Mathematics College

Can you help me please here is the image

Answers

Answer 1

Answer: D all of the above

Step-by-step explanation:

A. you can see that the majoritie of the area is dessort becuase of the long expance of lack of vegitation and water

B. Because there is no other water sourses the cities would have to be along water

C. Along the nile river is vegitation

D. Must be D.

Related Questions

Find the volume of the composite figure. First, find the volume of the triangular prism. Triangular prism Volume = [?] ft 8 ft Rectangular prism Volume = [ ] ft 10 ft Total Volume of Composite Figure = [ ] ft 14 ft 10 ft

Answers

Answer:

1440ft^3

Step-by-step explanation:

Answer:

120

Step-by-step explanation:

i already did it

How much would you need to deposit in an account now in order to have $2000 in the account in 15
years? Assume the account earns 2% interest compounded monthly.

Answers

4000 mcmcnxmamnxmxmnxnxns

For the function f(x)=ax^3+bx^2-5x+9, determine the values of a and b so that f(-1)=12 and f'(-1)=3

Answers

f(x) = ax ³ + bx ² - 5x + 9

then

f '(x) = 3ax ² + 2bx - 5

Given that f (-1) = 12 and f '(-1) = 3, we get the system of equations

-a + b + 5 + 9 = 12

3a - 2b - 5 = 3

-a + b = -2

3a - 2b = 8

Multiply through the first equation by 2 and add it to the second one to eliminate b and solve for a :

2(-a + b) + (3a - 2b) = 2(-2) + 8

-2a + 2b + 3a - 2b = -4 + 8

a = 4

Substitute this into the first equation above to solve for b :

-4 + b = -2

b = 2

Answer is a = 4, b = 2.

First derivative of an equation:

The derivative formula is one of the basic concepts used in calculus and the process of finding a derivative is known as differentiation. The derivative formula is defined for a variable 'x' having an exponent 'n'. The exponent 'n' can be an integer or a rational fraction. Hence, the formula to calculate the derivative is:

[tex]\frac{d}{dx} x^{n} = n x^{n-1}[/tex]

(Given)

[tex]f(x) = ax^{3} + bx^{2} - 5x + 9[/tex]

And f'(x) we get , [tex]f'(x) = 3ax^{2} + 2bx-5[/tex]

Now, also given f(-1) = 12

=> [tex]f(-1) =a (-1)^{3} + b(-1)^{2} - 5 (-1) + 9[/tex]

=> 12 = -a + b +5 + 9

=> a = b + 2 ------( 1 )

Also given, f'(-1) = 3.

i.e., [tex]3 = 3a(-1)^{2} + 2b(-1) - 5[/tex]

3 = 3a -2b -5

From eq - (1) we can replace a.

3 = 3(b + 2) - 2b - 5

3 = 3b + 6 - 2b - 5

b = 2.

a = 4.

Learn more about derivative of equation here:

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