Answer:
The number of turns is [tex]N = 1750 \ turns [/tex]
Explanation:
From the question we are told that
The inner radius is [tex]r_i = 12.0 \ cm = 0.12 \ m[/tex]
The outer radius is [tex]r_o = 15.0 \ cm = 0.15 \ m[/tex]
The current it carries is [tex]I = 1.50 \ A[/tex]
The magnetic field is [tex]B = 3.75 mT = 3.75 *10^{-3} \ T[/tex]
The distance from the center is [tex]d = 14.0 \ cm = 0.14 \ m[/tex]
Generally the number of turns is mathematically represented as
[tex]N = \frac{2 * \pi * d * B}{ \mu_o * r_o }[/tex]
Generally [tex]\mu_o[/tex] is the permeability of free space with value
[tex]\mu_o = 4\pi * 10^{-7} \ N/A^2[/tex]
So
[tex]N = \frac{2 * 3.142 * 0.14 * 3.75 *10^{-3} }{ 4\pi * 10^{-7} * 0.15 }[/tex]
[tex]N = 1750 \ turns [/tex]
How many marshmallows are in 80 bags if each bag hold 24 marshmallows?
Explanation:
80*24=1920 or 1,920
Just multiply
[tex]hopethishelpsyou[/tex]
Answer:
jeeze... this would be easier if the numbers were switched
Explanation:
i dont have an answer for ya but put 80x24=? in ur calculator
good luck m8
YOU ARE HUNGRY SO YOU WALK TO THE KITCHEN AND OPEN THE REFRIGERATOR DOOR. YOU NOTICE THAT THE LIGHT IS OFF AND THE FOOD IS COLD. YOU SEE THAT THE REFRIGERATOR IS PLUGGED IN THE WALL OUTLET. A MICROWAVE WHICH IS ON THE SAME ELECTRICAL OUTLET ALSO IS NOT WORKING.
MAKE A CLAIM, EVIDENCE, AND REASONING ABOUT ENERGY IN THE ABOVE SCENARIO
Which type of intelligence (analytic, creative, practical, verbal, mathematical, spatial, bodily-kinesthetic, musical, interpersonal, interpersonal, naturalist, or existentialist) does this individual has.
Professor Wooddro teaches an Introduction to Philosophy at the college. He loves to talk with students about the meaning of life and death and enjoys struggling with life's most challenging questions.
Answer:
verbal, IntrapersonalExplanation:
Remember, we are told that "Professor Wooddro teaches an Introduction to Philosophy at the college, and loves to talk about the meaning of life and death" which would require having verbal intelligence (the ability to understand and relate information using words).
Intrapersonal intelligence is also reflected by Professor Wooddro as we are told he "enjoys struggling with life's most challenging questions", which shows his knowledge of his own strengths or weaknesses.
Your mother has called you on your cell phone and asked you to pick up a few items at the grocery store on your way home. As you heard your mother state each item, which process transferred this information from your sensory memory to your short-term memory so you could jot each grocery item down?
Answer:
Encoding
Explanation:
Encoding is the initial learning of information. Encoding is the process of passing new information coming from sensory input into our brain so that it can be easily retrievable. In a nutshell, it is the sum total of the processes by which external information such as the list of items your mother asked you to pick up at the grocery store to be converted into a manner that can be stored within the brain and recalled later from long-term memory.
Encoding has to do with transferring external stimuli into short term and subsequently long-term memory.
What is the force of an object with a mass of 30 kg that is free falling?
Answer:
F = 294.3 [N]
Explanation:
To solve this problem we must use Newton's second law which tells us that force is equal to the product of mass by acceleration. It is this particular case the acceleration is due to the gravitational acceleration since the body is in free fall.
Therefore we have:
F = m*g
where:
F = force [N]
m = mass = 30 [kg]
g = gravity acceleration = 9.81 [m/s^2]
F = 30*9.81
F = 294.3 [N]
After she’s finished cooking Emily measures the mass of the dough balls. According to the law of conservation of mass, the mass of the dough bars should be equal to
Answer:
The weight of the dough bars after being cooked.
