Answer:
The angle is 3.95 rad.
Explanation:
The angle can be calculated as follows:
[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta [/tex]
Where:
[tex]\omega_{f}[/tex]: is the final angular speed
ω₀: is the initial angular speed = 0 (it starts from rest)
α: is the angular acceleration
θ: is the angle=?
The centripetal acceleration is:
[tex]a_{c} = \omega_{f}^{2}*r[/tex]
And the tangential acceleration is:
[tex] a_{T} = \alpha*r [/tex]
Since the magnitude of the centripetal acceleration is 7.9 times the magnitude of the tangential acceleration:
[tex]a_{c} = 7.9a_{T}[/tex]
[tex]\omega_{f}^{2}*r = 7.9*\alpha*r \rightarrow \alpha = \frac{\omega_{f}^{2}}{7.9}[/tex]
Now, the angle is:
[tex]\omega_{f}^{2} = 2(\frac{\omega_{f}^{2}}{7.9})\theta[/tex]
[tex] \theta = \frac{7.9}{2} = 3.95 rad [/tex]
Therefore, the angle is 3.95 rad.
I hope it helps you!
The angular distance traveled by the electric drill is 3.95 radians.
The given parameters;
initial angular speed, [tex]\omega_i[/tex] = 0centripetal acceleration, [tex]a_c[/tex] = 7.9aThe angular distance traveled by the electric drill is calculated as follows;
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]
The relationship between centripetal acceleration, tangential acceleration and angular speed is given as;
[tex]a_c = \omega ^2 r\\\\a = \alpha r\\\\a_c = 7.9a= 7.9\alpha r\\\\7.9\alpha r = \omega^2 r\\\\\alpha = \frac{\omega ^2}{7.9}[/tex]
Substitute the value of angular acceleration into the first equation;
[tex]\omega _f^2 = 0 + 2(\a (\frac{\omega _f^2}{7.9})\theta\\\\2\theta \omega_f^2 = 7.9\omega_f ^2\\\\\theta = \frac{7.9}{2} \\\\\theta = 3.95 \ rad[/tex]
Thus, the angular distance traveled by the electric drill is 3.95 radians.
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A cart with an unknown mass is at rest on one side of a track. A student must find the mass of the cart by using Newton’s second law. The student attaches a force probe to the cart and pulls it while keeping the force constant. A motion detector rests on the opposite end of the track to record the acceleration of the cart as it is pulled. The student uses the measured force and acceleration values and determines that the cart’s mass is 0.4kg . When placed on a balance, the cart’s mass is found to be 0.5kg . Which of the following could explain the difference in mass?
Answer choices:
A) The track was not level and was tilted slightly downward.
B) The student did not pull the cart with a force parallel to the track.
C) The wheels contain bearings that were rough and caused a significant amount of friction.
D) The motion sensor setting was incorrect. The student set it up so that motion away from the sensor would be the negative direction.
Answer: The correct answer is A) The track was not level and was tilted slightly downward.
Explanation: This is because of the two values: 0.4 kg and 0.5 kg. I won't go into much detail but due to this difference of mass, we know that the track was not level.
"The track was not level and was tilted slightly downward" could explain the difference in the mass.
Mostly because the university student or learners calculates a mass of just over the spring quantity, the vehicle speed seems to have been higher than there would have had to be.Option B, as well as Option C, are wrong because the acceleration would've been smaller in each of these 2 circumstances, so that computed mass would've been larger.
Thus Option A is appropriate.
Learn more:
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1. A 5.00 kg box is being pulled at constant speed up a 30o incline by a force of 45.0 N parallel to the incline. Determine the coefficient of kinetic friction between the box and the plane.
Answer:
μ = 0.48
Explanation:
To solve this problem we must make a free body diagram locating each of the respective forces on the boxes.
We must pay special attention that the body is moving at a constant speed, therefore there is no acceleration, and the sum of forces is equal to zero.
Attached is an image with the sum of forces and the equations of the sum of forces on the x & y axes.
The solution of all equations can be seen, in the attached image.
When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting, the current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V. When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V.
