Alexander stacked unit cubes to build the rectangular prism below. Use the rectangular prism to answer​

The solution to the system of equations is x=2 and y=-2.

To solve the system of simultaneous equations graphically, we need to graph both equations on the same coordinate plane and find their point of intersection.

First, we'll rearrange both equations to be in the form y=mx+b, where m is the slope and b is the y-intercept.

y = 2 - 2x can be rewritten as y = -2x + 2

y = 2x - 6 can be rewritten as y = 2x - 6

Now, we'll plot both equations on the same coordinate plane. To do this, we'll create a table of values for each equation and plot the points.

For y = -2x + 2: (0,2), (1,0), (2,-2)

For y = 2x - 6:(0,-6), (1,-4), (2,-2)

Next, we'll plot these points on the same graph and draw the lines connecting them.

The point where the lines intersect is the solution to the system of equations. From the graph, we can see that the point of intersection is (2,-2).

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The shape formed by a solid intersecting with a plane, so the At level X = 3, the area of the vertical cross-section A is 108 square units.

To find the area of the vertical cross section A at the level X = 3, we need to find the equation of the circle when it is intersected by the plane X = 3.
First, let's find the value of y when X = 3 using the equation of the circle x^2 + y^2 = 36:

(3)^2 + y^2 = 36
9 + y^2 = 36
y^2 = 27
y = ±√27

Since we are dealing with a circle, there are two points on the circle at X = 3, which are (3, √27) and (3, -√27).

The distance between these two points will be the base of the triangle, which is also equal to its height (as given in the problem).

Base and height of the triangle: 2 * √27

Now we can find the area A of the vertical cross-section, which is a triangle with equal base and height:

A = 1/2 * base * height
A = 1/2 * (2 * √27) * (2 * √27)
A = 4 * 27
A = 108

So, the area of the vertical cross-section A at the level X = 3 is 108 square units.

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For the expression (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸, the simplified-value is 9m¹⁰n⁻¹p⁻⁷.

To simplify the expression (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸, we first use the exponent-rule that states (qᵃ)ᵇ = qᵃᵇ to simplify the first part of the expression:

⇒ (3m⁴n)³ = 3³(m⁴)³n³ = 27m¹²n³;

Next, we can simplify the denominator by using the rules of exponents to combine the like terms:

⇒ 6m⁴n⁹p⁸ = 2×3m⁴n⁹p⁸;

Substituting the values,

We get;

⇒ (27m¹²n³)×(2m²n⁵p)/(2*3m⁴n⁹p⁸);

Simplifying the expression by cancelling out the common factors, we get:

⇒ 9m¹⁰n⁻¹p⁻⁷;

Therefore, the simplified-value is : 9m¹⁰n⁻¹p⁻⁷.

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The given question is incomplete, the complete question is

What is the simplified form of the expression below (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸;

Answer:

If point R is reflected across the x-axis, its y-coordinate will change sign. Therefore, the y-coordinate of R' will be 3 (the opposite of -3). Thus, the answer is A. (-8, 3)

Step-by-step explanation:

Answer:

In an isosceles right triangle, the length of the diagonal is √2 times the length of a leg.

c = 6√2 in. = 8.5 in.

Check the picture below.

To construct a confidence interval for the population proportion of Americans over 40 who smoke, we can use the formula:

Confidence Interval = Sample Proportion ± (Critical Value) x Standard Error

where the sample proportion is the number of individuals who don't smoke divided by the total sample size (806/1089), the critical value can be found using a normal distribution table or calculator with the given confidence level (85%), and the standard error can be calculated using the formula:

Standard Error = √[ (Sample Proportion x (1 - Sample Proportion)) / Sample Size ]

Plugging in the given values, we get:

Sample Proportion = 806/1089 = 0.740
Sample Size = 1089
Standard Error = √[(0.740 x 0.260) / 1089] = 0.016
Critical Value (using a normal distribution table or calculator) = 1.440

Therefore, the 85% confidence interval for the population proportion of Americans over 40 who smoke is:

0.740 ± (1.440 x 0.016) = 0.740 ± 0.023

Rounding to three decimal places, the confidence interval is (0.717, 0.763). This means that we can be 85% confident that the true proportion of Americans over 40 who smoke falls between 71.7% and 76.3%.

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Lara sold 3/5 of a box of candy, which is the same as 0.6 boxes of candy.

If Lucy sold 3/5 of a box of candy, then Lara sold 1/5 of 3/5, which is:

(1/5) * (3/5) = 3/25

Therefore, Lara sold 3/25 of a box of candy.

