DOES THE THE NUMBER LINE GOES ON FORVEVER

Answer: 10

Step-by-step explanation:

The sum of the roots is [tex](5+3i)+(5-3i)=10[/tex], so the answer is 10

The marked angle can be named in two different ways as: ∠HFG and ∠GFH.

To name an angle, the letter representing the vertex would always be at the middle.

Given the angle marked in the image below, where F is the vertex, we can name the marked angle in two different ways with F at the center as:

∠HFG and ∠GFH

Thus, the two different ways to name the marked angle are:

∠HFG and ∠GFH.

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Answer:

The correct option is;

B. Rolling a die; 1 or 2 represents door A, 3 or 4 represents door B, and 5 or 6 represents door C

Answer:

4 inches

Step-by-step explanation:

In a regular pentagon, all sides are equal in length

The converse of the statement will be : if x^2 = 100 then x = -10, which is not true.

In order to write a converse of a conditional statement "p then q",  will be "q then p" the hypothesis and conclusion interchanges.

Then the converse of the statement will be :

if x^2 = 100 then x = -10,

which is not true.

Since , x = +10, then x^2 = 100

Therefore, if x^2 = 100 then x = -10, which is not true.

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Step-by-step explanation:

10 that's what my teacher told me

Answer:

it is 2 spaces away. a positive number from zero would be +2 and a negative number would be -2

Step-by-step explanation:

The answer to the question on Parallelograms being rectangles is that; No; the diagonals may not be congruent

1) We cannot conclude that the parallelogram is a rectangle but we can say that all rectangles are parallelograms.

2) The explanation for number 1 above is that the parallelogram's diagonals may not be equal or congruent but in rectangles diagonals are always equal and bisect each other.

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Answer:

First Image:         Option D

Second Image:   Option D

Third Image:       Option C

Fourth Image:     Option B

Fifth Image:         Option B

Step-by-step explanation:

First Image:

Second Image:

Third Image:

Fourth Image:

Fifth Image:

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Multiply by 9/25 to make the coefficient of the variable 1 the answer is 9/25.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have a given linear equation.

After solving the linear equation we get:

[tex]\rm \dfrac{25}{9}x = 25[/tex]

To make the coefficient of the variable 1

Multiply by 9/25 on both sides.

[tex]\rm \dfrac{9}{25}\times\dfrac{25}{9}x = 25\times \dfrac{9}{25}[/tex]

x = 9

Thus, multiply by 9/25 to make the coefficient of the variable 1 the answer is 9/25.

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Answer: the answer is 9/25

Step-by-step explanation: Multiplying both sides of the equation by 9/25 isolates x

Answer:

D

Step-by-step explanation:

To find angle B, you should subtract 62 from 90 since because a right angle is 90 degrees.

C and A

X = at least 45 and more

This means we need to have a full closed dot.

It's A because the question says more than 75 ft meaning only open dots.

If the function is reflected over the y-axis and then translated down 2 units. the resulting function will be -∛x - 2

Transformation is a technique used to change the position of an object on an xy-plane.

Given the function y = ∛x

If the function is reflected over the y-axis and then translated down 2 units to form f(x), the resulting function f(x) will be:

f(x) = -∛x - 2

The graph of the resulting function is attached

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Answer:

B

Edge 2023

The other answer is incorrect!!!

Answer:

Slope: 10

Y-intercept: +9

Step-by-step explanation:

An equation written in slope-intercept form is y=mx+b. "m" is your slope and b is your y-intercept.

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The solution will be x= -10

Simplifying the given expression

[tex]1.8(1.1x - 1.3) - 1.88 = - 24.02[/tex]

Step1: Convert decimal to fraction

[tex]1.8( \frac{11x}{10} - 1.3) - 1.88 = - 24.02[/tex]

[tex]1.8( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]

[tex]\frac{18}{10} ( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]

Step2: Make denominator common

[tex]\frac{18}{10} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]

Step3: Simplifying the fraction

[tex]\frac{9}{5} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]

Step4: Make denominator common

[tex] \frac{9(11x - 13)}{5 \times 10} - \frac{1.88 \times 50}{50} = - 24.02[/tex]

[tex] \frac{9(11x - 13)}{50} - \frac{94}{50} = - 24.02[/tex]

