The correct answer is option e. 3.075 m/s. Speed is a scalar quantity, which means it has only magnitude and no direction.
What is Speed?
Speed is a measure of how quickly something moves from one place to another. It is the rate at which an object covers distance over time, and is usually expressed in units of meters per second (m/s) or kilometers per hour (km/h).
Since the temperature and pressure are the same for both oxygen and hydrogen gas, the only difference between the two is their molar mass. The molar mass of oxygen is 32 g/mol, and the molar mass of hydrogen is 2 g/mol. Therefore, we can calculate the RMS speed of hydrogen as:
u = √(3RT/M) = √(3RT/2)
The RMS speed of oxygen is given as 12.3 m/s. To find the RMS speed of hydrogen, we need to calculate the ratio of their speeds:
u(H2)/u(O2) = √(M(O2)/M(H2)) = √(32/2) = √16 = 4
Therefore, the RMS speed of hydrogen is:
u(H2) = u(O2)/4 = 12.3/4 = 3.075 m/s
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Chemistry 25 Points. Pls explain step by step
4: Calculate the pH of a 0. 25M solution of H3O+ (0. 5pt)
5: Calculate the pH of a 6. 3x10-8M solution of H3O+ (0. 5pt)
6: Look at your answer for 4 and 5 which one is a base? (0. 25pt)
7: Look at 4 and 5; which one is a strong acid?
4. The pH of the 0.25M solution of H₃O⁺ is 0.602.
5. The pH of the 6.3 x 10⁻⁸M solution of H₃O⁺ is 7.2.
6. Comparing the pH values from 4 and 5, the solution with a pH of 7.2 is a base.
7: Comparing the pH values from 4 and 5, the 0.25M H₃O⁺ solution (pH 0.60) is a strong acid because its pH is much lower than that of the 6.3x10^-8M H₃O⁺ solution (pH 7.20).
Let us learn more in detail.
1. pH: pH is a measure of the acidity or basicity of a solution. It is defined as the negative logarithm of the concentration of hydrogen ions (H⁺) in a solution.
2. H₃O⁺: H₃O⁺ is the hydronium ion, which is formed when a proton (H⁺) is added to a water molecule (H₂O). It is the most common form in which hydrogen ions exist in aqueous solution.
3. Strong acid: A strong acid is an acid that completely dissociates in water, producing a large number of H⁺ ions. Examples of strong acids include hydrochloric acid (HCl) and sulfuric acid (H₂SO₄).
Now, let's tackle the questions:
4. To calculate the pH of a 0.25M solution of H₃O⁺, we can use the following formula:
pH = -log[H₃O⁺]
where [H₃O⁺] is the concentration of hydronium ions in moles per liter. In this case, [H₃O⁺] = 0.25M, so:
pH = -log(0.25) = 0.602
Therefore, the pH of the solution is 0.602.
5. To calculate the pH of a 6.3x10-8M solution of H₃O⁺, we can use the same formula:
pH = -log[H₃O⁺]
In this case, [H₃O⁺] = 6.3x10-8M, so:
pH = -log(6.3x10-8) = 7.2
Therefore, the pH of the solution is 7.2.
6. To determine which solution is a base, we need to look at the pH. pH values below 7 indicate an acidic solution, while pH values above 7 indicate a basic solution. Therefore, the solution with a pH of 7.2 (from question 5) is a base.
7. To determine which solution is a strong acid, we need to consider the concentration of H₃O⁺+ ions. A strong acid is one that completely dissociates in water, producing a large amount of H⁺ ions. Therefore, the solution with a higher concentration of H₃O⁺ ions (from question 4) is a strong acid.
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Determine whether the stopcock should be completely open, partially open, or completely closed for each activity involved with titration. At the beginning of a titration Choose. Close to the calculated endpoint of a titration Choose. Filling the buret with titrant Choose. Conditioning the buret with titrant Choose
For each activity, you should set the stopcock as follows: completely closed at the beginning of titration, partially open near the endpoint, completely open when filling the buret, and partially open during buret conditioning.
To determine the stopcock position for each activity, we'll go through them one by one:
1. At the beginning of a titration: The stopcock should be completely closed. This ensures that no titrant is released from the buret until you are ready to begin the titration process.
2. Close to the calculated endpoint of a titration: The stopcock should be partially open. As you approach the endpoint, you'll want to slow down the titrant flow to ensure a more accurate and precise reading of the endpoint.
