Jean-Paul incorrectly states that
4.2874 + 1.286 = 4.416.
His work is
shown below.

Explain Jean-Paul's
mistake and correct his work.

Please help due at 4:20

Jean-Paul Incorrectly States That4.2874 + 1.286 = 4.416. His Work Isshown Below. Explain Jean-Paul'smistake

Answers

Answer 1
To start solving you need to have the decimals underneath it each other like this
4.2874 (U add a zero if there is no number for that area)
1.2860
_____
5.5743 is the right answer :)

Related Questions

Carrie drew two acute non-overlapping angles that share a ray and labeled them LADB and LBD The two angles have the same whole number measure. What is the least possible measure of LAD What is the greatest possible measure of LADC? O A. least: 2° greatest: 88°Carrie drew two acute non-overlapping angles that share a ray and labeled them LADB and LBD The two angles have the same whole number measure. What is the least possible measure of LAD What is the greatest possible measure of LADC?

Answers

Answer:

  B.  least 2°; greatest 178°

Step-by-step explanation:

The measure of ∠ADC will be the sum of the measures of the two acute angles ADB and BDC.

__

Each acute angle with a measure that is a whole number of degrees will have a measure between 1° and 89°, inclusive.

The least sum of two such angles will be ...

  1° +1° =

The greatest sum of two such angles will be ...

  89° +89° = 178°

100 points please answer asap!!!!!!!!!!! this is algebra 1

part a: describe two types of transformations that can be used to transform f(x) to g(x).

part b: solve for k in each type of transformation.

part c: write an equation for each type of transformation that can be used to transform f(x) to g(x).

Answers

Answer:

f(x) has slope (10-0)/(10-5) = 10/5 = 2

and intercept y - mx = 0 - 5(2) = -10 so f(x) = 2x - 10

g(x) has slope (10-0)/(2+3) = 2 and intercept y - mx = 10 - 2*2 =6

so g(x) = 2x + 6

So to transform f to g, you move the graph 16 units up.

Step-by-step explanation:

For which system of equations is the graph below a solution?

A. y = x - 2
y = - x - 3

B. y = x + 2
y = - x - 3

C. y = x - 2
y = -x + 3

D. y = x + 2
y = -x + 3​

Answers

Answer:

C

Step-by-step explanation:

Black line

slope = Δy / Δx = -3 / 3 = -1

Y intercept = 3

LINE equation ( y = slope times x + y intercept): y = -x +3

Blue line

slope = Δy / Δx = 2 / 2 = 1

Y intercept = -2

LINE equation ( y = slope times x + y intercept): y = x -2

Can someone pls help me

Answers

Answer:

? what do u want me todo

Step-by-step explanation:

Solve the inequality. Graph the solution. Describe the graph in the area provided. Be sure to indicate where there is an open or closed circle and what direction the number line is shaded in.

Answers

To solve this problem, we can to simply plot using a graphing tool and the region under the area would be given. We would see there's no solution for this compound inequality

Graphing of Inequality

The given inequalities in this question are

x + 4 > 0.0132 ≤ - 4x

When we plot this, we would see that no solution exists for this compound inequality problem.

Kindly check the attach image for more details.

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I need help asap !!!!! Olease

Answers

Answer:

[tex]\overline{BC}[/tex]

Step-by-step explanation:

[tex]\overline{BC}[/tex] does NOT intersect [tex]\overline{AG}[/tex]

Hope it helps you in your learning process.

simplify- 4c^2-36/8c^2-24c/12c+36/2c^2-6c
pls help :)

