Atomic size decreases in a period but the ionization energy and electronegativity increases across a period.
Describe the trends in the atomic size, ionization energy and electronegativity?Atomic radius decreases across a period because of nuclear charge increases whereas atomic radius of atoms generally increases from top to bottom within a group because there is again an increase in the positive nuclear charge.
Ionization energy increases when we move from left to right across an period and decreases from top to bottom.
Electronegativity also increases from left to right across a period and decreases from top to bottom.
So we can conclude that atomic size decreases in a period but the ionization energy and electronegativity increases across a period.
Learn more about Electronegativity here: https://brainly.com/question/24977425
#SPJ1
The heat of fusion of water is 79.9cal/g, the heat of vaporization of water is 540cal/g, and the specific heat of water is 1.00cal/deg/g. How much ice at 0 celsius could be converted to steam at 100 celsius by 9522cal of heat?
The amount of ice converted into steam is 13.23 gram.
What is Heat of Vaporisation ?Heat of Vaporisation is the amount of heat required to convert 1 gm to liquid at its boiling point to vapour.
Let x gram of ice is there
At first x gm of ice will melt
The heat required is x * Heat of fusion = x * 79.9 = 79.9x
Then the heat required to rise the temperature of x gm of water from 0 degree to 100 degree Celsius .
= mc ΔT
= x * 1 * 100 = 100x
The heat required to convert x gm of liquid into x gm of steam
= x * 540 = 540x
The total heat supplied is 9522 cal
79.9x + 100x + 540x = 9522
719.9 x = 9522
x = 13.23 gm
The amount of ice converted into steam is 13.23 gram.
To know more about Heat of Vaporisation.
https://brainly.com/question/9967928
#SPJ1
What is an open system?
A. A system that allows energy to move in and out but not mass
B. A system that allows energy and mass to move in and out of it
C. A system that allows mass to move in and out but not energy
OD. A system that does not allow energy or mass to move in or out of
it
Answer:
Open system :-
B. A system that allows energy and mass to move in and out of it.
Hope it helps!
Approximately 50% of our bone is chemically calcium phosphate, Ca3(PO4)2
If an adult has 12 kg of bone, calculate the mass of calcium is present
Calculate the pH of a solution that is 0.113 M HCI.
Simplified concentration
[tex]\\ \rm\Rrightarrow 1.13\times 10^{-2}M[/tex]
Now
[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]
[tex]\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})[/tex]
[tex]\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}[/tex]
[tex]\\ \rm\Rrightarrow pH=-0.05+2[/tex]
[tex]\\ \rm\Rrightarrow pH=1.95[/tex]
Highly acidic
A sample of 0.0084 mol of HCl is dissolved in water to make a 1500 mL solution. Calculate the molarity of the HCl solution, the [H3O+] and the pH. For a strong acid such as HCl, the [H3O+] is the same as the molarity of the HCl solution.
A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a Molarity of HCl of 5.6 × 10⁻³ M, a Molarity of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.
What is Molarity ?Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solutionA solution is prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution. The molarity of HCl is:
[HCl] = 0.0084 moles / 1.5 L
= 5.6 × 10⁻³ M
HCl is a strong acid according to the following equation.
HCl(aq) + H₂O(l) ⇒ Cl⁻(aq) + H₃O⁺(aq)
Thus, the concentration of H₃O⁺ will be equal to the initial concentration of HCl, 5.6 × 10⁻³ M.
Now, we will calculate the pH of the solution using its Formula ;
pH = - log[H₃O⁺]
= - log [5.6 × 10⁻³]
= 2.3
Hence, A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a Molarity of HCl of 5.6 × 10⁻³ M, a Molarity of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.
Learn more about pH here ;
brainly.com/question/14950262
#SPJ1
A scientist places a large beaker containing 325 g of 50degree Celsius water into a microwave. He has to run the microwave for 3 minutes until the water reaches a temperature at 92 degree Celsius. Calculate the amount of energy absorbed by the water.
The amount of energy absorbed by the 325g of water is 57,057J. Details about calorimetry can be found below.
How to calculate energy?The energy absorbed by a mass of substance can be calculated using the following formula;
Q = mc∆T
Where;
Q = quantity of heat absorbedm = mass of substancec = specific heat capacity∆T = change in temperatureQ = 325g × 4.18 × (92 - 50)
Q = 57,057J
Therefore, the amount of energy absorbed by the 325g of water is 57,057J.
Learn more about energy at: https://brainly.com/question/3609481
#SPJ1
PLEASE HELP ASAP!!!!!!!!!!!!!!!
