Consider the balloon and air inside the flask to be a closed system. Use the First Law of Thermodynamics to explain what happened to the balloon as heat was added by the environment.

Solution :

Given :

Rectangular wingspan

Length,L = 17.5 m

Chord, c = 3 m

Free stream velocity of flow, [tex]$V_{\infty}$[/tex] = 200 m/s

Given that the flow is laminar.

[tex]$Re_L=\frac{\rho V L}{\mu _{\infty}}$[/tex]

      [tex]$=\frac{1.225 \times 200 \times 3}{1.789 \times 10^{-5}}$[/tex]

    [tex]$= 4.10 \times 10^7$[/tex]

So boundary layer thickness,

[tex]$\delta_{L} = \frac{5.2 L}{\sqrt{Re_L}}$[/tex]

[tex]$\delta_{L} = \frac{5.2 \times 3}{\sqrt{4.1 \times 10^7}}$[/tex]

    = 0.0024 m

The dynamic pressure, [tex]$q_{\infty} =\frac{1}{2} \rho V^2_{\infty}$[/tex]

                                           [tex]$ =\frac{1}{2} \times 1.225 \times 200^2$[/tex]

                                          [tex]$=2.45 \times 10^4 \ N/m^2$[/tex]

The skin friction drag co-efficient is given by

[tex]$C_f = \frac{1.328}{\sqrt{Re_L}}$[/tex]

     [tex]$=\frac{1.328}{\sqrt{4.1 \times 10^7}}$[/tex]

     = 0.00021

[tex]$D_{skinfriction} = \frac{1}{2} \rho V^2_{\infty}S C_f$[/tex]

                  [tex]$=\frac{1}{2} \times 1.225 \times 200^2 \times 17.5 \times 3 \times 0.00021$[/tex]

                  = 270 N

Therefore the net drag = 270 x 2

                                      = 540 N

Answer:

Explanation:

If objects stick together, then a collision is inelastic. When objects don't stick together, If the kinetic energy is the same, then the collision is elastic.

Answer:

g ±Δg = (9.8 ± 0.2) m / s²

Explanation:

For the calculation of the acceleration of gravity they indicate the equation of the simple pendulum to use

          T = [tex]2\pi \sqrt{ \frac{L}{g} }[/tex]

          T² =  [tex]4\pi ^2 \frac{L}{g}[/tex]4pi2 L / g

          g = [tex]4\pi ^2 \frac{L}{T^2}[/tex]

They indicate the average time of 20 measurements 1,823 s, each with an oscillation

let's calculate the magnitude

           g = [tex]4\pi ^2 \frac{0.823}{1.823^2}[/tex]4 pi2 0.823 / 1.823 2

            g = 9.7766 m / s²

now let's look for the uncertainty of gravity, as it was obtained from an equation we can use the following error propagation

for the period

             T = t / n

             ΔT = [tex]\frac{dT}{dt}[/tex] Δt + [tex]\frac{dT}{dn}[/tex] ΔDn

In general, the number of oscillations is small, so we can assume that there are no errors, in this case the number of oscillations of n = 1, consequently

              ΔT = Δt / n

              ΔT = Δt

now let's look for the uncertainty of g

             Δg = [tex]\frac{dg}{dL}[/tex] ΔL + [tex]\frac{dg}{dT}[/tex]  ΔT

             Δg = [tex]4\pi ^2 \frac{1}{T2}[/tex]   ΔL + 4π²L  (-2  T⁻³) ΔT

a more manageable way is with the relative error

             [tex]\frac{\Delta g}{g} = \frac{\Delta L }{L} + \frac{1}{2} \frac{\Delta T}{T}[/tex]

we substitute

              Δg = g ( \frac{\Delta L }{L} + \frac{1}{2}  \frac{\Delta T}{T}DL / L + ½ Dt / T)

the error in time give us the stanndard deviation  

let's calculate

               Δg = 9.7766 ([tex]\frac{0.001}{0.823} + \frac{1}{2} \ \frac{0.671}{1.823}[/tex])

               Δg = 9.7766 (0.001215 + 0.0184)

               Δg = 0.19 m / s²

the absolute uncertainty must be true to a significant figure

                Δg = 0.2 m / s2

therefore the correct result is

               g ±Δg = (9.8 ± 0.2) m / s²

Answer:

R' = R/4

Explanation:

The resistance of a metal rod is R. It is given by the relation as follows :

[tex]R=\rho\dfrac{l}{A}[/tex]

Where

l is the length and A is the area of cross-section

[tex]A=\pi r^2=\pi (\dfrac{d}{2})^2[/tex]

If both its length and its diameter are quadrupled, it means,

l' = 4l

and d'= 4d

It means,

[tex]A'=\pi (\dfrac{4d}{2})^2[/tex]

Let new resistance be R'. So,

[tex]R'=\rho\dfrac{l'}{A'}\\\\R'=\rho\dfrac{4l}{\pi (\dfrac{4d}{2})^2}\\\\=\rho \dfrac{4l}{\pi \dfrac{16d^2}{2}}\\\\=\dfrac{4}{16}\times \dfrac{\rho l}{\pi \dfrac{d^2}{2}}\\\\=\dfrac{1}{4}\times \dfrac{\rho l}{\pi \dfrac{d^2}{2}}\\\\R'=\dfrac{R}{4}[/tex]

So, the correct option is (B) "R/4".

Answer:

i think rocks towards is correct answer

Answer:

It is gently on

Explanation:

I'm am not a 100 percent sure but try this o took that before

Answer:

Common Examples of Imagery

Taste: The familiar tang of his grandmother's cranberry sauce reminded him of his youth. Sound: The concert was so loud that her ears rang for days afterward. Sight: The sunset was the most gorgeous they'd ever seen; the clouds were edged with pink and gold.

I hope it's helpful!

Answer:

[tex]0.35598[/tex]

Explanation:

r = Radius = [tex]\dfrac{0.9}{2}=0.45\ \text{cm}[/tex]

R = Resistance = [tex]198\ \Omega[/tex]

A = Area = [tex]\pi r^2[/tex]

l = Length of blood in cylinder = 1 cm

h = Hematocrit of the blood

Resistivity is given by

[tex]\rho=\dfrac{1.32}{1-h}-0.79[/tex]

Resistance is given by

[tex]R=(\dfrac{1.32}{1-h}-0.79)\dfrac{l}{\pi r^2}\\\Rightarrow h=1-\dfrac{1.32}{\dfrac{R\pi r^2}{l}+0.79}\\\Rightarrow h=1-\dfrac{1.32}{\dfrac{198\times \pi\times (0.45\times 10^{-2})^2}{0.01}+0.79}\\\Rightarrow h=0.35598[/tex]

The hematocrit of the blood is [tex]0.35598[/tex].

Answer:

a

Explanation:

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Answer:

L = 5.08 10⁻¹ m = 50.8 cm

Explanation:

In a double slit experiment for constructive interference is given by

           d sin θ = m λ

let's use trigonometry to find a relationship with the distance

           tan θ = y / L

these experiments are very small angles

           tan θ = [tex]\frac{sin \ \theta}{cos \ \theta}[/tex] = sin θ

when substituting

           sin θ = y / L

substituting in the first equation

           d y / L = m λ

           L = [tex]\frac{d \ y}{m \ \lambda}[/tex]

let's calculate

           L = [tex]\frac{ 0.783 \ 10^{-6} \ 88.2 \ 10^{-2} }{2 \ 680 \ 10^{-9}}[/tex]

           L = 5.08 10⁻¹ m

The distance of viewing screen from the double slits will be L = 5.08 *10⁻¹ m = 50.8 cm

This position, where the resulting wave is larger than either of the two original, is called constructive interference.

In a double slit experiment for constructive interference is given by

d sin θ = m λ

let's use trigonometry to find a relationship with the distance

[tex]tan\theta=\dfrac {y}{L}[/tex]

these experiments are very small angles

tan θ =  = sin θ

when substituting

[tex]sin\theta = \dfrac{y}{l}[/tex]  

substituting in the first equation

[tex]\dfrac{dy}{L}=m\lambda[/tex]

[tex]L=\dfrac{dy}{L\lambda}[/tex]

let's calculate

[tex]L=\frac{0.783\times 10^{-6}\times 88.2\times 10^{-2}}{2.680\times 10^{-9}}[/tex]

L = 5.08 10⁻¹ m

Hence the distance of viewing screen from the double slits will be L = 5.08 10⁻¹ m = 50.8 cm

