A mixture of gases consists of N2, O2, H2 and F2. The total pressure of the mixture is 511.56 kPa. The pressure of the N2 is 584 mm Hg, the pressure of the O2 is 196 kPa and the pressure of the H2 is standard pressure. What is the pressure of the F2 (in mm Hg)?

Answers

Answer 1

Answer:

Step-by-step explanation:

The total pressure of a gas is the sum of the partial pressures of the gases that it consists of. It means that

N2 + O2 + H2 + F2 = pressure of mixture

1 kpa = 7.50061683 mmhg

The total pressure of the mixture is 511.56 kPa. Converting to mmHg, it becomes

511.56 × 7.50061683 = 3837.02 mmhg

The pressure of the O2 is 196 kPa. Converting to mmhg, it becomes

196 × 7.50061683 = 1470.12 mmhg

Since the the pressure of the H2 is standard pressure, it means that the pressure is 760 mmhg

Also, pressure of the N2 is 584 mm Hg

Therefore,

1470.12 + 760 + 584 + F2 = 3837.02

2814.12 + F2 = 3837.02

F2 = 3837.02 - 2814.12

F2 = 1022.9 mm Hg


Related Questions


When you add two rational numbers, each number
can be written as a ?

Answers

a Rational # , because when you add two rational #’s each number can be written as a rational #

-3× + 1 + 10x = x + 4​

Answers

Answer:

I WANT BRAINLIEST

Step-by-step explanation:

your question is

[tex]-3*1 + 10x = x+4[/tex]

-3+10x=x+4

9x=7

x = 7/9

Answer:

x=7/9

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

(−3)(1)+10x=x+4

−3+10x=x+4

10x−3=x+4

Step 2: Subtract x from both sides.

10x−3−x=x+4−x

9x−3=4

Step 3: Add 3 to both sides.

9x−3+3=4+3

9x=7

Step 4: Divide both sides by 9.

9x

9

= 7 /9

x= 7 /9

What is the radius of the circle whose equation is x2 + y2 = 9?
81
3
9

Answers

Answer:

3

Step-by-step explanation:

x^2 + y^2 = 9

The equation of a circle is

(x-h)^2 + (y-k)^2 = r^2

( h,k) is the center and r is the radius

x^2 + y^2 = 3^2

The radius is 3

What is the equation of the horizontal line through (-5,-2)

Answers

Answer:

  y = -2

Step-by-step explanation:

A horizontal line has an equation of the form ...

  y = constant

In order for the line to go through a point with a y-coordinate of -2, the constant must be -2.

  y = -2 . . . . horizontal line through (-5, -2)

what does a shape need to be a prallelogram?

Answers

Answer: Needs to be flat with opposite sides that are parallel and are the same in length

What’s the correct answer for this question?

Answers

Answer:

The answer is drawing the 6 of clubs or the 6 of spades because those are the only black 6's.

Which of the following measurements is the most precise?
A.A 15.5 foot tall tree
B.An 84-year-old man
C.A gas price of $2.359 per gallon

Answers

Answer:

C.)

Step-by-step explanation:

C.) Because it states the exact decimals rather than just stating about $2.36. Also, the other options were not specific. Hope this helps!  

I think it’s c. Because it’s the most precise going past three decimal places.


What is the quotient of 3/4 divided by 1/5

Answers

Answer:

15/4

Step-by-step explanation:

3/4:1/5= 3/4*5= 15/4

You take a train away from Bangkok at 1:50 a.m. on Wednesday. You ride the train for 16 hours and 40 minutes, at which point you arrive in Vladivostok at 9:30 p.m. on Wednesday, local time. How does Vladivostok’s time zone relate to Bangkok’s time zone?
a.
Vladivostok is three hours ahead of Bangkok.
b.
Vladivostok is nine hours behind Bangkok.
c.
Vladivostok is fifteen hours behind Bangkok.
d.
Vladivostok is twenty-one hours ahead of Bangkok.

Answers

Answer:

a.

Vladivostok is three hours ahead of Bangkok.

Step-by-step explanation:

Time the train left Bangkok is 1:50am

It traveled for 16 hours 40 minutes.

If the train was to be in Bangkok.

