Explanation:
ddhjdkdjjjkjkjkkkkkkkkk
how is the medium of a wave and transmit of a wave similar and different?
plssss I really need helpppp
Answer:
Sound and light are similar in that both are forms of energy that travel in waves. They both have properties of wavelength, freqency and amplitude. Here are some differences: Sound can only travel through a medium (substance) while light can travel through empty space.
Acceleration is rate of change of
A-Position
B-Time
C-Velocity
D-Speed
Which statement explains why a blue car does not appear to be red?
A. Blue light is absorbed by the car.
B. Red light is absorbed by the car.
C. Blue light is transmitted through the car.
D. Red light is transmitted through the car.
Answer: B. Red light is absorbed by the car.
Explanation:
The colour of the object is decided by the wavelength of light that it reflects.
Light with the longest wavelength appears red, and light with the shortest wavelength appears violet. The wavelengths of visible light that an object reflects or transmits determine the color that the object appears to the human eye.
The blue car appears blue as it absorbs red light and reflects blue colour.
In 1960, the US Navy sent the submersible Trieste to the bottom of the Marianas Trench 11,000m deep. What was the force on the small 15cm diameter circular viewing window?
Answer:
P = d g h pressure = density * g * depth
P = 1000 kg/m^3 * 9.8 m / s^2 * 1.1 * 10E4 m = 1.1 * 10E8 N/m^2
F = P * A = 1.1 * 10E8 N/m^2 * pi * .075^2 / m^2 = 1.9 * 10E6 N/m^2
Please help me with 1&2
Answer:
1: A
Explanation:
Particles q1 = +8.0 UC, 92 = +3.5 uc, and
q3 = -2.5 uC are in a line. Particles qi and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q2?
Answer:
-22.3
Explanation:
Acellus
The net force on particle q2 is 21.7 N.
The given parameters:
Charge on particle 1, q1 = 8 μCCharge on particle 2, q2 = 3.5 μCCharge on particle 3, q3 = -2.5 μCDistance between particle 1 and particle 2 = 0.1 mDistance between particle 2 and particle 3, = 0.15 mThe net force on particle q2 is calculated as follows;
[tex]Q_2_{net} = q_{12} \ + \ q_{23}\\\\Q_2_{net} = \frac{kq_1q_2}{r_{12} ^2} \ + \ \frac{kq_2q_3}{r_{23}^2} \\\\Q_2_{net} = \frac{9\times 10^9 \times 8 \times 10^{-6} \times 3.5 \times 10^{-6} }{0.1^2} \ + \ \frac{9 \times 10^9 b\times 3.5 \times 10^{-6} \times (-2.5) \times 10^{-6} }{0.15^2} \\\\Q_2_{net} = 25.2 \ N \ - \ 3.5 \ N\\\\Q_2_{net} = 21.7 \ N[/tex]
Thus, the net force on particle q2 is 21.7 N.
Learn more about Coulomb's law here: https://brainly.com/question/24743340
help pls thx!!!!!!!
this is my last question i hope!
Answer:
Left
Explanation:
newtons is a measure of force. Since there is more newtons(force) pushing to the left, the object will move left. the 15 newtons cancel each other out, leaving only 5 newtons pushing to one side with no resistance.
8.
A
2.0 m
A 1.0 kg box slides without friction around the
loop-the-loop apparatus as shown in the
diagram. If the object starts from rest at point A,
and the radius of the loop is 0.75 m, what is the
speed of the box at point B?
Answer:
6.26 m/s
Explanation:
From the given information:
Using the conservation of Energy;
M.E at A =M.E at B
[tex]\dfrac{1}{2}mv_A^2 + mgh _A = \dfrac{1}{2}mv_B^2 + mgh_B[/tex]
Replacing the values given in the equation:
[tex](1) (9.8) (2 \ m) +\dfrac{1}{2}(0)^2 = 1 \times 9.8 \times 0 + \dfrac{1}{2}(1) \times v_B^2 \\\\ 19.6 + 0 = 0 + 0.5v_B^2\\ \\ v_B^2 = \dfrac{19.6}{0.5} \\ \\ v_B^2 = 39,2 \\ \\ v_B = \sqrt{39.2} \\ \\ \mathbf{v_B = 6.26 \ m/s}[/tex]
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answer:
A point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
Explanation:
We can find the distance with the following equation since the acceleration is cero (the disk rotates at a constant rate):
[tex] d = v*t [/tex]
Where:
v: is the tangential speed of the disk
t: is the time = 30 s
The tangential speed can be found as follows:
[tex] v = \omega*r [/tex]
Where:
ω: is the angular speed = 100 rpm
r: is the radius = 50 cm = 0.50 m
[tex] v = \omega*r = 100 \frac{rev}{min}*\frac{2\pi rad}{1 rev}*\frac{1 min}{60 s}*0.50 m = 5.24 m/s [/tex]
Now, the distance traveled by the disk is:
[tex] d = v*t = 5.24 m/s*30 s = 157.2 m [/tex]
Therefore, a point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
I hope it helps you!
please help in this question!! I will mark brainlest
Answer:
im not too sure about that all i know is history
Which of the following is a device
that breaks down light into colors
and produces an image of the
spectrum, which can help
determine the chemical
composition of a star?
