Problem 3. Find the mass and center of mass of the lamina that occupies the region bounded by the parabolas y = r² and x = y², and has density function p(x, y) = √√T.

Answers

Answer 1

The mass and center of mass of the lamina that occupies the region D and has the given density function p is 57/14 and (14/27, 7/18) respectively.

The center of mass (x―,y―) of a lamina with density function ρ(x,y) is given by

x = M(y)/m, y = M(x)/m

Where, m=∫∫ρ(x,y)dA

Mx=∫∫ yρ(x,y)dA

My=∫∫ xρ(x,y)dA

Given that, D is bounded by y=x^2 and x=y^2

And ρ(x,y)=19√x

Now, for the point of intersection of y=x^2,x=y^2

The lamina is customary, so its focal point of mass is its mathematical focus. Take a lamina with three holes near its perimeter and now suspend it through each hole one at a time.

Here,

The mass density of a lamina is the mass per unit area. Take into consideration the following lamina, whose density varies with the object: On a semicircular lamina D with a radius of three, the density at any point is proportional to the distance from the origin.

We know,

A lamina's centroid is the point at which it would balance on a needle. The point at which a solid would "balance" is called the centroid.

Consider a lamina formed by the intersection of two curves y = f (x) and y = g (x) at points with x-coordinates of x = a and b.

Mass (M) = b a g (x) f (x) d y d x x-coordinate (x) = b a x (x, y) [ g (x) f (x)] d x y-coordinate (y) = b a 1 2 (x, y) [ [ g (x)] 2 [ f (x)] 2] d x.

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Related Questions

3. What do the parabolas x) = 3x² + 4x-9 and g(x)=-5x²-3x - 9 have in common? c. They have the same x-intercepts. a. They have the same y-intercept. b. They have the same vertex. d. They have the same axis of symmetry

Answers

Answer:

  a. They have the same y-intercept.

Step-by-step explanation:

You want to know what the parabolas f(x) = 3x² +4x -9 and g(x) = -5x² -3x -9 have in common.

X-intercepts

Referring to the attached graphs, we see that f(x) has two x-intercepts and g(x) has none. They do not have x-intercepts in common.

Y-intercept

The constants in the two functions are both -9. They have the same y-intercept.

Vertex

Referring to the attached graphs, we see that the functions have different vertices. They do not have a vertex in common.

Axis of symmetry

Referring to the attached graphs, we see that the x-coordinate of each vertex is different. They do not have an axis of symmetry in common.

40 POINTS ASAP NO LINKS PLSS

7. Abhijot has $20. Which two items could he buy that comes closest to $20 without going over? Remember to include 7% sales tax.​

Answers

Answer:   it's a good one

Step-by-step explanation:

To determine which two items Abhijot could buy that come closest to $20 without going over, we need to know the prices of the available items. Let's assume there are three items available:

Item 1: $7.50

Item 2: $8.75

Item 3: $10.25

To calculate the total cost of each item with sales tax included, we need to add 7% of the price to the price itself.

For Item 1: $7.50 + ($7.50 x 0.07) = $8.03

For Item 2: $8.75 + ($8.75 x 0.07) = $9.36

For Item 3: $10.25 + ($10.25 x 0.07) = $10.97

Now we can try different combinations of two items to see which ones come closest to $20 without going over:

Item 1 and Item 2: $8.03 + $9.36 = $17.39

Item 1 and Item 3: $8.03 + $10.97 = $18.00

Item 2 and Item 3: $9.36 + $10.97 = $20.33

Therefore, Abhijot could buy Item 1 and Item 3 that comes closest to $20 without going over, with a total cost of $18.00.

Answer:

Necklace and cologne with a total price after sales taxes of
13.90 + 6.09 = $19.99

Step-by-step explanation:

Before sales taxes:

12.99 Cologne

4.99 Candle

12.59 earrings

5.99 candy

7.99 plant

6.99 bouquet

5.69 Necklace

4.99 picture frame

14.99 Cd

Prices After sales taxes
Cologne:  12.99*1.07 = 13.90

Candle:  4.99*1.07 = 5.34

Earrings:  12.59*1.07 = 13.47

Candy:  5.99*1.07 = 6.41

Plant: 7.99*1.07 = 8.55

Bouquet: 6.99*1.07 = 7.48

Necklace: 5.69*1.07 = 6.09

Picture frame: 4.99*1.07 = 5.34

CD:    14.99*1.07 = 16.04

If he has only 20 dollars the closest is 13.90 of cologne + 6.09 dollars of the neckalce  => 13.90+6.09 = $19.99

Find the general solution of the system x'(t) = Ax(t) for the given matrix A. -1 A = - 11 9 x(t) = 2

Answers

To find the general solution of the system x'(t) = Ax(t) for the given matrix A, we need to perform the following steps:

Step 1: Find the eigenvalues of matrix A.

To find the eigenvalues, we solve the characteristic equation det(A - λI) = 0, where I is the identity matrix.

A = [[-1, -11], [9, 2]]

λI = [[λ, 0], [0, λ]]

det(A - λI) = | -1 - λ -11 |

| 9 2 - λ |

Expanding the determinant, we get:

(-1 - λ)(2 - λ) - (-11)(9) = 0

λ² - λ - 20 = 0

Solving the quadratic equation, we find two eigenvalues:

λ₁ = 5

λ₂ = -4

Step 2: Find the corresponding eigenvectors for each eigenvalue.

For λ₁ = 5:

(A - 5I) = [[-6, -11], [9, -3]]

Row reducing (A - 5I) to echelon form, we get:

[[1, 2], [0, 0]]

Letting x₂ = t (a parameter), the eigenvector for λ₁ = 5 is:

v₁ = [x₁, x₂] = [2, t]

For λ₂ = -4:

(A + 4I) = [[3, -11], [9, 6]]

Row reducing (A + 4I) to echelon form, we get:

[[3, -11], [0, 0]]

Letting x₂ = t (a parameter), the eigenvector for λ₂ = -4 is:

v₂ = [x₁, x₂] = [11t, t]

Step 3: Write the general solution.

