Answer with explanation.

Answer:

A) 2

B) 33

C) 13

Step-by-step explanation:

Baseball =26

Football = 23

Basketball = 22

Baseball and Football (BF) = 12

Baseball and basketball (BK) = 13

Football and basketball (FK) = 14

All three (BFK) = 7

A) The total number of cities that have basketball teams is given by the cities with basketball only, added to the cities with basketball and football and cities with basketball and baseball, minus the cities with all three sports:

[tex]22=K+BK+FK-BFK\\22=K+13+14-7\\K=2[/tex]

B) The total number of cities with baseball of football is given by sum of the cities with either sport, minus the number of cities with both sports:

[tex]B\ or\ F = 23+22-12\\B\ or\ F =33[/tex]

C) If 22 cities have basketball and only 2 have basketball only, 20 cities have basketball and either baseball, football or all three sports. The number of cities with baseball or football, but not basketball is:

[tex](B\ or\ F)\cap (not\ K) = 33-20=13[/tex]

Answer:

56.76% probability that it came from store A

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Defective.

Event B: Store A.

36% of the sales are from store A

This means that [tex]P(B) = 0.36[/tex]

7% of the DVD players sold at store A are defective.

This means that [tex]P(A|B) = 0.07[/tex]

Probability of a defective DVD:

36% come from store A, and of those, 7% are defective.

100 - 36 = 64% come from store B, and of those, 3% are defective. So

[tex]P(A) = 0.07*0.36 + 0.03*0.64 = 0.0444[/tex]

What is the probability that it came from store A

[tex]P(B|A) = \frac{0.36*0.07}{0.0444} = 0.5676[/tex]

56.76% probability that it came from store A

Answer:

A or D i think..

Step-by-step explanation:

Answer:

Q1 = 33

Q3 = 49.75

D2 = 28.4

D8 = 29.6

67th percentile = 46.10

Step-by-step explanation:

Given the data:

13 13 13 20 26 28 30 34 34 34 35 35 36 37 38

41 41 41 45 46 47 47 49 52 54 54 56 62 67 82

The first quartile (Q1) ;

1/4(n + 1)

Where n = number of observations

n = 30

Q1 = 0.25(30 + 1) = 0.25 × 31 = 7.75

7 : corresponds to 30

0.75 : (34 - 30) × 0.75 = 4 × 0.75 = 3

30 + 3 = 33

Third quartile (Q3) :

3/4(n + 1)

Where n = number of observations

n = 30

Q3 = 0.75(30 + 1) = 0.75 × 31 = 23.25

23 : corresponds to 49

0.25 : (52 - 49) × 0.25 = 3 × 0.25 = 0.75

49 + 0.75 = 49.75

Determine the second decile and the eighth decile.

Second decile (D2)

((n+1) × (2)) / 10

= (30 + 1)(2)/10 = 6.2

6 : corresponds to 28 +

0.2 : (30 - 28 )× 0.20 = 0.4

28 + 0.4 = 28.4

Eight decile (D8)

((n+1) × (8)) / 10

= (30 + 1)(8)/10 = 24.8

24 : corresponds to 52 +

0.8 : (54 - 52 )× 0.80 = 1.6

28 + 1.6 = 29.6

67th percentile :

67% × n = 0.67 × 30 = 20.10

20: corresponds to 46

0.1 : (47 - 46) × (0.1) = 0.1

46 + 0.1 = 46.10

The first quartiles is 33 and third quartiles is 23.25.

The second decile is 24.8  and the eight decile is 29.6

The 67th percentile is 46.10.

Given that,

Sample of the Thomas Supply Company Inc. invoices.13 13 13 20 26 28 30 34 34 34 35 35 36 37 38.

41 41 41 45 46 47 47 49 52 54 54 56 62 67 82

We have to determine,

Determine the first and third quartiles.

Determine the second decile and the eight decile.

Determine the 67th percentile.

