At Kennedy High School, the probability of a student playing in the band is 0. 15. The probability of a student playing in the band and playing on the football team is 0. 3. Given that a student at Kennedy plays in the band, what is the probability that they play on the football team?

Answer:

B

Step-by-step explanation:

Lisa's first step is to distribute, so you have to distribute all numbers.

(3+6x)-2(x+1)+5

3(1+2x)-2)x+1)+5

Hope this helps! :)

The minimum sample size which is need to to create the given confidence interval is equal to 467.

Sample size n

z = z-score for the desired confidence level

From attached table,

For 85% confidence level, which corresponds to a z-score of 1.44.

Maximum error or margin of error E = 0.06

Population standard deviation σ = 0.9

Minimum sample size required to construct a 85% confidence interval with an error of no more than 0.06,

Use the formula,

n = (z / E)^2 × σ^2

Plugging in the values, we get,

⇒ n = (1.44 / 0.06)^2 × 0.9^2

⇒ n = 466.56

Rounding up to the next integer, we get a minimum sample size of 467.

Therefore, the minimum sample size required to construct a 85% confidence interval with an error of no more than 0.06 is 467.

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Answer:

90

Step-by-step explanation:

a) It is verified that the situation is binomial

b. Probability of exactly coining 4 times is 1.83 × 10⁻³

c. Probability of winning atleast 3 times is 0.0234

d. Mean number of wins is 0.555

The total number of outcomes per toss is 6×6×6=216

a) Number of trails n = 20

Probability of win P = 6/216 = 1/36

Probability of lost Q = 1 - P

= 1 - 1/36

= 35/36

The outcome has two possibilities with P = 1/36, Q = 35/36  and with n = 20 times. Hence, it is binomial.

(B) Probability of exactly coining 4 times

[tex]P= C^{20}_{4} P^4Q^{16}[/tex]

= 4845 × (1/36)⁴ × (35/36)¹⁶

= 1.83 × 10⁻³

(C) Probability of winning atleast 3 times

[tex]P= 1-C^{20}_{0} P^0Q^{20}-C^{20}_{1} P^1Q^{19}-C^{20}_{2} P^2Q^{18}[/tex]

= 1 - 1 × (1/36)⁰ × (35/36)²⁰ - 20 × (1/36)¹ × (35/36)¹⁹ - 190 × (1/36)² × (35/36)¹⁸

= 1 - 0.5692 - 0.3252 - 0. 0882

= 0.0234

(D) Mean number of wins = nP

= 20 × (1/36)

= 0.555

a) It is verified that the situation is binomial

b. Probability of exactly coining 4 times is 1.83 × 10⁻³

c. Probability of winning atleast 3 times is 0.0234

d. Mean number of wins is 0.555.

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To the nearest dollar, the business initially invested approximately $3,449 in 1991.

To determine the initial investment in 1991, we can use the formula F = P(1 + R/100)^T, where F is the final amount, P is the initial investment amount, R is the annual interest rate, and T is the time in years.

In this case, F = $4,000 (the amount in the account at the end of 1996), R = 3% (the annual interest rate), and T = 5 years (1996 - 1991). We need to solve for P, the initial investment amount.

First, let's rewrite the equation: P = F / (1 + R/100)^T

Now, we can plug in the known values: P = 4000 / (1 + 3/100)^5

Next, we calculate the denominator: (1 + 0.03)^5 = 1.159274

Then, we divide the final amount by the denominator to find the initial investment: P = 4000 / 1.159274

Lastly, rounding to the nearest dollar, we get: P ≈ $3,449

So, the business initially invested approximately $3,449 in 1991.

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There are 39 red blocks out of 65 total blocks.

To solve this problem, we need to find the total number of blocks in each repeating pattern. The pattern is three red blocks followed by two blue blocks. So in each pattern, there are five blocks total.