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Answer:

please put pic of the questions

Answer:

Hello your question is poorly written below is the complete question

Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?

answer :

a) 231.48 days

b) n = 3.125 * 10^15

Explanation:

Battery moved 10,000 coulombs

current rate = 0.5 mA

A) Determine how long the clock run on the battery. use the relation below

q = i * t ----- ( 1 )

q = charge , i = current , t = time

10000 = 0.5 * 10^-3 * t

hence  t = 2 * 10^7 secs

hence the time = 231.48  days

B) Determine how many electrons per second flowed

q = n*e ------ ( 2 )

n = number of electrons

e = 1.6 * 10^-19

q = 0.5 * 10^-3 coulomb ( charge flowing per electron )

back to equation 2

n ( number of electrons ) = q / e = ( 0.5 * 10^-3 ) / ( 1.6 * 10^-19 )

hence : n = 3.125 * 10^15

Answer:

density = mass/volume

so . . .  

density = (36 g)/(15 cm³) = 2.4 g/cm³

Explanation:

Answer:

Formula of kinetic energy:

[tex]k.e = \frac{1}{2} m {v}^{2} [/tex]

Explanation:

k.e: kinetic energy (J)

m: mass (kg)

v: velocity (m/s)

kinetic energy equals one half of the multiplication between mass and velocity

Answer:

16.6 m

Explanation:

Let d be the distance the other person is ahead of you. Since the other person is walking at a speed, v = 1.17 m/s, after picking the wallet, the other person moves a distance , vt in time, t = 10.5 s, the total distance covered by you till catch up is D = d + vt.

Also, you moves with a speed of v' = 2.75 m/s in time t = 10.5 s as you pick up the wallet, you covers a distance d' = v't at catch up.

At catch up, D = d'

d + vt = v't

d = v't - vt

d = (v' - v)t

Substituting the values of the variables into d, we have

d = (2.75 m/s - 1.17 m/s)10.5 s

d = (1.58 m/s)10.5 s

d = 16.59 m

d ≅ 16.6 m

So, the other person was 16.6 m ahead of you when you started running.

The Answer to your question is:

A.

The Earth's tectonic activity occurs by the movement of the fourteen main tectonic plates of the planet, which move over the mantle continuously, and result in the formation of mountains, earthquakes, tsunamis, volcanic activities, etc.

The decrease in the Earth's tectonic activity would therefore occur if the Earth's mantle became cooler, as the tectonic plates move over the magma, which is a paste formed by silicate of iron and magnesium and whose temperature reaches 600° and 1,200° Celsius , driven by forces from inside the planet.

Therefore the letter C is correct, as with the Earth's mantle cooler, the magma would become more solid which would decrease the Earth's tectonic activity.

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Answer:

The current is increasing at a rate of 0.32 ampere per second.

Explanation:

The voltage of the resistor is modelled after Ohm's Law, which states that voltage is directly proportional to current:

[tex]V = i\cdot R[/tex] (1)

Where:

[tex]V[/tex] - Voltage, measured in volts.

[tex]i[/tex] - Current, measured in amperes.

[tex]R[/tex] - Resistance, measured in ohms.

An expression for the rate of change in voltage is found by Differential Calculus:

[tex]\frac{dV}{dt} = \frac{di}{dt}\cdot R +i\cdot \frac{dR}{dt}[/tex]

[tex]\frac{dV}{dt} = \frac{di}{dt}\cdot R + \frac{V}{R}\cdot \frac{dR}{dt}[/tex] (2)

Where:

[tex]\frac{dV}{dt}[/tex] - Rate of change in voltage, measured in volts per second.

[tex]\frac{di}{dt}[/tex] - Rate of change in current, measured in amperes per second.

[tex]\frac{dR}{dt}[/tex] - Rate of change in resistance, measured in ohms per second.

If we know that [tex]\frac{dV}{dt} = 0\,\frac{V}{s}[/tex], [tex]R = 5\,\Omega[/tex], [tex]V = 40\,\Omega[/tex] and [tex]\frac{dR}{dt} = -0.2\,\frac{\Omega}{s}[/tex], then the rate of change in current is:

[tex]5\cdot \frac{di}{dt}-1.6 = 0[/tex] (3)

[tex]\frac{di}{dt} = 0.32\,\frac{A}{s}[/tex]

The current is increasing at a rate of 0.32 ampere per second.

Here is a copy+pasted definition...

Transactive memory is a psychological hypothesis first proposed by Daniel Wegner in 1985 as a response to earlier theories of "group mind" such as groupthink.[1] A transactive memory system is a mechanism through which groups collectively encode, store, and retrieve knowledge. Transactive memory was initially studied in couples and families where individuals had close relationships but was later extended to teams, larger groups, and organizations to explain how they develop a "group mind",[1] a memory system that is more complex and potentially more effective than that of any of its individual constituents. A transactive memory system includes memory stored in each individual, the interactions between memory within the individuals, as well as the processes that update this memory. Transactive memory, then, is the shared store of knowledge.

In simple terms...

A transactive memory is a psychological hypothesis. It is a system in the brain which allows human's to encode, store, or get information.

For example...

let's say I learn 5 colors when I'm younger. My "transactive memory" will store it and will allow my brain to "retrieve" the information to allow me to remember colors I previously "stored".

Please mark brainliest!

Answer:

a) True

Explanation:

There are several possible explanations for this positive charge

* The explanation of the small positive charge in the plant when the bee approaches is like a defense system of the plants,

to prevent the bees from taking the pollen, but the flowers need the bees to transport the pollen for fertilization, so this possibility is not correct

* The air is conductive so the bee indexes a charge in the nearby air, this charge must be negative and this charge induced in the air induces a charge on the flower that must be positive.

When reviewing the different statements we have

a) True, it agrees with the second explanation of the phenomenon

b) False. The earth is a deposit of negative charge

c) false. If this is the case the charge should be negative

d) False. This residual charge from the other bees is quickly neutralized by the charge from the Earth.

Answer:

Explanation:

.

Answer:

$ 5.93

Explanation:

If we are to put into consideration the following factors even though it was not all stated in the question.

What is the cost of heating a hot tub containing 1500 kg of water from 10.0°C to 40.0°C, assuming 75.0% efficiency to take heat loss to surroundings into account? The cost of electricity is ¢8.50/kW·h.

Q = mc∆T .........1

Where m is the mass of water = 1500kg

C is the specific heat capacity of water = 4.184

∆T = temperature change

= 40° - 10°

= 30°

Now, substitute the values into equation 1

= 1500×4.184×30

= 188280

Q in kw/s

= 188280/3600

= 52.3kw/hr

Efficiency = 75%

= 75/100

= 0.75

Hence we have

52.3/0.75

= 69.73kw/hr

C = Q × cost per kw/hr

C = 69.73× $8.5/100

C = 5.92705

C =$ 5.93

Hence, the cost of heating the hot tub is $ 5.93

Answer:

42,250

Explanation:

It goes inside=

Displacemt

It does work=

Work done

To find efficiency of jule we do=

Dicplacement × Work done

650 × 65

42,250

Please mark me as a brainlist

Answer:

26.57 degrees

Explanation:

Let the two vectors be a and b

The dot product of two vectors is expressed as;

a.b = |a||b|cosθ

The cross product is expressed as;

a×b = |a||b|sinθ

If the magnitude of the cross product of two vectors is one-half the dot product of the same vectors, then;

|a×b| = 1/2|a.b|

|a||b|sinθ = 1/2|a||b|cosθ

sinθ = 1/2cosθ

2sinθ = cosθ

sinθ/cosθ = 1/2

tanθ = 1/2

θ = arctan(1/2)

θ = 26.57 degrees

Hence  the angle between the two vectors is 26.57 degrees

Answer:

Explanation:

Yes , it is possible .

When a negative charge moves towards a positive charge , it is moving in the direction of increasing electrical potential . In the whole process , its electrical potential energy decreases and its kinetic energy increases .

Actually the potential energy of a negative charge near a positive charge is negative and it is inversely proportional to distance .

V = - Qq / R , When R decreases , the negative value of potential increases . That means potential energy decreases .

Answer:

Kim was adopted as a baby and raised by loving parents in an enriched environment. Studies have shown that the correlation between IQ

( intelligence quotient) scores of adopted children and those of their biologically unrelated family members reduce to zero as they grow into adulthood.

