Angle RSU is complementary to angle UST. Angle QSR is congruent to angle RSU.

Lines Q, R, U, and T extend from point S from left to right. Angle R S T is a right angle.
Which statement is true about angles UST and QSR?

They are complementary.
They are supplementary.
They are congruent.
They are obtuse.

Answers

Answer 1

Answer:

Statement 1 is correct

Angles UST and QSR are complementary.

Step-by-step explanation:

Complementary angles are those angles whose addition gives result of 90°

Congruent angles are those angles which are equal to each other. We can say that there values are same.

Here angle RSU is complementary to angle UST.

Therefore there addition is equal to 90°

∠RSU + ∠UST =  90° - (i)

Here angle QSR is congruent to angle RSU.

Therefore their values are equal.

It means ∠QSR =∠RSU -(ii)

From equation (i) and (ii) we get

∠QSR + ∠UST =  90°

So angles UST and QSR are complimentary angles.

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Angle RSU Is Complementary To Angle UST. Angle QSR Is Congruent To Angle RSU.Lines Q, R, U, And T Extend
Answer 2

Answer:

Step-by-step explanation:

A


Related Questions

A water tank in the shape of an inverted circular cone has a base radius of 3 m and height of 7 m . If water is being pumped into the tank at a rate of 4.3 m^3 / min , find the rate at which the water level is rising when the water is 3.5 m deep. (Round your answer to three decimal places if required)

Answers

The water level increases by 0.608 meters per minute when the water is 3.5 m deep

How to determine the rate?

The given parameters are:

Radius, r = 3Height, h = 7Rate in, V' = 4.3m^3/min

The relationship between the radius and height is:

r/h = 3/7

Make r the subject

r = 3h/7

The volume of a cone is;

[tex]V = \frac 13\pi r^2h[/tex]

This gives

[tex]V = \frac 13\pi (\frac{3h}{7})^2h[/tex]

Expand

[tex]V = \frac{3h^3}{49}\pi[/tex]

Differentiate

[tex]V' = \frac{9h^2}{49}\pi h'[/tex]

Make h' the subject

[tex]h' = \frac{49}{9\pi h^2}V'[/tex]

When the water level is 3.5.

We have:

[tex]h' = \frac{49}{9\pi * 3.5^2}V'[/tex]

Also, we have:

V' = 4.3

So, the equation becomes

[tex]h' = \frac{49}{9\pi * 3.5^2} * 4.3[/tex]

Evaluate the products

[tex]h' = \frac{210.7}{346.36}[/tex]

Evaluate the quotient

h' = 0.608

Hence, the water level increases by 0.608 meters per minute

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How much of an alloy that is 30% copper should be mixed with 200 ounce of an alloy that is 70% copper in order to get an alloy that is 40% copper?

Answers

The alloy of copper will be 600 ounces.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

Let us represent

Number of ounce of 30% copper = x

Hence, our Equation will be given below:-

x × 30% + 200 × 70% = (x + 200) × 40%

0.3x + 140 = (x + 200)0.4

0.3x + 140 = 0.4x + 80

Collect like terms

0.4x - 0.3x = 140 - 80

0.1x = 60

x = 60/0.1

x = 600 ounces

Therefore the alloy of copper will be 600 ounces.

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How many square feet of tile is needed for a room of 24 foot x 24 foot

Answers

Answer:576

Step-by-step explanation:

24 squared is 576

Find the equation of the line parallel to y = 2x - 4 that runs through the point (-2, 4).
y = 1/2x + 4

y = 2x + 8

y = 2x + 4

y = -1/2x + 8

Answers

Answer:

y = 2x + 8

Explanation:

Equation: y = 2x - 4

Comparing it with slope intercept form "y = mx + b" where 'm' is slope and 'b' is y-intercept. This function has slope: 2 and y intercept of -4

Parallel lines has same slope.

Passes through (-2, 4)

[tex]\sf y - y_1 = m(x - x_1)[/tex]

[tex]\sf y - 4 = 2(x - (-2))[/tex]

[tex]\sf y - 4 = 2(x + 2)[/tex]

[tex]\sf y = 2x + 4 + 4[/tex]

[tex]\sf y = 2x + 8[/tex]

Answer: y = 2x + 8

Step-by-step explanation:

This is a fairly simple problem. I hope this helps!

So, to find a line parallel, it's simple, and it only requires that for the other line to have the same slope and a different y-intercept (or same "m" and different "b" in the equation y = mx + b).

To find a line parallel to a point is slightly harder, but don't worry, I'll teach you how.