To find the number of red blocks in 65 total blocks, we need to figure out how many times the pattern repeats. We can do this by dividing the total number of blocks (65) by the number of blocks in each pattern (5):

65 ÷ 5 = 13

So the pattern repeats 13 times.

In each pattern, there are three red blocks. So to find the total number of red blocks, we need to multiply the number of red blocks in each pattern (3) by the number of times the pattern repeats (13):

3 x 13 = 39

Therefore, there are 39 red blocks out of 65 total blocks.

The correct answer is option B.

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The equation of the circle graphed is given as follows:

(x + 1)² + (y + 3)² = 36.

The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

The radius of a circle represents the distance between the center of the circle and a point on the circumference of the circle.

The coordinates of the center of the circle are given as follows:

(-1, -3).

The radius of the circle is given as follows:

r = 6 units.

Then the equation of the circle is given as follows:

(x + 1)² + (y + 3)² = 36.

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1. The radius of the cylinder is  7. 05 cm

2. The length of the cylinder is  15, 384 meters

3. The radius of the big cylinder is 5. 64 cm

The formula for the volume of a cylinder is expressed as;

V = πr²h

Such that;

1. We have that volume = 2500 cm³

Height = 16cm

Substitute the values, we have;

2500 = π × r² × 16

Divide both sides by 16

r² = 49. 76

Find the square root

r = 7. 05 cm

2. Volume = 20000 cm³/100 = 200 meters

Radius = diameter/2 = 13/2 = 6.5cm = 0. 065 m

Substitute the values

200/0. 013 = h

Divide the values

h = 15, 384 meters

3. Volume = πr²h

Volume = 3.14 × 3.5² × 13

Volume = 500. 045 cm²

Then, substitute the values

500. 045 = 3.14 × r² × 5

r² = 31. 85

find the square root

r = 5. 64 cm

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Answer:

1.03x 10^{10}

Step-by-step explanation:

No explanation, simple calculator calculation does the job.

176, 264. your welcome!

Statement #3 is incorrect. To correct the statement:

The box plot does not provide information on the number of days of data collected.

The box plot, also known as a box-and-whisker plot, is a graphical representation of the distribution of a dataset. It displays information about the median, quartiles, and possible outliers.

However, the box plot itself does not directly provide information on the number of days of data collected.

The main components of a box plot include:

Median: This is the line inside the box that represents the middle value of the dataset. It divides the dataset into two equal halves, with 50% of the data falling below the median and 50% above it.

Quartiles: The box in the plot represents the interquartile range (IQR) of the data. The lower edge of the box corresponds to the first quartile (Q1), which is the 25th percentile. The upper edge of the box corresponds to the third quartile (Q3), which is the 75th percentile. The IQR represents the range of the middle 50% of the data.

Whiskers: These are the lines extending from the box. Typically, the whiskers extend to the smallest and largest observations within a certain range, often 1.5 times the IQR. Values outside this range are considered potential outliers and are represented as individual points beyond the whiskers.

The box plot can provide valuable information about the spread, skewness, and potential outliers in a dataset. However, it does not directly convey information about the number of days of data collected. To determine the number of days, one would need to refer to the raw data or other accompanying information.

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"The probability that the first freshman to arrive will be seated at a round table is (5/13)."

To calculate the probability, we need to determine the total number of seats and the number of seats at round tables.

There are 8 rectangular tables with 6 chairs each, so the total number of seats at rectangular tables is 8 * 6 = 48.

There are 5 round tables with 4 chairs each, so the total number of seats at round tables is 5 * 4 = 20.

The total number of seats in the community center is 48 + 20 = 68.

The probability of the first freshman being seated at a round table is the number of seats at round tables (20) divided by the total number of seats (68), which gives us 20/68 = 5/17.

Therefore, the correct answer is option C: 5/17.

In conclusion, the probability that the first freshman to arrive will be seated at a round table is 5/17. This is obtained by dividing the number of seats at round tables by the total number of seats in the community center.

