A sample of gas collected at 685 mm Hg occupies 131 mL. At constant temperature, what pressure does the gas exert if the volume increases to 478 mL? a. 188 b. 1320 c. 128 d. -88.8

Answers

Answer 1

Answer:

a.  P=188mmHg

Explanation:

A gas undergoing a change of volume and pressure at constant temperature (and not changing the number of molecules), follows Boyle's Law:  [tex]P_1V_1=P_2V_2[/tex]

The units of these quantities can be any measure of pressure and volume, so long as long as the units are the same between beginning and ending conditions.

Substitute and solve:

[tex]P_1V_1=P_2V_2[/tex]

[tex](685[mmHg])(131[mL])=P_2(478[mL])[/tex]

[tex]\dfrac{(685[mmHg])(131[mL\!\!\!\!\!\!\!\!\!{--}])}{478[mL\!\!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(478[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}{478[mL] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----}}[/tex]

[tex]187.730125523[mmHg]=P_2[/tex]

Accounting for significant figures, [tex]P_2=188[mmHg][/tex]


Related Questions

Specialized periodicals in which scientists publish the results of their works are called

Answers

Specialized periodicals in which scientists publish the results of their works are called scientific journals.

In educational publishing, a scientific journal is a periodical book intended to similarly the progress of technology, typically by way of reporting new studies.

Journal articles may include original research, re-analyses of studies, opinions of literature in a selected place, proposals of new but untested theories, or opinion pieces.

These scientific journals include the following.

original articles, case reports, technical notes, pictorial essays, reviews, commentaries editorials.

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What is the pH of a solution with a
POH of 8.35?

Answers

Answer: The pH of the solution is 5.65

Explanation:

The relationship between the pH and the pOH is that [tex]pH+pOH=14[/tex].

Given this, we can plug in the pOH and subtract that from 14.

[tex]14-pOH=pH\\14-8.35=5.65[/tex]

I hope this helped! Pls give brainliest!! :)

Answer:

Give the man above me brainliest

How many moles of propane
react when 294 g of CO2 form?

C3H8 +502 3CO2 + 4H₂O

?] mol C3H8

Answers

Starting mass: 294
Mass ratio: 3/5

The 9.6 g object displaced
3.2 mL of water.
What is its density in g/mL?
density=[?] g/mL

Answers

Answer: 3

Explanation:

Density is mass/volume divide the mass 9.6 by the volume of 3.2

[tex]\frac{9.6}{3.2} =3[/tex]

The density of the object displaced in water is equal to 3 g/ml.

What is the density?

The density of a substance can be described as the substance's mass per unit of its volume. The symbol is generally used to represent density ρ and the letter D can be used.

The mathematical formula of the density of a material can be represented as shown below:

Density = Mass/volume

ρ = m/V

The density of a material varies with pressure as well as temperature. There is a small variation in the density of the solids and liquids but much larger for gases. Increasing the pressure of the substance decreases the volume and thus increases its density.

As the object displaced water of volume of 3.2 ml.  

Therefore, the volume of the object, V = 3.2 ml

The mass of the object, m = 9.6 g

The density of the object placed in water can be calculated as:

Density of object = 9.6/3.2 = 3 g/ml

Therefore, the density of the object is 3 g/ml.

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Calculate the molecular mass of Al2(SO4)3(Molecular mass of Al=27, S=32, O=16) Pls fast

Answers

Al₂(SO₄)₃

= 2.Al+3.S+12.O

= 2.27 + 3.32+12.16

= 54+96+192

=342 g/mol


What is the mass of a 7.426-mole sample of sodium hydroxide (NaOH molar mass = 40.0 g/mol)?
Select one:
5.360 g
40.00 g
179.1g
297.0 g

Answers

[tex](40.0)(7.426)=\boxed{297.0 \text{ g (to 4 sf)}}[/tex]

Consider the reaction below.