A. barometer
B. phonograph
ald
C. spectograph
D. altimeter
Answer:
spectrograph
hope it is helpful to you
Answer: spectograph
Explanation:
Positioning a iron core in the middle of a current carrying solenoid creates:
a. A dipole
b. An electromagnet
c. Induced current
d. Mutual inductance
e. A natural magnet
Answer:
d
Explanation:
middle of a current carrying solenoid creates Mutual inductance
A 1,571 kilogram car travelling at 129 kilometers per hour is driving down a highway. The driver suddenly realizes a large animal is standing stationary on the highway in the way of the car. The driver manages to release their foot off the accelerator peddle, but does not have time to hit the brake peddle. The car strikes the animal which gets stuck to the car hood. Immediately after the collision the car slows to 59 kilometers per hour. Given this information, accident investigators are able to determine the mass of the animal as what
Answer:
[tex]1863.9\ \text{kg}[/tex]
Explanation:
[tex]m_1[/tex] = Mass of car = 1571 kg
[tex]u_1[/tex] = Initial velocity of car = 129 km/h
[tex]u_2[/tex] = Initial velocity of the animal = 0
[tex]v[/tex] = Velocity of combined mass = 59 km/h
[tex]m_2[/tex] = Mass of the animal
As the momentum of the system is conserved we have
[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow \dfrac{m_1u_1+m_2u_2}{v}-m_1=m_2\\\Rightarrow m_2=\dfrac{1571\times 129+0}{59}-1571\\\Rightarrow m_2=1863.9\ \text{kg}[/tex]
The mass of the animal is [tex]1863.9\ \text{kg}[/tex].
A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration?
B. How many radians did the disk turn while stopping ?
C. how many revolutions?
Answer:
A. α = - 1.047 rad/s²
B. θ = 14.1 rad
C. θ = 2.24 rev
Explanation:
A.
We can use the first equation of motion to find the acceleration:
[tex]\omega_f = \omega_i + \alpha t\\[/tex]
where,
ωf = final angular speed = 0 rad/s
ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s
t = time = 3 s
α = angular acceleration = ?
Therefore,
[tex]0\ rad/s = 3.14\ rad/s + \alpha (3\ s)\\[/tex]
α = - 1.047 rad/s²
B.
We can use the second equation of motion to find the angular distance:
[tex]\theta = \omega_i t + \frac{1}{2}\alpha t^2\\\theta = (3.14\ rad/s)(3\ s) + \frac{1}{2}(1.04\ rad/s^2)(3\ s)^2\\[/tex]
θ = 14.1 rad
C.
θ = (14.1 rad)(1 rev/2π rad)
θ = 2.24 rev
Light with a wavelength of 600 nm shines onto a single slit, and the diffraction pattern is observed on a screen 2.5 m away from the slit. The distance, on the screen, between the dark spots to either side of the central maximum in the pattern is 25 mm. (a) What is the distance between the same dark spots when the screen is moved so it is only 1.5 m from the slit
Answer:
"6.67 mm" is the right solution.
Explanation:
The given values are:
L = 2.5 my = .0125λ = 600 nmAs we know, the equation
⇒ [tex]\frac{y}{L} =\frac{x \lambda}{a}[/tex]
On substituting the values, we get
⇒ [tex]\frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}[/tex]
On applying cross multiplication, we get
⇒ [tex].0125a=2.5 (600\times 10^{-9})[/tex]
⇒ [tex]a=\frac{2.5(600\times 10^{-9})}{.0125}[/tex]
⇒ [tex]=1.2\times 10^{-4} \ m[/tex]
For new distance, we have to put this value of "a" in the above equation,
⇒ [tex]\frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex](1.2\times 10^{-4})y=1.5(600\times 10^{-9})[/tex]
⇒ [tex]y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}[/tex]
⇒ [tex]=3.22\times 10^{-3} \ m[/tex]
The total distance will be twice the value of "y", we get
= [tex]6.67\times 10^{-3} \ m[/tex]
or,
= [tex]6.67 \ mm[/tex]
Which of the following questions could you ask if you wanted to expand on the following piece of data?
