Answer:
700 N
Explanation:
The gravitational potential energy of the system decreases by 28,000 joules
The diver jumps from a height of 40 meters
Therefore the weight in Newton can be calculated as follows
= 28,000/40
= 700 newtons
It takes a minimum distance of 48.96 m to stop a car moving at 12.0 m/s by applying the brakes (without locking the wheels). Assume that the same frictional forces apply and find the minimum stopping distance when the car is moving at 25.0 m/s.
Answer:
102 m
Explanation:
Given that It takes a minimum distance of 48.96 m to stop a car moving at 12.0 m/s by applying the brakes (without locking the wheels). Assume that the same frictional forces apply and find the minimum stopping distance when the car is moving at 25.0 m/s.
Let the stopping distance be equal to S.
According to the definition of speed,
Speed = distance / time.
make time the subject of the formula
Time = distance / speed
then, the equivalent time is:
48.96 / 12 = S / 25
Cross multiply
12S = 48.96 x 25
12S = 1224
S = 1224 / 12
S = 102 m
Therefore, the stopping distance is 102 m
g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the tube has magnitude f. You attach the upper end of a lightweight vertical spring of force constant k to the cap at the top of the tube, and attach the lower end of the spring to the top of the cylinder. Initially the cylinder is at rest and the spring is relaxed. You then release the cylinder. What vertical distance will the cylinder descend before it comes momentarily to rest
Answer:
The vertical distance is [tex]d = \frac{2}{k} *[mg + f][/tex]
Explanation:
From the question we are told that
The mass of the cylinder is m
The kinetic frictional force is f
Generally from the work energy theorem
[tex]E = P + W_f[/tex]
Here E the the energy of the spring which is increasing and this is mathematically represented as
[tex]E = \frac{1}{2} * k * d^2[/tex]
Here k is the spring constant
P is the potential energy of the cylinder which is mathematically represented as
[tex]P = mgd[/tex]
And
[tex]W_f[/tex] is the workdone by friction which is mathematically represented as
[tex]W_f = f * d[/tex]
So
[tex] \frac{1}{2} * k * d^2 = mgd + f * d [/tex]
=> [tex] \frac{1}{2} * k * d^2 = d[mg + f ][/tex]
=> [tex] \frac{1}{2} * k * d = [mg + f ][/tex]
=> [tex]d = \frac{2}{k} *[mg + f][/tex]
A 6.13-g bullet is moving horizontally with a velocity of 361 m/s, where the sign indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1233 g, and its velocity is 0.741 m/s after the bullet passes through it. The mass of the second block is 1646 g. (a) What is the velocity of the second block after the bullet imbeds itself
Answer:
v₃ = 0.786 m/s
Explanation:
Here, we will use the law of conservation of momentum, which states the following:
Total Momentum of System Before Collision =
Total Momentum of System After Collision
m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃
where,
m₁ = mass of bullet = 6.13 g = 0.00613 kg
m₂ = mass of 1st block = 1233 g = 1.233 kg
m₃ = mass of 2nd block = 1646 g = 1.646 kg
u₁ = speed of first bullet before collision = 361 m/s
u₂ = speed of first block before collision = 0 m/s
u₃ = speed of 2nd block before collision = 0 m/s
v₁ = speed of bullet after collision
v₂ = speed of 1st block after collision = 0.741 m/s
v₃ = speed of 2nd block after collision = ?
Therefore,
(0.00613 kg)(361 m/s) + (1.233 kg)(0 m/s) + (1.646 kg)(0 m/s) = (0.00613 kg)(v₁) + (1.233 kg)(0.741 m/s) + (1.646 kg)(v₃)
2.2129 kg m/s + 0 kg m/s + 0 kg m/s - 0.9136 kg m/s = (0.00613 kg)(v₁) + (1.233 kg)(0.741 m/s) + (1.646 kg)(v₃)
1.2992 kg m/s = (0.00613 kg)(v₁) + (1.646 kg)(v₃)
since, the bullet is embedded in 2nd block after collision. Thus, there velocities will become same. (v₁ = v₃)
Therefore,
1.2992 kg m/s = (0.00613 kg)(v₃) + (1.646 kg)(v₃)
v₃ = (1.2992 kg m/s)/(1.6521 kg)
v₃ = 0.786 m/s
A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal component of the force is 4.5 N. At what angle (in degrees) above the horizontal is the force directed?
