BitTorrent, a P2P protocol for file distribution, depends on a centralized resource allocation mechanism through which peers are able to maximize their download rates.
True or False?

Answer:

.cn does Not belong the rest of them do belong

Answer:

4 days

Explanation:

Given - Ram and Hari can finish a piece of work in 6 days and 12 days

             respectively.

To find - In how many days will they finish it working together

Proof -

As given,

Ram and Hari can finish a piece of work in 6 days and 12 days respectively.

⇒1 day work of Ram done in = [tex]\frac{1}{6}[/tex]

   1 day work of Hari done in = [tex]\frac{1}{12}[/tex]

If they work together,

1 day work of both together done in = [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{12}[/tex] = [tex]\frac{2 + 1}{12} = \frac{3}{12}[/tex] = [tex]\frac{1}{4}[/tex]

As we know Work is inversely proportional to efficiency

And efficiency = Person's 1 day work

As we have ,

1 day work of both together done in =  [tex]\frac{1}{4}[/tex]

⇒ Total work done in 4 days if they work together.

Answer:

That is not a question.

Explanation:

Answer:

B, To use a consistent design throughout your presentation

Explanation:

Templates basically enforce overall consistency by having a pre-determined structure and layout. All documents made using a template will match its layout exactly. When it comes to your document's content, Word's Styles tool is a great way to maintain consistent formatting.

Answer:

The equivalent program in C++:

#include<iostream>

#include <sstream>

using namespace std;

int main(){

   string Score, Rank;

   cout<<"Enter student score and class rank: ";

   cin>>Score>>Rank;

   int testScore = 0, classRank = 0;

   stringstream sstream(Score);

   sstream>>testScore;

   stringstream tream(Rank);

   tream>>classRank;

   if (testScore >= 90){

       if(classRank >=25){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 80){

       if(classRank >=50){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 70){

       if(classRank >=75){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else{cout<<"Reject";}

   return 0;

}

Explanation:

This declares Score and Rank as string variables

   string Score, Rank;

This prompts the user for score and class rank

   cout<<"Enter student score and class rank: ";

This gets the user input

   cin>>Score>>Rank;

This declarees testScore and classRank as integer; and also initializes them to 0

   int testScore = 0, classRank = 0;

The following converts string Score to integer testScore

   stringstream sstream(Score);

   sstream>>testScore;

The following converts string Rank to integer classRank

   stringstream tream(Rank);

   tream>>classRank;

The following conditions implement the conditions as given in the question.    

If testScore >= 90

   if (testScore >= 90){

If classRank >=25

       if(classRank >=25){cout<<"Accept";}

If otherwise

       else{cout<<"Reject";}

   } ---

If testScore >= 80

   else if(testScore >= 80){

If classRank >=50

       if(classRank >=50){cout<<"Accept";}

If otherwise

       else{cout<<"Reject";}

   }

If testScore >= 70

   else if(testScore >= 70){

If classRank >=75

       if(classRank >=75){cout<<"Accept";}

If otherwise

       else{cout<<"Reject";}

   }

For testScore less than 70

   else{cout<<"Reject";}

Answer:

In Python:

tuition = 7180

year = 2019

rate = 0.035

for i in range(2019,2027):

   print(str(year)+": "+str(round(tuition,2)))

   tuition = tuition * (1 + rate)

   year = year + 1

Explanation:

This initializes the tuition to 7180

tuition = 7180

This initializes the year to 2019

year = 2019

This initializes the rate to 3.5%

rate = 0.035

This iterates through years 2019 to 2026

for i in range(2019,2027):

This prints the year and tuition

   print(str(year)+": "+str(round(tuition,2)))

This calculates the tuition

   tuition = tuition * (1 + rate)

This increments year by 1

   year = year + 1

Answer:

The capability of having an integrated 2D-3D environment allows you to work with your data, maps, and scenes alongside one another. You can quickly switch between maps and scenes as well as link them together for a synchronized viewing experience.

