Construct angle XYZ in which XY= 8.3 cm, YZ= 11.9 cm ii, Construct M the midpoint of XZ where XYZ= 60o

The minimum force required to move a block of 35 N resting on a steel table with a coefficient of static friction of 0.40 is 14 N.

Friction refers to the force that resists the motion and thus the force acts in the opposite direction of the force applied.

There are the following types of friction:

1. Static Friction

2. Limiting Friction

3. Kinetic Friction

F = μN

where μ is the coefficient of friction

N is the Normal Force

When the object is resting on a table, Normal force is the weight.

N = 35 N

μ = 0.40

F = 0.4 * 35

= 14 N

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The value of sides are KL=5.34, JK=16.434, JL=17.29 and ML=22.25.

∵ ΔJLM is a right triangle, as ∠MJL=90°

∴ tan(∠JML)= JL/JM            [∵ tan∅=perpendicular/hypotenuse]

⇒ tan(51°)=JL/14

⇒ JL=14×tan(51°)

       = 14×1.23

       = 17.29

∴ JL=17.29

Again, ΔJKL is a right triangle, with ∠JKL=90°

∴ cos(∠JLK)=KL/JL              [∵ cos∅=base/hypotenuse]

⇒cos(72°)= KL/17.29

⇒KL=17.29×cos(72°)

       = 17.29×0.309

        = 5.34

∴ KL=5.34

Hence, the value of KL is 5.34.

Also, tan(∠JLK)=KJ/KL

⇒tan(72°)=JK/5.34

⇒JK=5.34×tan(72°)

       = 5.34×3.077

       = 16.434

∴ JK=16.434

And, cos(∠JML)=JM/ML

⇒cos(51°)=14/ML

⇒ML=14/cos(51°)

        =14/.629

        =22.25

∴ ML=22.25

Hence, the value of sides are KL=5.34, JK=16.434, JL=17.29 and ML=22.25.

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The  volume of the region U is 16π cubic units.

To find the volume of the region U, we can use cylindrical coordinates. In cylindrical coordinates, a point in space is represented by the coordinates (r, θ, z), where r is the distance from the z-axis, θ is the angle between the x-axis and the projection of the point onto the xy-plane, and z is the height above the xy-plane.

In this case, the region U is defined by 0 ≤ r ≤ 2, 0 ≤ θ ≤ 2π, and 0 ≤ z ≤ 12 - r sin(θ).

To find the volume of U, we can integrate over the cylindrical coordinates. The volume of U is given by the integral:

V = ∫∫∫_U dV

where dV = r dz dr dθ is the volume element in cylindrical coordinates.

Substituting in the limits of integration, we have:

V = ∫₀²π ∫₀² ∫₀^(12-rsinθ) r dz dr dθ

Integrating with respect to z, we get:

V = ∫₀²π ∫₀² r(12-rsinθ) dr dθ

Integrating with respect to r, we get:

V = ∫₀²π [(6r² - (1/3)r³sinθ)] from r=0 to r=2 dθ

Simplifying, we get:

V = ∫₀²π [(24 - 16/3 sinθ)] dθ

Integrating, we get:

V = [24θ + 16/3 cosθ] from θ=0 to θ=2π

Simplifying, we get:

V = 48π/3 = 16π

Therefore, the volume of the region U is 16π cubic units.
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Corbin's account will have a higher balance than Victoria's account at the end of 3 years" is true.

To calculate the balance at the end of 3 years, we can use the simple interest formula for Victoria's account and the compound interest formula for Corbin's account.

For Victoria's account:

Simple interest = P * r * t

= 2000 * 0.05 * 3

= $300

Balance after 3 years = P + Simple interest

= 2000 + 300

= $2300

For Corbin's account:

Balance after 3 years = [tex]P * (1 + r)^t[/tex]

= 1800 * (1 + 0.09)³

= $2401.40

Therefore, the statement "Corbin's account will have a higher balance than Victoria's account at the end of 3 years" is true.

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The solutions to the triangle PQR are:

Angle Q ≈ 112°

Side QR ≈ 8.98

Side PR ≈ 13.71

To solve the triangle PQR, we can use the fact that the sum of the angles in a triangle is always 180°. So we can find angle Q by subtracting the measures of angles P and R from 180°:

angle Q = 180° - angle P - angle R

angle Q = 180° - 42° - 26°

angle Q = 112°

Now, we can use the law of sines to find the lengths of the sides QR and PR.