Answer:
Fy = 14.3 [N]
Explanation:
To be able to solve this problem we must know that the force is a vector and has magnitude and direction, therefore it can be decomposed into the force in the X & y components:
When we have the components on the horizontal and vertical axes we must use the Pythagorean theorem.
[tex]F = \sqrt{F_{x}^{2} +F_{y}^{2} }[/tex]
where:
F = 15 [N]
Fx = horizontal component = 4.5 [N]
Fy = vertical component [N]
[tex]15=\sqrt{4.5^{2}+F_{y}^{2}}\\ 15^{2}= (\sqrt{4.5^{2}+F_{y}^{2}})^{2} \\225 = 4.5^{2}+F_{y} ^{2}\\ F_{y}^{2} =225 -4.5^{2}\\ F_{y}^{2}=204.75\\F_{y}=\sqrt{204.75}\\ F_{y}=14.3 [N][/tex]
1. Name three branches of
science.
Answer:
Biology
Physics
Chemistry
Explanation:
Biology (life like cells, human reproduction, etc.)
Physics (Studies forces, like gravity.)
Chemistry (studies the atoms, the elements, etc.)
The flu _____.
is caused by bacteria
is noncommunicable
can be prevented by practicing good hygiene
was discovered by Edward Jenner during the 1700s
Answer:
b and d is wrong because if you sneezing and cough or other things like wiping your nose on your hand and touching things that other people touch can make people have the flu while you have it and edward jenner discovered cowpox and smallpox, not the flu
Explanation:
Please help with this science thank you
Answer:acbd
Explanation:
7. A 1,500-N force is applied to a 1,000-kg car. What is the car's acceleration?
Answer:
1.5m/s^2
Explanation:
Answer:
1.5 m/s2. accerelation =force ÷mass
The seasons of the year result from Earths movement, or____, around the sun.
Answer:
rotation
Explanation:
The seasons of the year result from Earths movement, or rotation around the sun. The answer for the blanks is rotation .
What is the earth's orbit?The Earth orbits the Sun in a counterclockwise pattern above the Northern Hemisphere at an average distance of 149.60 million km.
The Earth revolves around its axis once every 24 hours and orbits the sun once every 365 days. The Earth's rotation on its axis, not its orbit around the sun, causes day and night.
The term 'one day' refers to the time it takes the Earth to rotate once on its axis, which includes both day and night.
A season is a division of the year that is based on variations in weather, ecology, and the number of daylight hours in a certain place.
Seasons on Earth are caused by Earth's orbit around the Sun and its axial tilt relative to the ecliptic plane.
The seasons of the year result from Earths movement, or rotation around the sun.
Hence, the answer for the blanks is rotation .
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A system has the same velocity profile but a depth of 10 feet. The average velocity of the stream with a depth of 10 feet is __________ the stream with a depth of 6 feet.
a. Greater than
b. Less tharn
c. The same as
d. The answer cannot be determined with the given information.
Answer:
The average velocity of the stream with a depth of 10 feet is greater.
(a) is correct option.
