A package is dropped from a helicopter moving upward at 15 m/s

Answers

Answer 1

The distance the package above the ground when it was released, s ≈ 530 meters

What are kinematic equations?

The kinematic equation of motion gives the interrelationships of the variables of motion.The correct option for the distance the package above the ground when it was released, is the third option;

It is given that:

The velocity of the helicopter from which the package was dropped = 15 m/s

The time it takes the package to strike the ground = 12 seconds

The required parameter:

The height of the package from the ground when it was dropped

The kinematic equation of motion relating distance, s, time, t, acceleration due to gravity, g, initial velocity, u, and final velocity, v, is applied as follows;

The package continues the upward motion for some time, t₁, given as follows;

Upward motion of the package

v = u - g·t₁

v = 0 at highest point reached by the package;

Therefore;

0 = 15 m/s - 9.81 m/s²  × t₁

t₁ = 15 m/s/(9.81 m/s²) ≈ 1.5295022 seconds

The time the package takes to return to the initial starting point, t₂ = t₁

The time the package falls after returning to the point it was dropped, t₃, is given as follows;

t₃ = t - (t₂ + t₁) = t - 2 × t₁

∴ t₃ = 12 s - 2 × 1.5295022 s ≈ 8.940996 s

From the symmetry of the motion of a projectile, the velocity of the package when returns to its staring point where it was dropped = u (Downwards) = 15 m/s

The distance the package falls, s, which is the distance the package above the ground when it was released, is given as follows;

s = u·t + (1/2)·g·t²

s = 15× 8.940996  + (1/2) × 9.81 × 8.940996² = 526.22755346 ≈ 530

The distance the package falls, s ≈ 530 m = The height of the

The distance the package above the ground when it was released, s ≈ 530 meters

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Related Questions

How far away is the closest star?

Answers

Answer: Proxima Centauri is the closet star about 40,208,000,000,000 km away. 

Explanation:

Answer:

The closest star is about 25,300,000,000,000 miles (39,900,000,000,000 kilometers) away

Explanation:

A pulley system is used to lift an object. Which factor could affect the efficiency of the system? (1 point)
O the mass of the person pulling
O the distance the weight is lifted
O the friction of the individual pulleys
O the mass of the object

Answers

Answer:

the distance the weight is lifted

Explanation:

Which section from the article BEST explains why wavelength and frequency are dependent on each other? (A) "Amplitude And Height" (B) "Wavelength And Cycle" (C) "Frequency And Period" (D) "Speed"

Answers

C! Bejxjxksjxjcu u jkdmskxckc

For a bike that went a distance of 100 meters in 45 seconds
southeast to his friend's house. what would his velocity be?

Answers

Answer:

velocity = Displacement

Time

Velocity = 100m 45° SE

45s

= 2. 11m/s 45° SE

A proton moves with a speed of 0. 985c. (a) calculate its rest energy

Answers

The rest energy of the proton will be 938 MeV. The rest energy is related to the rest mass of the proton.

What is rest energy?

The rest energy is the rest mass times the square of the speed of light of a particle at rest in an inertial frame of reference.

The rest energy is found as;

[tex]\rm E_R= mC^2\\\\ E_R=(1.67 \times 10^{-27})\times 3 \times 10^8)^2\\\\ E_R= 9.375 \times 10^8 / eV[/tex]

Convert into the mega electron volt;

[tex]\rm E_R= 938 \ MeV[/tex]

Hence, the rest energy of the proton will be 938 MeV

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Two charges of +2.6 μC and –5.4 μC experience an attractive force of 6.5 mN. What is the separation between the charges?

Answers

Answer:

Explanation:

[tex]q_{1} =+2.6 X10^{_-6}C \\q_{2} =-5.4 X10^{_-6}C \\F=6.5mN\\F=\frac{Kq_{1}q_{2} }{d^{2} }[/tex]

A radar transmits a signal towards an aeroplane. The velocity of the signal is 3.0 x 10^8 m/s. After 0.0036 s, the radar detects the reflected signal. What is the distance of the aeroplane from the radar?

Answers

The distance of the airplane from the radar will be 1.08×10⁶ m. Distance can refer to a physical length.

What is distance?

Distance is a numerical representation of the distance between two objects or locations.

The distance of the airplane from the radar is found by the formula;

Distance = velocity × time

Distance =  3.0 x 10^8 m/s× 0.0036 s,

Distance =  1.08×10⁶ m.

Hence, the distance of the airplane from the radar will be 1.08×10⁶ m.

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Which of the following is a pure
substance?
A. Heterogenous mixture
B. Homogenous mixture
C. Solution
D. Element

Answers

Answer:

B. Homogenous mixture

Explanation:

........

NEED HELP ASAP PLEASE!
The primary coil of a transformer has 1,000 turns of wire, and its secondary coil has 2,000 turns of wire. The input voltage is 140 V. What is the output voltage of the transformer?

Answers

Answer:

Here is the solution hope it helps:)

Answer:

280v

Explanation:

An astronaut lands on a new, recently discovered planet in a different star system. The astronaut measures the acceleration due to gravity on the planet to be 12m/s2, and the mass of the planet is measured to be 7. 5E23kg. What is the radius of the new planet?

