Attempting to both study and watch television is an example of divided attention.
T
F

Answer:

Potential Energy to Kenetic Energy

Explanation:

When holding a ball in the air, the ball has potential energy. Once you drop the ball, the ball gains Kenetic Energy

Answer:

I don't rlly know anyone in harry Potter so I simp for........MYSELF :)

Answer:

Either Draco Malfoy or Harry Potter

Explanation:

UvU

Answer:

400 N

Explanation:

From the question,

F = kmm'/r²........................ Equation 1

Where F = gravitation force, m and m' = mass 1 and mass 2 respectively, r = distance between the masses.

Given; F = 800 N

Substitute these values into equation 1

800 = kmm'/r².............. Equation 2

If the distance is doubled (2r), and one of the mass is doubled (2m), The new force is

F' = k(2m)(m')/(2r)²

F' = 2kmm'/4r²

F' = kmm'/2r²................. Equation 3

Comparing equation 2 and equation 3

F' = F/2............................ Equation 4

Substitute the value of F into equation 4

F' = 800/2

F' = 400 N

Answer:

B: Relay

Explanation:

Out of all the options, the only device that relies upon the magnetic field of an electric current.

The principle relies upon the principle of electro magnetic attraction whereby when the circuit detects a faulty current, it makes the electromagnetic field to become energized which in turn produces the temporary magnetic field. This magnetic field then moves the relay armature which is used in opening or closing the connections.

Answer:

Option C. The force between them would be 4 times larger than with the

initial masses.

Explanation:

To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:

From:

F = GMₐM₆/ r²

Keeping G/r² constant, we have

F₁ = MₐM₆

Let the initial mass of both objects to be m

F₁ = MₐM₆

F₁ = m × m

F₁ = m²

Next, let the masses of both objects doubles i.e 2m

F₂ = MₐM₆

F₂ = 2m × 2m

F₂ = 4m²

Compare the initial and final force

Initial force (F₁) = m²

Final (F₂) = 4m²

F₂ / F₁ = 4m² / m²

F₂ / F₁ = 4

F₂ = 4F₁ = 4m²

From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the

initial masses.

Thus, option C gives the correct answer to the question.

Answer:

KE=1/2mv*

Explanation:

write the numbers inorder to the symbols

Ans use this formula to solve the problem

Answer:

Angle Angle Similarity Postulate

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 8 \ m/s}}[/tex]

Explanation:

Speed is equal to distance over time.

[tex]s=\frac{d}{t}[/tex]

The distance is 400 meters and the time is 50 seconds.

[tex]d= 400 \ m \\t= 50 \ s[/tex]

Substitute the values into the formula.

[tex]s=\frac { 400 \ m }{ 50 \ s}[/tex]

Divide.

[tex]s= 8 \ m/s[/tex]

The speed of the car is 8 meters per second.

Answer:

623.6N

Explanation:

There are 2.2 pounds in one kilogram, so you must divide 140 lb by 2.2 to convert the units to kilograms.

140/2.2 = 63.6 kg

The gravitational force also known as weight would equal mass times acceleration due to gravity.

Fg = (63.6 kg)(9.8 m/s^2) = 623.6N

Answer:

noice.

Explanation:

thanks for points.... idrk what im supposed to do

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yeah same.

Answer:

Momentum is equal to mass for velocity (p1=mv)

But momentum is also equal to Force for time of impact (p1=Ft). Hence the impact force is inversely proportional to the fall time and directly proportional to the mass and fall velocity : F=mv/t^2 or F=p1/t

If he slows down, v diminishes and F diminishes

Hence correct Answer is C

Answer:

Solution given:

force=20N

distance travelled=6m

work done=force *displacement=20*6=120joule

Work done=120joule.

Work done=Force×Displacement

[tex]\\ \rm\longmapsto Work\:done=20(6)[/tex]

[tex]\\ \rm\longmapsto Work\:done=120J[/tex]

Answer:

0.25 m/s squared

Explanation:

Mass of the body (m)= 24kg

Applied force on the body(F)= 6N

Acceleration of the body (a)= ?

Solution

F = ma

a = F/m

a = 6N/24kg

a = 0.25m/s^2

Answer: The acceleration of the body is 0.25m/s^2

I hope this helps

Answer:

[tex]\boxed {\boxed {\sf a=\frac {1}{3} \ m/s^2}}[/tex]

Explanation:

Force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass is 24 kilograms and the force is 8 Newtons. Let's convert the Newtons to make the problem easier.

Substitute the known values into the formula.

[tex]8 \ kg*m/s^2= (24 \ kg )*a[/tex]

Since we are solving for a, we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides by 24 kilograms.

[tex]\frac {8 \ kg*m/s^2}{24 \ kg}= \frac{(24 \ kg )*a}{24 \ kg}[/tex]

The kilograms will cancel, hence our earlier unit conversion.