The Time Will be 1+16 hours then 50+40 minutes

Which is 17 hours + 1 hour 30 minutes

Which is 18 hours and 30 minutes

And 18 hours = 6:00 pm

So if it was in Bangkok the time with be 6:30 pm

But in Vladivostok, it was 9:30 pm

It's clear that Vladivostok time is faster by 3 hours

Simplify the expression to a polynomial in standard form: (x-1)(3x^2-5x-3) (x−1)(3x 2 −5x−3)

Answers

Answer: 3x^3 -8*x^2 + 8*x + 3

Step-by-step explanation:

The standard form for a plolynomial is:

a*x^n + b*x^(n-1) + c*x^(n - 2) ........

We have:

(x-1)(3x^2-5x-3)

this is equal to:

3*x^3 - 5*x^2 + 3*x - 3*x^2 +5*x + 3

where the thing that i did is distribute the multiplication

this is equal to:

3x^3 -8*x^2 + 8*x + 3

When Easton goes bowling, his scores are normally distributed with a mean of 130
and a standard deviation of 11. What percentage of the games that Easton bowls does
he score higher than 112, to the nearest tenth?

Answers

Answer:

P(X≥112) = 0.9495

The  percentage of the games that Easton bowls does  he score higher than 112 = 94.95%

Step-by-step explanation:

Given mean of the Population = 130

Given standard deviation of the Population = 11

Let X= 112

[tex]Z =\frac{x-mean}{S.D} =\frac{112-130}{11}=-1.636[/tex]

P(X≥112) = P(Z≥ z)

               = 1-P(Z≤z)

               = 1- ( P(Z≤-1.636)

             =  1- (0.5-A(-1.636)

            = 0.5 +A(1.636)

            = 0.5 + 0.4495

P(X≥112) = 0.9495

The  percentage of the games that Easton bowls does

he score higher than 112 = 94.95%

Educators are testing a new program designed to help children improve their reading skills. The null hypothesis of the test is that the program does not help children improve their reading skills. For the educators, the more consequential error would be that the program does not help children improve their reading skills but the test indicated that it does help.

Which of the following should the researchers do to avoid the more consequential error?

a. Increase the significance level to increase the probability of Type I error.
b. Increase the significance level to decrease the probability of Type I error.
c. Decrease the significance level to increase the probability of Type I error.
d. Decrease the significance level to decrease the probability of Type I error.
e. Decrease the significance level to decrease the standard error.

Answers

Answer:

a

Step-by-step explanation:

increase the significance level to increase the probability of type 1 error

You can use the definition of type I and type II error to find the correct option.

To avoid the more consequential error, the researchers should do:
Option D: Decrease the significance level to decrease the probability of Type I error.

What is Type I and Type II error?

Firstly the whole story starts from hypotheses. The null hypothesis is tried to reject and we try to accept the alternate hypothesis.

The type 1 error occurs if we get false positive conclusion (false positive means we accuse null hypothesis being wrong when it was actually correct).The type 2 error occurs if we get false negative conclusion (false negative means we accept null hypothesis when it was actually false).

The negative is just like the doctor's test getting negative means no disease. Similarly, if we conclude null hypothesis negative means it is accepted. If it is accepted wrongly means the negative test result was false, thus called false negative. This error is called type II error.

How are the type I error and the level of significance of the hypothesis test related?

The probability of committing the type I error is called the significance level of the hypothesis test.

How to find what does researchers should do to avoid more consequential error?

Since in the given context, by using the definitions of the type I error and the type II error, we have

Type I error : False positive : Accepting that the new program does help the children in improving the reading skills when it actually don't.Type II error: False negative: Failing to reject that the program doesn't help the children in improving the reading skills when it actually improves the skill.

More consequential error for educators : For the educators, the more consequential error would be that the program does not help children improve their reading skills but the test indicated that it does help.


Thus, the more consequential error for the educators is committing the type I error.

To prevent committing this error, they need to decrease type I error's probability which is denoted by level of significance, need to decrease the level of significance of the hypothesis test.

Thus,

Option D: Decrease the significance level to decrease the probability of Type I error.

Lear more about type I and type II error here:
https://brainly.com/question/26067196

Please answer this correctly

Answers

Answer:

11 5/8

Step-by-step explanation:

Simply the 5/8 to 16th

5/8 equals to 10/16

Then add the 16ths together

The divide it by 16

Then add the whole numbers

Then add of them together to get your answer

Answer:

Exact Form:

93 /8

Decimal Form:

11.625

Mixed Number Form:

11  5 /8

Step-by-step explanation:

If you add every side together:

3 3/16 + 2 5/8 + 3 3/16 + 2 5/8 = 93/8

It's quite easy, just add everything together ;)

Explain what is meant by the equation lim x → 8 f(x) = 9. If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|. The values of f(x) can be made as close to 8 as we like by taking x sufficiently close to 9. f(x) = 9 for all values of x. If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|. The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8. Is it possible for this statement to be true and yet f(8) = 6?
Explain. Yes, the graph could have a hole at (8, 9) and be defined such that f(8) = 6. Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6. No, if f(8) = 6, then lim x→8 f(x) = 6. No, if lim x→8 f(x) = 9, then f(8) = 9.

