A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per minute. At point 2 in the pipe, the gauge pressure is 152kPa and the cross-sectional area is 8.00cm2. At point 1, 1.35m above point 2, the cross-sectional area is 2.00cm2. Part A Find the mass flow rate. M

Answers

Answer 1

Answer:

[tex]1.302\ \text{kg/s}[/tex]

Explanation:

[tex]\rho[/tex] = Density of water = [tex]1\ \text{kg/L}[/tex]

[tex]dV[/tex] = Change in volume = [tex]220\times 0.355\ \text{L}[/tex]

[tex]dt[/tex] = Time elapsed = 1 minute = 60 seconds

Mass flow rate is given by

[tex]\dot{m}=\rho\dfrac{dV}{dt}\\ =1\times \dfrac{220\times 0.355}{60}\\ =1.302\ \text{kg/s}[/tex]

The mass flow rate is [tex]1.302\ \text{kg/s}[/tex].


Related Questions

A container in the shape of a cube 11.6 cm on each edge contains air (with equivalent molar mass 28.9 g/mol) at atmospheric pressure and temperature 291 K. (a) Find the mass of the gas. kg (b) Find the gravitational force exerted on it. mN (c) Find the force it exerts on each face of the cube. kN (d) Why does such a small sample exert such a great force

Answers

Answer:

a.  0.00189 kg

b. 18.552 mN

c. 1.363 kN

d. Since the molecular density is high, the force exerted by the sample is thus high.

Explanation:

(a) Find the mass of the gas. kg

Using PV = mRT/M where P = pressure on gas = atmospheric pressure = 1.013 × 10⁵ Pa, V = volume of gas = L³ where L = length of cube = 11.6 cm = 0.116 cm,m = mas of gas, R = molar gas constant = 8.314 J/mol-K, T = temperature of gas = 291 K and M = molar mass of gas = 28.9 g/mol

So, m = PVM/RT = PL³M/RT

Substituting the values of the variables into the equation, we have

m = PL³M/RT

= 1.013 × 10⁵ Pa × (0.116)³ × 28.9 g/mol/ 8.314 J/mol-K × 291 K

= 0.0457 × 10⁵ Pa g/mol/2419.374J/mol

= 1.89 × 10⁻⁵ × 10⁵ g

= 1.89 g

= 1.89 × 10⁻³kg

= 0.00189 kg

(b) Find the gravitational force exerted on it. mN

The gravitational force, F exerted on it is its weight W

So, F = W = mg where m = mass of gas = 1.89 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²

F = mg

= 1.89 × 10⁻³ kg × 9.8 m/s²

= 18.522 × 10⁻³ kgm/s²

= 18.552 × 10⁻³ N

= 18.552 mN

(c) Find the force it exerts on each face of the cube. kN

Since pressure, P = F/A where F = force exerted on each face and A = area of each face = L² where L = length of side of cube = 11.6 cm = 0.116 m

So, F = PA since P = atmospheric pressure = 1.013 × 10⁵ Pa,

F = PL²

= 1.013 × 10⁵ Pa (0.116 m)²

= 0.01363 × 10⁵ N

= 1.363 × 10³ N

= 1.363 kN

(d) Why does such a small sample exert such a great force

To answer this question, we need to find the density of the gas in the cube.

So density of gas,ρ = m/V where m = mass of gas = 1.89 g and V = volume of gas = L³ and L = length of side of cube = 11.6 cm

ρ = m/V = m/L³ = 1.89 g/(11.6 cm)³ = 1.89 g/1560.896 cm³ = 0.00121 g/cm³

We now find the number of moles of gas in a cm³ by dividing its density by its molar mass.

So n = ρ/M = 0.00121 g/cm³ ÷ 28.9 g/mol = 23687.67 mol/cm³

Since there are 6.022 × 10²³/mol, we find the number of molecules in a cm³ which is n × 6.022 × 10²³/mol = 23687.67 mol/cm³ × 6.022 × 10²³/mol

= 143731.1 × 10²³ molecules/cm³

= 1.437311 × 10²⁸ molecules/cm³

≅ 1.44 × 10²⁸ molecules/cm³

Since the molecular density is high, the force exerted by the sample is thus high.

