Can you help me image is here which 2 Should I drag

Answer:

x = 3

y = 2

Step-by-step explanation:

Diagonals of a parallelogram bisect each other into two equal segments. Therefore:

3x - 1 = 2(x + 1)

Solve for x

3x - 1 = 2x + 2

Collect like terms

3x - 2x = 1 + 2

x = 3

Also:

5y + 1 = 6y - 1

Collect like terms

5y - 6y = -1 - 1

-y = -2

Divide both sides by -1

y = -2/-1

y = 2

Answer:

B

x + y = 712

8x + 4y = 4,256

Step-by-step explanation:

If x=the amount of adult tickets, and y=the amount of children's tickets, then the total amount of tickets (712) should be x+y. Our first equation: x+y=712

The total made from adult tickets is found by multiplying the amount of tickets by the price per ticket: 8x. The total made from children's tickets is found by multiplying the amount of tickets by the price per ticket: 4y.The total amount of money made (4256) is the sum of the amount made by adult tickets (8x) and the amount made by children's tickets (4y). Our second equation: 8x+4y=4256

Answer:

The equation i came up with is $55= 7.8x - 47.20

Answer:

Step-by-step explanation:

perimeter = 4(10x) = 40x units

if x = 12, perimeter = 480x units

5 ÷ 20 = 4

Answer:

0, 1 and 1

Step-by-step explanation:

Given the expressions;

x^3-2x^2+x = 0

x(x^2-2x+1) = 0

x = 0 and x^2-2x+1 = 0

Factorize x^2-2x+1 = 0

x^2-x-x+1 = 0

x(x-1)-1(x-1) = 0

(x-1)(x-1)= 0

x = 1 twice

hence the zeros of the equation are 0, 1 and 1

Answer:

it is 222

Step-by-step explanation:

1440 divided by 20 :)

Answer:

910$

Step-by-step explanation:

Answer:

$910

Step-by-step explanation:

Do $1,300 times .3 and you will get $390.

$390 is the amount of money being taken off.

now do $1,300 - $390 = $910 Final Price

Answer:

The correct answers are:

xii) (x+7)(x+7)

=x^2 +7x +7x +49

=x^2 +14x +49

xiv) (x+4)(x+2)

=x^2 +2x +4x +8

=x^2 +6x +8

xvi) 5x^3 ÷ 5x^3

=1

Answer:

This is your answer ☺️☺️

Answer:

I. Ella packed 70 books more than Ray.

II. Ray packed 580 books.

III. Ella packed 650 books.

Step-by-step explanation:

Given the following data;

Ray = 29 boxes of 20 books

Ella = 26 boxes with 25 books

To find the total number of books packed by Ray;

Total for Ray (Ray packed) = 29 * 20

Total for Ray = 580 books.

To find the total number of books packed by Ella;

Total for Ella (Ella packed) = 26 * 25

Total for Ella = 650 books.

Next, we find the difference between the books packed by Ella and Ray;

Difference = Ella - Ray

Difference = 650 - 580

Difference = 70 books

Multiply the total number of houses built by the fraction sold:

120 x 2/3 = (120 x 2)/3 = 240/3 = 80

80 houses were sold.

Answer:

I think it would be the first choice however I may be wrong

Step-by-step explanation:

Answer:

63c^5

Step-by-step explanation:

Answer:

it is b              furqufhrfhquh quf hqhf

Step-by-step explanation:bfygefy eyfeyfyewfyefwef eqf  

\fn qf7f

The value of the matrix X is X =  [tex]\left[\begin{array}{ccc}-7&-2\\7&0\\\end{array}\right][/tex].

Matrices are a set of numbers arranged in such a way that the numbers are arranged in rows and columns.

Each number is called element in a matrix.

Given are two matrices.

A = [tex]\left[\begin{array}{ccc}2&-7\\6&1\\\end{array}\right][/tex] and B = [tex]\left[\begin{array}{ccc}-9&5\\1&-1\\\end{array}\right][/tex]

We have given that, a matrix X exists such that,

X - A = B

We can rearrange this as,

X = A + B

Adding the two matrices,

The entries will be,

2 - 9 = -7

-7 + 5 = -2

6 + 1 = 7

1 - 1 = 0

X =  [tex]\left[\begin{array}{ccc}-7&-2\\7&0\\\end{array}\right][/tex]

Hence the X is option A.