A. Find the battery's EMF.
B. What is its internal resistance?
Answer:
EMF = 11.35 V
R = 0.031Ω
Explanation:
To find the battery's EMF and the internal resistance we need to use Ohm's law:
[tex] V = IR [/tex]
Where:
V: is the voltage
I: is the current
R is the resistance
We have:
The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:
[tex] \epsilon = V + IR [/tex]
[tex] \epsilon = 9.36 V + 64.2A*R [/tex] (1)
When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:
[tex] \epsilon = 11.3 V + 1.96A*R [/tex] (2)
By solving equation (1) and (2) for R we have:
[tex] 9.36 V + 64.2A*R = 11.3 V + 1.96A*R [/tex]
[tex]R = \frac{1.94 V}{62.24A} = 0.031 \Omega[/tex]
Hence, the internal resistance is 0.031 Ω.
Now, by entering R into equation (1) we can find the battery's EMF:
[tex]\epsilon = 9.36 V + 64.2A*0.031 \Omega[/tex]
[tex] \epsilon = 11.35 V [/tex]
Therefore, the battery's EMF is 11.35 V.
I hope it helps you!
Given a force of 10 N and an acceleration of 5 m/s2, what is the mass?
Answer:
2kg
Explanation:
i think i found it yous welcom
Which formula describes Boyle's law?
ОА.
OB.
D = m/v
V1T2 = V2T
P1V1 = P2V2
P1T2 = P2T1
Ос.
OD
Answer: P1V1 = P2V2
Explanation:
If the shoe has less mass, it will experience _______________ (more, less, the same) friction as it would with more mass.
A current of 1.0 A from a 1.0 mm diameter wire enters a sphere which is 1.0 m in radius and exits through a 1.0 mm diameter wire on the opposite side of the sphere. What is the smallest value of current density in the sphere?
Answer:
The current density in the sphere is 0.32 A/m²
Explanation:
Given that,
Current = 1.0 A
Diameter = 1.0 mm
Radius of sphere = 1.0 m
We need to calculate the current density in the sphere
Using formula of current density
[tex]J=\dfrac{I}{A}[/tex]
Where, I = total current
A = area of sphere
Put the value into the formula
[tex]J=\dfrac{1.0}{\pi\times(1.0)^2}[/tex]
[tex]J=0.32\ A/m^2[/tex]
Hence, The current density in the sphere is 0.32 A/m²
Which of the following is a form of kinetic energy?
A. Electrical energy
B. Potential energy
C. Sound energy
D. Nuclear energy
HELP URGENT
Answer:
Electrical energy ⚡ Hope this helps you Stay happy and safe Do mark as brainliest ✌️Answer:
Potential Energy. It's wrong but it was worth a try
According to the nebular theory of solar system formation, what key difference in their early formation explains why the jovian planets ended up so different from the terrestrial planets
Answer:
The Jovian planets formed beyond the Frostline while the terrestrial planets formed in the Frostline in the solar nebular
Explanation:
The Jovian planets are the large planets namely Saturn, Jupiter, Uranus, and Neptune. The terrestrial planets include the Earth, Mercury, Mars, and Venus. According to the nebular theory of solar system formation, the terrestrial planets were formed from silicates and metals. They also had high boiling points which made it possible for them to be located very close to the sun.
The Jovian planets formed beyond the Frostline. This is an area that can support the planets that were made up of icy elements. The large size of the Jovian planets is as a result of the fact that the icy elements were more in number than the metal components of the terrestrial planets.
What is the direction of the magnetic field if an electron moving in the positive x direction experiences a magnetic force in the positive z direction
Given :
An electron moving in the positive x direction experiences a magnetic force in the positive z direction.
To Find :
The direction of the magnetic field.
Solution :
We know, force is given by :
[tex]\vec{F}=q(\vec{v}\times \vec{B)}[/tex]
Here, q = -e.
[tex]\vec{F}=(-e)(\vec{v}\times \vec{B)}\\\\\hat{k}=(-e)(\hat{i}\times \vec{B})[/tex]
Now, for above condition to satisfy :
[tex]\hat{i}\times \vec{B}=-\hat{k}[/tex]
So, [tex]\vec{B}=-\hat{j}[/tex]
Therefore, direction of magnetic field is negative y direction.
Hence, this is the required solution.