Standardized testing helps hold schools and teachers accountable for students' performance.
A. Are there any negative effects associated with standardized testing?
B. How effective are the tests at assessing whether a student has learned a particular skill?
C. Who decides what should be included in a standardized test?
D. All of the above are correct.
If a force of 20kN acts on a circular rod of diameter 10mm, calculate the stress in the
rod.
The stress in the rod is equal to [tex]2.55 \times 10^8\;N/m[/tex]
Given the following data:
Force = 20 kN = 20,000 NewtonDiameter = 10 mm to m = 0.01 meterTo calculate the stress in the rod:
First of all, we would determine the area of the rod by using this formula:
[tex]Area = \frac{\pi d^2}{4} \\\\Area = \frac{3.142 \times 0.01^2}{4}[/tex]
Area = 0.00007855 meter.
Mathematically, stress is given by this formula:
[tex]Stress = \frac{Force}{Area}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Stress = \frac{20000}{0.00007855} \\\\Stress = 2.55 \times 10^8\;N/m[/tex]
Read more: https://brainly.com/question/14468674
Which sentence best explains the law of conservation of mass as applied to
chemical reactions?
A. The amount of mass changes only slightly during a chemical
reaction.
B. The volumes of the reactants and products are equal during a
chemical reaction.
C. The types of atoms can change during a chemical reaction, but
their masses cannot.
D. In a chemical reaction, the total mass of the reactants equals the
total mass of the products.
Answer:
A. The amount of mass changes only slightly during a chemical
reaction.
The 360-turn primary coil of a step-down transformer is connected to an ac line that is 120 V (rms). The secondary coil is to supply 15.0 A at 6.30 V (rms). 1) Assuming no power loss in the transformer, calculate the number of turns in the secondary coil. (Express your answer to two significant figures.)
Answer:
N₂ = 19 turns
Explanation:
A transform is a system with two different windings where the variation of the magnetic beam is the same, if there are no losses in the system we can use Faraday's law
V₁ = -N₁ [tex]\frac{d \Phi_B }{dt}[/tex]
v₂ = - N₂ \frac{d \Phi_B }{dt}
[tex]\frac{V_1}{N_1} = \frac{V_2}{N_2}[/tex]
in this case we look for the number of turns in the second winding
N₂2 = [tex]N_1 \ \frac{ V_2}{V_1}[/tex]
calculate us
N₂ = 360 6.30/ 120
N₂ = 18.9 turn
The number of turns must be an integer
N₂ = 19 turns
Help answer question in picture
In Figure (a), both batteries have em - 1.20 V and the external resistance R is a variable resistor. Figure (6) gives the electric potentials V between the terminals of each battery as functions of
Curve 1 corresponds to battery 1, and curve 2 corresponds to battery 2. The horizontal scale is set by R, -0.500 . What is the internal resistance of (a) battery 1 and (b) battery 2?
0.60
V(V)
0
-0.350
(
R(0)
(6)
Answer:
i know da way ese'
Explanation:
A man stands by a railway track.
A train travelling at 40 m/s takes 2.0 s to pass the man.
What is the length of the train?
40 m
D
80m
A 20m
B 38 m
Answer:
length of train is 80m
Explanation:
40*2
Ac soucre change it polarity how many time
4. Which of the following accurately pairs the part of an atom to its charge?
O A. Neutron-positive charge
O B. Electron-negative charge
O C. Proton-no charge
O D. Electron-no charge
Answer:
B Electrons are negatively charged while protons are positively charged
An SUV has a mass of 6000 kg and a compact car has a mass of 2000 kg. They both go around the same unbanked circular curve on the freeway. Bumper to bumper they go with the same speed vo. The centripetal acceleration of the compact car is ao and the centripetal force acting is Fo. The centripetal acceleration of the SUV is _____ ao of the compact car.
Answer:
Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.
Explanation:
FOR SUV:
[tex]ac_{suv} = \frac{mv^2}{r}\\[/tex]
where,
ac_suv = centripetal acceleration of the SUV = ?
m = mass of SUV = 6000 kg
v = speed of SUV = vo
r = radius of path
Therefore,
[tex]ac_{suv} = \frac{6000\ vo^2}{r}\\[/tex]---------------- equation (1)
FOR CAR:
[tex]ao = \frac{mv^2}{r}\\[/tex]
where,
ao = centripetal acceleration of the car = ?
m = mass of car = 2000 kg
v = speed of car = vo
r = radius of path
Therefore,
[tex]ao = \frac{2000\ vo^2}{r}\\[/tex]--------------------- equation (2)
Dividing equation (1) by eq(2):
[tex]\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao[/tex]
Therefore, the centripetal acceleration of the SUV is 3 times ao of the compact car.