3. Filling the buret with titrant: The stopcock should be completely open. This allows for quick and efficient filling of the buret with the titrant.
4. Conditioning the buret with titrant: The stopcock should be completely open initially to fill the buret, then partially open to release some titrant and wet the inner walls of the buret. This ensures that the buret is properly coated with the titrant for accurate measurements during titration.
In summary, for each activity, you should set the stopcock as follows: completely closed at the beginning of titration, partially open near the endpoint, completely open when filling the buret, and partially open during buret conditioning.
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A decomposition of hydrogen peroxide into water and oxygen gas is an exothermic reaction. If the temperature is initially 28˚ C, what would you expect to see happen to the final temperature? Explain what is happening in terms of energy of the system and the surroundings.
If the decomposition of hydrogen peroxide into water and oxygen gas is an exothermic reaction, we would expect the final temperature to be lower than the initial temperature of 28˚C.
This is because during an exothermic reaction, energy is released from the system into the surroundings in the form of heat. In other words, the energy of the products (water and oxygen) is lower than the energy of the reactants (hydrogen peroxide), and the excess energy is released into the surroundings.
As a result, the temperature of the surroundings (in this case, the container holding the reaction) will increase, while the temperature of the system (the reactants and products) will decrease. This means that the final temperature of the reaction will be lower than the initial temperature of 28˚C.
Overall, we would expect the reaction to release heat into the surroundings, causing the temperature of the surroundings to increase while the temperature of the system decreases.
4. A gas has a volume of 4 liters at 50 ℃. What will its volume be (in liters) at 100℃?
The volume of the gas at 100℃ would be 4.64 liters, assuming the pressure remains constant.
We can use the combined gas law, which relates the pressure, volume, and temperature of a gas. The combined gas law formula is: (P1 x V1) / T1 = (P2 x V2) / T2. Where P is the pressure, V is the volume, and T is the temperature. The subscripts 1 and 2 refer to the initial and final states of the gas, respectively.
In this case, we know that the initial volume (V1) is 4 liters and the initial temperature (T1) is 50 ℃. We want to find the final volume (V2) when the temperature is 100℃.To solve for V2, we can rearrange the formula as follows: V2 = (P1 x V1 x T2) / (P2 x T1).We don't know the pressure, but since the problem doesn't mention any changes in pressure, we can assume that it remains constant. Therefore, we can cancel out the P1 and P2 terms.
Plugging in the known values, we get: V2 = (4 L x 373 K) / (323 K) = 4.64 L (rounded to two decimal places)Therefore, the volume of the gas at 100℃ would be 4.64 liters, assuming the pressure remains constant.
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A 7.32 l tire contains 0.448 mol of gas at a temperature of 28°c. what is the pressure (in atm) of the gas in the tire?
The pressure of a gas is directly proportional to the number of moles of gas present, and inversely proportional to the volume of the container. Therefore, given the temperature of the gas in the tire remains constant, the pressure of the gas can be calculated using the ideal gas law:
PV = nRT
Where P is pressure, V is volume, n is number of moles, R is the ideal gas constant, and T is temperature.
In this case, the number of moles is 0.448 mol, the temperature is 28°C (or 301 K), and the volume is 7.32 l.
Plugging in all the values, we get:
P = (0.448 mol) × (8.314 L·atm·K−1·mol−1) × (301 K) / (7.32 l)
P = 4.20 atm
Therefore, the pressure of the gas in the tire is 4.20 atm.
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Chlorophyll is a green pigment in plants responsible for harnessing sunlight to help the plant produce sugars through the process of photosynthesis. If several tomato plants were to be grown under lamps producing only a single color of light, what would be the least effective choice for light color?
Group of answer choices
green
orange
red
blue
The least effective choice of color would be green color. Hence option a is correct.
The plants absorb all different wavelength lights of the visible light spectra but the only color that is not absorbed and reflected back is green color light.
The principal pigment in photosynthesis, chlorophyll, reflects green light and significantly absorbs red and blue light. Chloroplasts, which house the chlorophyll in plants, are where photosynthesis occurs.
The plant's green colour is a reflection of the green light. Violet and orange (chlorophyll a) and blue and yellow (chlorophyll b) are the colours that are most readily absorbed. Therefore, green colour light would be least effective for the production of sugar and fruit in this tomato plant.
