Can someone help me find if the function is increasing or decreasing and why the c intercept is (look at the photo)

The bottom end of the pendulum travels 18,115.2 meters/day, which is approximately 18.12 kilometers/day (since 1 kilometer = 1000 meters).

The motion of the pendulum is a simple harmonic motion and the period of oscillation can be calculated as follows:

T = 2π√(l/g)

where l is the length of the pendulum and g is the acceleration due to gravity (approx. 9.81 m/s²).

Substituting l = 1 m, we get

T = 2π√(1/9.81)

T ≈ 2.006 s.

In one day, there are

24 hours x 60 minutes/hour x 60 seconds/minute

= 86,400 seconds.

The pendulum makes half a period (i.e., one back-and-forth swing) in 2/2 = 1 second. Therefore, it makes

86,400/2

= 43,200 back-and-forth swings in one day.

The distance traveled by the bottom end of the pendulum in one complete swing is equal to the length of the pendulum times twice the maximum angle it makes with the vertical, which is

2 x 12 degrees

= 24 degrees

= 0.419 radians.

Therefore, the distance traveled by the bottom end of the pendulum in one complete swing is

1 meter x 0.419

= 0.419 meters.

Multiplying by the number of swings in one day, we get:

0.419 meters/swing x 43,200 swings/day

= 18,115.2 meters/day.

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In 12 days, both Eve and Jenna will work out on the same day again.

To find the number of days until Eve and Jenna work out on the same day again, we need to find the least common multiple (LCM) of 6 and 4.

One way to find the LCM is to list the multiples of each number until we find a multiple that they have in common:

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, ...

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, ...

From this list, we see that the least common multiple of 6 and 4 is 12.

This means that in 12 days, both Eve and Jenna will work out on the same day again.

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There are 29 degrees of freedom for this repeated-measures t-test.

The degrees of freedom (df) for a repeated-measures t-test is calculated as (n-1), where n is the number of paired observations.

In this case, each hamster's activity was measured during both summer and winter, resulting in a paired sample design. Therefore, the number of paired observations is equal to the number of hamsters, which is n = 30.

Hence, the degrees of freedom for this repeated-measures t-test is:

df = n - 1 = 30 - 1 = 29

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Out of 60 bikes in the repair department, 25 need two repairs and the range of bikes that need both tire and handlebar repairs without needing to fix the seat is 25 out of 60 bikes.

Let's use F, H, and S to represent the events that a bike has a flat tire, bent handlebars, and ripped seat, respectively. Then, we are given:

P(F) = 0.25

P(H) = 0.05

P(S) = 0.10

P(F ∩ H ∩ S) = 1/12

We want to find the number of bikes in the repair department and the number of bikes that need two repairs.

Let N be the total number of bikes in the repair department. Then, the number of repairs needed for each category is:

Flat tires: 0.25N

Bent handlebars: 0.05N

Ripped seats: 0.10N

The number of bikes that need all three repairs is:

P(F ∩ H ∩ S)N = (1/12)N

The number of repairs needed for these bikes is:

3P(F ∩ H ∩ S)N = (1/4)N

The number of repairs needed for bikes that need only two repairs is:

2[P(F ∩ H) + P(F ∩ S) + P(H ∩ S)]N = (5/12)N

The number of repairs needed for bikes that need only one repair is:

[P(F) + P(H) + P(S)]N = 0.4N

The total number of repairs needed is given as 101, so we have:

(1/4)N + (5/12)N + 0.4N = 101

Simplifying this equation gives:

N = 60

Therefore, there are 60 bikes in the repair department.

The number of bikes that need two repairs is:

(5/12)N = 25

Next, we need to find the range of bikes that need both the tires and handlebars repaired without needing to fix the seat. Let's use T and H to represent the events that a bike needs tire and handlebar repairs, respectively. We want to find P(T ∩ H ∩ not S).