1. Swordfish are capable of stunning output power for short bursts. A 650 kg swordfish has a cross-sectional area of 0.92 m2 and a drag coefficient of 0.0091- very low due to some evolutionary adaptations. Such a fish can sustain a speed of 30 m/s for a few seconds. Assume seawater has a density of 1026 kg/m3. a) How much power does the fish need to put out for motion at this high speed

Answers

Answer:

[tex]P_{sp}=178.4W/kg[/tex]

Explanation:

From the question we are told that:

Mass of fish [tex]m_f=650kg[/tex]

Cross-sectional area [tex]A=0.92 m^2[/tex]

Drag coefficient of [tex]\mu= 0.0091[/tex]

Seawater  density [tex]\rho= 1026 kg/m^3.[/tex]

Speed of  Fish [tex]v=30 m/s[/tex]  

Generally the equation for Drag force F_d is mathematically given by

[tex]F_d = \mu * \rho *A v^2 /2[/tex]

[tex]F_d = 0.0091* 0.92* 1026* 30^2/2 \\F_d= 3865. 35 N[/tex]  

Generally the equation for high speed  Power  [tex]P_{sp}[/tex] is mathematically given by

[tex]P_{sp}=3865*35*\frac{v}{m_f}[/tex]

[tex]P_{sp}=F_d*35*\frac{30}{650}[/tex]

[tex]P_{sp}=178.4W/kg[/tex]

A magnetic field is passing through a loop of wire whose area is 0.026 m2. The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of 0.24 T/s. (a) Determine the magnitude of the emf induced in the loop. (b) Suppose the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part

Answers

Answer:

a) 6.24 × 10⁻³ V

b) 4.16 × 10⁻³ m²/s

Explanation:

Given that:

(a)

Area A = 0.026 m²

[tex]\dfrac{dB}{dt}=0.24 \ T/s[/tex]

[tex]e=\dfrac{d\phi}{dt} \\ \\ = \dfrac{d}{dt}(BA) \\ \\ =A\dfrac{dB}{dt} \\\\= 0.026 \times 0.24 \\ \\ = 0.00624\ V \\ \\ \mathbf{= 6.24 \times 10^{-3} \ V}[/tex]

(b)

[tex]Here; \\ \\ e =0\\\\ \dfrac{d}{dt}(BA) =0 \\ \\ \implies B\dfrac{dA}{dt}+ A\dfrac{dB}{dt} = 0 \\ \\ B\dfrac{dA}{dt}= -A\dfrac{dB}{dt} \\ \\ \dfrac{dA}{dt}= -\dfrac{A}{B} \dfrac{dB}{dt} \\ \\ = -\dfrac{0.026}{1.5}\times 0.24 \\ \\ \dfrac{dA}{dt}= 4.16 \times 10^{-3}\ m^2/s[/tex]

4. How does the changing volume of the air inside the balloon affect the density


Answers

Answer:

please give me brainlist and follow

Explanation:

Since density is described as mass divided by volume, as volume decreases, density increases. With enough drop in volume, the helium balloon becomes too dense to float.

• What value is used to identify each element in the periodic table?​

Answers

Answer:

protons

Explanation:

Which point on the standing wave is a node?

Answers

The point on the standing wave which is referred to as a node is point B and is denoted as option B.

What is Standing wave?

This is also called stationary wave and it is referred to as a combination of two waves moving in opposite directions, each having the same amplitude and frequency.

A node is referred to as a point along a standing wave where the wave has minimum amplitude which is therefore denoted as point B in the graph given below.