Name
4 items found
the first aid kit and
in
the lab.
Answer:
ummmmmwm whattt
Explanation:
wuhsnnsnsnsnms
Answer:
medicines
band-aids
aqua liquid
paracetamol
Explanation:
Extra items:
alcohol
cottons
bitadine
cotton buds
mask
What is the velocity of a car that travels 200 meters In 8 seconds?
Answer:
25m/s
Explanation:
200m/ 8s =25m/s
1. who was john locke?
2. what were his 3 big ideas?
3. what does each of his 3 big ideas mean?
Which statement about two objects having the same momentum is true?
The product of mass X velocity is the same for both.
Mass and velocity are the same for both.
They both have the same mass.
They both have the same velocity.
Answer:
The product of mass X velocity is the same for both
Explanation:
The momentum of a body is the product of its mass and velocity.
Momentum = mass x velocity
Two objects having equal momentum will have the same for the product of their mass and velocity.
It is amount of motion a body can produce.what is the medium of the sound waves the student hears
Answer:
A
Explanation:
the air is the medium man
Answer:
the desk
Explanation:
8.98 dm3 of hydrogen gas
is collected at 38.8 °C. Find
the volume the gas will occupy
at -39.9 °C if the pressure
remains constant.
Answer:
6.71dm³
Explanation:
Given parameters:
Initial Volume of hydrogen gas = 8.98dm³
Initial Temperature = 38.8°C; in Kelvin = 38.8 + 273 = 311.8K
Final temperature = -39.9°C; in Kelvin = -39.9 + 273 = 233.1K
Unknown:
Final volume = ?
Solution:
To solve this problem, we apply the Charles's law. It states at;
"The volume of a fixed mass (mole) of a gas varies directly as its absolute temperature if the pressure is constant".
Mathematically;
[tex]\frac{V_{1} }{T_{1} }[/tex] = [tex]\frac{V_{2} }{T_{2} }[/tex]
V and T are temperature values
1 and 2 are the initial and final states
Insert the parameters and solve for V₂
[tex]\frac{8.98}{311.8 }[/tex] = [tex]\frac{V_{2} }{233.1}[/tex]
V₂ x 311.8 = 8.98 x 233.1
V₂ = 6.71dm³
Hello:) how to do 3?:)
Answer:
A
Explanation:
Ok soo idk what question to ask but one of my friends said tht she was dressing as Harley Quinn and she said i should dress as her too but then i said no i dont rlly dress up of those kind of people but then she started to flip out because i couldnt dress as her?? Should I tell her that not all people can dress the same even if they want to or not? What should I say so she can stop saying things that are rude just bc she is mad and thats not my fault??
Answer:
You should tell her in a nice way that that's just not your style and if she doesnt accept that then maybe you should just not talk to her for a while and let her cool down
Explanation:
Hope this helps
Why might using the speed of light to determine the length of the meter be
more reliable than using a measured distance around Earth?
Answer:ghjkdfrtghjExplanation:
Tech A says that when checking a voltage drop across an open switch, a measurement of 12 volts is normal. Tech B says that when checking voltage drop across an open switch, a measurement of 12 volts means there are 12 volts on each side of the switch. Who is correct
Answer:
Tech B is correct.
Explanation:
The voltage drop between the two terminals of a circuit is the measurement of the potential difference between the two terminals.
If [tex]v_1[/tex] and [tex]v_2[/tex] ( assuming [tex]v_1 > v_2[/tex]) are potentials at terminal 1 and terminal 2 of the given open circuit.
According to A, the measurement of the potential drop is 12 volts, i.e
The measurement of potential difference [tex]=v_1 -v_2[/tex]
= 12 volts which is correct.
But according to B, a measurement of 12 volts means there are 12 volts on each side of the switch ([tex]v_1= 12[/tex] volts and [tex]v_2=12[/tex] volts), i.e
According to the claim of B, the potential difference (or drop) across the terminals is
[tex]v_1-v_2= 12-12=0[/tex] but the measured potential drop is 12 volts, so B is wrong.
Hence, Tech B is correct.
