Answer:
Temperature and Speed of Sound
Temperature of AirSpeed of Sound Waves (m/s)0 °C33120 °C343100 °C386
Explanation:
Three adjacent keys on a piano (F, F-sharp, and G) are struck simultaneously, producing frequencies of 349, 370, and 392 Hz. What beat frequencies are produced by this discordant combination?
Answer:
21 Hz, 43 Hz and 22 Hz
Explanation:
The computation of the beat frequencies that are generated by this discordant combination is as follows:
As we know that
beat frequencies = |f_1 - f_2|
So
For the first one
= |349 Hz - 370 Hz|
= 21 Hz
For the second one
= |349 Hz - 392 Hz|
= 43 Hz
And, for the third one
= |370 Hz - 392 Hz|
= 22 Hz
Soda pop cane are made of aluminum having thickness of 0.12 mm. They are typically kept at a temperature of 4°C in refrigerator. Such cane has height of 4.83 inch and diameter of 2.6 inch. Suppose you bought such a cold soda pop and brought into the class where the temperature is 25°C.
Required:
Calculate the rate of heat transfer of the coke cane to the surroundings.
Answer:
Explanation:
For flow of heat through conduction , the formula is
Q = KA( T₂ -T₁ ) / d where K is thermal conductivity of material , A is surface area , T₂ - T₁ is temp diff .
Thermal conductivity of aluminum is 205 W /m.s
Surface area of cane = 2π r² + 2π r h where r is radius and h is height of cane .
A = 2π r ( r + h )
= 2 x 3.14 x 1.3 x .0254 ( 1.3 x .0254 + 4.83 x .0254 )
= .20736 ( .033 + .12268 )
A = .03228 m²
thickness d = .12 x 10⁻³ m
Putting the values ,
Q = 205 x .03228 x ( 25 - 4 ) / .12 x 10⁻³
= 1158 x 10³ J /s
unlike punishment, reinforcement ____
A. indicates what not to do
B. promotes discrimination
C. promotes generalization
D. indicate what to do
Answer:
B...................
An accelerometer has a damping ratio of 0.5 and a natural frequency of 18,000 Hz. It is used to sense the relative displacement of a beam to which it is attached. (a)If an impact to the beam imparts a vibration at 4500 Hz, calculate the dynamic error and phase shift in the accelerometer output. (b)Calculateits resonance frequency.(c)What isthe maximumpossiblemagnitude ratio that the system can achieve
Answer:
A) i) Dynamic error ≈ 3.1%
ii) phase shift ≈ -12°
B) 79971.89 rad/s
Explanation:
Given data :
Damping ratio = 0.5
natural frequency = 18,000 Hz
a) Calculate the dynamic error and phase shift in accelerometer output at an impart vibration of 4500 Hz
i) Dynamic error
This can be calculated using magnitude ratio formula attached below is the solution
dynamic error ≈ 3.1%
ii) phase shift
This phase shift can be calculated using frequency dependent phase shift formula
phase shift ≈ -12°
B) Determine resonance frequency
Wr = 2[tex]\pi[/tex] ( 18000 [tex]\sqrt{0.5}[/tex] ) = 79971.89 rad/s
C) The maximum magnitude ratio that the system can achieve
What is a black hole's escape velocity?
The simplest definition of a black hole is an object that is so dense that not even light can escape its surface. If we squished the Earth's mass into a sphere with a radius of 9 mm, the escape velocity would be the speed of light. Just a wee-bit smaller, and the escape velocity is greater than the speed of light.
HopeItHelps!
Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.152 N when their center-to-center separation is 60.9 cm. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.0395 N. Of the initial charges on the spheres, with a positive net charge, what was (a) the negative charge on one of them and (b) the positive charge on the other
Answer:
a) lets take the positive charge to be
q1 = 3.13 * 10^-6 C
b) lets take the negative charge to be
q2 = 3.13 * 10^-6 C
Explanation:
Given data:
electrostatic force between Two identical conducting spheres = 0.152 N
Center-to-center separation = 60.9 cm = 60.9 * 10^-2 m
When wire is removed
electrostatic force between the spheres ( repelling force ) = 0.0395 N
Determine the negative and positive charges on the identical spheres
q1, q2 = 6.26 * 10^-12 C ( positive net charge )
lets take the positive charge to be
q1 = 3.13 * 10^-6 C
lets take the negative charge to be
q2 = 3.13 * 10^-6 C
since q1,q2 = 6.26 * 10^-12 C
attached below is detailed solution
A 50kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3m/s. What was the force acting on the mass?