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5. If employers-want-union workers to return to work, they can ask the
court for an __

Answers

Answer:

they can asked to sue

Explanation:

bud

what is the planet that scientists are exploring now?​

Answers

Answer:

Mars

Explanation:

In the 1960s, humans set out to discover what the red planet has to teach us. Now, NASA is hoping to land the first humans on Mars by the 2030s. Mars has captivated humans since we first set eyes on it as a star-like object in the night sky.

good luck

please mark me as a brainliest

Two ice skaters, with masses of 40.0 kg and 65.0 kg , are at the center of a 50.0 m -diameter circular rink. The skaters push off against each other and glide to opposite edges of the rink. Part A If the heavier skater reaches the edge in 10.0 s , how long does the lighter skater take to reach the edge

Answers

Answer:

6.15 s

Explanation:

From the question,

Applying the law of conservation of momentum

Momentum of the Heavier skater = Momentum of the lighter skater.

Mv = mV................. Equation 1

Where M = mass of the heavier skater, m = mass of the lighter skater, v = Velocity of heavier skater, V = velocity of the lighter skater.

But,

v = r/t........................ Equation 2

V = r/t'................ Equation 3

Where r = radius of the circular rink, t = time taken for the heavier skater to reach the edge, t' = time taken for the lighter skater to reach the edge.

Substitute equation 2 and equation 3 into equation 1

M(r/t) = m(r/t')............. Equation 4

Given: M = 65 kg, m = 40 kg, r = 50/2 = 25 m, t = 10 s.

Substitute into equation 4 and solve for t'

65(25/10) = 40(25/t')

162.5 = 1000/t'

t' = 1000/162.5

t' = 6.15 seconds

What keeps the Earth's atmosphere from floating away? Earth's gravity keeps the air molecules of the atmosphere from escaping the area surround Earth The attraction between the different molecules of atmospheric gases The temperature of the gas is not high enough to allow it to spread out and escape the area surrounding Earth The differentiation between temperatures of the Earth and outer space traps the gases in the atmosphere

Answers

Answer: it is the earth gravity :’)

Explanation:

Earth's gravity keeps the air molecules of the atmosphere from escaping the area surround Earth

A boy held a ball in the air what force is he applying?

Answers

Answer:

strength

Explanation:

Answer:

Potential energy

Explanation:

Since the boy is holding is, it is not moving. So, it has potential energy. Also, since it is in the air, it has gravitational potential energy.

PLEASE HELP

name 4 fundamentally different options for cooking a chicken​

Answers

Answer:

roasting,

broiling,

pan-broiling,

pan-frying,

grilling.

Explanation:

good luck

Answer:

Explanation:

1. Stir frying

2. Pan frying

3. Grilling /BBQ

4. Baking/roasting

If I have an object with a 6.0 µC charge , and another with a -2.0 µC charge, when they touch how do I find the new charges

Answers

When charged objects touch, you can assume that the charges move between the objects, so that the total amount of charge doesn't change but it splits equally between the two objects.

-- like two water tanks standing next to each other, with a different amount of water in each one.  When you connect a pipe between their bottoms, some water flows across until the LEVEL of water is the same in both tanks.

-- like one hard full balloon and one soft mooshy balloon.  When you connect them together, some air flows from the hard balloon into the soft balloon, until the pressure of air is the same in both balloons.  

The total amount of charge on your two objects is (+6.0 μC  -  2.0 μC).  That's +4.0 μC  .

When they touch, charges move around until the charge is the same on both objects . . . +2 μC.

Fizik
Dua perintang 5 Ω dan 10 Ω disambung selari dengan 9 V bekalan kuasa. Kira kuasa output bekalan kuasa.​

Answers

Answer:

P = 24.32 W

Explanation:

The question is, "Two resistors 5 Ω and 10 Ω are connected in parallel with a 9 V power supply. Calculate the output power of the power supply.".

