Answer:
The Earth is traveling around the sun with an orbital velocity of 30 kilometers per second. This is exactly the speed it needs to be going to counteract the force of gravity from the sun pulling it inward. If the sun were to suddenly disappear, Earth would travel in a perfectly straight line at 30 km/s
Explanation:
What is the speed of a wave that has a frequency of 2,400 Hz and a wavelength of 0.75
Answer:
1800 m/s
Explanation:
The equation is v = fλ
λ= 0.75
f = 2400 Hz
V = 2400 × 0.75
V = 1800 m/s
[ you did not give units for wavelength, I assumed it would be m/s]
1 poir
A track star in the long jump goes into the jump at 15 m/s and launches
herself at 17.0° above the horizontal.How long is she in the air before
returning to Earth? (g = 9.81 m/s2) (do not include units in answer) *
Helppp now
PLEASE HELP 25 POINTS WHAT IS THE ANSWER
The answer is letter C vro
thanks me.later
1 identify two ways (factors) you can change in order to the charge the objects experience
Answer:
Follows are the solution to this question:
Explanation:
Please find the correct question in the attached file:
In point (a), The one factor is the charge on each of the objects. In point (b), at this point, the second factor is used as the distance between the charges.The two ways to charge an object are Friction and Induction.
Charging an object:To charge and object generally we can think of three ways, Friction, Conduction, and Induction. Here I am going to explain charging by friction and induction.
(i) Charging by Friction:
In this case, two objects are rubbed against each other. The friction between the two objects creates enough energy for the transfer of charges ( electrons) from one object's surface to the other. So the imbalance in the electrons produces a charge on the objects.
(ii) Charging by induction:
In this case, an already charged object is brought near a neutral object but there is no contact between the objects. The charged object attracts or repels the electrons of the neutral object, depending upon the type of charge it has. Thus creating a charge imbalance in the neutral object.
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Check all the answers that apply.
Energy is the ability to:
⚫️ Change direction
⚫️ Change speed
⚫️Change temperature
⚫️Do work
Energy is the ability to: ⚫️Do work
mark me brainiest pls
convert 4.5 hour into second
Answer:
4.5 hours =
16200 seconds
Explanation:
here you go
m_Cu * sh_CuA system consists of a copper tank whose mass is 13 kilogram , 4 kilogram of liquid water, and an electrical resistor of negligible mass. The system is insulated on its outer surface. Initially, the temperature of the copper is 27 degC and the temperature of the water is 50 degC . The electrical resistor transfers 100 kilojoule to the system. Eventually the system comes to equilibrium. Determine the final equilibrium temperature, in ∘C.
Answer:
T₂ = 49.3°C
Explanation:
Applying law of conservation of energy to the system we get the following equation:
Energy Supplied by Resistor = Energy Absorbed by Tank + Energy Absorbed by Water
E = mC(T₂ - T₁) + m'C'(T'₂ - T'₁)
where,
E = Energy Supplied by Resistor = 100 KJ = 100000 J
m = mass of copper tank = 13 kg
C = Specific Heat of Copper = 385 J/kg.°C
T₂ = Final Temperature of Copper Tank
T₁ = Initial Temperature of Copper Tank = 27°C
T'₂ = Final Temperature of Water
T'₁ = Initial Temperature of Water = 50°C
m' = Mass of Water = 4 kg
C' = Specific Heat of Water = 4179.6 K/kg.°C
Since, the system will come to equilibrium finally. Therefor: T'₂ = T₂
Therefore,
(100000 J) = (13 kg)(385 J/kg.°C)(T₂ - 27°C) + (4 kg)(4179.6 J/kg.°C)(T₂ - 50°C)
100000 J = (5005 J/°C)T₂ - 135135 J + (16718.4 J/°C)T₂ - 835920 J
100000 J + 135135 J + 835920 J = (21723.4 J/°C)T₂
(1071055 J)/(21723.4 J/°C) = T₂
T₂ = 49.3°C
2. An archer shoots an arrow. The action force is the bowstring against the arrow, The reaction force is...
a. Air resistance against the bow
b. Arrow's push against the bowstring
c. Grip of the archer's hand on the bow
Answer:b the arrows push against the bow string
Explanation:
The reaction force will be Arrow's push against the bowstring.
Option b is correct.
From Newton's Third Law of Action & Reaction, It states that for every action in nature there is an equal and opposite reaction.