The general solution of the system x'(t) = Ax(t) is given by:

x(t) = c₁e^(λ₁t)v₁ + c₂e^(λ₂t)v₂

Substituting the values of λ₁, v₁, λ₂, and v₂, we have:

x(t) = c₁e^(5t)[2, t] + c₂e^(-4t)[11t, t]

where c₁ and c₂ are arbitrary constants.

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Consider the partial differential equation ux​−ut​=0. Trying to solve this differential equation with the method of separation of variables, we assume that there is a product solution for this equation of the form u=XT such that X=X(x) and T=T(t). From the options below, select ALL the correct statements. The solution for the first order separable ODE corresponding to T will be T=be−λt The solution for the first order separable ODE corresponding to X will be X=ce−λx The product solution for the given PDE will be u=ke−λ(x−t). After rewriting the equation in terms of X and T, I will divide both sides of my new equation by xtXT. The solution for the first order separable ODE corresponding to X will be X=e−λcx The solution for the first order separable ODE corresponding to T will be T=beλt After rewriting the equation in terms of X and T, I will divide both sides of my new equation by XT. The product solution for the given PDE will be u=ke−λ(x+t).

Answers

The product solution for the given PDE will be u = ke^λ(x+t).The above statements are true .

Given partial differential equation is ux​−ut​=0.To solve this differential equation with the method of separation of variables, we assume that there is a product solution for this equation of the form u=XT such that X=X(x) and T=T(t).

Hence, X(x) T(t) = u(x, t)The derivative of u(x, t) with respect to x is given by,u_x = X'(x) T(t) .....(1)The derivative of u(x, t) with respect to t is given by,u_t = X(x) T'(t) .....

(2)Given that ux​−ut​=0Substitute (1) and (2) in the given equation we have,X'(x) T(t) - X(x) T'(t) = 0.

On dividing the above equation by X(x) T(t), we get,X'(x) / X(x) = T'(t) / T(t)Let λ be the constant such that λ = X'(x) / X(x) = T'(t) / T(t)Then we get the following two differential equations,X'(x) - λX(x) = 0 .....(3)T'(t) - λT(t) = 0 ....

.(4)Solving equation (3), we have,X(x) = c1e^(λx) ......(5)Solving equation (4), we have,T(t) = c2e^(λt) ......(6).

Therefore the solution for the given partial differential equation is,u(x, t) = X(x) T(t) = c1e^(λx) c2e^(λt) = ke^(λ(x+t)) The product solution for the given partial differential equation is u = ke^λ(x+t).

Hence, the correct statements are as follows:

The solution for the first order separable ODE corresponding to X will be X = c1e^λx.The solution for the first order separable ODE corresponding to T will be T = c2e^λt.

The product solution for the given PDE will be u = ke^λ(x+t).The above statements are true .

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22 4. Let f(x,y)= S, a) Find the domain of /. Provide a sketch of the domain in 2-dim to illustrate. b) Show that the limit does not exist: lim /(x,y) (y) (0,0) y? -4x?

Answers

The domain of the function / is all possible values of x and y that satisfy certain conditions and yhe limit of the function / as (x, y) approaches (0, 0) along the path y = -4x does not exist.

a) To find the domain of the function /, we need to determine the set of all valid input values (x, y) that satisfy any given conditions or restrictions. Without specific information about the function or its restrictions, it is difficult to provide a detailed domain. However, a sketch of the domain in a 2-dimensional space can help visualize the possible values of x and y that are valid inputs for the function.

b) The limit of the function / as (x, y) approaches (0, 0) along the path y = -4x is calculated by evaluating the function along that path. Substituting y = -4x into the function, we have lim /(x, -4x) as x approaches 0.

However, without knowing the specific form of the function /, it is not possible to evaluate the limit algebraically. We can analyze the behavior of the function along the given path by approaching (0, 0) from different directions, but since the limit does not exist, the function does not approach a single value as (x, y) approaches (0, 0) along the path y = -4x.

Therefore, the limit of the function does not exist at (0, 0) along the path y = -4x, indicating that the function does not approach a specific value at that point.

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Use the Laplace transform to solve the differential equation
y"-y’-2y=(1-2x)e²
with the initial condition y(0) = 0 and y/ (0)= 1. Solutions not using the Laplace transform will receive 0 credit.

Answers

The answer is (s^2 - s - 2)Y(s) - s - 1 = 1/s - 2(-d/ds[L[xe^2]]). To solve the given differential equation y" - y' - 2y = (1-2x)e^2 using the Laplace transform, apply the Laplace transform to both sides of the equation.

Use the initial conditions to determine the solution.

Applying the Laplace transform to the differential equation and using the initial conditions, we can solve for the Laplace transform of y(t), denoted as Y(s), and then find the inverse Laplace transform of Y(s) to obtain the solution y(t). Let's denote the Laplace transform of y(t) as Y(s). Applying the Laplace transform to the differential equation, we get s^2Y(s) - sy(0) - y'(0) - (sY(s) - y(0)) - 2Y(s) = L[(1-2x)e^2], where L denotes the Laplace transform operator. Substituting the initial conditions y(0) = 0 and y'(0) = 1, we have s^2Y(s) - s - Y(s) + 0 - 2Y(s) = L[(1-2x)e^2]. Simplifying this equation, we obtain the transformed equation as (s^2 - s - 2)Y(s) - s - 1 = L[(1-2x)e^2].

Next, we need to find the Laplace transform of the right-hand side of the equation. Applying the linearity property and the transform of the exponential function, we get L[(1-2x)e^2] = L[e^2] - 2L[xe^2] = 1/s - 2(-d/ds[L[xe^2]]). Substituting these results back into the transformed equation, we have (s^2 - s - 2)Y(s) - s - 1 = 1/s - 2(-d/ds[L[xe^2]]). We can solve for Y(s) by rearranging the equation and isolating Y(s).

Finally, after obtaining Y(s), we need to find the inverse Laplace transform of Y(s) to obtain the solution y(t). This involves finding the inverse transform of each term on the right-hand side of the equation and combining them appropriately. The solution y(t) will depend on the inverse Laplace transforms of the terms involved, which can be determined using Laplace transform tables or other techniques.