To find the number of boxes Lara sold, we can divide 3/25 by 1/5:

(3/25) ÷ (1/5) = (3/25) * (5/1) = 15/25 = 3/5

So Lara sold 3/5 of a box of candy, which is the same as 0.6 boxes of candy.

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The plumber worked for 4.5 hours and charged $138.70 for their services

To find out how many hours the plumber worked, we first need to subtract the initial charge of $14.95 from the total bill of $138.70.

$138.70 - $14.95 = $123.75

This gives us the amount that the plumber charged for the hours worked. Now, we can divide this amount by the hourly rate to find the number of hours:

$123.75 ÷ $27.50 per hour = 4.5 hours

However, we need to convert the decimal part (0.5) into minutes. We can do this by multiplying it by 60:

0.5 x 60 = 30 minutes

But we need to add the initial charge of $14.95 to get the final answer.

4 hours and 30 minutes is equivalent to 4.5 hours.

4.5 hours x $27.50 per hour = $123.75

$123.75 + $14.95 = $138.70

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Required Answer :

x(2x + 4)= x²+ 4 (9 - 3x)

2x² + 4x = x² + 36 - 12x

2x² - x² + 4x + 12x - 36=0

x² + 16x - 36=0

Quadratic equation in Standard form,

Using Quadratic formula,

[tex] \implies \sf x = \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \implies \sf x = \dfrac{ - 16 \pm \sqrt{ {16}^{2} - 4(1)( - 36)} }{2 \times 1} \\ \\ \implies \sf x = \dfrac{ - 16\pm \sqrt{256 - ( - 144)} }{2} \\ \\ \implies \sf x = \frac{ - 16 \pm \sqrt{256 + 144} }{2} \\ \\ \implies \sf x = \frac{ - 16 \pm \sqrt{400} }{2} \\ \\ \implies \sf x = \dfrac{ - 16 \pm20}{2} \\ \\ \implies \sf x = \dfrac{ - 16 \pm 20}{2} \\ \\ \implies \sf x = \dfrac{4}{2} \: or \: \dfrac{ - 36}{2} \\ \\ \implies \sf x = 2 \: or \: - 18[/tex]

The average rate of change of the function g(x)=6x from x=-1 to x=3 is found to be 6.

The function g(x) = 6x describes a relationship between x and the value of 6 times x. We want to find the average rate of change of this function from x = -1 to x = 3. The average rate of change tells us the average amount by which the function changes per unit of change in x over this interval.

In this case, by using the function g(x) = 6x and evaluating it for x = 3 and x = -1, a difference of 18 - (-6) = 24 is found. The difference in x's values is equal to 3 - (-1) = 4. We divide these to get an average rate of change of 6.

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So the estimated value of √6.02 using differentials is approximately 2.4556.

The change in g(x,y,z) can be estimated using partial derivatives and differentials.

We can start by finding the partial derivatives of g(x,y,z) with respect to x, y, and z:∂g/∂x = 3 + cos(z)∂g/∂y = -sin(z) + 1∂g/∂z = -x sin(z) - y cos(z)Next, we can use the point P0(1,-3,0) and the distance ds = 0.1 to find the differentials dx, dy, and dz:dx = -2/√6 dsdy = 2/√6 dsdz = 1/√6 dsUsing these values, we can estimate the change in g:Δg ≈ (∂g/∂x) dx + (∂g/∂y) dy + (∂g/∂z) dzΔg ≈ (3 + cos(0)) (-2/√6 ds) + (-sin(0) + 1) (2/√6 ds) + (-1 sin(0) - (-3) cos(0)) (1/√6 ds)Δg ≈ (3 - 2/√6) dsPlugging in ds = 0.1, we get:Δg ≈ (3 - 2/√6) (0.1)Δg ≈ 0.389

Therefore, the change in g(x,y,z) is estimated to be approximately 0.389 units if the point P(x,y,z) moves from P0(1,-3,0) a distance of ds = 0.1 unit toward the point P1(-1,-1,2).

Suppose we want to estimate the value of √6.02 using differentials. We can start by choosing x = 6 and Δx = 0.02. Then, we need to find the derivative of f(x) = √x with respect to x:

f(x) = √x

f'(x) = 1/(2√x)

Using these values, we can estimate Δy:

Δy ≈ dy = f'(x) Δx

dy ≈ (1/(2√6)) (0.02)

dy ≈ 0.005

This means that a small change of 0.02 in x produces a small change of approximately 0.005 in y. To estimate the value of √6.02, we can add this change to the known value of √6:

√6.02 ≈ √(6 + 0.02) ≈ √6.04 ≈ 2.4556

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The number of different committees that are possible is: 126

When you have a number of elements and then want to form subsets of elements of particular smaller size, you can utilize combinations or permutations. If the order of placement of the elements does not matter, we use combinations to quantify the number of groups formed.

