At The Fencing Center, 60% of the fencers use the foil as their main weapon. We randomly survey 21 fencers at The Fencing Center. We are interested in the numbers that do not use the foil as their main weapon.
Part (a) In words, define the Random Variable X.
the number of fencers that do not use the foil as their main weaponthe different types of weapons the number of fencers at The Fencing Centerthe number of fencers that do use the foil as their main weapon
Part (b) List the values that X may take on.
X = 0, 1, 2, . . ., 60X = 1, 2, 3, . . ., 21 X = 0, 1, 2, . . ., 21X = 1, 2, 3, . . ., 60
Part (c) Give the distribution of X.
X ~
,
Part (d) How many fencers are expected to not use the foil as their main weapon? (Round your answer to the nearest whole number.)
fencers
Part (e) Find the probability that eleven do not use the foil as their main weapon. (Round your answer to four decimal places.)
Part (f) Based on numerical values, would you be surprised if all 21 did not use foil as their main weapon?
Yes. The probability of all 21 fencers not using the foil as their main weapon is small (less than 1%).No. The probability of all 21 fencers not using the foil as their main weapon is large (more than 10%).

Answers

Answer 1

Answer:

A.) the number of fencers that do not use the foil as their main weapon

B.) X : 0, 1, 2, 3,..., 21

C.) X ~ p(X) ; 21 ~ 0.4

D.) 21 ~ 0.4

E.) 0.0895

F.) Yes. The probability of all 21 fencers not using the foil as their main weapon is small (less than 1%)

Step-by-step explanation:

A.) since it is reported that 60% of fencers use the foil as their main weapon ;

The random variable (x) : number of fencers that do not use foil as their main weapon ;

( 100% - 60%) = (1 - 0.6) = 0.4

B.) values that X may take on :

Sample size = 21 ;

X : 0, 1, 2,..., 21

The distribution of X

X ~ B ; X ~ p(X) ; 21 ~ 0.4

Part (d) How many fencers are expected to not use the foil as their main weapon?

X * p(x)

21 * 0.4

= 8.4

= 8 (nearest whole number)

Part (e) Find the probability that eleven do not use the foil as their main weapon.

P(x = 11)

Using the binomial probability relation :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

P(x = 11) = 21C11 * 0.4^11 * 0.6^10

P(x = 11) = 0.0895

Part (f) Based on numerical values, would you be surprised if all 21 did not use foil as their main weapon?

P(x = 21) = 21C21 * 0.4^21 * 0.6^0

P(x = 21) = < 0.00001 ( approximately 0)

Hence, based on this very low value which is almost equal to 0 ; it will be surprising if all 21 do not use foil as their main weapon


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Answer:

$30.40

Step-by-step explanation:

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Matching Equivalent Expressions
Quick
Check
Match each addition expression on the left with an equivalent expression on the right.
15 + 9
2(3 + 2)
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Answer:

15+9 is 3(5+3)

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Which inequality describes the graph?

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Answer:

I think it is B. -3x < - 30, but I might be wrong.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

since you see that the line goes from 10 and does not include it it would be x<10

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so A

[tex](4+\sqrt{-7}) (3+\sqrt{-7})[/tex]

Answers

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Which family lives the farthest from Disneyland?
Family A:
Family D
y = 95 - 55
Distance
50
Family B:
40
Family B lives 120 miles from Disneyland
and drives 60 mph.
30
Family
20
Hours
Distance
from
Disneyland
SO
10
0
1.5
0
0.2 0.4 0.6 0.8
112 Time (hours)
Family A
O Family B
O Family C
Family D

Answers

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2: x= 3y + 4, y eR
I think that’s right.-.

rob is saving to buy a new mp3 player. For every $15 he earns babysitting, he saves $7. On Saaturday, Rob erened $30 babysitting. How much money did he save. If he erend $30, he saved how many

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Answer:

thanks for the points

Step-by-step explanation:

In parts (a)−(d) below, either use the information given to determine the distribution of the random variable, or show that the information given is not sufficient by describing at least two different random variables that satisfy the given condition. (a) X is a random variable such that MX(t) = e 6t 2 when |t| < 2. (b) Y is a random variable such that MY (t) = 2 2−t for t < 0.5. (c) Z is a random variable such that MZ(t) = [infinity] for t ≥ 5. (d) W is a random variable such that MW (2)

Answers

Answer:

a.) X  ≈ N (0, 12)

b.) Y ≈  exp(2)

c.) The given distribution is not defined.

d.) Not a standard form of any distribution .

Step-by-step explanation:

Given - In parts (a)−(d) below, either use the information given to determine

            the distribution of the random variable, or show that the information

            given is not sufficient by describing at least two different random

            variables that satisfy the given condition.

To find - (a) X is a random variable such that Mₓ(t) = [tex]e^{6t^{2} }[/tex] when |t| < 2.

              (b) Y is a random variable such that  [tex]M_{Y}[/tex](t) = [tex]\frac{2}{2 - t}[/tex] for t < 0.5.

              (c) Z is a random variable such that [tex]M_{Z}[/tex](t) = ∞ for t ≥ 5.

              (d) W is a random variable such that [tex]M_{W}[/tex](2) = 2

Proof -

a.)

As we know that the moment generating function of normal distribution is given by

Mₓ(t) = [tex]e^{ut + \frac{1}{2}t^{2} \sigma^{2}}[/tex]

Now,

Mₓ(t) = [tex]e^{6t^{2} }[/tex]

       = [tex]e^{0(t) + \frac{12}{2} t^{2} }[/tex]

⇒μ = 0, σ = 12

Nd it is represented by

X  ≈ N (0, 12)

b.)

Moment generating function of exponential function is given by

[tex]M_{Y}[/tex](t) = [tex]( 1 - \frac{t}{\theta})^{-1}[/tex]

Now,

 [tex]M_{Y}[/tex](t) = [tex]\frac{2}{2 - t}[/tex] for t < 0.5.

          = [tex]\frac{1}{\frac{2 - t}{2} }[/tex]

          = [tex]\frac{1}{1 - \frac{t}{2} }[/tex]

          = [tex]( 1 - \frac{t}{2} )^{-1}[/tex]

And it is represented by

Y ≈  exp(2)

c.)

Z is a random variable such that [tex]M_{Z}[/tex](t) = ∞ for t ≥ 5.

The given distribution is undefined.

d.)

[tex]M_{W}[/tex](2) = E([tex]e^{2w}[/tex] )

           = [tex]\int\limits^{-\infty}_{\infty} {e^{2w} f(w) } \, dw[/tex]

          = 2

It is not the standard form of any distribution.


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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

A group of campers walked 4 2/3 miles along a hiking trail.

Distance = 4 2/3 miles

Another group of campers walked 1/4 of that distance with the first group before turning off onto another trail.

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How many miles did the two groups of campers walk with one another ?

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1 / 4 * 14 / 3

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Answers

This may be more complicated than it looks but here are the odd numbers before nine:

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--- × ------
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--------
60

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Answers

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I=PRT

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

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substitute y = 6 - x in equation (II)

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Answers

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Step-by-step explanation:

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