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Solve the initial-value problem: dy 3 dx I +=y=x² + x, y(1) = 2

Answers

The particular solution to the initial-value problem is: y = (2/e^(3/2))e^(x²/2 + x)  = 2e^(x²/2 + x - 3/2)

To solve the initial-value problem for dy/dx = y = x² + x and y(1) = 2, the solution can be found by following these steps:

Step 1: Find the general solution by solving the differential equation dy/dx = y

By separating the variables and integrating both sides, we get:

dy/y = dx

Integration of both sides leads to ln|y| = x²/2 + x + C, where C is a constant of integration.

To solve for y, we exponentiate both sides:

|y| = e^(x²/2 + x + C)

We can ignore the absolute value sign because it will be cancelled out by the constant of integration.

Thus, the general solution is:

y = Ce^(x²/2 + x), where C is a constant.

Step 2: Find the value of C using the initial condition y(1) = 2.

Substitute x = 1 and y = 2 into the general solution and solve for C:

2 = Ce^(1²/2 + 1)2

= Ce^(3/2)C

= 2/e^(3/2)

Therefore, the particular solution to the initial-value problem is:

y = (2/e^(3/2))e^(x²/2 + x)

= 2e^(x²/2 + x - 3/2)

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The area of the kite is 36ft^2, and the measures of the non-bisected diagonal are given. Find AC.

(please see attached photo, thx)

Answers

The value of measure of length AC is,

⇒ AC = 8 units

We have to given that,

The area of the kite is,

A = 36 ft²,

And, the measures of the non-bisected diagonal are given.

Since, We know that,

Area of kite = d₁ × d₂ / 2

Where, d₁ and d₂ are diagonals of kite.

Hence, Substitute all the given values, we get;

⇒ 36 = (6 + 3) × AC / 2

⇒ 36 = 9 × AC / 2

⇒ AC = 36 x 2 / 9

⇒ AC = 8

Thus, The value of measure of length AC is,

⇒ AC = 8 units

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The length of AC in a kite with an area of 36 sq ft and a non-bisected diagonal measuring 6ft and 3ft is 8ft

The kite ABCD can be divided into two triangles: Triangle ABC and Triangle ACD

let us consider the midpoint of the diagonals to be point O

The area of a triangle is 1/2×b×h

For triangle ABC,

Area(ABC) = 1/2 × AC × BO

Area(ABC) = 1/2 × AC × 6

Area(ABC) = 3 × AC

For Triangle ACD,

Area(ACD) = 1/2 × AC × DO

Area(ACD) = 1/2 × AC × 3

Area(ACD) = 3/2 × AC

Area (ABCD) = Area(ABC) + Area(ACD)

36 = 3×AC + 3/2×AC

36 = 9/2 × AC

72 = 9 × AC

AC = 72/9

AC = 8ft

Therefore, The length of AC in a kite with an area of 36 sq ft and a non-bisected diagonal measuring 6ft and 3ft is 8ft.

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Sumit’s mother is 22 years younger than Sumit’s grandmother and 27 years older than
Sumit. The sum of their ages is 121 years. Find the present age of Sumit

Answers

Sumit's present age is 15 years.

Let's assume Sumit's age as x.

According to the given information, Sumit's mother is 27 years older than Sumit, so her age would be x + 27.

Sumit's grandmother is 22 years older than Sumit's mother, so her age would be (x + 27) + 22 = x + 49.

The sum of their ages is 121 years:

x + (x + 27) + (x + 49) = 121.

Now, let's solve this equation to find the value of x:

3x + 76 = 121,

3x = 121 - 76,

3x = 45,

x = 45 / 3,

x = 15.

Therefore, Sumit's present age is 15 years.

Sumit's mother's age can be calculated as x + 27 = 15 + 27 = 42 years.

Sumit's grandmother's age can be calculated as (x + 49) = 15 + 49 = 64 years.

To verify the answer, we can check if the sum of their ages is indeed 121 years:

15 + 42 + 64 = 121.

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1.(a) Calculate the interest rate per annum for a loan of N2,720.00 for 4 years and a repayment of N2,856.00 (b)(i) Make V the subject of the formula E = mv2 2 (ii) Find the value of v when m=2 and E= 64​

Answers

a) The interest rate per annum for the loan is 1.25%.

b) i) v is the subject of the formula E = mv^2 / 2 when expressed as v = √(2E / m).

ii) When m = 2 and E = 64, the value of v is 8.

a) To calculate the interest rate per annum, we can use the formula for simple interest:

Interest = Principal * Rate * Time

Given:

Principal (P) = N2,720.00

Repayment (A) = N2,856.00

Time (T) = 4 years

We need to find the rate (R).

Since the repayment amount includes both the principal and interest, we can rewrite the formula as:

Repayment = Principal + Interest

Rearranging the formula, we have:

Interest = Repayment - Principal

Now we can substitute the given values into the formula:

Interest = N2,856.00 - N2,720.00

Interest = N136.00

Substituting this interest value and the other known values into the original formula, we can solve for the rate:

N136.00 = N2,720.00 * R * 4

Dividing both sides by N2,720.00 * 4:

R = N136.00 / (N2,720.00 * 4)

R = 0.0125 or 1.25%

Therefore, the interest rate per annum for the loan is 1.25%.

b)(i) To make V the subject of the formula E = mv^2 / 2, we can rearrange the equation:

E = mv^2 / 2

Multiply both sides of the equation by 2:

2E = mv^2

Divide both sides by m:

2E / m = v^2

Take the square root of both sides:

√(2E / m) = v

Therefore, v is the subject of the formula E = mv^2 / 2 when expressed as v = √(2E / m).

(ii) Given that m = 2 and E = 64, we can substitute these values into the equation v = √(2E / m):

v = √(2 * 64 / 2)

v = √(64)

v = 8

Therefore, when m = 2 and E = 64, the value of v is 8.

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Evaluate the line integral along the path C given by x = 2t, y = 4t, where 0 ≤ t ≤ 1.
∫c(x + 3y²) dy

Answers

The value of line integral along path C is 76/3. To evaluate line integral along path C, given by x = 2t and y = 4t, where 0 ≤ t ≤ 1, we need to substitute these parameterizations into integrand, calculate the integral.