Answer:
75N
Explanation:
a = v/t = 3/2
F = ma = 50(3/2) = 75
HELP PLEASE
(Look at the picture)
Answer:
what is that?
Explanation:
i dont know what us that sorry
Use the worked example above to help you solve this problem. The amount of charge that passes through a filament of a certain lightbulb in 2.09 s is 1.56 C. (a) Find the current in the bulb. A (b) Find the number of electrons that pass through the filament in 5.24 s. electrons (c) If the current is supplied by a 12.0-V battery, what total energy is delivered to the lightbulb filament
Answer:
a) i = 0.746 A, b) # _electron = 2.44 10¹⁹ electrons, c) E = 1.87 10⁴ J
Explanation:
a) The definition of current is the charge per unit of time
i = Q / t
i = 1.56 / 2.09
i = 0.746 A
b) Let's look for the cargo in passing at this time
i = Q / t
Q = i t
Q = 0.746 5.24
Q = 3.904 C
an electron has a charge e = -1.6 10⁻¹⁹ C, let's use a direct proportions rule
# _electron = 3.904 C (1 electron / 1.6 10⁻¹⁹)
# _electron = 2.44 10¹⁹ electrons
the number of electrons has to be an integer
c) In this part you are asked to calculate the power
P = V i
P = 12 0.746
P = 8.952 W
P = E/t
E = P t
E = 8.952 2.09
E = 1.87 10⁴ J
Write a conclusion to this lab in which you discuss when a person on a roller coaster ride would have sensations of weightlessness and when they would have sensations of weightiness. In your discussion, talk about accelerations and forces. Then finish off your conclusion by using Newton's second law to explain why such accelerations and force conditions cause these sensations.
Answer:
he lower part of the curve N = M (g + v² / r)
upper part of the curve N = m (v² /r -g)
Explanation:
In a roller coaster there is a long climb that allows the car to acquire gravitational potential energy, when this energy is converted into kinetic energy, there is a raven, in these curves we have two parts the lower part, where you have a feeling of great weight and another in the upper part where you have a feeling of weightlessness.
These sensations can be explained using Newton's second law, let's apply it to the lower part of the curve
N-W = m a
acceleration is centripetal
a = v² / r
we substitute
N = mg + m v² / r
N = M (g + v² / r)
In this part the apparent weight is increased by the speed of the body squared, it feels like a lot of fart.
In the upper part of the curve the force of gravity continues to act downwards, the normal that is the reaction of the surface also goes downwards, the centripetal acceleration pointing towards the center of the curve has a vertical downward direction
-N -W = -m a
N = ma -W
N = m (v² / r -g)
In this case we see that the normal that gives the sensation decreases, which is why we feel a loss of weight, in the case of v2 / r = g, the request is total and the sensation of weightlessness.
Cameron is standing on the edge of a 60 m high cliff. He horizontally throws a football
with an initial velocity of 10 m/s. How long does it take for the football to hit the
ground?
Answer:34.6 m/s
Explanation: It is asking how long meaning the answer is in time
How do spectroscopes help with studying of distance stars?
It measures the distance of faraway stars.
It collects sound waves from distant stars.
It breaks apart lights that comes from stars faraway.
It gives a clear image of the shape of stars.
Answer:
You take the light from a star, planet or galaxy and pass it through a spectroscope, which is a bit like a prism letting you split the light into its component colours. "It lets you see the chemicals being absorbed or emitted by the light source. From this you can work out all sorts of things," says Watson
Question 3 (5 points)
Yissel was going to be late to Mr. Scharff's science class. Just as the bell was about to ring. Vissel ran the last little bit of the hallway at 2.47
meters/second for 8 seconds to beat the bell. How far away was Yissel from Mr. Scharff's classroom when she started to run?
Physical quantities are generally not purely numerical: They have a particular dimension or combination of dimensions associated with them. Thus, your height is not 74, but rather 74 inches, often expressed as 6 feet 2 inches. Although feet and inches are different units they have the same dimension--length.
Required:
a. Find the dimensions [V] of volume.
b. Find the dimensions [v] of speed.
Answer:
a, The dimension of volume is L³
b. The dimension of speed = L/T
Explanation:
The three fundamental quantities are Mass, Length and time. Other physical quantities are obtained from or derived from these three. These other quantities are known as derived quantities. The units of the fundamental quantities are Kilogram (kg) for Mass, meters for length, and second for time.
