Consider this situation: A force is applied to a box to move it
to the right across the kitchen floor. Of the forces listed,
identify which act upon the box.

Answers

Answer 1

Answer:

The static "frictional force" and the "kinetic friction" will act on the box.

Answer 2

When  A force is applied to a box to move it to the right across the kitchen floor, static friction force comes into play before start moving. When the box starts moving, dynamic friction force comes into play.

What is friction?

The resistance provided by surfaces in touch as they move past one another is known as friction.

To walk without slipping, traction is provided by friction. In most situations, friction is advantageous. They do, however, give a strong amount of opposition to the move.

When  A force is applied to a box to move it to the right across the kitchen floor, static friction force comes into play until it starts moving. When the box starts moving, dynamic friction force comes into play.

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Related Questions

Write a paragraph on the nervous system.

Answers

Answer:

The basic building block of the nervous system is a nerve cell, or neurone. Neurones are shaped differently depending on where they are in the body and what role they play. All neurones have finger-like projections called dendrites and a long fibre called an axon.  In many cases, the axon is coated by a specialised membrane called a myelin sheath. The axon feathers out and has a number of bumps on it. Each bump sits near to a dendrite from another neurone. The space between the bump and the dendrite is called a synapse. Messages jump the synapse from one neurone to the next, using special chemicals called neurotransmitters.

Unlike other cells in the body, neurones aren’t easily replaced if they die or are damaged by infection or injury

Explanation: I hope this helped :)


A car is moving at a velocity of 25 ms-1.
It accelerates at a rate of 6 ms-2.
Find its velocity after 3 seconds

Answers

Velocity = 25 + (6x3)= 43 m/s

PLEASE HELP, WILL MARK BRAINLIEST
What objects exert the attractive force of gravity?
(1 Point)
Anything that has mass
Only planets, moons and stars
Only the Earth and the Sun
Only objects the size of the Earth or larger.

Answers

Answer:

Anything that has mass.

Explanation:

Answer: Anything that has mass.

Explanation:

It is not necessary to wear a lifejacket on a boat as long as there is one available.
Please select the best answer from the choices provided.
ОТ
OF

Answers

Answer:

OF I;m pretty sure.

Hope this helps

Answer:

False, Is the more likely answer.

1. An unbalanced force of 25N is applied to a 12kg mass. What is the acceleration of the mass?

Answers

Answer:

a=2.1 m/s^2

Explanation:

F=ma

a=F/m

a=25/12

a=2.1 m/s^2

what is 1/2 / 1/4. Please help am getting two answers.idk the correct one.​

Answers

Answer:

2

hope this helps :)

A student uses two identical balls to perform an investigation. The students throws ball a with a horizontal velocity from a height of 10 meters. At the same time another students drops ball b from the same height without horizontal velocity. Neglecting air resistance what can you expect to when the balls will land?

Answers

Answer:

Both objects will land at the same time

Explanation:

The ball projected with a horizontal velocity has a vertical component of velocity which is independent of the horizontal velocity. The horizontal component of the velocity enables the ball to travel a horizontal distance, s The initial component of the vertical download velocity is zero.

Similarly, the object dropped from the height above the ground has an initial vertical velocity zero.

Neglecting air resistance, objects falling near the surface of the earth experience the same acceleration due to gravitational force of the earth, g = 9.8 meters per second squared (9.8 m/s²). So the acceleration is the same for the objects, and consequently their velocity is also increasing at a constant rate. After some time, t, both objects would have been accelerated downwards to the same extent, and would thus land at same time, t.

State the forces acting on an object that is stationary/moving. Explain how acceleration changes when the same object is kicked with a great force and a small force. Describe the difference in the movement if the initial object now weighs 50 lbs and is acted on by a small force and a large force.​

Answers

Answer:

it all is force I the barly kick you then it won't do that much date but If the full force kick you then it might hurt.

Explanation:

i hope this helps

Which statement best explains why the overall charge on an atom is zero?

The positive charge of the neutrons in the nucleus equals the negative charge in the electron cloud.
The positive charge of the protons in the nucleus equals the negative charge in the electron cloud.
The negative charge of the neutrons in the nucleus equals the positive charge in the electron cloud.
The negative charge of the protons in the nucleus equals the positive charge in the electron cloud

Answers

Answer:

2nd statement is answer

Explanation:

Answer:

B. The positive charge of the protons in the nucleus equals the negative charge in the electron cloud.

Explanation:

got it right on t4l :D

The atomic mass of an atom do not contain electrons because

Electrons do not exist in all atoms.
Electrons are so small that it does not affect the mass of an atom.
Electrons are do not contain mass.
Electrons are not as important as protons and neutrons.

