5. If it takes 50 seconds to lift 10 Newtons of books to a height of 7 meters, calculate the power
required

Answer:

the correct  is D

Explanation:

In the calorimetry exercises, if there are no losses, we assume that all the heat lost by one body is absorbed by the other, but if there are losses

         Q_ {yielded} = Q_ {absent} + Q_ {lost}

Since energy cannot be created or destroyed, they only ask to change, therefore the term of the absorbed heat must decrease, consequently the final temperature of the system is lower when there is loss of energy.

When checking the answers, the correct one is D

Answer:

Option C.

Impulse = mass × change in velocity

Explanation:

Impulse is defined by the following the following formula:

Impulse = force (F) × time (t)

Impulse = Ft

From Newton's second law of motion,

Force = change in momentum /time

Cross multiply

Force × time = change in momentum

Recall:

Impulse = Force × time

Thus,

Impulse = change in momentum

Recall:

Momentum = mass x velocity

Momentum = mv

Chang in momentum = mass × change in velocity

Change in momentum = mΔv

Thus,

Impulse = change in momentum

Impulse = mass × change in velocity

Answer:

t = 7.8 seconds

Explanation:

Given that,

The initial speed of the car, u = 28 m/s

Acceleration of the car, a = 3.6 m/s²

We need to find the time taken for the police car to come to Stop. When it stops, its final speed is equal to 0. So, using the equation of kinematics to find it i.e.

[tex]v=u+at\\\\0=28+3.6t\\\\t=\dfrac{28}{3.6}\\\\t=7.8\ s[/tex]

So, the required time is 7.8 seconds.

10m/s East

Explanation:

p=mv

m1v1 = m2v

p = m1v1

2000kg*(20m/s) = 40000kg*m/s

Add the two masses together for m2

p = m2v2

40000kg*m/s = 4000kg * v2

v2 = 10m/s

Answer:

40m/s

Explanation:

Answer:

8.9875517923(14)×109 kg⋅m3⋅s−2⋅C−2

Explanation:

Exact number is 8.9875517923(14)×109 kg⋅m3⋅s−2⋅C−2

Answer:

Magnetic domains

Explanation:

Because when the electrons spin around the necleus of an atom, it causes the atom to become a tiny magnet

anser: 27s PoP

Explanation:

1 is the force, so the equal antiforce will be 1. weight of car divided by force from engine

34 pop / s = 129

27pOp

Answer:

your

answer is

12.004

Answer:

d

Explanation:

rzp-yyib-oiv

plèase jóin ón góógle mèèt

Answer:

a. a problem

Explanation:

The engineering process begins by defining a problem and completing background research on the problem.

molecular weights are written in the picture.

CH4<NH3<H2O<Cl2

Answer:

true , true, and I'm not sure about the last one!

Explanation:

Answer: 11 m/s

Explanation: velocity = distance /time = 55 m /5.0 s

Answer:40km/h

Explanation:

Answer:

0.225 s^-1

Explanation:

Please mark as brainliest

The angular velocity of the tire is 11.12 rad/s.

Angular velocity: This is the change in angular direction per time. The S.I unit is rad/s.

⇒ Formula:

⇒ Where:

⇒ Make ω the subject of the equation

From the question,

⇒ Given:

⇒ Substitute these values into equation 2

Hence, The angular velocity of the tire is 11.12 rad/s

Learn more about angular velocity here: https://brainly.com/question/20432894

Answer:

I'm pretty sure its the 2nd one.

Explanation:

Given that,

We need to find the orbital speed and period of a satellite in orbit [tex]1.44\times 10^2\ m[/tex] above Earth.

The formula for the orbital speed is given by :

[tex]v=\sqrt{\dfrac{GM}{r}} \\\\v=\sqrt{\dfrac{6.67\times 10^{-11}\times5.97\times 10^{24}}{(1.44\times 10^2+6.38\times 10^6)^2}} \\\\v=3.12\ m/s[/tex]

Let T be the time period of the satellite. It can b solved using Kepler's third law i.e.

[tex]T^2=\dfrac{4\pi^2}{GM}r^3\\\\T^2=\dfrac{4\pi^2\times (1.44\times 10^2)^3}{6.67\times 10^{-11}\times 5.97\times 10^{24}}\\\\T=5.44\times 10^{-4}\ s[/tex]

Hence, this is the required solution.

The orbital speed of the satellite is 3.13 m/s and the period of the satellite in orbit is 5.44 × 10⁻⁴ s.

The orbital speed of an astronomical object in a gravitational system is the speed at which it revolves around the central point or the speed required to keep an artificial or natural satellite in orbit.

It can be expressed by using the formula:

[tex]\mathbf{v = \sqrt{\dfrac{GM}{r}}}[/tex]

where;

[tex]\mathbf{v = \sqrt{\dfrac{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}{(1.44 \times 10^2 + 6.38 \times 10^6)^2}}}[/tex]

v = 3.13 m/s

In planetary motion, Kepler's third law states that the square of the period of a planet varies directly proportional to the cubes of the planets' mean distances (d).

The period of the satellite can be estimated by using Kepler's third law. It can be computed by using the formula:

[tex]\mathbf{T^2 =\dfrac{4 \pi^2}{GM}\times r^3}[/tex]

[tex]\mathbf{T^2 =\dfrac{4 \pi^2}{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}\times (1.44 \times 10^2)^3}[/tex]

[tex]\mathbf{T^2 =2.96037718\times 10^{-7}}[/tex]

[tex]\mathbf{T =5.44 \times 10^{-4} \ s}[/tex]

Learn more about orbital speed here:

https://brainly.com/question/855117

Answer:

The Cell Membrane is found in both plant and animal cells.