Radio waves travel at the speed of light. What is the wavelength of a radio signal with a frequency of 9.45 x 10^7 Hz?
The wavelength of this radio signal is equal to 3.18 meters.
Given the following data:
Frequency = [tex]9.45 \times10^7[/tex] Hz.Speed of light = [tex]3 \times 10^8[/tex] m/s.What is wavelength?Wavelength can be defined as the distance between two (2) successive crests (troughs) of a wave.
How to calculate wavelength.Mathematically, the wavelength of a wave is given by this formula:
[tex]\lambda = \frac{V}{F}[/tex]
Where:
F is the frequency of a wave.V is the speed of a sound wave.[tex]\lambda[/tex] is the wavelength of a sound wave.Substituting the given parameters into the formula, we have;
[tex]\lambda = \frac{3 \times 10^8}{9.45 \times10^7}[/tex]
Wavelength = 3.18 meters.
Find more information on waves here: brainly.com/question/23460034
The wavelength of the radio signal travel at speed of light is 3.17m.
Given the data in the question;
Frequency of the radio wave; [tex]f = 9.45 * 10^{7}Hz = 9.45 * 10^{7} s^{-1}[/tex]Wavelength of a radio signal; [tex]\lambda = \ ?[/tex]WavelengthWavelength the spatial period of a periodic wave. That is to say, when the shapes of waves are Wavelength , the distance over which they are repeated is called wavelength. Wavelength is expressed as;
[tex]\lambda = \frac{v}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is the frequency of the wave and c is the velocity or speed of light ( [tex]c = 3*10^8m/s[/tex] )
We substitute our values into the expression above.
[tex]\lambda = \frac{c}{ f}\\ \\\lambda = \frac{3*10^8m/s}{9.45*10^7s^{-1}} \\\\\lambda = \frac{3*10^8ms/s}{9.45*10^7}\\\\\lambda = 3.17m[/tex]
Therefore, the wavelength of the radio signal travel at speed of light is 3.17m.
Learn more about wavelength: brainly.com/question/16776907
Coherent light of frequency f travels in air and is incident on two narrow slits. The interference pattern is observed on a distant screen that is directly opposite the slits. The frequency of light f can be varied. For f = 5.60 × 1012 Hz there is an interference maximum for e = 60.0°. The next higher frequency for which there is an interference maximum at this Part A What is the separation d between the two slits? angle is 7.47 x 1012 Hz Express your answer with the appropriate units. HÀ Value d = _______.
Answer:
A) d = 6.1857 10⁻⁵ m
Explanation:
In the double-slit experiment the constructive interference is given by the expression
d sin θ = m λ
d =[tex]\frac{m \lambda }{sin \theta}[/tex]
let's use the relationship between speed, wavelength and frequency
c = λ f
λ = c / f
λ = 3 10⁸ / 5.60 10¹²
λ = 5.357 10⁻⁵ m
I do not know India in order of interference, we will assume that m= 1
d = 1 5,357 10⁻⁵ / sin 60
d = 6.1857 10⁻⁵ m
5. What is the period of a vertical mass-spring system that has an amplitude of
71.3 cm and maximum speed of 7.02 m/s? The spring constant is 12.07 N/m.
The period of the vertical mass-spring is 0.64 s.
The given parameters:Amplitude of the spring, A = 71.3 cm Maximum speed of the spring, V = 7.02 m/sSpring constant, k = 12.07 N/mThe angular speed of the vertical mass-spring is calculated as follows;
[tex]V_{max} = A \omega\\\\\omega = \frac{V_{max}}{A} \\\\\omega = \frac{7.02}{0.713} \\\\\omega = 9.85 \ rad/s[/tex]
The period of the vertical mass-spring is calculated as follows;
[tex]f = \frac{\omega }{2\pi} \\\\T = \frac{1}{f} \\\\T = \frac{2 \pi}{\omega } \\\\T = \frac{2\pi }{9.85} \\\\T = 0.64 \ s[/tex]
Thus, the period of the vertical mass-spring is 0.64 s.
Learn more about period of oscillation here: https://brainly.com/question/20070798
Two objects, one with a mass of 2 m and one with a mass of 4 m are attracted to each other
by a gravitational force. If the force on 2 m is F, what is the force on mass 4 m in terms of F?
My best friend just returned from the clinic. She just found out she is HIV- positive. She invited me for dinner. What should I do? Should I go? What do I say to her and her family? Can I eat the foods she cooked or touched? Will she be all right? Imagine this letter is from a friend. Write a page response. Include reasons for your advice.
Answer:
yes, because you dont want to be mean and make her feel worse about it and hiv has something do with s3x not germs so yes go
Explanation:
