Anyone help? Please I’ve tried -35 but the graph is just to ten

Answer:

(D) y = 2x - 5

Step-by-step explanation:

First locate where the line touches the y axis or vertical axis. Then find the rise over run or rate of change (slope) by using the triangle method.

I call this the triangle method because it involves drawing vertical(up, and down), and horizontal(left, and right) lines from the original or diagonal line (hypotenuse or longest line) to create a right (90 degree, because the angle between them forms a square) triangle. First draw a line going to the right from a point on the original line, and form a triangle by connecting the next point with a line going up, and down (vertical line) with the line going to the right (horizontal line)

Then count the units of the vertical line and divide them by the units counted by the horizontal line.

This is k(for constant) or m(slope or steepness of a graph ) = change in or rise of y divided by the change in or rise of x = ∆y(change in or rise of y)/∆x(change in or run of x).

For this graph, starting from -5 or the point where the line touches the y axis. Draw a line going up 1 square to the right, and another going up 2 squares. Repeat this, and you will realise that it's the same pattern every time. Because the line goes up 2 squares, every time it goes to the right 1 square. There is a change of 2 in y every change of 1 in x or rise of 2 for every run of 1. Therefore, the slope is 2/1 = 2. Then since we know the graph touches the y axis at -5, y = 2x - 5

Answer:

47.6 cm

Step-by-step explanation:

Since the triangle is equilateral then the 2 inclined sides = 7.2 cm

Perimeter is then the sum of the 5 sides

P = 13 + 7.2 + 13 + 7.2 + 7.2 = 47.6 cm

Answer: The Slope Is: m=2. The y -intercept Is: b=9 or (0,9)                        hope this helps :)

Step-by-step explanation:

Answer:

is thisssssssssssssssssss right????????????????????????????

Answer:

(a) 36 points

(b) Pr(rolling a double number) ≅ 0.167

(c) Pr(a sum of 6 is rolled) ≅ 0.139

(d) Pr(a sum of 11 is rolled)  ≅ 0.056

(e) No.

Step-by-step explanation:

Sample space = {1,1  1,2  1,3  1,4  1,5  1,6  2,1  2,2  2,3  2,4  2,5  2,6  3,1  3,2  3,3  3,4  3,5  3,6  4,1   4,2  4,3  4,4  4,5  4,6  5,1  5,2  5,3  5,4  5,5  5,6  6,1  6,2  6,3  6,4  6,5  6,6}

(a) The number of points in the sample space is 36.

(b) Pr(rolling a double number) = [tex]\frac{6}{36}[/tex]

                                                   = [tex]\frac{1}{6}[/tex]  ≅ 0.167

(c) Pr(a sum of 6 is rolled) = [tex]\frac{5}{36}[/tex] ≅ 0.139

(d) Pr(a sum of 11 is rolled) = [tex]\frac{2}{36}[/tex]

                                           = [tex]\frac{1}{18}[/tex] ≅ 0.056

(e) No. It is more likely to roll a sum of 6 than that a sum of 11.

Answer:

The probability is approximately 0.2222

Step-by-step explanation:

The correct question is as follows;

Suppose the time to process a loan application follows a uniform distribution over the range 7 to 15 days. What is the probability that a randomly selected loan application takes longer than 14 days to process

Please check attachment for solution to question

Answer:

C

Step-by-step explanation:

Slope equals rise over run, which means the change in y for every x value. On the table, we see that y increases by 10 and x increases by 2, so that would be 10/2. However, the slope must be shown in the simplest form so divide the fraction by 2 to get the final slope, 5/1=5.

To get the intercept you must find when x=0. Since the lowest x-value on the graph is 2 we need to subtract the slope twice to get to zero. So 10-5-5, which equals 0.

The equation would be y=5x.

Answer:

$11.20

Step-by-step explanation:

you just double the cost of 2.5 pounds because 2.5 +2.5 is 5

Answer:20.16

Step-by-step explanation:

That is we want the price of

9

pounds (lets call it

$

x

) to be such that

$

5.60

:

2.5

pounds

is the same as

$

x

:

9

pounds

or written as fractions, we want

$

5.60

2.5

pounds

=

$

x

9

pounds

That is

XXX

$

x

=

$

5.60

2.5

pounds

×

9

pounds

XXXXX

=

$

50.40

2.5

=

$

20.16

Answer:

10.5

Step-by-step explanation:

Answer:

He would use 10.5 lbs of apples.