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if a zero order reaction has a rate constant of 0.0119mhr and an initial concentration of 5.19 m, what will be its concentration after precisely two days? your answer should have three significant figures (round your answer to two decimal places)
The concentration of the reactant after precisely two days is 4.62 M.
For a zero-order reaction, the rate is independent of the concentration and is given by the expression:
rate = k
where k is the rate constant.
The integrated rate law for a zero-order reaction is:
[A] = -kt + [A]₀
where [A] is the concentration of the reactant at time t, [A]₀ is the initial concentration of the reactant, k is the rate constant, and t is time.
Substituting the given values into the equation, we get:
[A] = -kt + [A]₀
[A] = -0.0119 M/hr * (224 hr) + 5.19 M
[A] = -0.5712 M + 5.19 M
[A] = 4.6188 M
Rounding off to three significant figures and two decimal places, we get the final concentration as 4.62 M.
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A canister contains 425 kPa of carbon dioxide, 750 kPa of nitrogen, and 525 kPa of oxygen. What is the total
pressure of the container?
The total pressure of the container is 1,700 kPa.
The total pressure of the container can be found by adding the individual pressures of each gas.
In this case, we have:
Carbon dioxide (CO₂): 425 kPa
Nitrogen (N₂): 750 kPa
Oxygen (O₂): 525 kPa
To find the total pressure, simply add these values together:
Total pressure = 425 kPa (CO₂) + 750 kPa (N₂) + 525 kPa (O₂)
= 1700 kPa
So, the total pressure of the container is 1700 kPa.
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Sucrose has the molecular formula
c12h22011.
if a sucrose sample contains 3.6 x 1024
atoms of carbon, how many molecules of
sucrose are present in the sample?
[?] x 10[?]molecules c12h22011
In this sample there are 1.51 x 10^24 molecules of sucrose present in it.
To determine the number of molecules of sucrose present in the sample, we need to first calculate the number of moles of carbon present in the sample.
The molecular formula of sucrose (C12H22O11) contains 12 carbon atoms.
So, 3.6 x 10^24 atoms of carbon is equal to 3.6 x 1024/12 = 3 x 1023 moles of carbon.
Now, we can use the Avogadro's number (6.022 x 10^23 molecules per mole) to convert the number of moles of carbon to the number of molecules of sucrose:
Number of molecules of sucrose = 3 x 10^23 x (1 molecule of sucrose / 12 molecules of carbon) x (6.022 x 10^23 molecules per mole)
Number of molecules of sucrose = 1.51 x 10^24 molecules
Therefore, there are 1.51 x 10^24 molecules of sucrose present in the sample.
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57.49 grams of H₂SO4 reacting with 98.20 grams of NaCl will produce how many grams of HCI?
The amount of HCl produced when 57.49 grams of H₂SO4 after a chemical reaction with 98.20 grams of NaCl (in grams) is found out being 42.70 grams.
The balanced chemical equation as per the mentioned case, the reaction between H₂SO₄ and NaCl can be represented as,
H₂SO₄ + 2 NaCl -----> 2 HCl + Na₂SO₄
We are needed to use stoichiometry in the way to know the amount of HCl produced out from the given amounts of H₂SO₄ and NaCl.
Step 1: Convert the given masses of H₂SO₄ and NaCl into an amount of equivalent moles.
Molar mass of H₂SO₄ is = 98.08 g/mol
Molar mass of NaCl is 58.44 g/mol
Number of moles of H₂SO₄ = 57.49 g / 98.08 g/mol = 0.586 mol
Number of moles of NaCl = 98.20 g / 58.44 g/mol = 1.679 mol
Step 2: Now we have to balance the chemical equation to know the mole ratio for H₂SO₄ to HCl.
From the balanced equation, we observe that 1 mole of H₂SO₄ produces 2 moles of HCl. Therefore, the 0.586 moles of H₂SO₄ will be producing about 2 × 0.586 = 1.172 moles of HCl.
Lastly, Convert the moles of HCl to grams.
Molar mass of HCl = 36.46 g/mol
Mass of HCl produced = 1.172 mol × 36.46 g/mol = 42.70 g
Therefore, it can be concluded that about 57.49 grams of H₂SO₄ would be reacting with nearly 98.20 grams of NaCl in order to produce out about 42.70 grams of HCl.