2Al2O3 --> 4Al + 3O2

How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?
(a) 17.7 mol
(b) 19.9 mol
(c) 39.8 mol
(d) 53.0 mol

Answers

Answer:

(b)  19.9 moles

Explanation:

To convert from moles Al to moles O₂, you need to multiply the given value by the mole-to-mole ratio of each component. This ratio is constructed via the coefficients in the balanced reaction. The desired unit (moles O₂) should be placed in the numerator to allow for the cancellation of units.

2 Al₂O₃ ----> 4 Al + 3 O₂
                    ^         ^            

         

26.5 moles Al           3 moles O₂
---------------------  x  ----------------------  =  19.9 moles O₂
                                 4 moles Al

Identify the reaction type for each unrelated, radical reaction as either initiation, propagation, or termination. Reaction A. A chlorine chlorine bond splits into two chlorine radicals. What type of reaction is reaction A

Answers

A is the initial reaction when a chlorine bond splits into two chlorine radicals.

What are radicals?

In chemistry, a radical is an atom, molecule, or ion that has an unpaired valence electron.

The question is based on Radical Chain Reaction. And these reactions have three different phases: Initiation, Propagation and Termination.

Reaction A- Initiation

Reaction B- Termination

Reaction C- propagation

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What volume did a helium-filled balloon have at 18.1 °C and 2.61 atm if its new volume was 59.9 mL at 1.92 atm and 12.5°C?
a. 44.9
b. 63.8
c.43.2
d. 83.0

Answers

Answer:

a.  V=44.9mL

Explanation:

For a gas undergoing all of these changes, it will be important to combine Boyle's Law and Charles' Law to form the following equation (if it isn't already known):

[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

Where the Temperatures must be measured in Kelvin.

Recall that to convert Celsius to Kelvin, one must add 273 or use the equation [tex]T_C+273=T_K[/tex].

Thus, [tex]T_1=(18.1+273)[K]=291.1[K][/tex]  and [tex]T_2=(12.5+273)[K]=285.5[K][/tex]

To solve for the requested quantity, note that all of the other units match between beginning and end, so we substitute and solve:

[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

[tex]\dfrac{(2.61[atm])V_1}{(291.1[K])}=\dfrac{(1.92[atm])(59.9[mL])}{(285.5[K])}[/tex]

[tex]\dfrac{(2.61[atm] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----})\bold{V_1}}{291.1[K] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}*\dfrac{291.1[K] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}{2.61[atm]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}=\dfrac{(1.92[atm]\!\!\!\!\!\!\!\!\!\!\!{--})(59.9[mL])}{285.5[K\!\!\!\!\!{-}]}*\dfrac{291.1[K\!\!\!\!\!{-}]}{2.61[atm]\!\!\!\!\!\!\!\!\!\!\!{--}}[/tex]

[tex]V_1=44.928677576[mL][/tex]

Accounting for significant digits, [tex]V_1=44.9[mL][/tex]

Consider the compound calcium nitrate, Ca(NO3)2. Which statements are true about this compound? Check all that apply. There are two atoms of oxygen. There are six atoms of oxygen. There are two nitrogen atoms. There are two calcium atoms.

Answers

Calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.

Ca(NO₃)₂

Calcium nitrate is a compound consisting of calcium, nitrogen and oxygen compoundsIt is an inorganic compoundIt is water-absorbent and absorbs moisture from airCalcium nitrate has two forms, hydrous and anhydrousBoth forms are colourless and odourlessThe reaction to form Calcium nitrate is Ca + 2NO₃ -----> Ca(NO₃)₂

The number of oxygen atoms is: 2x3 = 6The number of nitrogen atoms is: 2x1= 1There is 1 calcium atom

Thus, calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.

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Answer:

B)There are six atoms of oxygen.

C)There are two nitrogen atoms.

Explanation:

edge 2023

Consider these two electron configurations for neutral atoms L and M.
L-1s²2s²2p^6 3s²
M-1s²2s²2p^6 3s¹3p¹
What is the atomic number of L?