[tex] \frac{9(11x - 13 - 94)}{50} = - 24.02[/tex]

[tex] \frac{99x - 117 - 94}{50} = - 24.02[/tex]

Step5: Simplifying

[tex] \frac{99x - 211}{50} = - 24.02[/tex]

[tex] 99x - 211 = - 24.02 \times 50[/tex]

[tex] 99x - 211 = - 1201[/tex]

[tex] 99x = - 1201 + 211[/tex]

[tex] 99x = - 990[/tex]

[tex] x = \frac{ - 990}{99} [/tex]

[tex]x = - 10[/tex]

Hence, the solution x=-10

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Answer:

V = 9 in^3

Step-by-step explanation

Comment

The formula for a Pyramid of any B is V = B * h / 3. You have to be able to calculate the Base or just be given in it.

In this case the Base is a triangle. So the first thing needed is the area of the base.

Base

Area_triangle = base length * height / 2

Neither the Base length nor the height need to be the same as the B and h used for the volume of the Pyramid

Givens

b = 4 inches

h = 1.5 inches

Area_triangle = 4 * 1.5 / 2

Area_triangle = 2 * 1.5

Area_triangle = 3 inches^2

Solution

Base (triangle) Area = 3

h = 9

V = B * h / 3  

V = 3 * 9 / 3

V = 9 cubic inches

Answer V = 9 in^3

A function assigns the values. The value of f(-3) and f(3) + f(-3) is 8 and -8, respectively.

A function assigns the value of each element of one set to the other specific element of another set.

Given the function f(x)=-x²-4x+5, therefore, the value of f(x) when the value of x is -3 is,

f(-3) = -(-3)² - 4(-3) + 5

f(-3) = -9 + 12 + 5

f(-3) = 8

Now, the value of f(x) when the value of x is 3 is,

f(3) = -(3)²-4(3)+5

f(3) = - 9 - 12 + 5

f(3) = -16

further, the value of f(3) + f(-3) is,

f(3) + f(-3) = -16 + 8

f(3) + f(-3) = -8

Hence, the value of f(-3) and f(3) + f(-3) is 8 and -8, respectively.

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Jessica sells = 240 books,

Josh sells = 16 books.

The price of one book is = $15

Jessica sold 15 times more books than Josh.

In total, they have sold 256 books.

We can easily find the answer using variables.

Let,

Josh sold a total of x books whereas Jessica sold a total number of 15x books.

together they sold 16x books.

So we can form the equation

16x= 256

by solving this equation we will get x=16

So, Josh sold 16 books and Jessica sold 16×15=240 books in total.

Answer:

Jessica=240

Josh=15

Step-by-step explanation:

Answer:

14.30

Step-by-step explanation:

6.50/5=1.3

so one ice cream is 1.30 pounds

1.30X11=14.3

so 11 ice creams is 14.30 pounds

The price elasticity of demand for this product is approximately will be 1.

The price elasticity is given as

[tex]\rm PE = \dfrac{\dfrac{Q_f-Q_i}{Q_f+Q_i}}{\dfrac{P_f-P_i}{P_f+P_i}}\\\\\\[/tex]

The quantity of a good demanded rises from 1000 to 1500 units when the price falls from $1.50 to $1.00 per unit.

The price elasticity of demand for this product is approximately will be

[tex]\rm PE = \dfrac{\dfrac{1500-1000}{1500+100}}{\dfrac{1.5-1}{1.5+1}}\\[/tex]

On further solving, we have

PE = (500 / 2500) x (2.5 / 0.5)

PE = 1

The price elasticity of demand for this product is approximately will be 1.

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Answer:

Domain = x ≥ 0

Range = y ≥ 20

Step-by-step explanation:

The equation in slope-intercept form would look like this:

y = 4x + 20

The slope is $4 because that is the money that can be made depending on the week. Because he received a random $20 at the beginning, this is just an additional income.

                     ---------------------------------------------------------------------------

In this scenario, the domain (x-values) represent the number of weeks. The range (y-values) represent the total money made.

So the domain is asking, what is the lowest/highest amount of weeks he can save for? We know the number of weeks cannot be negative because he can't save for negative weeks. However, he could save for zero weeks. He can be saving for theoretically infinite weeks. Therefore, the domain is x ≥ 0.