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The features of function gif g(x) = f(x + 4) + 8 is vertical asymptote of r = -4.

Since they enable us to convert an exponential equation into a logarithmic equation and vice versa, logarithmic functions are employed to solve equations involving exponents. They are also used in a variety of disciplines, including science, finance, and engineering.

Given equation:

g(x) = f(x + 4) + 8.

f(x) → f(x + 4)

Horizontal translation less 4 unit.

(x, y) → (x - y), y

f(x, y) + 8

Vertical translation up 4 unit.

(x, y) → (x, y + d)

f(x)

Vertical Asymptote x = 0,

f(x + 4) + 8

Vertical Asymptote x+ 4 = 0

x = -4

Therefore, the features of function gif g(x) = f(x + 4) + 8 is vertical asymptote of r = -4.

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The product of matrices C and D is:

[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]

The best answer is option b.

A matrix (plural matrices) is a set of numbers arranged in rows and columns so as to form a rectangular array.

The number of rows of a matrix can be determined by counting from top to bottom and the number of columns can be determined by counting from left to right.

The product (multiplication) of matrices C and D is:

CD = C * D

[tex]CD = \left[\begin{array}{ccc}2\\9\\4\end{array}\right] * \left[\begin{array}{ccc}-3&2&-1\\\end{array}\right][/tex]

To get the product, multiply each row by the column. That is:

2 * (-3) = -6

9 * 2 = 18

4 * (-1) = -4

[tex]CD = \left[\begin{array}{ccc}-6&18&-4\\\end{array}\right][/tex]

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Let's start by using algebra to represent the relationships between the dimensions of the box:

So the dimensions of the box are: height = h, width = 2h, length = 3h.

Now let's find the volume of the box:

Since we know that each chocolate rests in a cube with a side length of 1 inch, the volume of each chocolate is [tex]1^3 = 1[/tex] cubic inch. So the total volume of all 48 chocolates is 48 cubic inches.

Therefore, we can set up an equation to solve for h:

  [tex]48 = (6h^3) / (1 cubic inch/chocolate)[/tex]

[tex]48 = 6h^3[/tex]

[tex]8 = h^3[/tex]

   h = 2

So the height of the box is 2 inches, the width is 4 inches (since it is 2 times the height), and the length is 6 inches (since it is 1.5 times the width).

To check our work, we can calculate the volume of the box:

   Volume = height x width x length

   Volume = 2 x 4 x 6

   Volume = 48 cubic inches

This matches the total volume of all  48 chocolates, so we can be confident in our answer.

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The main types of markets are:

So, the correct answer is "consumer" and "industrial".

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Answer:

a + s = 21.7

7a = 6s - 0.8

Step-by-step explanation:

I just used pattern recognition in my head and stuff i dont know how to explain

The base area of the pyramid is 5 units squared.

The pyramid has a volume of 20 cubic units and the height of the pyramid is 4 units.

Therefore, the area of the base can be calculated as follows:

Hence,

volume of the pyramid = base area × height of the prism

20 = base area × 4

Therefore,

base area of the pyramid = 20 / 4

base area of the pyramid = 5 units squared.

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The system of equation is 7.71 feet, under the condition the area of a rug is 108 square feet and the length it it’s diagonal is 14 feet.

Now to solve this problem, we can use the formula for the area of a rectangle which is A = L x W . Therefore, we can write the equation 108 = L x W

Now the length of the diagonal is 14 feet. We can use this information to write another equation using the Pythagorean theorem which states that for any right triangle with legs of length a and  b  and hypotenuse of length c ,
a² + b² = c²
Since a rectangle is made up of two right triangles, we can use this theorem to find the length and width of the rectangle.