Answers

Calculate electrons

1s²2s²2p⁶3s²[Ne]3s²

Total electrons=10+2=12

The element is Magnesium with symbol Mg as atomic no is 12

Additional:-

M:-

1s²2s²2p⁶3s¹3p¹

Excited state of magnesium

Which of the following shows the combustion of a hydrocarbon?
OA. NaOH + HCI → NaCl + H₂O
OB. CO₂ + H₂O → H₂CO3
OC. 2C₂H₂ +502 + 4CO2 + 2H₂O
OD. C₂H4 + Cl₂ ⇒ C₂H4Cl₂​

Answers

Answer:

C

Explanation:

with combustion you must know that your products must be carbon dioxide and water. I think you copied your question incorrectly.

Did you write these compounds?
KBr
2 NH₂OH
2HNO3

Answers

The missing components of the neutralisation reaction include the following:

KBr KBr 2NH4OHKBr 2NH4OH2HNO2

What is neutralisation reaction?

Neutralisation reaction is defined as the type of reaction that leads to the formation of salt and water when an acid and a base reacts.

From the reactions given the missing components are replaced as follows:

HBr + KOH --> KBr + H2O

H2SO4 + 2NH4OH --> (NH4)2SO4 + 2H2O

2HNO3 + Mg(OH)2 --> Mg(NO3)2 + 2H2O

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Ethanoic acid reacts with ethanol to form an ester and water. How many moles of ethanoic acid are required to produce 0.5 mol of the ester? (A) 0.05 (B) 0.5 (C) 1 (D) 2​

Answers

0.5 moles of ethanoic acid are required to produce 0.5 mol of the ester , Option B is the right answer.

What is esterification reaction ?

The reaction in which a carboxylic acid combine with an alcohol to form ester and water is called esterification reaction.

It is given in the question that

Ethanoic acid reacts with ethanol to form an ester and water

C₂H₅OH  +  CH₃​COOH  →   CH₃COOH  +  H₂O

The moles of ethanoic acid required to produce 0.5 mole of ester.

In the following reaction it can be seen that the mole fraction of ethanoic acid to ester is 1: 1

Therefore 0.5 mole of ethanoic acid will be required to produce 0.5 mol of ester.

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What is the answer to this question? I need help!!

Answers

Answer:

[tex]\fbox {C}[/tex]

Explanation:

By repeating the experiment with new amounts of each reactant, this conflict can be resolved as we can see the effect of a reactant on the final amount of product formed.

A solution is 0.225M Na2SO4. What is the molarity of the sodium ion in solution

Answers

The molarity of the sodium ion in the solution is 0.450 M.

How do we determine the molarity of sodium ions in a solution?

The molarity of the sodium ion in a solution can be determined by the dissociation of the given solution Na2SO4(sodium sulfate).

The dissociation of Na2SO4 is computed as follows:

1 mole of Na2SO4 dissociates to give 2 moles of sodium cations and 1 mole of sulfate anion.

i.e.

[tex]\mathbf{Na_2SO_4 \to 2Na^{+} + SO_4^{2-}}[/tex]

The molarity for sodium-ion [Na+] is:

= 2 × 0.225 M

= 0.450 M

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Ordinary water boils at 100°C. Can it be made to boil at 95°C or 105°C.​

Answers

It can be done. Normally the boiling point of water is 100°C. It will boil at temperature greater than 100°C more quickly. Water can be boiled at 95°C but for that the atmospheric pressure of the water should be decreased which will decrease the boiling point of water.

Concept :

To boil water at 95°C, decrease the atmospheric pressure.

At 105°C, the water will be boiling quickly than normal at 100°C.

The best way is add alcohol .

The common way is that decrease the atmospheric pressure .

This will work as per Boyles law ,and boiling point can be decreased.

but it has few restrictions

You can't decrease pressure simply at normal conditionsFor decreasing pressure you have to go hill tops .