The line integral along the path C is given by:

∫c(x + 3y²) dy

Substituting the parameterizations x = 2t and y = 4t, where 0 ≤ t ≤ 1, into the integrand, we have:

∫c(x + 3y²) dy = ∫(2t + 3(4t)²) (4 dt)

Simplifying the expression inside the integral, we get:

∫(2t + 48t²) (4 dt)

Expanding and integrating term by term, we have:

∫(8t + 192t²) dt = ∫8t dt + ∫192t² dt

Evaluating each integral, we get:

= 4t² + 64t³/3 + C

Now, substituting the limits of integration t = 0 and t = 1, we can find the value of the line integral:

= (4(1)² + 64(1)³/3) - (4(0)² + 64(0)³/3)

= (4 + 64/3) - (0 + 0)

= 4 + 64/3

= 76/3

Therefore, the value of the line integral along the path C is 76/3.

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Which is greater: the area of a bubble whose radius is 7 cm or the total area of seven bubbles, each of which has a radius of 1 cm? explain.

Answers

To determine which is greater, we can calculate the area of each bubble and compare them.

The formula for the area of a circle is A = πr^2, where A is the area and r is the radius.

For the single bubble with a radius of 7 cm, the area would be:

A = π(7 cm)^2 = 153.94 cm^2

For each of the seven bubbles with a radius of 1 cm, the area would be:

A = π(1 cm)^2 = 3.14 cm^2

The total area of all seven bubbles would be:

Total area = 7 x 3.14 cm^2 = 21.98 cm^2

Comparing the two areas, we can see that the area of the single bubble with a radius of 7 cm is greater than the total area of the seven bubbles with a radius of 1 cm.

Therefore, the area of a bubble with a radius of 7 cm is greater than the total area of seven bubbles, each with a radius of 1 cm.

a helicopter hovers 500 feet above a small island. the figure shows that the angle of depression from the helicopter to point p is 37 degrees. how far off the coast, to the nearest foot is the island?

Answers

To the nearest foot, the distance from the helicopter to the island is approximately 664 feet.

To determine the distance from the helicopter to the island, we can use trigonometry and the concept of the angle of depression. Let's denote the distance from the helicopter to the island as "x".

From the information given, we know that the helicopter is hovering 500 feet above the island. This creates a right triangle, where the height of the triangle is 500 feet and the angle of depression is 37 degrees.

Using trigonometry, we can use the tangent function to find the value of "x". The tangent of an angle is defined as the ratio of the opposite side to the adjacent side.

In this case, the opposite side is the height of the triangle (500 feet), and the adjacent side is the distance from the helicopter to the island (x). Therefore, we can set up the equation:

tan(37 degrees) = 500 / x

To find the value of "x", we rearrange the equation:

x = 500 / tan(37 degrees)

Using a calculator, we can evaluate the right-hand side of the equation:

x ≈ 500 / 0.7536 ≈ 663.74 feet

Therefore, to the nearest foot, the distance from the helicopter to the island is approximately 664 feet.

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For a continuous random variable X, P26 sXs67)=0.21 and PX>67) = 0.18. Calculate the following probabilities. (Round your answers to 2 decimal places.) a. P(X

Answers

P(26 ≤ X ≤ 67) = 0.21P(X > 67) = 0.18We are to calculate:a. P(X < 26)Since X is a continuous random variable, we know that: P(a ≤ X ≤ b) = ∫f(x)dx where f(x) is the probability density function of X.To find P(X < 26),

we can use the complement rule:

P(X < 26) = 1 - P(X ≥ 26) = 1 - P(26 ≤ X ≤ 67) - P(X > 67)

We know that:

P(26 ≤ X ≤ 67) = 0.21P(X > 67) = 0.18

Therefore: P(X < 26) = 1 - P(26 ≤ X ≤ 67) - P(X > 67)= 1 - 0.21 - 0.18= 0.61 So,

P(X < 26) = 0.61 (rounded to 2 decimal places)

Therefore, the probability that X is less than 26 is 0.61.

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Linear Algebra

for a complex vector space, let x = (i, 1+i) and y = (3-i, i).

Which case is correct and why? Please advise.

Answers

The vectors x and y are not orthogonal, and case (ii) is correct: The vectors x and y are not orthogonal.

The expression for the dot product of complex vectors x and y with complex conjugates is given byx · y* = [ (i)(3-i) + (1+i)(i) ] = (3i - i² + i - 1) = (4i - 2)

When the dot product of x and y with complex conjugates is zero, the vectors are orthogonal.

Let's begin by computing the dot product of x and y with complex conjugates: (i, 1+i) · (3-i, i)*= (i)(3-i) + (1+i)(i)= 3i - i² + i + i= 4i - 1

Next, we check whether this dot product is zero or not.

If it is zero, then the given vectors are orthogonal.If 4i - 1 = 0, then 4i = 1.

Solving for i, we get:i = 1/4

Since the imaginary part of i is non-zero, we know that the dot product is not zero.

Therefore, the vectors x and y are not orthogonal, and case (ii) is correct: The vectors x and y are not orthogonal.

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Thomas bought 800 shares of stock in T.J Maxx (TIX) on November 30, 2020, paying $63.51 per share. On November 30, 2021, he received a dividend of $0.26 per share, and he sold his shares which had risen to $69.40 per share. Assume the SEC fee is $5.10 per $1,000,000 of principal, rounded up to the next cent. Find each of the following: a) Thomas's total cost for the stock if he made a $25 broker-assisted trade on 11/30/2020. b.) The amount received by Thomas if he made an automated phone sale of $5 on 11/30/2021. c.) Thomas's capital gain if he sold the stock on 11/30/2021. d.) The total dividend amount. e.) Thomas's total return on his one-year ownership of this stock.