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If the reaction above has 118.3g of CS2 and 3.12 Mol of NaOH determine the limiting reactant in the reaction??3CS2+6NaOH— >2Na2CS3+Na2CO3+3H2O
Answer ASAP pls
[tex]CS_2[/tex] is the limiting reactant in the reaction.
The balanced chemical equation for the reaction is:
3 [tex]CS_2[/tex] + 6 [tex]NaOH[/tex] → 2 [tex]Na_2CS_3[/tex] + [tex]Na_2CS_3[/tex] + 3 [tex]H_2O[/tex]
To determine the limiting reactant, we need to calculate the amount of product that each reactant can produce and compare it to the actual amount of product that is formed.
First, we need to convert the mass of [tex]CS_2[/tex] to moles:
118.3 g [tex]CS_2[/tex] × (1 mol [tex]CS_2[/tex] /76.14 g [tex]CS_2[/tex]) = 1.555 mol [tex]CS_2[/tex]
Next, we need to calculate the amount of product that can be formed from 1.555 mol of [tex]CS_2[/tex]. According to the balanced equation, 3 mol of [tex]CS_2[/tex] will produce 2 mol of [tex]Na_2CS_3[/tex]. Therefore, 1.555 mol of [tex]CS_2[/tex] will produce:
(2/3) × 1.555 mol = 1.037 mol [tex]Na_2CS_3[/tex]
Now, let's calculate the amount of product that can be formed from 3.12 mol of [tex]NaOH[/tex]. According to the balanced equation, 6 mol of [tex]NaOH[/tex] will produce 2 mol of [tex]Na_2CS_3[/tex]. Therefore, 3.12 mol of [tex]NaOH[/tex] will produce:
(2/6) × 3.12 mol = 1.04 mol [tex]Na_2CS_3[/tex]
Comparing the amount of product that can be formed from each reactant, we see that 1.037 mol of [tex]Na_2CS_3[/tex] can be produced from the 1.555 mol of [tex]CS_2[/tex], while 1.04 mol of [tex]Na_2CS_3[/tex] can be produced from the 3.12 mol of [tex]NaOH[/tex]. Therefore, the limiting reactant in the reaction is [tex]CS_2[/tex].
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1.
What is the boiling point of a solution prepared by dissolving 2. 50 g of biphenyl (C12 H10)
in 85. 0 g of benzene. The molecular weight of biphenyl is 154 g.
The boiling point of the solution prepared by dissolving 2.50 g of biphenyl in 85.0 g of benzene is 80.58 °C.
The boiling point elevation of the solution can be determined using the equation ΔTb = Kb x m, where ΔTb represents the boiling point elevation, Kb is the boiling point elevation constant (for benzene, Kb = 2.53 °C/m), and m denotes the molality of the solution.
To calculate the molality, we first need to find the number of moles of biphenyl in the solution. By dividing the given mass of biphenyl (2.50 g) by its molar mass (154 g/mol), we obtain 0.0162 mol.
Next, we can determine the molality by dividing the moles of solute by the mass of the solvent in kilograms. Given that the mass of the solvent is 85.0 g (0.085 kg), the molality is calculated as 0.0162 mol / 0.085 kg = 0.191 mol/kg.
Substituting this molality into the equation, we have ΔTb = 2.53 °C/m x 0.191 mol/kg = 0.484 °C.
This indicates that the boiling point of the solution is raised by 0.484 °C compared to the boiling point of pure benzene, which is 80.1 °C.
Therefore, the boiling point of the solution, prepared by dissolving 2.50 g of biphenyl in 85.0 g of benzene, is 80.58 °C.
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Compute the mass of KI needed to prepare 500 mL of a 0. 750 M solution
The mass of KI needed to prepare 500 mL of a 0. 750 M solution is 62.25 grams
To compute the mass of KI needed to prepare 500 mL of a 0.750 M solution, use the formula:
Molarity (M) = moles of solute / volume of solution in liters
First, convert the volume to liters: 500 mL = 0.5 L
Next, rearrange the formula to find the moles of solute:
moles of solute = Molarity × volume of solution in liters
moles of KI = 0.750 M × 0.5 L
moles of KI = 0.375 moles
Now, find the molar mass of KI (Potassium Iodide):
K (Potassium) = 39.10 g/mol
I (Iodine) = 126.90 g/mol
Molar mass of KI = 39.10 g/mol + 126.90 g/mol = 166.00 g/mol
Finally, calculate the mass of KI needed:
mass of KI = moles of KI × molar mass of KI
mass of KI = 0.375 moles × 166.00 g/mol
mass of KI = 62.25 g
Therefore, you will need 62.25 grams of KI to prepare 500 mL of a 0.750 M solution.