Now, the order of the members in the committee does not matter and as such we will use combinations which has the formula:

nCr = n!/(r!(n - r)!)

We are given:

n = 9

r = 5

Thus:

9C5 = 9!/(5!(9 - 5)!)

= 126 different committees

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The value of the expression is 2

Index forms are described as those forms that are used to represent numbers that are too large or small in more convenient forms.

They are also described as numbers that are raised to a variable or an exponents.

Other names for index forms are scientific notations and standard forms.

One of the rules of index forms is that the exponents are added when the have the same and are being multiplied.

From the information given, we have that;

(2^-1/2) / (2^1/2)

subtract the exponents

2^-1/2-1/2

subtract the values

2^ -1

Then, we have;

2

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Answer:

  (c)  y < -x +1

Step-by-step explanation:

You want the inequality that matches the graph.

The boundary line of the shaded area has a negative slope: it falls one unit for each unit to the right, so the slope is ...

  m = rise/run = -1/1 = -1

The line crosses the y-axis at y = 1, so the y-intercept is b = 1.

The equation of the boundary line is ...

  y = mx + b

  y = -x +1

The boundary line is dashed, so its values are not part of the solution set. The shading is below the line, so only y-values less than those on the line are included.

The inequality is ...

  y < -x +1 . . . . . choice C

<95141404393>

The correct answer is option B, a reflection over the y-axis followed by a translation of (1,y) → (1, y-6).

To solve this problem, we need to find the sequence of rigid motions (i.e., transformations that preserve distance and angle) that maps quadrilateral ABCD to quadrilateral EFGH.

First, we need to identify the corresponding vertices of the two quadrilaterals. Let's assume that vertex A maps to vertex E, vertex B maps to vertex F, vertex C maps to vertex G, and vertex D maps to vertex H.

Now, we can apply different transformations to map each vertex of quadrilateral ABCD to the corresponding vertex of quadrilateral EFGH. We can try each option provided and check if it maps all the vertices correctly.

Option A involves a reflection over the x-axis, followed by a translation of (0,y) → (0, y - 4). This transformation does not map vertex A to vertex E correctly.

Option B involves a reflection over the y-axis, followed by a translation of (1,y) → (1, y - 6). This transformation maps vertex A to vertex E, vertex B to vertex F, vertex C to vertex G, and vertex D to vertex H, which is the correct mapping.

Option C involves a translation of (+,y) → (2, y - 3) followed by a reflection over the y-axis. This transformation does not map vertex A to vertex E correctly.

Option D involves a translation of (1-6, y) followed by a reflection over the x-axis. This transformation does not map vertex A to vertex E correctly.

Therefore, the unique sequence of rigid motions that maps quadrilateral ABCD to quadrilateral EFGH is a reflection over the y-axis followed by a translation of (1,y) → (1, y-6), which is option B.

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The spring constant is 180 N/m.

To solve for the spring constant, we can use the equation: k = (m * g) / x
where k is the spring constant, m is the mass of the box, g is the acceleration due to gravity (9.8 m/s^2), and x is the compression distance of the spring.
First, let's get the final velocity of the box when it hits the spring. We can use the equation:
v^2 = u^2 + 2as
where v is the final velocity (0 m/s), u is the initial speed (3.0 m/s), a is the acceleration (which is constant and equal to -k/m since the force from the spring is in the opposite direction of the box's motion), and s is the compression distance of the spring (0.30 m).
Rearranging the equation, we get:
k/m = (u^2 - v^2) / (2s)
k/4.0 = (3.0^2 - 0^2) / (2 * 0.30)
k/4.0 = 45
k = 180 N/m
Therefore, the spring constant is 180 N/m.

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Answer:

12

325

Step-by-step explanation:

When it mentions the word "fit", you use TSA.

TSA cuboid = 2[LH+BH+LH] = 2 [ (2×3/2)+(3/2×7/2)+(2×7/2)] = 2 [ 3 + 21/4 + 7] = 2 [5¼+10] = 2 [15¼] = 2 × 61/4 = 61/2 = 30½ ft²

TSA ½ foot cube = 6L² = 6(½)² = 6×¼ = 2½

Number of cubes = 30.5÷2.5 = 12.2 = 12

TSA ⅛ foot cube = 6(⅛)² = 6×1/64 = 3/32

Number of cubes = 30.5÷3/32 = 325⅓ = 325

For a random sample of 155 observations results in 62 successes.

a) A 90% confidence interval for the population proportion of successes is equals to the (0.335 , 0.465).

b) A 90% confidence interval for the population proportion of failure is equals to the (0.535 , 0.665).