We know that P(T ∩ H ∩ S) = P(F ∩ H ∩ S) = 1/12. Also, P(S) = 0.10, so P(not S) = 0.90. Therefore:

P(T ∩ H ∩ not S) = P(T ∩ H) - P(T ∩ H ∩ S)

= 2[P(F ∩ H) + P(F ∩ H ∩ S) + P(H ∩ S)] - P(F ∩ H ∩ S)

= 2(5/12) - 1/12

= 5/12

So, less than half of all the bikes have a ripped seat, and the range of bikes that need both the tires and handlebars repaired without needing to fix the seat is 5/12 of all the bikes, or 25 out of 60 bikes.

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The solutions of the inequalities are shown below

x [tex]\geq[/tex] 5

x< 13

x[tex]\geq[/tex]1

x> 1

Solving inequalities involves finding all possible values of a variable that make the inequality true. The process for solving an inequality depends on the type of inequality and the operations involved.

[tex]6^x + 4 \leq 6^{2x - 1} \\x + 4 \leq 2x - 1\\x - 2x\leq -1 - 4\\-x \leq -5\\x \geq 5[/tex]

[tex]2^{x + 3} > 4x^{x - 5} \\2^{x + 3} > 2^{2x - 10}\\x + 3 > 2x - 10\\x - 2x > - 10 - 3\\-x > - 13\\x < 13[/tex]

[tex]9^x \leq 9^{2x - 1}\\ x \leq 2x - 1\\x - 2x \leq -1\\-x \leq -1\\x \geq 1[/tex]

[tex]5^4 > 25^{2x} \\5^4 > 5^{4x} \\4 > 4x\\x > 1[/tex]

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a) over the interval of 0 - 10 hours, the average rate of change of the temperature is 17,088°C/hr.

b) the average temperature of the water in the system is 1527.

c) over the interval of 10 - 20 hours, the total change in the temperature of the water in the solar steam power system is -14,351°C.

a) g'(x) = 2 + [tex]\int\limits^x_0[/tex] ƒ'(t) dt

g'(-3) = -2

b) The absolute maximum value of g on the closed interval [-5, 5]=

10 + 2√7.

c) The x-coordinates of the points of inflection of the graph of g are -1, 0 and 2.

What is right Riemann sum formula?

The right Riemann sum formula uses the right-most value of each interval as the value of the function over that interval.

a) g(5) = 2(5) + [tex]\int\limits^5_0[/tex] ƒ(t) dt

= 10 + 2√7

g'(x) = 2 + [tex]\int\limits^x_0[/tex] ƒ'(t) dt

g'(-3) = 2 + [tex]\int\limits^3_0[/tex]ƒ'(t) dt

= 2 - (4 + 0)

= -2

b) The absolute maximum value of g on the closed interval [-5, 5]=

10 + 2√7.

This is because the highest value of ƒ(t) dt on the interval= 4√7, which occurs at x = 2.

The highest value of g is thus given by 10 + 2√7.

c) The x-coordinates of the points of inflection of the graph of g are -1, 0 and 2.

This is because ƒ'(t) dt is undefined at these points, so the second derivative of g is also undefined.

a) To evaluate the  S'(t) dt, we need to calculate the area under the curve of the temperature data given in the table. To do this, we use the trapezoidal rule. This gives us the following:

[tex]\int\limits^10_0[/tex] S'(t) dt = [(142 + 210 + 254 + 280 + 274 + 268)/2] × 8

= 17,088

This means that over the interval of 0 - 10 hours, the average rate of change of the temperature is 17,088°C/hr.

This can be interpreted in the context of the problem as the average rate at which the temperature of the water in the solar steam power system is changing over the given time interval.

b) To approximate the average temperature of the water in the system using a right Riemann approximation, we need to calculate the area under the curve of the temperature data given in the table. We can do this using the right Riemann sum formula, which gives us the following:

Right Riemann Approximation = [(210 + 254 + 280 + 274)/4] × 6 = 1527

In this case, the right-most value of each interval is lower than the true average over that interval, so the approximation will be lower than the true average.

c) To determine the total change in the temperature of the system for the interval 10≤t≤20, we need to calculate the area under the curve of the equation S'(t)=-√2xe (√x²-100)/x.

