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The value of tan A is 0. 667. Option B

To determine the value of the identity, we need to take note of the different trigonometric identities.

these identities are;

We also have that the ratio for the tangent identity is expressed as;

tan θ= opposite/adjacent

From the information given, we have that;

The hypotenuse is 18.03, the side opposite to angle A is 10, and the side adjacent to angle A is 15

Then, for the identity, we have;

tan A = 10/15

Divide the values

tan A = 0. 667

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Jordan's account balance at the end of the month would be $143.85.

What is the basic arithmetic operations?

The four basic mathematical operations are Addition, subtraction, multiplication, and division.

To determine Jordan's account balance at the end of the month, we need to add up the deposits and withdrawals to the initial balance.

Initial balance: $92.66

Deposits: $7.72 + $70.42 + $107.46 = $185.60 (sum of positive amounts)

Withdrawals: -$84.26 + (-$50.15) = -$134.41 (sum of negative amounts)

To calculate the account balance at the end of the month, we can add the deposits and withdrawals to the initial balance:

Account balance at the end of the month = Initial balance + Deposits - Withdrawals

= $92.66 + $185.60 - $134.41

= $143.85

Hence, Jordan's account balance at the end of the month would be $143.85.

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The result of the operation that we have done here is -5√3.

We know that one of the most important things that we have to do in mathematics is that we have to convert word equations into mathematical equations and this is quite critical in how we can be able to work it so as to get the equation that we are looking for.

We now have that;

5/-3 * 3 * √3

5/-1 * √3

-5* √3

-5√3

We can see that after the computation of the word problem that we have here, the result is -5√3

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Both parabolic equations yield distinct y values for any x in the set of integers (Z). Thus, there are two distinct y values satisfying the given equation.

There are two distinct y values satisfying the given equation.

First, we rewrite the equation as |y-3| = 5 - x² + 8x - 18. Then, we express |y-3| as two cases: y-3 and -(y-3).

Case 1: y - 3 = 5 - x² + 8x - 18

Solving for y, we get y = x² - 8x + 16.

Case 2: -(y - 3) = 5 - x² + 8x - 18

Solving for y, we get y = x² - 8x + 10.

Both parabolic equations yield distinct y values for any x in the set of integers (Z). Thus, there are two distinct y values satisfying the given equation.

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The percentage of the powdered lemon mix in Dianelys's mix indicates that Dianelys's mix is more lemony.

A percentage is an expression of a ratio of two quantities as a fraction of 100.

The number of cups of water Zachary mixes with 5 cups of powdered lemon mix = 11 cups of water
Number of cups of water Dianelys mixes with 4 cups of powdered lemon mix = 7 cups of water

Zachary's percentage of powdered lemon mix = (5/(11 + 5)) × 100 = 31.25%

Dianelys's percentage of powdered lemon mix = (4/(7 + 4)) × 100 = 36.[tex]\overline{36}[/tex]%

The percentage of powdered lemon mix for Dianelys which is more than the percentage in Zachary's powdered lemon mix indicates that Danialys mix is more lemony.

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Answer:

Step-by-step explanation:

8,800x0.09=792. The salesperson earns $792 in commission.

Answer:

$792

Step-by-step explanation:

8800×0.09= 792

9÷100=0.09

commission =$792

Our table looks like this:
x | y
--|--
1 | 3
2 | 6
-2 | -6
0 | 0

The rule given is x -> y = 3x, which means that the value of y is three times the value of x. To fill in the table with at least 4 points, we can choose any four values of x and calculate their corresponding values of y using the rule.

Let's start with x = 1. Plugging this value into the rule, we get y = 3(1) = 3. So the first point in our table is (1, 3).

Next, let's try x = 2. Using the rule, we get y = 3(2) = 6. So the second point in our table is (2, 6).

Moving on, let's choose x = -2. Using the rule, we get y = 3(-2) = -6. So the third point in our table is (-2, -6).

Lastly, let's try x = 0. Using the rule, we get y = 3(0) = 0. So the fourth point in our table is (0, 0).
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The decimal - 2. 97 is the solution to the subtraction problem of D.  - 6. 1  - ( - 3. 13 ).

When subtracting decimal numbers, the effective method is to align their decimal points and begin removing each corresponding digit from one another. You may extend any decimals with fewer digits by appending zeros on the right-hand side as required for parity.

= - 6. 1  - ( -3. 13 )

= - 6. 1  + 3. 13

= - 2. 97

The decimal 2.97 is the solution to the subtraction problem - 6. 61 - (- 3. 13).