Answers

a) Thomas's total cost for the stock is $50,812.  b) The amount received by Thomas from the automated phone sale is $55,377.80. c) Thomas's capital gain from selling the stock is $5,048. d) The total dividend amount received by Thomas is $208. e) Thomas's total return on his one-year ownership of the stock is 12.82%.

a) To calculate Thomas's total cost for the stock, we multiply the number of shares (800) by the price per share ($63.51) and add the broker-assisted trade fee ($25). The calculation is: Total cost = (800 * $63.51) + $25 = $50,812.

b) The amount received by Thomas from the automated phone sale can be calculated by multiplying the number of shares (800) by the selling price per share ($69.40) and subtracting the automated phone sale fee ($5). The calculation is: Amount received = (800 * $69.40) - $5 = $55,377.80.

c) Thomas's capital gain is the difference between the selling price per share ($69.40) and the purchase price per share ($63.51), multiplied by the number of shares (800). The calculation is: Capital gain = (800 * ($69.40 - $63.51)) = $5,048.

d) The total dividend amount received by Thomas is the dividend per share ($0.26) multiplied by the number of shares (800). The calculation is: Total dividend amount = 800 * $0.26 = $208.

e) Thomas's total return on his one-year ownership of the stock can be calculated using the formula: Total return = (Capital gain + Dividend amount) / Total cost * 100. Plugging in the values, we have: Total return = ($5,048 + $208) / $50,812 * 100 = 12.82%.

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Given the functions (z) = z³ - z² and g(z) = 3z - 2, find gofy fog.
Find the image of the vertical line x=1 under the function ƒ(z) = z².

Answers

The composition gofy fog is 9z⁶ - 6z⁵ + 3z⁴ - 3z³ + 6z² - 6z + 2. The image of the vertical line x=1 under ƒ(z) = z² is the line y = 1.

To find the composition gofy fog, we first evaluate fog by substituting the function g into f: fog(z) = f(g(z)). Using f(z) = z³ - z² and g(z) = 3z - 2, we get fog(z) = (3z - 2)³ - (3z - 2)². Expanding and simplifying, we obtain fog(z) = 9z⁶ - 6z⁵ + 3z⁴ - 3z³ + 6z² - 6z + 2.

For the image of the vertical line x = 1 under the function ƒ(z) = z², we substitute x = 1 into the function to find the corresponding y values. Since z = x + iy, where i is the imaginary unit, we have z = 1 + iy. Squaring z gives z² = (1 + iy)² = 1 + 2iy - y². As x = 1 remains constant, the resulting image is the line y = 1.

In summary, gofy fog is 9z⁶ - 6z⁵ + 3z⁴ - 3z³ + 6z² - 6z + 2, and the image of the vertical line x = 1 under the function ƒ(z) = z² is the line y = 1.

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Researchers have tested the effect of Omega-3 fatty acids found in fish and fish oil
supplements on cognitive performance. Two doses of Omega-3 supplements and
placebo was given to independent groups of subjects. Then became
the subjects asked to solve a set of mathematical problems, and
the researchers measured the time (in minutes).

Placebo 79 65 69 80 78 Low dose 59 60 71 74 68 High dose 42 59 41 50 40

a) Is there evidence to conclude that Omega 3 has an impact on time? Use
a significance level of 0.05 and assume that the populations are normally distributed and
has the same variance.

Answers

The p-value is less than 0.05, which means that we can reject the null hypothesis, there is sufficient evidence to conclude that Omega 3 has an impact on time.

How to explain the hypothesis

The null hypothesis is that there is no difference in the mean time to solve the mathematical problems between the three groups (placebo, low dose, and high dose). The alternative hypothesis is that there is a difference in the mean time to solve the mathematical problems between the three groups.

The p-value is less than 0.05, which means that we can reject the null hypothesis. Therefore, there is sufficient evidence to conclude that Omega 3 has an impact on time. Specifically, the high dose of Omega 3 appears to have a positive impact on time, as the mean time to solve the mathematical problems was significantly lower in the high dose group than in the placebo and low dose groups.

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Let R be the region in the first quadrant that is bounded by the curves y= =√x ₁ x=0 and y=2-x- Find the volume of the solid generated when the region R is revolved about the y -axis. Your solution must include a graph that shows a typical slice of the region for the method you use, and the result of revolving this slice about the axis of rotation.

Answers

To find the volume of the solid generated when the region R is revolved about the y-axis, we can use the method of cylindrical shells.

First, let's sketch the region R:

The region R is bounded by the curves y = √x, x = 0, and y = 2 - x.

By setting the two curves equal to each other, we can find the x-coordinate where they intersect:

√x = 2 - x

Squaring both sides, we get:

x = 4 - 4x + x^2

Rearranging the terms, we have:

x^2 + 5x - 4 = 0

Factorizing the quadratic equation, we get:

(x + 4)(x - 1) = 0

So the intersection points are x = -4 and x = 1. However, we are only interested in the region in the first quadrant, so we take x = 1 as the upper limit of integration.

Now, let's set up the integral to find the volume using cylindrical shells:

The radius of each cylindrical shell is x, and the height is the difference between the curves:

height = (2 - x) - √x

The differential volume element is given by:

dV = 2πx(2 - x - √x)dx

To find the total volume, we integrate this expression from x = 0 to x = 1:

V = ∫[0,1] 2πx(2 - x - √x)dx

Simplifying the integrand, we have:

V = 2π ∫[0,1] (2x - x^2 - x√x)dx

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Which of the following gives a probability that is determined based on the classical approach? When playing Monopoly, the probability of rolling a 7 on the next roll of the dice is determined to be 1/

Answers

There is only one possible outcome that can result in a 7: rolling a 1 and a 6 or rolling a 2 and a 5 or rolling a 3 and a 4 or rolling a 4 and a 3 or rolling a 5 and a 2 or rolling a 6 and a 1. As a result, the probability of rolling a 7 is 1/6.

The probability that is determined based on the classical approach when playing Monopoly is that the probability of rolling a 7 on the next roll of the dice is determined to be 1/6.The classical approach is a statistical method that assesses the likelihood of an event based on the possible number of outcomes.

It's used to predict future events by counting the number of possible outcomes of an event. For example, the probability of getting a head or tail when flipping a coin is 1/2.