Answer:
A and B
Explanation:
A is crust
B is mantle
Calcular la normalidad de 1 Kg de sulfuro de aluminio en 5000 ml de solucion.
Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.
Normality comes out to be 8.11
Given Mass of solute: 1000gVolume of solution (V): 5000 ml = 5 liters Equivalent mass of solute (E) = molar mass / n-factorn-factor for [tex]Al_{2}S_{3}[/tex] is 6 and molar mass is 148g
So, on calculating equivalent mass is equal to 24.66g
FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)
N=[tex]\frac{1000}{24.66*5}[/tex]
N=8.11
Therefore, normality of 1 kg aluminum sulfide is 8.11
Learn more about normality here https://brainly.com/question/25507216
#SPJ10
What can help engineers develop ways to prevent rusting?
OA. Understanding the solubility of metal ions
B. Understanding double-displacement reactions
C. Understanding oxidation-reduction reactions
D. Understanding the phase changes of metals
Answer: Understanding oxidation-reduction reactions
Explanation:
Rusting occurs when electrons are exchanged between iron and oxygen.
The properties of an element depend on the electron structure within its atoms. The electrons are arranged in different
orbitals, at different energy levels and sublevels. Match each sublevel to the maximum number of electrons it can
accommodate?
The electrons are arranged in different orbitals, at different energy levels and sublevels.
What are Orbitals ?An atomic orbital is a function describing the location and wave-like behavior of an electron in an atom.
This function can be used to calculate the probability of finding any electron of an atom in any specific region around the atom's nucleus.
Following are the sublevel with the maximum number of electrons that can be accommodated by it ;
2 Electrons : S-SubshellTherefore, S-Subshell has 2 electrons, P-subshell has 3 electrons, d-subshell has 10 electrons and f-subshell has 14 electrons.
Learn more about Subshells here ,
https://brainly.com/question/19221869
#SPJ1
If 4.5 moles of an ideal gas has a temperature of 286 K and a pressure 9.4 atm, what is the volume of the container
Answer:
V = 11 L
Explanation:
To find the missing value, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this formula,
----> P = pressure (atm)
----> V = volume (L)
----> n = number of moles
----> R = constant (0.0821 atm*L/mol*K)
----> T = temperature (K)
You have been given all of the values in the correct units. Therefore, you can plug these values into the equation and simplify to find volume. The answer should have 2 sig figs to match the given value with the lowest amount of sig figs.
PV = nRT
(9.4 atm)V = (4.5 moles)(0.0821 atm*L/mol*K)(286 K)
(9.4 atm)V = 105.6627
V = 11 L
7.71 Classify each of the following as exothermic or endothermic:
a. CHÂ(g) + 2O₂(g) —^> CO₂(g) + 2H₂O(g) + 802 kJ
b. Ca(OH)₂(s) + 65.3 kJ →→→ CaO(s) + H₂O(l)
c. 2Al(s) + Fe₂O3(s) — Al₂O3(s) + 2Fe(s) + 850 kJ
A. Heat is released, so the reaction is exothermic.
B. Heat is absorbed, so the reaction is endothermic.
C. Heat is released, so the reaction is exothermic.
How many valence electrons does Rb (rubidium) have?
Answer:
The total number of electrons in a valence shell is called valence electrons. The electron configuration of rubidium shows that the last shell of rubidium has an electron. Therefore, the valence electrons of rubidium(Rb) are one.
What would be the mass, in grams, of 2.408 x 1024 molecules of tetraphosphorus decaoxide?
Answer:
1,135 grams P₄O₁₀
Explanation:
To find the mass, you need to (1) convert molecules to moles (via Avogadro's Number) and then (2) convert moles to grams (via molar mass from periodic table values). It is important to arrange the ratios/ conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 4 sig figs to reflect the given value (2.408 x 10²⁴).
Avogadro's Number:
1 mole = 6.022 x 10²³ molecules
tetraphosphorus decaoxide = P₄O₁₀
Molar Mass (P₄O₁₀): 4(30.974 g/mol) + 10(15.998 g/mol)
Molar Mass (P₄O₁₀): 283.876 g/mol
2.408 x 10²⁴ molecules P₄O₁₀ 1 mole 283.876 g
------------------------------------------- x ------------------------------------ x -----------------
6.022 x 10²³ molecules 1 mole
= 1,135 grams P₄O₁₀
A camel's hump is a trait that evolved through the process of ____________ to allow the camels to survive for longer periods without water.