Answer:

14 in

Step-by-step explanation:

Given:

Circumference of circle = 44 in

Required:

The length of the diameter of the circle.

SOLUTION:

Circumference of circle = πd

Circumference = 44 in

π = 3.14

d = ?

Plug the values into the formula

44 = 3.14*d

Divide both sides by 3.14

44/3.14 = d

14.01 = d

d ≈ 14 in

Answer:

odds and probably are the same. If there is 0.25 chance that means there is basically a 25% chance the event will happen or 1/4 chance.

Step-by-step explanation:

Answer:

A. 6 B. 8 min C. yes

Step-by-step explanation:

Answer:

5000

Step-by-step explanation:

2% of 250,000 is 5000

Answer:

Explained below.

Step-by-step explanation:

Let X represents the tree heights.

It is provided that X follows a normal distribution with mean μ = 112 inches and standard deviation σ = 10 inches.

(a)

Compute the 22nd percentile of the tree heights as follows:

[tex]P(X<x)=0.22\\\\P(Z<z)=0.22[/tex]

The z-score for the corresponding probability is, z = -0.77.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\-0.77=\frac{x-112}{10}\\\\x=112-(0.77\times 10)\\\\x=104.3[/tex]

Thus, the 22nd percentile of the tree heights is 104.3 inches.

(b)

Compute the 80th percentile of the tree heights as follows:

[tex]P(X<x)=0.80\\\\P(Z<z)=0.80[/tex]

The z-score for the corresponding probability is, z = 0.84.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\0.84=\frac{x-112}{10}\\\\x=112+(0.84\times 10)\\\\x=120.4[/tex]

Thus, the 80th percentile of the tree heights is 120.4 inches.

(c)

Compute the first quartile of the tree heights as follows:

[tex]P(X<x)=0.25\\\\P(Z<z)=0.25[/tex]

The z-score for the corresponding probability is, z = -0.67.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\-0.67=\frac{x-112}{10}\\\\x=112-(0.67\times 10)\\\\x=113.3[/tex]

Thus, the first quartile of the tree heights is 113.3 inches.

(d)

The tallest 1% of the trees, i.e. P (X > x) = 0.01.

That is, P (X < x) = 0.99.

⇒ P (Z < z) = 0.99

The corresponding z-value is, z = 2.33.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\0.99=\frac{x-112}{10}\\\\x=112+(0.99\times 10)\\\\x=121.9[/tex]

Thus, the tallest 1% of the trees are more than 121.9 inches tall.

Answer: What's the question?

Step-by-step explanation:

Answer:

500

Step-by-step explanation:

Answer:

f(x) = (x + 5)(x - 1)

Step-by-step explanation:

f(x) = (x + 5)(x - 1) has the roots of -5 and 1, when you set each factor equal to zero.

x + 5 = 0

x = -5

So, -5 is a root of the function.

x - 1 = 0

x = 1

So, 1 is the other root of the function.

f(x) = (x + 5)(x - 1) is the polynomial function with the roots of -5 and 1

Answer:start on -4 go over 3 right and up 4

Step-by-step explanation:

Answer:

Start at -4 on the y axis(the axis that goes up and down). Then draw a line from this point that goes to the right 3 squares, and up 4 squares. Then just continue the line with the same movements to the right, and opposite movements to the left.

Step-by-step explanation:

Magic

Answer:

The probability is  [tex]P(\= X  > 103.7  )  =   0.9862 [/tex]

Step-by-step explanation:

From the question we are told that

  The population mean is  [tex]\mu =  106 \  gallons[/tex]

   The population standard deviation is  [tex]\sigma  =  6 \ gallons[/tex]

    The sample size is  [tex]n  =  33[/tex]

Generally the standard deviation of sample mean is mathematically represented as  

        [tex]\sigma_{x} = \frac{\sigma }{\sqrt{n} }[/tex]

=>      [tex]\sigma_{x} = \frac{6}{\sqrt{33} }[/tex]

=>      [tex]\sigma_{x} = 1.044[/tex]

Generally the probability that the sample mean would be greater than 103.7 gallons is mathematically represented as

        [tex]P(\= X  > 103.7  )  =  P(\frac{X - \mu }{\sigma_{x}} > \frac{103.7  -  106}{1.044 }  )[/tex]

