pls help! What is N for CLO3- ?
Answer:
There is no molecule or ion as ClO3. The correct formula of chlorate ion is ClO3-.
Compare the ionization energies of each pair of atoms. Enter the symbol for the atom with the larger ionization energy.
(If both atoms would be expected to have the same ionization energy, enter the word same.)
Pairs Symbol of atom with the larger ionization energy
Cl and I
Na and K
F and Br
Answer: 1. I
2. Na
3. F
Explanation:
Ionization energy is the energy required to remove the most loosely bound electron from an isolated gaseous atom.
In a group, the ionization energy decreases as we move down a group as the size increases. The electrons get added to the next shell. Thus the valence electron moves far from the nucleus and thus less energy is required to remove the valence electron.
1. Cl and I: Cl will have larger ionization energy as I lies lower in the group.
2. Na and K : Na will have larger ionization energy as K lies lower in the group
3. F and Br : F will have larger ionization energy as Br lies lower in the group.
28.
Hormones:
A. are released into the interstitium.
B. require target cell receptors to illicit a target cell response.
C. are always proteins.
Only A & B are correct
Answer: I believe that B) require target cell receptors to illicit a target cell response, is the right answer.
Explanation:
The earths magnetic poles are located in different areas close to its geographic poles?
a.) true
b.) false
Answer:
Explanation:
The answer is true
Answer:I think the answer is true
Explanation:
c5h12 with one tertiary carbon
Answer:
See attached image.
Explanation:
Hello there!
In this case, according to the isomeric structure of hydrocarbons, it is possible to draw a five-carbon hydrocarbon with a tertiary carbon by keeping in mind these tertiary carbons are characterized by the presence of three bonds with carbon atoms.
In such a way, as shown on the attached image, the second carbon from left to right is tertiary because of the aforementioned, and also, the compound has five carbon atoms and twelve hydrogen atoms.
Best regards!
3.
Balance the following reactions.
i)
Mg +
HCI →
MgCl2 +
H2
ii)
Mg(OH)2 +_
HCI →
MgCl2 +
H20
AgNO3 +
K3PO4 →
Ag3PO4 +
KNO3
iv)
H2SO4 +
Pb(OH)4 →
Pb(SO4)2 +
H2O
v)
Ca (OH)2 +
H3PO4 →
Ca3(PO4)2 +
H20
Answer: i) [tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]
ii) [tex]Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O[/tex]
iii) [tex]3AgNO_3+K_3PO_4\rightarrow Ag_3PO_4+3KNO_3[/tex]
iv) [tex]2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+4H_2O[/tex]
v) [tex]3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+6H_2O[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical reactions will be:
i) [tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]
ii) [tex]Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O[/tex]
iii) [tex]3AgNO_3+K_3PO_4\rightarrow Ag_3PO_4+3KNO_3[/tex]
iv) [tex]2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+4H_2O[/tex]
v) [tex]3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+6H_2O[/tex]
An orgo lab student named Bob wanted to synthesize an isoamyl acetate ester because it smells like bananas and he really likes to sniff it. He heated 7.50 grams of isoamyl alcohol (3-methyl-1-butanol) with 22.5 grams of acetic acid (ethanoic acid) and 4.50 grams of sulfuric acidto prepare his favorite ester. Based on these numbers, how many grams of isoamyl acetateshould he theoretically obtain
Answer:
The answer is "11.07 g".
Explanation:
Isoamyl alcohol is a reagent restriction
Isoamyl alcohol Moles:
[tex]= \frac{7.5}{88.15} \\\\ =0.085[/tex]
Moles only with the shape of isoamyl acetate are equivalent to numbers.
Isoamyl acetate grams:
[tex]= 0.085 \times 130.19\\\\ = 11.07 \ g[/tex]
This is a freebie for anyone for one get the crown
Answer:
hhh
Explanation:
Why do gas molecules move at different speeds at a given temperature?
