Answer:
materia
Explanation:
Answer:
the answer to your question is matter
According to American Heart Association, your target heart rate is__________.
Group of answer choices
A .all of the above
B. 85% - 95% of your max heart rate
C. 20%-30% of your max heart rate
D. 50%-85% of your max heart rate
Answer:
B
Explanation:
A normal heart rate is from 85-95% the other heart rate is not normal because your heart is beating more than normal
Sometimes we will want to write vectors in terms of a coordinate grid. To show a vector points
horizontally (along the x-axis), place an x after the magnitude of the vector. To show a vector point
vertically (along the y-axis), place a y after the magnitude.
4) Using the notation above,
i. How would you write d1?
ii. How would you write d2?
iii. How would you write dtotal?
d1=(0,5)
d2=(5,5)
Answer:
III) [tex]d_{1}+ d_{2}=d_{t}[/tex]
Explanation:
I) coordinate (0,5) is the head for [tex]d_{1}[/tex] I will put the tail coordinate as (0,0) but it could be any other number in the x just not in the 5 with the the y being any other value.
II) coordinate (5,5) is the head for [tex]d_{2}[/tex] the tail needs to be in the head of [tex]d_{1}[/tex] being (0,5)
III) coordinates for [tex]d_{t}[/tex] is connecting the tail from [tex]d_{1}[/tex] and the head of [tex]d_{2}[/tex] making it (0,0)[tex](tail)[/tex] and (0,5)[tex](head)[/tex] and is written as [tex]d_{1}+ d_{2}=d_{t}[/tex]
(i) using coordinate grid notation to represent d₁, d₁ = 5y
(ii) using coordinate grid notation to represent d₂, d₂ = 5x + 5y
(ii) The sum of d₁ and d₂ is written as 5x + 10y
In order to show the horizontal direction of a vector, we will place x after the magnitude of the vector.
Also, to show the vertical direction of a vector, we will place a y after the magnitude of the vector.
(i) Using coordinate grid to represent d₁ = (0, 5)
[tex]d_1 = 0(x) + 5(y)\\\\d_1 = 5y[/tex]
(ii) Using coordinate grid to represent d₂ = (5, 5)
[tex]d_2 = 5x + 5y[/tex]
(iii) The total vector is written as;
[tex]d_1 + d_2 = 5y + (5x + 5y)\\\\d_1 + d_2 = 5y + 5x + 5y\\\\d_1 + d_2 = 5x + 10y[/tex]
Learn more here: https://brainly.com/question/17212749
A steel ball moves from a position of +125 meters to a position of -75 meters. This motion takes 90.0 seconds. What is the velocity of the steel ball?
Answer:
2.22m/s to the left
Explanation:
Given parameters:
Initial position = +125m
Final position = -75m
Motion time = 90s
Unknown:
Velocity of the steel ball = ?
Solution:
The velocity of the steel ball is given as the displacement divided by the time;
Velocity = [tex]\frac{displacement}{time}[/tex]
The net displacement of the ball = 125- (-75) = 200m to the left
Input the parameters and solve for the velocity;
Velocity = [tex]\frac{200}{90}[/tex] = 2.22m/s to the left
A lamp of mass m hangs from a spring scale which is attached to the ceiling of an elevator. When the elevator is stopped at the fortieth floor, the scale reads mg. What does it read as the elevator slows down to stop at the ground floor?
a. more than mg
b. mg
c. less than mg
d. zero
e. can't tell
Answer:
The correct answer is (a)
Explanation:
A spring scale measures the weight of an object not the mass because according to hooke's law the extension of a spring is directly proportional to the load or force attached/applied to it. The force of gravity acting on the mass of any substance as it goes up actually reduces and increases as it comes down.
If F = ma, as a increases, F will also increase and vice versa
Where F = force
m = mass
a = acceleration (due to gravity in this case)
From the above explanation, it can be deduced that the scale will read more than mg as it gets to the ground because of an increase in the force of gravity (which also increases a) as it approaches the ground.