We have a random sample of 155 observations results in 62 successes. So,

Observed value, x = 62

Sample size,n = 155

Population Proportion, p = x/n

= 62/155

= 0.4

a) We have to determine 90% confidence interval for the population proportion of successes. Using the distribution table, for 90% confidence interval, z-score value is equals to 1.6. Consider Confidence interval formula with proportion, CI [tex]= p ± z×\sqrt\frac{p(1-p)}{n}[/tex]

substitute all known values in above formula, [tex]= 0.4 ± 1.64\sqrt\frac{0.4(1- 0.4)}{155}[/tex]

= 0.4 ± 0.0645

= (0.4 - 0.0645 , 0.4 + 0.0645)

= (0.335 , 0.465)

b) Now, we have to determine a 90% confidence interval for the population proportion of failures.

Now consider, here failure observed values, x = 155 - 62

= 93

proportion, p = x/n

= 93/155 = 0.6

Consider the confidence interval formula, CI [tex]= p ± z×\sqrt\frac{p(1-p)}{n}[/tex]

substitute values, [tex]= 0.6 ±1.64×\sqrt\frac{0.6(1-0.6)}{155}[/tex]

= 0.6 ± 0.0645

= (0.6 - 0.0645 , 0.6 + 0.0645)

= (0.535 , 0.665)

Hence, required value is (0.535 , 0.665).

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The missing angles ;

22.6°

53.1°

28.1°

A right triangle is a type of triangle that has one of its angles measuring 90 degrees (a right angle). The side opposite to the right angle is called the hypotenuse, and the other two sides are called legs or catheti.

We have that;

[tex]Sin \alpha = 5/13\\ \alpha = Sin-1(5/13)\\ \alpha = 22.6[/tex]

[tex]Tan  \alpha = 16/12\\\alpha = Tan-1 (16/12)\\= 53.1[/tex]

[tex]Sin \alpha = 8/17\\\alpha = Sin-1(8/17)\\\alpha = 28.1[/tex]

Right triangles have many practical applications, such as in trigonometry, engineering, and architecture.

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Step-by-step explanation:

18 m = hypotenuse = c

5 m = b

a² + b² = c²

a² + (5)² = (18)²

a² + 25 = 324

a² = 324 - 25

a² = 299

a = √299

a = 17.29 or 17.3 m

perimeter = a + b + c

= 17.3 + 18 + 5

= 40.3 m

Point B is the image of point A under a rotation about the origin.

Rotation is a transformation in which an object or a point is turned around a fixed point or a fixed axis. The fixed point or axis is called the center of rotation, and the angle of rotation specifies the amount and direction of the turn. When an object is rotated, its orientation changes but its shape and size remain the same.

For example, if you rotate a square by 90 degrees around its center, it will look the same as before, but it will be oriented differently. Similarly, if you rotate a point in a coordinate system around the origin, its position will change, but its distance from the origin will remain the same.

Rotations are commonly used in geometry, physics, and engineering to describe the motion of objects, such as the rotation of the Earth around its axis or the rotation of a wheel on an axle. They are also used in computer graphics to create animations and in robotics to control the movement of robotic arms and other devices.

When point A is rotated about the origin to form point B, the distance between the origin and each point remains the same. The direction from the origin to point A and the direction from the origin to point B are related by the angle of rotation. Specifically, point B is the image of point A under a rotation about the origin.

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The sample space for choosing one marble from the given marbles which are red, green, blue, yellow, and orange is s = {red, green, blue, yellow, orange}

Given color of the marbles which are present in the paper bag are,

The five color marbles are present in the paper bag so, the sample space also contains all five marbles without repeating any color again.

Sample space: sample space is nothing but listing all the outcomes of the event. In the above event, we have to list the all outcomes when choosing one marble from the paper bag which containing five different marbles.

So, the sample space S = {red, green, blue, yellow, orange}

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The graphs are identified as follows

1. the domain is option G

2. the range is option E

3. the domain is option D

4. the range is option C

In coordinate geometry, the domain and range are concepts used to describe the set of possible inputs (x-values) and outputs (y-values) of a function, respectively.