Let us assume the length of the rug L and the width of the rug  W

L²+ W² = 14²

We have two equations with two unknowns

108 = L x W
L² + W² = 14²

We can solve for one variable in terms of another using substitution. From the first equation,

W = 108 / L

Substituting this into the second equation gives:


L² + (108 / L)² = 14²
L² - 196L² + 11664 = 0


This is a quadratic equation in terms of  L². We can solve for L²  


L² = (196 ± √(196² - 4 x 11664)) / 2
L² = (196 ± √(38416)) / 2
L² = (196 ± 196) / 2


Taking the positive root gives:

L² = 196

So:

L = √(196) = 14

Substituting this back into one of our original equations gives:

W = 108 / L
= 108 / 14
≈ 7.71

Therefore, the length of the rug is 14 feet and its width is approximately 7.71 feet.
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None of the inequalities is true.

Explain inequalities

Inequalities are mathematical expressions that compare two quantities or values using inequality symbols, such as "<" (less than), ">" (greater than), "<=" (less than or equal to), ">=" (greater than or equal to), or "!=" (not equal to). They represent relationships where one quantity is larger, smaller, or not equal to the other, and can be solved using algebraic manipulation and logical reasoning.

According to the given information

Since 115 is an integer, we can see that it cannot be strictly between any two consecutive integers.

A: 8 < 115 < 9 is not true because 115 is not less than 9.

B: 9 < 115 < 10 is not true because 115 is not less than 10.

C: 10 < 115 < 11 is not true because 115 is not less than 11.

D: 11 < 115 < 12 is not true because 115 is not less than 12.

Therefore, none of the given inequalities is true.

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The surface area of the pyramid is 72 + 486√3 metres.

The pyramid above is an hexagonal pyramid. The surface area of the hexagonal pyramid can be found as follows:

surface area of a hexagonal pyramid = ph / 2 + B

where

Therefore,

Base area = 1 / 2pa

where

Base area = 1 / 2 × (18 × 6) × 9√3

Base area = 1 / 2 × 108 × 9√3

Base area = 54 × 9√3

Base area = 486√3 metres

surface area of a hexagonal pyramid = 108 × 18 / 2 + 486√3

Therefore,

surface area of a hexagonal pyramid = 972 + 486√3 metres

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The service should wax approximately 233 cars daily to maximize profit.

To maximize profit, we need to find the number of cars (q) that would result in the highest profit. Profit function P(q) can be calculated as:

P(q) = Revenue - Cost
P(q) = 65q - (0.06q² + 37q + 360)

Now, to find the optimal value of q, we can calculate the derivative of the profit function with respect to q and set it to zero:

dP(q)/dq = 65 - (0.12q + 37)
0 = 65 - 0.12q - 37

Solve for q:

0.12q = 28
q = 28 / 0.12
q ≈ 233.33

Since the number of cars must be a whole number, we can round q to the nearest integer. Therefore, the service should wax approximately 233 cars daily to maximize profit.

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The cost of a Powerade is $0.75 if 2 bags of chips and 2 Powerades cost $3.50 and one bag of chips and 3 Powerades cost $3.75.

Let the cost of one Powerade be x

The cost of one bag of chips be y

Cost of 2 bags of chips and 2 Powerades = $3.50

Cost of 2 bags of chips = 2y

Cost of 2 Powerades = 2x

2x + 2y = 3.50 ----(i)

Cost of one bag of chips and 3 Powerades= $3.75

Cost of 1 bag of chips = y

Cost of 3 Powerades = 3x

x + 3y = 3.75

Multiply the above equation by 2

2x + 6y = 7.50 -----(ii)

Subtract (ii) and (i)

4y = 4

y = $1

The cost of one bag of chips is $1

x + 3 = 3.75

x = $0.75

The cost of one Powerade is $0.75

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The cucumber is also considered a vegetable due to its culinary usage in salads and savory dishes.

Vegetables are edible plants that are commonly used as a food source. They are a primary source of vitamins, minerals, fiber, and other nutrients that are important for maintaining good health.