This can be done using the definite integral of the equation, which gives us the following:

Total Change = ∫1020-√2xe (√x²-100)/x dx

= -14,351

This means that over the interval of 10 - 20 hours, the total change in the temperature of the water in the solar steam power system is -14,351°C.

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The calculated value of the probability that the experiment results in exactly 1 success is 0.08719

From the question, we have the following parameters that can be used in our computation:

n = 7

x = 1

p = 0.45

The probability is then calculated as

P(x = x) = nCr * p^x * (1 - p)^(n - x)

Substitute the known values in the above equation, so, we have the following representation

P(x = 1) = 7C1 * (0.45)^1 * (1 - 0.45)^(7-1)

Evaluate the expression

So, we have

P(x = 1) = 0.08719

Hence, the probability is 0.08719

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The formula for the partial sum of a geometric sequence with first term a₁, common ratio r, and n terms is given by:

Sₙ = a₁(1 - rⁿ)/(1 - r)

A geometric sequence is a non-zero numerical sequence in which each term after the first is found by multiplying the preceding one by a fixed, non-zero quantity known as the common ratio.

In the formula, Sₙ is the sum of the first n terms of the sequence.

Alternatively, the formula can be expressed as:

Sₙ = (a₁(rⁿ - 1))/(r - 1)

Both of these formulas give the same result and can be used to calculate the partial sum of a geometric sequence.

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The expression can be simplified to get:

2.7^(1)*3.8^(5)

The correct option is C.

Remember that if we have the product of two powers with the same base, we only need to add the exponents.

Then we will get:

2.7^(-3) * 3.8^(2) * 2.7^(4) * 3.8^(3)

= (2.7^(-3)*2.7^(4)*3.8^(2)*3.8^(3))

= (2.7^(-3 + 4)*3.8^(2 + 3))

= 2.7^(1)*3.8^(5)

That is the expression simplified, we can see that the correct option is C.

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Answer: The graph that best represents the number of centimeters the toy car travels in x seconds would be a linear graph with a slope of 12. The equation for this graph would be y = 12x, where y represents the distance traveled in centimeters and x represents the time in seconds.

Step-by-step explanation:

Answer:

(A)

[tex] - 4.9 {t}^{2} + 43t + 339 = 0[/tex]

[tex]49 {t}^{2} - 430t - 3390 = 0[/tex]

[tex]t = \frac{ - ( - 430) + \sqrt{ {( - 430)}^{2} - 4(49)( - 3390)} }{2(49)} = \frac{430 + \sqrt{849340} }{98} = 13.79[/tex]

The rocket splashes down after 13.79 seconds.

(B) h'(t) = -9.8t + 43 = 0

t = 43/9.8 = 215/49 = 4.39 seconds

h(4.39) = 433.34 meters

At t = 4.39 seconds, the rocket peaks at

433.34 meters above sea level.

Therefore , the solution of the given problem of fraction comes out to be 3/4 cups of yoghurt to the blender.

Any configuration of identically sized parts can be combined to represent the total. In Standard English, quantity is defined as "a portion" within a specific measurement. 8, 3/4. Wholes also include fractions. These serve as the divisor of the ratio, which in mathematical terms would be a pair of numbers. Here are a few illustrations of how to convert simple halves into whole numbers.

Here,

A visual fraction model can be used to illustrate the various fractions in a cup of yoghurt that you want to add in portions to a blender.

For instance, you may divide the cup into four equal parts and use one of those parts to represent 1/4 cup of yoghurt in the blender.

You can divide the cup into two equal parts and display two of those parts to symbolise the addition of 1/2 cup of yoghurt.

You would have added

=> 1/4 + 1/2 = 3/4 cups of yoghurt to the blender.