The law of sines states that in any triangle ABC, the following equation holds:

a/sin(A) = b/sin(B) = c/sin(C)

where a, b, and c are the side lengths of the triangle, and A, B, and C are the opposite angles, respectively.

Applying this formula to triangle PQR, we can write:

QR/sin(R) = PQ/sin(Q)

QR/sin(26°) = 19/sin(112°)

Solving for QR, we get:

QR = (19 × sin(26°))/sin(112°)

QR ≈ 8.98

Similarly, we can find PR by applying the law of sines to triangle PQR as follows:

PR/sin(P) = PQ/sin(Q)

PR/sin(42°) = 19/sin(112°)

Solving for PR, we get:

PR = (19 × sin(42°))/sin(112°)

PR ≈ 13.71

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The true statements are Numbers with same absolute value are opposites because they are same distance from each other and from 0 on the number line. The |7.1| = 7.1. So, correct options are B, C and E.

b) Numbers with the same absolute value are opposites because they are the same distance from each other. This is true because absolute value is the distance from a number to zero on the number line, and if two numbers have the same distance from zero, then they must be equidistant from zero and therefore, they are opposite in sign.

c) The |7.1| = 7.1 because the distance from 7.1 to 0 on the number line is 7.1 units. This is true because the absolute value of a number is always positive, and it represents the distance of that number from zero on the number line.

d) The |-8.4| = 8.4 because the distance from -8.4 to 8.4 on the number line is 0 units. This is false, as the distance between -8.4 and 8.4 on the number line is 16.8 units. The correct value of the absolute value of -8.4 is 8.4.

e) Numbers with the same absolute value are opposites because they are the same distance from 0 on the number line. This is true because 0 is the midpoint of the number line, and if two numbers have the same distance from 0, then they must be equidistant from zero and therefore, they are opposite in sign.

Therefore, the correct statements are b, c, and e.

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If he visited all the cities in order A(O,4), B(4,1). C(3. 1) and D(-1. 2). then he traveled 12.3 units distance ( nearest tenth).

John visited four cities that form a rectangle on a coordinate grid at A(0, 4), B(4, 1), C(3, 1), and D(-1, 2). If he visited all the cities in order and ended up where he started, the distance he traveled can be found by calculating the perimeter of the rectangle.

Calculate the distance between consecutive points.
AB = √[(4-0)^2 + (1-4)^2] = √[16 + 9] = √25 = 5
BC = √[(3-4)^2 + (1-1)^2] = √[1 + 0] = √1 = 1
CD = √[(-1-3)^2 + (2-1)^2] = √[16 + 1] = √17 ≈ 4.1 (rounded to nearest tenth)
DA = √[(0-(-1))^2 + (4-2)^2] = √[1 + 4] = √5 ≈ 2.2 (rounded to nearest tenth)

Calculate the total distance traveled (perimeter of the rectangle).
Total Distance = AB + BC + CD + DA = 5 + 1 + 4.1 + 2.2 = 12.3

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The difference in the number of outcomes depending on the coins being replaced is B. 10 outcomes.

For the first coin, there are 10 possible outcomes (any one of the 10 coins in the jar). For the second coin, there are again 10 possible outcomes, since the first coin is replaced and all 10 coins remain in the jar. Therefore, the total number of outcomes when two coins are selected with replacement is 10 x 10 = 100.

The number of outcomes when two coins are selected without replacement can be calculated as follows:

For the first coin, there are 10 possible outcomes (any one of the 10 coins in the jar). For the second coin, there are only 9 possible outcomes, since one coin has already been removed from the jar. Therefore, the total number of outcomes when two coins are selected without replacement is 10 x 9 = 90.