A.
natural selection
B.
fossilization
C.
mutualism
D.
genetics
Answer:
Natural Selection
The answer is:
A. Natural Selection
Na2 C6H6O7 (sodium hydrogen citrate)
Express the mass of sodium to three significant figures.
mNa =
The exact mass of one Na - atom is 22.98977 amu and thus, the weight of two sodium atoms in present in Na₂C₆H₆O₇ is 45.979539 g/mol.
What is Molar mass ?The molar mass of a substance is the mass in grams of 1 mole of the substance.
We can obtain a substance's molar mass by summing the molar masses of its component atoms.
Mass of one Na atom = 22.98977
Mass of two Na atom = 22.98977 x 2
= 45.97954
= 45.9 (up to 3 Significant figures)
Learn more about significant figure here ;
https://brainly.in/question/11059319
#SPJ1
How many grams S03
are needed to make 400g
H₂So4 in 49%
160 g of SO3 are needed to make 400 g of 49% H2SO4.
How many grams of SO3 are required to prepare 400 g of 49% H2SO4?The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:
[tex]SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]
1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
Learn more about mass and moles at: https://brainly.com/question/15374113
#SPJ1
A 8.63 g sample of a compound contains 5.51 g of iron, Fe, 1.02g of phosphorus, P, and oxygen, O. Calculate the empirical formula for the compound
The empirical formula for the compound is [tex]Fe_3PO_4[/tex] if A 8.63 g sample of a compound contains 5.51 g of iron, Fe, 1.02g of phosphorus, P, and oxygen, O.
What is the empirical formula?An empirical formula tells us the relative ratios of different atoms in a compound.
We need to calculate the number of moles:
Given data:
Mass of iron - 5.51 g
Mass of phosphorus -1.02g
Mass of oxygen -2.1 g
Moles of iron - [tex]\frac{mass}{molar \;mass}[/tex]
Moles of iron - [tex]\frac{5.51 g}{56 g/mol}[/tex]
0.098 mole
Moles of phosphorus [tex]-\frac{mass}{molar \;mass}[/tex]
Moles of phosphorus - [tex]\frac{1.02g}{31 g/mol}[/tex]
0.032 moles
Moles of oxygen -[tex]\frac{mass}{molar \;mass}[/tex]
Moles of oxygen - [tex]\frac{2.1 g}{16 g/mol}[/tex]
0.13moles
Dividing each mole using the smallest number that is divided by 0.032moles.
Fe:P:O :: 3:1:4
The empirical formula for the compound is [tex]Fe_3PO_4[/tex].
Learn more about empirical formula here:
brainly.com/question/14044066
#SPJ1
Hydrogen peroxide is a liquid that decomposes to form oxygen gas and
water. The occasional bubble you might see in a beaker that contains
hydrogen peroxide is evidence of this reaction. But if a small amount of
manganese oxide powder is added to the beaker, many small bubbles start
forming in the liquid. What part does the manganese oxide play in this
reaction?
A. It is a catalyst that increases the rate of the reaction.
B. It is a substance that supplies extra energy for the reaction.
C. Its addition to the liquid makes molecules of hydrogen peroxide
move faster.
D. It is a reactant that is necessary for the reaction to begin.
SUBMIT
pls tell this answers
Answer:
okay
Explanation:
9 . acidic
10. hydrogen
answer the following questions
11. Gold as a precious metal is used widely in making jewelry items. This metal is preferred over others for jewelry pieces for various reasons. One important reason for its popularity is that it does not react with atmospheric moisture and therefore, it does not rust.
12. corrosion is defined as rust it's due to humidity and moisture
13. Sulphur appears much below chlorine in the reactivity table and cannot displace chlorine from dilute HCl.
14. Highly conductive metal
Surpassed only by silver, copper is a highly conductive metal. This means electricity can pass through it with greater ease, making it ideal for use in electrical wires. Companies can use other conductive metals to create electrical wires.
15. Corrosion
Copper metal when exposed to air turns green in color due to corrosion. When the copper vessel is exposed to air in the rainy season, the metal reacts with gases, moisture, and atmospheric gases to form a mixture of copper carbonate and copper hydroxide. This gives a green color to the surface of the copper meta
16. Silicon
silicon is the backbone of the electronics industry. Because silicon is the reason for the fast development happened in the field of electronics. therefore, silicon is the backbone of electronics.
17. High chemical reactivity
Sodium is stored under kerosene because of its high chemical reactivity with almost all of the other elements (for example oxygen from the air which oxidizes it instantly). Kerosene and mineral oil are the only chemicals that make sodium inert. Usually, when Na reacts with a solvent it liberates hydrogen gas from its composition.