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2As2O3+3C=3C02+4As; if 8.00g of As2O3 reacts with 1.00 g of C, how many grams of carbon dioxide can be produced?
Answer:
The balanced chemical equation is:
2As2O3 + 3C → 3CO2 + 4As
To find out how many grams of carbon dioxide can be produced, we need to use stoichiometry.
First, we need to determine which reactant is limiting. We can do this by calculating the amount of carbon that reacts with As2O3:
1.00 g C × (1 mol C / 12.01 g) × (2 mol As2O3 / 3 mol C) × (197.84 g As2O3 / 1 mol As2O3) = 2.60 g As2O3
This means that only 2.60 g of the As2O3 will react, and the rest will be in excess.
Now we can use the balanced equation to calculate the amount of CO2 that will be produced:
2 mol As2O3 : 3 mol CO2
2.60 g As2O3 × (1 mol As2O3 / 197.84 g) × (3 mol CO2 / 2 mol As2O3) × (44.01 g CO2 / 1 mol CO2) = 3.56 g CO2
Therefore, 3.56 grams of carbon dioxide can be produced.
In the electrowinning process, a Metallurgical/Chemical Engineer uses an Infrared (IR) camera to detect metallurgical short-circuits (hot spots) over the anodes and cathodes. Given that the mass of an electron is 9. 109× 1031 and Rydberg’s constant is 1. 090×107 −1 , determine the energy (in MJ) applied when 5 mol of IR photons having a wavelength of 32 nm is used in the copper electrolysis process
In the electrowinning process, the energy applied using 5 mol of IR photons with a wavelength of 32 nm is 1.863 MJ.
1. Convert wavelength to energy using the equation: E = (hc)/λ, where h is Planck's constant (6.626×10⁻³⁴ Js), c is the speed of light (3×10⁸ m/s), and λ is the wavelength (32 nm = 32×10⁻⁹ m).
2. Calculate the energy of one IR photon: E = (6.626×10⁻³⁴ Js × 3×10⁸ m/s) / (32×10⁻⁹ m) = 6.184×10⁻¹⁹ J.
3. Determine the energy for 5 moles of IR photons: Total energy = 6.184×10⁻¹⁹ J × 5 × 6.022×10²³ photons/mol = 1.863×10⁶ J.
4. Convert energy to megajoules: 1.863×10⁶ J = 1.863 MJ.
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2. Some ionic compounds are hydrates—solid compounds to which is bound a specific
percentage of water. Some hydrates melt when heated and release energy when they
solidify. For example, at 32 °C, liquid Glauber's salt-sodium sulfate decahydrate,
Na S04:10 H,00)—solidifies and releases 78. 0 kJ/mol of energy. Calculate the
enthalpy change when 2. 50 kg of Glauber's salt enters the solid state?
The enthalpy change when 2.50 kg of Glauber's salt solidifies is 605.28 kJ.
To calculate the enthalpy change when 2.50 kg of Glauber's salt (sodium sulfate decahydrate, Na2SO4·10H2O) solidifies, you can follow these steps:
1. Convert the mass of Glauber's salt to moles:
2.50 kg = 2500 g
Molar mass of Na2SO4·10H2O = (2×23) + (32) + (4×16) + (10×(2+16)) = 46 + 32 + 64 + 180 = 322 g/mol
Moles of Glauber's salt = 2500 g / 322 g/mol = 7.76 mol
2. Multiply the moles by the energy released per mole:
Energy released = 7.76 mol × 78.0 kJ/mol = 605.28 kJ
The enthalpy change when 2.50 kg of Glauber's salt solidifies is 605.28 kJ.
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Carbonyl bromide, cobr2, can be formed by reacting co with br2. a mixture of 0.400 mol co, 0.300 mol br2, and 0.0200 mol cobr2 is sealed in a 5.00l flask. calculate equilibrium concentrations for all gases, given that the kc
To calculate the equilibrium concentrations, we first need to determine the initial concentrations of each gas.
The initial concentration of CO is 0.400 mol/5.00 L = 0.0800 M, Br2 is 0.300 mol/5.00 L = 0.0600 M, and COBr2 is 0.0200 mol/5.00 L = 0.00400 M.