Difference is:

= 100 - 90

= 10 outcomes

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The probability that a) the sample has a proportion between 0.5 and 0.7 is 0.780. b) The probability that the sample has a proportion within 5% is 0.819. c) The probability that the sample has a proportion less than 0.50 is 0.001. d) The probability that the sample has a proportion greater than 0.80 is 0.000.

a) To calculate this probability, we first need to standardize the interval (0.5, 0.7) using the formula: z = (p - P) / (σ / √(n))

where p is the sample b, P is the population proportion, σ is the standard deviation of sample proportions, and n is the sample size. Substituting the values, we get:

z1 = (0.5 - 0.62) / (0.8 / √(40)) = -2.24

z2 = (0.7 - 0.62) / (0.8 / √(40)) = 1.12

Using the standard normal table or calculator, the area between -2.24 and 1.12 is 0.780. Therefore, the probability that the sample has a proportion between 0.5 and 0.7 is 0.780.

b) The probability that the sample has a proportion within 5% of the population proportion is 0.819. We can find the range of sample proportions within 5% of the population proportion by adding and subtracting 5% of the population proportion from it, which gives: P ± 0.05P = 0.62 ± 0.031

The interval (0.589, 0.651) represents the range of sample proportions within 5% of the population proportion. To calculate the probability that the sample proportion falls within this interval, we standardize it using the formula above and find the area under the standard normal curve between -1.55 and 1.55, which is 0.819.

c) The probability that the sample has a proportion less than 0.50 is 0.001. To calculate this probability, we standardize the value of 0.50 using the formula above and find the area to the left of the resulting z-score, which is: z = (0.50 - 0.62) / (0.8 / √(40)) = -4.46

Using the standard normal table or calculator, the area to the left of -4.46 is 0.001. Therefore, the probability that the sample has a proportion less than 0.50 is 0.001.

d) The probability that the sample has a proportion greater than 0.80 is 0.000. To calculate this probability, we standardize the value of 0.80 using the formula above and find the area to the right of the resulting z-score, which is: z = (0.80 - 0.62) / (0.8 / √(40)) = 5.60

Using the standard normal table or calculator, the area to the right of 5.60 is very close to 0.000. Therefore, the probability that the sample has a proportion greater than 0.80 is 0.000.

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A definite integral is defined as the signed area under a function between certain limits (bounds) of integration.

An indefinite integral represents the family of antiderivatives of a function and is also known as its general integral or antiderivative.

An indefinite integral represents the family of antiderivatives of a function and is also known as its general integral or antiderivative. An indefinite integral does not have specific limits of integration; its result includes a constant of integration (usually denoted +C), which accounts for all possible constant shifts within its antiderivative.

A definite integral is defined as the signed area under a function between certain limits (bounds) of integration. The real number that represents its net area between it and x-axis during an interval.

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The correct option is D, the statement that best describes the expression 4+3x means "4 plus 3 times x".

An expression is a combination of numbers, symbols, and/or variables that represents a mathematical or logical statement. It can be as simple as a single number or letter, or as complex as a series of operations that involve multiple variables and functions. Expressions can be used to represent equations, inequalities, functions, and other mathematical concepts. They can be evaluated to produce a numerical value or a boolean value (true or false) depending on the values of the variables involved.

Expressions are used to represent calculations or logical conditions. They can be used to assign values to variables, manipulate data, and control the flow of a program. expressions are a fundamental concept in both mathematics and computer science, and play a critical role in solving problems and building complex systems.

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Step-by-step explanation:

[tex] - \infty \: and \: 0[/tex]

or

[tex]x \leqslant 1[/tex]

Therefore, Sara has 3.5 grams of white beads in her jar.

Based on the information provided, Sara has 2.5 grams of blue beads, 4.9 grams of pink beads, and 7.1 grams of yellow beads. If she weighs her jar this week and finds out she has a total of 18 grams of beads, we can determine the number of grams of white beads she has by following these steps:

Step 1: Add the weights of the blue, pink, and yellow beads together.
2.5 grams (blue) + 4.9 grams (pink) + 7.1 grams (yellow) = 14.5 grams

Step 2: Subtract the total weight of the blue, pink, and yellow beads from the total weight of the jar (18 grams).
18 grams (total weight) - 14.5 grams (blue, pink, and yellow beads) = 3.5 grams
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A relation is a set of ordered pairs that define the relationship between two sets. And, a function is a relation in which each element of the domain is connected to a single element of the codomain. The evaluated function is -10.

To find the expression (f(7) - f(3))/ 7 -3, we need to first find f(7) and f(3).

Using the given function F(X) = - 8 - x^2, we can find:

f(7) = -8 - 7^2 = -57

f(3) = -8 - 3^2 = -17

Now, we can substitute these values into the expression:

(f(7) - f(3))/ 7 -3 = (-57 - (-17))/ (7-3) = -40/4 = -10

Therefore, the answer is -10.
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The time taken by the younger sister to finish the same work by herself is 12 hours.