18. Metal oxides are oxides of metals. Nonmetal oxides are oxides of nonmetals. The main difference between metal oxides and nonmetal oxides is that metal oxides are basic compounds whereas nonmetal oxides are acidic compounds.
19. Silver is more likely to tarnish near a petroleum refinery than in a place far away from it because when silver reacts with petroleum or hydrogen sulfide present in it as a pollutant in the air, it starts forming a black coating of silver sulfide.
20. A noble metal is ordinarily regarded as a metallic chemical element that is generally resistant to corrosion and is usually found in nature in its raw form. Gold, platinum, and the other platinum group metals (ruthenium, rhodium, palladium, osmium, iridium) are most often so classified. Silver, copper, and mercury are less often to sometimes included as noble metals although each of these usually occurs in nature combined with sulfur.
Fe + H₂O → Fe3O4+H₂ help
Answer:
3Fe + 4H₂O --> Fe3O4 + 4H2
The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0 % yield. How many grams would be produced from 7.45 g of butanoic acid and excess ethanol?
Express your answer in grams to three significant figures.
7.66g of ethyl butyrate is produced.
The reaction is
CH₃CH₂CH₂COOH + CH₃CH₂OH ----> CH₃CH₂CH₂COOCH₂CH₃
The molar mass of butanoic acid is 88.11g/molWe have 7.45g of butanoic acidThe moles of butanoic acid we have is 7.45/88.11 = 0.0845 molIf the yield is 100%, 1 mole of butanoic acid gives 1 mole of ethyl butyrateBut the reaction yield is 78%1 mole of butanoic acid gives 0.78 mole of ethyl butyrateFrom 0.0845 mol of butanoic acid we get 0.78 x 0.0845 = 0.66 mol of ethyl butyrate.
The molar mass of ethyl butyrate is 116.16g/mol
So 0.66 x 116.16 = 7.66g
7.66g of ethyl butyrate is produced.
Learn more about esterification here:
https://brainly.com/question/14028062
#SPJ10
Pure water boils at 100°C.
What happens to the water particles when water
boils?
A They gain energy and move further apart.
B They gain energy and stay close together.
C They lose energy and move further apart.
D They lose energy and stay close together.
Answer:
A
Explanation:
Here: Describe the non metal elements .What group number are non metals
Answer:
A nonmetal is a chemical element that generally lacks a predominance of metallic properties. Non-metals are mostly found in groups 5, 6 and 7. These non-metals will have 5, 6 or 7 electrons in the outer shell.
The outer shell of a non-metal is, therefore, more than half full of electrons.
If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of KCI in the resulting solution?
1.199 M is the concentration of KCI in the resulting solution.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
No.of moles of KCI
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]
= 0.599 moles
Vol.of the solution,V= 500 ml
= 0.5 liter
Molarity
[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]
[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]
= 1.199 M
Hence, 1.199 M is the concentration of KCI in the resulting solution.
Learn more about moles here:
https://brainly.com/question/8455949
#SPJ1
ements
tton
2 NH3 + 3 CuO -->3 Cu + N₂ + 3H₂O
In the above equation how many moles of N₂ can be made when 156.1 grams of CuO are
consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report
the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark
your answer incorrect.:
Element Molar Mass
Hydrogen 1
Nitrogen 14
Copper 63.5
Oxygen 16
Answer: The amount of moles that can be produced when 156.1 grams of CuO are consumed is .653 moles.
Explanation: The first thing to do is to convert the 156.1 grams of Copper(II) Oxide (CuO).
In order to convert the 156.1 grams of Copper(II) Oxide to moles we have to first calculate the molar mass of Copper(II) Oxide. This can be done by simply adding the Copper's molar mass, 63.5, to the Oxygen's molar mass, 16.
16 g + 63.5 g = 79.5 g
Once you have obtained the molar mass of the Copper (II) Oxide you can then proceed to convert the 156.1 grams from before into moles.
This is done by multiplying 156.1 grams by 1 mole / 79.5 grams.
[tex]156.1 g *1 moles/79.5 g = 1.96 moles[/tex]
Now that you have calculated the 1.96 moles of Copper(II) Oxide, you need to set up an equation to convert between moles amounts.
This can be done by looking at the coefficients in the chemical equation. So, in this chemical reaction, it tells us for every 3 moles of CuO there is 1 moles of N2.
With this we can write a conversion equation as follows.
[tex]1.96*\frac{1}{3} = .653[/tex]
*Note: in conversion equations the denominator should match the units and or element being multiplied by the other fraction in the numerator. Such as in this instance the 1.96 moles of CuO and 3 moles of CuO are the same.