To understand the origin of the torque on a current loop due to the magnetic forces on the current-carrying wires.
This problem will show you how to calculate the torque on a magnetic dipole in a uniform magnetic field. We start with a rectangular current loop, the shape of which allows us to calculate the Lorentz forces explicitly. Then we generalize our result. Even if you already know the general formula to solve this problem, you might find it instructive to discover where it comes from.
a) Give a more general expression for the magnitude of the torque τ. Rewrite the answer found in Part A in terms of the magnitude of the magnetic dipole moment of the current loop m. Define the angle between the vector perpendicular to the plane of the coil and the magnetic field to be ϕ, noting that this angle is the complement of angle θ in Part A.
Give your answer in terms of the magnetic moment m, magnetic field B, and ϕ.
Answer:
The torque is [tex]\tau = B * m sin(\phi )[/tex]
Explanation:
Generally when current flow through a rectangular loop the magnetic dipole generated we can denote this as [tex]\vec m[/tex]
Here k is the length of the side of one side of the rectangular loop
Now when this loop is place in a magnetic field, the torque it experience is mathematically represented as
[tex]\vec \tau = \vec B \ X \ \vec m[/tex]
Here X stands for cross - product
From the question we are told that the angle between the vector ( [tex]\vec m[/tex])perpendicular to the plane of the coil and magnetic field(B) as [tex]\phi[/tex]
So
=> [tex]\tau = B * m sin(\phi )[/tex]
Which of the following describes the mass of an object precisely ? *
2.34 kg
2.345 kg
2 kg
2.3 kg
Answer:
2.345 would be the most precious because you have more numbers to work with and exact numbers
What road would exert the least amount of friction on a car?
A road laid out on an air-hockey table, with a thin coat of ice on the table, and a little bit of oil or lard on top of the ice.
NOTE: The car couldn't actually GO anywhere on this road, because a car needs friction in order to move where you want it to. A car on THIS road would just go wherever the wind blew it.
What force is needed to move a barrel 45-m if 3600 J of work are accomplished?
Answer:
The answer is 80 NExplanation:
The force acting on the object can be found by using the formula
[tex]f = \frac{w}{d} \\ [/tex]
where
d is the distance
w is the work done
We have
[tex]f = \frac{3600}{45} \\ [/tex]
We have the final answer as
80 NHope this helps you
The data table shows how the amplitude of a mechanical wave varies with
the energy it carries. Analyze the data to identify the mathematical
relationship between amplitude and energy. Use your equation to find the
energy if the amplitude is 6 units.
Amplitude
Energy
1 unit
2 units
2 units
8 units
3 units
18 units
4 units
32 units
Answer:
162
Explanation:
When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units. Therefore, option C is correct.
What do you mean by an amplitude ?The term amplitude is defined as the maximum distance moved by a point on a vibrating body or wave calculated from its equilibrium position.
We have given,
first amplitude, A = 1, corresponding energy = 2
second amplitude, A = 2, corresponding energy = 8
The energy of a string at a given amplitude is calculated as follows;
E ∝ A²
Energy varies as the square of the change in amplitude.
If amplitude of one has energy of two
Amplitude of 2 (double of 1)
= ( 2 x 2 ) = 4 x 2
= 8 4 times the energy at amplitude of 1.
Then for 8 units of amplitude change
8 x 8 = 64 x 2
= 128
Thus, When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units, option C is correct.
To learn more about an amplitude, follow the link;
https://brainly.com/question/15930409
#SPJ2
Your question is incomplete, most probably your question was
The data table shows how the amplitude of a mechanical wave varies with the energy it carries. Analyze the data to identify the mathematical relationship between amplitude and energy. Use your equation to find the energy if the amplitude is 8 units.
Amplitude
1
2
3
4
energy
2
8
18
32
A.66 units
B. 108 units
C. 128 units
D. 88 units
An object is moving with an initial velocity of 5.5 m/s. It is then subject to an acceleration of 2.5 m/s² for 11 s. How far will it have traveled during the time of its acceleration? OML HELP
Answer: 211.75m
Explanation:
Listing everything the question gives you:
Vi = 5.5
a = 2.5
t = 11
ΔX = ?
