A stack of one dozen cookies of diameter 5 in. exactly fits in a cylindrical container of volume 176.715 in.3. Which is the thickness of each cookie? please show work!!

Answer:

W = 11340 J

Step-by-step explanation:

Given,

Force ( F ) = 567 N

Distance ( s ) = 20 N

To find : Work done ( W )

Formula : -

W = Fs

W = 567 x 20

W = 11340 J

Hence,

the amount of work done is 11340 J.

Answer:

x=120°

Step-by-step explanation:

sum of all angles in a triangle is equal to 180

let the unknown angle be

[tex] \alpha [/tex]

[tex]60 + 60 + \alpha = 180 \\ \alpha = 180 - 60 - 60 \\ \alpha = 60 \\ [/tex]

[tex] \alpha + x = 180 \\ x = 180 - \alpha \\ x = 180 - 60 \\ x = 120[/tex]

Answer:

y = 3x + 3

Step-by-step explanation:

when you check, only that equation delivers the correct x and y pairs.

x = 0, => y = 3×0 + 3 = 3

x = 1, y = 3×1 + 3 = 3+3 = 6

x = 2, y = 3×2 + 3 = 6 + 3 = 9

x = 3, y = 3×3 + 3 = 9 + 3 = 12

it all fits.

Answer:

y=3x-27

Step-by-step explanation:

[tex]\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]

               Write an equation of the line passing through (6, -9) and has a slope of -3.

[tex]\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}[/tex]

First, we need to write the equation in point-slope form:-

[tex]\hookrightarrow\sf{y-y_1=m(x-x_1)}[/tex]

[tex]\hookrightarrow\sf{y-(-9)=3(x-6)}[/tex]

[tex]\bigstar[/tex] On simplification,

[tex]\hookrightarrow\sf{y+9=3(x-6)}[/tex]

[tex]\bigstar[/tex] On further simplification,

[tex]\hookrightarrow\sf{y+9=3x-18}[/tex]

[tex]\star[/tex] Subtract 9 from both sides, which results in:-

[tex]\hookrightarrow\sf{y=3x-27}[/tex]

So we conclude that Option B is correct.

[tex]\rule{300}{1}[/tex]

Answer:

√5

Step-by-step explanation:

Given:

[tex]\displaystyle \large{5\div \sqrt{5}}[/tex]

Which can be rewritten as:

[tex]\displaystyle \large{\dfrac{5}{\sqrt{5}}}[/tex]

To find:

To find simplified form of the expression, keep in mind that surds should not remain as denominators. Therefore, what we have to do is to multiply both numerator & denominator by the surd itself so the denominator will be cleared as rational number.

[tex]\displaystyle \large{\dfrac{5\cdot \sqrt{5}}{\sqrt{5}\cdot \sqrt{5}}}[/tex]

We know that if same surds multiply each other, the surd will be canceled and remains only the insides. To express it in math, it can be as:

[tex]\displaystyle \large{\sqrt{a}\cdot \sqrt{a} = \left(\sqrt{a}\right )^2 =a}[/tex]

Therefore:

[tex]\displaystyle \large{\dfrac{5\sqrt{5}}{5}}[/tex]

Cancel 5:

[tex]\displaystyle \large{\sqrt{5}}[/tex]

Henceforth, the simplified expression is √5

Answer:

mean is 2 brothers.

mean, means average

Answer:

y intercept: 65

rate of change: $2.75

Step-by-step explanation:

Really quite simple lad. Your equation is y=2.75x+65. 65 is your y-intercept, and you have a rate of change of 2.75 per bouquet.

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]-2x+4y=8\implies 4y=2x+8\implies y=\cfrac{2x+8}{4} \\\\\\ y=\cfrac{2x}{4}+\cfrac{8}{4}\implies y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+2\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

since we know that's its slope, then

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{1}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{1}\implies -2}}[/tex]

so then we're really looking for the equation of a line whose slope is -2 and passes through (2 , 1)

[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-2}(x-\stackrel{x_1}{2}) \\\\\\ y-1=-2x-4\implies y=-2x-3[/tex]

Answer:

Step-by-step explanation:

167.00 / 100 = $1.67

Answer:

See below ~

Step-by-step explanation:

Details of Graph

Answer:

hope you understand......

The best estimate and the degree of freedom when the t-distribution is used to find a confidence interval is 7 and 56 respectively.