Sheldon and Penny are sitting in the back seat of a car that is moving in the x-direction with avelocity of 20 m/s. Sheldon makes a snide remark and Penny responds by throwing the cap ofher soda bottle at him with a velocity of 11 m/s (in what we'll call the y-direction) in theirreference frame. From the point of view of someone standing alongside the road, the speed ofthat cap would be closest to:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is E
Explanation:
From the question we are told that
The velocity in the x direction is [tex]v_x = 20 \ m/s[/tex]
The velocity of the cap of the soda bottle in the y direction is [tex]v_y = 11 \ m/s[/tex]
Gnerally the speed of the cap as seen by the observer is mathematically represented as
[tex]v_c = \sqrt{v_x^2 + v_y^2}[/tex]
=> [tex]v_c = \sqrt{ 20^2 + 11^2}[/tex]
=> [tex]v_c = 22.83 \ m/s [/tex]
=> [tex]v_c = 23 \ m/s [/tex]
Help please it’s urgent
Answer:
Q. No 1, true
Explanation:
Direct current is flow of current
Not sure about it
Sorry if it's wrong
Omar observes that many buildings in his city were built using limestone. He has read that acid rain can damage limestone. He also knows that limestone reacts with acids and that chemical reactions are affected by temperature. With this in mind, he conducts an investigation to see how the amount of damage to the limestone is affected by the amount of acid on the stone.
Which statement describes the correct plan for his procedure?Rhonda watched a video taken by a camera that was lifted into the upper atmosphere by a weather balloon. She saw the balloon pop when it reached a certain height. Afterward, Rhonda wondered what effect the air pressure at high altitudes has on the volume of gas in balloons.
What scientific practice is Rhonda performing
Answer:he conducts the investigation to see the effect acidic water has on limestone
Explanation:
Complete each statement by dragging the forms of energy into their appropriate boxes.
wind turbine
roller coaster going downhill
toaster
car
A
converts electrical energy into thermal energy.
A
converts rotational energy into electrical energy.
A
converts gravitational energy into mechanical energy.
A
converts rotational energy into mechanical energy.
Statements 1,2,3 and 4 match statements B, C, A, and D respectively.A wind turbine converts rotational energy into electrical energy.
What is the law of conservation of energy?According to the Law of conservation of energy. Energy can not be created nor be destroyed, it can transfer from one to another form.
1.A wind turbine converts rotational energy into electrical energy.
2.A roller coaster going downhill converts gravitational energy into mechanical energy
3. Toaster converts electrical energy into thermal energy
4.A car converts rotational energy into mechanical energy.
Hence,statements 1,2,3 and 4 match statements B, C, A, and D respectively.
To learn more about the law of conservation of energy refer:
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An 10.2-kg stone at the end of a steel (Young's modulus 2.0 x 10^11 N/m2) wire is being whirled in a circle at a constant tangential
speed of 11.6 m/s. The stone is moving on the surface of a frictionless horizontal table. The wire is 3.62 m long and has a radius of
4.10 x 10^-3m. Find the strain in the wire.
Answer:
[tex]3.6\times 10^{-5}[/tex]
Explanation:
m = Mass of stone = 10.2 kg
v = Tangential velocity = 11.6 m/s
l = Length of wire = 3.62 m
r = Radius of wire = [tex]4.1\times 10^{-3}\ \text{m}[/tex]
A = Area of wire = [tex]\pi r^2[/tex]
Y = Young's modulus of steel = [tex]2\times 10^{11}\ \text{N/m}^2[/tex]
[tex]\varepsillon[/tex] = Strain
The force acting on the stone will be centripetal
[tex]F=\dfrac{mv^2}{l}\\\Rightarrow F=\dfrac{10.2\times 11.6^2}{3.62}\\\Rightarrow F=379.15\ \text{N}[/tex]
Stress is given by
[tex]\sigma=\dfrac{F}{A}\\\Rightarrow \sigma=\dfrac{379.15}{\pi (4.1\times 10^{-3})^2}\\\Rightarrow \sigma=7179488\ \text{N/m}^2[/tex]
Young's modulus is given by
[tex]Y=\dfrac{\sigma}{\varepsilon}\\\Rightarrow \varepsilon=\dfrac{\sigma}{Y}\\\Rightarrow \varepsilon=\dfrac{7179488}{2\times 10^{11}}\\\Rightarrow \varepsilon=3.6\times 10^{-5}[/tex]
Strain in the wire is [tex]3.6\times 10^{-5}[/tex].
A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m
from the base of the cliff. Whall was the initial horizontal velocity of the cannon ball?