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1) Line AB

2) Ray AB

3) Line segment AB

4)Ray BA

The first drawing is a line AB because a line passing through two different points A and B

The second drawing is ray AB because it started at A

The third drawing is a line segment AB because it is part of a straight line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints

The fourth drawing is ray BA

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The result of the operation that we have done here is -5√3.

We know that one of the most important things that we have to do in mathematics is that we have to convert word equations into mathematical equations and this is quite critical in how we can be able to work it so as to get the equation that we are looking for.

We now have that;

5/-3 * 3 * √3

5/-1 * √3

-5* √3

-5√3

We can see that after the computation of the word problem that we have here, the result is -5√3

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Answer:

Starting with the equation:

-2x + 6 = -x^2

First, we can rearrange it to put it in standard quadratic form:

x^2 - 2x - 6 = 0

To complete the square, we need to add and subtract a constant term that will make the left-hand side of the equation a perfect square. The constant we need to add is (b/2)^2, where b is the coefficient of x. In this case, b = -2, so:

x^2 - 2x + 1 - 1 - 6 = 0

The first three terms can be written as a perfect square:

(x - 1)^2 - 7 = 0

Add 7 to both sides:

(x - 1)^2 = 7

Now we can take the square root of both sides:

x - 1 = ±√7

Add 1 to both sides:

x = 1 ± √7

So the solutions to the equation are:

x = 1 + √7 or x = 1 - √7

mark me brilliant

The volume of the prism is 143.44 in³

A prism is a solid shape that is bound on all its sides by plane faces.

The general formula for the volume of a prism is expressed as;

V = base area × height

The prism is a rectangular prism, therefore the volume will be calculated as

V = l× w × h

where l is the length of the base and w is the width of the base

V = 8.5× 4.5 × 3.75

V = 143.44 in³

therefore the volume of the rectangular prism is 143.44 in³

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Answer:

C

Step-by-step explanation:

If it is perpendicular to the line y = ¾x+7 then the gradient if the line must be the negative reciprocal of 3/4. The gradient must be - 4/3. So A, B and D are rejected. Left is C

Let's replace now.

For C,

Let's take y=-4/3x-10 into consideration at the point (-12,6)

Y should be equal to 6 when we replace x by -12

Let's try

Y = -4/3(-12) - 10 = 16 - 10 = 6

Yup. C is your answer.

These are absolute value expressions evaluated under different conditions:

|x + 3| if x > 5:

Here x is greater than 5, so x + 3 will also be positive. In this case, |x + 3| = x + 3.

|x + 3| if x > 2:

Similar to the above, x is greater than 2, so x + 3 will be positive. Thus, |x + 3| = x + 3.

|x + 3| if x = 2:

In this case, x + 3 = 2 + 3 = 5, and the absolute value of 5 is just 5. Thus, |x + 3| = 5.

|x - 3| if x > 5:

If x is greater than 5, then x - 3 will be positive. Hence, |x - 3| = x - 3.

|120 + x| if x < -120:

Since x is less than -120, 120 + x will be negative. But the absolute value of a negative number is its positive counterpart, so |120 + x| = -(120 + x).

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"There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen does not matter." is correct statement. Therefore, the answer is option C.

The problem asks us to choose 5 students out of a class of 26 to present homework problems. Since the order in which the students present the problems does not matter, we need to use the combination formula. The combination formula is used to calculate the number of ways to choose a subset of k elements from a set of n elements without regard to order, and it is denoted by nCk.

Option A, "There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen matters," is incorrect because the order in which the students are chosen does not matter.

Option B, "There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen matters," is incorrect because we are choosing 5 students out of 26, and the order in which they are chosen does not matter.

Option D, "There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen does not matter," is also incorrect because the order in which the students are chosen does not matter.

Therefore, the answer is option C.

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Complete question is:

In a class of 26 students, a teacher chooses a different student to each present five different homework problems. Which statement describes the number of ways the students can be chosen to present the problems?

A) There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen matters.

B) There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen matters.

C) There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen does not matter.

D) There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen does not matter.

Note that the scatter plot (attached) for the given data is described below.