Answer:
Gas molecules move at different speed at a given temputure bc as temp increases they move faster
Explanation:
they move faster bc they gain kinetetic energy
Some alkenes have geometric (cis-trans) isomers because ________. all of the carbon atoms in the compound are rigid and cannot rotate the carbon atoms in the double bond are free to rotate the carbon atoms in the double bond cannot rotate each of the carbon atoms in the double bond has four different groups attached to it one of the carbon atoms in the double bond has two identical groups attached to it
Answer:
the carbon atoms in the double bond cannot rotate
Explanation:
Isomers refer to molecules that have a distinct arrangement of the atoms in the molecule but have the same molecular formula.
Alkenes refer to a series of unsaturated hydrocarbons that contain ethylene and propylene.
Some alkenes have geometric (cis-trans) isomers because the carbon atoms in the double bond cannot rotate.
Question 2
Which of the following correctly describes what a mutation is?
A). A change in the DNA code of an organism
B). A change to a gene of an organism
C). A change to the nucleotide sequence
D).All the above
Answer:
d
Explanation:
a mutation is the variation of a norm, a mutation can alter any organism in any way
If I have 150g of NaNO3, how many moles are there?
a) 1.76 mol NaNO3
b) 12750 mol NaNO3
c) 17.6 g NaNO3
d) 0.56 mol NaNO
Answer:
[tex]\boxed {\boxed {\sf A.\ 1.76 \ mol \ NaNO_3}}[/tex]
Explanation:
To covert from grams to moles, the molar mass is used. This is the mass of 1 mole of a substance. These are located on the Periodic Table. They are the equivalent to the atomic masses, but have different units: grams per mole.
We are given the compound: NaNO₃
Look up the values for each individual element (sodium, nitrogen, and oxygen)
Na: 22.989769 g/mol N: 14.007 g/mol O: 15.999 g/molNow find the molar mass of the entire compound. Notice that oxygen has a subscript of 3 in the formula, so there are 3 atoms of oxygen per molecule. We must multiply its molar mass by 3 before adding the others.
O₃: 15.999*3=47.997 g/mol NaNO₃: 22.989769+14.007+47.997=84.993769 g/molUse this value as a ratio.
[tex]\frac {84.993769 \ g \ NaNO_3}{1 \ mol \ NaNO_3}[/tex]
Multiply by the given number of grams: 150
[tex]150 \ g \ NaNO_3*\frac {84.993769 \ g \ NaNO_3}{1 \ mol \ NaNO_3}[/tex]
Flip the ratio so the grams of sodium nitrate cancel.
[tex]150 \ g \ NaNO_3*\frac {1 \ mol \ NaNO_3}{84.993769 \ g \ NaNO_3}[/tex]
[tex]150 *\frac {1 \ mol \ NaNO_3}{84.993769}[/tex]
[tex]\frac {150}{84.993769} \ \ mol \ NaNO_3[/tex]
[tex]1.7648352551 \ mol \ NaNO_3[/tex]
If we round to the nearest hundredth, the 4 in the thousandth place tells us to leave the 6.
[tex]1.76 \ mol \ NaNO_3[/tex]
150 grams of sodium nitrate is approximately 1.76 moles of sodium nitrate. Therefore, choice A is correct.
Use the expression we obtained in class to write the molar absorption coefficient of a particular transition in terms of the transition dipole moment of the transition. If the transition dipole moment is tripled in value, how would the molar absorption coefficient change
Answer:
Initially the function is symmetric with respect to the axis of the one dimensional box. In the final state it is also symmetrical, however you can envision a snapshot of the system as the light field is interacting with the wave-function wherein a node begins to develop as is shown in the middle and the wave function is evolving from the initial to final state. Now consider that the electron density during process is the square of the wave function:
Electron density during transition
As can be seen in the initial and final states the electron density is symmetrically distributed with respect to the axis of the box. However with the field on, the electron density is not symmetrically distributed and a transitory dipole moment can be present. To relate back to real molecules think of each of those orbitals as a linear combination of atomic orbitals. One important factor is the symmetry. But there may be one other factor that will be just as important as symmetry. If you treat orbital 1 as a linear combination over n orbitals and orbital 2 as a linear combinations of orbitals as well, there will be a spatial over lap between the orbital in the ground state and the orbital in the excited state. If there is no spatial overlap between the ground state and excited state orbitals there will be no transition dipole moment. However, if the electrons are in the same place spatially, a large transition dipole moment will result.