Learn more about Matrices here :

https://brainly.com/question/30646566

#SPJ7

Answer:

wow that's a lot lol

Step-by-step explanation:

i needthe points i'm ssrry

Answer:

√130 or ≈ 11.40175425

Step-by-step explanation:

(-6, 0) & (5, 3)

To find the distance between these two points, we want to use the distance formula: d = √[(x₂ - x₁)² + (y₂ - y₁)²]

Plug in the given values.

d = √[(5 - (-6))² + (3 - 0)²]

Simplify the parentheses.

d = √[(5 + 6)² + (3 - 0)²]

d = √[(11)² + (3)²]

Evaluate the exponents.

d = √[(121) + (9)]

Add the expression within the brackets [ ].

d = √[130]

This is your answer.

√130

or

≈ 11.40175425

Hope this helps!

Answer:

A and C

Step-by-step explanation:

20) Since the triangles are similar, you can say that 98 corresponds to 42 and 77 corresponds to 3x+6, because of this you can write an equation ((98/77)(3x-6) =42) and then simplify to get x = 13.

21) Since ABC and DFE are similar, we can say that 2x+2 corresponds to x+3 and 24 corresponds to 16. You can write this as the equation (24/2x+2)(x+3) = 16 and simplify to get x=5.

I hope this helps :)

9514 1404 393

Answer:

  B  (2 violet)

Step-by-step explanation:

Let the colors be represented by their first letter. Then the balances give rise to two equation:

  o +y +b +v = r +g +b

  o +y +v = g +v

Subtracting the second equation from the first gives ...

  (o +y +b +v) -(o +y +v) = (r +g +b) -(g +v)

  b = r +b -v

Adding v-b to both sides, we have ...

  b +(v -b) = r +b -v +(v -b)

  v = r

Multiplying this result by 2, we can match the final balance:

  2r = 2v . . . . . . . choice B

Answer:

the answer is B.2 purple

Answer:

x > -20

Step-by-step explanation:

-x < 20

When dividing by negative numbers, flip the inequality.

x > -20

inclusive -> open circle

greater than -> to the right

open circle at -20 going to the right

Answer:

The mean number of packages that will be filled before the process is stopped is 50.

Step-by-step explanation:

For each package, there are only two possible outcomes. Either it fails outside the specifications, or it does not. Packages are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Number of trials expected for n sucesses

Also called inverse binomial distribution, is given by:

[tex]E = \frac{n}{p}[/tex]

In which p is the probability of a success in a trial.

Assume that each package has probability 0.02 of falling outside the specification and that the weights of the packages are independent.

This means that [tex]p = 0.02[/tex]

Find the mean number of packages that will be filled before the process is stopped.

This is when [tex]n = 1[/tex], as the process is stopped when a package is outside the specifications. So

[tex]E = \frac{n}{p} = \frac{1}{0.02} = 50[/tex]

The mean number of packages that will be filled before the process is stopped is 50.

Answer:

If the difference of x and 22=8

then equation is

X -22=8

X=22+8

X=30

therefore now we put the value of x in the equation

30-22=8

8=8

Answer:

x would be 30

Step-by-step explanation:

x-22=8

x=8+22

x=30

Answer:

<5=112° corresponding angle

may be 28 am i write sir or mam

Answer:

The number is -5

Step-by-step explanation:

Equation: 8(7+x) = 16

Distribute: 56 + 8x = 16

Subtract 56 from both sides: 8x = -40

Divide both sides by 8: x = -5

Answer:

[tex]L_{1}[/tex] ⊥ [tex]L_{2}[/tex] ; [tex]L_{3}[/tex] ⊥ [tex]L_{2}[/tex] ; [tex]L_{1}[/tex] ║ [tex]L_{3}[/tex]

Step-by-step explanation:

( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )

( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )

m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

y = mx + b

"m" is slope

"b" is y-intercept (coordinates are (0, b)

Parallel lines have the same slopes and different y-intercepts.

Slopes of perpendicular lines are opposite reciprocals: [tex]m_{1}[/tex] × [tex]m_{2}[/tex] = - 1

~~~~~~~~~~~~~~~~~~~~~~

[tex]L_{1}[/tex] :  y = x + 5 , [tex]m_{L_{1} }[/tex] = 1 , b = 5

[tex]L_{2}[/tex] : y = - x + 7 , [tex]m_{L_{2} }[/tex] = - 1 , b = 7

[tex]L_{1}[/tex] ⊥ [tex]L_{2}[/tex]

[tex]L_{3}[/tex] : [tex]m_{L_{3} }[/tex] = 1 , b = - 2

[tex]L_{1}[/tex] ║ [tex]L_{3}[/tex] and [tex]L_{2}[/tex] ⊥ [tex]L_{3}[/tex]