PLEASE HELP
A sharpshooter fires a 0.22 caliber rifle horizontally at 100 m/s at a target 75m away. How far does the
bullet drop by the time it reaches the target?
This question involves the concept of semi-projectile motion. It can be solved using the equations of motion in the horizontal and the vertical motion.
The bullet drops "2.76 m" by the time it reaches the target.
First, we will analyze the horizontal motion. We assume no air resistance, so the horizontal motion will be uniform. Hence, using the equation of uniform motion here to find the total time to reach the target:
[tex]s = vt\\\\t = \frac{s}{v}[/tex]
where,
s = distance = 75 m
v = velocity = 100 m/s
t = time = ?
Therefore,
[tex]t = \frac{75\ m}{100\ m/s}[/tex]
t = 0.75 s
Now, we will analyze the vertical motion of the bullet. We will use the second equation of motion in the vertical direction to find the height dropped by the bullet.
[tex]h = v_it+\frac{1}{2}gt^2[/tex]
where,
h = height dropped = ?
vi = initial vertical speed = 0 m/s
t = time interval = 0.75 s
g = acceleration due to gravity = 9.81 m/s²
therefore,
[tex]h = (0\ m/s)(0.75\ s)+\frac{1}{2}(9.81\ m/s^2)(0.75\ s)^2[/tex]
h = 2.76 m
Learn more about equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion in the horizontal and vertical directions.
Electric Charge andStatic ElectricityIt was known as early as 600BCEthat objects could become charged by rubbing fur on various substances such as amber. Charged objects could be used to attract light objects such as hair. In the 1700s, it was determined that charge came in two varieties that could cancel each other out. Charles-Augustin de Coulomb established a quantitativerelation in 1783 that describes how charged objects interact via the electric force. The electric force:
Answer:
Explanation:
In 1785, Coulomb investigated quantitatively, the force exerted between point charges.
The Coulomb's Law states that: "The force of attraction or repulsion between two, point charges is directly proportional to the product of magnitude of the charges and inversely proportional to the square of the distance between them. "
If q₁ and q₂ are two, point charges and r is the distance between them, then the electric force of attraction or repulsion F between them, according to Coulomb’s law will be:
F ∝ q₁q₂ ________________________ eqn (1)
F ∝ 1/r² ________________________ eqn (2)
Combining eqn (1) and eqn (2), we get:
F ∝ (q₁ q₂)/r²
F = (kq₁q₂)/r²
where,
k = constant of proportionality = 9 x 10⁹ N.m² / C²
While you were at the skate park, what did you notice about potential and kinetic energy
Answer: I only know that the skater riding down the ramp increeses it's kinetic energy.
Explanation:
The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth’s electric field? (b) What would be the force of repulsion between two people each with the charge calculated in part (a) and separated by a distance of 100 m? Is use of the earth’s electric field a feasible means of flight? Why or why not?
Answer:
a) The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The force of repulsion between two people is [tex]13.851\times 10^{6}[/tex] newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.
Explanation:
a) From Second Newton's Law, we form this equation of equilibrium:
[tex]\Sigma F = F_{E}-W = 0[/tex] (Eq. 1)
Where:
[tex]F_{E}[/tex] - Electrostatic force exerted on human, measured in Newton.
[tex]W[/tex] - Weight of the human, measured in Newton.
If we consider that human can be represented as a particle and make use of definitions of electric field and weight, the previous equation is expanded and electric charge is cleared afterwards:
[tex]q\cdot E-m\cdot g = 0[/tex]
[tex]q = \frac{m\cdot g}{E}[/tex] (Eq. 2)
[tex]E[/tex] - Electric field, measured in Newtons per Coloumb.
[tex]m[/tex] - Mass, measured in kilograms.
[tex]g[/tex] - Gravity acceleration, measured in meters per square second.
[tex]q[/tex] - Electric charge, measured in Coulomb.