Answer:
vₓ = 6.73 m/s
Explanation:
Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:[tex]v_{x} = \frac{\Delta x}{\Delta t} (1)[/tex]
Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:[tex]\Delta h = \frac{1}{2} * g * t^{2} (2)[/tex]
where Δh = -37.0 m , g = -9.8 m/s2Solving (2) for t, we get:[tex]t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)[/tex]
Taking t₀ = 0, ⇒ Δt = tReplacing (3) in (1), we get:[tex]v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t} = \frac{18.5m}{2.75s} = 6.73 m/s[/tex]
As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.It takes 525 J of work to compress a spring 25 cm. What is the force constant of the spring (in kN/m)?
Answer:
1.680kN/m
Explanation:
Work done by the spring is expressed as shown:
[tex]W = \frac{1}{2}ke^2[/tex] where:
k is the spring constant
e is the extension
Given
W = 525Joules
extension = 25cm = 0.25m
Substitute into the formula:
[tex]525 = \frac{1}{2}k(0.25)^{2} \\525 = \frac{0.0625k}{2}\\ 525 = 0.03125k\\k = \frac{525}{0.3125}\\k = 1680N/m\\k = 1.680kN/m[/tex]
Hence the force constant of the spring is 1.680kN/m
based on how this sample looks, which term describes the matter that makes up granite?
OA. pure substance
OB. element
OC. mixture
OD. compound
Answer:
C. mixture
Explanation:
A mixture is an impure substance. It has the following properties;
It's composition is indefinite Their constituents retain their identities i.e. physical properties are retained Constituents react differently to changed conditionsThey can easily be separated into constituents by physical methods.Granite is a rock. A rock is usually formed by a combination of different minerals.
Granite is made up of many compounds and so it is a mixture.
what is the force produced on a body of 30kg mass when a body moving with the velocity of 26km/hr is acceleted to gain the velocity of 54 km/hr in 4 sec
Answer:
F = 58.35 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that force is equal to the product of mass by acceleration. But first we must use the following equation of kinematics.
We have to convert speeds from kilometers per hour to meters per second
[tex]\frac{26km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s}=\frac{7.22m}{s} \\\frac{54km}{hr}*\frac{1000m}{1km}*\frac{1hr}{3600s}=15\frac{m}{s}[/tex]
[tex]v_{f}=v_{o}+(a*t) \\[/tex]
where:
Vf = final velocity = 15 [m/s]
Vi = initial velocity = 7.22 [m/s]
a = acceleration [m/s^2]
t = time = 4 [s]
Note: the positive sign of the above equation is because the car increases its speed
15 = 7.22 + (a*4)
a = 1.945 [m/s^2]
Now we can use the Newton's second law:
F = m*a
F = 30*1.945
F = 58.35 [N]
An FM radio station, 20 miles away, broadcast at a 93.4 MHz frequency(a) What is the wavelength of the radio wave associated with this signal ?(b) How long does it take for the signal to reach your radio from the station ?
Answer:
(a) Wavelength = 3.21 m (b) Time = [tex]1.07\times 10^{-4}\ s[/tex]
Explanation:
Given that,
The frequency of FM radio station, f = 93.4 MHz
(a) We need to find the wavelength of the radio wave associated with this signal. The relation between wavelength and frequency is given by :
[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{93.4\times 10^6}\\\\\lambda=3.21\ m[/tex]
(b) It is given that, an FM radio station, 20 miles away. Let t is time taken for signal to reach your radio from the station. So,
[tex]t=\dfrac{d}{c}\\\\t=\dfrac{20\times 1609.34}{3\times 10^8}\\\\t=1.07\times 10^{-4}\ s[/tex]
Hence, this is the required solution.
When making a budget, you should prioritize ___________ before "__________." A. Needs/wants B. Wants/needs C. Electricity/Water D. Healthcare/Housing
Answer A
Explanation: because u need to make sure you know the difference between a need and a want
Answer:
a
Explanation:
There are two unitless vectors:
F1 = 8.92 i + 17.37 j
F2 = 8.31 i - 10.97 j
A third vector is added to them such that they add up to to the null vector:
F1 + F2 + F3 = 0
What is the angle of the third vector with respect to the +x-axis?