Explanation:

Kim was adopted as a baby and raised by loving parents in an enriched environment. Studies have shown that the correlation between IQ

( intelligence quotient) scores of adopted children and those of their biologically unrelated family members reduce to zero as they grow into adulthood.

Also, a loving environment is equally important for a child's upbringing.

Answer:

5.7375 seconds

Explanation:

The computation of the time required to reach that maximum velocity is shown below:

Given that

Mass = m =  5100 kg

Net upward force F = 8 × times 10^5 N

Initial speed = V_i = 0

Maximum speed = V = 900 m.s

Based on the above information

Impluse J = m(V - V_i)

= 5100 (900 - 0)

= 459 × 10^4 kg m.s

As we know that

J = FT

So

T = J ÷ F

= (459 × 10^4) ÷ (8 × 10^5)

= 5.7375 seconds

Answer:

The Big Bang theory predicts that the early universe was a very hot place and that as it expands, the gas within it cools. Thus the universe should be filled with radiation that is literally the remnant heat left over from the Big Bang, called the “cosmic microwave background", or CMB.

Explanation:

The Big Bang theory suggest  that the universe in early stage was at very hot place and which can be expanded, the gas within it cools. It is in an infinite universe and it has no edge.

The Big Bang theory is a cosmological model which explain the existence of the observable universe from the earliest periods to the large-scale evolution.

The model describes the mechanism behind the universe expansion from an initial state of high density and temperature, it is very important concept as a lot of research is going on in this field to find out exactly how the universe began billions of years ago.

The universe began to cool down in order to allow the formation of particles become atoms after its initial phase of expansion,  Primordial elements  such as Hydrogen, Helium, and Lithium are condensed through gravity are formed early stars and galaxies.

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Answer:

the kinetic energy is 120 J

Explanation:

a. The computation of the kinetic energy before it strikes the glove is as follows:

As we know that

The Kinetic energy is

=  1 ÷ 2 × m × v^2

= 1 ÷ 2 × (0.15)(40^2)

= 120 J

Hence, the kinetic energy is 120 J

This question is incomplete, the complete question is;

A monatomic gas fills the left end of the cylinder in the following figure. At 300 K , the gas cylinder length is 14.0 cm and the spring is compressed by65.0 cm . How much heat energy must be added to the gas to expand the cylinder length to 16.0 cm ?

Answer:

the required heat energy is 16 J

Explanation:

Given the data in the question;

Lets consider the ideal gas equation;

PV = nRT

from the image, we calculate initial pressure;

Pi = ( 2000N/M × 0.06m) / 0.0008 m²

Pi = 15 × 10⁴ Pa

next we find Initial velocity

Vi = (0.0008 m²)(0.14) = 1.1 × 10⁻⁴ m²

now we find the number of moles

n = [(15 × 10⁴ Pa)(1.1 × 10⁻⁴ m²)] / 8.31 J/molK × 300K

N = 6.6 × 10⁻³ mol

next we calculate the final temperature;

Pf = ( 2000N/m × 0.08) / 0.0008 m²

Pf = 2 × 10⁵ Pa

Calculate the final Volume

Vf = (0.0008 m² × 0.16 m = 1.28 × 10⁻⁴ m³

we also determine the final temperature

[tex]T_{f}[/tex] =  (2 × 10⁵ Pa × 1.28 × 10⁻⁴ m³) / 6.6 × 10⁻³ × 8.31 J/molK

[tex]T_{f}[/tex]  = 466.8 K

so change in temperature ΔT

ΔT =  466.8 K - 300K = 166.8 K

we then calculate the change in thermal energy

ΔU = nCΔT

ΔU = ( 6.6 × 10⁻³ mol ) × 12.5 × 166.8K

ΔU = 13.761 J

C is the isochoric molar specific heat which is equal to 3R/2 for monoatomic

now we calculate the work done;

W = 1/2 × K( x[tex]_{i\\}[/tex]² - x[tex]_{f\\}[/tex]² )

W = 1/2 × ( 2000 N/m) ( 0.06² - 0.08² )

= - 2.8 J

and we then calculate the heat energy using the following expression;

Q = ΔU - W

we substitute

Q = 13.761 - (- 2.8 J)

Q = 13.761 + 2.8 J)

Q =  16 J

Therefore, the required heat energy is 16 J