Answers

Complete Question

1 Explain what is meant by the equation lim x → 8 f(x) = 9.

A If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|.

B The values of f(x) can be made as close to 8 as we like by taking x  sufficiently close to 9.

C  f(x) = 9 for all values of x.

D If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|.

E The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8.

2  Is it possible for this statement to be true and yet f(8) = 6? Explain.

A Yes, the graph could have a hole at (8, 9) and be defined such that f(8) =6.

B Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6.

C No, if f(8) = 6, then lim x→8 f(x) = 6.

D No, if lim x→8 f(x) = 9, then f(8) = 9.

Answer:

1

   The correct option is  D

2

    The correct option is   A

Step-by-step explanation:

Generally a a limit function  [tex]\lim_{n \to x } f(x) = L[/tex]

Tell us that as n tends toward x the values of  f(x) tends towards L hence for the first question E is the correct option

Now looking at the second question

  Yes it is possible for  lim x → 8 f(x) = 9.  to be true and  f(8) = 6 this is because the graph defined by this limit equation can have a hole the point

(8, 9) and created in such a way that f(8) = 6

Calculus's basic idea of limits in mathematics describes how a function behaves when its input approaches a specific value. No, if f(8) = 6, then lim x → 8 f(x) = 6. The correct option is C.

The statement "lim x → 8 f(x) = 9" means that as x approaches 8, the limit of f(x) is equal to 9. This implies that the function f(x) gets arbitrarily close to 9 as x gets arbitrarily close to 8.

If f(8) = 6, it means that the function f(x) has a specific value of 6 at x = 8. This contradicts the idea that f(x) gets arbitrarily close to 9 as x approaches 8.

Therefore, if f(8) = 6, it is not possible for the statement "lim x → 8 f(x) = 9" to be true.

To know more about equation limits follow

https://brainly.com/question/34255916

#SPJ3

he mayor of a town has proposed a plan for the construction of a new community. A political study took a sample of 900 voters in the town and found that 81% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is more than 78%. Testing at the 0.02 level, is there enough evidence to support the strategist's claim?

Answers

Answer:

[tex]z=\frac{0.81 -0.78}{\sqrt{\frac{0.78(1-0.78)}{900}}}=2.173[/tex]  

The p value for this case is given by this probability:

[tex]p_v =P(z>2.173)=0.0149[/tex]  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of people who favored te construction is significantly higher than 0.78 or 78%

Step-by-step explanation:

Information given

n=900 represent the random sample taken

[tex]\hat p=0.81[/tex] estimated proportion of residents who favored the construction

[tex]p_o=0.78[/tex] is the value to test

[tex]\alpha=0.02[/tex] represent the significance level

z would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to test if the true proportion is more than 0.78 or not.:  

Null hypothesis:[tex]p\leq 0.78[/tex]  

Alternative hypothesis:[tex]p > 0.78[/tex]  

The statistic is given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

Replacing the info we got:

[tex]z=\frac{0.81 -0.78}{\sqrt{\frac{0.78(1-0.78)}{900}}}=2.173[/tex]  

The p value for this case is given by this probability:

[tex]p_v =P(z>2.173)=0.0149[/tex]  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of people who favored te construction is significantly higher than 0.78 or 78%

What is the minimum and maximum whole number side length for △ABC with given side lengths of 9 cm and 11 cm? Please explain why

Answers

Answer:

Step-by-step explanation:

We would assume that triangle ABC is a right angled triangle. This means that we can apply Pythagoras theorem in determining the unknown side length.