When rolling a dice, there are six possible outcomes; each side of the dice has a number, therefore the probability of rolling a 7 is 1/6.Based on the classical approach, probabilities are calculated by dividing the number of favorable outcomes by the total number of outcomes.

Thus, for the given example, the probability of rolling a 7 is calculated by dividing the number of possible outcomes resulting in a 7 by the total number of possible outcomes.

In this case, there is only one possible outcome that can result in a 7: rolling a 1 and a 6 or rolling a 2 and a 5 or rolling a 3 and a 4 or rolling a 4 and a 3 or rolling a 5 and a 2 or rolling a 6 and a 1. As a result, the probability of rolling a 7 is 1/6.

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A client is receiving a volume of 10 mL over 2 min IV Push. How many mL will the client receive every 30 seconds? 19. The medication order reads: heparin 6,000 units IV via pump in 250 mL of D5W at 1,200 units/h. How many mL/h will the patient receive?

Answers

The client will receive 5 mL every 30 seconds during the 2-minute IV push. For the heparin medication order, the patient will receive 20 mL/hour.

In the first scenario, the client is receiving a volume of 10 mL over 2 minutes. To determine the amount the client will receive every 30 seconds, we divide the total volume (10 mL) by the total time (2 minutes) and then multiply it by the desired time interval (30 seconds). So, the client will receive [tex]\frac{10 mL}{2min} *\frac{30 s}{1 min} = 5 mL[/tex] every 30 seconds.

In the second scenario, the heparin medication order states that the patient will receive 6,000 units of heparin in 250 mL of D5W at a rate of 1,200 units per hour. To determine the mL/hour rate, we divide the total volume (250 mL) by the time interval (1 hour). Thus, the patient will receive [tex]\frac{250mL}{1 hour} = 250 mL/h[/tex].

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In
a state's pick 3 lottery game, you pay $1.39 to select a sequence
of three digits (from 0 to 9), such as 886. if you select the same
sequence of three digits that are drawn, you win and collect
$29
courses/83995/assignments/2176667 Section 5.1 Homework Due Monday by 11:59pm Points 8 Submitting an external tool 2022 Summer - Math 11 = Homework: Section 5.1 Homework Question 7, 5. Part 4 of 5 In a

Answers

The expected value of the game is -1.36. This means that on average, a player can expect to lose $1.36 per game.

The given problem states that in a state's Pick 3 lottery game, you pay $1.39 to select a sequence of three digits (from 0 to 9), such as 886.

If you select the same sequence of three digits that are drawn, you win and collect $29.

The question asks to find out the expected value of the game, so we need to compute the probability of winning and losing the game.

Let us denote the event of winning by W and the event of losing by L.

The probability of winning the game isP(W) = 1/1000

since there are 1000 possible sequences of three digits and only one will be the winning sequence.

The probability of losing the game is

P(L) = 999/1000

since there are 999 possible sequences of three digits that are not the winning sequence.

The cost of playing the game is 1.39, and the amount won is 29.

Therefore, the net profit from winning is 29 - 1.39 = 27.61.

We can now use the formula for the expected value of the game, which is

E(X) = P(W) × profit from winning + P(L) × profit from losing

(X) = (1/1000) × 27.61 + (999/1000) × (-1.39)E(X)

= 0.02761 - 1.38661E(X) = -1.359

Therefore, the expected value of the game is -1.36. This means that on average, a player can expect to lose $1.36 per game.

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Suppose that in a large metropolitan area, 90% of all households have a flat-screen television. Suppose you are interested in selecting a group of six households from this area. Let X be the number of households in a group of six from this area with a flat-screen television. Part a: Show that this problem satisfies the requirements to be a binomial distribution. Part b: For what proportion of groups will exactly four of the six households have a flat-screen television? Part c: For what proportion of groups will at most two of the households have a flat-screen television? Part d: What is the expected number of households with flat-screen television?

Answers

Therefore, the degree of the resulting polynomial is m + n when two polynomials of degree m and n are multiplied together.

What is polynomial?

A polynomial is a mathematical expression consisting of variables and coefficients, which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents. Polynomials can have one or more variables and can be of different degrees, which is the highest power of the variable in the polynomial.

Here,

When two polynomials are multiplied, the degree of the resulting polynomial is the sum of the degrees of the original polynomials. In other words, if the degree of the first polynomial is m and the degree of the second polynomial is n, then the degree of their product is m + n.

This can be understood by looking at the product of two terms in each polynomial. Each term in the first polynomial will multiply each term in the second polynomial, so the degree of the resulting term will be the sum of the degrees of the two terms. Since each term in each polynomial has a degree equal to the degree of the polynomial itself, the degree of the resulting term will be the sum of the degrees of the two polynomials, which is m + n.

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Find the indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.) ∫(√x + 4/x - 3eˣ) dx
Consider the following initial-value problem. f'(x) = 9x² - 4x, f(1) = 8 Integrate the function f'(x). (Use C for the constant of integration.) ∫ f'(x) dx = Find the value of C using the condition f(1) = 8. C= State the function f(x) found by solving the given initial-value problem. f(x) =

Answers

The indefinite integral of √x + 4/x - 3eˣ with respect to x is (√x^3)/3 + 4ln|x| - 3eˣ + C, where C is the constant of integration.

To find the indefinite integral of the given function, we can integrate each term separately.

∫√x dx:

Using the power rule of integration, we add 1 to the exponent and divide by the new exponent:

∫√x dx = (√x^3)/3

∫(4/x) dx:

This term can be simplified as 4∫(1/x) dx, which equals 4ln|x|.

∫(-3eˣ) dx:

The integral of eˣ is eˣ, so the integral of -3eˣ is -3eˣ.

Adding up the integrals of each term, we have (√x^3)/3 + 4ln|x| - 3eˣ + C, where C represents the constant of integration.

For the second part of the question, we are given the initial-value problem f'(x) = 9x² - 4x and f(1) = 8.

To find the function f(x), we need to integrate f'(x) and then use the given condition to determine the constant of integration.