So, the amount of moles of N2 that can be made when 156.1 grams of CuO are consumed is .653 moles.
Answer:
0.7 mole N₂
Explanation:
To find the amount of N₂ produced, you need to (1) convert grams CuO to moles CuO (via the molar mass) and then (2) convert moles CuO to moles N₂ (via mole-to-mole ratio from reaction coefficients).
The molar mass is the sum of the element molar masses times their quantities. The ratios/conversions should be arranged in a way that allows for the cancellation of units (desired unit in the numerator).
Molar Mass (CuO): 63.5 g/mol + 16 g/mol
Molar Mass (CuO): 79.5 g/mol
2 NH₃ + 3 CuO ----> 3 Cu + 1 N₂ + 3 H₂O
^ ^
156.1 g CuO 1 mole 1 mole N₂
------------------- x ----------------- x ---------------------- = 0.7 mole N₂
79.5 g 3 moles CuO
PLEASE HELP ASASP!!!!!!!
Answer:
B
Explanation:
I took the test
Which TWO of the following processes will increase the concentration of al solution?
(a) Increase the amount of solute.
(b) Decrease the amount of solute.
(c) Increase the amount of solvent.
(d) Decrease the amount of solvent.
Answer:
B decrease the amount of solute
What is the electron configuration of a sodium atom?
1s¹, 2s², 2p6, 356
1s¹, 2s2, 2p6, 3s¹
2s², 2s², 2p6, 3s¹
1s², 2s², 2p6, 3s¹
Answer:
1s²,2s²,2p6,3s¹.Atomic no. of sodium is 11electronic configuration = 2,8,1.that Is 1s²,2s²,2p6,3s1.for electromic configuration - only 2 electron can be there in a single orbital there are 1 s orbital, 3 p orbital ...and so on.3A. The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced REDUCTION half reaction.
Cl- + SiO32- Cl2 + Si
Reactants Products
3B.
The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced OXIDATION half reaction.
Bi + HPO32-Bi(OH)3 + H2PO2-
Reactants Products
4A. The following skeletal oxidation-reduction reaction occurs under acidic conditions. Write the balanced REDUCTION half reaction.
Cd + SO42- Cd2+ + H2SO3
Reactants Products
4B. The following skeletal oxidation-reduction reaction occurs under acidic conditions. Write the balanced OXIDATION half reaction.
Mn2+ + NiO2MnO4- + Ni2+
Reactants Products
The balanced redox equations of the reactions are:
[tex]SiO_{3}^{2-} + 3\:H_{2}O + 4\:e^{-} \rightarrow Si + 6\:OH^{-}[/tex][tex]2\:Bi + 6\:OH^{-} \rightarrow 2\:Bi(OH)_{3} + 6\:e^{-}[/tex] [tex]SO_{4}^{2-} + 4\:H^{+} + 2\:e^{-} \rightarrow H_{2}SO_{3} + H_{2}O[/tex][tex]Mn^{2+} + 4\:H_{2}O \rightarrow MnO_{4}^{-} +8\:H^{+} + 5\:e^{-}[/tex]What are balanced redox equations?Balanced redox equations are those in which the atoms and electrons transferred are equal on both sides of the equation.
The balanced redox equations of the reactions are given below:
(3a) Balanced REDUCTION half reaction of the equation under basic conditions:
[tex]SiO_{3}^{2-} + 3\:H_{2}O + 4\:e^{-} \rightarrow Si + 6\:OH^{-}[/tex](3b)Balanced OXIDATION half reaction of the equation under basic conditions:
[tex]2\:Bi + 6\:OH^{-} \rightarrow 2\:Bi(OH)_{3} + 6\:e^{-}[/tex](4a) Balanced REDUCTION half reaction of the equation under acidic conditions:
[tex]SO_{4}^{2-} + 4\:H^{+} + 2\:e^{-} \rightarrow H_{2}SO_{3} + H_{2}O[/tex](4b) Balanced OXIDATION half reaction of the equation under acidic conditions:
[tex]Mn^{2+} + 4\:H_{2}O \rightarrow MnO_{4}^{-} +8\:H^{+} + 5\:e^{-}[/tex]Therefore, the balanced oxidation and reduction half reactions are balanced by adding the numerical coefficients to the reacting species as well hydrogen ions, hydroxide ions, water molecules and electrons to the appropriate side of the reactions.
Learn more about redox equations at: https://brainly.com/question/1161855
#SPJ1