It means that If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.Therefore, If an archer shoots an arrow. The action force is the bowstring against the arrow, The reaction force will be Arrow's push against the bowstring
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why the bodies of water important for recreation
Explanation:
Recreational water activities can have substantial benefits to health and well-being. Swimming pools, beaches, lakes, rivers and spas provide environments for rest and relaxation, physical activity, exercise, pleasure and fun. Yet they also present risks to health.
pls make it the brainliest of it has helped you !!!!
Suppose a star the size of our Sun, but with mass 9.0 times as great, were rotating at a speed of 1.0 revolution every 7.0 days. If it were to undergo gravitational collapse to a neutron star of radius 13 km , losing three-quarters of its mass in the process, what would its rotation speed be
Answer:
Its rotation will be 3.89x10⁴ rad/s.
Explanation:
We can find the rotation speed by conservation of the angular momentum:
[tex] L_{i} = L_{f} [/tex]
[tex] I_{i}\omega_{i} = I_{f}\omega_{f} [/tex] (1)
The initial angular speed is:
[tex] \omega_{i} = \frac{1 rev}{7 d} = 0.14 \frac{rev}{d} [/tex]
The moment of inertia (I) of a sphere is:
[tex] I = \frac{2}{5}mr^{2} [/tex] (2)
Where m is 9 times the sun's mass and r is the sun's radius
By entering equation (2) into (1) we have:
[tex] \frac{2}{5}m_{i}r_{i}^{2}\omega_{i} = \frac{2}{5}m_{f}r_{f}^{2}\omega_{f} [/tex]
[tex]9m_{sun}(696342 km)^{2}0.14\frac{rev}{d} = \frac{3}{4}9m_{sun}(13 km)^{2}\omega_{f}[/tex]
[tex]\omega_{f} = \frac{4}{3}*0.14 \frac{rev}{d}(\frac{696342 km}{13 km})^{2} = 5.36 \cdot 10^{8} \frac{rev}{d}*\frac{1 d}{24 h}*\frac{1 h}{3600 s}*\frac{2\pi rad}{1 rev} = 3.89 \cdot 10^{4} rad/s[/tex]
Hence, its rotation will be 3.89x10⁴ rad/s.
I hope it helps you!
A 100 kg man climbs the stairs at a football stadium 50 m tall in 45 s. What was the man's required power output?
.Answer:
1111.11 W
Explanation:
Power is the rate of doing work with respect to time, its S.I unit is in watts but it can also be expressed in J/s. Power is calculated using the formula:
[tex]Power=\frac{energy}{time}[/tex]
Power is also the rate at which energy is used per second.
Given that mass (m) = 100 kg, height (h) = 50 m, acceleration due to gravity (g) = 10 m/s and time = 45 s.
The man climb the stairs and experiences a potential energy, hence:
potential energy = mgh = 100 * 10 *50 = 50000 J,
[tex]Power=\frac{energy}{time}=\frac{50000}{45}=1111.11\ W[/tex]
A 66-N ⋅ m torque acts on a wheel with a moment of inertia 175 kg ⋅ m2. If the wheel starts from rest, how long will it take the wheel to make one revolution?
Answer:
t = 5.77 s
Explanation:
This exercise will use Newton's second law for rotational motion
τ = I α
α = τ / I
α = 66/175
α = 0.3771 rad/s²
now we can use the rotational kinematics relations, remember that all angles must be in radians
θ = 1 rev = 2π radians
θ = w₀ t + ½ α t²
as the wheel starts from rest w₀ = 0
t = √ (2θ/α)
let's calculate
t = √ (2 2π / 0.3771)
t = 5.77 s
If you weigh 660 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 20.0 km? Take the mass of the sun to be 1.99×10^30, the gravitational constant to be G = 6.67×10^−11Nm^2/kg^2, and the acceleration due to gravity at the earth's surface to be g = 9.810 m/s^2.p
Answer:
8.93*10^13 N.
Explanation:
Assuming that in this case, the weight is just the the force exerted on you by the mass of the star, due to gravity, we can apply the Universal Law of Gravitation:[tex]F_{g}= \frac{G*m_{1}*m_{s}}{r_{s}^{2} }[/tex]
where, m1 = mass of the man = 660 N / 9.81 m/s^2 = 67.3 kg, ms = mass of the star = 1.99*10^30 kg, G= Universal Constant of Gravitation, and rs= radius of the star = 10.0 km. = 10^4 m.Replacing by the values, we get:[tex]F_{g}= \frac{6.67e-11Nm^2/kg^2*1.99e30 kg*67.3 kg}{10e4m^2} = 8.93e13 N[/tex]
Fg = 8.93*10^13 N.the amplitude of a wave is
Answer:
The amplitude of a wave is a measure of the displacement of the wave from its rest position. The amplitude is shown on the graph below. Amplitude is generally calculated by looking on a graph of a wave and measuring the height of the wave from the resting position. The amplitude is a measure of the strength or intensity of the wave.