Explanation:
1. How many grams are in 1.4 moles of Mg(NO3)2?
Explanation:
molar mass of the compound = 24 + 2× 14+ 16×6
= 24 + 28 + 96
= 148g/mol
no of moles = given mass / molar mass of the compound
1.4 = given mass/ 148
1.4×148=given mass
207.2 g
this type of air pressure is associated with warm air rising
Areas where the air is warmed often have lower pressure because the warm air rises. These areas are called low pressure systems. Places where the air pressure is high, are called high pressure systems. A low pressure system has lower pressure at its center than the areas around it.
What is the volume of 3.00 × 10 20atoms in an aluminum block? The density of aluminum is 2.70 g/cm 3 .
Answer:
[tex]V=4.98x10^{-3}cm^3[/tex]
Explanation:
Hello there!
In this case, according to the given atoms of aluminum, it is possible for us to calculate the mass via the Avogadro's number and its atomic mass of 27.0 g/mol:
[tex]m_{Al}=3.00x10^{20}atoms Al*\frac{1molAl}{6.022x10^{23}atomsAl} *\frac{27.0gAl}{1mol}=0.0135gAl[/tex]
Noe, given the density of the Al, we can calculate the volume as shown below:
[tex]d=m/V\\\\V=m/d\\\\V=0.0135g/(2.70g/cm^3)\\\\V=4.98x10^{-3}cm^3[/tex]
Best regards!
How many moles of methane gas are present in 425 L of the gas? Round answer to 3 significant figures.
Answer:
No. of moles of methane = 18.9 mol
Explanation:
No. of moles = Volume of gas / Volume of gas (at STP)
Volume of gas at STP (Standard Temperature and Pressure) = 22.4L
N = 425 / 22.4
N = 18.973
∴No. of moles of methane = 18.9 mol
h20 (s) -> h20 (g)
endothermic or exothermic
Answer:
Endothermic.
Explanation:
Hello there!
In this case, it is necessary to keep in mind that exothermic processes are characterized by the release of energy and the endothermic processes by the absorption of heat. In such a way, every process from solid to liquid or gas is endothermic as they require energy to separate the molecules and therefore turn out in the phase change. On the other hand, every process from gas to liquid or solid is exothermic as heat is released to rejoin the molecules and produce the phase change.
Therefore, since solid water molecules tend to be well-arranged, it is necessary to add heat to the system to produce the phase change until gas; in such a way, this process is endothermic as energy must be absorbed by the ice.
Best regards!
Rain, snow, hail, and sleet are examples of
a
bad weather.
b condensation.
C precipitation.
d evaporation
Answer:
C. Precipitation
It made me put more on my answer.
Calculate the volume (in mL) of 6.0 M NaOH solution required to prepare 1.0 L of 0.09000 N NaOH solu
Answer:
the volume in mL is 15
Explanation:
The computation of the volume in mL is shown below:
As we know that
N = nM
where
N denotes the normality
n denotes the number of equivalents
M denotes the molarity
Also
For NaOH , N = M
Now
M× V_1 = N × V_2
V_1 = N × V_2 ÷ M
= 0.09000 N × 1.0 L ÷ 6.0 M
= 15 mL
hence, the volume in mL is 15
Identify an alkene and carboxylic acid using primary observations
If the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation. It is not a carboxylic acid if it does not react with sodium carbonate. A substance is not an alkene or a carboxylic acid if it does not decolorize bromine water and is not acidic.
