a woman spent 3/5 of her weekly salary on rent and 25% of her weekly salary on food. Her food cost $2500. How much did she spend on rent
​

Answer:

1.18

Step-by-step explanation:

$1.17

Step-by-step explanation:

He divided the total cost by 3 not 3 dozen (36).

Given:

The functions are

[tex]f(x)=4x^2+7x-5[/tex]

[tex]g(x)=-9x^2+4x-13[/tex]

To find:

The functions [tex](f+g)(x)[/tex] and [tex](f-g)(x)[/tex].

Solution:

We know that,

[tex](f+g)(x)=f(x)+g(x)[/tex]

[tex](f+g)(x)=4x^2+7x-5-9x^2+4x-13[/tex]

[tex](f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)[/tex]

[tex](f+g)(x)=-5x^2+11x-18[/tex]

And,

[tex](f-g)(x)=f(x)-g(x)[/tex]

[tex](f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)[/tex]

[tex](f+g)(x)=4x^2+7x-5+9x^2-4x+13[/tex]

[tex](f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)[/tex]

[tex](f-g)(x)=13x^2+3x+8[/tex]

Therefore, the required functions are [tex](f+g)(x)=-5x^2+11x-18[/tex]

and [tex](f-g)(x)=13x^2+3x+8[/tex].

Answer:

6 jared used six pounds

Step-by-step explanation:

you have it aubtexact what he used the first night and then divide by 4percwnt

Answer:

parabola

Step-by-step explanation:

The path followed by a ball can be modeled by a graph.

Throwing a ball is a parabola or quadratic graph.

When a ball is thrown, the path it follows can be represented by:

[tex]\mathbf{f(x) = ax^2 + bx + c}[/tex]

or

[tex]\mathbf{f(x) = a(x - h)^2 + k}[/tex]

The above equations are functions of a parabola or quadratic graph.

Hence, throwing a ball is a parabola or quadratic graph.

Read more about graphs at:

https://brainly.com/question/9915751

Answer:

Step-by-step explanation:

$21.75/(3 crabs) = $7.25/crab

Answer:

a) 0.34 = 35% probability that at least one member of a married couple will vote.

b) 0.7143 = 71.43% probability that a wife will vote

c) 0.0968 = 9.68% probability that a husband will vote

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

This is used for itens B and C. For item a, we treat the probabilities as Venn sets.

A) What is the probability that at least one member of a married couple will vote?

I am going to say that:

Event A: Husband votes.

Event B: Wife votes.

The probability that the husband will vote on a bond referendum is 0.21

This means that [tex]P(A) = 0.21[/tex]

The probability that the wife will vote on the referendum is 0.28

This means that [tex]P(B) = 0.28[/tex]

The probability that both the husband and the wife will vote is 0.15.

This means that [tex]P(A \cap B) = 0.15[/tex]

At least one votes:

This is [tex]P(A \cup B)[/tex], which is given by:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

So

[tex]P(A \cup B) = 0.21 + 0.28 - 0.15[/tex]

[tex]P(A \cup B) = 0.34[/tex]

0.34 = 35% probability that at least one member of a married couple will vote.

B) What is the probability that a wife will vote, given that her husband will vote?

Here, we use conditional probability:

Event A: Husband votes:

Event B: Wife votes

The probability that the husband will vote on a bond referendum is 0.21

This means that [tex]P(A) = 0.21[/tex]

Intersection of events A and B:

Intersection between husband voting and wife voting is both voting, which means that [tex]P(A \cap B) = 0.15[/tex]

The desired probability is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.21} = 0.7143[/tex]

0.7143 = 71.43% probability that a wife will vote.

C) What is the probability that a husband will vote, given that his wife does not vote?

Event A: Wife does not vote.

Event B: Husband votes.

The probability that the wife will vote on the referendum is 0.28

So 1 - 0.28 = 0.62 probability that she does not vote, which means that [tex]P(A) = 0.62[/tex]

Probability of husband voting and wife not voting:

0.21 probability husband votes, 0.15 probability wife votes, so 0.21 - 0.15 = 0.06 probability husband votes and wife does not, so [tex]P(A \cap B) = 0.06[/tex]

The desired probability is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.62} = 0.0968[/tex]

0.0968 = 9.68% probability that a husband will vote

Answer:

40%

Step-by-step explanation:

Answer:

y=-2x+4

Step-by-step explanation:

Answer:

9/16

is already in the simplest form. It can be written as 0.5625 in decimal form (rounded to 6 decimal places).