For the case of the minimum side length, we would assume that the unknown length, L is one of the shorter legs of the triangle. By applying Pythagoras theorem, it becomes

11² = 9² + L²

L² = 121 - 81 = 40

L = √40 = 6.32

For the case of the maximum side length, we would assume that the unknown length, L is one of the hypotenuse of the triangle. By applying Pythagoras theorem, it becomes

L² = 9² + 11²

L² = 81 + 121 = 202

L = √202 = 14.21

The minimum side length is 6.32 and the maximum side length is 14.21

I WILL MARK BRAINLIEST!!! I NEED HELP!! MY PARENTS ARE IN THE HOSPITAL I HAVE NO ONE TO ASK FOR HELP!!! I HAVE TWO MINUTES LEFT!!! I AM FINISHING THIS COURSE TO MAKE THEM PROUD!!! SOMEONE HELP!!!

Answers

Answer:

D

Step-by-step explanation:

The Interplanet Space Centre is planning to launch a probe which will travel from Earth to Mars, on to Jupiter and then to Saturn. Distance from Earth to Mars 78 300 000 km Distance from Mars to Jupiter 550 400 000 km Distance from Jupiter to Saturn 648 700 000 km million km
Estimate to the nearest million how far it will travel on its journey.

Answers

Answer:

1,300,000,000

Step-by-step explanation:

 78    300   000

 550  400   000

 648  700   000

1  277  400   000

To the nearest million

1,2 | 77 400 000            more than 4, so +1

1,300,000,000

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before​ treatment, 17 subjects had a mean wake time of 100.0 min. After​ treatment, the 17 subjects had a mean wake time of 90.3 min and a standard deviation of 21.8 min. Assume that the 17 sample values appear to be from a normally distributed population and construct a 99​% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 100.0 min before the​ treatment? Does the drug appear to be​ effective?

Answers

Answer:

Step-by-step explanation:

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation = 21.8

n = number of samples = 17

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 17 - 1 = 16

Since confidence level = 99% = 0.99, α = 1 - CL = 1 – 0.99 = 0.01

α/2 = 0.01/2 = 0.005

the area to the right of z0.005 is 0.005 and the area to the left of z0.005 is 1 - 0.005 = 0.995

Looking at the t distribution table,

z = 2.921

Margin of error = 2.921 × 21.8/√17

= 15.44

The confidence interval for the mean wake time for a population with drug treatments is

90.3 ± 15.44

The upper limit is 90.3 + 15.44 = 105.74 mins

The lower limit is 90.3 - 15.44 = 74.86 mins

The result suggests that the mean wake time might have really reduced since the values barely fall above 100 minutes as in before treatment with a high degree of confidence. Therefore, the drug is effective.

The sugar company will choose from two companies to transport its sugar to market. the first company charges $6500 to rent trucks plus an additional fee of $150.50 for each Ton of sugar. The second company charges $4995 to Trang trucks plus an additional fee of $225.75 for each Ton of sugar. For what amount of sugar do the two companies charge the same?

Answers

Answer:

20 ton

Step-by-step explanation:

We created a system of two separate equations to answer these questions.

"y" will be the total cost to transport the sugar

"x" will be the amount of sugar transported

Therefore, we have to:

y = 3995 + 225.50 * x

y = 6500 + 100.25 * x

We must establish these equations equal to each other because it asks how much of x is necessary to make the same amount of y, therefore:

3995 + 225.50 * x = 6500 + 100.25 * x

solved we have:

225.50 * x - 100.25 * x  = 6500 - 3995

125.25 * x = 2505

x = 2505 / 125.25

x = 20

which means that when the amount of sugar transported is 20 tons, the price is the same

Suppose that you had consumer group wanted to test to see if weight of participants in a weight loss program changed (up or down). They computed a 95% confidence interval of the result (-4.977, 2.177). What do we know about the p-value for the test?

Answers

Answer:

What we know about the p-value for the test is that it will be less than 0.05

Step-by-step explanation:

The complete question is as follows;

Suppose that you had consumer group wanted to test to see if weight of participants in a weight loss program changed (up or down). They computed a 95% confidence interval of the result (-4.977, -2.177). Suppose that we had a significance test with the following hypothesis:

H0: population mean weight loss = 0

Ha: population mean weight loss does not equal 0

What do we know about the p-value for the test?

solution;

Given the information in the question, we are concerned with saying what we know about the p-value for the test

To answer this question, we shall be looking at it from the angle of the confidence interval

The confidence interval given is 95%.

Now what does this indicate?

It indicates that 95% confidence interval contains only values which are less than 0.

What does this mean for the p-value?