Explanation:

Answer:

B: to customize the 3-D map for different displays with the same data

Explanation:

EDGE2021

common commands such as bold, underline, copy, and paste. Also for cells format worksheet something like that...

The one that is a part of the Cells group on the home tab is insert. The correct option is 1.

In Microsoft Word, the Home tab is the default tab. The relevant commands are divided into five groups: Clipboard, Font, Paragraph, Styles, and Editing.

It enables you to edit document settings such as font size, bullet placement, style selection, and many other standard features.

The most utilised document controls can be found under the Home Tab; using these controls, you can alter the text's font and size, paragraph and line spacing, copy and paste, and organisational structure. The Home Tab is divided into four separate sections.

Insert is the one that is a member of the Cells group on the home tab.

Thus, the correct option is 1.

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Your question seems incomplete, the missing options are:

i. Insert

ii. Delete

iii Format

iv. All of these​

Answer:

Answered below

Explanation:

#program is written in Java

class RoomDimension{

double length;

double width;

RoomDimension (double length, double width){

this.length = length;

this.width = width;

}

public double roomArea ( ){

return length * width;

}

}

class RoomCarpet{

RoomDimension rd;

double price;

RoomCarpet ( RoomDimension rd, double price){

this.rd = rd;

this.price = price;

}

public double totalCost( ){

double area = rd.roomArea();

return area * price;

}

}

Answer:

a job or profession.

Answer:

An occupation is something that someone does for a living.

Explanation:

An occupation is something that someone does for a living and it can also be called a job or profession. For example, my occupation is a fast food crew member.

Answer:

hot components or sharp edges of computer is an example of a mechanical hazard

Answer:

1. append

2. array

3. elament

4. To the end of an array.

5. Changes all negative numbers to positives.

6. To do number calculations.

7. an elament

8. Assigning

9. zebra

10. len(tests)

Explanation:

got 100% on the test

Answer:

The answer here is False.

Explanation:

Encryption protects the data and not access to data.

In some cases, the hacker may not necessarily be trying to access or decrypt the data. They may prevent one from accessing it by placing a Ransomeware virus on it.

What a Ransomeware virus would do is to prevent the legal and rightful owner from accessing such data (whether encrypted or not) until their demands are met.

In many cases, they would ask for monies or cryptocurrencies.

Another way hackers attempt to get encrypted files is to try to get the decryption keys instead. The best practice against this is to keep decryption keys manually or in a password manager. Another way to protect very sensitive information is to have sensitive systems isolated from the internet.

Cheers

Answer:

In C++:

#include <iostream>

#include <string>

#include <sstream>

using namespace std;

int main(){

   string lname, fname,stringnum;    int num; string login, pwd;

   cout<<"Last Name: ";    cin>>lname;

   cout<<"First Name: ";    cin>>fname;

   cout<<"Four-digit integer: ";    cin>>num;

   stringnum = to_string(num).substr(0,4);

   stringstream geek(stringnum);    geek>>num;

   num = num%100;

   pwd = to_string(num);

   if(lname.length()<5){ login = lname+fname.substr(0,1);    }

   else{ login = lname.substr(0,5)+fname.substr(0,1);    }

   cout<<"Login Name: "<<login<<endl;

   cout<<"Password: "<<pwd<<endl;

   return 0;

}

Explanation:

This declares all necessary variables

   string lname, fname,stringnum;    int num;     string login, pwd;

This prompts the user for last name

   cout<<"Last Name: ";    cin>>lname;

This prompts the user for first name

   cout<<"First Name: ";    cin>>fname;

This prompts the user for a four digit integer

   cout<<"Four-digit integer: ";    cin>>num;

This converts the input number to string and gets only the first four integer

   stringnum = to_string(num).substr(0,4);

This converts the string back to an integer

   stringstream geek(stringnum);    geek>>num;

This gets the last two of the four digit integer

   num = num%100;

This gets the password of the user

  pwd = to_string(num);

This gets the login name of the user.