According to the question,

Where n = number of observations

n = 30

Then,

[tex]= \dfrac{1(30+1)}{4}\\\\= 0.2 \times 31\\\\= 6.2[/tex]

Then, 7 : corresponds to 30,

[tex](34 - 30) \times 0.75 = 4 \times 0.75 = 3\\\\30 + 3 = 33[/tex]

 And Third quartile (Q3) is; [tex]\dfrac{3(n+1)}{4}[/tex]

Where n = number of observations

n = 30

Then,

[tex]= \dfrac{3(30+1)}{4}\\\\= 0.75 \times 31\\\\= 23.25[/tex]

23 : corresponds to 49

[tex]0.25 : (52 - 49) \times 0.25 = 3 \times 0.25 = 0.75\\\\49 + 0.75 = 49.75[/tex]  

Second decile (D2) ; [tex]\dfrac{2(n+1)}{10}[/tex]

Where n = 30

Then,

[tex]= \dfrac{2(30+1)}{10}\\\\= 0.2 \times 31\\\\= 6.1[/tex]

6 : corresponds to 28,

[tex](30 - 28 ) \times 0.20 = 0.4\\\\28 + 0.4 = 28.4[/tex]

 And the Eight decile (D8); [tex]\dfrac{8(n+1)}{10}[/tex]

Where n = 30,

Then,

[tex]\dfrac{(30 + 1)(8)}{10} = 24.8[/tex]

24 : corresponds to 52,

[tex](54 - 52 ) \times 0.80 = 1.6\\\\28 + 1.6 = 29.6[/tex]

67% × n = 0.67 × 30 = 20.10

20: corresponds to 46

0.1 : (47 - 46) × (0.1) = 0.1

46 + 0.1 = 46.10

The 67th percentile is 46.10

To  know more about Percentile click the link given below.

https://brainly.com/question/16842626

Answer:

(D)d>2.5

Step-by-step explanation:

Given that the circumference of a circle is greater than 8 meters.

For a circle of diameter d:

Circumference[tex]=\pi d[/tex]

Since [tex]\pi =3.14[/tex]

[tex]3.14d>8[/tex]

To obtain possible values of the diameter d, we divide both sides of the equation by 3.14.

[tex]\dfrac{3/14d}{3.14}>\dfrac{8}{3.14}\\\\ d>2.5$ (correct to 1 decimal places)[/tex]

The correct option is D.

Answer:

To simplify the answer above, D

Step-by-step explanation:

Answer:

x =42

Step-by-step explanation:

(3x+12)+x=180

Combine like terms

4x +12 = 180

Subtract 12 from each side

4x +12-12=180-12

4x = 168

Divide by 4

4x/4 =168/4

x =42

Answer:

x=42

Step-by-step explanation:

180-12=168

168 divided by 4 = 42

x=42

Answer:

1/2 hour

Step-by-step explanation:

I am assuming you meant "lives 5km"

The first km would take 1/4 an hour because she is going 4km/h for one hour. One hour she would go 4km but we only need 1 mile so it would be cut to a fraction.

The same fraction goes for the bus. 4 is 1/4 of 16 so you would have to add them together and have 1/2 and hour to get home.

Answer:

x=5

Step-by-step explanation:

5x- 7 = 18

5x=18+7

5x=25

Therefore, 5 will cancel 25 five(5) times.

x= 5.

Answer:

x = 5

Step-by-step explanation:

Since AB is the bisector, so MO is equal to NO

MO = NO

5x-7 = 18

5x = 18+7

5x = 25

Dividing both sides by 5

x = 5

Answer:

Area = 5/18 square feet

Step-by-step explanation:

To find the area of a rectangle, you need to multiply 5/12 and 2/3. You multiply the numerators and then multiply the denominators. Then you should get 10/36. This fraction can be simplified into 5/18. To do this find the greatest common factor of 10 and 36 (you'll get 2 as the GCF). Then divide 2 to both the numerator and denominator.

Answer:

[tex]\left[\begin{array}{ccc}2&-6&2\\0&3&-2\\0&2&2\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]= \left[\begin{array}{ccc}1\\-5\\-3\end{array}\right][/tex]

Step-by-step explanation:

Given system of equations are

2x-6y-2z = 1

3y - 2z = -5

2y + 2z = -3

given

2 x - 6 y - 2 z = 1

0 x + 3 y - 2z = -5

0 x +2y + 2 z = - 3

The Matrix form of the given system of equations

A X = B

[tex]\left[\begin{array}{ccc}2&-6&2\\0&3&-2\\0&2&2\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]= \left[\begin{array}{ccc}1\\-5\\-3\end{array}\right][/tex]

Answer:

Option B; EF = ( About ) 4.47 units, Perimeter of Δ EFG = ( About ) 12.94 units

Step-by-step explanation:

If we were to consider the height of this triangle EFG, it would be 4 units of length, supposedly splitting base GF into two ≅ parts, each 2 units of length. First let us name the point drawn to base GF ⇒ point H, so that the height of Δ EFG ⇒ EH. Now as EH splits GF into two ≅ parts, by Converse to Coincidence Theorem, Δ EFG ⇒ Isosceles Δ;

EH and FH are legs of a right triangle EFH, so that Pythagorean Theorem can be applied to solve for the length of EF and EG, knowing that as Δ EFG ⇒ Isosceles Δ, EF ≅ EG;

( EH )^2 + ( FH )^2 = ( EF )^2,

( 4 )^2 + ( 2 )^2 = ( EF )^2 ⇒ take square of 4 & 2,

16 + 4 = ( EF )^2 ⇒ combine like terms,

( EF )^2 = 20 ⇒ take square root on either side to solve for EF,

EF = √ 20 = ( About ) 4.47 units = EG,

Perimeter of Δ EFG = EF + GF + EG = 4.47 + 4 + 4.47 = ( About ) 12.94 units,

Solution; Option B

Answer:

[tex] z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903[/tex]

And we can find this probability to find the answer:

[tex] P(z<-0.903)[/tex]

And using the normal standar table or excel we got:

[tex]  P(z<-0.903)=0.1833 [/tex]

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(0.917,0.303)[/tex]  

Where [tex]\mu=0.917[/tex] and [tex]\sigma=0.303[/tex]

We have the following info from a sample of n =37:

[tex] \bar X= 0.872[/tex] the sample mean

And we want to find the following probability:

[tex] P(\bar X \leq 0.872)[/tex]

And we can use the z score formula given by;

[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And if we find the z score for the value of 0.872 we got:

[tex] z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903[/tex]

And we can find this probability to find the answer:

[tex] P(z<-0.903)[/tex]

And using the normal standar table or excel we got:

[tex]  P(z<-0.903)=0.1833 [/tex]

Answer:

42 student tickets and 98 adult tickets

Step-by-step explanation:

Let's call the number of student tickets 's' and the number of adult tickets 'a'.

Then, we can write the two equations below:

5s + 8a = 994

a = 2s + 14

Using the value of 'a' from the second equation in the first one, we have:

5s + 8*(2s + 14) = 994

5s + 16s + 112 = 994

21s = 882

s = 42

Now, finding the value of 'a', we have:

a = 2*42 + 14 = 98

Answer:

The total sold was 98 tickets for adults and 42 for students.

Step-by-step explanation:

In order to calculate the number of tickets of each kind sold we need to create a system of equations with the given information. The first equation can be created is that the sum of adult tickets multiplied by its cost with the student tickets also multiplied by its cost must be equal to the total value of tickets sold, so:

[tex]5*\text{students} + 8*\text{adults} = 994[/tex]

We also know that the number of adult tickets was 14 more than 2 times the number of student tickets, therefore:

[tex]\text{adults} = 2*\text{students} + 14[/tex]

If we apply the second expression on the first one we can solve for the number of tickets sold to students, we have:

[tex]5*\text{students} + 8*(2*\text{students} + 14)= 994\\5*\text{students} + 16*\text{students} + 112 = 994\\ 21*\text{students} = 994 - 112\\\text{students} = \frac{882}{21} = 42[/tex]

We can use this value to find the number of adults ticket sold:

[tex]\text{adults} = 2*42 + 14\\\text{adults} = 98[/tex]

The total sold was 98 tickets for adults and 42 for students.

Answer:

[tex]1[/tex]

Step-by-step explanation:

[tex]log(6)-log(16)+log(4)-log(3)+log(20)[/tex]

[tex]0.77815125038-1.20411998266+0.60205999132-0.47712125472+1.30102999566[/tex]

[tex]=0.99999999998[/tex]

Answer:

$5759.12

Step-by-step explanation:

$5759.12

At the end of the year, the compound interest on her loan is: $5000(1+0.1212)12=$5000(1.01)12≈$5634.12. To pay off the loan at the end of the year, she pays 5634.12+125=$5759.12.