Answers

Answer:

Electrons are so small that it does not affect the mass of atom .

Explanation:

Electrons are much smaller in mass than protons, weighing only 9.11 × 10^-28 grams, or about 1/1800 of an atomic mass unit. Therefore, they do not contribute much to an element's overall atomic mass.

Answer:

Electrons are so small that it does not affect the mass of an atom

Explanation:

If gravity is the only force acting on you, why
aren't you moving down right now?

Answers

Answer: Because the force of gravity depends on the size of the planet, so a smaller planet will have less gravitational force than a larger planet. So our gravitational force is not as strong as a bigger planet so we can still stand up and jump normally but on a smaller planet we could jump higher and on a bigger planet, we could not even be able to jump at all.

Answer:

gravity holds you down, floors protect that

Explanation:

Karen has 50 cats, Gary has 14 fewer cats than Karen and Billy has 8 times more than Gary. How many cats does Billy have?

Answers

Answer:

The answer is:

14 x 8= 1.120

Answer:

288 cats

Explanation:

K = 50

G = 50 - 14 = 36

B = 36 x 8 = 288

Billy has 288 cats.

Please let me know if I'm incorrect!

a soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of the cliff What is the time of flight of the soccer ball?

Answers

2 seconds because time=distance/speed so time=16/8 which gives 2

The time of flight of the soccer ball is 2 seconds.

Given the following data:

Initial speed = 8 m/sDisplacement = 16 meters.

To find the time of flight of the soccer ball;

Mathematically, the time of flight for a horizontal displacement is given by the formula;

[tex]Time \;of \;flight = \frac{Displacement}{Initial \; velocity}[/tex]

Substituting the values into the formula, we have;

[tex]Time \;of \;flight = \frac{16}{8}[/tex]

Time of flight = 2 seconds.

Therefore, the time of flight of the soccer ball is 2 seconds.

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What affect does doubling the net force have on the acceleration of the object (when
the mass of the object stays the same)? Identify a set of two trials that support your answer to question 1

Answers

Answer: The acceleration doubles

===========================================================

Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

---------------

In summary, if you double the net force applied to the object, then the acceleration doubles as well.

Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.

So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.

We don't know anything about the "trials".  This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.

We also don't know anything about "question 1".

How can you tell the difference between a colloid and a suspension?

Answers

Answer: Particles in a suspension are usually more than 1,000 nm, while those in a colloid range from 1-1,000 nm. Unlike those in a suspension, particles in a colloid do not separate when sitting still. ... Particles in a suspension can be seen by the naked eye, but those in a colloid must be viewed using a light microscope.

hope this helps:)

Explanation:

Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 63.9 N63.9 N , Jill pulls with 79.1 N79.1 N in a direction 45° to the left, and Jane pulls in a direction 45° to the right with 183 N183 N . (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?) Find the magnitude of the net force the people exert on the donkey.

Answers

Answer:

a) F = (137.4 i ^ + 185 j ^) N

b)    F = 230.2 N  ,  θ = 53.5º

Explanation:

In this exercise we ask to find the net force, for which we will define a coordinate system fix the donkey and use trigonometry to decompose the forces

Jack       F₁ₓ = 63.9 N

Jill          F₂ = 79.1 N with direction 45º to the left

              cos (180 -45) = F₂ₓ / F₂

              sin 135 = [tex]F_{2y}[/tex] / F₂

              F₂ₓ = F₂ cos 135

              F_{2y} = F₂ sin 135

              F₂ₓ = 79.1 cos 135 = -55.9 N

              F_{2y} = 79.1 sin 135 = 55.9 N

Jane      F₃ = 183 N direction 45th to the right

             cos 45 = F₃ₓ / F3

             sin 45 = F_{3y} / F3

             F₃ₓ = F₃ cos 45 = 183 cos 45

             F_{₃y} = F₃ sin 45 = 183 sin 45

             F₃ₓ = 129.4 N

             F_{3y} = 129.4 N

we add each component of the force

       Fₓ = F₁ₓ + F₂ₓ + F₃ₓ

       Fₓ = 63.9 + (-55.9) + 129.4

       Fₓ = 137.4 N

       F_{y} = F_{2y} + F_{3y}

       F_{2y} = 55.9 + 129.4

       F_{2y} = 185.3 N

we can give the result of the forms

 

a) F = (137.4 i ^ + 185 j ^) N

b) in the form of module and angle

         F = RA (Fₓ² + F_{y}²)

         F = Ra (137² + 185²)

         F = 230.2 N

         tan θ = F_{y} / Fₓ

         θ = tan⁻¹ F_{y} / Fₓ

        θ = tan⁻¹ (185/137)

        θ = 53.5º

what would the acceleration of the car be ?