To do this, we have to recognize the point. The point given is (-2, 4) where -2 is the x-value and 4 is the y-value. Remember, points always go by (x, y).

So, we set y to 4, and we set x to -2.

When testing out lines that are parallel to a point, you must always be careful that you end up with the same value. Such as 4 = 4 or 8 = 8, etcetera.

We get:

4 = 2 × (-2) + 8

Simplifying, we get:

4 = -4 + 8

Adding -4 to 8, we get 4:

4 = 4

Thus, y = 2x + 8 is parallel to the point (-2, 4)

NO LINKS!! Please help me with this problem​

Answers

Answer:

23.1 years  (nearest tenth)

Step-by-step explanation:

Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]

where:

A = final amountP = principal amountr = interest rate (in decimal form)n = number of times interest applied per time periodt = number of time periods elapsed

Given:

A = $1200P = $600r = 3% = 0.03n = 12 (as compounded monthly)t = years

Substitute the given values into the formula and solve for t:

[tex]\implies \sf 1200=600\left(1+\dfrac{0.03}{12}\right)^{12t}[/tex]

[tex]\implies \sf 1200=600\left(1.0025\right)^{12t}[/tex]

[tex]\implies \sf \dfrac{1200}{600}=\left(1.0025\right)^{12t}[/tex]

[tex]\implies \sf 2=\left(1.0025\right)^{12t}[/tex]

Take natural logs:

[tex]\implies \sf \ln 2=\ln \left(1.0025\right)^{12t}[/tex]

[tex]\implies \sf \ln 2=12t\ln \left(1.0025\right)[/tex]

[tex]\implies t=\dfrac{ \ln 2}{12 \ln (1.0025)}[/tex]

[tex]\implies t=23.13377513...[/tex]

[tex]\implies t=23.1\: \sf years \:\:(nearest\:tenth)[/tex]

The money will double in value in approximately [tex]\boxed{\sf 23.1}[/tex] years.

Used formula

[tex]\boxed{\sf A=P(1+\dfrac{r}{n})^{nt}}[/tex]

[tex]\\ \implies \sf 1200=600\left(1.0025\right)^{12t}[/tex]

[tex]\\ \implies \sf \dfrac{1200}{600}=\left(1.0025\right)^{12t}[/tex]

[tex]\\ \implies \sf 2=\left(1.0025\right)^{12t}[/tex]

Apply natural logarithm on both sides

[tex]\implies \sf \ln 2=\ln \left(1.0025\right)^{12t}[/tex]

[tex]\\ \implies \sf \ln 2=12t\ln \left(1.0025\right)[/tex]

[tex]\\ \implies t=\dfrac{ \ln 2}{12 \ln (1.0025)}[/tex]

[tex]\\ \implies t=23.1years[/tex]

Question 3(Multiple Choice Worth 4 points)
Which expression is equivalent to 73.7-57
0 72
0 77
17

Answers

Answer: [tex]\frac{1}{7^{2}}[/tex]

Step-by-step explanation:

Using the exponent rule [tex]a^{b} \cdot a^{c}=a^{b+c}[/tex], we get that

[tex]7^{3} \cdot 7^{-5}=7^{-2}[/tex]

Then, using the exponent rule [tex]a^{-b}=\frac{1}{a^b}[/tex], we get that

[tex]7^{-2}=\boxed{\frac{1}{7^{2}}}[/tex]

Value of x or y so that the line through the points has the given slope:

(X,9) and (9,-3), slope is -6/7

Sorry if it’s not worded great.

Answers

If we want the slope to be -6/7, then the value of x must be -5.

How to find the value of x?

Remember that if a linear equation passes through (x₁, y₁) and (x₂, y₂), then the slope is:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Here we have the points (x, 9) and (9, -3), and the slope must be -6/7, so we need to solve:

[tex]\frac{- 3 - 9}{9 - x} = \frac{-6}{7} \\\\\frac{-12}{9 - x} = \frac{-12}{14}[/tex]

Where on the second line we multiplied and divided the right fraction by 2.

Comparing the fractions, we see that we must have:

9 -x = 14

9 - 14 = x

-5 = x

So the value of x must be -5.

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If you could please answer this that would be awesome!

Please graph it!

Answers

The graph is attached with the answer, This is looking like a horizontal staircase

What is a Step Function ?

A step function is a piece wise function whose all pieces are horizontal line or a point.

It is given in the question to graph the interval

-2 ≤x≤2

for f(x) = |x+3|

-2    1

-1     2

0     3

1      4

2     5

The graph is attached with the answer.

