Physics College

An NFL prospect running the 40-yd dash (Otherwise known as the 36.6 m dash). He accelerates at 4.9 m/s² to a final velocity of 8.17 m/s then finishes the rest of the dash at that velocity. What was this prospect's 40-yd dash time?

Thanks in advance!!​

Answers

Answer 1

The NFL prospect's 40-yard dash time is approximately 5.92 seconds.

How to find dash time?

1. Calculating the time for acceleration:

Using the equation of motion: v = u + at,

where v = final velocity, u = initial velocity, a = acceleration, and t = time.

Given:

Initial velocity (u) = 0 m/s (assuming the prospect starts from rest)

Final velocity (v) = 8.17 m/s

Acceleration (a) = 4.9 m/s²

v = u + at

8.17 = 0 + 4.9t

Solving for t:

t = 8.17 / 4.9

t ≈ 1.67 seconds

2. Calculating the time for the remaining distance:

The remaining distance is 36.6 m - the distance covered during acceleration.

Distance covered during acceleration:

Using the equation of motion: s = ut + (1/2)at²

s = 0 × t + (1/2) × 4.9 × t²

s = (1/2) × 4.9 × t²

Distance covered during acceleration = (1/2) × 4.9 × (1.67)²

Remaining distance = 36.6 m - [(1/2) × 4.9 × (1.67)²]

3. Calculating the time for the remaining distance:

Using the equation of motion: s = vt,

where s is the remaining distance, v is the constant velocity, and t is the time.

s = v × t

[36.6 - (1/2) × 4.9 × (1.67)²] = 8.17 × t

Solving for t:

t = [36.6 - (1/2) × 4.9 × (1.67)²] / 8.17

t ≈ 4.25 seconds

4. Calculating the total dash time:

Total dash time = time for acceleration + time for remaining distance

Total dash time = 1.67 + 4.25

Total dash time ≈ 5.92 seconds

Therefore, the NFL prospect's 40-yard dash time is approximately 5.92 seconds.

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Related Questions

817 cm3 at 80.8 kPa to 101.3 kPa: __________ cm3 (No temp. change)

Answers

The final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law can be represented by the equation: P₁V₁ = P₂V₂

Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.

Given:

Initial volume, V₁ = 817 cm³

Initial pressure, P₁ = 80.8 kPa

Final pressure, P₂ = 101.3 kPa

We need to find the final volume, V₂.

Using Boyle's Law equation, we can rearrange it to solve for V₂:

V₂ = (P₁V₁) / P₂

Plugging in the given values:

V₂ = (80.8 kPa * 817 cm³) / 101.3 kPa

Simplifying the expression:

V₂ ≈ 652.9 cm³

Therefore, the final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.

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What is the formula for Angular velocity?​

Answers

Answer:

The formulas are down below

Explanation:

[tex]w = \frac{o}{t} [/tex]

From V=rw

[tex]w = \frac{v}{r} [/tex]

Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2​

Answers

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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