Then pick a kinematic equation to solve for the missing variable
I used this one: Δx = Vit + [tex]\frac{1}{2} at^2[/tex]
When you plug in all ur variables you get Δx = 211.75m
The object has travelled a distance of 211.75 meters.
We have an object moving with an initial velocity of 5.5 m/s.
We have to determine how far will it have traveled during the time of its acceleration.
What is Acceleration ?The rate of change of velocity with respect to time is called Acceleration.
a = dv/dt
According to the question -
initial velocity = u = 5.5 m/s
acceleration = a = 2.5 m/s²
time = t = 11 seconds
Therefore -
S = ut + [tex]\frac{1}{2} at^{2}[/tex]
S = 5.5 x 11 + 0.5 x 2.5 x 11 x 11
S = 211.75 meters
Therefore, the object has travelled a distance of 211.75 meters.
To solve more questions on Kinematics visit the link below-
https://brainly.com/question/13587439
#SPJ2
Explain and reason why the the moon rotates around the earth every lunar cycle
Pls explain ASAP
Best answer will be marked as BRAINLIEST✨
to avoid an accident, a driver with a mass of 60kg applies his brakes and decelrates from 30m/s to 1m/s in 2 seconds. how much force was absorbed by his seat belt
Answer:
[tex]F=-870\ N[/tex]
Explanation:
Net Force
The net force applied to an object of mass m that moves at an acceleration a is given by:
F=m.a
The acceleration can be calculated by the equations of the constant acceleration motion:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
Where vf is the final speed, vo is the initial speed, and t is the time.
Substituting the given values:
[tex]\displaystyle a=\frac{1-30}{2}=\frac{-29}{2}=-14.5\ m/s^2[/tex]
The force absorbed by his seat belt:
[tex]F=60\ kg\cdot (-14.5\ m/s^2)[/tex]
[tex]\boxed{F=-870\ N}[/tex]
Force absorbed by the seatbelt is : 870 N
Given data :
mass of body = 60 kg
Initial velocity ( V₁ ) = 30 m/s
Final velocity ( V₂ ) = 1 m/s
Time = 2 secs
Determine the force absorbed by the seat belt
Force = Mass * acceleration --- ( 1 )
where ;
acceleration = Δ v / t ---- ( 2 )
Δ v = ( 30 - 1 ) = 29 m/s
t = 2 secs
Back to equation ( 2 )
acceleration = 29 / 2 = 14.5 m/s²
∴ Force exerted on seatbelt
F = m * a
= 60 kg * 14.5 m/s² = 870 N
Hence we can conclude that the force absorbed by his seatbelt is 870 N
Learn more : https://brainly.com/question/24953628
Suppose you are climbing a hill whose shape is given by the equation z = 2000 − 0.005x2 − 0.01y2, where x, y, and z are measured in meters, and you are standing at a point with coordinates (60, 40, 1966). The positive x-axis points east and the positive y-axis points north. (a) If you walk due south, will you start to ascend or descend? ascend descend Correct: Your answer is correct. At what rate? Correct: Your answer is correct. vertical meters per horizontal meter (b) If you walk northwest, will you start to ascend or descend? ascend descend Correct: Your answer is correct. At what rate? (Round your answer to two decimal places.) Correct: Your answer is correct. vertical meters per horizontal meter (c) In which direction is the slope largest? What is the rate of ascent in that direction? vertical meters per horizontal meter At what angle above the horizontal does the path in that direction begin? (Round your answer to two decimal places.)