The voltage of the power supply, V = 9 V

Resistor 1, R₁ = 5 Ω

R₂ = 10 Ω

The equivalent of parallel combination of resistors is given by :

[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_{eq}}=\dfrac{1}{5}+\dfrac{1}{10}\\\\R_{eq}=3.33\ \Omega[/tex]

The power of the output is given by :

[tex]P=\dfrac{V^2}{R_{eq}}\\\\=\dfrac{9^2}{3.33}\\\\P=24.32\ W[/tex]

So, the output power is equal to 24.32 W.

The concepts in this problem are similar to those in Multiple-Concept Example 4, except that the force doing the work in this problem is the tension in the cable. A rescue helicopter lifts a 81.7-kg person straight up by means of a cable. The person has an upward acceleration of 0.729 m/s2 and is lifted from rest through a distance of 7.86 m. (a) What is the tension in the cable

Answers

Answer:

Explanation:

Given that:

distance (z) = 7.86 m

mass of the person = 81.7 kg

Acceleration (a) = 0.729 m/s²

By using Newton's second law along the vertical axis:

[tex]T - mg = ma\\ \\ T = ma + mg \\ \\ T = m(a+g) \\ \\[/tex]

T = 81.7 (0.729 +9.8)

T = 860.22 N

The work done now is:

[tex]W_T = T\times z \\ \\[/tex]

[tex]W_T = 860.22 \times 7.86[/tex]

[tex]\mathbf{W_T =6761.3292\ N}[/tex]

Calories are a unit of energy that are reserved for heat energy but can be
directly converted to and from mechanical units of energy (Joules). How
many calories of energy are there in 500 Joules of energy?

Answers

Use photo to see the solve of your problem

Speed and time play a major factor in:
Scrimmage
Tactical movement
Situation awareness
Drill

Answers

Answer:

Tactical movement

Explanation:

Speed and time play a significant factor in Tactical movement. The correct option is B.

What is a Tactical movement?

Tactical movement refers to the coordinated and strategic movement of military units or teams to achieve a specific objective. It is a fundamental aspect of military operations and involves the use of various tactics and techniques to move troops and equipment safely and efficiently on the battlefield.

Tactical movement can involve various modes of transportation, such as on foot, in vehicles, or by air. It also involves the use of cover and concealment to avoid detection by the enemy, and the use of communication and signal systems to coordinate movements and maintain situational awareness.

The success of the tactical movement depends on many factors, including the terrain and weather conditions, the size and composition of the units involved, the available resources and equipment, and the tactics and strategies employed by both friendly and enemy forces. It requires careful planning, training, and execution to ensure that the movement is successful and achieves the desired outcome.So, tactical movement is an essential component of military operations, and plays a critical role in achieving victory on the battlefield.

Here in the Question,

Tactical movement refers to the movement of military units or teams in a coordinated and strategic manner to achieve a specific objective. In such movements, speed and time are critical factors because they determine the success or failure of the mission. The speed of movement can help to surprise the enemy, take advantage of a weakness in their defense, or seize a key position before they can respond. Time is also important because the longer it takes to achieve the objective, the more likely the enemy is to detect and counter the movement. Therefore, tactical movement requires careful planning and execution to ensure that the right units move at the right speed and at the right time to achieve the desired outcome.

Therefore, the correct option is B i.e Tactical movement.

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Which is not a component of an electromagnet?
A. solenoid
B. power source
C. ferromagnetic core
D. permanent magnet

Answers

It would probably be B

the melting point and boiling point of Ice are respectively
a. 273k,373k. b. 373k,273k c.0k,100k d.100k,0k​

Answers

a. 273k,373k

This is the answer.

One of the scientists suggests that he can build a
cooling system for the theoretical photovoltaic cells
Experiment 2, which will keep the cells 1°C cooler
dan normal but decrease their efficiency by 1%. The
teoretical photovoltaic cells capturing which frequency
ranges
, if any, would benefit from this cooling system?

Answers

Answer: SORRY

SORRY AM DOING IT FOR POINTS

Explanation:

Moira is experiencing noticeable memory loss, muscle loss, and bone loss. What age group is Moira most likely in?
adolescence
early adulthood
middle adulthood
late adulthood

Answers

Late adulthood is the answer

Answer:

Late adulthood

Explanation:

Just did it :)




HELP PLEASE
Two 24 ohm resistors are in parallel and placed across a 12 V battery. What is the current in each branch of the circuit?
20 A
0.0125 A
0.5 A
.