This is looking like a horizontal staircase

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What is the slope of the line that passes through the points (6, 2) and (4, 10)? −4 −14 14 4

Answers

Answer:

-4

Step-by-step explanation:

The equation for slope is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

m: Slope

(6, 2) = [tex](x_1, y_1)[/tex]

(4, 10) = [tex](x_2, y_2)[/tex]

Substitute these values into the equation:

[tex]m=\frac{10-2}{4-6}=\frac{8}{-2}=-4[/tex]

Therefore the slope is -4.

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SOLVING

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

What is the slope of the line that passes through the points? 2 points given

[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]

The formula used here, is [tex]\bf{\dfrac{y2-y1}{x2-x1}}[/tex].

[tex]\rule{300}{1.7}[/tex]

[tex]\bf{\dfrac{10-2}{4-6}}[/tex] | subtract

[tex]\bf{\dfrac{8}{-2}}[/tex] | evaluate

[tex]\bf{-4}[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\bf{Result:}[/tex]

           [tex]\bf{=Slope\;-4}[/tex]

[tex]\boxed{\bf{aesthetic\not101}}[/tex]

Help me and i'll help you earn more points if the question is right

Answers

-21x^3 - 8x^3 = -29x^3
-7/4x^(1/2) - 0 = -7/4x^(1/2)
-6x^(1/4)
-12x^(-1/2)
12x^(-1/4)
14x^4

Therefore, the correct option is the 2nd one.

Please help, will give the brainliest!


(J) 80 • 125

(K) (80+65) • 125

(L) (65 • 80) + (80 • 60)

M (65•80)+(80•60)

N (65•80)+ 1/2 (125 • 100)

Answers

Answer:

option N is the correct option, apply Formula of area of rectangle and triangle by splitting figure into 2 parts

What are the zeros of the quadratic function f(x)=6x^2+12x-7

Answers

Answer:

[tex]A) \ x=-1 \ ^ +_-\frac{\sqrt{13} }{\sqrt{6}}.[/tex]

Step-by-step explanation:

if to solve the given equation, then

D=6²+42=78;

[tex]\left[\begin{array}{ccc}x=\frac{-6-\sqrt{78}}{6} \\x=\frac{-6+\sqrt{78}}{6} \end{array} \ = > \ \left[\begin{array}{ccc}x=-1-\sqrt{\frac{13}{6} } \\x=-1+\sqrt{\frac{13}{6} } \end{array}[/tex]

Find the area of the shaded portion of the
figure. All angles are right angles.
Dimensions are in inches.
3
8
5

Answers

Answer:  22 square inches

======================================================

Explanation:

The white rectangle is 3 by 6 with area of 3*6 = 18 square inches.

The larger rectangle is 8 by 5 with area of 8*5 = 40 square inches.

The difference of these will get us the shaded area:

40 - 18 = 22 square inches

The credit remaining on a phone card (in dollors) is a linear function of the total calling trime made with the card ( in minutes). The remaining credit after 22 minutes is $36.70, and the remaining credit after 52 mintues is $32.20. What is the remaining credit after 85 mintues of calls?

Answers

After 85 minutes of calls, there are $27.25 left on the card.

What is the remaining credit after 85 minutes of calls?

A linear equation in slope-intercept form is:

y = a*x + b

Where a is the slope.

If the line passes through two points (x₁, y₁) and (x₂, y₂) the slope is:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

In this case, we know that the line passes through the points (22, 36.7) and (52, 32,20)

(points of the form (time, dollars)).

So the slope is:

[tex]a = \frac{32.2 - 36.7}{52 -22} = -0.15[/tex]

The linear equation is then:

y = -0.15*x + b

To find the value of b, we use the point (22. 36.7)

36.7 = -0.15*22 + b

36.7 + 0.15*22 = b = 40

Then the linear equation is:

y = -0.15*x +40

The amount remaining in the credit card after 85 minutes is given by evaluating the above equation in x = 85.

y = -0.15*85 + 40 = 27.25

This means that after 85 minutes of calls, there are $27.25 left on the card.

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distribute 5x(3x+7)
help asap

Answers

Answer:

The Answer is 50 or 50x

Answer: 15x^2+35x ✅

Step-by-step explanation:

Hii, do you need to distribute [tex]\boldsymbol{5x(3x+7)}[/tex]? No problem! (:

How to Distribute?