Answer:

the standard error of the proportion is 0.0272

Step-by-step explanation:

We have that if the sample size is greater than 5% of the entire population, a finite population correction factor (fpc) is multiplied with the standard error :

fpc = [tex]\sqrt{\frac{N -n}{N -1} }[/tex]

We know that N = 250 n = 91, replacing:

fpc = [tex]\sqrt{\frac{250 - 91}{250 -1} }[/tex]

fpc = 0.799

Now, the formula would then be:

SE  = [tex]\sqrt{\frac{p * (1 -p)}{n} }[/tex]*fpc

Now replacing, knowing that p = 0.12

SE= [tex]\sqrt{\frac{0.12 * (1 - 0.12)}{91} }[/tex]*0.799

SE = 0.0272

So the standard error of the proportion is 0.0272

Answer:

63 cubic inches

Step-by-step explanation:

You have to first find the volume of each mold:

6 × 4 × 2= 48 cubic inches

3 × 5 × 1= 15 cubic inches

Add these two volumes together to find the overall volume of the whole sand castle.

48+15= 63 cubic inches

Answer:

The whole castle can hold 63 in² of sand.

Step-by-step explanation:

First, find the volume of the first mold.

V = whl          Substitute

V = (6)(2)(4)    Multiply

V = 48 in²

Now, find the volume of the second mold.

V = whl          Substitute

V = (5)(1)(3)    Multiply

V = 15 in²

Add together both volumes to find the volume of the whole castle.

48 + 15 = 63 in²

Answer:

  (13, 11)

Step-by-step explanation:

The vertex of g(x) = |x| is (0, 0).

When the function is transformed to ...

  f(x) = g(x -h) +k

the vertex is moved to (h, k).

Here, we have (h, k) = (13, 11), translating the function to ...

  f(x) = |x -13| +11

and moving the vertex to (13, 11).

Answer:

D. (13, 11)

Step-by-step explanation:

EDGE 2020 :)

Answer:

we will mix 55 liters of 20% solution and 20 Liters of 50% solutions.

Step-by-step explanation:

let the 20% solution = x liters

let the 50% solution = y liters

total solution of the mixture of the two solutions in % = 28%

total solution of the mixture of the two solutions in liters = 75 liters

considering the total solutions given, we will have the following equations if we mix the solutions in equal proportion;

20x + 50y = 28 (75)

0.2x + 0.5y = 0.28(75)

0.2x + 0.5y = 21 -------equation 1

Also,

x + y = 75 ------equation 2

y = 75 - x  

(substitute this into equation 1)

0.2x + 0.5(75 - x) = 21

0.2x + 37.5 - 0.5x = 21

0.2x - 0.5x = 21 - 37.5

-0.3x = -16.5

x = -16.5 / -0.3

x = 55 liters

Recall, y = 75 - x

y = 75 -55

y = 20 Liters

Thus, we will mix 55 liters of 20% solution and 20 Liters of 50% solutions.

Answer:no the vertices of the image and pre image don’t correspond

Step-by-step explanation:

Just did it

No, the vertices of the image and pre-image do not correspond

Step-by-step explanation:

It’s correct

Answer:

D.

Step-by-step explanation:

Question:

Identify the like terms in the algebraic expression

[tex]\frac{2x}{5} -5.2y +2.2 + \frac{x}{3}[/tex]

Answer:

The like terms in the given expression are [tex]\frac{2x}{5}[/tex] and [tex]\frac{x}{3}[/tex]

Step-by-step explanation:

Given:

[tex]\frac{2x}{5} -5.2y +2.2 + \frac{x}{3}[/tex]

Required:

Identify the like terms

To solve this, we need to understand what like term is all about.

Like term simply refer to terms or entities that have the same variable and exponents (power)

From the expression above, there are two variables;

x and y.

To get the like terms of x and/or y;

we simply look for another occurrence of x and/or y in the expression; and this occurrence must have the same exponent as x and/or y.

For x

[tex]\frac{2x}{5}[/tex] and [tex]\frac{x}{3}[/tex] have the same variable and exponent; Hence, they are like terms

There's only one occurrence of variable y;

Conclusively, the like terms in the given expression are [tex]\frac{2x}{5}[/tex] and [tex]\frac{x}{3}[/tex]

2x/5 and -5.2y

hope this helps

Answer:

Given:

Sample size, n = 350

Sample proportion, P' = 0.21

H0 : p = 0.16

Ha : p ≠ 0.16

a) A 90% confidence interval for P.