Explanation:
Given that,
Depth [tex]h_{1}= 10\ feet[/tex]
Depth [tex]h_{2}=6\ feet[/tex]
We need to calculate the average velocity of the stream
According to question,
[tex]h_{1} > h_{2}[/tex]
The velocity for first case,
[tex]v_{1}=u_{1}\dfrac{x_{1}}{h_{1}}[/tex]
[tex]\dfrac{v_{1}}{x_{1}}=\dfrac{u_{1}}{h_{1}}[/tex]
The velocity for second case,
[tex]v_{2}=u_{2}\dfrac{x_{2}}{h_{2}}[/tex]
[tex]\dfrac{v_{2}}{x_{2}}=\dfrac{u_{2}}{h_{2}}[/tex]
For the same velocity profile,
[tex]\dfrac{dv}{dx}=\dfrac{v_{1}}{x_{1}}=\dfrac{v_{2}}{x_{2}}[/tex]
Then,
[tex]\dfrac{u_{1}}{h_{1}}=\dfrac{u_{2}}{h_{2}}[/tex]
Put the value into the formula
[tex]\dfrac{u_{1}}{10}=\dfrac{u_{2}}{6}[/tex]
[tex]u_{1}=\dfrac{5}{3}u_{2}[/tex]
[tex]u_{1}=1.67u_{2}[/tex]
The velocity is [tex]u_{1} > u_{2}[/tex]
We need to calculate the average velocity for first case
Using formula of average velocity
[tex]v_{avg}_{1}=\dfrac{0+u_{1}}{2}[/tex]
Put the value into the formula
[tex]v_{avg}_{1}=\dfrac{0+u_{1}}{2}[/tex]
[tex]v_{avg}_{1}=\dfrac{u_{1}}{2}[/tex]
We need to calculate the average velocity for second case
Using formula of average velocity
[tex]v_{avg}_{2}=\dfrac{0+u_{2}}{2}[/tex]
Put the value into the formula
[tex]v_{avg}_{2}=\dfrac{0+u_{2}}{2}[/tex]
[tex]v_{avg}_{2}=\dfrac{u_{2}}{2}[/tex]
If [tex]u_{1} > u_{2}[/tex] then [tex]\dfrac{u_{1}}{2} >\dfrac{u_{2}}{2}[/tex]
So, we can say that the average velocity of the stream with a depth of 10 feet will be greater than the stream with a depth of 6 feet.
Hence, The average velocity of the stream with a depth of 10 feet is greater.
(a) is correct option.
Hollywood and video games often depict the bad guys being "blown away" when they’re shot by a bullet (i.e. once hit, their feet leave the ground and they fly backwards). Assuming that even if a handgun cartridge did generate enough momentum for the bullet to do this, why is it still nonsense on-screen?
Answer:
Taking a look at Newton's third law of motion which states "for every force exerted, their is an opposite force equal in magnitude and opposite in direction on the first force".
Similarly if a bullet had enough forces behind it to hurl someone through the air when they were hit, a similar force would act on the person holding the gun that fired the bullet.
What we load into the gun is called a 'cartridge' Each piece is composed of four basic substance the casing, the bullet, the primer, and the powder.
The primer explodes lighting the powder which causes a buildup of pressure behind the bullet. This powder can be used in rifle cartages because the bullet chamber is designed to withstand greater pressures.
It is difficult in practice to measure the forces within a gun bagel, but the one easily measured parameter is the velocity with which the bullet exits muzzle velocity, therefore assuming that even if a handgun cartridge which generate enough momentum for the bullet to do this, it is still nonsense on screen in Hollywood and video.
a 12000.0-kg car is traveling at 19 m/s. the driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic friction between the tires and the road is 0.80. for what length of time is the car skidding?
) A 1000-gallon tank currently contains 100.0 gallons of liquid toluene and a gas saturated with toluene vapor at 85°F and 1 atm. (a) What quantity of toluene (lbm) will enter the atmosphere when the tank is filled and the gas displaced? (b) Suppose that 90% of the displaced toluene is to be recovered by compressing the displaced gas to a total pressure of 5 atm and then cooling it isobarically to a temperature T(°F). Calculate T.
Answer:
A) m[tex]_{T}[/tex] = 0.3025 * 0.0476 * 92.13 = 1.327 Ibm
B) T= 63.32°F
Explanation:
Given data:
1000 gallon tank currently contains 100.0 gallons of liquid toluene
and A gas saturated with toluene vapor at 85°F and 1 atm
A) Calculate quantity of toluene ( Ibm ) that will enter the atmosphere when the tank is filled
m[tex]_{T}[/tex] = [tex]n_{gas} * Y_{T} * M_{T}[/tex]
[tex]n_{gas}[/tex] (total mole of gas) = 0.3025 Ib-mole ( calculated using : [tex]\frac{PV}{RT}[/tex] )
[tex]Y_{T}[/tex] (mole fraction of toluene) = 0.0476 ( calculated using [tex]\frac{P_{T} }{P}[/tex] )
M[tex]_{T}[/tex] = 92.13 Ibm/Ib-mole
therefore: m[tex]_{T}[/tex] = 0.3025 * 0.0476 * 92.13 = 1.327 Ibm
B) using Antoine equation to solve for T
Antoine equation : [tex]log_{10} (P_{T} ) = A - \frac{B}{T+C}[/tex]
PT( partial pressure ) = 18.95 ( calculated using : [tex]y_{tb} * P[/tex] )
A = 6.95805
B = 1346.773
T = ?