[tex]\frac {8 \ m/s^2}{24 }= a[/tex]

[tex]\frac {1}{3} \ m/s^2=a[/tex]

The acceleration is 1/3 meter per square second.

Answer:

bottle opener and door knob

Explanation:

Answer:

bottle opener

door handle

365.25 or 366.25 in a leap year

Answer:

500 Joules

Explanation:

W(work)= force * distance

w = 100*5

W= 500

Answer:

The weight of the object X is approximately 3.262 N (Acting downwards)

The weight of the object Y is approximately 8.733 N (Acting downwards)

Explanation:

The question can be answered based on the principle of equilibrium of forces  

The given parameters are;

The weight of Z = 12 N (Acting downwards)

The weight of the pulleys = Negligible

From the diagram;

The tension in the in the string attached to object Z = The weight of object Z = 12 N

The tension in the in the string attached to object X = The weight of the object X  

The tension in the in the string attached to object Y = The weight of the object Y

Given that the forces are in equilibrium, we have;

The sum of vertical forces acting at a point, [tex]\Sigma F_y[/tex] = 0

Therefore;

[tex]T_{1y} + T_{2y} + T_{3y} = 0[/tex]

[tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex]

Where;

[tex]T_{1y}[/tex]  = The weight of object Z = 12 N

[tex]T_{1y}[/tex]  = 12 N

[tex]T_{2y}[/tex] = The vertical component of tension, T₂ = T₂ × sin(24°)

∴  [tex]T_{2y}[/tex] = T₂ × sin(156°)

Similarly;

[tex]T_{3y}[/tex] = T₃ × sin(50°)

From [tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex], and [tex]T_{1y}[/tex]  = 12 N, we have;

12 N = -(T₂ × sin(156°) + T₃ × sin(50°))...(1)

Given that the forces are in equilibrium, we also have that the sum of vertical forces acting at a point, ∑Fₓ = 0

Therefore at point B, we have;

T₁ₓ + T₂ₓ + T₃ₓ = 0

The tension force, T₁, only has a vertical component, therefore;

∴ T₁ₓ = 0

∴ T₂ₓ + T₃ₓ = 0

T₂ₓ = -T₃ₓ

T₂ₓ =  T₂ × cos(156°)

T₃ₓ = T₃ × cos(50°)

From T₂ₓ = -T₃ₓ, we have;

T₂ × cos(156°) = - T₃ × cos(50°)...(2)

Making T₃ the subject of equation (1) and (2) gives;

Making T₃ the subject of equation in equation (1), we get;

12 = -(T₂ × sin(156°) + T₃ × sin(50°))

∴ T₃ = (-12 - T₂ × sin(156°))/(sin(50°))

Making T₃ the subject of equation in equation (2), we get;

T₂ × cos(156°) = - T₃ × cos(50°)

∴ T₃ = T₂ × cos(156°)/(-cos(50°))

Equating both values of T₃ gives;

(-12 - T₂ × sin(156°))/(sin(50°)) = T₂ × cos(156°)/(-cos(50°))

-12/(sin(50°)) = T₂ × cos(156°)/(-cos(50°)) + T₂ × sin(156°)/(sin(50°))

∴ T₂ = -12/(sin(50°))/((cos(156°)/(-cos(50°)) + sin(156°)/(sin(50°))) ≈ -8.02429905283

∴ T₂ ≈ -8.02 N

From T₃ = T₂ × cos(156°)/(-cos(50°)), we have;

T₃ = -8.02× cos(156°)/(-cos(50°)) = -11.3982199717

∴ T₃ ≈ -11.4 N

The weight of the object X = -T₂ × sin(156°)

∴ The weight of the object X ≈ -(-8.02 × sin(156°)) = 3.262 N

The weight of the object X ≈ 3.262 N (Acting downwards)

The weight of the object Y = -(T₃ × sin(50°))

∴ The weight of the object Y = -(-11.4 × sin(50°)) ≈ 8.733 N

The weight of the object Y ≈ 8.733 N (Acting downwards)

Answer:

7.14285714286

Explanation:

Carbon is the element modeled

Answer:

5 Components of Physical Fitness

Cardiovascular Endurance.

Muscular Strength.

Muscular endurance.

Flexibility.

Body Composition.

Answer:

6 m/s

Explanation:

p=mv

p=3 kg.m/s

m=0.5 kg

rearrange and substitute to find v:

(3)=(0.5)v

v=3/0.5

v=6 m/s

Answer:

Force = 125 Newton

Explanation:

Given the following data;

Pressure = 50 pa

Area = 2.5 m²

To find the force applied;

Force = pressure * area

Substituting into the formula, we have;

Force = 50 * 2.5

Force = 125 Newton