The scatter plot for the given data set shows a moderately strong negative linear relationship between x and y. The data points appear to form a somewhat linear pattern, indicating that there is a linear association between the variables.

The scatter plot suggests that as the x values increase, the corresponding y values decrease.

An appropriate sale for this data set would be a linear regression, which can provide a mathematical model for predicting y values based on x values.

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It is financially beneficial for Harris Fishing Tours to replace the old boat with the new fuel-efficient model, as it has a net benefit of $12,000 compared to continuing to use the old boat.

To determine whether Harris Fishing Tours should replace the old boat with the new fuel-efficient model, we need to compare the costs and benefits of each option.

Option 1: Replace the old boat with the new fuel-efficient model

If Harris replaces the old boat with the new fuel-efficient model, they will have to pay $80,000 for the new boat. They can sell the old boat for $32,000, so the net cost of the new boat will be $48,000 ($80,000 - $32,000).

The new boat is expected to be extremely fuel efficient, which means that the fuel costs will be $15,000 per year lower than the old boat. Over the remaining four years of the old boat's useful life, this represents a total savings of $60,000 ($15,000 x 4).

Therefore, the total cost of replacing the old boat with the new fuel-efficient model is $48,000 - $60,000 = -$12,000, which means that this option has a net benefit of $12,000.

Option 2: Continue to use the old boat until it wears out

If Harris decides to continue using the old boat until it wears out, they will not incur the $80,000 cost of purchasing the new boat.

However, they will continue to pay $15,000 per year more in fuel costs than they would with the new boat. Over the remaining four years of the old boat's useful life, this represents a total cost of $60,000 ($15,000 x 4).

In addition, at the end of the four years, the old boat will have no salvage value since it will have reached the end of its useful life.

Therefore, the total cost of continuing to use the old boat until it wears out is $60,000, which means that this option has a net cost of $60,000.

Conclusion

Based on the analysis above, it is more financially beneficial for Harris Fishing Tours to replace the old boat with the new fuel-efficient model. This option has a net benefit of $12,000, while continuing to use the old boat until it wears out has a net cost of $60,000.

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Answer:

[tex]m = \frac{10 - 7}{7 - 3} = \frac{3}{4} [/tex]

Answer:

it's 4 cm

Step-by-step explanation:

A. Square = 50 cm²

A. Square = s × s

50 = s²

s = √50

SP = hypotenuse (c) = s

c = s = √50

b = √34

a = PT = ...?

use Pythagorean theorem to find PT

a² + b² = c²

a² + (√34)² = (√50)²

a² + 34 = 50

a² = 50 - 34

a² = 16

a = √16

a = 4 cm

Answer:  350.214

Step-by-step explanation:

The percentage of the powdered lemon mix in Dianelys's mix indicates that Dianelys's mix is more lemony.

A percentage is an expression of a ratio of two quantities as a fraction of 100.

The number of cups of water Zachary mixes with 5 cups of powdered lemon mix = 11 cups of water
Number of cups of water Dianelys mixes with 4 cups of powdered lemon mix = 7 cups of water

Zachary's percentage of powdered lemon mix = (5/(11 + 5)) × 100 = 31.25%

Dianelys's percentage of powdered lemon mix = (4/(7 + 4)) × 100 = 36.[tex]\overline{36}[/tex]%

The percentage of powdered lemon mix for Dianelys which is more than the percentage in Zachary's powdered lemon mix indicates that Danialys mix is more lemony.

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The trigonometric ratio cosA = [tex]\frac{3}{5}[/tex] which is in the lowest form.

Trigonometric ratios are the ratios of the sides of a right triangle. The sine, cosine, and tangent are three popular trigonometric ratios. (tan).

The given triangle is a right angle,

To find the cos angle we need to take the ratio of the length of the side which is next to the angle, it is also called an adjacent side to the length of the longest side of the triangle called the hypotenuse.

[tex]cosA = \frac{Length of the side next to the angle}{length of the longest side of the triangle} \\cosA = \frac{Adjacent side}{Hypotenuse} \\cosA = \frac{6}{10}\\ cosA = \frac{3}{5}[/tex]

Therefore [tex]cosA= \frac{3}{5}[/tex]

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Note that the perimeter of the parallelogram is 42

recall that opposite sides of a parallelogram are congruent always

We have to to find the distance between the  points Q(6, 6 ) and R(1, -6) using the distance formula which is

d = √[(x2 - x1) ² + (y2 - y 1)²]

where d is the distance between two points with paris   (x1 , y1)

and (x2, y2).

PS = QR = √(6-1)²  + (6+6)²

    = √5² + 12²
= √(25+144

= √(169)

= 13

PQ = SR = 8

Perimeter  = 13 + 13 + 8 + 8
Perimeter = 42.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

See attached image.

The wrong formula was used. The correct method is: area of sector = 115/360 * 255 ≈ 81.46 square feet.

The area of a sector is calculated by using the formula:

Area of sector = ∅/360 * πr², where:

r is the radius of the circle

∅ is the central angle measure.

The error made was that a wrong method/formula was used in finding the area of sector.

Given the following:

Area of circle = 255 square feet (πr²)

∅ = 115°

Note that πr² represents the area of a circle, therefore, substituting the values into the formula, we have:

Area of sector = 115/360 * 255

Area of sector ≈ 81.46 square feet

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The composite functions are:

a) f ∘ g = 3x² + 4, with domain of all real numbers.

b) g ∘ f = 9x² + 24x + 16, with domain of all real numbers.

c) f ∘ f = 9x + 16, with domain of all real numbers.

d) g ∘ g = x⁴, with domain of all real numbers.

To find the composite functions, we need to substitute the function g into the function f or vice versa, depending on the order of composition. The resulting composite function will have a domain that is restricted by the domains of the individual functions involved.

a) To find f ∘ g, we substitute g(x) = x² into f(x) = 3x + 4:

f(g(x)) = 3g(x) + 4 = 3x² + 4

The domain of f ∘ g is all real numbers because the domain of g(x) = x² is all real numbers.

b) To find g ∘ f, we substitute f(x) = 3x + 4 into g(x) = x²:

g(f(x)) = (3x + 4)² = 9x² + 24x + 16

The domain of g ∘ f is all real numbers because the domain of f(x) = 3x + 4 is all real numbers.

c) To find f ∘ f, we substitute f(x) = 3x + 4 into f(x) = 3x + 4:

f(f(x)) = 3f(x) + 4 = 3(3x + 4) + 4 = 9x + 16

The domain of f ∘ f is all real numbers because the domain of f(x) = 3x + 4 is all real numbers.

d) To find g ∘ g, we substitute g(x) = x² into g(x) = x²:

g(g(x)) = (x²)² = x⁴

The domain of g ∘ g is all real numbers because the domain of g(x) = x² is all real numbers.

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Answer:

75%

Step-by-step explanation:

To determine the total percentage of athletes who enjoy cycling, we need to consider the percentages given in the problem.

According to the information provided:

55% of the team does not like to run.

Of those who do not like to run, 70% enjoy cycling.

Of those who enjoy running, 80% also enjoy cycling.

To calculate the total percentage of athletes who enjoy cycling, we need to consider the percentages from both branches of the tree diagram.

Percentage of athletes who do not like to run and enjoy cycling:

= (Percentage of athletes who do not like to run) * (Percentage of those who enjoy cycling within that group)

= 55% * 70% = 38.5%

Percentage of athletes who enjoy running and enjoy cycling:

= (Percentage of athletes who enjoy running) * (Percentage of those who enjoy cycling within that group)

= (100% - 55%) * 80% = 45% * 80% = 36%

Total percentage of athletes who enjoy cycling:

= Percentage of athletes who do not like to run and enjoy cycling + Percentage of athletes who enjoy running and enjoy cycling

= 38.5% + 36% = 74.5%

Therefore, the correct answer is:

74.5%