on them.
How do these forces compare?
2. The sheet on your bed gives negative charged electrons to your blanket on your bed. If both objects
started this interaction as neutral, what is the charge of the sheet now?
3. A batter swings a Louisville Slugger Baseball bat that has a charge of +12, while a pitcher throws a
baseball with a charge of -2. What is the net charge of the two objects in this scenario?
4. In the bat and ball example (above in question 3), what will the charge of the ball be after the batter
hits it with the bat?
5. We know that opposite charges attract each other, but according to Coulomb's Law what is the single
most important factor in the strength of these forces?
Answer:
mb
Explanation:
m b
Just as water flows from a region of high pressure to a region of low pressure, electric charge flows from a region of:.
Due to concentration difference, electric charge flows from a region of high electric potential to a region of low electric potential.
How electric charge move?Electric charge flows from a region of high electric potential to a region of low electric potential because of concentration difference. This movement is same as the diffusion in which molecules move from high concentration to lower concentration.
So we can conclude that due to concentration difference, electric charge flows from a region of high electric potential to a region of low electric potential.
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Help!
11. A string vibrates at a frequency of 15 Hz. What is its period?
12. A speaker vibrates at a frequency of 292 Hz. What is its period?
13. A swing has a period of 12 seconds. What is its frequency?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
As we know, period (t)of a wave and it's frequency (f) are Reciprocal of each other, so if one is know then we can just reverse the order to get the other one.
that is :
[tex]\qquad \sf \dashrightarrow \: frequency = \dfrac{1}{period} [/tex]
Now, let's move on to problems ~
# 11. f = 15 hertz, t = ?
[tex]\qquad \sf \dashrightarrow \: t = \dfrac{1}{15} \: \: sec[/tex]
[tex]\qquad \sf \dashrightarrow \: t \approx0.067 \: \: sec[/tex]
#12. f = 292 hertz, t = ?
[tex]\qquad \sf \dashrightarrow \: t = \dfrac{1}{292} \: \: sec[/tex]
[tex]\qquad \sf \dashrightarrow \: t \approx0.0034 \: \: sec[/tex]
#13. t = 12 seconds, f = ?
[tex]\qquad \sf \dashrightarrow \: f= \dfrac{1}{12} \: \: hertz[/tex]
[tex]\qquad \sf \dashrightarrow \: f \approx0.083 \: \: hertz[/tex]
We know that, frequency = reciprocal of the period of time an object swings or vibrates at. Therefore,
[tex]\tt\:FORMULA \downarrow\\\\\star\boxed{\mathfrak{Frequency = \frac{1}{period \: of \: time}}}[/tex]
Now, let's solve the questions by using this formula.
[tex]\rule{150pt}{2pt}[/tex]
11. Frequency = 15 Hz
Period = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:15 = \frac{1}{period}\\\boxed{\bf\:period = \frac{1}{15} = 0.67 \: s}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
12. Frequency = 292 Hz
Period = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:292 = \frac{1}{period}\\\boxed{\bf\:period = \frac{1}{292} = 0.0034 \: s}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
13. Period = 12 s
Frequency = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:Frequency = \frac{1}{12}\\\boxed{\bf\:Frequency = 0.083 \: Hz}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
Note:The SI units of,
Frequency = Hertz (Hz)Period of time = Second (s / sec)[tex]\rule{150pt}{2pt}[/tex]
Motion is a change in
1.Time
2.Speed
3.Position
4.Velocity
Motion is a change in position measured by distance and time.
What are the minimum energies of the two oppositely directed gamma rays in a PET procedure?
The minimum energy of the two oppositely directed gamma rays in a PET procedure is : 0.51 MeV
What happens in a PET procedure ?In a PET procedure when an electron and positron collide the energy equivalent of their individual masses are converted into gamma rays which will move in directions opposite to each other.
Given that an electron and a positron posses equal masses the minimum energy of the gamma ray will be 0.51MeV
Hence we can conclude that the minimum energy of the two oppositely directed gamma rays in a PET procedure is 0.51MeV.
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An astronaut is weighed before he sets off to the Moon. He has a mass of 80 kg.
What will his weight be on Earth?
formula
weight= mass×gravity
weight=80×10=800
When white light shines on a thin film of soap, light is reflected from:.
When white light shines on a thin film of soap, light is reflected from back surface of the film only.
What is doppler shift?Doppler Shift is the change in frequency of sound based on the observer’s point of view.
When white light falls on a thin film of soap, light gets reflected and refracted inside the soap. This results in refraction of the reflected light rays.
When white light shines on a thin film of soap, light is reflected from the back surface of the film only.
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Can someone please answer this, ill give you brainliest Would be very appreciated.
Answer:
frost wedging
Explanation:
When glaciers melt and the rock beneath is weathered and broken down, this is called frost wedging.
A beach ball is rolling in a straight line toward you at a speed of 9 m/sec. it's momentum is 3 kg.m/sec. what is the mass of the beach ball?
Answer:
1/3 kg
Explanation:
Concepts
The formula p = mv tells us that momentum is mass times velocity. We can easily rearrange this equation to solve for m by dividing both sides by v:
p/v = mv/vm = p/vApplication
We are asked to find the mass of a beach ball, given the velocity as 9 m/s and the momentum as 3 kg · m/s. We can use the formula m = v/p to find the mass of the ball in kilograms.
Solution
[tex]m = \frac{3}{9}[/tex] [tex]m = 1/3[/tex]Starting at a position of 10m [W] of your car, you run to a position of 150m [W] of your car in 35s. What was your
velocity?
Answer:
4 m/s
Explanation:
you moved 140 meters in 35 seconds
v = 140 / 35 = 4 m/s
What is the speed of a wave with a frequency of 2 Hz and a wavelength of 87 m? 0. 023 m/s 43. 5 m/s 89 m/s 174 m/s.
Can someone please answer this, ill give you brainliest Would be very appreciated.
Thermal stress is a type of (options, chemical, mechanical, biological) weathering.
Answer:
mechanical
Explanation:
Thermal stress is a type of mechanical weathering. This occurs due to breakdown of rocks which takes place via expansion and/or contraction induced by heating and/or cooling.
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball initially moving in the same direction at a spe
Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
What is conservation of momentum?Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,
[tex]m_1u_1 + m_2u_2 = (m_1+m_2)v[/tex]
Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,
[tex]v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}[/tex]
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,
[tex]v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}[/tex]
Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,
[tex]v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s[/tex]
Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
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Please help help help mee
Answer:
.60 A
Explanation:
The RMS (Root Mean Square) voltage (the effective voltage) of the PEAK voltage is .7 * peak
.7 * 425 = 297.5 v
Now, V = IR re-arranged to V/R = I
297.5 v / 500 ohm = .595 A = ~ .6 A
Two cats are sitting on a 30 m hill. One cat
has a mass of 4 kg and the other 6 kg.
Which cat has greater potential energy?
Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
Note:gravitational field in Earth is 10 N/kg = fixed unit
Given:1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
Solve for g.p.e:1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm
The acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
What is center of mass?The center of mass of a object or for a system of object is the point, where the center of distribution of mass in space. The center of mass for the two bodies can be given as,
It can be given as,
[tex]x_{cm}=\dfrac{m_1x_1+m_2x_2}{m_1+m_2}[/tex]
Here, (m) represents the mass and (x) represents the distance.
The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm has to be find out.
The image of the blocks-string-pulley system is attached below. The acceleration of this system is,
[tex]\vec a_{cm}=\left(\dfrac{m_1-m_2}{m_1+m_2}\right)g[/tex]
Thus, the acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
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