In the given question:
a. Volume = length * breadth * height
since breadth and height all measure length, the dimension of volume becomes:
volume = length * length * length = L³
Thus, the dimension of volume is L³
b. Speed, v = distance/time
Distance measures length, therefore, the dimension of speed will be:
Speed = length / time = L/T
Therefore, the dimension of speed = L/T
What is the speed of a vehicle that travels 50 meters in 5 seconds m/s
Answer:
10m/s
Explanation:
S=D/T
S=50m/ 5sec (make sure to write correct units, they sometimes mark you on that in physics)
S=10 m/sec (be careful of what the units that they want the answer in, different story if it was m/min
A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Who has greater angular displacement?
a) boy
b) girl
c) both have the same angular displacement
Answer:
c) both have the same angular displacement
Explanation:
In this scenario, girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Therefore, both have the same angular displacement.
a jogger runs around a quarter of a full track in 10 seconds what is the period of teh motion around teh track
40 seconds
Explanation:
a quarter is 1/4 so to go the full thing requires you do it 4 time, and sense it takes 10 seconds to do a 1/4 you'd have to multiply 10 by 4.
I have a problem in this questions?
Answer:
8.46E+1
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = 39 C
Charge 2 (q₂) = –53 C
Force (F) of attraction = 26×10⁸ N
Electrical constant K) = 9×10⁹ Nm²/C²
Distance apart (r) =?
The distance between the two charges can be obtained as follow:
F = Kq₁q₂ / r²
26×10⁸ = 9×10⁹ × 39 × 53 / r²
26×10⁸ = 1.8603×10¹³ / r²
Cross multiply
26×10⁸ × r² = 1.8603×10¹³
Divide both side by 26×10⁸
r² = 1.8603×10¹³ / 26×10⁸
r² = 7155
Take the square root of both side
r = √7155
r = 84.6 m
r = 8.46E+1 m
In the Styrofoam ball investigation, it is likely that the charges on the ball and rod are
?
A. the same
B. opposite
C. constantly changing.
Answer:
answer = opposite
they are not changing being in a place as being they-self
the same would not be true because its different then the Styrofoam and it could only be different and its make the most sense aswell.
Both ball and rod has opposite charges on their bodies because of presence of different charges on it.
What are the charges on ball and rod?In the Styrofoam ball investigation, it is likely that the charges on the ball and rod are opposite because Styrofoam ball is negatively charged due to the presence of electrons while on the other hand, the rod is positively charged because of lining of positive charges on the rod.
So we can conclude that both ball and rod has opposite charges on their bodies because of presence of different charges on it.
Learn more about charges here: https://brainly.com/question/25923373
#SPJ2
Force = mass X acceleration. Acceleration due to gravity is 9.8 m/s/s regardless of height or mass. This means a single object will hit the ground with the same force regardless of the height it is dropped from. If this is true, I normally drop a pumpkin from different heights during this unit. why does dropping the pumpkin stay together when dropped from one meter but break apart when dropped from a height of 5 meters?
Question 2 (1 point)
70 cm are equivalent to how many m? State your answer using Scientific Notation.
70 x 10^-2 m
b
7.5 x 10^-2 m
이
ОООО
с
.75 X 10^-2 m
d
0.75 x10^-2 m
uction
Answer:
A) 70 x 10^-2
Explanation:
it would be 70 times negative 100 which equals 0.70
Suppose you need to design a clipper circuit to clip off the portions of an input voltage that fall above +5 V or below +2 V. Assume that diodes having a constant forward drop of 0.7 V are available. Ideal Zener diodes of any breakdown voltage required are available. Dc voltage sources of any value needed are available.
Answer:
attached below
Explanation:
The required design for a clipper circuit is attached below
From the attached circuit
It can be seen that the battery voltage needs to be high so that it will be in forward bias considering the assumption that the diodes have a constant forward drop of 0.7 V.
hence 4.3 has to be >2.7
Linear Motion is the most basic type of motion. Question 2 options: True False
What is the momentum if the mass is 1.5 kg and the velocity is 4 m/s?
Answer:
6
Explanation:
momentum = mass * velocity
momentum = 1.5 * 4
momentum = 6
Suppose the particle is placed at the 40V equipotential surface along the line connecting the two central positive and negative charges.