Explanation:
Hope this helps! <3
An electromotive force E(t) = 200, 0 ≤ t ≤ 50 0, t > 50 is applied to an LR-series circuit in which the inductance is 50 henries and the resistance is 5 ohms. Find the current i(t) if i(0) = 0.
Answer:
The answer is below
Explanation:
An LR series circuit has a differential equation in the form of:
[tex]L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=200,for\ 0 \leq t \leq\ 50. Hence:\\\\50\frac{di}{dt}+5i =200\\\\\frac{di}{dt}+0.1i =4\\\\Solving\ the\ differential\ equation:\\\\The\ integrating\ factor(I)=e^{\int\limits {0.1} \, dt }=e^{0.1t}. The\ DE\ becomes:\\\\e^{0.1t}\frac{di}{dt}+e^{0.1t}(0.1i) =4e^{0.1t}\\\\e^{0.1t}i=\int\limits {4e^{0.1t}} \, dt \\\\e^{0.1t}i=40e^{0.1t}+A\\\\i(t)=40+Ae^{-0.1t}\\\\but\ i(0)=0\\\\0=40+Ae^{-0.1(0)}\\\\A=-40\\\\i(t)=40-40e^{-0.1t}\\\\[/tex]
At 50 seconds:
[tex]i(50)=40-40e^{-0.1*50}\\\\i(50)=40-40e^{-5}[/tex]
[tex]L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=0,for\ t> 50. Hence:\\\\50\frac{di}{dt}+5i =0\\\\\frac{di}{dt}+0.1i =0\\\\\frac{di}{dt}=-0.1i\\\\\frac{di}{i}=-0.1dt\\\\\int\limits {\frac{di}{i}} =\int\limits {-0.1} \, dt\\ \\ln(i)=-0.1t+A\\\\taking\ exponential:\\\\i=e^{-0.1t+A}\\\\i=e^{-0.1t}e^A\\\\i(t)=Ce^{-0.1t}\\\\i(50)=40-40e^{-5}=Ce^{-5}\\\\C=40(e^5-1)\\\\i(t)=40(e^5-1)e^{-0.1t}\\\\[/tex]
[tex]i(t)=\left \{ {{40-40e^{-0.1t}\ \ \ \ 0 \leq t \leq 50 } \atop {40(e^5-1)e^{-0.1t}\ \ \ \ t>50}} \right.[/tex]
The volume of a cube is found by multiplying length times
width times height. If an object has a volume of 1.44 m?,
what is the volume in cubic centimeters? Remember to mul-
tiply each side by the conversion factor.
Answer:
The volume in cubic centimeters is 1,440,000
Explanation:
You know that an object has a volume of 1.44 m³ and you want to calculate the volume in cubic centimeters cm³.
The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.
If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:
a ⇒ b
c ⇒ x
So, [tex]x=\frac{c*b}{a}[/tex]
Since 1 m³ is equal to 1,000,000 cm³ ( this is the conversion factor) , then you can apply the following rule of three: if 1 m³ is equal to 1,000,000 cm³, 1.44 m³ is equal to how many cm³?
[tex]cm^{3} =\frac{1.44m^{3}*1,000,000 cm^{3} }{1m^{3} }[/tex]
cm³=1,440,000
The volume in cubic centimeters is 1,440,000
How did the Mayflower Compact influence colonists’ views on government?
Answer:
It demonstrated that the colonists were capable of local, self-government.
Explanation:
this is the correct answer because i have already done this
What can reduce the flow of heat
Answer:
To minimize heat flow through a layer of material by conduction, choose the right material, make the layer as thick as possible, and make the surface area as small as possible. Clothing intended to reduce heat flow should use low-thermal conductivity materials.
Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor dissipates more power
Answer:
A dissipates more power.
Explanation:
In a series circuit, the current is the same at any point in it.The power dissipated in any resistor follows Joule's law, as follows:[tex]P = I^{2} * R[/tex]
So, for a given current, the power is directly proportional to the resistance of the resistor.In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.What are two different ways that resistors can be connected together in a circuit? Explain the difference between the two in terms of calculating equivalent resistance.