Explanation:

Chloroplast, Large Vacuole and Cell Wall are all found in plant cells.

Answer:

it would be 83% in a fatal crash.

Answer:

a)     v₀ = 2.5 m / s,   heading south.

b)  W = 1,219 10⁵ J

Explanation:

a) For this exercise we can use the conservation of the moment, we create a system formed by all the 4 cars, in this case when the last one separates the forces are intense and the moment is conserved

initial instant. Before separation

        p₀ = M v₀

final instant. When uncoupling the last car

        p_f = 3m v₁ + m v₂

where they indicate that the speed of the wagons is v₁ = 2.00 m / s and the speed of the last wagon is v₂ = 4.00 m / s

the total mass is M = 4m

how the moment is preserved

           p₀ = p_f

         4m v₀ = 3m v₁ + mv₂

         v₀ = ¾ v₁ + v₂ / 4

let's calculate

           v₀ = ¾ 2 + ¼ 4

           v₀ = 2.5 m / s

heading south.

b) work is equal to the change in kinetic energy

              W = ΔK = K_f -K_o

              W = ½ m v_f² - ½ m v₀²

               W = ½ m (v_f² -v₀²)

               W = ½ 2.50 10⁴ (4² - 2.5²2)

               W = 1,219 10⁵ J

Answer:

[tex]69.06\ \text{N/m}[/tex]

Explanation:

m = Mass of bungee jumper = 55 kg

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

h = Height at the bottom = 40 m

k = Spring constant

x = Displacement of bungee cord = 25 m

Applying the principle of conservation of energy to the system we have

[tex]mgh=\dfrac{1}{2}kx^2\\\Rightarrow k=\dfrac{2mgh}{x^2}\\\Rightarrow k=\dfrac{2\times 55\times 9.81\times 40}{25^2}\\\Rightarrow k=69.06\ \text{N/m}[/tex]

The spring constant of the bungee cord is [tex]69.06\ \text{N/m}[/tex].

Id say its the last option of the fourth option

Explanation:

Answer:  

1:increase the number of coils, increase the strength of the magnet

2:increase the speed of the magnet

3: increasing the time used to power up an electromagnet

Explanation:

1). Increasing the number of turns of wire in the coil – By increasing the amount of individual conductors cutting through the magnetic field, the amount of induced emf produced will be the sum of all the individual loops of the coil, so if there are 20 turns in the coil there will be 20 times more induced emf than in one piece of wire.

2). Increasing the speed of the relative motion between the coil and the magnet – If the same coil of wire passed through the same magnetic field but its speed or velocity is increased, the wire will cut the lines of flux at a faster rate so more induced emf would be produced.

3). Increasing the strength of the magnetic field – If the same coil of wire is moved at the same speed through a stronger magnetic field, there will be more emf produced because there are more lines of force to cut.

Answer:

10,000 N

Explanation:

Using Newton's Second Law of Motion, Force = Mass*Acceleration.

Plugin 2500 kg for the mass and 4 m/s^2 for the acceleration.

Force = 2500 kg*4 m/s^2 = 10000 Newtons

(SI unit of force is Newtons)

Answer:

Explanation:

B. Central Nervous System

Solution :

Given :

Weight = 4 lb

Stretched of a spring in  equilibrium,Δ = 2 ft

a). We know that

F = kΔ

4 = k x 2

k = 2 lb/ft

∴ Stiffness of the spring is, k = 2 lb/ft

Motion is critically damped.

[tex]$\epsilon = 1$[/tex]

[tex]$\epsilon=\frac{C}{C_c} = 1$[/tex]

[tex]$C=C_c[/tex]

[tex]$C=C_c=\sqrt{4k_m}[/tex]

[tex]$C=\sqrt{4 \times 2 \times \left(\frac{4}{32.174}\right)}[/tex]

C = 0.99729 lb.s/ft.

b). Displacement

   [tex]$y(t)=y_0 \sin (\omega t)$[/tex]

[tex]$\dot{y}(t)= y_0 \omega \cos (\omega t)$[/tex]

[tex]$[\dot{y}(t)]_{mon}= y_0 \omega $[/tex]

Initial displacement = 6 inches

    [tex]$y_0 = 0.5 \ ft , \ \ \ \dot y (t) = 3 \ ft/sec$[/tex]

  [tex]$\Rightarrow 3=0.5 \times \omega$[/tex]

 [tex]$\Rightarrow \omega = 6$[/tex]

Therefore, displacement :

    [tex]$y(t)=y_0 \sin (\omega t)$[/tex]

   [tex]$y(t)=0.5 \sin (6 t)$[/tex]

Answer:

B radiation

Explanation:

every type of transmitted waves are radioactive in a way.

Answer: D. When both objects reach the same temperature.

Explanation: When will heat flow between the objects stop? Heat will always flow from the warmer object to the colder object. The heat transfer will stop when the two objects are at the same temperature and reach thermal equilibrium.

Answer: Heat will always flow from the warmer object to the colder object. The heat transfer will stop when the two objects are at the same temperature and reach thermal equilibrium.

so the answer to your question is c

Explanation:

Answer:

7i, 5j, 0k

Explanation:

Add up the two vectors.

Add

i+i       1+6  = 7i

j+j       2+3 = 5j

k+k    -2+2 = 0k

therefore A+B = (7i, 5j, 0k)

Answer:

Explanation:

V = I R

V = 0.0418 * 30

V = 1.254

this battery seems dead  :P

Answer:

Explanation:

Let's just assume that the battery has no internal  resistance. If we get an absurd answer, we'll come back and look at that assumption.

E = I * R

I = 41.8/1000 amps = 0.0418

R = 30.0 ohms

E = 0.0418 * 30

E = 1.254 volts. This is an OK answer. The battery is a little old.