The best estimate from the information given in the research will be:

= X1 - X2

= 53.5 - 46.5

= 7

The degree of freedom will be:

= 38 + 20 - 2

= 56

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Answer:

A. -2

Step-by-step explanation:

Answer:

129060

Step-by-step explanation:

135 000 - .044(135000) = 129 060

[tex]\csc \theta \tan \theta - \tan \theta \sin \theta \\\\\\=\dfrac 1{\sin \theta} \cdot \dfrac{\sin \theta }{\cos \theta }- \dfrac{\sin \theta }{\cos \theta} \cdot \sin \theta\\\\\\=\dfrac{1}{\cos \theta}-\dfrac{\sin^2 \theta}{\cos \theta}\\\\\\=\dfrac{1- \sin^2 \theta}{\cos \theta}\\\\\\=\dfrac{\cos^2 \theta}{\cos \theta}~~~~~~~~~~~~~~;[\sin^2 \theta + \cos^2 \theta =1 ]\\\\\\=\cos \theta[/tex]

Let's write out some trigonometric identities that we can use:

Now let's try solving them out:

  [tex]csc(x)tan(x)-tan(x)sin(x)=\frac{1}{sin(x)}tan(x)-sin(x)tan(x)\\\\ csc(x)tan(x)-tan(x)sin(x)=tan(x)(\frac{1}{sin(x)}-sin(x))\\\\ csc(x)tan(x)-tan(x)sin(x)=tan(x)(\frac{1}{sin(x)} -\frac{sin^2(x)}{sin(x)} )\\\\csc(x)tan(x)-tan(x)sin(x)=tan(x)*(\frac{1-sin^2(x)}{sin(x)} )\\\\csc(x)tan(x)-tan(x)sin(x)=\frac{sin(x)}{cos(x)}*\frac{cos^2(x)}{sin(x)} \\\\csc(x)tan(x)-tan(x)sin(x)=\frac{sin(x)}{sin(x)}*\frac{cos^2(x)}{cos(x)}\\\\csc(x)tan(x)-tan(x)sin(x)=1 * cos(x)\\\\ csc(x)tan(x)-tan(x)sin(x)=cos(x)[/tex]

  *I used a different variable, but that doesn't change the answer

Answer: cos(x)

Hope that helps!

If there is no picture for the spinner and we assume that it is completely fair, meaning that you have an equal chance of landing on any spot: You will expect to get a certain color every 3 spins because you have 3 different colors. In this case the answer would be 20 pupcakes.

Answer:

0.9974

Step-by-step explanation:

[tex]arcsin( \frac{1}{7} ) = 0.1433 \\ cos( \frac{0.1433}{2} ) = 0.9974[/tex]

Answer:

1/3

Step-by-step explanation:

Number of pizza=12

Number of students=4

Therefore,4/12=4/4

=1/3

Answer:

33v - 48

Step-by-step explanation:

- 9v - 6(8 - 7v) ← multiply each term in the parenthesis by - 6

= - 9v - 48 + 42v ← collect like terms

= 33v - 48

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: - 9v - 6(8 - 7v)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - [(6 \times 8) - (6 \times 7v)][/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - (48 - 42v)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - 48 + 42v[/tex]

[tex]\qquad \sf  \dashrightarrow \:33v - 48[/tex]

Hope it helps ~

Answer:

scale

Step-by-step explanation:

it would be used to measure

The limit of the expressions [tex]3^{2n} + 1[/tex] and [tex]4^{n + 2} - 3[/tex] for n to infinity is infinity

The expressions are given as:

[tex]3^{2n} + 1[/tex]

[tex]4^{n + 2} - 3[/tex]

The limits of the expressions as they approach infinity are represented as:

[tex]\lim_{n \to \infty} 3^{2n} + 1[/tex] and [tex]\lim_{n \to \infty} 4^{n + 2} - 3[/tex]

Substitute [tex]\infty[/tex] for n in both expressions

[tex]\lim_{n \to \infty} 3^{2 * \infty} + 1[/tex] and [tex]\lim_{n \to \infty} 4^{\infty + 2} - 3[/tex]

Solve both expressions independently;

[tex]\lim_{n \to \infty} 3^{2n} + 1 = 3^{2 * \infty} + 1[/tex]

Evaluate the product

[tex]\lim_{n \to \infty} 3^{2n} + 1 = 3^{\infty} + 1[/tex]

Evaluate the exponent

[tex]\lim_{n \to \infty} 3^{2n} + 1 = \infty + 1[/tex]

Evaluate the sum

[tex]\lim_{n \to \infty} 3^{2n} + 1 = \infty[/tex]

Also, we have:

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 = 4^{\infty + 2} - 3[/tex]

Evaluate the sum

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 = 4^{\infty} - 3[/tex]

Evaluate the exponent

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 =\infty - 3[/tex]

Evaluate the difference

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 =\infty[/tex]

Hence, the limit of the expressions for n to infinity is infinity

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Answer:

cross multiplication

x