To solve the problem of how long it will take the younger sister to finish the job by herself, let's use the following terms:

1. Older sister's work rate = O
2. Younger sister's work rate = Y
3. Time taken by the younger sister alone = T

Given that the older sister works 3 times faster than the younger sister, we have:  O = 3Y.

Also, the sisters together can finish the job in 3 hours. Therefore, their combined work rate is equal to completing 1/3 of the job per hour. So,

O+Y=1/3.

Now, we can substitute O with 3Y:  3Y+Y=1/3. Combine the terms and simplify:

4Y=1/3

Now, solve for Y:

Y=1/12

Since Y is the work rate of the younger sister, to find the time it takes for her to complete the job alone (T), we can use the following formula:

Work rate × Time = 1 job.

So, Y × T = 1.

Substitute Y with  1/12:

[tex]\frac{1}{12} \times T=1[/tex]

Now, solve for T:

T = 12.

Therefore, it will take the younger sister 12 hours to finish the job by herself.

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Step-by-step explanation:

To solve for inverse, utilize the following steps.

Step 1: let f(x)=y so we get

[tex]y = \sqrt{x - 6} + 5[/tex]

Step 2: Swap y and x

[tex]x = \sqrt{y - 6} + 5[/tex]

Solve for y.

[tex]x - 5 = \sqrt{y - 6} [/tex]

[tex](x - 5) { }^{2} + 6 = y[/tex]

Step 4: Let y =f^-1(x)

[tex](x - 5) {}^{2} + 6 = f {}^{ - 1} (x)[/tex]

Answer: [tex]f^{-1}(x) =[/tex] x²-10x+19

Step-by-step explanation:

Let's replace f(x) for y for now.

[tex]y=\sqrt{x-6}+5[/tex]

To find inverse.  make your y into x, and your x into y

[tex]x=\sqrt{y-6}+5[/tex]        >Now you solve for y.  subtract 5 from both sides

[tex]x-5=\sqrt{y-6}[/tex]        >Square both sides to get rid of root

[tex](x-5)^{2} =(\sqrt{y-6})^{2}[/tex]     >drop root and square (x-5)

(x-5)(x-5) = y-6              >FOIL

x²-5x-5x+25 = y-6        > combine like terms

x²-10x+25 = y-6            >add 6 to both sides

x²-10x+19=y            > this is your inverse now put the y into inverse form

[tex]f^{-1}(x) =[/tex] x²-10x+19

Length of the platform at the front of the room whose area is 3x² + 10x - 8 and width is (x+4) m is (3x - 2) m

Area of the rectangular platform = 3x² + 10x - 8

Width of the rectangular platform = x+4

Area = length × width

Length = area/width

Length = [tex]\frac{3x^{2} + 10x - 8}{x+4}[/tex]

By splitting the middle term we get

Length = [tex]\frac{3x^{2} + 12x -2x -8 }{x+4}[/tex]

By taking common we get

Length = [tex]\frac{3x(x+4) - 2(x+4)}{x+4}[/tex]

By taking x+4 common we get

Length = [tex]\frac{(3x-2)(x+4)}{x+4}[/tex]

Cutting the x+4 from denominator and numerator we get

Length = 3x-2

Length of the platform at the front of room is 3x-2

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Each of the three sisters owes $75 to cover the cost of hiring the karaoke deejay for Taylor's graduation party.

To determine how much each sister owes, we need to first calculate the total cost of the party and then divide that cost by three, since there are three sisters splitting the cost.

1. Tent rental: $45
2. Microphone system: $60
3. Deejay cost: $30/hour × 4 hours = $120

Now, we'll add these costs together to find the total cost:
Total cost = $45 (tent) + $60 (microphone) + $120 (deejay) = $225

Finally, we'll divide the total cost by the number of sisters (3) to find out how much each sister owes:
Amount owed per sister = $225 (total cost) ÷ 3 (sisters) = $75

So, each sister owes $75 for the karaoke deejay at Taylor's graduation party.

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The equilibrium quantity is approximately 34.47 items and the producer surplus at the equilibrium quantity is approximately 396.11.