Hence there is a spare way

Add alcohol

General alcohols like ethanol,butanol can decrease the boiling point of water

Given the balanced equation representing a
reaction:
2NO+ O₂ → 2NO₂ + energy
1. The mole ratio of NO to NO₂ is
(1) 1 to 1
(2) 2 to 1
(3) 3 to 2
(4) 5 to 2

Answers

Answer: it would be a 1 to 1 ratio

Explanation: originally it would be 2 to 2 but you have to reduce

Ammonia gas occupies a volume of 450. mL at a pressure of 720. mm Hg. What volume will it occupy at standard pressure?
Show your work Please!!!!

Answers

the amount of ammonia,

V1 = 450 ml

P1 pressure equals 720 mmHg.

P2 is the standard pressure (1 atm is 760 mmHg).

V2 = the volume,

By applying Boyle's law,

P1V1 =P2V2V2 = P1V1/ P2

= (720 × 450) / 760V2

= 426 ml

426 ml is the volume at standard pressure.

Please answer step by step.

Answers

3 moles of NaOH reacts with 1 mole of phosphoric acid.

What is the moles ratio of the NaOH and Phosphoric acid reaction?

The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:

[tex]3\:NaOH + H_{3}PO_{4} \rightarrow Na_{3}PO_{4} + 3\:H_{2}O \\ [/tex]

Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.

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7.0 mol Mn reacts with 5.0 mol
O2 according to the equation below:
2Mn + O₂ → 2MnO
How many moles of MnO form from
5.0 mol Mn?
? ] mol MnO
Round your answer to the tenths place.

Answers

Answer:

5.0 mol

Explanation:

From the coefficients of the equation, we know that for every 2 moles of Mn consumed, 2 moles of MnO are produced.

Thus, the number of moles of Mn consumed is equal to the number of moles of MnO produced, and thus the answer is 5.0 mol.

The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.

What is a limiting reagent?

In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.

In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.

Thus, the moles of oxygen consumed by 7 moles of Mn is:

2 moles Mn = 1 mole O₂

7 moles Mn = 3.5 moles O₂

The available moles of O₂ = 5 mol.

The remaining moles of O₂ = 5-3.5 moles

The remaining moles of O₂ = 1.5 moles

The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.

The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂

1 mole O₂ = 2 moles MnO

1.5 moles O₂ = 2 * 1.5 moles MnO

1.5 moles O₂ = 3 moles MnO

Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.

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A thermodynamically-controlled process describes a reaction that ________.

Answers

A thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.

What is a  thermodynamically-controlled process?

A  thermodynamically-controlled process is a reaction in which the ratio of the product formed is determined by the relative stability of the products.

Thermodynamic control ensures that the most stable or more stable of two products is formed.

Therefore, a thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.

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What mass of ammonium nitrate
is needed to dissolve in 995 g of
water to make a 1.50 m solution?

Answers

Answer:

=> 119.4597 g

Explanation:

From our question, we have been provided with the molarity of the resultant solution.

We know that, molarity of a solution is contained in 1 L or 1000 cm³ of solution.

Hence we have 1.50 moles in 1000 cm³.

Also, we know that, 1 cm³ equivalent to 1 g for water.

Thus, from our question we have 995 cm³ of water.

Lets now solve our problem;

1.5 moles are contained in 1000 c

x moles are contained in 995 cm³

Cross multiply

[tex]x \: moles \: = \frac{(995 {cm}^{3} \times 1.5 \: moles )}{(1000 {cm}^{3} )} \\ = \frac{1492.5 \: moles}{1000} \\ = 1.4925 \: moles[/tex]

1.4925 moles of NH4NO3 are required to be dissolved in water.

To find the mass of solute (NH4NO3) we use the formula;

Mass = RFM (Relative Formula Mass) x Number of moles

[tex] = 80.04 \: \frac{g}{mol} \times1.4925 \: mol \\ = 119.4597 \: g [/tex]

Therefore the mass of NH4NO3 needed to be dissolved in 995 g of water is 119.4597 g

Answer:

119.4597

Explanation:

Acellus

The exothermic reaction between solid aluminium powder and solid manganese (IV) oxide, produces solid manganese and
another product. How many moles of aluminium powder are needed to produce 203.7 grams of manganese?

Answers

The number of moles of aluminum powder needed to produce 203.7 grams of manganese is 5 moles.