What is the flowchart for identification of an alkene and carboxylic acid?The following flowchart can be used to recognize an alkene and a carboxylic acid:
1. Start with the hypothetical unknown substance.
2. Use bromine water to test the substance.
a. An alkene is a substance that discolors bromine water.
b. Move on to the following stage if the compound does not lighten bromine water.
3. Use universal indicator paper or litmus paper to test the chemical.
a. The substance might be a carboxylic acid if it is acidic and causes the paper to turn red.
b. Go to the following step if the chemical is not acidic.
4. Use sodium carbonate to evaluate the substance.
a. A substance is a carboxylic acid if it reacts with sodium carbonate to release carbon dioxide gas.
b. The chemical is not a compound if it does not react with sodium carbonate.
Therefore, if the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation.
Learn more about Alkene, here:
https://brainly.com/question/31033378
#SPJ2
Your question is incomplete, most probably the complete question is:
TASK 2 - Pass 2B.P4 Identify an alkene and carboxylic acid using primary observations. To achieve 2B.P4, learners should follow guidance to identify an alkene and a carboxylic acid (for example, ethanoic acid) from primary observations. Learners will be expected to identify an alkene in the way described in 1B.4. For ethanoic acid this is by its pH and its reaction with sodium carbonate. The guidance given to the learners could be in the form of a flowchart.
If carbon is in an animal is it:
A. Abiotic matter
B. Biotic matter
C. Energy storage molecules
D. Carbon dioxide
I WILL MARK BRAINLIEST IF YOU HELP!
Do not guess or give me a file or I will report you!!
Answer:
It is A
Explanation:
Abiotic matter
8. A train travels at a at a speed of 30 miles per hour if 1 mile = 1.6 kilometers, how fast is the train traveling in kilometers per minute?
A. 0.8 km/min
B. 1.0 km/min
C. 0,4 km/min
D. 0,6 km/min
Answer:
Explanation:
A: 0.8 KM/Min
1.6 x 30 = 48
48/60 = 0.8
Any type of material or substance that has mass and volume is called
Answer:
Matter
Explanation:
In classical physics and general chemistry, matter is any substance that has mass and takes up space by having volume.
Which statement describes a reason scientists predict that carbon dioxide emissions will increase over the next few decades? Choose the correct answer.
The use of geothermal energy is increasing.
Fossil fuels are being replaced with renewable energy sources.
Increased carbon dioxide in the atmosphere can lead to a loss of biodiversity.
Many countries are undergoing an increase in technology and standard of living.
Answer:
Many countries are undergoing an increase in technology and standard of living.
Explanation:
The statement describes a reason scientists predict that carbon dioxide emissions will increase over the next few decades is many countries are undergoing an increase in technology and standard of living. Therefore, option D is correct.
What increases carbon dioxide emissions?The main contributor to the rising carbon dioxide concentrations in the atmosphere is human activity, specifically the burning of fossil fuels like coal, oil, and gas, as well as deforestation.
Coal and oil emissions are expected to be higher than they were in 2021, with oil accounting for the majority of the increase in overall emissions.
The delayed recovery of international aviation following COVID-19 pandemic limitations accounts for a major portion of the increase in emissions from burning oil.
Greenhouse gases have far-ranging environmental and health effects. They make climate change by trapping heat, and they also impart to respiratory disease from smog and air pollution.
Thus, option D is correct.
To learn more about the carbon dioxide emissions, follow the link;
https://brainly.com/question/14275614
#SPJ6
What is the pressure, in mmHg, of a 4.00 g sample of O2 gas, which has a temperature of 37.0 °C, and a volume of 4400 mL?
Answer:
549.48 mmHg
Explanation:
We'll begin by calculating the number of mole of oxygen in 4 g. This can be obtained as follow:
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ = 4 g
Mole of O₂ =?