As electric field of the Earth is directed in toward the center of the planet, that is, in the same direction of gravity, electric field must be a negative value. If we know that [tex]m = 60\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]E = -150\,\frac{N}{C}[/tex], the charge that a 60-kg human must have to overcome weight is:
[tex]q = \frac{(60\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{-150\,\frac{N}{C} }[/tex]
[tex]q = -3.923\,C[/tex]
The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The electric force of repulsion between two people with the same charge calculated in part (a) is determined by Coulomb's Law, whose definition we proceed to use:
[tex]F = \kappa \cdot \frac{q^{2}}{r^{2}}[/tex] (Eq. 3)
Where:
[tex]\kappa[/tex] - Electrostatic constant, measured in Newton-square meter per square Coulomb.
[tex]q[/tex] - Electric charge, measured in Coulomb.
[tex]r[/tex] - Distance between two people, measured in meters.
If we know that [tex]\kappa = 9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q = -3.923\,C[/tex] and [tex]r = 100\,m[/tex], then the force of repulsion between two people is:
[tex]F = \left(9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot \left[\frac{(-3.923\,C)^{2}}{(100\,m)^{2}} \right][/tex]
[tex]F = 13.851\times 10^{6}\,N[/tex]
The force of repulsion between two people is [tex]13.851\times 10^{6}[/tex] newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.
True/False
1. The Law of Superposition states that older rocks are on the top, younger rocks are on the botom.
Answer:
yeah
Explanation:
Geology. a basic law of geochronology, stating that in any undisturbed sequence of rocks deposited in layers, the youngest layer is on top and the oldest on bottom, each layer being younger than the one beneath it and older than the one above it.
Answer:
Found this answer off of google, "Geology. a basic law of geochronology, stating that in any undisturbed sequence of rocks deposited in layers, the youngest layer is on top and the oldest on bottom, each layer being younger than the one beneath it and older than the one above it."
Hope this helps, have a great day and stay safe!
Also Happy Halloween! :) :D :3
A stone is thrown horizontally with an initial speed of 10m/s from the edge of the cliff. A stop watch measures the stone’s trajectory with time from the top of the hill to the bottom to be 6.7s. What is the height of the cliff?
Answer:
Answer and steps in the pic
how can water be boiled in a paper cup?
Answer:
if you place a glass of boiling water in a paper cup filled with hot pads
Explanation:
am I thinking too deeply into this or does it make sense
Consider the trajectories of a projectile that experiences drag due to air resistance. Maximum range is achieved by launching the projectile at ________.
a. An angle less than 45 degrees.
b. An angles of 45 degrees.
c. An angle greater than 45 degrees.
d. An angle that depends on the launch speed
Answer:
Maximum range is achieved by launching the projectile at an angles of 45 degrees.
so the answer is B
Explanation:
What is the range of a projectile?
this can be defined as the maximum horizontal distance covered by a projectile
R=v^2sin(2θ)/2g
Why is 45 degrees maximum range?
"The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range puts 2θ = 90 degrees and, therefore, θ = 45 degrees."
Hence a projectile, travels the farthest when it is launched at an angle of 45 degrees
Question 7
Identify the correct Earth System in order from #1-4.
Reorder answers
1.Atmosphere
Reorder answers
2.Geosphere
Reorder answers
3.Hydrosphere
Reorder answers
4.Biosphere
Answer:
2, 3, 4, 1
Explanation:
geosphere, hydrosphere, biosphere, and atmosphere
Answer:
Lithosphere hydrosphere biosphere atmosphere
Explanation:
So yea mark me brainliest
dimensional formula of stress is same as
Dimensional formula of stress is same as pressure.
Scott travels north 2 miles and then goes west 5 miles before coming straight back south 7 miles what is his displacement
Answer:
Displacement is 5√2 miles
Explanation:
From south, Scott travelled 2 miles north and then 5 miles west then he came back south by 7 miles.
I've attached a diagram to indicate Scott's path travelled
Now, displacement is a vector quantity that tells us the overall change in position by Scott i.e distance from his initial position to his current final position while distance is a scalar quantity and tells us how much ground Scott covered in his motion over the entire trip.