Step-by-step explanation:

Answer:

5m•5m•5m

Step-by-step explanation:

so you  multiply the factor by itself as many times as the exponent says so if the factor is 5m you would multiply it by the exponent which in this case is 3

5m.5m.5m and 125m³  is the equivalent expressions of the expression (5m)³.

An expression is combination of variables, numbers and operators.

The given expression is (5m)³

We have to find the equivalent expression of (5m)³

Equivalent expressions are expressions that work the same even though they look different

(5m)³ can be written as 5m.5m.5m

The value of five cube is one hundred twenty five.

125m³

Hence, 5m.5m.5m and 125m³  is the equivalent expressions of the expression (5m)³.

To learn more on Expressions click:

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#SPJ2

Given:

The equation is

[tex]\dfrac{1}{3}x=\dfrac{1}{5}[/tex]

To find:

The coefficient and reciprocal.

Solution:

We have,

[tex]\dfrac{1}{3}x=\dfrac{1}{5}[/tex]

Here, [tex]\dfrac{1}{3}[/tex] is multiplied with x.

So, the coefficient of x is [tex]\dfrac{1}{3}[/tex].

To find the reciprocal, we need to interchange numerator and denominator of a fraction.

So, the reciprocal of [tex]\dfrac{1}{3}[/tex] is [tex]\dfrac{3}{1}=3[/tex]

Therefore, the reciprocal is 3.

Answer:

3.You deposit $1000 in an account that earns 9% annual interest compounded semiannually.

1. You deposit $950 in an account that earns 9% annual interest compounded daily.

2. You deposit $1000 in an account that earns 8% annual interest compounded daily.

4. You deposit $1000 in an account that earns 10% simple interest.

Step-by-step explanation:

P.S - The exact question is -

To find - Three different accounts are described below. Order the accounts  

             according to their values after 10 years, from greatest to least.

             1. You deposit $950 in an account that earns 9% annual

                 interest compounded daily.

            2. You deposit $1000 in an account that earns 8% annual

                 interest compounded daily.

             3.You deposit $1000 in an account that earns 9% annual

                 interest compounded semiannually.

              4. You deposit $1000 in an account that earns 10% simple interest.

Proof -

1.)

Value after 10 years = 950( 1 + 0.09)¹⁰

                                 = 950 ( 1.09)¹⁰

                                 = 950(2.37) = 2248.995

⇒Value after 10 years = 2248.995

2.)

Value after 10 years = 1000( 1 + 0.08)¹⁰

                                 = 1000 ( 1.08)¹⁰

                                 = 1000(2.159) = 2158.925

⇒Value after 10 years = 2158.925

3.)

As it is compounded semiannually , so time period is doubles and rate goes half.

Value after 10 years = 1000( 1 + 0.045)²⁽¹⁰⁾

                                 = 1000 ( 1.045)²⁰

                                 = 1000(2.412) = 2411.714

⇒Value after 10 years = 2411.714

4.)

Value after 10 years = 1000×[tex]\frac{10}{100}[/tex]×10 = 1000

∴ we get

2411.714 > 2248.995 > 2158.925 > 1000

⇒ 3.) > 1.) > 2.) > 4.)

So,

3.You deposit $1000 in an account that earns 9% annual interest compounded semiannually.

1. You deposit $950 in an account that earns 9% annual interest compounded daily.

2. You deposit $1000 in an account that earns 8% annual interest compounded daily.

4. You deposit $1000 in an account that earns 10% simple interest.

Answer:

32 and 18

Step-by-step explanation:

This is a question of simultaneous equation.

Let's say the two numbers are x and y.

ATQ,

x+y =50 ——I

x-y=14——II

On adding I and II,

We get 2x=64

Implying x=32

Putting the value of x in equation I,

32+y=50

y=50–32

=18.

The answer is 32 and 18

Answer:

$4,166,67

Step-by-step explanation:

Step-by-step explanation:

.......................

Answer:

Rs 16

Step-by-step explanation:

Amount of money paid for 16 pens = Rs 256

Amount of money paid for 1 pen =

[tex] \frac{256}{16} = \frac{128}{8} \\ = \frac{64}{4} = \frac{32}{2} \\ = \frac{16}{1} \\ [/tex]

Therefore, amount paid for one pen is Rs 16

Answer:

5+12i

Step-by-step explanation:

So 12-7 = 5 and 8i+4i=12i and that equals 5+12i

Answer:

q^6

Step-by-step explanation:

Answer:

x=10/3 y=17/3

Step-by-step explanation:

Use substitution to solve your equation. Plug in y=2x-1 into y=1/2x+4. This makes (2x-1)=1/2x+4. Simplify this to get 3/2x-1=4. Simplify it again to get 3/2x=5. No one likes fractions so multiply both sides by 2 to get 3x=10. Simplify this and get x=10/3. Plus 10/3 into one of the equations. You can pick anyone but I picked y=2x-1. Because you know x=10/3, you put y=2(10/3)-1. Simplify this and get y=20/3-1. Convert 1 into a fraction and get y=20/3-3/3. Simplify this and get y=17/3.