The balanced equation for the reaction is:
CO(g) + Br2(g) ⇌ COBr2(g)
Let's assume that at equilibrium, the concentrations of COBr2 is x M. Therefore, the concentrations of CO and Br2 will be (0.0800 - x) M and (0.0600 - x) M, respectively.
The equilibrium constant expression (Kc) for this reaction is:
Kc = [COBr2] / ([CO] * [Br2])
Substituting the equilibrium concentrations into the Kc expression, we have:
Kc = (x) / ((0.0800 - x) * (0.0600 - x))
Solving for x using the given values and the equation above, we find x ≈ 0.0040 M.
Therefore, the equilibrium concentrations for the gases are:
[CO] ≈ 0.0760 M
[Br2] ≈ 0.0560 M
[COBr2] ≈ 0.0040 M
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Explique las diferentes definiciones de ácido y base. Presente un ejemplo de cada uno y las características
para su identificación
There are several definitions of acids and bases, and each definition provides a unique perspective on their properties and behaviors.
Arrhenius Definition:
According to the Arrhenius definition, an acid is a substance that dissociates in water to form hydrogen ions (H+), while a base is a substance that dissociates in water to form hydroxide ions (OH-).
For example, hydrochloric acid (HCl) dissociates in water to form H+ and Cl- ions:
HCl → H+ + Cl-
On the other hand, sodium hydroxide (NaOH) dissociates in water to form Na+ and OH- ions:
NaOH → Na+ + OH-
Characteristics for identification:
Acids typically have a sour taste and can cause a burning sensation on the skin. Bases have a bitter taste and can feel slippery to the touch. They also typically have a higher pH value (greater than 7) in aqueous solutions.
Bronsted-Lowry Definition:
According to the Bronsted-Lowry definition, an acid is a substance that donates a proton (H+) to another molecule or ion, while a base is a substance that accepts a proton (H+) from another molecule or ion.
In this reaction, acetic acid is the acid because it donates a proton, while water is the base because it accepts a proton.
Characteristics for identification:
Acids and bases in the Bronsted-Lowry sense are identified by the presence or absence of a hydrogen ion. An acid must contain a hydrogen ion that can be donated to a base, while a base must have an available lone pair of electrons to accept a hydrogen ion.
Lewis Definition:
According to the Lewis definition, an acid is a substance that accepts a pair of electrons, while a base is a substance that donates a pair of electrons.
In this reaction, boron trifluoride is the acid because it accepts a pair of electrons, while ammonia is the base because it donates a pair of electrons.
Characteristics for identification:
Acids and bases in the Lewis sense are identified by their electron-pair accepting or donating abilities. An acid must be able to accept a pair of electrons, while a base must be able to donate a pair of electrons.
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Correct Question:
Explain the different definitions of acid and base. Give an example of each and the characteristics of your identification.
Zinc reacts with HCl to produce hydrogen gas, H2, and ZnCl2.
Zn(s) + 2 HCl(aq) --> H2(g) + ZnCl2(aq)
How many liters of a 1.50 M HCl solution completely react with 5.32 g of zinc?
Answer:
0.108L HCl
Explanation:
5.32 g zinc * 1 mol zinc/65.38g zinc * 2 mol HCl/1 mol zinc * L HCl/1.5 mol HCl = 0.108L HCl
A car tire has a volume of 15 L at a temperature of 22. 0°C. What will the new volume
be if the temperature is increased to 34. 0°C?
The new volume of the tire is 15.6 L if the temperature is increased from 22° C to 34°C if the previous volume was 15 L.
The relation between pressure and volume in a system is explained by Charles's Law. It states that the temperature is inversely proportional to the volume in the system. It is expressed as:
[tex]T_2V_1=T_1V_2[/tex]
where T is the temperature
V is the volume
with no change in pressure and a number of moles of gases.
Given in the question,
[tex]V_1[/tex] = 15 L
[tex]T_1[/tex] = 22°C = 295 K
[tex]T_2[/tex] = 34°C = 307 K
307 * 15 = 295 * [tex]V_2[/tex]
[tex]V_2[/tex] = 15.6 L
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I need help with this question PLEASE
The oxidation number approach, commonly referred to as the oxidation states, keeps track of the electrons obtained during reduction and the electrons lost during oxidation.
Thus, Each atom in a charged or neutral molecule is given an oxidation number. Oxidation takes place whenever the oxidation number rises. Reduction happens when the oxidation number goes down. The total charge of a chemical is equal to the sum of all of its oxidation numbers.
The roles of oxidation and reduction is the only foolproof method for balancing a redox equation. Then you achieve equilibrium by bringing the electron gain and loss into balance.
The oxidation numbers of all atoms are determined using the oxidation number method. The altered atoms are then multiplied by small whole numbers.
Thus, The oxidation number approach, commonly referred to as the oxidation states, keeps track of the electrons obtained during reduction and the electrons lost during oxidation.
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What is the freezing point of a solution of 0. 300 mol of lithium bromide in 525 mL of water?
The freezing point of the lithium bromide solution is approximately -1.06°C.
To determine the freezing point of the solution, we need to use the freezing point depression formula:
ΔTf = Kf * molality
where ΔTf is the freezing point depression, Kf is the freezing point depression constant (which depends on the solvent), and molality is the concentration of the solution in mol/kg.
First, we need to calculate the molality of the solution:
molality = moles of solute / mass of solvent (in kg)
The mass of 525 mL of water is:
mass = volume * density = 525 mL * 1 g/mL = 525 g
The number of moles of lithium bromide is:
moles of LiBr = 0.300 mol
Therefore, the molality of the solution is:
molality = 0.300 mol / 0.525 kg = 0.571 mol/kg
The freezing point depression constant for water is 1.86 °C/m. Therefore, the freezing point depression is:
ΔTf = 1.86 °C/m * 0.571 mol/kg = 1.06306 °C
Finally, to find the freezing point of the solution, we need to subtract the freezing point depression from the freezing point of pure water (0°C):
Freezing point = 0°C - 1.06306°C = -1.06306°C
Therefore, the freezing point of the lithium bromide solution is approximately -1.06°C.
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A 255 liter volume of helium gas is at a pressure of 435 mm of Hg and has a temperature of 299 K. What is the volume of the same gas (in liters) at 655 mm of Hg and 199 K? Again, only enter your numerical answer here; no units! Always follow significant figure rules
The volume of the same gas is 320 L.
Use the combined gas law to solve for the final volume of the gas:
(P1V1/T1) = (P2V2/T2)
Substituting the given values, we get:
(435 mmHg)(255 L)/(299 K) = (655 mmHg)(V2)/(199 K)Solving for V2, we get:
V2 = (435 mmHg)(255 L)/(299 K) x (199 K)/(655 mmHg)V2 = 320 LTherefore, the volume of the gas at the new conditions is 320 L.
The combined gas law relates the pressure, volume, and temperature of a gas in a closed system. It states that the product of pressure and volume divided by the temperature is a constant for a given mass of gas in a closed system undergoing changes in pressure, volume, and temperature. Mathematically, the combined gas law can be represented as:
(P₁V₁)/T₁ = (P₂V₂)/T₂Where P₁ and V₁ are the initial pressure and volume, T₁ is the initial temperature, P₂ and V₂ are the final pressure and volume, and T₂ is the final temperature. This equation is useful in predicting the behavior of gases when the conditions of pressure, volume, and temperature are changed. The combined gas law is a combination of Boyle's law, Charles's law, and Gay-Lussac's law, and it can be derived from the ideal gas law.
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5. It is helpful to occasionally rinse the sides of the beaker or flask with distilled water
during the titration procedure. Explain why or why not it is necessary to measure the
volume of rinse water used during the procedure.
Measuring the volume of rinse water does not significantly impact the overall volume during titration.
What is titration?Titration is a commonly employed laboratory method that involves determining the concentration of an unknown solution by reacting it with a solution of known concentration, known as the titrant, until the chemical reaction between the two is fully completed. This process requires precision and accuracy to ensure reliable results are obtained.
Why or why not it is necessary to measure the volume of rinse water used during the procedure?To guarantee that all reactants are thoroughly mixed and avoid any skewing of results due to reactants left on the walls of the container, it is useful to rinse the sides of the beaker or flask with distilled water during titration. However, measuring the volume of rinse water used is not necessary as it does not significantly impact the overall volume of titrant used in titration. It is crucial to be mindful not to use an excessive amount of rinse water as this can dilute the sample and compromise result accuracy. Rest assured that accuracy will not be affected by the volume of rinse water used, but it's essential to maintain a balance between thorough rinsing and preserving sample concentration.
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A sample of helium gas occupies 12. 4 L at 23°C and 0. 956 atm. What volume will it occupy at 1. 20 atm assuming that the temperature stays constant?
