A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength?

A.

0.034 newtons/amp·meter

B.

0.17 newtons/amp·meter

C.

0.26 newtons/amp·meter

D.

0.77 newtons/amp·meter

E.

6.0 newtons/amp·meter

A square loop of wire lies in the plane of the page. A decreasing magnetic field is directed into the page. The induced current in the loop is maximum and clockwise.

The region of space where an object experiences a magnetic force towards it is called magnetic field.

The change in magnetic field induces the current. This induced current again opposes the original magnetic field in the opposite direction. The original magnetic field is decreasing into the page. So, magnetic field of induced current will have to add it and into the page.

Thus, the induced current in the loop is maximum and clockwise.

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Answer:

[tex]F=ma \\ 14000 = 5m \\ m = \frac{14000}{5} \\ \therefore \: m = 2800 \: kg[/tex]

Answer:

The amplitude of a wave is the height of a wave as measured from the highest point on the wave (peak or crest) to the lowest point on the wave (trough). Wavelength refers to the length of a wave from one peak to the next.

Explanation:

Answer:

4, 56

Explanation:

Hope this helped!

Answer:

4, 56

Ex................................................................................

Braking force is applied to brakes to stop the car. The average braking force is 2kN.

Force is the product of mass of the object and acceleration.

The braking force is the force applied on the brakes to stop the car at a distance.

Suppose, the mass of the car is m=1000kg

The initial velocity of the car is u=10m/s

The time is t=5s

The final velocity of the car is v = 0 m/s

Applying the first equation of motion, to calculate the acceleration,

v=u + at

a=(v−u) / t

a =0−10 / 5

a =−2m/s²

Then, apply Newton's Second Law of Motion to calculate the braking force

F = ma = 1000 x 2= 2000 N or 2kN

Thus, the magnitude of the average braking force on the car is most nearly 2kN.

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The value of maximum current for A 35-mf capacitor which is connected to an ac source with a frequency of 400 hz and a maximum emf of 20 v is 1.76 ampere.

The capacitance of a capacitor is the ratio of the electric charge stored inside the capacitance to the potential difference.  The value of capacitive reactance can be calculated as,

[tex]X_c=\dfrac{1}{2\pi fC}[/tex]

Here, C is capacity and (f) is the frequency.

A 35-mf capacitor is connected to an AC source with a frequency of 400 hz and a maximum emf of 20 v.

[tex]X_c=\dfrac{1}{2\pi fC}\\X_c=\dfrac{1}{2\pi (35\times10^{-6})(400)}\\\X_c=11.37\rm\; ohm[/tex]

The maximum current flowing is the ratio of maximum emf to the capacitive reactance. Thus, the maximum current is,

[tex]I_{\text{RMS}}=\dfrac{V_{\text{RMS}}}{X_C}\\I_{\text{RMS}}=\dfrac{20}{11.37}\\I_{\text{RMS}}=1.76\rm\; Amp[/tex]

Thus, the value of maximum current for A 35-mf capacitor which is connected to an ac source with a frequency of 400 hz and a maximum emf of 20 v is 1.76 ampere.

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Answer:

15 N

Explanation:

Force=mass x acceleration

15= 5 x 3

Answer: 15N

Explanation:

If the object has a mass of 5kg and accelerates 5m/s^2, force that is applied to move the object is simply the product of mass and acceleration.

Carol's speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle is 36km/hr.

The average speed of a moving body can be calculated by dividing the distance moved by the time taken.

According to this question, the distance between Carol's house and her uncle's house is 24 km. The speed it will take her to get to her uncle's house in 40 minutes by motorcycle is as follows:

Average speed = 24km ÷ 40/60 hour

Average speed = 36km/hr

Therefore, Carol's speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle is 36km/hr.

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The total work is done by the weight lifter who lifts a mass m at constant speed to a height h in time t, is (mgh)/t.

The amount of energy which is required to lift a object at a height is known as the work done of lifting an object.

The work done to lift an object for a time period of t is given as,

[tex]W=\dfrac{mgh}{t}[/tex]

Here, (m) is the mass of the object, (g) is the acceleration due to gravity and (h) is the height.

It is given that a weight lifter lifts a mass m at constant speed to a height h in time t. Thus, the work done by the weight lifter is,

[tex]W=\dfrac{mgh}{t}[/tex]

Hence, the total work is done by the weight lifter who lifts a mass m at constant speed to a height h in time t, is (mgh)/t.

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The frequency of the signal is = 2.5 Hz

The wavelength of the sonar device = 5.9 m

The velocity of the sound = 15 m/s

The frequency = ?

But the formula for the velocity of sound wave = frequency × wavelength

Male frequency the subject of formula,

f = v/ wavelength

f = 15/5.9

f = 2.5Hz

Therefore, the frequency of the signal is = 2.5Hz

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Explanation:

The study of properties of matter, energy and of their mutual relationships is called physics

Answer:

The Local Group/ Virgo Cluster

Explanation:

Our solar system is part of a galaxy called the Milky Way galaxy. The Milky Way galaxy is part of a small cluster of just over 30 galaxies known as the "Local Group." This cluster resides in a larger cluster of galaxies called the "Virgo Cluster" (sometimes called the Virgo Supercluster). The Virgo cluster contains just about 2000 galaxies.

Answer:

The object must be equally buoyant with the surrounding fluid

is an untrue statement - because the object could not float - it could be anywhere in the fluid

Answer:

Both

Explanation:

Both of them are part of newtons laws of motion

At a known mass of the spaceship, the amount of energy that would be needed to accelerate the spaceship to half the speed of light is 1.5 x 10⁸  x m (J).