Explanation:
Resistors in circuits can either be connected in series or in parallel.
For a series connected resistors, the same current flows through the resistors while different voltages is passed across them. The formula for calculating effective resistances in a circuit is expressed as
[tex]R_T = R_1+R_2+R_3...+R_n[/tex] where R1, R2, R3 etc. are the resistances connected in series.
The effective resistances for series connected resistors is the sum of the individual resistors
For a parallel connected resistors, different current flows through the resistors while same voltage is passed across them. The formula for calculating effective resistances in a circuit is expressed as:
[tex]\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} +...\frac{1}{R_n}[/tex]
The effective resistances for parallel connected resistors is the sum of the reciprocal of the individual resistors
What determines the paths of electrons around a nucleus?
a. the fundamental quantum of energy
b. interaction with other atoms
c magnetism
d. the number of neutrons in the nucleus
Answer:
* positive repulsion, which makes the electrons move as far away as possible
* Attraction with the core atomizes
he analysis is the foundations of quantum theorizing
Explanation:
Electrons are deposited in an atom following two principles.
* positive repulsion, which makes the electrons move as far away as possible
* Attraction with the core atomizes
The mathematical model used for the analysis is the foundations of quantum theorizing
Peter rides his bike 5 blocks north and then 10 blocks east. What is his displacement? What is his total distance traveled?
Answer:
5 blocks east. His total distance is 15 feet.
Explanation:
I hope that this helps! Have a good day!
A ball is thrown upward from the ground with an initial speed of 20.6 m/s; at the same instant, another ball is dropped from a building 14 m high. After how long will the balls be at the same height above the ground?
Answer:
t= 0.68 s
Explanation:
Neglecting air resistance, both balls are only under the influence of gravity, so we can use the kinematic equation for vertical displacement for both balls.First of all, we define two perpendicular axes, coincidently with horizontal and vertical directions, that we denote as x-axis and y-axis respectively.Assuming that the upward direction is the positive one, g must be negative as it always points downward.Taking the ground as our zero reference for the vertical axis (y axis), the equation for the ball thrown upward can be written as follows:[tex]y = v_{o}* t -\frac{1}{2} * g * t^{2} (1)[/tex]
As the second ball is dropped, its initial velocity is 0. Taking the height of the building as the initial vertical position (y₀), we can write the equation for the vertical displacement as follows:[tex]y = y_{o} - \frac{1}2}*g*t^{2} (2)[/tex]
As the left sides of (1) and (2) are equal each other (the height of both balls above the ground must be the same), the time must be the same also.We can rearrange (2) as follows:[tex]y -y_{o} = -\frac{1}{2}*g* t^{2} (3)[/tex]
Replacing the right side of (3) in (1), we get:[tex]y = v_{o}*t + (y- y_{o})[/tex]
⇒ [tex]t =\frac{y_{o} }{v_{o} } =\frac{14 m}{20.6 m/s} = 0.68 s[/tex]
⇒ t = 0.68s
until a train is a safe distance from the station, it must travel at 5 m/s. once the train is on open track, it can speed up to 45m/s. if it takes 8 seconds to reach 4 m/s, what is the acceleration of the train?
Answer:
5 meters per second squared
Explanation:
We calculate the acceleration using the formula:
a = (vf - vi) / t
where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.
In our case:
a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2
If a car is traveling at an average speed of 70 kilometers per hour how long does it take the car to travel 14 kilometers
Answer:
Explanation:
O.20 hour A
If a car is traveling at an average speed of 70 kilometers per hour, 0.2 hours it takes the car to travel 14 kilometers.
What is average speed?By multiplying the distance that an item travels in one unit by the amount of time it takes to go that distance, one may determine the speed of the object. The speed of the item on this voyage, denoted by the letter "s," is equal to s = D/T if "D" is indeed the distance traveled in certain time "T."
Understanding average speed will help you better comprehend the pace of a travel. On a travel, the pace could occasionally change. Knowing the average speed then becomes crucial to getting an idea of how quickly the route will be finished.
Distance covered = average speed × Time travelled
14=70× Time travelled
Time travelled = 0.2 hours
Therefore, 0.2 hours it takes the car to travel 14 kilometers.