Answers

Explanation:

Here you go, hope this helps!

two same size anvils are dropped from different heights. Assume both anvils are made of the same material (iron) and there is no air resistance. Which anvil has the greatest acceleration during the fall? ​

Answers

Everything falls at the same rate.

A bomber is flying at a height of 9 km at 800 km/h. How far in front of the target should he drop his bombs?

Answers

Answer:

The distance in front of the target is 9.524 km

Explanation:

Given;

height of the bomber above the ground, h = 9 km = 9000 m

velocity of the bomber, v = 800 km/h = 222.22 m/s

The time the bomb will get to the target is given by;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2*9000}{9.8} }\\\\ t = 42.857 \ s[/tex]

The lead distance or distance in front of the target is given by;

x = vt

x = (222.22 m/s) x (42.857 s)

x = 9523.68 m

x = 9.524 km

Therefore, the distance in front of the target is 9.524 km

In front of the target, the distance will be "9.524 km".

Distance and Height

According to the question,

Bomber's height, h = 9 km or,

                                = 9000 m

Bomber's velocity, v = 800 km/h or,

                                  = 222.22 m/s

Now,

The time will be:

→ t = [tex]\sqrt{\frac{2h}{g} }[/tex]

By substituting the values, we get

     = [tex]\sqrt{\frac{2\times 9000}{9.8} }[/tex]

     = [tex]\sqrt{\frac{18000}{9.8} }[/tex]

     = 42.857 s

hence,

The lead distance will be:

→ x = vt

By putting the values,

     = 222.22 × 42.857

     = 9523.68 or,

     = 9.524 km

Thus the above answer is correct.

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I WILL GIVE BRAINLIEST A battery contains two metals that have different tendencies to attract electrons. If one is lithium with an electron affinity of −3.05, and the other is zinc with an electron affinity of −0.76, describe how the electrons will flow. Then, describe how you could make this an even stronger battery. (4 points)

Answers

Answer:

electrons will flow from lower (lithium) to higher (zinc)

You can make a stronger battery by having a larger electron affinity difference.

Hope this helps \(-._.-)/

What is the smallest animal on earth?

Answers

Answer:

Pa edo phr yne amanuensis

Explanation:

is a species of microhylid frog from Papua New Guinea. At 7.7 mm in snout–to–vent length, it is considered the world's smallest known vertebrate. The species was listed in the Top 10 New Species 2013 by the International Institute for Species Exploration for discoveries made during 2012

Does horizontal motion have any formula?

Answers

X = v*t is the formula for horizontal projectile motion

The connections of many simple pieces in the brain is evidence of the:
O A. lobes of the brain
B. brain's complexity
C. function of neurons
D. cerebral cortex

Answers

B. Brains Conplexity

Hope This Helps ♡

Answer:

B. brain's complexity

Explanation:

Ape.x

The frequency of a F-sharp sound wave in music is 370 Hz, and its wavelength is 0.93 m. what is the wave speed?

Answers

Answer:

wave speed =344.1 m/s

using v=fΠ

where v is the speed

The wave speed will be 344.1 m/sec. The wave speed is found as the product of the wavelength and the frequency of the wave.

What is wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The given data in the problem is;

v is the speed = ?

f is the frequency= 370 Hz

λ is the wavelength of the wave=0.96 m

The relationship between the wave's wavelength, frequency, and speed is given as;

wavelength = speed of wave / frequency

[tex]\rm \lambda = \frac{v}{f} \\\\ v = \lambda \times f \\\\ v = 0.93 \times 370 \ Hz \\\\ v= 344.1 \ m/sec[/tex]

Hence, the wave speed will be 344.1 m/sec.

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When you move a magnet into a coil of wires, it induces a current in the wires. When you take the same magnet and move it in the opposite
direction through the coils, it still induces a current. What is differnet about the currents created in these situations?

Answers

Answer:

If in an area, the magnetic flux will change then the emf (Electromotive force) induced in the wire will induce current flow in it.