Answers

Answer:

The radius of the new planet is ~2.04 * 10⁶ m, or 2,041,752 m.

Explanation:

We can use Newton's Law of Universal Gravitation:

[tex]\displaystyle F_g=G\frac{Mm}{r^2}[/tex]

Let's look at Newton's 2nd Law:

[tex]F=ma[/tex]

We can set these equations equal to each other:

[tex]\displaystyle G\frac{Mm}{r^2} =ma[/tex]

The mass of the second mass (astronaut) cancels out. We are left with:

[tex]\displaystyle G\frac{M}{r^2} =a[/tex]

We are solving for the radius of the new planet, so we can rearrange the equation:

[tex]\displaystyle r=\sqrt{\frac{GM}{a} }[/tex]

Substitute in our known values given in the problem (G = 6.67 * 10⁻¹¹ ; M = 7.5 * 10²³ ; a = 12).

[tex]\displaystyle r =\sqrt{\frac{(6.67\times 10^{-11})(7.5 \times 10^{23}}{12} }[/tex][tex]r=2.04 \times 10^6[/tex]

The radius of the new planet is ~2.04 * 10⁶ m.

How long will it be before the moon will be too far away from Earth to totally cover the sun after a solar eclipse?

Answers

Answer:

600 million years

Explanation:

i think its pretty simple and u should memorize it :)

You throw a ball straight up into the air with velocity 40 ft/sec and catch it (at the same height) when it comes back down. What is the total distance traveled by the ball

Answers

The total distance traveled by the ball is determined as 49.68 ft.

Height travelled by the ball

The height travelled by the ball or the maximum height attained by the ball is calculated as follows;

v² = u² - 2gh

at maximum height, v = 0

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (40²)/(2 x 32.2)

h = 24.84 ft

Total distance = 2 x 24.84 ft = 49.68 ft

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Identify the amplitude of the wave using the picture below.

Answers

Answer:

Line 2 is the amplitude

Explanation:

The amplitude is the distance from equilibrium to the top of the maximum or minimum of the wave.

A tube is open only at one end. A certain harmonic produced by the tube has a frequency of 475 hz. The next higher harmonic has a frequency of 1425 hz. The speed of sound in air is 343 m/s

Answers

The formula for the fundamental frequency for an open tube at one end is : F = nV/4L the integer n = 3 which describe the frequency 450 hertz and length of tube L = 0.6m approximately

What is frequency?

Frequency of the object is defined as the number of cycles attend in a second .

Given that a tube is open only at one end. And a certain harmonic produced by the tube has a frequency of 450 Hz. The next higher harmonic has a frequency of 750 Hz. The formula for the fundamental frequency for an open tube at one end is :

[tex]F = \dfrac{V}{4L}[/tex]

That is, 1st harmonic

[tex]\dfrac{V}{4L} = F[/tex]

2nd harmonic =

[tex]\dfrac{3V}{4L} = 3F[/tex]

3rd harmonic =

[tex]\dfrac{5V}{4L} = 5F[/tex]

The general formula can therefore be [tex]F =\dfrac{ nV}{4L}[/tex]

For the first harmonic in the question,

[tex]450 = \dfrac{343n}{4L}[/tex]

make 4L the subject of the formula

[tex]4L = \dfrac{343n}{450}[/tex]

The next higher harmonic will be

[tex]750 = \dfrac{343(n + 2)}{4L}[/tex]

make 4L the subject of the formula

[tex]4L = \dfrac{343(n + 2)}{ 750}[/tex]

Equate the two 4L

[tex]\dfrac{343n}{450} = \dfrac{343( n + 2)}{750}[/tex]

cross multiply

[tex]257250n = 154350( n + 2 )[/tex]

[tex]257250n = 154350n + 308700[/tex]

collect the likes term

[tex]257250n - 154350n = 308700[/tex]

[tex]102900n = 308700[/tex]

[tex]n =\dfrac{ 308700}{102900}[/tex]

n = 3

Given that the speed of sound in air is 343 m/s, The length of the tube can be calculate by using the same formula.

[tex]F = \dfrac{nV}{4L}[/tex]

[tex]450 = \dfrac{3(343)}{4L}[/tex]

[tex]4L = \dfrac{1029}{450}[/tex]

4L = 2.28

[tex]L = \dfrac{2.28}{4}[/tex]

L = 0.57 m

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help please!
will give brainliest to the correct answer.

question; the work one by friction force to stop a car of mass 1000 kg moves with velocity 72km/h is ..........

a) 72 x 10³ J

b) 2 x 10⁴ J

c) 2 x 10⁵ J

d) 4 x 10⁵ J
​​
an explanation for future reference would be appreciated^^​

Answers

Answer:

b)

Explanation:

The work done by friction is equal to the all of the initial Kinetic Energy lost when the vehicle comes to a complete stop

KE = 1/2 m v^2

       72 km / hr = 20 m/s

 KE = 1/2  *  1000 kg  * (20 m/s)^2  = 200 000 J = 2 x 10^4 J

During which season is the sun highest in the sky?.