Answer:
(a) Ascend at 0.8 vertical meter/meter
(b) Descend at -0.2·√2 vertical meter/meter
(c) In the (-0.6, -0.8) direction. The path begins at 45° to the horizontal
Explanation:
The given equation of the shape of the hill is z = 2000 - 0.005·x² - 0.01·y²
The current location = (60, 40, 1966)
The direction of the positive x-axis = east
The direction of the positive y-axis = north
(a) Walking due south = Reducing the y-value 40
From the equation, the elevation varies inversely with the motion towards the north
Therefore, walking south increases the elevation, and we ascend
The rate is given by the partial derivative at in the -j direction, which is 0.02
The rate is therefore 40 × 0.02 = 0.8
(b)The unit vector in the northwest direction u = 1/√2·(-1, 1)
∴ The rate = (-0.01(60), -0.02(40))·u = (-0.6, -0.8)·1/√2·(-1, 1) = -0.2·√2
Therefore we descend
(c) The slope is largest in the grad of the function at the point (60, 40) which is given as follows;
d(2000 - 0.005·x² - 0.01·y² )/dx, d(2000 - 0.005·x² - 0.01·y² )/dy = (-0.6, -0.8)
Therefore, the direction is tan⁻¹(-0.8/-0.6) ≈ S 36.87° W
The slope =(√((-0.4)² + (-0.8)²) = 1
Therefore, the angle is 45° to the horizontal.
25 PTS AND BRAINLIEST ANSWER PLEASE HELP ME BEFORE 9 PM
A truck accelerates at a rate of 1 m/s2 for 10 seconds. At that time the truck continues traveling at a constant velocity for the next 20 seconds. The truck then begins to slow down at a rate of -1 m/s2 until it comes to rest.
1.What was the truck’s speed at 10 seconds?
2. How far did the truck travel during the first ten seconds?
3. How far did the truck travel for the whole 30 seconds?
Answer:
I think?
Explanation:
1. 20 seconds
2. 1 mile
3. 3 miles
I think i got it right not sure
Answer:
Explanation:
1m/ 10s^2
5 miles?
15 miles
How does a decrease in thermal energy affect the particle motion in each state of matter
A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motion model, h = -16t2 + v … t +s, where y is the initial velocity in feet per second and s is the height in feet, to calculate the amount of time the baseball is in the air before it hits the ground.
Answer:
t = 3.25 seconds.
Explanation:
A person throws a baseball from a height of 7 feet with an initial vertical velocity of 50 feet per second is given by :
[tex]h=-16t^2+vt+h_0[/tex]
[tex]h=-16t^2+50t+7[/tex]
We need to find the amount of time the baseball is in the air before it hits the ground. ATQ,
h = 0
[tex]-16t^2+50t+7=0\\\\t=\dfrac{-50 \pm \sqrt{50^2-4\times (-16)(7)} }{2(-16)}\\\\t=\dfrac{-50 + \sqrt{50^2-4\times (-16)(7)} }{2(-16)}, \dfrac{-50- \sqrt{50^2-4\times (-16)(7)} }{2(-16)}\\\\t=-0.134\ s,3.25\ s[/tex]
Neglecting negative value, t = 3.25 s
So, the baseball will hit the ground at t = 3.25 seconds.
otd-2)A softball is thrown straight up into the air at 25 m/s. if it returns to the thrower after 5.0 seconds, how high did it go?
One way:
The ball returned to the thrower's hand after 5 seconds. It spent 2.5 seconds going up, and 2.5 seconds coming back down.
Use the formula Distance = (1/2) (acceleration) (time squared)
Distance = (1/2) (gravity) (2.5 sec)
Distance = (1/2) (9.8 m/s ²) (6.25 sec² )
Distance = (4.9 m/s²) (6.25 sec²)
Distance = 30.63 meters
Another way:
The thrower threw the ball straight up at 25 m/s.
It sailed upward for 2.5 seconds.
At the top of its trip, before it started falling, its speed was zero.
Its average speed was (1/2) (25+0) = 12.5 m/s
At an average speed of 12.5 m/s for 2.5s, the ball rose (12.5x2.5) = 31.25m.
(Why are the two answers different ?
Because if the ball was thrown straight up at 25 m/s, it would actually return to the thrower in 5.1 seconds, not 5.0 seconds.
So if you use the acceleration of gravity to solve the problem, you get one answer, but if you use 5.0sec to solve it, you get a slightly different one.)
When a light ray enters water, its velocity is _________.
Answer:
UR ANSWER IS WAVELENGTH