This means that the p-value will be less than 0.05

why should i have different units for volume and base area Ex: volume = [tex]in^{3}[/tex] Base Area = [tex]in^{2}[/tex] pyramid ^^^

Answers

Answer:

Step-by-step explanation:

Volume has three parameters and is three dimensional, thus needing a unit in the third power

In difference,

Area is two-dimensional and has only 2 parameters, thus needing a unit only in the second power

Answer:

see below

Step-by-step explanation:

Area is found by multiplying two dimensions  together ( l*w)

Volume is found by multiplying three dimensions together ( l*w*n)

Solve the following equation algebraically:
4x2 = 100
a. +0.2
b. +5
C.
+12.5
+10
d.

Answers

Answer:

[tex]\boxed{\sf \ \ \ answer \ b. \ \ +5 \ \ \ }[/tex]

Step-by-step explanation:

Hello

let's assume that we are looking for x >=0

[tex]4x^2=100 <=> \dfrac{4x^2}{4}=x^2=\dfrac{100}{4}=25\\<=>\sqrt{x^2}=25\\<=> |x| = 5 <=> x = 5 \ or \ x=-5[/tex]

Let's assume that we are looking for x>=0

so the correct answer is 5

ssume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -1.94°C and -1.5°C.

Answers

Answer:

[tex]P(-1.94<X<-1.5)=P(\frac{-1.94-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{-1.5-\mu}{\sigma})=P(\frac{-1.94-0}{1}<Z<\frac{-1.5-0}{1})=P(-1.94<z<-1.5)[/tex]

And we can find this probability with this difference:

[tex]P(-1.94<z<-1.5)=P(z<-1.5)-P(z<-1.94)=0.0668-0.026= 0.0408[/tex]

Step-by-step explanation:

Let X the random variable that represent the temperatures of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(0,1)[/tex]  

Where [tex]\mu=0[/tex] and [tex]\sigma=1[/tex]

We are interested on this probability

[tex]P(-1.94<X<-1.5)[/tex]

And using the z score formula given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

And using this formula we got:

[tex]P(-1.94<X<-1.5)=P(\frac{-1.94-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{-1.5-\mu}{\sigma})=P(\frac{-1.94-0}{1}<Z<\frac{-1.5-0}{1})=P(-1.94<z<-1.5)[/tex]

And we can find this probability with this difference:

[tex]P(-1.94<z<-1.5)=P(z<-1.5)-P(z<-1.94)=0.0668-0.026= 0.0408[/tex]

rewrite the following equation in logarithmic form and exponential form

Answers

Answer:The answer for the first one is log2(.25)=-2

The answer for the second one is 8^3=512

Step-by-step explanation:

In one lottery, a player wins the jackpot by matching all five numbers drawn from white balls (1 through 41) and matching the number on the gold ball (1 through 31). If one ticket is purchased what is the probability of winning the jackpot?
(Type answer as an integer or a simplified fraction)

Answers

Answer:

1 / 2,787,760,560

Step-by-step explanation:

The number of permutations is:

41 × 40 × 39 × 38 × 37 × 31 = 2,787,760,560

So the probability of winning the jackpot is 1 / 2,787,760,560.

cones and pyramids both have only one base ?

Answers

Answer:

Yes

Step-by-step explanation:

They both have only one base. They are different from prisms and cylinders.

yes. they both do only have one base and are separate from cylinders and prisms

What errors are shown here? Check all that apply.
-the arrows should be a length of 2
-the arrows should be a length of 6
-the arrows should be pointing in the positive direction
-the arrows should start at zero
-the arrows should point in the negative direction

Answers

Answer:

-The arrows should be a length of 6

-The arrows should point in the negative direction

-The arrows should start at zero

Step-by-step explanation:

Hope this helps!

Answer:

B

D

E

Step-by-step explanation:

Find the critical value needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places.
Part 1 of 4
(a) For level 95% and sample size 7.
Part 2 of 4
(b) For level 98% and sample size 12.
Part 3 of 4
(c) For level 99% and sample size 27.
Part 4 of 4
(d) For level 98% and sample size 14.