Answers

[tex]\displaystyle \dfrac{\dfrac{4c^2-36}{8c^2-24c}}{\dfrac{12c+36}{2c^2 -6c}}\\\\\\=\left(\dfrac{4c^2 -36}{8c^2 -24c}\right) \cdot \left(\dfrac{2c^2 -6c}{12c+36}\right)\\\\\\=\left[\dfrac{4(c^2 -9)}{8(c^2-3)}\right]\cdot\left[\dfrac{2(c^2-3)}{12(c+3)}\right]\\\\\\=\dfrac{8(c^2-3^2)}{8 \cdot 12(c+3)}\\\\\\=\dfrac{(c+3)(c-3)}{12(c+3)}\\\\\\=\dfrac{c-3}{12}[/tex]

[tex]\text{Hence the answer is d.}[/tex]

Answer:

d

Step-by-step explanation:

separate the 2 divisions and simplify each , that is

[tex]\frac{4c^2-36}{8c^2-24c}[/tex] ← factor numerator/ denominator

= [tex]\frac{4(c^2-9)}{8c(c-3)}[/tex] ← factor difference of squares on numerator

= [tex]\frac{4(c-3)(c+3)}{8c(c-3)}[/tex] ← cancel (c - 3) and 4/8 on numerator/ denominator

= [tex]\frac{c+3}{2c}[/tex]

---------------------------------------------------

[tex]\frac{12c+36}{2c^2-6c}[/tex] ← factor numerator/ denominator

= [tex]\frac{12(c+3)}{2c(c-3)}[/tex] ← cancel 12 and 2 on numerator/ denominator

= [tex]\frac{6(c+3)}{c(c-3)}[/tex]

----------------------------------------------------------

to divide the top fraction by the lower fraction

leave top fraction, change division to multiplication, turn lower fraction upside down.

[tex]\frac{c+3}{2c}[/tex] × [tex]\frac{c(c-3)}{6(c+3)}[/tex] ← cancel (c + 3) and c on numerator/ denominator

= [tex]\frac{c-3}{2(6)}[/tex]

= [tex]\frac{c-3}{12}[/tex] → d

can someone help me with this problem please? Thank you!

Answers

Answer:

50

Step-by-step explanation:

since the Pythagorean theorem is

[tex]c=[/tex] √[tex]a^2+b^2[/tex]

b is the bottom line (48)

a is the right line (14)

c is the top line (c)

plug that in

[tex]c =[/tex] √[tex]14^2 + 48^2[/tex]

then do the exponets

[tex]14^2[/tex] = 14 * 14 = 196

[tex]48^2[/tex] = 48 * 48 = 2304

then add them together

196 + 2304 = 2500

[tex]c =[/tex] √2500

the sqrt of 2500 is 50 (50 * 50 = 2500)

c = 50

your answer is 50

hope this helps:)

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's calculate the value of c using Pythagoras theorem ~

[tex]\qquad \sf  \dashrightarrow \: c {}^{2} = a {}^{2} + {b}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c {}^{2} = {14}^{2} + {48}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = \sqrt{196 + 2304} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = \sqrt{2500} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 50 \: units[/tex]

what is the expression of the product for 17 and s?

Answers

Answer:

17s

Step-by-step explanation:

Note: an expression is NOT an equation

"Product" means the answer to a multiplication of two numbers.

You are asked to write the answer to 17 and s being multiplied together.

The product is therefore

17 x s = 17s

Why is 3 x 1/10 less than 3x 10

Answers

Answer:

Because 1/10 is less than 10

Step-by-step explanation:

10 is 100 times greater than 1/10

[tex]\frac{10}{1/10} =100[/tex]

Hope this helps

Because 3 x (1/10)=0.3 thus, < 3 x 10=30
0.3<30

Use >, <, or = to solve the following problems below.
(6^2)____(-6^2)
-5____ |-5|
0.372×1,000____37.2×100
(will mark brainliest)​

Answers

(6^2)__>__(-6^2)

-5__=__ |-5|

0.372×1,000__<__37.2×100

i cant figure this one out at all

Answers

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

Someone please tell me if this is right or not!!