Mole = mass /molar mass
Mole of O₂ = 4/32
Mole of O₂ = 0.125 mole
Next, we shall convert 37.0 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T (°C) = 37.0 °C
T(K) = 37.0 °C + 273
T(K) = 310 K
Next, we shall convert 4400 mL to L.
1000 mL = 1 L
Therefore,
4400 mL = 4400 mL × 1 L / 1000 mL
4400 mL = 4.4 L
Next, we shall determine the pressure. This can be obtained as follow:
Number of mole (n) = 0.125 mole
Temperature (T) = 310 K
Volume (V) = 4.4 L
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 4.4 = 0.125 × 0.0821 × 310
Divide both side by 4.4
P = (0.125 × 0.0821 × 310) / 4.4
P = 0.723 atm
Finally, we shall convert 0.723 atm to mmHg.
1 atm = 760 mmHg
Therefore,
0.723 atm = 0.723 atm × 760 mmHg / 1 atm
0.723 atm = 549.48 mmHg
Thus, the pressure is 549.48 mmHg
Methanol has a melting point of -97 degrees celsius and a boiling point of 65 degrees celsius. What phase is methanol in at 80 degrees celsius? (Solid, Gas, or Liquid?)
how atom split go boom boom? :)
Answer:
To split an atom a neutron, traveling at an accurate speed must be shot at the nucleus.
Explanation:
g What are the relative rates of diffusion of the three naturally occurring isotopes of krypton, 80Kr80Kr , 82Kr82Kr, and 83Kr83Kr. What are the relative rates of diffusion of the three naturally occurring isotopes of krypton, , , and . The relative rates of diffusion are: 82Kr(1.02)>82Kr(1.02)>83Kr(1.01)>80Kr(1.00)83Kr(1.01)>80Kr(1.00) The relative rates of diffusion are: 80Kr(1.02)>80Kr(1.02)>82Kr(1.01)>83Kr(1.00)82Kr(1.01)>83Kr(1.00) The relative rates of diffusion are: 82Kr(1.02)>82Kr(1.02)>80Kr(1.01)>83Kr(1.00)80Kr(1.01)>83Kr(1.00) The relative rates of diffusion are: 83Kr(1.02)>83Kr(1.02)>82Kr(1.01)>80Kr(1.00)82Kr(1.01)>80Kr(1.00)
Solution :
According to the Graham's law of diffusion, we know that, the rate of the diffusion varies inversely to the molar mass of the gas, i.e.
Rate of diffusion, [tex]$r_d = \frac{a}{\sqrt M}$[/tex]
where, the 'M' is the molar mass of the gas.
Now in the case of the isotopes of the Krypton,
Atomic mass of [tex]$^{80}Kr$[/tex] = 80 AMU
Atomic mass of [tex]$^{82}Kr$[/tex] = 82 AMU
Atomic mass of [tex]$^{83}Kr$[/tex] = 83 AMU
So the ratio of the rate of diffusion of the three isotopes are :
[tex]$M_{d,^{80}Kr}:M_{d,^{82}Kr}:M_{d,^{83}Kr}$[/tex]
[tex]$=\frac{1}{\sqrt{80}}:\frac{1}{\sqrt{82}}:\frac{1}{\sqrt{83}}$[/tex]
[tex]$=0.1118:0.1104:0.10976$[/tex]
Dividing the above three with the smallest number among the three i.e. 0.10976, we get the relative rates of diffusion.
∴ [tex]$M_{d,^{80}Kr}:M_{d,^{82}Kr}:M_{d,^{83}Kr}$[/tex]
= 1.02 : 1.01 : 1
Hence the relative rate of diffusion are :
[tex]$^{80}Kr(1.02)>^{82}Kr(1.01)>^{83}Kr(1.00)$[/tex]
Determine the moles of carbon dioxide in 2.9 X 10¹² molecules.Round to 2 significant figures.