∫ f'(x) dx:

Using the power rule of integration, we integrate each term of f'(x):

∫(9x² - 4x) dx = 3x³ - 2x² + C

Now, we apply the initial condition f(1) = 8. Plugging in x = 1 into the function f(x), we have:

f(1) = 3(1)³ - 2(1)² + C

8 = 3 - 2 + C

8 = 1 + C

Solving for C, we find C = 7.

Therefore, the function f(x) that solves the given initial-value problem is:

f(x) = 3x³ - 2x² + 7.

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What is the 20th term of the expansion (c-d)³⁵?

Answers

The 20th term of the expansion (c-d)³⁵ can be determined using the binomial theorem. The binomial theorem states that the coefficients of the terms in the expansion of (a+b)ⁿ can be found using the formula:

C(n, r) * a^(n-r) * b^r

where C(n, r) represents the binomial coefficient, given by n! / (r!(n-r)!). In the case of (c-d)³⁵, the exponent of c decreases by one in each term, while the exponent of d increases by one.

To find the 20th term, we need to find the value of r that satisfies the equation C(35, r) = 20. Solving this equation, we find that r = 15.

Substituting r = 15 into the formula, we have:

C(35, 15) * c^(35-15) * (-d)^15

Simplifying, we get:

C(35, 15) * c^20 * d^15

Therefore, the 20th term of the expansion is given by C(35, 15) * c^20 * d^15.

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A box contains six 25-watt light bulbs, nine 60-watt light bulbs, and five 100- watt light bulbs. What is the probability of randomly selecting a 60 watt light bulb?

Answers

The problem involves calculating the probability of randomly selecting a 60-watt light bulb from a box containing different wattage bulbs. The box contains six 25-watt light bulbs, nine 60-watt light bulbs, and five 100-watt light bulbs.

To calculate the probability of randomly selecting a 60-watt light bulb, we need to consider the total number of light bulbs and the number of 60-watt light bulbs in the box.
The total number of light bulbs in the box is the sum of the individual counts for each wattage: 6 (25-watt bulbs) + 9 (60-watt bulbs) + 5 (100-watt bulbs) = 20 bulbs.
The probability of randomly selecting a 60-watt light bulb can be calculated by dividing the number of 60-watt bulbs by the total number of bulbs:
Probability = Number of 60-watt bulbs / Total number of bulbs
Probability = 9 / 20
Calculating this expression, we find that the probability of randomly selecting a 60-watt light bulb is 0.45, or 45% when expressed as a percentage.
In conclusion, the probability of randomly selecting a 60-watt light bulb from the given box is 0.45 or 45%. This means that there is a 45% chance of picking a 60-watt light bulb if a bulb is chosen at random from the box.


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Find the domain and range of the function without graphing. Explain how you find the answer.
y= 1/3 (√x-4)

Answers

The domain of the function y = 1/3 (√x - 4) consists of all the values that x can take without causing any undefined or problematic behavior in the function.

In this case, the square root function (√x) requires its argument (x) to be non-negative, since the square root of a negative number is undefined in the real number system. Additionally, the function has a denominator of 3, which means that it cannot be equal to zero. Therefore, the domain of the function is all x-values greater than or equal to 4, expressed as [4, ∞).

The range of the function y = 1/3 (√x - 4) represents all the possible output values of y for the corresponding x-values in the domain. Since the function involves a square root, the values inside the square root must be greater than or equal to zero to avoid imaginary results. Therefore, the minimum value that the square root can take is 0, which occurs when x = 4. As x increases, the square root term (√x - 4) also increases, but since it is divided by 3, the overall function y decreases. As a result, the range of the function is all real numbers less than or equal to 0, expressed as (-∞, 0].

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A population of values has a normal distribution with j = 72.5 and a = 65.2. If a random sample of size = 19 is selected a. Find the probability that a single randomly selected value is less than 45.6. Round your answer to four decimals PIX < 45.6) D. Find the probability that a sample of size n = 19 ts randomly selected with a mean less than 45.6. Round your answer to four decimals. PIM 45.6)

Answers

The probability that a single randomly selected value is less than 45.6 from the given population is approximately 0.3409. The probability that a sample of size n = 19, randomly selected with a mean less than 45.6 from the given population, is approximately 0.0247.

To find the probability that a single randomly selected value is less than 45.6 from a population with a mean (μ) of 72.5 and a standard deviation (σ) of 65.2, we can use the standard normal distribution.

Standardizing the value 45.6 using the formula: z = (x - μ) / σ, where x is the value, μ is the mean, and σ is the standard deviation.

z = (45.6 - 72.5) / 65.2 = -0.411

Use a standard normal distribution table or calculator to find the probability associated with the standardized value.

The probability P(X < 45.6) corresponds to the area under the standard normal curve to the left of z = -0.411.

Using the standard normal distribution table or calculator, we find that the probability P(Z < -0.411) is approximately 0.3409 (rounded to four decimals).

Therefore, the probability that a single randomly selected value is less than 45.6 from the given population is approximately 0.3409.

To find the probability that a sample of size n = 19, randomly selected from the population with a mean less than 45.6, we need to consider the sampling distribution of the sample mean.

Assuming that the population follows a normal distribution, the sampling distribution of the sample mean will also be approximately normal.

The mean of the sampling distribution is equal to the population mean (μ) and the standard deviation is equal to the population standard deviation (σ) divided by the square root of the sample size (n).

Using the formula for the standard deviation of the sampling distribution of the sample mean (σ/√n), we can calculate the standardized value:

Standardizing the value 45.6 using the formula: z = (x - μ) / (σ/√n)

z = (45.6 - 72.5) / (65.2/√19) ≈ -1.970

Finding the probability P(Z < -1.970) using the standard normal distribution table or calculator.

Using the standard normal distribution table or calculator, we find that the probability P(Z < -1.970) is approximately 0.0247 (rounded to four decimals).

Therefore, the probability that a sample of size n = 19, randomly selected with a mean less than 45.6 from the given population, is approximately 0.0247.

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1. If the position function for a moving particle is s(t) =< -8 sin ().- ()+4, 6t²/3 +t-3>, where -cos distances are in meters and r is in seconds, find the speed of the particle when = 6. Give the simplified exact result or round accurately to 4 decimal places, and include the units with your answer. (14)

Answers

Therefore, the speed of the particle when θ = 6 is 38.61 m/s.