Answers

Answer:

a) [tex] t_{\alpha/2}=\pm 2.447[/tex]

b) [tex] t_{\alpha/2}=\pm 2.718[/tex]

c) [tex] t_{\alpha/2}=\pm 2.779[/tex]

d) [tex] t_{\alpha/2}=\pm 2.650[/tex]

Step-by-step explanation:

Part a

The degrees of freedom are given by:

[tex] df=n-1= 7-1=6[/tex]

The confidence is 95% or 0.95 the significance would be [tex]\alpha=0.05[/tex] and the critical values would be:

[tex] t_{\alpha/2}=\pm 2.447[/tex]

Part b

The degrees of freedom are given by:

[tex] df=n-1=12-1=11[/tex]

The confidence is 98% or 0.98 the significance would be [tex]\alpha=0.02[/tex] and the critical values would be:

[tex] t_{\alpha/2}=\pm 2.718[/tex]

Part c

The degrees of freedom are given by:

[tex] df=n-1=27-1=26[/tex]

The confidence is 99% or 0.99 the significance would be [tex]\alpha=0.01[/tex] and the critical values would be:

[tex] t_{\alpha/2}=\pm 2.779[/tex]

Part d

The degrees of freedom are given by:

[tex] df=n-1=14-1=13[/tex]

The confidence is 98% or 0.98 the significance would be [tex]\alpha=0.02[/tex] and the critical values would be:

[tex] t_{\alpha/2}=\pm 2.650[/tex]

A value of a test statistic defines the upper bounds of a confidence interval, statistical significance in a test statistic is known as the crucial value.

critical value:

For part a )

n = 7

Calculating the degrees of freedom [tex]= df = n - 1 = 7 - 1 = 6[/tex]

At [tex]95\%[/tex] the confidence level, the t:

[tex]\alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\frac{\alpha}{ 2} = \frac{0.05}{ 2} = 0.025\\\\t_{\frac{\alpha}{ 2}}\\\\df = t_{0.025,6} = 2.447\\\\[/tex]

The critical value = 2.447

For part b )

n =12

Calculating the degrees of freedom[tex]= df = n - 1 = 12 - 1 = 11[/tex]

At [tex]98\%[/tex] the confidence level , the t:

[tex]\alpha = 1 - 98\% = 1 - 0.98 = 0.02\\\\\frac{\alpha}{ 2}= \frac{0.02}{ 2} = 0.01\\\\t_{\frac{\alpha}{ 2}}\\\\df = t_{0.01,11} =2.718\\\\[/tex]

The critical value =2.718

For part c )

n = 27

Calculating the degrees of freedom [tex]= df = n - 1 = 27 - 1 = 26[/tex]

At [tex]99\%[/tex] the confidence level, the t:

[tex]\alpha = 1 - 99\% = 1 - 0.99 = 0.01\\\\\frac{\alpha}{ 2} = \frac{0.01}{ 2} = 0.005\\\\t_{\frac{\alpha}{ 2}}\\\\df = t_{0.005,26}=2.779\\\\[/tex]

The critical value =2.779

For part d )

n = 14

Calculating the degrees of freedom [tex]= df = n - 1 = 14 - 1 = 13[/tex]

At [tex]98\%[/tex] the confidence level, the t:

[tex]\alpha = 1 - 98\% = 1 - 0.98 = 0.02\\\\\frac{\alpha}{ 2} = \frac{0.02}{ 2} = 0.01\\\\t_{\frac{\alpha}{ 2}} \\\\df = t_{0.01,13} =2.650[/tex]

The critical value =2.650

Find out more about the critical value here:

brainly.com/question/14508634

Consider the following equation. f(x, y) = sin(4x + 3y), P(−6, 8), u = 1 2 3 i − j (a) Find the gradient of f. ∇f(x, y) = (b) Evaluate the gradient at the point P. ∇f(−6, 8) = (c) Find the rate of change of f at P in the direction of the vector u. Duf(−6, 8) =

Answers

Answer:

Step-by-step explanation:

a) Find the gradient

[tex]\nabla f(x,y) =f_x(x,y)\bold{i} +f_y (x,y)\bold{j}[/tex]

[tex]Also, sin(4x+3y)= sin(4x)cos(3y)+sin(3y)cos (4x)[/tex]

[tex]f_x(x,y) = 4cos(4x)cos(3y)-4sin(3y)sin(4x) = 4 cos(4x-3y)[/tex]

[tex]f_y(x,y) = -3sin(4x)sin(3y)+3cos(3y)cos(4x)=3cos(4x-3y)[/tex]

Hence

[tex]\nabla f(x,y) = 4cos(4x-3y)\bold{i}+3cos(4x-3y)\bold{j}[/tex]

b) At point (-6, 8) just replace the values in gradient to find it out. You can do it.

c) directional derivative in the direction u.

[tex]D_uf(x,y)=\nabla f(x,y). u[/tex]

I stuck with your 1 2 3 i -j . What does 1 2 3 mean? is it not 123 or 1 2/3 or else?

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