C = 219.693
to calculate T make T the subject the subject of the equation
T + 219.693 = 1346.773 / 5.68044
∴ T = 17.40°C
convert T to Fahrenheit
T = 1.8 * 17.40 +32
= 63.32°F
A motor in a radio control car uses 7.2 volts and draws 14.4 Amps of electricity. What is the resistance of the motor?
Answer :
0.5 Ω
Explanation:
The following data were obtained from the question:
Voltage (V) = 7.2 V
Current (I) = 14.4 A
Resistance (R) =..?
The resistance of the motor can be obtained by applying the ohm's law equation as shown below:
V = IR
7.2 = 14.4 × R
Divide both side by 14.4
R = 7.2/14.4
R = 0.5 Ω
Therefore, the resistance is 0.5 Ω
Answer:
Answer :
0.5 Ω
Explanation:
The following data were obtained from the question:
Voltage (V) = 7.2 V
Current (I) = 14.4 A
Resistance (R) =..?
The resistance of the motor can be obtained by applying the ohm's law equation as shown below:
V = IR
7.2 = 14.4 × R
Divide both side by 14.4
R = 7.2/14.4
R = 0.5 Ω
Therefore, the resistance is 0.5 Ω
50 pounds is equal to 22,700 grams. How many pounds does this backpack full of gold weigh? Would you be able to carry out that backpack filled with gold?
The question is incomplete. Here is the complete question.
7) A standard backpack is approximately 30cm x 30cm x 40cm. Suppose you find a hoard of pure gold (density = 19.3 g/cm³) while treasure hunting in the wilderness. How much mass would your backpack hold if you filled it with gold?
8) 50 pounds is equal to 22,700 grams. How many pounds does this backpack full of gold weigh? Would you be able to carry out that backpack filled with gold?
Answer: 7) m = 694,800g
8) It wieghts 1530.4 lbf
Explanation:
7) Volume of the backpack will be
V = 30 x 30 x 40
V = 36000 cm³
According to density of gold, each cm³ corresponds to 19.3g, then:
m = 19.3[tex]\frac{g}{cm^{3}}[/tex] * 36000cm³
m = 694800g
If I filled it with gold, the backpack will hold 694800g or 694.8kg.
8) 50 pounds is equal to 22700g. Then:
50 pound = 22700g
W = 694800g
W = [tex]\frac{694800.50}{22700}[/tex]
W = 1530.4 lbf
The backpack, in pounds, will weigh 1530.4lbf, which is very heavy to be supported by a human body.
my heart strike him to dead.what figure of speech is that?
Answer:
Hyperbole
Explanation:
this is an extreme exaggeration or overstatement/ magnification
An alligator crawls 25\,\text m25m25, start text, m, end text to the left with an average velocity of -1.2\,\dfrac{\text m}{\text s}−1.2
s
m
minus, 1, point, 2, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.
Answer:
21 s.
I hope this helps!
Answer:21s
Explanation:
Cells make proteins on small structures called vesicles.
True
False
The statement about making of protein on small structure by cell is True.
Vesicles can be regarded as small, fluid-filled sacs which its appearance can be seen on our skin. Transport vesicles is the vesicle that helps in transportation of materials from one part of the cell to other. this material could be proteins as well as other molecules.When protein is been made by a cell , then the transporter vesicles will then be responsible for the movement of this proteins to the Golgi apparatus, where actions like sorting and refining will be performed.With the help of vesicle pressure in the cell can be regulatedThe fluid that is contained inside these sacs is usually clear, and sometimes it could be white or yellow with blood.The diameter of a Vesicles are about 5 to 10 millimeters.Therefore, vesicles helps in movement of molecules.