We can solve problems like this one by using what is known as the "distributive property". What it says is: If you have a term that comes before the parentheses, you multiply it times every single term in the parentheses. Let me show you what I mean...

[tex]\twoheadrightarrow\sf 5x(3x+7)[/tex]

[tex]\bullet[/tex] Multiply 5x tmes 3x and 7 - you will obtain

[tex]\twoheadrightarrow\sf 15x^2+35x[/tex] (if we multiply x times x we obtain x²)

Voila! There's our solution, cheers! (:

--

Hope that this helped! Best wishes.

[tex]\it Reach\quad far.\:Aim\quad high. \,Dream\quad big.[/tex]

[tex]\bigstar\underbrace[/tex]

--

The law of cosines is a² + b² - 2abcosC = c². Find the value of 2abcosC.
A. 20
B. 40
C. 37
D. -40​

Answers

Answer:

C

Step-by-step explanation:

a = 4

b = 5

c = 2

C = arccos((a² + b² - c²) / 2ab)

C = arccos((16 + 25 - 4) / 2(4)(5))

C = arccos(37 / 40)

C = 22.33°

2abcosC

2(4)(5)cos(22.33)

40(0.925)

37

Option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.

What is Trigonometry?

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

We have from law of cosines that a² + b² - 2abcosC = c²

We have to find the value of 2abcosC.

Now let us find the value of C

C = arccos((a² + b² - c²) / 2ab)

C = arccos((16 + 25 - 4) / 2(4)(5))

C = arccos(37 / 40)

C = 22.33°

Now plug in the value of C in  2abcosC.

2abcosC

=2(4)(5)cos(22.33)

=40(0.925)

=37

Hence, option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.

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A motorboat moves across a lake at a constant speed. When it begins, it is 64 km from the shore. After 17 minutes, it is 30 km from the shore. Which function describes the motorboat's distance from the shore?

A. y=-17x+30
B. y=2x+64
C. y=-17x+64
D. y=-2x+64

Please solve fast!
I am giving a lot of points!

Answers

Answer:

y = -2x + 64

Explanation:

The x represents the time in minutes and y represents distance in km.

Determine coordinates: (0, 64), (17, 30)

Find slope:

[tex]\sf slope : \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

[tex]\rightarrow \sf slope \ (m) : \dfrac{30-64}{17-0} = -2[/tex]

Find equation:

[tex]\sf y- y_1 = m(x - x_1)[/tex]

[tex]\sf y - 64 = -2(x - 0)[/tex]

[tex]\sf y = -2x + 64[/tex]

Statement: "Three less than four times a number is greater
than or equal to 41."

Answers

Answer:

x≥11

Step-by-step explanation:

4x-3≥41

4x≥41+3   -44

x≥44/4 = 11


Find the domain and range of the function graphed below. Write your answers in interval notation.

Answers

Answer:

Domain: [tex][1, \infty)[/tex]Range: [tex](-\infty, -2][/tex]

Step-by-step explanation:

The domain is the set of x-values and the range is the set of y-values.

At school B, 108 year 8 students study French.
This is 60% of the year group.
How many students do not study French in year 8 in school B?

Answers

Step-by-step explanation:

108 = 60%

1% = 60%/60 = 108/60 = 1.8

100% = 1%×100 = 1.8×100 = 180

how many do not study French ?

the remainder of the students. that is 40% (100% - 60%) or 72 students (40×1.8 or simply 180-108).

Answer:

72 students do not study French.

Step-by-step explanation:

60% = 108 students

1. 108 ÷ 60 = 1.8 ( this is to find 1% of the students)

2. 1.8(1%) × 40 = 72

To check the answer:

108 + 72 = 180

180 × 60% = 108

Your load is a container full of water. The container measures
1.0m x 1.25m x 1.1m and weighs 50kg when empty. Since 1 cubic
metre of water weighs 1 tonne, find the weight of the load

Answers

Answer:

1282kg

Step-by-step explanation:

1.0*1.12*1.1=1.232 tonnes

50kg + 1232kg = 1282kg

Hope this helps :)

the weight is 1282 kg

If I=$312.50 R=25% T=0.25 what is P

Answers

Step-by-step explanation:

please mark me as brainlest

If you drive 72 miles and use 6 gallons of gas, what is your rate

Answers

Answer:

Well, it depends if you are asking the rate per gallon it would be 12 miles per gallon.

the amount of money sue needs to pay (m) equals $30 to go to an apple orchard and pick apples plus $5 for every bushel of apples (b) she takes home

Answers

the elegante is aborto 3


In the 30-60-90 triangle below, side s has a length of.
length of
30
90⁰
S
10
60"
A. 5.2: 5.2
B. 5,10,3
and side q has a

Answers

Answer: C, 5, 5√3

Step-by-step explanation:

The short leg of a 30-60-90 triangle equal half the hypotenuse, 10/2 = 5. The long leg equals √3 times the short leg, 5*√3 = 5√3.