This is executed if the length of the first name is less than 5

   if(lname.length()<5){ login = lname+fname.substr(0,1);    }

This is executed if otherwise

   else{ login = lname.substr(0,5)+fname.substr(0,1);    }

This prints the login name

   cout<<"Login Name: "<<login<<endl;

This prints the password

   cout<<"Password: "<<pwd<<endl;

Answer:

B, D, and E.

Explanation:

Answer:

B,D,E

Explanation:

Edg 2021 just took test

A set of run-length encodings would not be a challenge because of the predictability of the challenges.

We can arrive at this answer because:

When this is approached within a game, it promotes simple, repetitive, and predictable stages, where the player can easily know where the challenges will present themselves and how to overcome them, in addition to getting software that is simple to handle.

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Answer:

A cell reference refers to a cell or a range of cells on a worksheet and can be used in a formula so that Microsoft Office Excel can find the values or data that you want that formula to calculate. In one or several formulas, you can use a cell reference to refer to: ... Data contained in different areas of a worksheet.

I hope it's helpful!

Answer:What is the sandwich tech

Explanation:

Answer:

for me personally, it would help if the items were rearranged with like items, for example: snow, sleet, rain, and hail would go together.

so the list should look something like this:

    weather conditions

    fruits

   sports

hope i helped <3 have a nice day

Answer:

weather(rssh) fruit(sabo) sport(fstr)

Explanation:

Answer:

The pseudocode is as follows:

Input Qty

Discount = 0%

If Qty>= 100:

       Discount = 15%

 Print Discount

Explanation:

This gets the quantity of bags

Input Qty  

This initializes the discount percentage to 0%

Discount = 0%  

This checks if the quantity is greater than or equal to 100.

If Qty>= 100:

If true, the discount percentage is set to 15%

       Discount = 15%

This prints the calculated discount percentage

Print Discount

See attachment for flowchart

Answer:

Follows are the code to the given question:

class BankAccount //defining a class BankAccount

{

 int balance;//defining integer variable balance  

 String name;//defining String variable name

 BankAccount()//defining default constructor

 {

 }

  BankAccount(int balance, String name)//defining parameterized constructor that accepts two parameters  

  {

     this.balance = balance;//use this to hold parameter value

     this.name = name;//use this to hold parameter value

  }

}

public class Main//defining Main class

{

 public static void main(String[] asr)//main method  

 {

  BankAccount obv = new BankAccount(1969, "Mustang");//creating class object and pass value in parameter

   System.out.println("Your name is: " + obv.name + " and " +"Your balance is: "+ obv.balance);//print value with message

 }

}

Output:

Your name is: Mustang and Your balance is: 1969

Explanation:

In this code a class "BankAccount" is declared, that  defines the two variable "name and balance" as a integer and string, and in the next step a parameterized constructor is declared, that uses this keyword to hold value.

In the main class the main method is declared and inside the method class object is created that accepts parameter value and use the print method to print its value.

Answer:

// In the number.cpp file;

#include "Number.h"

#include <iostream>

using namespace std;

Number::Number(int number)

{

   num = number;

}

void Number::SetNum(int number)

{

   num = number;

}

int Number::GetNum()

{

   return num;

}

ostream &operator<<(ostream &out, const Number &n)

{

   out << "The value is " << n.num << endl;

   return out;

}

// in the main.cpp file;

#include "Number.cpp"

#include <iostream>

using namespace std;

int main()

{

   int input;

   cin >> input;

   Number num = Number(input);

   cout << num;  

   return 0;

}

Explanation:

The main function in the main.cpp file prompts the user for the integer value to be displayed. The Number file contains defined functions and methods of the number class to set, get and display the "num" variable.