Answers

Answer:

.5 A

Explanation:

You leave a pastry in the refrigerator on a plate and ask your roommate to take it out before youget home so you can eat it at room temperature, the way you like it. Instead, your roommateplays video games for hours. When you return, you notice that the pastry is still cold, but thegame console has become hot. Annoyed, and knowing that the pastry will not be good if it ismicrowaved, you warm up the pastry by unplugging the console and putting it in a clean trashbag (which acts as a perfect calorimeter) with the pastry on the plate. After a while, you find thatthe equilibrium temperature is a nice, warmTeq.. You know that the game console has a mass ofm1. Approximate it as having a uniform initial temperature ofT1. The pastry has a mass ofm2and a specific heat ofc2, and is at a uniform initial temperature ofT2. The plate is at the sameinitial temperature and has a mass ofm3and a specific heat ofc3. What is the specific heat ofthe console

Answers

Answer:

   [tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]

Explanation:

This is a calorimeter problem where the heat released by the console is equal to the heat absorbed by the cupcake and the plate.

           Q_c = Q_{abs}

where the heat is given by the expression

           Q = m c_e ΔT

            m₁ c_{e1) (T₁-T_{eq}) = m₂ c_{e2} (T_{eq} -T₂) + m₃ c_{e3} (T_{eq}- T₁)

note that the temperature variations have been placed so that they have been positive

They ask us for the specific heat of the console

           [tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]

An explosive eruption by a single volcano can affect
OA. only the lifeforms living on the volcano.
OB. only the lifeforms living on the same continetu
OC. lifeforms throughout the world.
OD. Earth's climate but not its lifeforms.

Answers

I think the answer is C but it also could be D

Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 246 Hz, while the other produces 289 Hz. When a tuning fork is sounded together with the 246-Hz tone, a beat frequency of 18.0 Hz is produced. When the same tuning fork is sounded together with the 289-Hz tone, a beat frequency of 25.0 Hz is produced. What is the frequency of the tuning fork

Answers

Answer:

[tex]264\ \text{Hz}[/tex]

Explanation:

Beat frequency of the first case = 18 Hz

Beat frequency of the second case = 25 Hz

Tone of first fork = 246 Hz

Tone of second fork = 289 Hz

First case

Beat frequency is given by

[tex]\Delta f=|f_2-f_1|\\\Rightarrow f_1=246\pm18\\\Rightarrow f_1=264, 228\ \text{Hz}[/tex]

Second case

[tex]f_2=289\pm 25\\\Rightarrow f_2=264, 314\ \text{Hz}[/tex]

The frequency of the tuning fork is [tex]264\ \text{Hz}[/tex].

Select the correct answer.
Which graph shows the correct relationship between kinetic energy and speed?

Answers

Answer:

D

Explanation:

Kinetic energy = 1/2mV^2

From the formula above, we can deduce that kinetic energy is proportional to the square of speed. That is,

K.E = V^2

Graphically, the relationship isn't linear but a positive exponential. Therefore, option D is the correct answer.

Answer:

Its D

Explanation:

What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?

Answers

Answer:

Wavelength = 1.36 * 10^{-34} meters

Explanation:

Given the following data;

Mass = 0.113 kg

Velocity = 43 m/s

To find the wavelength, we would use the De Broglie's wave equation.

Mathematically, it is given by the formula;

[tex] Wavelength = \frac {h}{mv} [/tex]

Where;

h represents Planck’s constant.

m represents the mass of the particle.

v represents the velocity of the particle.