Answers

Answer:

close countess

Step-by-step explanation:

remember that the sign has to be postive so just change all the signs ,  then,   you'll have a leading coefficient of  +1,  in front of the [tex]x^{2}[/tex],  the 5 is in front of the 2nd term,  they were just trying to trick you with that.   the last answer is good     :)

The degree and standard form are correct, good job!
For the leading coefficient, I would see why you think it’s 5 since the highest number in front of x
but the definition of leading coefficient is the number of highest power of x
In this case it would be -x^2 is the higher power making -1 the leading coefficient
Hope this help, let me know if you have any question or concerns !

How do you think a car engine gets energy from gasoline?

Answers

A car engine gets energy from gasoline during the production of the combustion of gasoline in a car engine which is converted as kinetic energy.

How is the energy of the universe conserved?

In a car driven by a gasoline combustion engine, heat energy is quickly converted into kinetic energy which results in the motion of the car.

The law of the conservation of energy states that "Energy cannot be destroyed or created. It can only be transformed from one form to another".

The combustion of gasoline in a car engine tends to generate heat energy, this heat energy will be transferred as kinetic energy which results in the motion of the car.

This energy of the universe will be conserved as the energy created by the combustion is used as kinetic energy for the motion of cars.

Learn more about energy;

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Answer:

A car engine gets energy from gasoline during the production of the combustion of gasoline in a car engine which is converted as kinetic energy.

Step-by-step explanation:

How is the energy of the universe conserved?

In a car driven by a gasoline combustion engine, heat energy is quickly converted into kinetic energy which results in the motion of the car.

The law of the conservation of energy states that "Energy cannot be destroyed or created. It can only be transformed from one form to another".

The combustion of gasoline in a car engine tends to generate heat energy, this heat energy will be transferred as kinetic energy which results in the motion of the car.

This energy of the universe will be conserved as the energy created by the combustion is used as kinetic energy for the motion of cars.

Write the equation of the circle given center (-13,-16) and point on the circle (-10,-16)

Answers

Answer:

Step-by-step explanation:

An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up. The ladder makes an angle of 77^{\circ} ∘ with the ground. Find the length of the ladder. Round your answer to the nearest hundredth of a foot if necessary.

Answers

The length of the ladder nearest hundredth of a foot is 23 feet.

We have given that,

An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up.

The ladder makes an angle of [tex]77^{\circ}[/tex]  the ground.

What is the sin ratio?

[tex]sin(\theta)=\frac{perpendicular \ side}{hypotenous}[/tex]

Therefore we get,

[tex]\implies\frac{22}{H} =sin(77)[/tex]

[tex]\implies H=22/sin(77)[/tex]

[tex]\implies 22.59ft\\\\=23ft[/tex]

Therefore, The length of the ladder nearest hundredth of a foot is 23 feet.

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Taxi charges 2.95 for the first mile and 0.30 per 1/8 gary was charged 25.45 for this taxi ride. Not including the first mile how many miles did Gary travel.

Answers

Using proportions, considering the cost of the taxi per mile, it is found that Gary traveled 9.375 miles, not including the first.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, the company charges 2.95 for the first mile and $0.3 per each 1/8 mile next = $2.4 per mile. After the first mile, he was charged a total of $25.45 - $2.95 = $22.5. Hence the number of miles is given by:

22.5/2.4 = 9.375.

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Gideon has a rectangular garden with an area of 19.6 square feet. If the length of the garden is 4.3 feet, what is the length of the diagonal of the garden? Round to the nearest tenth.

Answers

The length of the diagonal of the garden with 19.6 square feet and 4.3 length is : 6.3 feet

What is a rectangle?

A rectangle is a quadrilateral with four sides and four vertices  each of angle 90°.

Analysis:

Area of rectangle: 19.6 square feet

length of one side = 4.3 feet

width of one side = Area/length = 19.6/4.3 = 4.6 feet

the diagonal and width and length of a rectangle for a right angle triangle.