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Answer:

5%

Step-by-step explanation:

Percent error equation is:

(Absolute value of experimental value - actual value / actual value) * 100

Experimental Value: 315

Actual Value: 300

315 - 300 / 300 = 0.05

0.05*100 = 5

Percent error is 5%

Answer: the percent error is 5%

Step-by-step explanation:

Answer:

(x-3)(x+4)

Step-by-step explanation:

This way is how it s done in Greece. If u don't understand don't read the explanation Δ=β2-4αγ=81-32=49

χ1,2=-1+-7^2=3

=-4

Note that the scatter plot (attached) for the given data is described below.

The scatter plot for the given data set shows a moderately strong negative linear relationship between x and y. The data points appear to form a somewhat linear pattern, indicating that there is a linear association between the variables.

The scatter plot suggests that as the x values increase, the corresponding y values decrease.

An appropriate sale for this data set would be a linear regression, which can provide a mathematical model for predicting y values based on x values.

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The work done in pushing the car along the level road from point A is found to be 8147 foot-pounds.

The work done in pushing a car along a level road can be calculated using the formula,

work = force × distance × cos(angle) where the angle between the force and the direction of motion is 0 degrees (since the force is parallel to the level road). The force is given as 103 pounds, and the distance is 79 feet. Therefore,

work = 103 × 79 × cos(0) = 8147 foot-pounds

Rounding to the nearest foot-pound, the work done in pushing the car from point A to point B is 8147 foot-pounds.

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Answer:

Step-by-step explanation:

When x_1 =7 then you can figure out by given condition say X_n+1= 2X_n-3

then X_2= 11 by substituting the value of X_1 as 7 similarly you can find out the value of X_3 by substituting X_2 as 11 so X_3 =19.

Similarly you can find out b)

Answer:

To find the product of matrices AB, we need to multiply the elements of the rows of matrix A with the corresponding elements of the columns of matrix B, and then sum these products.

Since matrix A is a 2x2 matrix and matrix B is a 2x3 matrix, we can perform the multiplication as follows:

AB = | 1 2 |   | 1 2 3 |   | (1*1)+(2*4)  (1*2)+(2*5)  (1*3)+(2*6) |

    | 3 4 | x | 4 5 6 | = | (3*1)+(4*4)  (3*2)+(4*5)  (3*3)+(4*6) |

                          |              |              |              |

    |  9 12 15 |          |  9  12  15 |

Therefore, the product of matrices AB is a 2x3 matrix, and the answer is C) 2x3.

The probability of needing fewer than 4 rolls to get doubles is 13/25.

Probability is a branch of mathematics that deals with the likelihood of something happening. It is used in many areas such as finance, engineering, and even gambling. Probability is the measure of how likely an event is to take place. This is usually expressed as a number between 0 and 1, where a 0 indicates an impossible event, and a 1 indicates an event that is certain to happen. Probability is an important component of decision making, as it allows us to calculate the chances of different outcomes.

This can be calculated by using the binomial probability formula. The binomial probability formula is used to calculate the probability of a certain number of successes in a certain number of trials. In this case, the number of successes is 2 (the number of doubles required to win the game) and the number of trials is 4 (the maximum number of rolls necessary to win the game).

Using the formula P(x) = nCx * pˣ* qⁿ⁻ˣ, where n is the number of trials, x is the number of successes, p is the probability of success and q is the probability of failure, we can calculate the probability of needing fewer than 4 rolls to get doubles as follows:

P(2) = 4C2 * (1/2)² * (1/2)⁴⁻² = 4 * ( 1/4 ) * (1/4) = 1/4

P(1) = 4C1 * (1/2)¹ * (1/2)⁴⁻¹= 4 * (1/2) * (1/2) = 1/4

The total probability of needing fewer than 4 rolls to get doubles is the sum of the probabilities of needing 1 or 2 rolls to get doubles, which is 1/4 + 1/4 = 1/2, or 13/25.

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Complete questions as follows-

Based on the results, what is the probability of needing fewer than 4 rolls to get doubles? 13/25.

Answer:

Step-by-step explanation:

actual area : 60 x 12 = 720

1/2 = 0.5

60 + 0.5 = 60.5        12 + 0.5 = 12.5  -max area = 60.5 x 12.5 = 756.25

60 - 0.5 = 59.5         12 - 0.5 = 11.5    -min area =  59.5 x 11.5 = 684.25

absolute error :  1/2(756.25-684.25) = 36

relative error : 36/720 = 0.05

 ... your welcome  

Answer:

it's 4 cm

Step-by-step explanation:

A. Square = 50 cm²

A. Square = s × s

50 = s²

s = √50

SP = hypotenuse (c) = s

c = s = √50

b = √34

a = PT = ...?

use Pythagorean theorem to find PT

a² + b² = c²

a² + (√34)² = (√50)²

a² + 34 = 50

a² = 50 - 34

a² = 16

a = √16

a = 4 cm

The missing step of the congruent triangles is ΔMDA ≅ ΔMBC by ASA theorem

Given data ,

Let the two triangles be represented as ΔMDA and ΔMBC

Now , the measure of side MD ≅ MB ( given )

And , the measure of angle ∠DMA ≅ ∠BMC ( vertical angles theorem )

Now , the measure of ∠MDA ≅ measure of ∠MBC ( alternate interior angles)

Two angles are the same and a corresponding side is the same (ASA: angle, side, angle)

So , ΔMDA ≅ ΔMBC by ASA theorem

Hence , the congruent triangles are solved

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The sum of all the number is found to be 630 which is not given in the options.