Answers

Answer: summer

Explanation:

In June, when the Earth is tilted towards Sun and the Sun reaches its highest point in the sky, that is called the summer solsticeand is the longest day of the year.

2. At the earth’s surface, a projectile is launched straight up at a speed of 10. 0 km/s. To what height will it rise? ignore air resist

Answers

Answer:

5.097 m

Explanation:

H = vo t - 1/2 a t^2

   = 10t - 1/2 (9.81) t^2       max occurs at -b/2a   =  10/9.81=1.0194 sec

  sub in this 't' value to get H =5.097 m

If I am driving on the highway and see a pig on the road and go from 60m/s to 20 m/s in 5 s. What is my acceleration? ​

Answers

Explanation:

Acceleration = final velocity - initial velocity

______________________

time taken

= 20 m/s - 60m/s

________________

5seconds

= -40 m/s

_______

5 seconds

= -8m/s^2

If air resistance acts on a falling object will all of its potential energy be converted into kinetic energy?

Answers

Answer:

No, some energy will be dissipated energy due to work of air resistance.

I need help with my homework please?

Answers

Answer:

i need the describtion like what i need to do

Explanation:

Answer:

it's easy bro once try yourself if you can't then l am here

what particle collides with a fissionable nucleus in order to begin the fission process?

Answers

Answer:

neutrons

Explanation:

Neutrons are usually released when fission takes place. Fission of a nucleus may be spontaneous, that is, it may happen at random due to internal processes within the nucleus. Fission can also be induced by bombarding a nucleus with a neutron.

You walk 6 meters east followed by 4 meters west in 4 seconds. What is your velocity

Answers

Answer:

16 velocity

Explanation:

A 1.5 x 105 kg train is accelerating. The force applied to the train is 7.0 x 104 N. What is the train’s acceleration?

Answers

Answer:

See below

Explanation:

F = ma

7 X 10^4   =  1.05 x 10^5   * a

a = .666  = 2/3 m/s^2

Place the elements c, n, and o in order of increasing ionization energy

Answers

The increasing order for the first ionization energy has been:

< C < N < O.

What is ionization energy?

The first ionization energy has been the amount of energy required for removing the electron from the gaseous state. The molecules that have small structures and available valence electrons, the ionization energy has been decreased.

In the periodic table, on moving from left to right there has been an increase in the size of the atom, as well as the valence electrons. The increase in size results in more attraction by the nucleus resulting in increased first ionization energy.

The increasing order for the first ionization energy has been:

C < N < O.

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I need help on this asap!!!!

Answers

In my opinion the answer is C, your net force cannot be zero so that eliminated D. The velocity cannot be constant because the direction is always changing. The speed is constant, but there are forces acting on the object such as the acceleration, without this there is no circular path. So the only answer which I see viable is C

Two beams of coherent light are shining on the same piece of white paper. with respect to the crests and troughs of such waves, darkness will occur on the paper where

Answers

Answer:

"where crests and troughs have their maxima at the same time"

Crests and troughs are 180 deg out of phase and when they have their maxima at the same time and place, their net contribution will be zero"

2. FAt=p (remember p=mv). A 2.5Jg baseball moving at 8.5m/s to the left is slowed by a tipped
catch to 7.5m/s to the right in 0.25 seconds, what was the force of the tipped catch?

Answers

The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N

Data obtained from the question Initial velocity (u) = 8.5 m/sFinal velocity (v) = 7.5 m/sTime (t) = 5 ms = 0.25 sMass (m) = 2.5 KgForce (F) = ?

How to determine the force

The force exerted on the ball can be obtained as follow:

F = m(v + u) / t

F = [2.5(7.5 + 8.5)]/ 0.25

F = 40 / 0.25

F = 160 N

Thus, the force exerted on the ball is 160 N

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A surfacing whale in an aquarium produces water wave crests having an amplitude of 1.2 meters every 0.40 second. If the water wave travels at 4.5 meters per second, the wavelength of the wave is

Answers

The wavelength of the water wave having a amplitude of 1.2 meters every 0.4 seconds is 1.8 m .

What is wavelength?

Wavelength is the total distance traveled by a wave in one cycle.

To calculate the wavelength of the wave, we use the formula connecting

speed, wavelength, and Period.

Formula:

v = λ/T........... Equation 1

Where:

v = Velocity of the waveλ = WavelengthT = Period

Make λ the subject of the equation

λ = vT............ Equation 2

From the question,

Given:

v = 4.5 m/sT = 0.40 s

Substitute these values into equation 2

λ = (4.5×0.4)λ = 1.8 m

Hence, The wavelength of the water wave having a amplitude of 1.2 meters every 0.4 seconds is 1.8 m .

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How is sound intensity measured?

Answers

Answer:

Sound intensity is measured with a sound level meter or Sound pressure Level (SPL) Meter.

Explanation:-

It measure sound intensity is the sound pressure level. The unit of measurement is decibels.

An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 ev, 27 ev, and 48 ev

Answers

Answer:

l=3.5 x 10^-10m

Explanation:

just toook the test got it right good luck!

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