To find the diagonal, we use Pythagoras theorem

[tex](diagonal)^{2}[/tex] = [tex](length)^{2}[/tex] + [tex](width)^{2}[/tex]

[tex](diagonal)^{2}[/tex] = [tex](4.3)^{2}[/tex] + [tex](4.6)^{2}[/tex]

[tex](diagonal)^{2}[/tex] = 39.7

diagonal = [tex]\sqrt{39.7}[/tex] = 6.3 feet

in conclusion, the diagonal of the rectangular garden is 6.3 feet

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A parabola has vertex (−2, −1) and passes through the point (1, 26). Find its equation.

Answers

[tex]\text{Equation of parabola in vertex form,}\\\\~~~~~~~~~y = a(x-h)^2 +k\\\\\implies 26 = a(1+2)^2 -1~~~~~~~~;[(x,y) = (1,26)~ \text{and}~ (h,k) = (-2,-1)]\\\\\implies 26 = 9a -1\\\\\implies 9a = 26+1\\\\\implies 9a = 27\\\\\implies a = \dfrac{27} 9 \\\\\implies a = 3\\\\\text{Now,}\\\\~~~~~~~~y = 3(x+2)^2 -1~~~~~~~~~~;[\text{Vertex form.}]\\\\\implies y=3(x^2 +4x +4) -1\\\\\implies y = 3x^2 +12x +12 -1 \\\\\implies y=3x^2 +12x+11~~~~~~~~;[\text{Standard form.}][/tex]

PLEASE HELP :))
Select the correct answer from each drop-down menu consider the given triangles
The length of side PR in PQR is____ and the measure of J in JKL is___

Answers

The measure of the side PR in PQR is 8.07 units and the measure of angle J in JKL is 35.30 degree.

What is the triangle?

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

Applying cos law in the triangle PQR:

[tex]\rm PR = \sqrt{5^2+9^2-2(5)(9)cos63}[/tex]

PR = 8.07 units

Applying sin law in the triangle, JKL:

[tex]\rm Angle \ J = sin^{-1}[sin 52 \ (\dfrac{11}{15})][/tex]

Angle J = 35.30 degree

Thus, the measure of the side PR in PQR is 8.07 units and the measure of angle J in JKL is 35.30 degree.

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Answer: POR NADA

Step-by-step explanation: ANSWER ON EDMENTUM/PLUTO

Combine like terms to answer the question.

Answers

Answer:

3r + 5

Step-by-step explanation:

by "combining like terms", this means that if we have, for example,

1 * x + 5 * x, we can factor this out to be x*(1+5) = 6 * x and the like terms (1x and 5x) are combined

thus, we have

-5r + 8r + 5

the "like terms" here are -5r and 8r because they both have an r attached to it. thus, we can set out to only factor the r in these two numbers, resulting in

-5 * r + 8 * r + 5 = r * (-5 + 8) + 5 = r * 3 + 5 = 3r + 5

Camile is packing seeds to send to her mother in law. She estimates that she needs a box with a volume of at least 6,856 cubic inches. Here are the boxes she has to choose from Option A Length: 13 inches, Width 12 inches, Height: 16 inches Option B Length: 18 inches, Width: 25 inches, Height: 16 inches Option C Length:12 inches, Width: 14 inches Height: 22 inches Option D Length: 20 inches, Width:22 inches, Height: 17 inches Which boxes con she choose?​

Answers

Step-by-step explanation:

the volume of a box (or prism) is always

length × width × height

so, box A

13 × 12 × 16 = 2,496 in³

box B

18 × 25 × 16 = 7,200 in³

box C

12 × 14 × 22 = 3,696 in³

box D

20 × 22 × 17 = 7,480 in³

so, she can use B or D.

is this the RIGHT answer

Answers

Answer:

Yes

Step-by-step explanation:

The horizontal line on a graph is the x axis and the "C" appears to be on the horizontal line therefore the answer would be x-axis


reasons its not the other answer choices

Y axis is the vertical line

Origin is where the two axis cross

Quadrant 1 may appear where C is however the C is pointing to the X axis

Please write the solution

Answers

Answer:

D.