Let the middle number be x. Then the five numbers smaller than x have an average of 44, so their sum is 544 = 220. Similarly, the five numbers larger than x have an average of 68, so their sum is 568 = 340.

The total of all the numbers is 9x since x is the median and average of all the numbers. The total of all the numbers equals 9x since we know that x is the average of all the numbers.

Therefore, we have,

9x = 220 + x + 340

Simplifying and solving for x, we get,

8x = 560

x = 70

Therefore, the sum of all the numbers is 9x = 970 = 630.

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Complete question - Nine numbers are written in ascending order, the middle number is the average of all the numbers, the average of the five largest numbers is 68, and the average of the five smallest is 44. What is the sum of all the numbers? ?

a) 112

b) 504

c) 144

d) 560

d) 122

The length of the Green Route in miles is 64 miles.

Miles is a unit of linear measurement. It is traditionally defined as 5,280 feet, or 1,760 yards, and is equivalent to 1.609 kilometers. Miles are commonly used to measure long distances, such as the distance between two cities. They are also used to measure the lengths of roads and other paths. Miles are one of the most commonly used units of measurement in the United States.

The length of the Green Route in miles can be calculated by subtracting the total mileage traveled on the Blue Route from the total mileage traveled on both routes.

Total miles traveled on Monday = 38 miles
Total miles traveled on Tuesday = 80 miles

Total miles traveled on the Blue Route = 5 + 11 = 16 miles

Therefore, the total miles traveled on the Green Route = 80 - 16 = 64 miles

Therefore, the length of the Green Route in miles is 64 miles.

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Answer:

26

Step-by-step explanation:

For the given vector v = 2i - 3j, the value of the vector magnitude ||2v|| is 2√13.

To find the norm, or magnitude, of a vector, we use the Pythagorean theorem in the following way:

||v|| = √(v₁² + v₂² + ... + vn²)

In this case, we have v = 2i - 3j, so:

||v|| = √((2)² + (-3)²)

= √(4 + 9)

= √13

So the norm of the vector v is √13.

To find ||2v||, we simply double the vector and then find its norm:

2v = 2(2i - 3j)

= 4i - 6j

||2v|| = √((4)² + (-6)²)

= √(16 + 36)

= √52

= 2√13

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On performing the given row-operation on the given augmented-matrix:

(a) multiplying row1 by -2 and adding to row2, we have [tex]\left[\begin{array}{ccc}5&-2&6\\-10&10&-15\end{array}\right][/tex],

(b) interchanging row1 and row2, we have [tex]\left[\begin{array}{ccc}0&6&-3\\5&-2&6\end{array}\right][/tex],

(c) Multiplying row1 by 2, the matrix becomes [tex]\left[\begin{array}{ccc}10&-4&12\\0&6&-3\end{array}\right][/tex].

The augmented matrix on which we have to perform the row operation is

⇒ [tex]\left[\begin{array}{ccc}5&-2&6\\0&6&-3\end{array}\right][/tex],

Part(a) : We have to multiply row1 by -2 and and add to row2,

The row-operation is performed as : [tex]\left[\begin{array}{ccc}5&-2&6\\(5\times-2)+0&(-2\times-2)+6&(6\times-2)-3\end{array}\right][/tex];

Simplifying further ,

We get,

[tex]\left[\begin{array}{ccc}5&-2&6\\-10&10&-15\end{array}\right][/tex].

Part(b) : We have to interchange the "row1" and "row2",

On interchanging,

We get,

[tex]\left[\begin{array}{ccc}0&6&-3\\5&-2&6\end{array}\right][/tex].

Part(c) : We have to multiply the elements of "row1" by 2,

So, On multiplying the "row1" by 2,

We get,

⇒ [tex]\left[\begin{array}{ccc}5\times 2&-2\times 2&6\times 2\\0&6&-3\end{array}\right][/tex]

⇒ [tex]\left[\begin{array}{ccc}10&-4&12\\0&6&-3\end{array}\right][/tex].

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There are 29 degrees of freedom for this repeated-measures t-test.

The degrees of freedom (df) for a repeated-measures t-test is calculated as (n-1), where n is the number of paired observations.