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In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasing it from her hand. The pitcher maintains a component of force on the ball of constant magnitude 30.9 N in the direction of motion around the complete path. The speed of the ball at the top of the circle is 16.0 m/s. If she releases the ball at the bottom of the circle, what is its speed upon release?
Answer:
The velocity is [tex]v_b = 20.17 \ m/s[/tex]
Explanation:
From the question we are told that
The mass of the ball is [tex]m = 0.245 \ kg[/tex]
The radius is [tex]r = 59.8 \ cm = 0.598 \ m[/tex]
The force is [tex]F = 30.9 \ N[/tex]
The speed of the ball is [tex]v = 16.0 \ m/s.[/tex]
Generally the kinetic energy at the top of the circle is mathematically represented as
[tex]K_t = \frac{1}{2} * m * v^2[/tex]
=> [tex]K_t = \frac{1}{2} * 0.245 * 16.0 ^2[/tex]
=> [tex]K_t = 31.36 \ J[/tex]
Generally the work done by the force applied on the ball from the top to the bottom is mathematically represented as
[tex]W = F * d[/tex]
Here d is the length of a semi - circular arc which is mathematically represented as
[tex]d = \pi * r[/tex]
So
[tex]W = 30.9 * 0.598 [/tex]
[tex]W = 18.48 \ J [/tex]
Generally the kinetic energy at the bottom is mathematically represented as
[tex]K_b = \frac{1}{2} * m * v_b^2[/tex]
=> [tex]K_b = \frac{1}{2} * 0.245 * v_b^2[/tex]
=> [tex]K_b = 0.1225 * v_b^2[/tex]
From the law of energy conservation
[tex]K_t + W =K_b[/tex]
=> [tex]31.36+ 18.48 = 0.1225 * v_b^2[/tex]
=> [tex]v_b = 20.17 \ m/s[/tex]
Apply the general results obtained in the full analysis of motion under the influence of a constant force in Section 2.5 to answer the following questions. You hold a small metal ball of mass a height above the floor. You let go, and the ball falls to the floor. Choose the origin of the coordinate system to be on the floor where the ball hits, with up as usual. Express all results in terms of , , and . Just after release, what are and
Answer:
y(i) = h
v(y.i) = 0
Explanation:
See attachment for elaboration
A car drives 20 miles north and then 3 miles south. What is the displacement
of the car?
A. 23 miles north
B. 23 miles
C. 17 miles north
D. 17 miles
If the speed of a car is increased by 75%, by what factor will its minimum braking distance be increased, assuming all else is the same
Answer:
breaking distance will increase by a factor 3.0625
Explanation:
From Newton's equation of motion, we can say that;
v² = u² + 2as
Where initial velocity is zero, we have;
v² = 2as
s = v²/2a
Where s is the distance and v is the final speed.
We will assume the deceleration(negative acceleration) is the same value,
Now, we see that the distance is directly proportional to the square of the velocity.
Now, 75% increase in speed means it has increased by a factor of 1.75
Thus means;
1.75²v² is directly proportional to the 1.75²d
Distance =
1.75²v² = 3.0625d
Thus, breaking distance will increase by a factor 3.0625
In a double-slit arrangement the slits are separated by a distance equal to 120 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum
In a double-slit arrangement the slits are separated by a distance equal to 120 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum(b) What is the distance between these maxima on a screen 5.79m from the slits?
Answer:
a
[tex]\theta = 0.476 ^ o[/tex]
b
[tex]y = 0.0481 \ m [/tex]
Explanation:
From the question we are told that
The slit separation is [tex]d = 120 \lambda[/tex]
Here [tex]\lambda[/tex] is the wavelength of the light
Generally the condition for constructive interference is mathematically represented as
[tex]dsin (\theta) = m * \lambda[/tex]
=> [tex]\theta = sin^{-1} [\frac{n * \lambda}{ d } ][/tex]
=> [tex]\theta = sin^{-1} [\frac{n * \lambda}{ 120 \lambda } ][/tex]
Here n is the order of maxima which is 1 given that we are considering the central maximum and an adjacent maximum
So
[tex]\theta = sin^{-1} [\frac{1}{ 120} ][/tex]
=> [tex]\theta = 0.476 ^ o[/tex]
Generally given that the distance of the screen is D = 5.79 m from the slit then the distance between these maxima is mathematically represented as
[tex]y = D tan (\theta )[/tex]
=> [tex]y = 5.79 * tan (0.476)[/tex]
=> [tex]y = 0.0481 \ m [/tex]