Significance level = 1 - confidence interval = 1 - 0.90 = 0.10

For Z critical, we have:

Z critical = [tex] Z_0_._1_/_2 = Z_0_._0_5 = 1.645 [/tex] (using z table)

Standard error, S.E = [tex] \sqrt{\frac{P'(1 - P')}{n}} = \sqrt{\frac{0.21(1 - 0.21)}{350}} = 0.02177 [/tex]

Margin of error, E = 1.645 * 0.02177 =0.03581

The 90% confidence interval =

0.21 ± 0.03581

The lower limit: 0.21 - 0.03581 = 0.17419

The upper limit: 0.21+0.03581 =0.24581

b) Based on the confidence interval at significance level = 0.10,

We reject null hypothesis, H0, since 0.16 is not cointained in the confidence interval. We conclude that p ≠ 0.16.

c) Standard error is based on sample proportion p^ while standard deviation is based on hypothesized proportion Po.

d) Standard error is used to compute the confidence interval.

Step-by-step explanation:

1. 45/5 = 9

2. 53 is not a multiple of 5

3. 164 - 20 = 144

4. 372 rounded is 400.

5. 5 edges

6. 382 + 200 = 582

7. 6500 meters

8. -6

9. 65 cm

10. 90/2 = 45

11. idk since i live in us

12. 8 * 3 = 24

13. July 30th

14. 6

15. 28

16. 2.5 * 3 = 7.50

Answer:

the answer is Point G

Answer:

  5.7

Step-by-step explanation:

The altitude divides right triangle ABC into similar right triangles ADB and BDC. The ratios of short leg to long leg will be proportional in these similar triangles, so you have ...

  AD/BD = BD/CD

Cross multiplying gives ...

  AD·CD = BD²

  (x+3)(2x+3) = 5²

  2x² +9x = 16 . . . . . perform the multiplication, subtract 9

  2(x² +4.5x) = 16

  2(x² +4.5x +2.25²) = 16 +2(2.25²) . . . . . add 2(2.25²) to complete the square

  2(x +2.25)² = 26.125 . . . . . write as a square

  x +2.25 = √13.0625 . . . . . .divide by 2, take the positive square root

  x = -2.25 +√13.0625 . . . . subtract 2.25 to find x

We want the value of CD, so ...

  CD = 2x +3 = 2(-2.25 +√13.0625) +3

  CD = -1.5 +2√13.0625 ≈ 5.7284

The length of CD is about 5.7 units.

Answer: 2sqrt(33)

Step-by-step explanation:

We want to find the length of the line y = 4 in the circle x^2+y^2=49.

Substitute y = 4 to get x^2 = 33, so x = sqrt(33) or -sqrt(33).

That means the total length is sqrt(33) * 2 = 2sqrt(33).

Hope that helped,

-sirswagger21

The approximate length of the portion of the line is 11.49.

Circle centered at (h,k) with radius r is  [tex](x-h)^{2} + (y-k)^{2}=r^{2}[/tex]

A circle of a radius 7 centered at the origin:

[tex]x^{2} +y^{2}=49[/tex]   ......... (i)

[tex]y=4[/tex]               ..........(ii)

We have a circle and a line.  We need to find the points of

intersection and find the distance between those two points.

Replace y with 4 in the 1st equation and solve for x.

[tex]x^{2} +4^{2} =49\\x^{2} =49-16\\x^{2} =33\\[/tex]

[tex]x=[/tex] ±[tex]\sqrt{33}[/tex]

We have the 2 values of x where the line intersects the circle.

Plug those into one of the original equations to find the associated

y values.

[tex]\sqrt{33} ^{2} +y^{2} =49\\y^{2}=49-33\\y=4[/tex]

Two points on the circle are [tex](\sqrt{33} , 4)[/tex] and [tex](-\sqrt{33} , 4)[/tex]

Using the distance formula:-

[tex]=\sqrt{(4-4)^{2}+(-\sqrt{33}-\sqrt{33)} ^{2} } \\=\sqrt{(2\sqrt{33}) ^{2} } \\=2\sqrt{33}\\[/tex]

≈ 11.49

Therefore, the length of the portion of the line is approximately 11.49.

For more information:

https://brainly.com/question/24214108

Answer:

[tex]i[/tex]

Step-by-step explanation:

[tex]\sqrt{-1} =i[/tex]

[tex]i[/tex]  is an imaginary number that represents the square root of -1.