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A 0.75 m3 rigid tank initially contains air whose density is 1.18 kg/m3. The tank is connected to a high-pressure supply link through a valve. The valve is opened, and air is allowed to enter the tank until the density in the tank rises to 4.95 kg/m3. Determine, in kg, the mass of air that has entered the tank..
Answer:
2.83kg
Explanation:
Answer:
2.83kg
Explanation:
Given
initial density = 1.18 kg/m3
Final density in the tank = 4.95 kg/m3.
Let us write the mass balance first.
Change in the mass of the system=mass of the air entering the system - Mass of air out the system
Mass that entered= M2 - M1
But DENSITY= MASS/ VOLUME
Mass= volume × Density
We can expressed the mass in terms of density since density is given in the question.
Mass that entered= (volume × density)2 - ( volume × density)1
= (V ρ)2 - (V ρ)1
But V1= V2 the volume remains the same
= ( ρ2 - ρ1)v
= (4.95 kg/m3 - 1.18 kg/m3) 0.75 m3
= 3.77× 0.75
= 2.8275kg
Mass that entered= 2.83kg
therefore, mass of air that has entered the tank= 2.83kg
The word acid comes from the Latin word
A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.
A) What is the magnitude of the particle's acceleration produced by a uniform magnetic field B = (1.63T)i^+(0.980T)j^?
B) What is the direction of the particles acceleration? Please show steps so I can follow.
Answer:
a = -0.33 m/s² k^
Direction: negative
Explanation:
From Newton's law of motion, we know that;
F = ma
Now, from magnetic fields, we know that;. F = qVB
Thus;
ma = qVB
Where;
m is mass
a is acceleration
q is charge
V is velocity
B is magnetic field
We are given;
m = 1.81 × 10^(−3) kg
q = 1.22 × 10 ^(−8) C
V = (3.00 × 10⁴ m/s) ȷ^.
B = (1.63T) ı^ + (0.980T) ȷ^
Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;
a = qVB/m
a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))
From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^
Thus;
a = -0.33 m/s² k^
When adding the components of a vector, the resultant magnitude is always the sum of the two component magnitudes.
True or false?
Answer:False
Explanation:
Answer:
False
Explanation:
Find the work done by a 75.0 kg person in climbing a 2.50 m flight of stairs at a constant speed.
Answer:
1,839.375 Joules
Explanation:
Work is said to be done is the force applied to an object cause the object to move through a distance.
Workdone = Force * Distance
Workdone = mass * acceleration due to gravity * distance
Given
Mass = 75.0kg
acceleration due to gravity = 9.81m/s²
distance = 2.50m
Substitute the given parameters into the formula:
Workdone = 75.0*9.81*2.50
Workdone = 1,839.375Joules
Hence the workdone is 1,839.375 Joules
Blood is 92% water. Blood is
drawn using a capillary tube.
Write 1 sentence explaining how it
illustrates this characteristic of
water. Use the terms adhesion
and capillary action.
Answer:
Plasma, which constitutes 55% of blood fluid, is mostly water (92% by volume), and contains proteins, glucose, mineral ions, hormones, carbon dioxide (plasma being the main medium for excretory product transportation), and blood cells themselves.
Explanation:
Capillary motion is crucial for circulating water. Your body's cells would not hydrate without this flow, and crucial communication between your brain and body would slack off, hence blood contains water 92% water helps in capillary action.
What is Capillary action?Capillary action, also known as capillary effect or motion, is the process by which liquid moves through constricted areas without the aid of external forces like gravity but rather with the help of intermolecular forces that exist between the liquid and solid surface (s).
Adhesion: The attraction of two different molecules, such as the hydrogen and oxygen molecules found in water and plastic drinking straws.
Proteins, glucose, mineral ions, hormones, carbon dioxide (plasma is the principal medium for excretory product transfer), and blood cells themselves are contained in plasma, which makes up 55% of blood fluid. Plasma is mostly water (92% by volume) and contains water as well as several other substances.
Therefore, the water contains in the blood helps in capillary action.
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calculate sound intensity
Answer:
I dont know sorry,I hope you find what are you looking for.