How to calculate the number of moles of Aluminium powder?

Heat, Mn, and Al2O3 are produced when aluminum powder and manganese dioxide are heated.

[tex]3MnO_{2} + 4Al - > 3Mn + 2Al_{2} O_{3} + Heat[/tex]

The balanced chemical equation in this situation indicates that there are 3 moles of manganese and 4 moles of aluminum involved in the reaction, which results in a 3:4 mole ratio.

You may make use of this mole ratio by calculating how many moles of aluminum are required to react with the 203.7g of Manganese. So,

Firstly, the mass of Aluminium has to be taken out

Let the mass be considered x.

So, the number of moles of Aluminium = x/27

Number of moles of Manganese = 203.7/54

Hence, the mass x will be,

[tex]x = 4 *203.7 * 27 / 3 * 54[/tex]

[tex]x = 135.8g[/tex]

Hence,  the number of moles of Aluminium is = 135.8/27 = 5 moles.

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Identify 3 chemicals that produce a potentially dangerous reaction with hydrochloric acid.

Answers

Alcohol, Carbides, and Chlorates

What is the volume of 0.24 mol oxygen (02) gas at 345 k and a pressure of 0.75

Answers

9.06 L  is the volume of 0.24 mol oxygen (02) gas at 345 k and a pressure of 0.75.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

We know that the ideal gas equation relates the pressure, volume, temperature, and moles of gases as:

PV =nRT

This is a combined gas law based on other gas law like Boyle's law, Charle's law, Avagadro's law, Gay Lussac's law

P =  pressure = 0.75 atm

V = volume = ?

n = moles = 0.24 mol

R = 0.0821 L atm / molK  [gas constant]

T = temperature = 345 K

Putting the values

Volume =[tex]\frac{nRT}{ P}[/tex]

Volume = 0.24 X 0.0821 X 345 / 0.75

= 9.06 L

Hence, 9.06 L is the volume of 0.24 mol oxygen (02) gas at 345 k and a pressure of 0.75.

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Which would be a good use for an organic substance? Check all that apply. A. Electrical conductors B. Waterproof coatings C. Fuels such as gasoline D. Microchips E. Plastic storage containers

Answers

Answer:

B. waterproof coating

Explanation:

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the hemiacetal below is treated with 18o-labeled methanol (ch3o*h) and acid. where will the label appear in the products?

Answers

The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

Position of 18o-labeled methanol in the products

The 18O label will appear at position b in the product as indicated in the image.

This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).

While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.

Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

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The scientists who have contributed to our current body of knowledge were
from what part of the world?

A. All areas of the world

B. Mostly Europe

C. Mostly the Middle East

D. Only the United States
SEMIT

Answers

Answer:

A.

Explanation:

Well, Nicola Tesla was from Croatia.

Albert Einstein was from Germany.

Thomas Edison was from the U.S.

So I think all over.

All areas of the world (A)

A car's tires are inflated to 2.11 atm at 25c. after driving to the grocery store, the tires are at 2.25 atm. what is the temperature of the air in the tire after the drive?

Answers

Answer:

T₂ = 26.7 °C

Explanation:

Because you are dealing with pressure and temperature, you can use Gay-Lussac's Law to find the final answer. The equation looks like this:

P₁ / T₁ = P₂ / T₂

In this form, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. You have been given the values for all of the variables but "T₂". Therefore, by plugging these values into the equation, you can simplify to find "T₂".

P₁ = 2.11 atm                   T₁ = 25 °C

P₂ = 2.25 atm                 T₂ = ?

P₁ / T₁ = P₂ / T₂                                            <--- Gay-Lussac's Law equation
(2.11 atm) / (25 °C) = (2.25 atm) / T₂           <--- Plug variables into equation

0.0844 = (2.25 atm) / T₂                            <--- Divide 2.11 by 25

(0.0844) x T₂ = 2.25 atm                           <--- Multiply both sides by T₂

T₂ = 26.7                                                    <--- Divide both sides by 0.0844

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