The amount of energy that would be needed to accelerate a large spaceship to half the speed of light is calculated as folllows;

E = mc²

where;

half the speed of light = 1.5 x 10⁸ m/s

E = 1.5 x 10⁸  x m

Thus, at a known mass of the spaceship, the amount of energy that would be needed to accelerate the spaceship to half the speed of light is 1.5 x 10⁸  x m (J).

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When, the mass and gravitational constant is provided, the  velocity v in terms of r is 6.534 x 10⁶ r^(-1/2) m/s.

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The gravitational potential energy is directly proportional to the negative of product of masses of the object and inversely proportional to the distance between them.

U = - GMm/r

From the equation 1, k =-Ug

where k = Kinetic energy = 1/2mv²

here, m is the mass of the object, v is the velocity and g is the grvaitational acceleration.

1/2mv² = -(GMm/r) g

v = sq rt(2GM/r)

Given is the mass M =  3.2 x 10²³ kg , gravitational constant G = 6.67 x 10⁻¹¹ m³/kg.s²

Substitute the values and calculate the velocity v,

v = sq rt [( 2 x6.67 x 10⁻¹¹ x  3.2 x 10²³) / r]

v = 6.534 x 10⁶ r^(-1/2) m/s

Thus, the value of velocity v in terms of r is 6.534 x 10⁶ r^(-1/2) m/s.

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Relative to the movement of the building,  a mass damper on the roof of an earthquake resistant building move in the opposite direction.  The correct option is C.

Mass dampers absorbs the kinetic energy of the waves, converting them into the heat energy. This heat energy is dissipated to the hydraulic fluid.

The mass dampers used on roof of the buildings are called as the tuned mass dampers. They are also known as seismic dampers. When seismic wave strikes the building, it vibrates and sways. The kinetic energy of theses waves are absorbed by movement of the mass damper. The kinetic energy is converted to the heat energy which in turn is transmitted to the fluid.

Relative to the movement of the building, a mass damper on the roof of an earthquake resistant building move in the opposite direction.

Thus, the correct option is C.

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The total distance traveled during the recorded time interval would be 5 meters and the displacement of the object would be 5 meters.

Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.

As given in the problem we have to find out the total distance and the displacement of the object from the graph shown in the problem,

The displacement of the object = Final position - Initial position

                                                     =6 - 1

                                                     = 5 meters

Thus, The total distance traveled during the recorded time interval would be 5 meters and the displacement of the object would be 5 meters.

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The force between the two charges will be 16,000 N. It is the force exerted by one charge on another charge.

The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.

The given data in the problem is;

The magnitude of charge of sphere q₁  = +3.0 μC=-3.0×10⁻⁶ C

The magnitude of charge of sphere q₂ =  -9.0 μC=9.0×10⁻⁶ C

k is the proportionality constant = 9 × 10⁹ Nm²

r is the separated distance to be found;

The electric force is F =  0.20 mN = 0.20 ×10⁻³ N

The electric force is found as;

[tex]\rm F = \frac{K q_1q_2}{r^2} \\\\ \rm 0.20 \times 10^{-3} = \frac{9 \times 10^9 \times 3.0 \times 10^{-6}\times 3.0 \times 10^{-6} }{r^2} \\\\\ R^ 2 =4.04\times 10^{-4} \\\\ R= 0.020 \ m[/tex]

Hence, the force between the two charges will be 16,000 N.

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Answer: the guy is right

Explanation:

:)

Answer: here are some of the places that use nuclear fusion

Commonwealth Fusion Systems (CFS)

TAE Technologies.

General Fusion (Canada)

Helion Energy.

Tokamak Energy (U.K.)

First Light (U.K.)

Explanation: nuclear fusion is a nuclear reaction in which atomic nuclei of low atomic number fuse to form a heavier nucleus with the release of energy.

Answer:

The correct answer should be high amplitude : )

Explanation:

A high energy wave is characterized by a high amplitude, a low energy wave is characterized by a low amplitud

The emf is induced in the wire will be 1.56 ×10 ⁻³ V. The induced emf is the product of the magnetic field,velocity and length of the wire.

Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.

When the flux coupling with a conductor or coil changes, electromotive Force, or EMF, is said to be induced.

The given data in the problem is;

B is the magnitude of the magnetic field,= 5.0 ×10⁻⁵ T

V(velocity)=125 M/SEC

L(length)=25 cm=0.25 m

The maximum emf is found as;

E=VBLsin90°

E=125 × 5.0 × 10⁻⁵ ×0.25

E=1.56 ×10 ⁻³ V

Hence, the emf is induced in the wire will be 1.56 ×10 ⁻³ V

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Answer:

d

Explanation:

dence means closely compacted in substance.

Answer:

Power is defined as Work / Time

P1 = P2 = W1 / T1 = W2 / T2       W1 and W2 are not necessarily the same Power expended depends on both work input over a unit of time

Answer:

The bottom three pie graphs show the breakdown for each of three greenhouse gases in comparison to the total. Seventy two percent (72%) of the total greenhouse gases emitted was carbon dioxide, 18% methane and 9% nitrous oxide.

Explanation:

Answer:

According to sciences, when under moderate pressure and temperature, gases tend to follow the ideal gas law.

Answer:

91 is the missing number because an alpha particle with a charge of 2 was emitted.