The domain of a function is the set of all possible x-values for which the function is defined. In other words, it is the set of all values that can be plugged into the function and produce a meaningful output.

The range of a function is the set of all possible y-values that the function can take on as x varies over its domain. In other words, it is the set of all values that the function can output.

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The length of chord segment EG = 6 inches and the length of FG = √23 inches.

Given, chord EG = 8 inches and the distance from the center of J to the chord is 3 inches.

We can draw a diagram as follows:

              J

            /   \

           /     \

          /       \

         /         \

        E-----------G

              |

              |

              |

              |

              |

              F

Here, OJ is perpendicular to chord EG at point F.

As per the theorem, the length of the perpendicular from the center of the circle to a chord is half the length of the diameter intersecting the chord.

So, we can find the length of the diameter intersecting chord EG and then use it to find the radius of the circle.

Length of chord EG = 8 inches

Length of OJ = 3 inches

Using Pythagorean theorem in right triangle OFG, we get:

OG² = OF² + FG²

Let x be the length of FG

We know that OF = OJ = 3 inches

OG = radius of the circle

So, we have:

radius of circle = OG = √(OF² + FG²) = √(3² + x²)

The diameter of the circle = 2(radius) = 2√(3² + x²)

Now, using the theorem mentioned above, we can say:

Length of perpendicular from the center of the circle to chord EG = OF = 3 inches

Length of diameter intersecting chord EG = 2√(3² + x²)

So, we get:

Length of chord segment EG = 2 * length of perpendicular

                            = 2 * 3 inches

                           = 6 inches

Now, we know that the chord segment EG divides the diameter intersecting it into two equal parts.

So, we have:

Length of one part of the diameter = (2√(3² + x²))/2 = √(3² + x²)

Using Pythagorean theorem in right triangle OJF, we get:

OJ² + JF² = OF²

3² + JF² = 8²

JF² = 8² - 3² = 55

JF = √55

Using Pythagorean theorem in right triangle JFG, we get:

JG² + FG² = JF²

(√(3² + x²))² + x² = 55

9 + x² + x² = 55

2x² = 46

x² = 23

x = √23

Therefore, the length of chord segment EG = 6 inches and the length of FG = √23 inches.

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The term which is important in terms of making meaning of those scores is measures of central tendency (mean, median, mode), option A.

A single number that seeks to characterise a set of data by pinpointing the centre location within that set of data is referred to as a measure of central tendency. As a result, measurements of central location are occasionally used to refer to measures of central tendency.

These also fit within the category of summary statistics. You are probably most familiar with the mean (sometimes known as the average), but there are additional central tendency measures, including the median and the mode.

The mean, median, and mode are all reliable indicators of central tendency, however depending on the situation, certain indicators are more useful than others.

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Answer: x = -3

Step-by-step explanation:

Hope this helps.

An equation that express each relationship for the joint variation is X = kyz. Solving for y will give the equation y = X/(kz)

Joint variation is a mathematical concept that describes the relationship between two or more variables. 

If X varies jointly as y and z, we can express this relationship mathematically using the formula:

X = k × y × z

X = kyz

where k is a constant of proportionality.

We can solve for y by dividing both sides by kz follows:

X/kz = kyz/kz

X/(kz) = y

Therefore, the equation that express each relationship for the joint variation is X = kyz. And the equation solved for y is y = X/(kz).

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Answer: TJ has 17 quarters and Demi has 26 quarters.

Step-by-step explanation:

Let t be the number of quarters TJ has and d be the number of quarters Demi has.

First, we will write an equation based on the first detail given:

       d = t + 9

Next, we will write an equation based on the second detail given:

       2t + 3d = 112

Now, we will substitute the first equation into the second and solve for t.

       2t + 3d = 112

       2t + 3(t + 9) = 112

       2t + 3t + 27 = 112

       5t + 27 = 112

       5t = 85

       t = 17 quarters

Lastly, we know that Demi has 9 more quarters than TJ. We will add 9.

       17 quarters + 9 quarters = 26 quarters

Answer:

TJ has 17 quarters.

Step-by-step explanation:

Let d and t equal the numbers of quarters Demi and TJ have, respectively.

"Demi has nine more quarters than TJ."

d = t + 9

"if you double the number of quarters TJ has and triple the number of quarters then he has you would get 112 quarters in total"

I think that "then he" above really should read "Demi."

2t + 3d = 112

d = t + 9

2t + 3d = 112

2t + 3(t + 9) = 112

2t + 3t + 27 = 112

5t = 85

t = 17

Answer: TJ has 17 quarters.