Now, from the attached image, the displacement is denoted by "d".
d can be found from pythagoras theorem.
Thus;
d² = 5² + 5²
d = √50
d = 5√2 miles
In a railroad switchyard, a rail car of mass 41,700 kg starts from rest and rolls down a 2.65-m-high incline and onto a level stretch of track. It then hits a spring bumper, whose spring compresses 79.4 cm. Find the spring constant.
Answer:
The spring constant is 3.44x10⁶ kg/s².
Explanation:
We cand find the spring constant by conservation of energy:
[tex] E_{i} = E_{f} [/tex]
[tex] mgh = \frac{1}{2}kx^{2} [/tex] (1)
Where:
m is the mass = 41700 kg
g is the gravity = 9.81 m/s²
h is the height = 2.65 m
x is the distance of spring compression = 79.4 cm
k is the spring constant =?
Solving equation (1) for k:
[tex]k = \frac{2mgh}{x^{2}} = \frac{2*41700 kg*9.81 m/s^{2}*2.65 m}{(0.794 m)^{2}} = 3.44 \cdot 10^{6} kg/s^{2}[/tex]
Therefore, the spring constant is 3.44x10⁶ kg/s².
I hope it helps you!
Compare the kinetic energy of a 21,000 kg truck moving at 130 km/h with that of an 84.0 kg astronaut in orbit moving at 28,000 km/h.
Answer:
K.E of the Astronaut is greater
Explanation:
Mathematically;
K.E = 1/2 * m * v^2
For the truck, the kinetic energy will be
1/2 * 21,000 * 130^2 = 177,450,000 J
while for the astronaut, his K.E will be
1/2 * 84 * 28,000^2 = 3.2928 * 10^10
This shows that the K.E of the astronaut is greater
Which of the following is NOT a benefit of cool down activities?
Answer:
Blood is moved away from the brain
Explanation:
Took the test
Complete this problem so that it can be solved using the concept listed Angela is playing basketball
A. Acceleration
B. Speed
what chemical diverged from trees
a resin and turpentine
b sodium
c lead
d marcotting
Answer:
a. resin and turpentine
Explanation:
The chemicals that diverged from trees are resin and turpentine.
Resin are produced by special cells in trees, most times we see them when a tree is damaged or cut. They are usually derived from pines and firs.
Turpentine is obtained by distilling resin.
Turpentine has an antiseptic property that has different uses. They are used as cleansing agents and for producing sanitary materials.
why are elements important
Answer: Scientists believe that about 25 of the known elements are essential to life. Just four of these – carbon, oxygen, hydrogen, and nitrogen– make up about 96% of the human body. Six common elements that are important in living things are carbon, hydrogen, oxygen, nitrogen, sulfur, and phosphorus. These large molecules make up the structures of cells and carry out many many processes essential to life.
Plz mark brainliest:)
Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley on frictionless bearings. The other end of this string supports a second similar pulley, over which passes a second string supporting a mass of 3m at one end and m at the other. Using two suitable generalized coordinates, set up the Lagrangian and use the Lagrange equations to find the acceleration of the mass 4m when the system is released. Explain why the top pulley rotates even though it carries equal weights on each side.
Answer:
Hello your question is incomplete attached below is the complete question
Answer : x ( acceleration of mass 4m ) = [tex]\frac{g}{7}[/tex]
The top pulley rotates because it has to keep the center of mass of the system at equilibrium
Explanation:
Given data:
mass suspended = 4 meters
mass suspended at other end = 3 meters
first we have to express the kinetic and potential energy equations
The general kinetic energy of the system can be written as
T = [tex]\frac{4m}{2} x^2 + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2[/tex]
T = [tex]4mx^2 + 2my^2 -2mxy[/tex]
also the general potential energy can be expressed as
U = [tex]-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant[/tex]
The Lagrangian of the problem can now be setup as
[tex]L =4mx^2 +2my^2 -2mxy +2mgy + constant[/tex]
next we will take the Euler-Lagrange equation for the generalized equations :
Euler-Lagrange equation = [tex]4x-y =0\\-2y+x +g = 0[/tex]
solving the equations simultaneously
x ( acceleration of mass 4m ) = [tex]\frac{g}{7}[/tex]
The top pulley rotates because it has to keep the center of mass of the system at equilibrium
true or false- When an atom's charge is balanced, the amount of negative charge equals the amount of neutral charge.