Use the property of real numbers to write the expression 2/5 x (-7)x 5/2

Answers

The simplified form of the expression 2/5 x (-7)x 5/2 would be -7.

How to solve the expression?

When two fractions are multiplying each other, the numerator of both fractions multiplies each other, likewise the denominator of both fractions respectively.

Use the property of real numbers to write the expression

[tex]\dfrac{2}{5} \times (-7) \times \dfrac{ 5}{2}\\\\\dfrac{10}{10} \times (-7) \\\\-7 \times 1\\\\= -7[/tex]

Therefore, The simplified form of the expression would be -7.

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Find the inverse of the function y = 3x + 5 Find the inverse of the function y=3x+5​

Answers

Answer:

First Inverse function= f^-1(x)=x/3-5/3

Second Inverse function=f^-1(x)=x/3-5/3

Step-by-step explanation:

Transportation officials tell us that 60% of drivers wear seat belts while driving. Find the probability that more than 562 drivers in a sample of 900 drivers wear seat belts.

Answers

The  probability that more than 562 drivers is 0.9328

What is probability?

It is a branch of mathematics that deals with the occurrence of a random event.

Given: p = 0.60

n = 900

Let X denote the number of drivers that wear a seat belt,

P(X > 562)

[tex]\mu[/tex] = n*p = 900(0.60) = 540

[tex]\sigma^{2}[/tex]= n*p*(1-p)

=900*0.60*0.40

=216

P(X >562) = Pr( Z > 1.4976)

                = 0.9328

Hence, the probability that more than 562 drivers is 0.9328

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What negative Z-score (standard score) would the area under the curve be 0.8621

z* = _______​

Answers

0.8721 = z because its have a asymptote there

Look at the photo and answer it pls

Answers

Answer:

There isn't a photo

Step-by-step explanation:

There is no photo

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When Madame Villeneuve set off from the coast to visit Paris, she left Pauline in a convent. The young woman spent her time studying with the nuns and went so far in her training that she asked to become a nun herself and remain in the convent. The nuns agreed, which enraged Madame Villeneuve. She rushed to a judge, demanding to have her property back. Was Pauline a free woman, a bride of Christ, or an item to be bought, sold, and warehoused when she was not in use?Twenty-three years earlier, King Louis XIV had issued a set of rules that defined slavery as legal in the French sugar islands. But when two slaves managed to reach France, he freed themsaying they became free "as soon as they [touched] the soil" of France. The judges sided with Paulineshe was real to them, human, not a piece of property. For Pauline's judges, as for King Louis, slavery far off across the seas was completely different from enslaved individuals in France.Slave owners fought back, arguing that owners should be able to list their slaves as property when they arrived in France and take them with them when they left. Though most parts of France agreed to this, lawmakers in Paris hesitated. Pierre Lemerre the Younger made the case for the slaves. "All men are equal," he insisted in 1716exactly sixty years before the Declaration of Independence.To say that "all men are equal" in 1716, when slavery was flourishing in every corner of the world and most eastern Europeans themselves were farmers who could be sold along with the land they worked, was like announcing that there was a new sun in the sky. In the Age of Sugar, when slavery was more brutal than ever before, the idea that all humans are equal began to spreadtoppling kings, overturning governments, transforming the entire world.How do the details in the passage support the central idea?They compare the end of slavery in the French colonies with the end of slavery in other colonies.They provide details about the final few years of slavery in Europe and its many colonies.They provide examples of how laws and attitudes about equality changed in France.They explain why enslaved people entered convents in an attempt to gain their freedom. what types of physical drives does windows disable defragmenting, but provides another method of optimization? . Reading a stream of consciousness narrative is like _____ Now that you've learned some vocabulary relating to nature and the environment, it's time to talk with your classmates using what you've learned. pay particular attention to subject / verb agreement as always, and make sure you are using your new vocabulary correctly. Imagine that you are preparing to do an experiment in the location pictured below. To prepare for your experiment, you need to gather some data about the location. What are two pieces of qualitative data that you will collect about this location? What are two pieces of quantitative data that you will collect about this location? Be sure to distinguish which data is qualitative and which is quantitative.