Given the position function for a moving particle is

s(t) = <-8 sin(θ)-cos(θ)

, 6t²/3 +t-3>

where -cos distances are in meters and r is in seconds. To find: The speed of the particle when θ = 6.Explanation:The position vector is given by

r(t) = <-8 sin(θ)-cos(θ), 6t²/3 +t-3>

differentiating wrt timer

v(t) = <8 cos(θ) + sin(θ)

4t + 1>

The speed of the particle is given by the magnitude of

rv(t), i.e.,v(t) = |rv(t)|=√[8 cos(θ) + sin(θ)]² + (4t + 1)²

Substituting

θ = 6,

we get

v(6) = √[8 cos(6) + sin(6)]² + (4(6) + 1)²v(6) = √(12.2027)² + (25)²v(6) = √(1492.0589)v(6) = 38.61 m/s (rounded to 4 decimal places)

Therefore, the speed of the particle when θ = 6 is 38.61 m/s.

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How much money should be deposited today in an account that earns 5% compounded semiannually so that it will accumulate to $8000 in three years?
The amount of money that should be deposited is $ __ (Round up to the nearest cent.)

Answers

the amount of money that should be deposited today, rounded up to the nearest cent, is $6,896.55.

To calculate the amount of money that should be deposited today, we can use the formula for the future value of an investment:

A = P * (1 + r/n)^(n*t)

where:

A is the future value ($8000 in this case)

P is the principal amount (the amount to be deposited)

r is the interest rate (5% or 0.05)

n is the number of compounding periods per year (2 for semiannually)

t is the number of years (3 years)

We need to solve for P, so we rearrange the formula:

P = A / (1 + r/n)^(n*t)

Substituting the given values:

P = $8000 / (1 + 0.05/2)^(2*3)

P = $8000 / (1 + 0.025)^6

P = $8000 / (1.025)^6

P = $8000 / 1.160375

P ≈ $6,896.55

Therefore, the amount of money that should be deposited today, rounded up to the nearest cent, is $6,896.55.

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Coupon payments are made semi-annually with an annual interest rate of 6%. If the face value of the bond is $1,000 calculate the value of the bond today which has a required rate of return of 7.5%. (7 marks) 30 In general, which strategy is better suited to buildbrand equity?Group of answer choicesPenetration pricingSkimming pricingLoss-leader pricingNone of the above as brand equity is based onadv which of the following should be consumed at intervals throughout the day? a. vitamin-rich foodsb. fat-containing foodsc. mineral-rich foodsd. carbohydrate-containing foods Solar Car Limited Liability Company ("Solar Car") is a joint venture of Tesla Limited Liability Company ("Tesla") and ViFa Limited Liability Company. Tesla owns 60% of Solar Cars shares. After successfully developing the worlds first solar-powered car for general use, Solar Cars board of management ("Board") has determined that it shall now attempt to move into a new product line: flying cars. Solar Cars Board believes that if they can develop a feasible flying car design, they may be able to then leverage their solar technology to create not only the worlds first flying car for everyday use, but the worlds first solar powered flying car. Solar Cars Board decides to create a separate, wholly-owned subsidiary to develop the flying car. The subsidiary is called Jet Car Limited Liability Company ("Jet Car").In connection with their research and development into the flying car, Jet Cars engineers acquire substantial knowledge about the production of jet packs for individual use. Jet Cars board mentions to Elun Misk, now Jet Cars Chief Engineering Officer, that they are considering bringing a line of personal jet backs to market based on the intellectual property developed by Jet Cars engineers. They tell Elun Misk that they will not be in a position to start pursuing the jetpack business until mid-2022 at the earliest. In the interim, Elun Misk resigns from his role at Jet Car and registers a new business, Rocketman Limited Liability Company. Elun Misk uses engineering data that he took with him when he left Jet Car to quickly finalize a prototype personal jet pack, which he hopes to start selling by early 2023.Questions:Is it legal to establish Jet Car?Is it possible for Elun Misk to register a new business - Roketman Co. Ltd?Is it legal when Elun Misk use previous companys data for his new business? Consider the experiment of flipping a balanced coin three times independently. Let X= Number of heads - Number of tails. Find the following: a) Distribution probability b) Mean c) Standard deviation d Adam Smith launched a repair business Softworks in April 1. The company had the following transactions during April.a. Adam Smith invested followings in the businessi. Cash $65,000ii. Equipment $5,750iii. Computer equipment $30,000b. Softworks purchased land for $22,000 for construction of office building by cash payment $5,000 and a long-term note payable $17,000.c. Softworks purchased a movable building with $34,500 cash and moved it onto the land.d. Two years pre-paid insurance $5,000 paid in cashe. Services provided for cash $4,600f. Additional computer equipment $4,500 by paying $800 cash and a long-termg. Services provided on credit $4,250h. Purchased $950 office equipment on credit.i. Services provided for $10,200 on credit.j. Unpaid rent $580 due within 30 days.k. Softworks received 50% of the cash from the transaction i.l. Wages paid $1,800.m. Paid $950 cash to settle the obligation created in transaction h.n. Computer equipment maintenance cost $608o. Cash dividend paid $6,230.p. Another $1,800 cash for wagesq. Advertisement expense $750 paid in cashRequiredPrepare general journal entries, general ledgers, and trial balance to record the above transactions Reflecting on the budgets and budget concepts that youve learned related to the different budgets the personnel budget, the operating budget, and the capital budget in your own words provide a brief description of each.Differentiate the uniqueness of each; what is their purpose and how are they used?What is the purpose of an annual or monthly budget? In sociometer theory, the sociometer is aGroup of answer choicesspecific part of our brain that detects how social others are feeling at any given time.tool that measures ones level of social skill, and uses that to predict social success in the workplace.mechanism that helps us detect acceptance versus rejection and translate that perception into high- versus low self-esteem.measure of self-esteem that is traditionally used in most research. Find f(-2) for the function f(x) = 3x^2 2x + 7A. -13B. -1C. 1D. 23