A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct expression for the gravitational field strength of Planet X?
A. The gravitational field strength of Planet X is mg.
B. The gravitational field strength of Planet X is Wx/m.
C. The gravitational field strength of Planet X is 9.8 N/kg.
D. The gravitational field strength of Planet X is mWx.
Answer: B. The gravitational field strength of Planet X is Wx/m.
Explanation:
Weight is a force, and as we know by the second Newton's law:
F = m*a
Force equals mass times acceleration.
Then if the weight is:
Wx, and the mass is m, we have the equation:
Wx = m*a
Where in this case, a is the gravitational field strength.
Then, isolating a in that equation we get:
Wx/m = a
Then the correct option is:
B. The gravitational field strength of Planet X is Wx/m.
The velocity of a body travelling in a circular path can be measured with an uncertainty estimated at 4%. The Radius R of the circular path can be measured within 2%. What is the uncertainty associated with the determination of normal acceleration, a, from a = v^2/R Would it make much difference if the radius could be measured within 1%?
Answer:
a) uncertainty percentage = 10%
b) if R could be measured within 1%, uncertainty percentage is 9%,
it wouldn't make much difference
Explanation:
Given that;
velocity v = 4%
radius R = 2%
using calculation on errors / uncertainties in mumber,
To find error/uncertainty in aₙ
aₙ = V² / R
= V₂ × 1/R
V × V × 1/R
let U + V be x and relative error ΔV/V = 4% = 0.04
also, let R be Y and error (relative) ΔR/R = 2% = 0.02
so aₙ = V²/R = x² / y --------------------- let this be equ 1
Δaₙ/aₙ = ΔV/V + ΔR/R + ΔV/V {V×V×1/R}
Δaₙ/aₙ = 0.4 + 0.02 + 0.4
Δaₙ/aₙ = 0.1
so 0.1 × 100 = 10%
therefore uncertainty percentage = 10%
if R could be measured within 1%
Δaₙ/aₙ = (0.04 × 2) + 0.01
= 0.08 + 0.01
= 0.09
so 0.09 × 100
= 9%
therefore if R could be measured within 1%, uncertainty percentage is 9%,
it wouldn't make much difference
A force of 41 N acts on an object which has a mass of 2.4 kg. What acceleration (in m/s2) is produced by the force
Answer:
The acceleration is [tex] a = 17.083 \ m/s^2 [/tex]
Explanation:
From the question we are told that
The force is [tex]F = 41 \ N[/tex]
The mass of the object is [tex]m = 2.4 \ kg[/tex]
Generally the force is mathematically represented as
[tex]F = m* a[/tex]
=> [tex] 41 = 2.4* a[/tex]
=> [tex] a = 17.083 \ m/s^2 [/tex]
Homeboy Joe is riding his skateboard and playing Among Us. Because he's distracted he doesn't notice he's about to skate right off the 69.0 m cliff he's on. If he lands 22.0 m from the cliff, how fast was he skating?
plz help me
what do you meant by significant figure?give different rules to clarify significant figure.
Two vectors have magnitudes 20 m and 44 m. Which of the following cannot possibly be the magnitude of the resultant of the two vectors ?
Answer:
44M 64M
Explanation:
4. A teacher throws the stapler at her students 23 m in 1.2 seconds. What speed must the teacher throw the
stapler and what will be the staplers highest point during its flight?
dy = - 42gt2
dx = Vyt
Answer:
dy
Explanation:
My guess of guts.
okay bye