Answer:

12

Explanation:

and it is also an error

Answer:

def create_3_copies(initial_list):

   another_list = []

   for i in range(3):

       for x in initial_list:

           another_list.append(x)

   return another_list

initial_list = []

while True:

   value = input("Enter a value: ")

   if value == "exit":

       break

   initial_list.append(value)

for x in create_3_copies(initial_list):

    print(x, end=" ")

Explanation:

Create a function that takes initial_list as parameter. Inside the function:

Create an empty list called another_list

Create a nested for loop. The outer loop iterates 3 times (Since we need to add every value 3 times). The inner loop iterates through the another_list and adds each value to the another_list.

When the loops are done, return the another_list

In the main:

Create an empty list named initial_list

Create an indefinite while loop. Inside the loop, ask the user to enter a value. If the value equals "exit", stop the loop. Otherwise, add the value to the initial_list

Create another for loop that calls the function we created passing the initial list as a parameter and iterates through the values that it returns. Inside the loop, print each value

Answer:

Cell

Explanation:

A cell is the intersection of a row and a column—in other words, where a row and column meet.

To insert the row, Click the Insert command on the Home tab. The new row will appear above the selected row.

A column and a row's intersection form a rectangular space known as a cell. The Cell Name or Reference, which is discovered by adding the Column Letter and the Row Number, is used to identify cells.

A row can be inserted either above or below where the cursor is. Then click the Table Layout tab after selecting the area where you wish to add a row. Click Above or Below under Rows & Columns. A row can be inserted either above or below where the cursor is.

Then click the Table Layout tab after selecting the area where you wish to add a row. Click Above or Below under Rows & Columns.

Therefore, it can be concluded that the raw appears in the home tab in the section of Row.

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Answer:

The algorithm is as follows :

1. Record Current Position, Final Destination

2. While Current Position is not Final Destination, repeat the following:

2.1 If destination location is up then:

  2.1.1 If an obstacle is directly above you then:

     2.1.1.1 Look for alternate position (left, right, down)

     2.1.1.2 If alternate position is found then

        2.1.1.2.1 Move there

        2.1.1.2.2 Record Current Position

     2.1.1.3 If no alternate position is found then

        2.1.1.3.1 Call for help

        2.1.1.3.2 End

  2.1.2 If no obstacle is directly above you then:

     2.1.2.1 Move up

     2.1.2.1 Record Current Position

2.2 If destination location is down then:

  2.2.1 If an obstacle is directly below you then:

     2.2.1.1 Look for alternate position (left, right, up)

     2.2.1.2 If alternate position is found then

        2.1.1.2.1 Move there

        2.2.1.2.2 Record Current Position

     2.2.1.3 If no alternate position is found then

        2.2.1.3.1 Call for help

        2.2.1.3.2 End

  2.2.2 If no obstacle is directly below you then:

     2.2.2.1 Move down

     2.1.2.1 Record Current Position

2.3 If destination location is right then:

  2.3.1 If an obstacle is directly by your right then:

     2.3.1.1 Look for alternate position (down, up, left)

     2.3.1.2 If alternate position is found then

        2.3.1.2.1 Move there

        2.3.1.2.2 Record Current Position

     2.3.1.3 If no alternate position is found then

        2.3.1.3.1 Call for help

        2.3.1.3.2 End

  2.3.2 If no obstacle is directly by your right then:

     2.3.2.1 Move right

     2.3.2.1 Record Current Position

2.4 If destination location is left then:

  2.4.1 If an obstacle is directly by your left then:

     2.4.1.1 Look for alternate position (down, up, right)

     2.4.1.2 If alternate position is found then

        2.4.1.2.1 Move there

        2.4.1.2.2 Record Current Position

     2.4.1.3 If no alternate position is found then

        2.4.1.3.1 Call for help

        2.4.1.3.2 End

  2.4.2 If no obstacle is directly by your left then:

     2.4.2.1 Move left

     2.4.2.1 Record Current Position

Explanation:

The algorithm is straight forward.

All it does is to check for available position and move into the position if there is any available.

It keeps checking and moving until an obstacle prevents it from moving.