If we moved the magnet inside coil of wire then its change in flux is more compared to the outside moving magnet then the induced current is more in the magnet that moves inside coil of wire

Explanation:

A 22 kg toboggan is pulled along at a constant speed by a horizontal force of 31N. a) What is the force of gravity on the toboggan? b) What is the coefficient of friction? c) How much force is needed to pull the toboggan if two children each with a mass of 50 kg are sitting on it?

Answers

(a) This is essentially asking for the weight of the toboggan, which is

w = (22 kg) (9.80 m/s²) = 215.6 N ≈ 220 N

(b) Being pulled with constant speed means the toboggan is in equilibrium, so

n + (-w) = 0

where n is the magnitude of the normal force, and

31 N + (-f ) = 0

where f is the magnitude of the friction force.

f is proportional to n by a factor of µ such that

f = µ n

We have

n = w = 215.6 N

f = 31 N

so

31 N = µ (215.6 N)   →   µ ≈ 0.14

(c) Let p denote the magnitude of the required pulling force. The combined mass of the toboggan and children is now 122 kg, so its weight is

w = (122 kg) (9.80 m/s²) = 1195.6 N

which means the normal force is also n = 1195.6 N.

We want to have

p + (-f ) = 0   →   p = f

so we just need to find the magnitude of the friction force using the coefficient from part (b).

p = f = 0.14 (1195.6 N) ≈ 170 N

A Punnett square is used to determine the *

Answers

Answer:

predict the genotypes of a particular cross or breeding experiment

Explanation:

Answer:

A.

Explanation:

If two cars are 5 m apart, and one car has a mass of 2,565 kg and the other
car has a mass of 4,264 kg, what is the gravitational force between the two
cars? Newton's law of gravitation is F gravity
Gm; m2 The gravitational
constant G is 6.67 x 10-11 Nm2/kg?.
A. 5.84 x 10-6N
B. 4.37 % 105 N.
C. 1.46 10-4N
D. 2.92 x 10-5 N

Answers

Gravitational force between two cars are 2.92 × 10 ⁻¹¹ Nm²/kg.

The universal force of attraction happened between two objects is called as gravitational force.

The mass of the two cars, m₁ = 2565 kg

                                            m₂ = 4264 kg

                                             r = 5m

                                            G = 6.67 ₓ 10 ⁻11 Nm²/kg

How gravitational force can be calculated?

Definition of gravitational force: The force of attraction between any two bodies is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

                            F ∝ m₁ m₂ ÷ r²

where the force exerted between the two masses m₁ and m₂,

                            F = G (m₁ m₂) ÷ r²

where as,  F - Gravitational force between two bodies,

                 G - Gravitational constant,

                 m₁ - mass of the first body,

                m₂ - mass of the second body,

                r² - square of the distance between two bodies.

                        F= 6.67 × 10⁻¹¹ Nm²/kg ( 2565 kg × 4264 kg) ÷ ( 5²)

         Hence,

                         F = 2.92 × 10⁻⁵ N

Option D is correct answer.

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Birdman is flying horizontally at a
speed of 17 m/s and a height of 78
m. Birdman releases a turd directly
above the start of the field. How far
from the start of the field should the
robot hold the bucket to catch the
turd?

Answers

Answer:

68 m

Explanation:

Given that the horizontal velocity of the birdman = 17 m/s and

the height, h= 78 m.

The gravitational force is acting in the downward direction, so it will not change the horizontal speed.

The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.

Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, [tex]u_0=17[/tex] m/s.

In the vertical direction, u = 0,

The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e

s= 78 m

Let t be the time taken to cover a distance of 78 m.

Now, applying the equation of motion in the vertical direction,

[tex]s=ut+\frac 12 at^2[/tex]

where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.

Here, [tex]a=g=9.81 m/s^2[/tex], so

[tex]78=0\times t +\frac 12 (9.81)t^2[/tex]

[tex]\Rightarrow t^2=(78\times2)/9.81[/tex]

[tex]\Rightarrow t = 4[/tex] seconds.

Hence, the time taken to reach the ground is 4 seconds.

As the horizontal speed, [tex]u_0=17[/tex] m/s, is constant throughout the journey, so

the horizontal distance covered by turd

[tex]= u\times t[/tex]

[tex]= 17 \times 4 = 68[/tex] m.

So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly  above the start of the field.

Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.

What is the equation for momentum (p)?
O A. p = mgh
B. p = my
C. p = ma
O D. p = 127v2

Answers

p=mv. Im guessing theres a typo in choice b.
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