Answer:
[tex]200.38^0[/tex]
Explanation:
Given the forces:
F1 = 8.92 i + 17.37 j
F2 = 8.31 i - 10.97 j
If a third vector is added to them such that they add up to to the null vector as F1 + F2 + F3 = 0
then to get F3:
F3 = -F2-F1
F3 = -(8.31 i - 10.97 j)-(8.92 i + 17.37 j )
F3 = -8.31 i + 10.97 j-8.92 i - 17.37 j
F3 = -8.31i-8.92i+10.97j-17.37j
F3 = -17.23i-6.4j
from the vector:
x = -17.23 and y = -6.4
angle of the third vector with respect to the +x-axis is expressed as:
[tex]\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{-6.4}{-17.23}\\\theta = tan^{-1}0.3715\\\theta = 20.38^0[/tex]
Hence the angle the vector makes with the x axis will be [tex]\theta = 180+20.38 = 200.38^0[/tex]
For both resonance curves and Fourier spectra, amplitude is plotted vs frequency, but these two types of plots are not the same. Describe how they are different.
Answer:
he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
Explanation:
In a resonance experiment, the amplitude of the system is plotted as a function of the frequency, finding maximums for the values where some natural frequency of the system coincides with the excitation frequency.
In a Fourier transform spectrum, the amplitude of the frequencies present is the signal, whereby each peak corresponds to a natural frequency of the system.
From this explanation we can see that in the first case the peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
I need help with this answer
decomposition
A decomposition reaction is just the opposite of combination reaction
A 1200-kg car pushes a 2100-kg truck that has a dead battery to the right. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500 N. Which, if any, of the following gives a correct acceleration constraint for this problem? The variable ac is the acceleration of the car, and the variable t is the acceleration of the truck.
a. ac=at
b. ac=−at
c. ac=21001200at
d. ac=12002100at
e. There are no acceleration constraints for this problem.
Answer:
Option A: a_c = a_t
Explanation:
Let's denote the force acting on the car due to the truck as F_ct
Similarly, the force acting on the truck due to the car is denoted as F_tc.
Now, F_ct = m_c × a_c
Where;
m_c is mass of car
a_c is acceleration of car
Also, F_tc = m_t × a_t
Where;
m_c is mass of truck
a_c is acceleration of truck
Now, since the car is the one pushing the truck, from Newton's laws, we can say that they stick together and move in the same direction at the same acceleration.
Thus, the truck will move with an acceleration equal to that of the car pushing it.
Thus; a_c = a_t
"NEED HELP FAST" Which of the following is a vector quantity?
A. Time
B. Velocity
C. Temperature
D. Distance
Answer:
the answer is b. b velocity. remember v=v
Consider the system consisting of two pendulums coupled by a spring. Write the equations of motion in matrix form. Use small angle approximation.
Answer:
hello your question is incomplete attached below is the complete question
and solution to the question
Explanation:
To write The equation of the motion in Matrix form
i)First we write the net torque equation for left mass
ii)Next we write the net torque equation for right mass
iii) represent the equation of motion in Matrix form
Determine the accelerations that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object.
ans: 4m/s²
and 2m/s²
step:
f=m.a
in first condition
f=12N , M=3kg
so,
12=3.a
a=12/3
a=4m/s².
similarly
in second condition
f=12N ,M=6Kg
so,
12=a.6
a=12/6
a=2m/s²
An LED lamp powered by a USB-based portable battery has an effective resistance of 500 Ohm. If the battery is rated for 10,000 mAh, then how long can the lamp be powered and what is the total power consumed by the lamp? The operating voltage of a USB powered device is 5V. Assume that the battery is also rated at 5V.
Answer:
Time = 1000 h
Power = 0.05 W = 50 mW
Explanation:
First we will find the current consumed by the lamp. For this purpose we can use the Ohm's Law. The equation of Ohm's Law is written as follows:
V = IR
I = V/R
where,
I = Current = ?
V = Voltage = 5 V
R = Resistance = 500 Ω
Therefore,
I = 5 V/500 Ω
I = 0.01 A = 10 mA
Now the time duration of the operation f lamp can be found by:
Time = Rating/Current
Time = 10000 mAh/ 10 mA
Time = 1000 h
The power consumption of lamp is given as follows:
Power = IV
Power = (0.01 A)(5 V)
Power = 0.05 W = 50 mW
We recommend that our students get at least _____ hours of behind-the-wheel instruction.
A. 6
B. 10
C. 25
D. 50