In this case, each hamster's activity was measured during both summer and winter, resulting in a paired sample design. Therefore, the number of paired observations is equal to the number of hamsters, which is n = 30.

Hence, the degrees of freedom for this repeated-measures t-test is:

df = n - 1 = 30 - 1 = 29

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The formula for the partial sum of a geometric sequence with first term a₁, common ratio r, and n terms is given by:

Sₙ = a₁(1 - rⁿ)/(1 - r)

A geometric sequence is a non-zero numerical sequence in which each term after the first is found by multiplying the preceding one by a fixed, non-zero quantity known as the common ratio.

In the formula, Sₙ is the sum of the first n terms of the sequence.

Alternatively, the formula can be expressed as:

Sₙ = (a₁(rⁿ - 1))/(r - 1)

Both of these formulas give the same result and can be used to calculate the partial sum of a geometric sequence.

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The values of the composite functions are (g o f)(x) = [tex]\frac{9x^2-18x+4}{4}-5[/tex], (j o g)(x) = 3x² - 15x + 1, (g o h)(x) = [tex]\frac{\left(2x-1\right)^2}{1089}-\frac{5\left(2x-1\right)}{33}[/tex] and (g o g)(-2) = 126

Given that we have the function definitions

The composite functions are calculated below

(g o f)(x) = g(f(x))

(g o f)(x) = (f(x))² - 5f(x)

So, we have

(g o f)(x) = (3/2x + 1)² - 5(3/2x + 1)

Evaluate

(g o f)(x) = [tex]\frac{9x^2-18x+4}{4}-5[/tex]

Next, we have

(j o g)(x) = j(g(x))

(j o g)(x) = 3g(x) + 1

So, we have

(j o g)(x) = 3(x² - 5x) + 1

(j o g)(x) = 3x² - 15x + 1

Next, we have

(g o h)(x) = g(h(x))

(g o h)(x) = (h(x))² - 5h(x)

So, we have

(g o h)(x) = ((2x - 1)/33)² - 5((2x - 1)/33)

Evaluate

(g o h)(x) = [tex]\frac{\left(2x-1\right)^2}{1089}-\frac{5\left(2x-1\right)}{33}[/tex]

Lastly, we have

(g o g)(-2) = g(g(-2))

(g o g)(-2) = (g(-2))² - 5g(-2)

So, we have

(g o g)(-2) = ((-2)² - 5(-2))² - 5((-2)² - 5(-2))

(g o g)(-2) = 126

Hence, the values are (g o f)(x) = [tex]\frac{9x^2-18x+4}{4}-5[/tex], (j o g)(x) = 3x² - 15x + 1, (g o h)(x) = [tex]\frac{\left(2x-1\right)^2}{1089}-\frac{5\left(2x-1\right)}{33}[/tex] and (g o g)(-2) = 126

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In 12 days, both Eve and Jenna will work out on the same day again.

To find the number of days until Eve and Jenna work out on the same day again, we need to find the least common multiple (LCM) of 6 and 4.

One way to find the LCM is to list the multiples of each number until we find a multiple that they have in common:

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, ...

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, ...

From this list, we see that the least common multiple of 6 and 4 is 12.

This means that in 12 days, both Eve and Jenna will work out on the same day again.

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According to Jean-Claude Maleuvre's book "Museum Memories: History, Technology, Art," Gauguin's views on Polynesian women were complex and contradictory. On the one hand, he was fascinated by their exotic beauty and saw them as a source of artistic inspiration. On the other hand, he objectified and exoticized them, portraying them as primitive and sexually available. Gauguin's depictions of Polynesian women have been criticized as perpetuating colonialist stereotypes and promoting a Westernized gaze.

"There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen does not matter." is correct statement. Therefore, the answer is option C.

The problem asks us to choose 5 students out of a class of 26 to present homework problems. Since the order in which the students present the problems does not matter, we need to use the combination formula. The combination formula is used to calculate the number of ways to choose a subset of k elements from a set of n elements without regard to order, and it is denoted by nCk.

Option A, "There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen matters," is incorrect because the order in which the students are chosen does not matter.

Option B, "There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen matters," is incorrect because we are choosing 5 students out of 26, and the order in which they are chosen does not matter.

Option D, "There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen does not matter," is also incorrect because the order in which the students are chosen does not matter.

Therefore, the answer is option C.

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Complete question is:

In a class of 26 students, a teacher chooses a different student to each present five different homework problems. Which statement describes the number of ways the students can be chosen to present the problems?

A) There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen matters.

B) There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen matters.

C) There are 26C₅ = 65,780 ways the students can be chosen because the order they are chosen does not matter.

D) There are 26P₅ = 7,893,600 ways the students can be chosen because the order they are chosen does not matter.