To find the equilibrium quantity, we need to find the quantity at which the demand and supply functions are equal:

Demand function: d(x) = 588.7 – 0.4x^2

Supply function: s(x) = 8(x) = 0.322

Setting these two functions equal to each other, we get:

588.7 – 0.4x^2 = 0.322x

Simplifying this equation, we get:

0.4x^2 + 0.322x - 588.7 = 0

Using the quadratic formula, we get:

x = (-0.322 ± √(0.322^2 + 40.4588.7)) / (2*0.4)

x ≈ 34.47 or x ≈ -43.67

Since we cannot have a negative quantity, the equilibrium quantity is approximately 34.47 items.

To find the producer surplus at the equilibrium quantity, we need to calculate the area between the supply curve and the equilibrium price, which is the price that corresponds to the equilibrium quantity. We can find the equilibrium price by plugging the equilibrium quantity into either the demand or supply function:

s(34.47) = 8(34.47) = 11.58

So the equilibrium price is approximately 11.58.

Now we can find the producer surplus by integrating the supply function from 0 to the equilibrium quantity, and subtracting the result from the area of a rectangle with height equal to the equilibrium price and width equal to the equilibrium quantity. The formula for producer surplus is:

Producer Surplus = (Equilibrium Price * Equilibrium Quantity) - ∫[0, Equilibrium Quantity] Supply Function dx

Plugging in the values we found, we get:

Producer Surplus = (11.58 * 34.47) - ∫[0, 34.47] 0.322 dx

Integrating the supply function, we get:

∫[0, 34.47] 0.322 dx = 0.322 * 34.47 ≈ 11.10

So the producer surplus is:

Producer Surplus ≈ (11.58 * 34.47) - 11.10 ≈ 396.11

Therefore, the equilibrium quantity is approximately 34.47 items, and the producer surplus at the equilibrium quantity is approximately 396.11.

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The mass of the Antarctic iceberg is approximately 2.56 × 10¹more kilograms than the mass of the Rock of Gibraltar.

To find out, we can subtract the mass of the Rock of Gibraltar from the mass of the Antarctic iceberg:

4.55 × 10¹³ kg - 1.78 × 10¹² kg = 4.37 × 10¹³ kg

Therefore, the mass of the Antarctic iceberg is about 2.56 × 10¹ (or 25.6) times greater than the mass of the Rock of Gibraltar.

This is because the mass of the Antarctic iceberg is much larger than the mass of the Rock of Gibraltar, as it is a massive block of ice floating in the ocean while the Rock of Gibraltar is a solid rock formation on land.

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After 5 years with 8% depreciation, the Audi R8's value will be around $81,249.36.

To determine how much money you must have in your account now, you can use the formula A = Pe^(rt), where A is the final amount, P is the principal (the initial amount invested), e is the constant 2.71828, r is the annual interest rate expressed as a decimal, and t is the time in years. We will calculate using this formula.Plugging in the given values, we get:
A = $23,000
r = 0.068 (6.8% expressed as a decimal)
t = 5 years
So, $23,000 = P*e^(0.068*5)
Solving for P, we get:
P = $16,376.59
Therefore, you must have $16,376.59 in your account now to reach your goal of $23,000 in 5 years with 6.8% continuous compounding interest. To determine how much the Audi R8 will be worth in 5 years, you can use the formula A = P(1 - r)^t, where A is the final amount, P is the initial amount, r is the annual depreciation rate expressed as a decimal, and t is the time in years. Plugging in the given values, we get:
P = $148,700
r = 0.08 (8% expressed as a decimal)
t = 5 years
So, A = $148,700*(1 - 0.08)^5
Simplifying, we get:
A = $81,249.36
Therefore, the Audi R8 will be worth approximately $81,249.36 in 5 years with 8% depreciation.

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Answer: The answer is (A

Step-by-step explanation:

The answer isB because A is constant, C is irrelevant, and D is dependent.

The measure of the smallest angle is 37.1 degrees

From the question, we have the following parameters that can be used in our computation:

The legs of a right triangle measure 11.4 meters and 15.1 meters

So, the measure of one of the acute angles is

tan(x) = 11.4/15.1

Evaluate

tan(x) = 0.7550

Take the arc tan of both sides

So, we have

x = 37.1

This means that the measure of the smallest angle is 37.1 degrees

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Thus, the coordinates of ΔF'I'G' after a rotation of 90° clockwise about the origin. are - F'(4,-2), I'(4,-5) and G'(2,-3).

A rotation is a turn made about a specific axis. Both clockwise and anticlockwise rotations are possible. Whereas the image is really the rotating image, the pre-image is the original item.