(Hint: The electric field can be obtained using the 40V and 30V potential difference lines.)
1. What is the force on the charged particle if q=80μC? (mN) (m-milli 10-3)
2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN)
Answer:
Hello some part of your question is missing below is the missing part
2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN) (hint: The electric field can be obtained as above using the 0V and -10V equipotential lines.)
answer :
1) 0.8 mN
2) 0.8 mN
Explanation:
Given data:
1) Calculate the force on the charged particle
q = 80 μC , Va = 30v , Vb = 40v, ∝ = 1 m
E = ( Δv ) / ∝
= ( Vb - Va ) / ∝
F = qE
= 80 μC * ( 40 - 30 ) / 1 m
= 800 μC
F = 0.8 mN
2) Calculate the force on the charged particle when it is located at 0V
Va = -10V , Vb = 0V, q = 80 μC, ∝ = 1 m
F = qE
where E = ( 0 - ( -10 ) / 1
F = 80 μC * ( 0 - ( -10 ) / 1
= 800 μC = 0.8 mN
How can you explain the process of reflection based from your experience?
Answer:
Reflection brings learning to life. Reflective practice helps learners find relevancy and meaning in a lesson and make connections between educational experiences and real life situations. It increases insight, and creates pathways to future learning. Reflection is called by many different names in the education field including processing, reviewing, and debriefing. I personally have moved towards referring to this key ingredient in teaching and group facilitation as reflection or reflective practice.
Explanation:
During the nineteenth century, biologists knew that South America and Africa contained similar fossils. These fossils let them to believe that a temporary land bridge between South America and Africa allowed ancient species to move between both continents. In the twentieth century, evidence showed that South America and Africa were once part of the same larger continent and that there were no land bridges between them. How should biologists respond to the new geological finding?
A. Biologists should reject the geological finding, because it is new.
B. Biologists should ask physicists what to do, because physics is a more exact science.
C. Biologists should reject the belief in ancient species, because there were no land bridges.
D. Biologists should update the history of life, because it should include the new geological finding.
Explain
Explain why two electric charges of the same magnitude, when on a collision course with each other, won't actually collide
(serious answers only)
Answer:
Explanation:
When two charges of equal magnitude and sign approach each other, they interact through Coulomb's law
F = [tex]k \frac{q_ 1q_2}{z^2 }[/tex]k q1 q2 / r2
In you case the house are of equal magnitude and sign
q1 = q2 = q
F = k q2 / r2
Let's analyze this expression, the charge is repulsive on each charge, when they are on a collision course as they approach they feel an electric field opposite to their direction of movement, this field decreases its speed, the closer they get, the greater the repulsive force. , up to the point where this force is equal to or greater than the impulse, therefore the point where the velocity reaches zero, for this reason the particles do not actually touch
4. Which of these is exerted by an engine?
(1 Point)
Thrust
Water resistance
Friction
Air resistance
Air resistance is exerted by an engine
Two loudspeakers, A and B are driven by the same amplifier and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. The frequency of the sound waves produced by the loudspeakers is 206 Hz. Consider a point P between the speakers and along the line connecting them, a distance x to the right of A. Both speakers emit sound waves that travel directly from the speaker to point P. For what values of x will:
a. destructive interference occur at P
b. constructive interference occur at P
Answer:
a) 0, ±1.65 b) ± 0.825m
Explanation:
This is a sound interference exercise, it can be described by the path difference between the two waves
for the case of constructive interference
Δr = 2n λ/ 2 n = 0, 1, 2 ...
for the case of destructive interference
Δr = (2n + 1) λ/ 2
the speed of sound is related to the wavelength
v = λ f
λ = v / f
λ= 340/206
λ = 1.65 m
let's set a reference system in the center between the two speakers
a) let's find the distances for constructive interference
Δr = 2n 1.65 / 2
Δr = 1.65 n
* the first interference occurs at n = 0
Δr = 0
therefore the interference in the center is maximum
* n = 1
Dr = 1.65 m
the second inference occurs at 1.65 m from the center, therefore there is a right wing and a left wing,
We do not have any more interference between the speakers because
n = 2 Δr = 3.3m this distance can be from the speaker
b) let's look for the destructive interference points
Δr = (2n + 1) 1.65 / 2
Δr = (2n + 1) 0.825
m = 0 Δr = 0.825m
m = 1 Δr = 2,475m
We can see that we only have the first destructive interference, one on each side.