The range is asking, how much money can he save? Since he starts out with a baseline of $20, this is the lowest amount of money he can have. If he were to save for an infinite amount of weeks, he could make an infinite amount of money. Therefore the range is y ≥ 20.

a) When x = -2, g(x) = 5.

b) When x = -4, g(x) = 7.

c) When g(x) = 6, x = -3

d) When g(x) = -1, x = 4

Answer: [tex]5\frac{1}{4}[/tex] gallons are left

Step-by-step explanation:

convert to mixed number...

[tex]8\frac{3}{4} = \frac{35}{4}[/tex]

[tex]3 \frac{1}{2} = \frac{7}{2}[/tex] or [tex]\frac{14}{4}[/tex]

[tex]\frac{35}{4} -\frac{14}{4}=\frac{21}{4}[/tex]

[tex]\frac{21}{4} =5\frac{1}{4}[/tex]

therefore, [tex]5\frac{1}{4}[/tex] gallons are left in Ms. Mather's fuel tank

Answer:

5 1/4 gallons are left... correct

Answer

T-axis of his graph should go from 0 to at least 720, and the h-axis of his graph should go from 0 to at least 40.

Explanation

We know form our problem that  is the total pay,  is the number of hours, and $18 is the rate per hour, so putting it all into an equation we get:

We also know that James works between 25 and 40 hours each week, so we can replace the number of hours in our equation to get how much he can make per week:

- For

- For

Now we know that he can make between $450 and $720 working between 25 and 40 hours per week. So, to best show this information the T-axis should go from 0 to at least 720; otherwise, we won't be able to show values between $450 and $720. Similarly, the h-axis should go form 0 to at least 40; otherwise, we wont be able to show values between 25 and 40 hours.

It looks like you're talking about the indefinite integral

[tex]\displaystyle \int t^2 e^{-10t} \, dt[/tex]

Integrate by parts:

[tex]\displaystyle u\,dv = uv - \int v\,du[/tex]

Let

[tex]u = t^2 \implies du = 2t \, dt[/tex]

[tex]dv = e^{-10t} \, dt \implies v = -\dfrac1{10} e^{-10t}[/tex]

Then

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \int t e^{-10t} \, dt[/tex]

Integrate by parts again, this time with

[tex]u = t \implies du = dt[/tex]

[tex]dv = e^{-10t} \, dt \implies v = -\dfrac1{10} e^{-10t}[/tex]

Then

[tex]\displaystyle \int t e^{-10t} \, dt = -\frac1{10} t e^{-10t} + \frac1{10} \int e^{-10t} \, dt[/tex]

Putting everything together, we get

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \int t e^{-10t} \, dt[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \left(-\frac1{10} t e^{-10t} + \frac1{10} \int e^{-10t} \, dt\right)[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} + \frac1{50} \int e^{-10t} \, dt[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} + \frac1{50} \left(-\frac1{10} e^{-10t}\right) + C[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} - \frac1{500} e^{-10t} + C[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = \boxed{-\frac{e^{-10t}}{500} \left(50t^2 + 10t + 1\right) + C}[/tex]

Answer:

740

Step-by-step explanation:

$415-$230=$185

$185×0.25=740 max miles

Answer:

(-5, -6)

Step-by-step explanation:

The smaller integer is x.

The larger integer is x + 1.

x + 1 = 7 + 2x

-x = 6

x = -6

x + 1 = -6 + 1 = -5

Answer: (-5, -6)

The mean and standard deviation of the x sampling distribution for each of the following sample sizes will be [tex]N(100,10/\sqrt{41} ), N(100,10/\sqrt{130} )[/tex].

Suppose X has a distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma,[/tex]then,

the distribution of the mean of samples of size n, drawn from the values of X, is normally distributed with a mean equal to the mean of X, and a standard deviation equal to [tex]\sigma/\sqrt{n}[/tex]

Symbolically, we write it as:

[tex]X \sim N(\mu, \sigma) \implies \overline{X} \sim N(\mu,\sigma/\sqrt{n} )[/tex]

A random sample is selected from a population with a mean = of 100 and a standard deviation = of 10.

The mean and standard deviation of the x sampling distribution for each of the following sample sizes.

If N=41

[tex]X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{41} )[/tex]

If N=130

[tex]X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{130} )[/tex]

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