From the pre-image point, calculate the image. The listed pre-image point is (x , y). Change the x and y coordinates, then multiply this same previous y coordinate by -1 to get a 90 degree anticlockwise rotation. Use the guidelines mentioned below to calculate each rotation.

Clockwise :

Given :

F(2, 4), I(5, 4) and G(3, 2)

After 90 degree rotation: (x , y) ----> (y , -x)

F'(4,-2), I'(4,-5) and G'(2,-3).

Thus, the coordinates of ΔF'I'G' after a rotation of 90° clockwise about the origin. are - F'(4,-2), I'(4,-5) and G'(2,-3).

Graphs for the both triangles are obtained.

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Correct question:

ΔFIG has vertices at F(2, 4), I(5, 4) and G(3, 2). Graph ΔFIG and ΔF'I'G' after a rotation of 90° clockwise about the origin.​

To calculate d²y/dx², we first need to find the first derivative of y, which is dy/dx. For y = 0.5x^-0.2, we can use the power rule of differentiation, which states that the derivative of x^n is n*x^(n-1). Therefore,

dy/dx = -0.1x^-1.2

To find the second derivative, d²y/dx², we need to differentiate dy/dx again. Using the power rule again, we get:

d²y/dx² = 0.12x^-2.2

This is the second derivative of y with respect to x.

In calculus, a derivative is a measure of how a function changes as its input changes. The second derivative is a measure of how the rate of change of the function itself changes as its input changes. It tells us about the curvature of the function at any given point.

In this case, we have calculated the second derivative of y, which gives us information about the rate of change of the slope of the function. If the second derivative is positive, the function is concave up (curving upward), and if it is negative, the function is concave down (curving downward). If the second derivative is zero, the function has an inflection point (a point where the curvature changes direction).

Overall, the second derivative is a powerful tool in calculus that helps us understand the behavior of functions in more detail.

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Answer:

The radius of the basketball is 20 cm.

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr^3, where V is the volume and r is the radius.

We are given that the volume of the basketball is 11488.2 cm, so we can set up the equation:

Simplifying, we get:

Dividing both sides by (4/3)π, we get:

Taking the cube root of both sides, we get:

Rounding to the nearest whole number, the radius of the basketball is 20 cm.

a) The median of the dataset is: 11.5

b) The mean of the dataset is: 12.5

c) The mode of the dataset is: 9 and 14

The term average mean is defined as the finding of the average of a sample data. Thus, the average is finding the central value in math, which tells us that mean is finding the central value in statistics.

The numbers arranged in ascending order is:

5, 7, 9, 9, 14, 14, 19, 23

a) The median is defined as the middle term of the distribution when arranged in ascending or descending order. Thus, the median here is:

(9 + 14)/2 = 11.5

b) The mean of the data is expressed as:

(5 + 7 + 9 + 9 + 14 + 14 + 19 + 23)/8

= 12.5

c) The mode is the most frequently occurring term in the data.

In this case, the mode is 9 and 14

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r has negative values when 2 cos θ > 1, and positive values otherwise.

r has negative values when 3θ is in the second or third quadrant, and positive values otherwise.

r has negative values when sin θ > 1/5, and positive values otherwise.

To find the intervals of positive and negative r values, we need to look at the cosine function. Since the cosine function has a maximum value of 1, we have r = 1 - 2 cos θ ≥ -1. Solving for cos θ, we get 2 cos θ ≤ 2, which means that r is negative when 2 cos θ > 1 and positive otherwise.

We can rewrite the polar equation r = 5 sin (3θ) as r = 5(sin θ)(cos^2 θ)(3)^(1/2). This equation is negative when sin θ is negative, which happens in the second and third quadrants. Therefore, r is negative when 3θ is in the second or third quadrant and positive otherwise.

Similarly, we can rewrite the polar equation r = 1 - 5 sin θ as r = 5(cos θ)(sin(π/2 - θ)). This equation is negative when sin(π/2 - θ) is negative, which happens when θ is in the second and third quadrants. Therefore, r is negative when sin θ > 1/5, and positive otherwise.

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Answer:

The answer is C. x=z

Step-by-step explanation:

The correct answer is C. x=z.

Since x = y and y = z, then x = z. This is the transitive property of equality.

Here is a more detailed explanation:

The transitive property of equality states that if a = b and b = c, then a = c.

In this case, x = y and y = z. Therefore, x = z.