From a biological perspective, Sheila would most likely classify the apples and lemons as fruits. In botanical terms, fruits are the mature ovary of a flowering plant, containing seeds. Both apples and lemons contain seeds and develop from the ovary of a flower, so they are classified as fruits. The tomato and cucumber, on the other hand, are classified as vegetables.

While the tomato also develops from the ovary of a flower and contains seeds, it is considered a vegetable in culinary terms due to its savory flavor and common usage in savory dishes.

Therefore, The cucumber is also considered a vegetable due to its culinary usage in salads and savory dishes.

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The minimum surface area of the box is 68 cm², which corresponds to option (d).

Let the side length of the square base be x and the height of the box be h. Then, we have:

Volume of the box = x²h = 32

h = 32/x²

The surface area of the box is given by:

S = x² + 4(xh) = x² + 4x(32/x²) = x² + 128/x

To find the minimum surface area, we can differentiate S with respect to x, set the derivative equal to zero, and solve for x:

dS/dx = 2x - 128/x² = 0

2x = 128/x²

x⁴ = 64

x = 2 cm

Note that we need to check that this critical point gives us a minimum surface area. We can do this by checking the second derivative:

d²S/dx² = 2 + 256/x³

d²S/dx² at x = 2 is positive,

indicating that this critical point gives us a minimum surface area.

Substituting x = 2 in the equation for S, we get:

S = 2² + 128/2 = 4 + 64 = 68

Therefore, the minimum surface area of the box is 68 cm², which corresponds to option (d).

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The value of c is 0.4 and  the corresponding horizontal distance travelled by the ball is 4 meters.

We are given the projectile equation:

y = -1/8x² + x + c

To find the value of c, we can use the fact that the maximum height attained by the ball is 2.4 meters. The maximum height occurs at the vertex of the parabola, which is given by:

x = -b/2a

where a = -1/8 and b = 1.

Therefore,

x = -(1)/(2*(-1/8)) = 4

So, the corresponding horizontal distance travelled by the ball is 4 meters.

Now, we can use the maximum height attained by the ball to solve for c.

y = -1/8x² + x + c

Substituting x = 4 and y = 2.4, we get:

2.4 = -1/8(4)² + 4 + c

2.4 = -1/8(16) + 4 + c

2.4 = -2 + 4 + c

c = 0.4

Therefore, the value of c is 0.4.

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Yes. The null hypothesis is that the changes in the course did not have a significant impact on the DFW rate. The chi-squared statistic is 44.63, with 2 degrees of freedom, and the p-value is less than 0.001.

1. Yes, it is likely that the changes in the gateway course had an impact on the DFW rate, as the rate decreased from 42.1% in Year 1 to 19.4% in Year 3.

2. The null hypothesis is that the changes in the course did not have a significant impact on the DFW rate, while the alternative hypothesis is that the changes did have a significant impact on the rate.

3. The chi-squared statistic is 44.63, with 2 degrees of freedom, and the p-value is less than 0.001. This indicates that there is a significant relationship between the year the course was given and the DFW rate, providing evidence to reject the null hypothesis in favor of the alternative hypothesis that the changes made to the course had a significant impact on the DFW rate.

The p-value of less than 0.001 indicates strong evidence against the null hypothesis, as it is less than the significance level of 0.1.

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Answer:

Step-by-step explanation:

(a)

x + y = -1

3x = 4 - 3y

from 1st equation we can write x = -1 - y and put this x in the 2nd equation

3(-1 -y) = 4 -3y

-3 -3y = 4 -3y

now here y is getting cancel so that means this two equation has no common solution.

(b)

3x - 4y +2 = 0

10 -10y = 10y -15x

from 1st equation we can write x = (4y - 2)/3 and put this x in the 2nd equation

10 = 10y +10y -15((4y - 2)/3)

2 = 2y +2y - 3((4y -2)/3)

2 = 4y - (4y - 2)

again here 4y and 4y getting cancel so both the equation has no common solution.