What volume of solution is required to create a solution of a concentration of 1.3x 10^-2 M from 1.0x 10^-3 moles of calcium hydroxide
Approximately 0.0769 liters (76.9 mL) of solution is required to create a 1.3 x [tex]10^-2[/tex] M concentration of calcium hydroxide using [tex]1.0 x 10^-3[/tex] moles of solute.
A solute is a material that a solvent can dissolve into a solution. A solute can take on various shapes. It might exist as a solid, a liquid, or a gas. Solvent refers to the component of a solution that is most prevalent. It is the fluid in which the solute has been dissolved.
Molarity (M) = moles of solute / volume of solution (L)
Here, you're given the desired molarity ([tex]1.3 x 10^-2[/tex] M) and the moles of solute ([tex]1.0 x 10^-3[/tex]moles). You need to find the volume of solution (in liters).
Volume (L) = moles of solute / Molarity (M)
Now, plug in the given values:
Volume (L) = [tex](1.0 x 10^-3[/tex] moles) / ([tex]1.3 x 10^-2[/tex]M)
Volume (L) ≈ 0.0769 L
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A solution of potassium hydroxide reacts completely with a solution of nitric acid. What solid mixture, what will remain after the water dissolves?.
A solution of potassium hydroxide reacts completely with a solution of nitric acid. Potassium nitrate will remain after the water dissolves in solid mixture.
What is a solid mixture?
This kind of mixture consists of two or more solids. Alloys are what are used when the solids are made of metals. Sand and sugar, stainless steel, etc. are a few examples of solid-solid combinations.
2KOH(aq) + HNO₃(aq) → KNO₃(aq) + 2H₂O(l)
When a solution of potassium hydroxide (KOH) reacts completely with a solution of nitric acid (HNO₃), potassium nitrate (KNO₃) is formed in aqueous form, along with water (H₂O). The solid mixture that will remain after the water evaporates is potassium nitrate (KNO₃).
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What information does the formula of a compound give
Answer:
A chemical formula tells us the number of atoms of each element in a compound.
Explanation:
Explanation:
formula shows
types of element ( composition ) number of atom type of mol ( which is monoatomic , diatomic and polyatomic.)259 mL of gas is collected at 112 kPa of pressure. What will be the volume at standard pressure, assuming the temperature remains constant? Remember, STP is standard temperature (273 K) and standard pressure (1 atm). Round your answer to 3 significant figures.
Love you so much if you can answer x
The volume at standard pressure will be 293 mL.
To find the volume of gas at standard pressure, we need to use the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature.
Since the temperature remains constant, we can rearrange the equation to solve for the volume at standard pressure:
(P₁V₁) / P₂ = V₂
Where P₁ is the initial pressure, V₁ is the initial volume, P₂ is the final pressure (standard pressure), and V₂ is the final volume (what we're solving for).
Plugging in the given values, we get:
(112 kPa)(259 mL) / (1 atm) = V₂
Simplifying and converting units of pressure and volume, we get:
(112000 Pa)(0.259 L) / (1.01325 × 10⁵ Pa) = V₂
Solving for V₂, we get:
V₂ = 0.293 L = 293 mL
Rounding to 3 significant figures, we get that the volume at standard pressure will be 293 mL.
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Consider the following scenario
In a muddy lake environment some fish have brown scales. Most fish, however have silver scales Predators have a harder time seeing the fish with brown scales
Which term best describes the brown scales?
advantageous trait
new mutation
predominant phenotype
inactivated gene
An advantageous trait describes the brown scales in fish living in a muddy lake environment, providing them with a better chance of survival and reproductive success by blending in with their surroundings and making it harder for predators to see them.
The term that best describes the brown scales in this scenario is advantageous trait. An advantageous trait is a characteristic that provides an organism with a greater chance of survival and reproductive success in a specific environment. In this case, the brown scales provide an advantage to the fish living in the muddy lake environment as they blend in better with their surroundings, making it harder for predators to see them. As a result, fish with brown scales are more likely to survive and reproduce, passing on this trait to their offspring. The silver scales are the predominant phenotype, meaning they are the most common physical expression of the fish's genotype. The brown scales may have arisen through a new mutation, but their persistence in the population suggests they have become a part of the fish's genetic makeup. There is no indication that an inactivated gene is responsible for the brown scales.
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