Step-by-step explanation:

that is the answer to the question above

find the area of the following figure ​

Answers

Answer:

okay

Step-by-step explanation:

calculate the areas of those rectangles separately

[tex]say \: rectangle \: 1 \\ area = 21 \times 18 \\ = {378in}^{2} \\ rectangle \: two \\ area = 17 \times 9 \\ = {153in}^{2} \\ \\ total \: area \: = 153 + 378 \\ = {531in}^{2} [/tex]

Find the area and perimeter of this compound shape. Explain.

Answers

Answer:

area = 232.5

perimeter=71.243

how does the scatter plot show that age and time spent talking on the phone have a linear association?

Answers

Answer:

When the y variable tends to increase as the x variable increases we say there is a positive correlation between the variables

I NEED Help NOW FOR 10 POINTS

Answers

In picture 1, the diameter of the circle is being shown.

Which of the following can be found on a credit report?
A Personal Social Security Number
B Checking Account Balance
C Late Payments to Lenders
D Credit Card Balances


B and D Only
A Only
Not here
A, C, and D Only​

Answers

Answer:

A, C, & D only

Step-by-step explanation:

All of the following are listed on your credit report except option B) your checking account balance.

A cylinder is inscribed in a right circular cone of height 2.5 and radius (at the base) equal to 5.5. what are the dimensions of such a cylinder which has maximum volume?

Answers

Check the picture below.

so hmm if we look at the cone straight from the front and check a cross-section of it, it'd look like the cross-section of the right-hand-side of the picture.

Now, with the cylinder having radius "r" and height "h", those two triangles we see in greenish color are similar, thus we can use proportions to correlate "h" and "r", so let's do that.

[tex]\cfrac{2.5-h}{r}~~ = ~~\cfrac{h}{5.5-r}\implies 13.75-5.5h-2.5r+rh=rh \\\\\\ 13.75-2.5r=5.5h\implies \boxed{\cfrac{13.75-2.5r}{5.5}=h}[/tex]

now, let's plug that in the volume of the cylinder's equation

[tex]V(r)=\pi r^2\cdot \cfrac{13.75-2.5r}{5.5}\implies V(r)=\cfrac{\pi }{5.5}(13.75r^2-2.5r^3) \\\\\\ \cfrac{dV}{dr}=\cfrac{\pi r(27.5-7.5r)}{5.5}\hspace{5em}0~~ < ~~r ~~ < ~~ 2.5[/tex]

now, our "r" variable can't be 0 or 2.5, as the cylinder tiptoes up and down, because if that ever happens, our cylinder's volume goes poof.

[tex]0=\cfrac{\pi r(27.5-7.5r)}{5.5}\implies 0=27.5-7.5r\implies 7.5r=27.5 \\\\\\ r=\cfrac{27.5}{7.5}\implies r=\cfrac{11}{3}[/tex]

the way I do region testing for the 1st derivative, is I usually grab the critical point and subtract hmm say 0.0000001 from it and put it in a variable in my calculator, then I add 0.0000001 to it and put it in another variable, then I use that variable in the 1st derivative calculation.  Anyhow, doing so and running a 1st derivative test, we'd see that the region to the left of 11/3 is positive whilst the region to the right is negative, as you can see in the picture at the bottom, yielding a maximum extremum, r = 0 is another critical point but as we noticed the constraints is out of bounds, so not in consideration.

so V(r) is at a maximum when r = 11/3

[tex]\blacksquare~~ r=\cfrac{11}{3} ~~\blacksquare \hspace{5em} \cfrac{13.75-2.5\left( \frac{11}{3} \right)}{5.5}=h~\hfill \implies ~\hfill \blacksquare~~ \cfrac{5}{6}=h ~~\blacksquare[/tex]

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