Therefore,

x=10/3 y=17/3

Hoped this helps you

Answer:

the reading of the length of the cylinder is 2.84 cm

Step-by-step explanation:

Given the data in the question;

the main scale reading = 2.8 cm

the Vernier reading = 4

the least count of the Vernier = 0.01 cm

the reading of the length of the cylinder = ?

To determine the reading of the length of the cylinder, we simply say;

Reading length = main scale reading + ( Vernier reading × least count )

so we substitute in our given values

Reading length =  2.8 cm + ( 4 × 0.01 cm )

Reading length =  2.8 cm + 0.04 cm

Reading length =  2.84 cm

Therefore,  the reading of the length of the cylinder is 2.84 cm

Answer:

Two-Half Planes. Or, You can Call it a Boundary line.

Step-by-step explanation:

Answer:

half-planes or boundary region

Step-by-step explanation:

Answer:

1/6 hour, or 10 minutes

Step-by-step explanation:

This is a subtraction problem.

1/2 - 1/3 =

We need a common denominator for 2 and 3. We can use 6.

= 1/2 * 3/3 - 1/3 * 2/2

= 3/6 - 2/6

= 1/6

Answer: 1/6 hours, or 10 minutes

Answer:

look it up

Step-by-step explanation:

Answer:

12

4*3

That's the answer

Answer:

d) -4

Step-by-step explanation:

-9.4 - 2.4b = 0.2

-2.4b = 9.6

b = -4

good luck, i hope this helps :)

Answer:

A. It is a two tailed test about a proportion

Step-by-step explanation:

We are given;

Population proportion; p= 8% = 0.08

Sample size; n = 450

Defective ones in the sample = 27

Sample proportion; p^ = 27/450 = 0.06

Let's define the hypotheses.

Null Hypothesis; H0: p = 0.08

Alternative hypothesis;Ha: p ≠ 0.08

≠ is used for the alternative hypothesis because we can't really ascertain if the training was going to make things worse.

Thus, this is a two tailed hypothesis test about a proportion.

Answer:40b simplified

Step-by-step explanation:

Answer:

$14,080

Step-by Step Explanation:

Answer:

$14,080

Step-by-step explanation:

Hope this helps.

Answer:

0.0256 ; 0.1536 ; 0.3456 ; 0.3456 ; 0.1296

Step-by-step explanation:

P, that each bulldozer will be operational for atleast 6 months = 0.6

p = 0.6 ; q = 1 - p = 1 - 0.6 = 0.4

Number of bulldozers purchased, n = 4

Probability that :

Exactly 0 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 0) = 4C0 * 0.6^0 * 0.4^4

P(x = 0) = 1 * 1 * 0.0256

P(x = 0) = 0.0256

Probability that :

Exactly 1 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 1) = 4C1 * 0.6^1 * 0.4^3

P(x = 1) = 4 * 0.6 * 0.064

P(x = 1) = 0.1536

Probability that :

Exactly 2 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 2) = 4C2 * 0.6^2 * 0.4^2

P(x = 2) = 6 * 0.36 * 0.16

P(x = 2) = 0.3456

Probability that :

Exactly 3 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 3) = 4C3 * 0.6^3 * 0.4^1

P(x = 3) = 4 * 0.216 * 0.4

P(x = 3) = 0.3456

Probability that :

Exactly 4 bulldozer will be operational at the end of 6 months :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 4) = 4C4 * 0.6^4 * 0.4^0

P(x = 1) = 1 * 0.1296 * 1

P(x = 1) = 0.1296

Answer:

I do not agree with Sylvia

Step-by-step explanation:

Given

1 small box

64 triangle pattern blocks

Required

Is she right?

From the question, we understand that she fills the box with 64 blocks.

For the fact that she did this; it does not mean that the volume of the small box is 64 cubic units (even if she filled the box completely and the triangle pattern blocks are identical)

The reason for this is that, the volume of each box may not be 1 cubic unit.

So, first she needs to determine the volume of each pattern block, then multiply by 64. If the result is 64, then the volume of the box is 64 cubic units.

Since, it is not stated, we will not make any assumptions.

Hence, I do not agree with Sylvia.