We know that Planck’s constant = 6.6262 * 10^{-34} Js

Substituting into the formula, we have;

[tex] Wavelength = \frac {6.6262 * 10^{-34}}{0.113*43} [/tex]

[tex] Wavelength = \frac {6.6262 * 10^{-34}}{4.859} [/tex]

Wavelength = 1.36 * 10^{-34} meters

An 85-year-old woman who was having trouble breathing checked into the hospital. There, her heart stopped beating and doctors determined she suffered heart failure. After being resuscitated, she was in a coma and had no brain function. Her family then made the difficult decision to take her off life support, and the woman passed away.

Which order of events did the woman experience?
brain death Right arrow. clinical death Right arrow. somatic death
somatic death Right arrow. brain death Right arrow. clinical death
clinical death Right arrow. brain death Right arrow. somatic death
clinical death Right arrow. somatic death Right arrow. brain death

Answers

Answer:c

Explanation:

clinical death Right arrow. brain death Right arrow. somatic death this order of events did the woman experience. Hence option C is correct.

What is death ?

The permanent end of all biological activities that support an organism is defined as death. Death may also be defined as the permanent cessation of functioning of the entire brain, including the brainstem, in creatures with a brain, and brain death is frequently used as a legal definition of death.Normally, the remnants of a previous creature begin to degrade quickly after death. Death is an unavoidable process that happens in all species. Turritopsis dohrnii, for example, is physiologically immortal. They can, however, perish from causes other than ageing.

It has been difficult to determine when someone has died. Initially, death was defined as the cessation of breathing and heartbeat.

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Approximate the human form as an unclothed vertical cylinder of 0.3 m diameter and 1.75 m length with a surface temperature of 30 oC.(a)Calculate the heat loss in a 10 m/s wind at 20 oC.(b)What is the heat loss if the skin is covered with a thin layer of water (i.e., sweat) at 30 oC and the relative humidity of the air is 60 %

Answers

Answer:

[tex]q=1118.865W[/tex]

Explanation:

From the question we are told that

Diameter of the cylinder [tex]D=0.3m[/tex]

Length of the cylinder [tex]L=1.75m[/tex]

Surface temperature of cylinder [tex]T_s=30 \textdegree C=303k[/tex]

Speed of air [tex]V=10m/s[/tex]

Temperature of air [tex]T=20 \textdegree C[/tex]

Generally the equation for Reynolds number is mathematically given by

[tex]Re_D=\frac{VD}{v}[/tex]

where

[tex]v=15.27*10^-^6[/tex]

[tex]Re_D=\frac{10*0.3}{15.27*10^-^6}[/tex]

[tex]Re_D=1.96*10^5[/tex]

Generally the equation for Nusselt number is mathematically given by

[tex]N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}[/tex]

where

Prandtl number

[tex]Pr=0.71[/tex]

[tex]N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}[/tex]

[tex]N_u=0.6(1.96*10^5)^{0.6}(0.71)^{0.37}[/tex]

[tex]N_u=791.53[/tex]

Generally the equation for convective heat transfer is mathematically given by

[tex]h=Nu \frac{k}{D}[/tex]

where

[tex]k=25.7*10^{-3}[/tex]

[tex]h=791.53*\frac{25.7*10^{-3}}{0.3}[/tex]

[tex]h=67.81W/m^2K[/tex]

Generally the equation for surface area of a cylinder is mathematically given by

[tex]A=\pi DL[/tex]

[tex]A=\pi *0.3*1.75[/tex]

[tex]A=1.65m^2[/tex]

Generally the equation for convective heat transfer is mathematically given by

[tex]q=h4(T_s-T_{inty)}[/tex]

[tex]q=(67.81)*1.65*(30-20)\\[/tex]

[tex]q=1118.865W[/tex]

8. Before leaving the ground an airplane traveling with constant acceleration makes a run on the
runway of 1800 meters in 12 seconds. Determine:
a. Acceleration
b. Speed at which it leaves the ground
c. Distance traveled during the first and twelfth seconds

Answers

Answer:

[tex]\color{Blue}\huge\boxed{Answer} [/tex]

B. Speed at which it leaves the ground
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