Help solve these two problems im having trouble trying to start these problems?
Answer:
25. Approximately 8.1 meters
26. North 1.31 km, and East 2.81 km
Explanation:
25.
Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:
[tex]d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m[/tex]
which can be rounded to 8.1 m.
26.
Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.
We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):
[tex]east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km[/tex]
and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.
[tex]north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km[/tex]
A battery is used to charge a parallel-plate capacitor, after which it is disconnected. Then the plates are pulled apart to twice their original separation. This process will double the: __________A. capacitance
B. surface charge density on each plate
C. stored energy
D. electricfield between the two places
E. charge on each plate"
Answer: C.
Explanation:
For a parallel-plate capacitor where the distance between the plates is d.
The capacitance is:
C = e*A/d
You can see that the distance is in the denominator, then if we double the distance, the capacitance halves.
Now, the stored energy can be written as:
E = (1/2)*Q^2/C
Now you can see that in this case, the capacitance is in the denominator, then we can rewrite this as:
E = (1/2)*Q^2*d/(e*A)
e is a constant, A is the area of the plates, that is also constant, and Q is the charge, that can not change because the capacitor is disconnected.
Then we can define:
K = (1/2)*Q^2/(e*A)
And now we can write the energy as:
E = K*d
Then the energy is proportional to the distance between the plates, this means that if we double the distance, we also double the energy.
If the plates are pulled apart to twice their original separation, then this will double the stored energy. Hence, option (C) is correct.
The given problem is based on the concept of parallel plat capacitor. For a parallel-plate capacitor where the distance between the plates is d.
The capacitance is:
C = e*A/d
here.
e is the permittivity of free space.
Since, the distance is inversely proportional then if we double the distance, the capacitance halves. Now, the stored energy can be given as,
E = (1/2)*Q^2/C
here,
Q is the charge stored in the capacitor.
Now you can see that in this case, the capacitance is in the denominator, then we can rewrite this as:
E = (1/2)*Q^2*d/(e*A)
e is a constant, A is the area of the plates, that is also constant, and Q is the charge, that can not change because the capacitor is disconnected.
Then we can define:
K = (1/2)*Q^2/(e*A)
And now we can write the energy as:
E = K*d
So, the energy is proportional to the distance between the plates.
Thus, we can conclude that if the plates are pulled apart to twice their original separation, then this will double the stored energy. Hence, option (C) is correct.
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A loop of area 0.250 m^2 is in a uniform 0.020 0-T magnetic field. If the flux through the loop is 3.83 × 10-3T· m2, what angle does the normal to the plane of the loop make with the direction of the magnetic field?
Answer:
40.0⁰
Explanation:
The formula for calculating the magnetic flux is expressed as:
[tex]\phi = BAcos\theta[/tex] where:
[tex]\phi[/tex] is the magnetic flux
B is the magnetic field
A is the cross sectional area
[tex]\theta[/tex] is the angle that the normal to the plane of the loop make with the direction of the magnetic field.
Given
A = 0.250m²
B = 0.020T
[tex]\phi[/tex] = 3.83 × 10⁻³T· m²
3.83 × 10⁻³ = 0.020*0.250cosθ
3.83 × 10⁻³ = 0.005cosθ
cosθ = 0.00383/0.005
cosθ = 0.766
θ = cos⁻¹0.766
θ = 40.0⁰
Hence the angle normal to the plane of the loop make with the direction of the magnetic field is 40.0⁰
King crimson vs DIO? for science of course. and for an essay
Answer:
king crimson
Explanation:
bc
Explanation:
It could go either way.
King crimsons ability is to see into the future and erase something, changing the outcome, while The Worlds ability is to Stop time. I believe DIO would beat Diavolo,but thats if certain requirements are met.Like, the fight being at night, but if Diavolo got a good combo of attacks on DIO, theres a high chance he would kill DIO, but DIO could end the fight in seconds by stopping time and killing him in his Stopped time, or his World, hope this helped
One way to increase friction is to use (A.wax,B.sand,C.water ,D.oil
Answer:
using sand
Explanation:
We can increase friction by making rough surface.