Generally  [tex]\frac{X - \mu }{\sigma_{x}}  =  Z (The \  standardized \  value \  of  \= X )[/tex]

So

[tex]P(\= X  > 103.7  )  =  P(Z > -2.203 )[/tex]

From the z table  the probability of (Z > -2.203 ) is  

     [tex]P(Z > -2.203 ) = 0.9862[/tex]

So

    [tex]P(\= X  > 103.7  )  =   0.9862 [/tex]

Answer:

74

Step-by-step explanation:

Answer:74 students ate soup

Step-by-step explanation:

37% of 200 = 74

or

.37 x 200 = 74

Answer:

3/5

Step-by-step explanation:

m = change in y / change in x

m = 3 / 5

Answer:

9and 11

Step-by-step explanation:

it also can be -9 and -11

Answer: 0.9887

Step-by-step explanation:

Let p be the probability that flights are on time.

As per given, p =70% = 0.7

Sample size : n = 8

Let x be a binomial variable that represents the number of fights are on time ( i.e. success).

Using binomial formula: [tex]P(X=x) = \ ^nC_xp^x(1-p)^{n-x}[/tex]

Now,  the probability that at least 3 flights are on time = [tex]P(X\geq 3)=1-P(X<3)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\=1-[^8C_0(0.7)^0(0.3)^8+^8C_1(0.7)^1(0.3)^7+^8C_2(0.7)^2(0.3)^6]\\\\=1-[(0.3)^8+8(0.7)(0.3)^7+\dfrac{8!}{2!6!}(0.7)^2(0.3)^6]\\\\=1-[0.00006561+0.00122472+0.01000188]\\\\=1-0.01129221\\\\=0.98870779\approx\ 0.9887[/tex]

The probability that at least 3 flights are on time = 0.9887

Answer:

13.9

Step-by-step explanation:

The mean of a set of numbers is the sum divided by the number of terms

Answer:

The 95% confidence interval  is   [tex] 2.354 <   3.526 [/tex]

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  5

    The sample  data is  3.32  2.53  3.45  2.38   3.01

Gnerally the sample mean is mathematically represented as

      [tex]\= x  =  \frac{\sum x_i}{n}[/tex]

=>    [tex]\= x  =  \frac{3.32+  2.53 +3.45+ 2.38+ 3.01 }{5}[/tex]

=>    [tex]\= x  =   2.94 [/tex]

Generally the standard deviation is mathematically represented as

     [tex]s =  \sqrt{ \frac{ \sum (x_i -  \= x )^2}{n-1} }[/tex]

=> [tex]s =  \sqrt{ \frac{  ( 3.32 -  2.94  )^2 +  ( 2.53 -  2.94  )^2+ \cdots + ( 3.01  -  2.94  )^2}{5-1} }[/tex]

=>  [tex]s =   0.472 [/tex]  

Generally the degree of freedom is mathematically represented  as

    [tex]df =  n-1[/tex]

=>  [tex]df =  5-1[/tex]

=>  [tex]df =  4 [/tex]    

From the question we are told the confidence level is  95% , hence the level of significance is  

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the t distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] at a degree of freedom of   [tex]df =  4 [/tex]  is  

   [tex]t_{\frac{\alpha }{2} ,df } =  2.77[/tex]

Generally the margin of error is mathematically represented as  

      [tex]E =t_{\frac{\alpha }{2} ,df }  *  \frac{\sigma }{\sqrt{n} }[/tex]

        [tex]E = 2.77 *  \frac{0.472 }{\sqrt{5} }[/tex]

        [tex]E = 0.586 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x -E <  \mu <  \=x  +E[/tex]

     [tex]2.94-0.586 <  2.94  + 0.586[/tex]

     [tex] 2.354 <   3.526 [/tex]

The standard normal distribution has a mean of 0 and a standard deviation of 1

Answer:

5/9

Step-by-step explanation:

2/3 • 5/2 • 2/3

1/3 • 2/5 • 2/3

multiply 1/3 for 5/2

5

-----------

3 • 2

multiply 3 for 2

5/6 • 2/3

anular el factor común 2

5/3 • 1/3

multiply 5/3 for 1/3

5

------------

3 • 3

multiply 3 for 3

5/9

the result

5/9

form decimal

0.5